Mathematics College

Scores on a final exam in a large class were normally distributed with a mean of 75 and a standard deviation of 8. What percent of the students scored above an 83?

Answers

Answer 1

Using z - score, the percentage of students above 83 is 15.9%

What is the percentage of students that scored above 83?

To find the number of students that scored above 83 can be calculated using z - score formula.

This is given as

z = x - μ / σ

μ = meanσ = standard deviationx = score

Substituting the values into the formula;

z = 83 - 75 / 8

z = 1

The z-score is 1

Let's find the percentage of z -score under the score

p(x > 83) = 1 - P(x < 83) = 0.15866

p = 15.9%

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Related Questions

A study of religious practices among college students interviewed a sample of 125
students; 105
of the students said that they prayed at least once in a while. What is the sample proportion who said they pray?


0.84

1.19

105

84

Answers

The sample proportion who said they pray is approximately 0.84, or 84%.

How to solve for the sample proportion

The sample proportion of college students who said they pray can be calculated by dividing the number of students who said they pray (105) by the total number of students in the sample (125).

Sample proportion = Number of students who said they pray / Total number of students in the sample

Sample proportion = 105 / 125

Sample proportion = 0.84

Therefore, the sample proportion who said they pray is approximately 0.84, or 84%.

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The dosage the pharmacy carries in stock (on hand), is different than the prescribers order. Use ratio and proportion to calculate the total quantity of tablets to dispense for each of the prescriptions below: Order: Zocor 40 mg po qd for 60 days On hand: 20 mg tabs How many 20 mg tabs should be given? Give:

Answers

Using ratios and proportions, the number of 20 mg tabs that should be given in place of 40 mg po qd for 60 days is 120 tabs.

How the number is determined:

Using ratios and proportions, the number of tabs of 20 mg that should be given in place of 40 mg qd for 60 days is determined as follows:

Order: Zocor 40 mg po qd for 60 days

= 60 tabs since it is once per day (qd)

Total mg = 2,400 mg (40 mg x 60 tabs)

On hand: 20 mg tabs

Proportionately, 20 mg = 120 tabs (2 x 60) since 40 mg is for 60 tabs

Total mg = 2,400 mg (20 mg x 120 tabs)

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help me please!! I’m not quite sure how to solve this so explanations for this will be appreciated

Answers

The solution is:

the area of this figure is 21.9 ft².

Here, we have,

To find the area of this figure, we must find the area of the 6 x 6 square and subtract the area of a semi-circle with a diameter of 6.

Area square:

6 x 6

36

Area semi-circe:

A = 1/2(πr²)

A = 1/2(6/2)²π

A = 1/2(9π)

A = 14.1

Area shape:

36 - 14.1

21.9

The units are ft², so the answer is 21.9 ft².

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A golf ball rolls at a speed of 8 m/s for 12 seconds. Mandy hits the golf ball and it rolls
for 16 seconds at a speed of 12 m/s. What is the total distance travelled by the golf ball?

Answers

Using the given information, the total distance travelled by the golf ball is 288 m

Calculating the total distance travelled by the golf ball

From the question, we are to calculate the total distance travelled by the golf ball

The distance travelled by the golf ball can be calculated by using the formula,

Distance = Speed × Time

From the given information,

The golf ball rolls at a speed of 8 m/s for 12 seconds

Thus,

The distance travelled at this time is

Distance = 8 m/s × 12 s

Distance = 96 m

Also,

Mandy hits the golf ball and it rolls for 16 seconds at a speed of 12 m/s

The distance travelled at this time is

Distance = 12 m/s × 16 s

Distance = 192 m

The total distance travelled by the golf ball is 96 m + 192 m

=

Hence, the total distance travelled by the golf ball is 288 m

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URGENT HELP PLEASE!!!


In a class of students, the following data table summarizes how many students have a
a
cat or a dog. What is the probability that a student chosen randomly from the class
has a cat and a dog?

Answers

Answer: 5/13

Step-by-step explanation:

To solve this problem, we can use the formula for conditional probability:

P(A|B) = P(A and B) / P(B)

where P(A and B) is the probability of both events A and B happening, and P(B) is the probability of event B happening.

Let's first calculate the total number of people in the class:

Total number of people = 5 + 6 + 2 + 11 = 24

Now, let's calculate the probability of having a cat and a dog:

P(cat and dog) = 5 / 24

Next, let's calculate the probability of having a cat:

P(cat) = (5 + 6 + 2) / 24 = 13 / 24

Finally, let's calculate the probability of having no dog:

P(no dog) = (6 + 11) / 24 = 17 / 24

Using the formula for conditional probability, we can calculate the probability of having both a cat and a dog given that a person has a cat:

P(cat and dog | cat) = P(cat and dog) / P(cat) = (5 / 24) / (13 / 24) = 5 / 13

Therefore, the probability that a student chosen randomly from the class has a cat and a dog is 5/13.

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