Reduce 22/154
to its lowest form.

The number of installations in September were forty that lead to John and Wesley earning same amount of money.

Let the number of installations be x. The equation of be formed for each paycheck will be -

Total paycheck = base pay + number of installations × comission on each installation

The total paycheck and number of installations is same. So equating the equations by keeping x.

2000 + 65.25x = 380 + 105.75x

Rewriting the equation -

105.75x - 65.25x = 2000 - 380

Performing subtraction on each side of the equation

40.5x = 1620

x = 1620/40.5

Performing division on Right Hand Side of the equation

x = 40

There were 40 installations.

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Answer : if each topping is 1.25 then multiply that by 3 because there's 3 toppings on the pizza and if the total was 16.25 the original price of the pizza is 12.5. I hope this was the answer you were looking for a good luck :)

Step-by-step explanation:

Answer:

Slope = -1 or (-1/1)

Step-by-step explanation:

slope = m

Point 1: (0, 2); Point 2: (2, 0)

           (x₁, y₁)                (x₂, y₂)

        y₂ - y₁       0 - 2        -2

m = ----------- = ---------- = ------- = -1 or (-1/1)

        x₂ - x₁       2 - 0        2

I hope this helps!

Step-by-step explanation:  12 - 14 is 2 years

                                               14 - 15 is 1 year

                                               15 - 17 is 3 years

I would say the rang is 1 -3 years apart

Hope this helps any

The coefficient of XYZ in the product of 2xy 3zx and Y 2z is 0.

The formula for coefficient is C = a*b, where a and b are the coefficients of the terms being multiplied.

In the given example, the coefficients for the terms being multiplied are 2 for 2xy, 3 for 3zx, and 0 for Y 2z. Since 0 multiplied by any number is 0, the coefficient of XYZ in the product is 0.

Mathematically, this can be expressed as:

C = 2*3*0 = 0

Therefore, the coefficient of XYZ in the product of 2xy 3zx and Y 2z is 0.

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Answer:

awser is D. I did the text

The length of the line segment BP = 15 using the trigonometric ratio of sine for the angle P.

The trigonometric ratios involves the relationship of an angle of a right-angled triangle to ratios of two side lengths. Basic trigonometric ratios includes; sine cosine and tangent.

Considering the right triangles formed by points at P, A and the tangent to the bigger circle with its radius as base;

radius r = 10 and hypotenuse AP = 30

sinP = 10/30 {opposite/hypotenuse}

sinP = 1/3

Also for the smaller circle, with right triangle formed by points at P, B and the tangent to the smaller circle with its radius as base;

radius r and hypotenuse BP = 20 - r

sinP = r/(20 - r)

1/3 = r/(20 - r)

3r = 20 - r {cross multiply}

3r + r = 20 {collect like terms}

4r = 20

r = 20/4 {divide through by 4}

r = 5

BP = 20 - 5

BP = 15

Therefore, length of the line segment BP is derived using the trigonometric ratio of sine as 15.

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The equation is

log ( milligrams of drug A ) =3 - 0.0737 ( Time)

As per the details  stated above,

Curved relationship between the number of milligrams of drug A is  (x) still in the body and the number of hours since drug A was delivered (y)

The co-efficient of the constant is 3.00

the co-efficient of the time is -0.0737

the SE  co-efficient of the constant is 0.4017

the SE co-efficient of the time is 0.005

the t-ratio of the constant is 7.481

the t-ratio of the time is -14.74

now the equation formed is

logarithm of drug A in milligrams is  (The co-efficient of the constant - the co-efficient of the time )

that is log ( milligrams of drug A ) =3 - 0.0737 ( Time).

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The displacement of the pizza delivery driver for the full journey is therefore 6.08 miles.

The pizza delivery driver's displacement for the entire trip is the total distance and direction that she travels from the restaurant to her last delivery and back.

