Answer:
The answer is "36 grams".
Explanation:
In this question, the weight of the ball is not mentioned but is the weight of the cookies is declared, which is equal to 36 grams, and all the cookies are squeezes into the ball and after that, it calculates the overall weight so, let assume that ball weight is =0 and then the overall weight is:
[tex]=\text{weight of ball + cookies weight}\\\\=0+36 \ grams \\\\=36 \ grams[/tex]
What is a material that electricity cannot flow through called?
Answer:
Things that electricity cant flow through are called insulators.
Now set the tension to low and wiggle the wrench to create more waves. Can you explain how moving the first point on the string, the one closest to the wrench, affects the next point on the spring? How does this fit with your understanding of the force of a stretched spring?
Answer:
When the string moves, it creates a very small change in the distance to the next point, th
Explanation:
When the string moves, it creates a very small change in the distance to the next point, this generates a restoring force that tends to push the string back, this small disturbance propagates along the string and is what creates the pulse.
This is similar to what happens when a spring is stretched and a restoring force is generated shaved by the law of shortening.
F = k Dx
Answer:
As the first particle travels upward, it pulls on the next particle, which follows the first particle upward. Then next in line is pulled up in turn, and so on. The motion of each particle follows the one before it, either up or down, with a slight lag in time. This succession of particles moving up or down travels along the string as a wave. Eventually, it pulls every particle along the string up and down in series.
Explanation:
Since the universe is infinite, the probability of events and reoccurrence is infinite. So that means that there is a chance, if not 100% chance, that SOMEWHERE there is another earth, with another you, living the same life, at the same time. What are your thoughts about this??? that's so crazy to me
Answer:
That insane it might be true because a planet sometimes quoted to be an Earth 2.0 or Earth's Cousin based on its characteristics; also known by its Kepler Object of Interest designation KOI-7016.01) is an exoplanet orbiting the Sun-like star Kepler-452 about 1,402 light-years (430 pc) from Earth in the constellation Cygnus.
Explanation:
find the odd one out: asteroids on the asteroid belt, a comet, the moon or Saturn
Answer:
Explanation:
A change in an object’s motion—such as Xander speeding up on his scooter—is called acceleration. Acceleration occurs whenever an object is acted upon by an unbalanced force. The greater the net force acting on the object, the greater its acceleration will be, but the mass of the object also affects its acceleration. The smaller its mass is, the greater its acceleration for a given amount of force. Newton’s second law of motion summarizes these relationships. According to this law, the acceleration of an object equals the net force acting on it divided by its mass.
The adult house fly lives for only about 1 month, or 8 x 10^-2 y. The oldest recorded age of a tortoise was 1.8800 x 10^2 y. What is the difference between these two ages?
187.92 years
8*10^-2= .08
1.88*10^2= 188
188-.08=187.92
calculate the ground pressure of a 90kg gas cylinder the diameter of the cylinder is 1.1 m
Answer:
P = 928.09 Pa
Explanation:
Given that,
Mass of a gas cylinder, m = 90 kg
The diameter of the cylinder, d = 1.1 m
Radius, r = 0.55 m
We need to find the ground pressure. The pressure is equal to force per unit area. So,
[tex]P=\dfrac{F}{A}\\\\P=\dfrac{mg}{\pi r^2}\ (A\ is\ area\ of\ base)\\\\P=\dfrac{90\times 9.8}{\pi \times (0.55)^2}\\\\P=928.09\ Pa[/tex]
So, the ground pressure is 928.09 Pa.
Calculate the wavelength of light that has a frequency of 5.2 x 1012 1/s.
Answer:
Wavelength = 5.77 * 10^-5 meters.
Explanation:
Given the following data:
Frequency of light = 5.2 *10^12 Hz
We know that the Speed of light = 3.0 * 10^8 m/s
To find the wavelength of light;
Mathematically, wavelength is calculated using this formula;
[tex] Wavelength = \frac {speed}{frequency} [/tex]
Substituting into the equation, we have;
[tex] Wavelength = \frac {3*10^{8}}{5.2 *10^{12}} [/tex]
Wavelength = 5.77 * 10^-5 meters.
Look at the image provided, it shows forces acting on a box.
What is the NET FORCE on the box?
