Samir had 30 dollars to spend on 3 gifts. He spent 9
9
10
dollars on gift A and 5
3
5
dollars on gift B. How much money did he have left for gift C?

Answers

Answer 1

Answer:

Gift 1 ($9) Gift 2 ($10)

Step-by-step explanation:

First we know that Samir had 30 dollars to spend on 3 gifts. If he bought gift 1 for $9, and gift 2 for $10. Then Samir should have $11 for gift 3 that he can spend.

9+10=$19,  $30-19=$11 Hope This helps! Mark Brainllest if it is correct!

Answer 2

Hence, the money did he have left for gift C is [tex]15.5[/tex].

What is the simplification?

Simplification is the process of replacing a mathematical expression by an equivalent one, that is simpler (usually shorter), for example Simplification of a fraction to an irreducible fraction.

Here given that,

Samir had [tex]30[/tex] dollars to spend on [tex]3[/tex] gifts. He spent  [tex]9.\frac{9}{10}[/tex] dollars on gift A and  [tex]4.\frac{3}{5}[/tex]  dollars on gift B.

So,

[tex]A=9.\frac{9}{10}\\\\A=\frac{90+9}{10}\\\\A=\frac{99}{10}\\\\A=9.9[/tex]

[tex]B=4.\frac{3}{5}\\\\B=\frac{20+3}{5}\\\\B=\frac{23}{5}\\\\B=4.6[/tex]

To find out the money did he have left for gift C is

[tex]A+B+C=G[/tex]

Here,

[tex]A=9.9\\B=4.6\\G=30[/tex]

Then,

[tex]9.9+4.6+C=30\\\\C=30-9.9-4.6\\\\C=30-14.5\\\\C=15.5[/tex]

Hence, the money did he have left for gift C is [tex]15.5[/tex].

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Answers

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