To find her displacement, we can use the Pythagorean theorem to find the total distance from the start to the endpoint.

The displacement is the distance between the start and end point and the direction of the trip. Here we can see that she traveled 4 miles north, 6 miles east, and 5 miles south,

To find the displacement we will use the Pythagorean theorem (ax2 + bx2 = cx2)

where c is the displacement and a and b are the east-west and north-south distances respectively.

so, a = 6 miles (east-west)

b = (4 miles - 5 miles) = -1 miles (north-south)

so, c = √(ax2 + bx2)

c = √(6x2 + (-1)x2)

c = √(36 + 1)

c = √(37)

c = 6.08 miles

So the pizza delivery driver's displacement for the entire trip is 6.08 miles.

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The approximate length, in feet, of lights that she needs to create one triangle is 64

This is an approximate estimate as the exact length would depend on the specific measurements of the roof line. However, if the roof line is a typical house roof and the string lights are hung horizontally across to connect the ends of the roof line, creating a triangle, the approximate length of lights needed would be the hypotenuse of the triangle (the longest side) which is equal to the square root of (leg 1^2 + leg 2^2).

A typical house roof is approximately 40 feet wide and 20 feet tall, which creates a right triangle with legs of 40 and 20. The hypotenuse of this triangle (the length of lights needed) would be approximately 64 feet (the square root of (40^2 + 20^2) = 64).

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The basis for the eigenspace corresponding to lambda=5,1,4 are None,[tex]\left[\begin{array}{c}-1 \\\frac{1}{2} \\0\end{array}\right][/tex] and [tex]$\left[\begin{array}{l}2 \\ 1 \\ 1\end{array}\right]$[/tex]

[tex]$$A=\left[\begin{array}{ccc}5 & -12 & 10 \\0 & 7 & -3 \\0 & 6 & -2\end{array}\right]$$[/tex]

Eigenspace corresponding to lambda=5,1,4

The eigenspace E_lambda corresponding to the eigenvalue lambda is the null space of the matrix a [tex]\mathrm{A}-(\lambda) \mathrm{I}"[/tex]

for lambda=5

[tex]$$\mathrm{E}_5=\mathrm{N}(\mathrm{A}-5 \mathrm{I})$$[/tex]

Reducing the matrix A-5I by elementary row operations

[tex]$$\begin{aligned}A-5 I & =\left[\begin{array}{ccc}5-5 & -12 & 10 \\0 & 7-5 & -3 \\0 & 6 & -2-5\end{array}\right] \\& =\left[\begin{array}{ccc}0 & -12 & 10 \\0 & 2 & -3 \\0 & 6 & -7\end{array}\right] \\& \sim\left[\begin{array}{ccc}0 & -12 & 10 \\0 & 1 & -\frac{3}{2} \\0 & 6 & -7\end{array}\right] R_2 \rightarrow \frac{R_2}{2} \\& \sim\left[\begin{array}{ccc}1 & 0 & -8 \\0 & 1 & -\frac{3}{2} \\0 & 6 & -7\end{array}\right] R_1 \rightarrow R_1+2 R_2\end{aligned}$$[/tex]

[tex]\sim\left[\begin{array}{ccc}1 & 0 & -8 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 2\end{array}\right] R_3 \rightarrow R_3-6 R_2$$\\\sim\left[\begin{array}{ccc}1 & 0 & -8 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 1\end{array}\right] R_3 \rightarrow \frac{\mathrm{R}_3}{2}$$\\\sim\left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 1\end{array}\right] \mathrm{R}_1 \rightarrow \mathrm{R}_1+8 \mathrm{R}_3$[/tex]

[tex]$\sim\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right] R_2 \rightarrow R_2+\frac{2 R_3}{2}$[/tex]

The solutions x of A-5I=0 satisfy x_1=x_2=x_3=0 that is, the null space solves the matrix

[tex]$$\left[\begin{array}{lll}1 & 0 & 0 \\0 & 1 & 0 \\0 & 0 & 1\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{l}0 \\0 \\0\end{array}\right]$$[/tex]

Hence The null space is [tex]\left[\begin{array}{l}0 \\ 0 \\ 0\end{array}\right] E_5[/tex] has no basis

[tex]$$\begin{aligned}& \text { case: } 2 \\& \text { for } \lambda=1 \\& \mathrm{E}_5=\mathrm{N}(\mathrm{A}-(1) \mathrm{I})\end{aligned}$$[/tex]

we reduce the matrix A-I by elementary row operations as follows.

