Record the lengths of the sides of ABC and ADE.

Answer:

L = 11.014 cm

Explanation:

Halfway between the two lenses is 19/2 = 9.5 cm.

Thus, this means virtually with respect to lens, the final image is at -9.5 cm

Thus, from here, we will work this out backwards.

Let's first solve for the initial position of the object for the second lens;

(1/S2) + (1/s'2) = (1/f2)

Where s'2 is the real image.

F2 is focal length

Thus;

(1/s'2) = (1/f2) - (1/s2)

(1/s'2) = (1/15) - (1/-9.5)

(1/s'2) = 0.1719

s'2 = 5.82 cm

The object for the second lens is located at 5.82 cm in front of the second lens.

Now, The object for the second lens and the image for the first lens will be the same.

This means the distance of the image from the first lens is at; 19 - 5.82 = 13.18 cm.

Now let's solve for the object distance of the first lens which will be denoted by L.

1/L = (1/f1) + (1/s'1)

Where f1 = 6 cm

1/L = (1/6) - (1/13.18)

1/L = 0.090794

L = 1/0.090794

L = 11.014 cm

Answer:

M = 1.409 10¹⁴ kg

Explanation:

In this exercise we have that the prioress with a minimum speed can escape from the asteroid, therefore we can use the conservation of energy relation.

Starting point. When you drop the stone

         Em₀ = K + U

         Em₀ = ½ m v² - G m M / r

where M and r are the mass and radius of the asteroid

Final point. When the stone is too far from the asteroid

          Em_f = U = - G m M / R_f

as there is no friction, the energy is conserved

          Em₀ = Em_f

          ½ m v² - G m M / r = - G m M / R_f

          ½ v² = G M (1 / r - 1 /R_f)

indicate that for the speed of v = 45.7 m /s, the stone does not return to the asteroid so R_f = ∞

          ½ v² = G M (1 /r)

          M = [tex]\frac{v^2 r}{2G}[/tex]

let's calculate

          M = [tex]\frac{45.7^2 \ 9}{ 2 \ 6.67 \ 10^{-11}}[/tex]

          M = 1.409 10¹⁴ kg

Answer:

eqcubuohwehuuc

Explanation:

the the the the the the the the the the the the the the the the dhueirrjhrhjrirjrheh3jeiiruj fnrhfjjjrjrj fjfiirrjejrjejej jrkrjrjrjrjrjdjdjfjrhruriruru rjridjhwjjsjd

Answer:

if i am not mistaken the volume is 7, because it only took that much space

Answer:

From Earth, the Sun looks like it moves across the sky in the daytime and appears to disappear at night. This is because the Earth is spinning towards the east. The Earth spins about its axis, an imaginary line that runs through the middle of the Earth between the North and South poles.

Answer:

The right solution is "50200 days".

Explanation:

Given:

Calories intake,

= 6000 kcal,

or,

= [tex]2.52\times 10^7 \ J[/tex]

Force,

= 500 N

As we know,

⇒ [tex]Work \ done = Force\times distance[/tex]

Or,

⇒ [tex]distance = \frac{Work \ done}{Force}[/tex]

By putting the values, we get

                  [tex]=\frac{2.52\times 10^7}{500}[/tex]

                  [tex]=0.502\times 10^5[/tex]

                  [tex]=50200 \ m[/tex]

hence,

The number of days will be:

= [tex]\frac{50200}{1}[/tex]

= [tex]50200 \ days[/tex]

Answer:

[tex]W=2.76\times 10^{-6}\ J[/tex]

Explanation:

Given that,

The distance between two spheres, r = 25 cm = 0.25 m

The capacitance, C = 26 pF = 26×10⁻¹² F

Charge, Q = 12 nC = 12 × 10⁻⁹ C

We need to find the work done in moving the charge. We know that, work done is given by :

[tex]U=\dfrac{Q^2}{2C}[/tex]

Put all the values,

[tex]U=\dfrac{(12\times 10^{-9})^2}{2\times 26\times 10^{-12}}\\\\U=2.76\times 10^{-6}\ J[/tex]

So, the work done is [tex]2.76\times 10^{-6}\ J[/tex].

Answer:

m_cable = 2,676 kg

Explanation:

For this exercise we must look for the acceleration with the kinematic ce relations

          v² = v₀² + 2 a x

since the block starts from rest, its initial velocity is vo = 0

          a = v² / 2x

          a = 4.2² /(2 2.0)

          a = 4.41 m / s²

now we can use Newton's second law

Note that the mass that the extreme force has to drag is the mass of the block plus the mass of the cable.