If a person runs 68m in 8s, what is his speed?
Answer:
19.01396 mph.
Explanation:
A rock is thrown horizontally off a cliff with an initial velocity of 15 m/s. How high was the cliff if the rock lands 22 m from the base of the cliff?
Answer:
22 m
Explanation:
Answer:
cliff height = 10.55 m
Explanation:
Remarks
This is one of those questions that defies belief. The final vertical velocity is the same as if you just dropped the rock, which is amazing.Another amazing fact is that the horizontal speed has no acceleration. And amazing fact number three is the the vertical initial speed is 0.And finally, the time taken to go horizontally = time to go vertically.Solution
Time
So the time taken is d = r * t
Remember, this formula can only be used when there is no acceleration.
d = 22 meters
r = 15 m/s
t = ?
t = d / r
t = 22 / 15
t = 1.467
Height of the Cliff
vi = 0 (vertially)
a = 9.8 m/s^2
t = 1.467 seconds The time horizontally and vertically is the same.
d = ?
Formula
d = vi*t + 1/2 a t^2
Solution
d = 0 + 1/2 * 9.8 * 1.467^2
d = 10.55 meters.
If Calcium has 2 valence electrons and Chlorine has 7 valence electrons, how many Cl-1 ions would need to combine with 1 Ca+2 ion?
Answer:
CALCIUM IDENINE ADEININE AND PHOSPHATE
Explanation:
1. A truck of mass 3120 kg is accelerated from rest to a speed of 22.1 m/s. How much work was done on the truck to achieve that speed?
Answer:
.5(3120kg)(22.1m/s)^2 = 7.62x10^5 J
Explanation:
The work done on the truck to achieve given speed is [tex]7.62*10^{6}[/tex] Joules.
The work done on the truck is equivalent to the kinetic energy.
Work done = Kinetic energy = [tex]\frac{1}{2} mv^{2}[/tex]
Where m is mass of truck and v is final velocity of truck.
Given that, [tex]m=3120Kg,v=22.1m/s[/tex]
Substitute values in above equation
[tex]Workdone=\frac{1}{2}*3120*(22.1)^{2} \\\\Workdone=0.5*3120*488.41=7.62*10^{6} KJ[/tex]
Thus, The work done on the truck to achieve given speed is [tex]7.62*10^{6}[/tex] Joules.
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PLEASE PLEASE HELPPPP
Answer: 8 volt battery in each device.
I think the units is 7.
Explanation:
Help with physics please! Offering a bunch of points!
Meg has two glasses of grape juice. Glass A has 80 grams of juice at 30 °C. Glass B has 80 grams of juice at 50 °C.
Which of the following steps will make the kinetic energy of the molecules of the juice in both glasses equal?
Decrease the temperature of juice in Glass A by 20 °C
Increase the temperature of juice in Glass A by 20 °C
Decrease the temperature of juice in Glass B by 30 °C
Increase the temperature of juice in Glass B by 30 °C
Answer:
Increase the temperature of juice in Glass A by 20 °C
Answer:
lil baby
Explanation:
1. Any event or situation that evokes a response is a
a. positive reinforce
b. cognitive map
c. stimulus
d. model
stimulus. Because its the only thing I can really think of that evokes.
How would you describe your appetite over the past couple of weeks? Have your eating habits altered in any way?
Answer:
no im in a rehab program so we eat the sam shi every day
Explanation:
brainlest?
Explanation:
During lockdown, I ate LOADS OF JUNK FOOD. TRUST ME!!
I gained 14 kg of weight and became 68 kg
just due to junk food.I am 13 btw and at that time I was 5 feet 4 so definitely fat. all those pizzas and burgers and all.then I realised that I have gained weight. I have to REDUCE MY WEIGHT. I am quite determined on what I say. it took me 3 months or so and I finally got back to my original weight. How? just by going for a stroll everyday, eating healthy and constantly working out. eating less is not the solution,eating less calories is the solution.Also, by eating healthy food,I grew taller. I am 5 feet 6 now. So yes, definitely it helps put alot and keep eating healthy food and you will definitely be healthy.
Thank You.