[tex]$$\begin{aligned}A-1 & =\left[\begin{array}{ccc}5-1 & -12 & 10 \\0 & 7-1 & -3 \\0 & 6 & -2-1\end{array}\right] \\& =\left[\begin{array}{ccc}1 & -3 & \frac{5}{2} \\0 & 6 & -3 \\0 & 6 & -3\end{array}\right] R_1 \rightarrow \frac{R_1}{4} \\& \sim\left[\begin{array}{ccc}1 & -3 & \frac{5}{2} \\0 & 1 & -\frac{1}{2} \\0 & 6 & -3\end{array}\right] R_2 \rightarrow \frac{R_2}{6}\end{aligned}[/tex]

[tex]$$$\sim\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 6 & -3\end{array}\right] R_1 \rightarrow R_1+3 R_2$\\$\sim\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 0 & 0\end{array}\right] R_3 \rightarrow R_3-6 R_2$[/tex]

Thus, the solutions x of (A-I) X=0 satisfy

[tex]$\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 0 & 0\end{array}\right]\left[\begin{array}{l}x_1 \\ x_2 \\ x_3\end{array}\right]=\left[\begin{array}{l}0 \\ 0 \\ 0\end{array}\right]$[/tex]

x_3=t

[tex]$\Rightarrow \mathrm{x}_1=-\mathrm{t}, \mathrm{x}_2=\frac{\mathrm{t}}{2}$[/tex]

[tex]$\vec{x}=\left[\begin{array}{c}-t \\ \frac{t}{2} \\ t\end{array}\right]=\left[\begin{array}{c}-1 \\ \frac{1}{2} \\ 1\end{array}\right] t$[/tex]

The Basis for the nullspace A-I will be: [tex]$\left.\left(\begin{array}{c}-1 \\ \frac{1}{2} \\ 1\end{array}\right]\right)$[/tex]

case:3

lambda=4

[tex]$$\mathrm{E}_5=\mathrm{N}(\mathrm{A}-(4) \mathrm{I})$$[/tex]

we reduce the matrix A-4I by elementary row operations as follows.

[tex]$\begin{aligned} A-4 \mid & =\left[\begin{array}{ccc}5-4 & -12 & 10 \\ 0 & 7-4 & -3 \\ 0 & 6 & -2-4\end{array}\right] \\ & =\left[\begin{array}{ccc}1 & -12 & 10 \\ 0 & 3 & -3 \\ 0 & 6 & -6\end{array}\right] \\ & \sim\left[\begin{array}{ccc}1 & -12 & 10 \\ 0 & 1 & -1 \\ 0 & 6 & -6\end{array}\right] R_2 \rightarrow \frac{R_2}{3}\end{aligned}$[/tex]

[tex]$\begin{aligned} & \sim\left[\begin{array}{ccc}1 & 0 & -2 \\ 0 & 1 & -1 \\ 0 & 6 & -6\end{array}\right] \mathrm{R}_1 \rightarrow \mathrm{R}_1+12 \mathrm{R}_2 \\ & \sim\left[\begin{array}{ccc}1 & 0 & -2 \\ 0 & 1 & -1 \\ 0 & 0 & 0\end{array}\right] \mathrm{R}_3 \rightarrow \mathrm{R}_3-6 \mathrm{R}_2\end{aligned}$[/tex]