          F = (m + m_cable) a

          m_cable  = F / a -m

          m_cable = 100 / 4.41 - 20

          m_cable = 2,676 kg

Answer:

carbon has tetra valency while oxygen  can make 2 bonds while nitrogen can make 3 bonds  and hydrogen can make 1 bond so i think answer is definatly carbon

Explanation:

Answer:

Mercury - 800°F (430°C) during the day, -290°F (-180°C) at night. Venus - 880°F (471°C) Earth - 61°F (16°C) Mars - minus 20°F (-28°C)30-Jan-2018

Answer:

Option C. 50 N

Explanation:

From the question given above, the following data were obtained:

Force (F) applied = 100 N

Angle (θ) = 60°

Horizontal component (Hₓ) =?

The horizontal component of the force can be obtained as follow:

Hₓ = F × Cos θ

Hₓ = 100 × Cos 60

Hₓ = 100 × 0.5

Hₓ = 50 N

Therefore, the horizontal component of the force acting on the dog is 50 N

Answer:

Explanation:

V=ds/dt

Where s =distance traveled

Given

V= 2ti - 3t²j

ds/dt=2ti - 3t²j

ds=(2ti - 3t²j)dt

Integrating

S= 2t²i/2 - 3t³j/3 + C

S=t²i - t³j + C

Since the object starts from Rest when t=0 and s(distance)=0

0=0²i - 0³j + C

C=0

Therefore

S=t²i - t³j

At t=2sec

S=(2)²i - (2)³j

S=4i - 8j

Magnitude of S(distance) = √4²+(-8)²

S= 4√5 meters

S=8.94meters.

2.mass =2kg

F(t)=5e^-0.1t

From Newton 2nd Law

F(t) = mdv/dt

5e^-0.1t= 2dv/dt

2dv = (5e^-0.1t)dt

Integrating

2V(t) = 5e^-0.1t/(-0.1) + C

2v(t) = - 50e^-0.1t + C

Since it started from rest at t=0. That is v(0)=0

2(0) = -50e^-0.1(0) + C

0 = -50 + C

C= 50

v(t) = -50e^-0.1t + 50

At t=10sec

v(10) = -50e^-0.1(10) + 50

V= -18.39 + 50

V= 31.61ms-¹.

While using your calc to evaluate -50e^-0.1(10)

Don't forget the -(minus) sign at the top of the exponential.

If you neglect it... You'll have a different answer.

Hope this helps.

Have a great day!!!

Answer:

The velocity of wind with respect to cyclist is [tex]-15.5 \widehat{i} - 3.5 \widehat{j}[/tex].

Explanation:

speed of cyclist = 12 km/h east

speed of wind = 5 km/h south west

Write the speeds in the vector form

[tex]\overrightarrow{vc} = 12 \widehat{i}\\\\overrightarrow{vw} = - 5 (cos 45 \widehat{i} + sin 45 \widehat{j})\\\\\overrightarrow{vw} =-3.5 \widehat{i} - 3.5 \widehat{j}[/tex]

The velocity of wind with respect to cyclist is

[tex]\overrightarrow{vw} =-3.5 \widehat{i} - 3.5 \widehat{j}\overrightarrow{v_(w/c)} = \overrightarrow{vw}-\overrightarrow{vc}\\\\\overrightarrow{v_(w/c)} = - 3.5 \widehat{i} - 3.5 \widehat{j} - 12 \widehat{i}\\\\\overrightarrow{v_(w/c)} =-15.5 \widehat{i} - 3.5 \widehat{j}[/tex]

Answer:

What is the answer bro idont now

Answer:

[tex]w_2=38.3rpm[/tex]

Explanation:

From the question we are told that:

Mass of turntable [tex]M=2.2kg[/tex]

Diameter of turntable [tex]d=20cm=>0.2m[/tex]

Angular Velocity [tex]\omega =80rpm[/tex]

Mass of Blocks [tex]M_b=600g=>0.6kg[/tex]

Generally the equation for inertia is mathematically given by

Initial scenario at \omega=80rpm

 [tex]I_1=\frac{1}{2}mR^2[/tex]

 [tex]I_1=\frac{1}{2}*2.2*0.1^2[/tex]

 [tex]I_1=0.11kgm^2[/tex]

Final scenario

 [tex]I_2=I_1+2mR^2[/tex]

 [tex]I_2=0.011+(2*0.6*0.12)[/tex]

 [tex]I_2=0.023[/tex]

Generally the equation for The relationship between Angular velocity and inertia is mathematically given by

 [tex]I_1w_1=I_2w_2[/tex]

 [tex]w_2=\frac{I_1 \omega}{I_2}[/tex]

 [tex]w_2=\frac{0.011*80}{0.023}[/tex]

 [tex]w_2=38.3rpm[/tex]

Answer:

the correct answer is C

Explanation:

In this exercise we will analyze the situation.