How do the metal aluminum coils in an air conditioner help keep a house cool? They insulate the house from outside thermal energy. They conduct thermal energy from inside the house and release it outside the house. They insulate the surrounding air from indoor thermal energy. They conduct thermal energy from outside the house and release it inside the house.
Answer:
They conduct thermal energy from inside the house and release it outside the house.
Explanation:
An air conditioner works to by conducting thermal energy or heat from inside the house and releasing this heat energy outside the house, thus making inside of the house cooler than the outside.
Warm air from inside the house is circulated around the evaporator fins. The refrigerant liquid is made to pass through the evaporator coil made of aluminum ,where the coils exchanges the heat it absorbs from the air surrounding it with the refrigerant. Aluminum metal is used in making the evaporator coils because it is a good conductor of heat. The heat absorbed by the refrigerant coverts it to vapor, which is then reconverted into liquid by the condenser removing the heat absorbed from inside the outside by means of a fan. As the heat is removed from the air, the air is cooled and blown back inside the house. This process is repeated several times until the desired temperature is attained inside the house.
Answer:
B is the answer
Explanation:
pls give me brainliest
What changes into energy in the sun?
Answer:
The sun generates energy from a process called nuclear fusion. During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons. Hydrogen nuclei fuse to form one helium atom. During the fusion process, radiant energy is released. :D
Imagine that someone is walking across a carpeted room and then touches a metal doorknob. Describe what happens when a doorknob is touched if there’s a buildup of static electricity.
Answer: if the door knob is metal the static electricity will exit your body, but shock you in the process
Explanation:
May you please help me?
Answer:
The first one is 9 times the original
The second one is 1/2 times
The third one is 1/3 times
5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on
low-friction wheels and as the bullet struck the target, the target with
bullet embedded bullet sped off with a velocity of 6.0 ms.
Calculate the velocity of the bullet just before it hit the stationary
target.
Answer:
306 m/s
Explanation:
Law of conservation of momentum
m1v1 + m2v2 = (m1+m2)vf
m1 is the bullet's mass so it is 0.1 kg
v1 is what we're trying to solve
m2 is the target's mass so it is 5.0 kg
v2 is the targets velocity, and since it was stationary, its velocity is zero
vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s
plugging in, we get
(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)
(0.1)(v1) + 0 = 30.6
(0.1)(v1) = 30.6
v1 = 306 m/s
The initial velocity of the bullet can be determined from the total momentum of the system. The velocity of the bullet was 306 m/s.
What is momentum ?Momentum of a body is the product of its mass and velocity. For a collision, the momentum before and after collision will be the same for the colliding system.
Let m1 and m2 be the masses and u be the initial velocity and v is the final velocity.
then, m1 u1 + m2 u2 = m1 v1 + m2 v2.
Given m1 = 5 kg
m2 = 0.1 kg
The velocity of the combined mass v = 6 m/s.
The momentum of the target is zero since it was stationary.
(0.1 × u1) = (0.1 + 5)6 m/s
(0.1 × u1) = 30.6 m/s
then u1 = 30.6/0.1 = 306 m/s
Therefore, the velocity of the bullet before hitting was 306 m/s.
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If a bicycle travels 1200m, and it takes 300seconds, what is its speed in m/s.
An airplane moving horizontally at 150 m/s drops a package from an altitude is 490 m. How long does it
take the package to reach the ground? How far, horizontally, from the spot over which it was dropped
does the package land?
Answer:
640
Explanation:
cause you should just add the 2
It takes 10 second the package to reach the ground.
The package reaches the ground after 10 second and it was dropped 1500 m far from the package landing.
Given parameters:
Altitude of the plane; h = 490 m.
Initial horizontal velocity of the plane; u = 150 m/s.
We have to find; time taken by the package to reach the ground: t =?
And, horizontal distance covered by the package before land; d = ?
We know that a free falling object has acceleration equal to acceleration due to gravity = g = 9.8 m/s².
So,
h = 1/2gt²
⇒ t = √(2h/g) = √(2×490/9.8) second = 10 second.
In this time,
horizontal distance covered by the package before land; d = ut
= 150 m/s × 10 s
= 1500 m.
Hence, the package reaches the ground after 10 second and it was dropped 1500 m far from the package landing.