Thus, the solutions x of (A-4IX)=0 satisfy

[tex]$$\left[\begin{array}{ccc}1 & 0 & -2 \\0 & 1 & -1 \\0 & 0 & 0\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{l}0 \\0 \\0\end{array}\right]$$[/tex]

x_3=t

[tex]$\Rightarrow \mathrm{x}_1=2 \mathrm{t}, \mathrm{x}_2=\mathrm{t}$[/tex]

[tex]$$\vec{x}=\left[\begin{array}{c}2 t \\t \\t\end{array}\right]=\left[\begin{array}{l}2 \\1 \\1\end{array}\right] t$$[/tex]

The Basis for the nullspace A-4 I will be [tex]\left(\left[\begin{array}{l}2 \\ 1 \\ 1\end{array}\right]\right)[/tex]

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Each friend of Arya will receive 0.625 cupcakes.

To divide 5 cupcakes equally among 8 friends, we can use simple division. We would divide the total number of cupcakes (5) by the total number of friends (8) to find the number of cupcakes each friend would receive. In this case, 5 divided by 8 is equal to 0.625. This means that each friend will receive 0.625 cupcakes. However, since cupcakes are not divisible it is not possible to divide 5 cupcakes equally among 8 friends. In this case, either Arya will have to make more cupcakes or they will have to decide on a different way to divide the cupcakes.

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Elsa purchased 6 pounds of coffee.

The process of figuring out a product's quantitative worth based on both internal and external elements is called product pricing. Product price directly affects your company's entire success, including cash flow, profit margins, and client demand.

Here is an easy example of value-based pricing. When you bring a young child to a petting zoo, she expresses a desire to feed the goats. The goat food dispenser is topped off with a quarter. From a financial standpoint, there is the price of the goat food, which is around two cents.

Calculate the total cost of all the items you bought. To calculate the cost price, divide the total cost by the quantity of units purchased. To determine the ultimate price, use the selling price formula: Cost price plus profit margin equals selling price.

Since she started with $80 and ended with with $34,88, we can find the total amount she spent by subtracting these amounts:

$80 - $34.88 = $45.12

This means that she spent $45.12 on coffee.  If each pound cost $7.52, we can divide $45.12 by $752 to see how many pounds she bought (ignoring tax):

45.12 / 7.52 = 6 pounds of coffee purchased

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Answer:

93.3% i hope this is right

Step-by-step explanation:

percentage increase= final-original/originalx100

58-30/30x100=93.3333%

Some acceptable board lengths are: 15.8 ft, 16.20 ft and 16.10 feet

Now, According to the question:

Board lengths that should be accepted

From the question, we have the following parameters that can be used in our computation:

Length = 16 ft

Percent error = 1.5%

This means that the acceptable lengths are

Acceptable = Length ± Percent error * Length

Substitute the known values in the above equation, so, we have the following representation

Acceptable = 16 ± 1.5% * 16

So, we have

Acceptable = 16 ± 0.24

Evaluate

Acceptable = 15.76 to 16.24

Some board lengths that should be accepted are 15.8 ft, 16.20 ft and 16.10 feet

Board lengths that should be rejected

In (a), we have

Acceptable = 15.76 to 16.24

Some board lengths that should be rejected are 14.8 ft, 17.20 ft and 12.10 feet

The intended lengths of the boards

Here, we have

Lengths = 10, 12 and 14 feet

Length too long = 2.3 inches

Convert to inches

Length too long = 0.19

So, we have

Intended lengths = (10, 12 and 14 feet) + 0.19

Evaluate

Intended lengths = 10.19, 12.19 and 14.19 feet

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In scenerio 1, the money in the retirement account at 62 years old is         $1,267,250.76

In scenerio 2, the money in the retirement account at 62 years old is         $ 633,625.38.