When the person is on the ice, the friction coefficient is very small, if the box is in a place where there is no ice, the coefficient is different, so the friction force on each body is different.

Therefore the acceleration that each body acquires is different.

If we apply the conservation of momentum, each body moves in the opposite direction, but with different speeds.

If we use Newton's third law, the force applied to each body has the same magnitude and opposite direction, which is why the force is of the action and reaction type

Consequently the correct answer is C

The correct answer is option B. Determine whether experimental observations can provide evidence to support a conclusion.

1. Identify the research question: Begin by clearly defining the question or problem that you want to investigate. This question should be specific and focused, allowing for clear hypotheses to be developed.

2. Conduct background research: Familiarize yourself with existing knowledge and previous research related to your question. This step will help you understand the current state of knowledge in the field and identify any gaps or areas that require further investigation.

3. Formulate a hypothesis: Based on your background research, develop a hypothesis that proposes a possible explanation or answer to your research question. A hypothesis should be a clear statement that can be tested through experimentation or observation. It should be specific, measurable, and falsifiable, meaning that it can be proven wrong if the evidence does not support it.

4. Design experiments or observations: Once you have formulated a hypothesis, consider the experimental or observational methods that can be used to test it. Determine what data you need to collect, what variables you need to manipulate or measure, and what controls should be put in place to ensure the validity of your results.

5. Predict outcomes: Based on your hypothesis, make predictions about the expected outcomes of your experiments or observations. These predictions should be derived from your hypothesis and should be specific enough to be tested.

6. Conduct the experiment or observation: Carry out the planned experiments or observations, ensuring that you collect and record data accurately. Implement proper controls and procedures to minimize any biases or confounding factors that could affect the results.

7. Analyze the data: Once you have collected the data, analyze it using appropriate statistical or analytical methods. Evaluate whether the data supports or contradicts your hypothesis and predictions.

8. Draw conclusions: Based on the analysis of your data, draw conclusions about whether the evidence supports or refutes your hypothesis. Clearly state the findings and discuss their implications in the context of the research question.

9. Communicate the results: Share your findings with the scientific community through scientific papers, presentations, or other appropriate means. Allow other scientists to review and replicate your work, fostering further discussion and advancement in the field.

Remember, the scientific process is iterative, and developing a hypothesis is just the starting point. Scientists continuously refine and revise their hypotheses based on new evidence and insights gained from their experiments and observations.

For more such questions on observations , click on:

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Answer:

The work done is -209.42 J.

Explanation:

F(x) = (- 20 - 3 x ) N

x = 0 to x = 6.9 m

Here, the force is variable in nature, so the work done by the variable force is given by

[tex]W =\int F dx\\\\W =\int_{0}^{6.9}(-20- 3x dx )\\\\W= \left [ - 20 x - 1.5 x^2 \right ]_{0}^{6.9}\\\\W = - 20 (6.9 - 0) - 1.5(6.9\times 6.9 - 0)\\\\W =- 138 - 71.42\\\\W = - 209.42 J[/tex]

Answer:

Explanation:

Wind is caused by the uneven heating of the atmosphere by the sun, variations in the earth's surface, and rotation of the earth. ... Wind turbines convert the energy in wind to electricity by rotating propeller-like blades around a rotor. The rotor turns the drive shaft, which turns an electric generator

Answer:

telekinesis moving things with your mind

Answer:

A. 6.13 x 107

Explanation:

Given the expression

5.92 x 10^7 + 2.11 x 10^6

First, we need to convert to the whole number

5.92 x 10^7 = 59200000

2.11 x 10^6 = 2110000

Add both values

59200000 + 2110000

= 61,310,000

Express in standard form

= 6.13 * 10^7

This gives the required result

The time spent by the campers when they turn around downstream is 15 minutes.

The concept of total distance traveled by Nick and Chloe can be used to determine the time they turn around downstream.