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what do fluorine, sodium, and aluminum have in common
How efficient is a pulley system if it enables you to lift a 700.0 Newton engine (Fr) 0.550 meters (dr) if you exerted 35.7 Newtons (Fe) of force while pulling 11.43 meters (de) of rope?
Answer:
96.3%
Explanation:
Efficiency = Work input/Work output * 100%
Work done = Force * distance\
Work done by the engine is the work output = 700 * 0.55
Work output = 423.5Nm
Work done by you is the work input = 35.7*11.43
Work input = 408.051Nm
Efficiency = 408.051/423.5 * 100
Efficiency = 0.963 * 100
Efficiency = 96.3%
Hence the efficiency of the pulley system is 96.3%
can someone help me please
1 HELP
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A box is connected to a spring is extended to 200mm, and it stored 3578J of energy. Find the
force.
Answer:
The force applied to the spring is 35,780 N
Explanation:
Given;
extension of the spring, x = 200 mm = 0.2 m
energy stored in the spring, E = 3578 J
The force applied to the spring is calculated as;
E = ¹/₂Fx
where;
F is the applied force
F = 2E/x
F = ( 2 x 3578) / 0.2
F = 35,780 N
Therefore, the force applied to the spring is 35,780 N
Which two statements are true about the wave shown?
A. The wave could be transmitting light. B. The wave is a transverse wave.
C. The wave is a mechanical wave.
D. The wave could be transmitting sound.
Answer:
c and d
Explanation:
The wave shown in the figure is Sound waves. The sound wave is a mechanical wave. Hence, options C and D are correct.
What are sound waves?Sound is traveled by means of vibrations of particles in the medium. Sound waves require a medium to propagate. The energy propagation by means of adiabatic loading and unloading is called sound or acoustic waves.
The sound waves produce compression and rarefaction in the air. The sound waves are called Longitudinal waves because the direction of propagation is parallel to the vibration of particles.
Sound waves are considered only as waves because they exhibit a wave nature. Light has both properties of wave and particle. Light is an electromagnetic wave and it is transverse in nature.
The sound waves require a medium like air, water, solids, etc for propagation. Hence it is called Mechanical waves. Light waves do not require a medium to propagate. From the given wave pattern, it exhibits the property of sound waves.
Hence, the correct option is C) the wave is a mechanical wave, and D) the wave could be transmitting sound.
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Un bloque de 3 kg en reposo se deja libre a una altura de 5 m sobre una rampa curva y sin rozamiento. Al pie de la rampa se encuentra un resorte de constante k = 400 N/m, como se muestra en la fig. El objeto desliza por la rampa y llega a chocar contra el resorte comprimiéndolo una distancia x antes de que quede en reposo momentáneamente. Determinar: a) La velocidad con la que el bloque alcanza al resorte. ____________________ b) La distancia x que el bloque comprime al resorte. __________________ c) La velocidad con la que el bloque es expulsado por el resorte. ____________________ d) La altura que alcanza sobre la parte curva. ________________ e) ¿Alcanzará la misma altura si la rampa no está libre de rozamiento? ___________________
Answer:
a) La velocidad del bloque cuando llega al resorte es de aproximadamente 9,9 m / s
b) La distancia a la que se comprime el resorte es de aproximadamente 0,86 m
c) La velocidad con la que el resorte expulsa el bloque es de aproximadamente 9,9 m / s
d) La altura que alcanza el bloque es de 5 metros.
e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción
Explanation:
a) Los parámetros dados del bloque son;
La masa del bloque, m = 3 kg
La altura a la que se coloca el bloque, h = 5 m
La constante de resorte, k = 400 N / m
La aceleración debida a la gravedad, g = 9,8 m / s²
La energía potencial de un cuerpo, P.E. = m · g · h
Por tanto, la energía potencial inicial del bloque, P.E. se da como sigue;
P.E. = 3 kg × 9,8 m / s² × 5 m = 147 julios
P.E. = 147 julios
La energía cinética del bloque al pie de la rampa, K.E. = 1/2 · m · v²
Dónde;
v = La velocidad del bloque cuando llega al resorte
Por lo tanto, para el bloque dado tenemos;
K.E. = 1/2 · m · v² = 1/2 × 3 kg × v²
Por el principio de conservación de la energía, tenemos;
El PE. del bloque en reposo a una altura de 5 m = La energía cinética al pie de la rampa. K.E.