Scenerio 1:

a) 6% of salary = Salary * 6% = $6,100 * 6% = $366

b) Total amount the company paid monthly = 6% of salary = Salary * 6% = $6,100 * 6% = $366

c) The money in the retirement account at 62 years old can be calculated using the formula for calculating the Future Value (FV) of an Ordinary Annuity given as follows:

FV = M * (((1 + r)^n - 1) / r) ................................. (1)

Where:

FV = Future value = Money in the retirement account at 62 years old = ?

M = Monthly payment = Contribution you + Contribution by the employer = $366 + $366 = $732

r = Monthly interest rate = Annual interest rate / 12 = 6.28% / 12 = 0.0628 / 12 = 0.0052

n = number of months = Number years * Number of months in a year = (Retirement age – Age when hired) * 12 = (62 - 25) * 12 = 37 * 12 = 444

Substituting all the values into equation (1), we have:

FV = $732 * (((1 + 0.0052)^444 - 1) / 0.0052)

FV = Money in the retirement account at 62 years old = $1,267,250.76

d) Amount of money you put into the account = 6% of salary * number of months = $366 * 444 = $162,504

e) Amount of money your employer put into your account = Amount of money you put into the account = $162,504

f) Amount your account gained in interest over the years = FV – (Amount of money you put into the account + Amount of money your employer put into your account) = $1,267,250.76 – ($162,504 + $162,504) = $942,242.76

Scenario 2:

a) 3% of salary = Salary * 3% = $6,100 * 3% = $183

b) Total amount the company paid monthly = 3% of salary = Salary * 3% = $6,100 * 3% = $183

c) Using equation (1), we have:

M = Monthly payment = Contribution you + Contribution by the employer = $183 + $183 = $366

Substituting all the values into equation (1), we have:

FV = $366 * (((1 + 0.0052)^444 - 1) / 0.0052)

FV = Money in the retirement account at 62 years old = $633,625.38

d) Amount of money you put into the account = 3% of salary * number of months = $183 * 444 = $81,252.00

e) Amount of money your employer put into your account = Amount of money you put into the account = $81,252

f) Amount your account gained in interest over the years = FV – (Amount of money you put into the account + Amount of money your employer put into your account) = $633,625.38 – ($81,252 + $81,252) = $471,121.38

The difference in the amount of money at age 62 between scenarios 1 and 2 = Money in the retirement account at 62 years old in scenarios 1 + Money in the retirement account at 62 years old in scenarios 2 = $1,267,250.76 - $633,625.38 = $633,625.38

Difference in the amounts of money you put into retirement between scenarios 1 and 2 = $366 - $183 = $183

Amount got from your employer in scenario 1 than 2 = $366 - $183 = $183

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The function’s average rate of change over the interval from x = 1 to x = 2 is: -2. The correct option b.

In mathematics, a line's slope, also known as its gradient, is a numerical representation of the line's steepness and direction.

We have the interval from x = 1 to x = 2.

To find the function’s average rate of change over the interval from x = 1 to x = 2 is:

We interpreted the interval in the coordinate form.

The curve from (1, 2) to (2, 0) is a straight line.

And the slope of the line is the average rate of change of the function.

If a line passes through two points (x₁ ,y₁) and (x₂, y₂) ,

then the equation of line is

y - y₁ = (y₂- y₁) / (x₂ - x₁) x (x - x₁)

To find the slope;

m =  (y₂- y₁) / (x₂ - x₁)

m = (0-2) / (2-1)

m = -2/1

m = -2

Therefore, the average rate of change is -2.

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Answer:

69%

Step-by-step explanation:

There are 42 teachers who work in a school. On Monday, 29 teachers were present. The percentage of the teachers that showed up for work will be:

= 29 / 42 × 100

= 69%

Answer:

Step-by-step explanation:

In any case where you're asked, "what percentage of A is B?" you can simply divide the number B by the A. The decimal you get is the answer. for example, if you're being asked what percentage 12 is of 25, you just divide 12 by 25 to get 0.48, which translates to 48 percent. in your case, 29/42 is 0.69 (rounded down from 0.6904761905) which equals 69%.