Let time for downstream = t1

Let time for upstream = t2

distance covered in upstream = distance covered in downstream = d

12(t1) = d

4(t2) = d

12t1 = 4t2

t1 + t2 = 1

t2 = 1 - t1

12t1 = 4(1 - t1)

12t1 = 4 - 4t1

16t1 = 4

t1 = 4/16

t1 = 0.25 hours

t1 = 0.25(60 min) = 15 mins

Learn more about distance here: https://brainly.com/question/2854969

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Answer: 0.04

Explanation:

Given

Radius of turntable [tex]r=0.8\ m[/tex]

Block is present at a distance of [tex]r_o=0.4\ m[/tex]

Turntable rotates at a speed of [tex]v=0.8\ m/s[/tex]

angular speed of turntable [tex]\omega =\dfrac{v}{r}[/tex]

[tex]\Rightarrow \omega =\dfrac{0.8}{0.8}\\\Rightarrow \omega =1\ rad/s[/tex]

block will experience a force i.e. centripetal force equal to [tex]m\omega ^2r[/tex]. This must balance the friction force [tex]\mu mg[/tex]

[tex]\Rightarrow m\omega^2 r_o=\mu mg\\\Rightarrow 1^2\times 0.4=\mu \times 9.8\\\Rightarrow \mu =0.04[/tex]

Thus, the coefficient of static friction force is [tex]0.04[/tex]

Complete question:

A bullet is shot straight up into the air from ground level. It reaches a maximum height at h = 739 m. Calculate the initial velocity of the bullet.

Answer:

the initial velocity of the bullet is 120.35 m/s

Explanation:

Given;

maximum height reached by the bullet, h = 739 m

let the initial velocity of the bullet = u

At maximum height the final velocity of the bullet, v = 0

Apply the following kinematic equation to determine the initial velocity of the bullet.

v² = u² - 2gh

0 = u² - 2gh

u² = 2gh

u = √2gh

u = √(2 x 9.8 x 739)

u = 120.35 m/s

Therefore, the initial velocity of the bullet is 120.35 m/s

Answer:

W = 2 eV

Explanation:

Given that,

The wavelength of a photon = 455 nm

The kinetic energy of a photon, K = 0.73 eV

We need to find the work function of the electron. It can be solved using Einstein's equation such that,

[tex]W=E-K[/tex]

E is the energy of the photon

So,

[tex]W=\dfrac{hc}{\lambda}-K\\\\W=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{455\times 10^{-9}\times 1.6\times 10^{-19}}-0.73\\\\W= 2.73\ eV-0.73\ eV\\\\W=2\ eV[/tex]

So, the work function of the metal is 2 eV.

Answer:V=Aq=KQr

Explanation:

Không biết V bạn kí hiệu ở đây là gì nhỉ? Có phải là điện thế?

Điện thế tại 1 điểm trong điện trường được định nghĩa là công làm vật dịch chuyển từ vị trí đó đến vô cùng. V = A/q

Chứng minh thì được, nhưng chỉ e bạn không có hiểu biết về nguyên hàm, tích phân nên không hiểu.

- Xét tại vị trí cách điện tích Q một đoạn x, khi đó điện tích q sẽ chịu 1 lực: dF=KQ.qx2

Điện tích q dịch chuyển 1 khoảng dx rất nhỏ. Khi đó công do lực điện trường gây ra là:

dA=dF.dx=KQ.qx2dx

Công để dịch chuyển điện tích q từ vị trí r đến vô cùng là:

A=∫∞rdA=∫∞rKQ.qx2dx=KQ.qr−KQ.q∞=KQ.qr

Theo đúng định nghĩa: V=Aq=KQr

Answer:

Refer to the attachment!~

Answer:

Explanation:

From the question we are told that:

Energy [tex]Q=7950kcal=3.3*10^7[/tex]

Initial Volume [tex]V_1=12.8 m^2[/tex]

Final Volume [tex]V_2=19.4 m^2[/tex]

a)

Generally the equation for Work done is mathematically given by

 [tex]W=P \triangle V[/tex]

Where

 [tex]P= Pressure at 1atm[/tex]

Therefore

 [tex]W=(1.01*10^5)(19.4-12.8)[/tex]

 [tex]W=6.67*10^5J[/tex]

a)

Generally the equation for Change in internal energy of the gas is mathematically given by

 [tex]\triangle U=Q-W[/tex]

 [tex]\triangle U=3.3*10^7-6.67*10^5J[/tex]

 [tex]\triangle U=3.2*10^7J[/tex]