∴ P.E. = K.E.
147 J = 1/2 × 3 kg × v²
v² = 147 J / (1/2 × 3 kg) = 98 m² / s²
v = √ (98 m² / s²) = 7 · √2 m / s
v = 7 · √2 m / s ≈ 9,9 m / s
b) La energía recibida por el resorte comprimido, E = 1/2 · k · x²
Dónde;
k = La constante del resorte = 400 N / m
x = La distancia a la que se comprime el resorte
Por el principio de conservación de la energía, tenemos;
La energía recibida por el resorte comprimido, E = La energía potencial inicial del resorte, P.E.
∴ E = 1/2 · k · x² = P.E.
De lo que tenemos;
E = 1/2 × 400 N / m × x² = 147 julios
x² = 147 Julios / (1/2 × 400 N / m) = 0,735 m²
x = √ (0,735 m²) = 0,7 · √ (3/2) m ≈ 0,86 m
La distancia a la que se comprime el resorte = x ≈ 0.86 m
c) La velocidad con la que el resorte expulsa el bloque se indica a continuación;
La energía en el resorte = 1/2 · k · x² = La energía cinética dada al bloque, 1/2 · m · v²
∴ 1/2 · k · x² = 1/2 · m · v²
∴ La velocidad con la que el bloque es expulsado por el resorte, v = La velocidad con la que el bloque llega al resorte = 7 · √2 m / s
La velocidad con la que el resorte expulsa el bloque, v = 7 · √2 m / s ≈ 9,9 m / s
d) La altura que alcanza el bloque también viene dada por la siguiente relación anterior;
P.E. = K.E.
∴ m · g · h = 1/2 · m · v²
v = 7 · √2 m / s
De donde tenemos h = La altura inicial del bloque en la rampa = 5 metros
e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción porque se utilizará energía para superar la fuerza de fricción
a) La velocidad final del bloque es aproximadamente 9.903 metros por segundo.
b) El resorte se deforma 0.858 metros.
c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.
d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).
a) Conforme a la situación de este problema, la energía cinética traslacional final ([tex]K[/tex]), en joules, es igual a la energía potencial gravitacional inicial ([tex]U[/tex]), en joules.
[tex]U = K[/tex] (1)
Por las definiciones de las energías cinética traslacional y potencial gravitacional expandimos la ecuación anterior:
[tex]m\cdot g\cdot h = \frac{1}{2}\cdot m\cdot v^{2}[/tex] (1)
Ahora despejamos la velocidad de esa ecuación:
[tex]v = \sqrt{2\cdot g\cdot h}[/tex]
Donde:
[tex]m[/tex] - Masa del bloque, en kilogramos.[tex]g[/tex] - Aceleración gravitacional, en metros por segundo al cuadrado.[tex]h[/tex] - Altura inicial del bloque, en metros.[tex]v[/tex] - Velocidad final del bloque, en metros por segundo.Si sabemos que [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] y [tex]h = 5\,m[/tex], entonces la velocidad final del bloque es:
[tex]v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}[/tex]
[tex]v\approx 9.903\,\frac{m}{s}[/tex]
La velocidad final del bloque es aproximadamente 9.903 metros por segundo.
b) Por el principio de conservación de la energía, la energía cinética traslacional inicial es igual a la energía potencial elástica final, cuyas fórmula es la siguiente:
[tex]\frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}[/tex] (2)
Where:
[tex]k[/tex] - Constante de resorte, en newtons por metro.[tex]x[/tex] - Deformación del resorte, en metros.Ahora despejamos la deformación del resorte:
[tex]x = \sqrt{\frac{m}{k} }\cdot v[/tex] (3)
Si sabemos con [tex]k = 400\,\frac{N}{m}[/tex], [tex]m = 3\,kg[/tex] y [tex]v \approx 9.903\,\frac{m}{s}[/tex], entonces la deformación del resorte es:
[tex]x = \sqrt{\frac{3\,kg }{400\,\frac{N}{m} } }\cdot \left(9.903\,\frac{m}{s} \right)[/tex]
[tex]x \approx 0.858\,m[/tex]
El resorte se deforma 0.858 metros.
c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.
d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).
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