In a case where B is larger than A, you still do the same, only with the addition of the whole number. Ex: what percentage of 25 is 86?

86/25 is 3.44, so your answer is 344%.

Hope this helped :)

to get the slope of any straight line, we simply need two points off of it, let's use those two in the picture below.

[tex](\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{3}-\stackrel{y1}{(-4)}}}{\underset{\textit{\large run}} {\underset{x_2}{4}-\underset{x_1}{(-2)}}} \implies \cfrac{3 +4}{4 +2} \implies {\large \begin{array}{llll} \cfrac{7 }{ 6 } \end{array}}[/tex]

[tex]16r^2s^2[/tex] as the product of power is written as [tex](4rs)^2[/tex]

The power of a product rule states that [tex](a^m)(a^n) = a^(m+n)[/tex], where "a" is the base, "m" is the exponent of the first term, and "n" is the exponent of the second term. This rule allows us to simplify expressions where multiple variables are being raised to a power and multiplied together by adding the exponents.

For example, [tex](a^2)(a^3) = a^(2+3) = a^5[/tex].

It is also important to remember that when we are using the power of a product rule, the bases must be the same. If we have different bases, we cannot use this rule.

For example, [tex](a^2)(b^3) = a^2 * b^3, not a^(2+3) = a^5[/tex].

Rewritten as power of product:

[tex]16r^2 s^2= 4*4*r*r*s*s\\16r^2s^2= 4^2*r^2*s^2\\16r^2s^2=(4rs)^2[/tex]

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The equation of the perpendicular bisector of the segment with the endpoints (-8,-1) and (4,5)  is 2x+y = -2.

The line between these locations' slopes must equal the negative reciprocal of the bisector's slope. It must go through the segment midway.

The slope of the line through the given points :

m = (y2 -y1)/(x2 -x1) = (5 -(-1))/(4 -(-8)) = 6/12 = 1/2

Then, The slope of the required bisector:   m = -1/(1/2) = -2

The midpoint of the given segment:

((-8, -1) +(4, 5))/2 = (-8+4, -1+5)/2 = (-4, 4)/2 = (-2, 2)

Then the point-slope form of the equation of the bisector:

y -y1 = m(x -x1)

y -2 = -2(x -(-2))

y = -2x -4 +2

y = -2x -2 . . . . . . . slope-intercept form equation

2x +y = -2 . . . . . . .standard form equation

Thus, The equation of the perpendicular bisector of the segment with the endpoints (-8,-1) and (4,5)  is 2x+y = -2.

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The y - intercept of the graph, given the formula of 2 y - 5x = 16, is y - intercept : ( 0, 8)

To find the y - intercept, use the slope - intercept form of the equation of a line which is:

y = mx + b

m = slope

b = y - intercept

So first rewrite the formula given to look like the slope - intercept :

2 y - 5x = 16

2 y = 5x + 16

( 2 y = 5x + 16 ) / 2

y = 5/ 2 x + 8

The y- intercept is therefore 8. As a point on the graph, this is ( 0, 8 )

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Using the regression concept to find the equation and applying derivative, The rate of change is 10.

Regression analysis is a group of statistical procedures used in statistical modeling to determine the associations between a dependent variable and one or more independent variables. The dependant variable's predicted value in basic linear regression is given by the equation = b0 + b1x. In order to minimize the total sum of squared errors, the values of b0 and b1 are derived from the data using the equation line = b0 + b1X. 

The derivative of a function of a real variable in mathematics assesses how sensitively the function's value changes in response to changes in its argument. Calculus's core tool is the derivative.

from the given data,

y= a + bx is our regression line.

a=8 and b =10

y=8+10x is the line.

derivate the line , we get,

[tex]\frac {dy}{dx} = 10[/tex]

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Answer:

(I cannot show a picture of a bar model, apologies)

Answer: 12.96

Step-by-step explanation: you should multiply 12 * 0.08 = 0.96

then just add 0.96 + 12 = 12.96

Answer:

[tex]C=59.6902604182[/tex]

Step-by-step explanation:

The formula to calculate the circumference of a circle given the diameter is:

[tex]C=\pi d[/tex]

Substitute and solve:

[tex]C=\pi \times19=59.6902604182[/tex]
[tex]C=59.6902604182[/tex]

Since the question doesn't say to round your answer is "59.6902604182."

Hope this helps.

The equation can be rewritten as: [tex]ax^4 = (log(6))(2^4)[/tex]

Therefore, [tex]a = log(6) \ and\ x=2[/tex]

A logarithm is a mathematical function that describes the relationship between a number and its exponent. It is the inverse operation of exponentiation. Logarithms are typically written as log base b, where b is the base of the logarithm and is a positive number.

The logarithm of a number x to base b is denoted as [tex]logb(x)[/tex] and it is the exponent to which we need to raise the base b in order to get the number x.

For example, if we are given [tex]log10(100) = 2[/tex], this means that [tex]10^2 = 100[/tex].

The equation [tex]6^x * 6 * 6[/tex] can be rewritten as [tex]6^x * 6^2[/tex].

To convert 6^x to ax form, we need to take the logarithm of both sides of the equation:

[tex]log(6^x) = log(6^2)[/tex]

And we can simplify the equation as:

[tex]xlog(6) = 2log(6)[/tex]

So, the value of a is log(6) and the value of x is 2.

Therefore, the equation can be rewritten as:

[tex]ax^4 = (log(6))(2^4)[/tex]

Therefore, [tex]a = log(6)\ and\ x=2[/tex]

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Therefore, since the area of room B is four times the area of room A, four boxes of tiles will be needed to complete the flooring of room B.

The area is the volume a flat, two-dimensional item occupies in a plane. The space occupied by a three-dimensional object is referred to as its volume. Area is measured in square units. Volume is measured in cubic units.

The area is the area occupied by a two-dimensional flat surface. It has a square unit of measurement. The surface area of a three-dimensional object is the space taken up by its outer surface.

Since the side lengths of room B are double the side lengths of room A, the area of room B is four times the area of room A.

The number of tiles needed to cover a floor is equal to the area of the floor divided by the area of each tile.

Since the boxes of tiles are identical, the number of tiles in each box must also be identical.

Therefore, since the area of room B is four times the area of room A, four boxes of tiles will be needed to complete the flooring of room B.

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The various statements regarding the given scatter plot is checked and found to be true or false.

What is a scatter plot?

A set of dots plotted on a horizontal and vertical axis is known as a scatter plot. Because they can demonstrate the degree of connection, if any, between the values of observed quantities.

1)The equation of the line is y = 2500x - 125.

From the graph we can take two points on the line,

( 2,2250) and ( 10,1250)

Standard equation of line is y = mx + b

where b is y - intercept and m is slope

m = [tex]\frac{y_{2} - y_{1} }{x_{2}-x_{1}}[/tex] = [tex]\frac{1250 - 2250}{10 - 2}[/tex] = -125

From graph, b = 2500

Equation of line is

y = -125x + 2500

Therefore the given equation is false.

2) The group of hikers descends about 250 feet every minute.

      From the graph it is evident that for the interval between two points on y-axis is 250 feet and interval of x-axis is 1 minute.

So the hikers descend 250 feet every minute.

Therefore the given statement is true.

3) The hikers began at the elevation of 2500 feet.

     The x-intercept of the graph is 2500 feet.

      So the beginning elevation is 2500 feet.

 Therefore the statement is true.

4) The graph shows a negative association.

Since the line in the graph is going down and the slope is negative, the graph shows a negative association.

Therefore the statement is true.

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