Select the reasons why gases deviate from ideal behavior at extremes of pressure and temperature. Select all that apply.

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Answer:

See explanation.

Explanation:

Hello!

In this case, when having the cationic and anionic species with the specified charges, in order to abide by the net charge rule, we need to exchange the charges in the form of subscripts and without the sign, just as shown below:[tex]X^{m+}Y^{n-}\rightarrow X_nY_m[/tex]

Thus, for all the given combinations, we obtain:

- Y⁻

[tex]X^+Y^-\rightarrow XY\\\\X^{2+}Y^-\rightarrow XY_2\\\\X^{3+}Y^-\rightarrow XY_3[/tex]

- Y²⁻

[tex]X^+Y^{2-}\rightarrow X_2Y\\\\X^{2+}Y^{2-}\rightarrow X_2Y_2\rightarrow XY\\\\X^{3+}Y^{2-}\rightarrow X_2Y_3[/tex]

- Y³⁻

[tex]X^+Y^{3-}\rightarrow X_3Y\\\\X^{2+}Y^{3-}\rightarrow X_3Y_2 \\\\X^{3+}Y^{3-}\rightarrow X_3Y_3\rightarrow XY[/tex]

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Answer:

Terbium

Explanation:

Answer:

[tex]\Delta S_{sys}=0.020kJ=20J[/tex]

Explanation:

Hello!

In this case, given the required energy to vaporize 1.00 mol of ethanol as the enthalpy of vaporization:

[tex]\Delta H_{vap}=\frac{38.6kJ}{1.00mol}=38.6kJ/mol[/tex]

We can compute the entropy of the system for the vaporization of 8.00 g of ethanol, by first computing the moles:

[tex]n_{et}=8.00g*\frac{1mol}{46.07g} =0.174mol[/tex]

And then setting up the following expression:

[tex]\Delta S_{sys}=\frac{n_{et}*\Delta H_{vap}}{T}[/tex]

Whereas the temperature is in kelvins; thus, we obtain:

[tex]\Delta S_{sys}=\frac{0.174mol*38.6\frac{kJ}{mol} }{79.6+273.15K}\\\\\Delta S_{sys}=0.020kJ=20J[/tex]

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The entropy of the system ([tex]\Delta S_{sys}[/tex]) for the vaporization of 8.00 grams of ethanol at 79.6 °C is 0.0190 kilojoules.

Given the following data:

Conversion:

Temperature = [tex]79.6 + 273 = 352.6 \;K[/tex]

To find the entropy of the system ([tex]\Delta S_{sys}[/tex]) for the vaporization of 8.00 grams of ethanol at 79.6 °C:

First of all, we would determine the heat of vaporization.

[tex]Heat\; of \;vaporization = \frac{Energy}{moles} \\\\Heat\; of \;vaporization = \frac{38.6}{1}[/tex]

Heat of vaporization = 38.6 kJ/mol.

Next, we would determine the number of moles in 8.00 grams of ethanol:

[tex]Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{8}{46.07}\\\\Number\;of\;moles = 0.1737 \;moles[/tex]

Mathematically, the entropy of a system ([tex]\Delta S_{sys}[/tex]) is given by the formula:

[tex]\Delta S_{sys} = \frac{n\Delta H }{T}[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]\Delta S_{sys} = \frac{0.1737 \times 38.6 }{352.6}\\\\\Delta S_{sys} = \frac{6.7048 }{352.6}\\\\\Delta S_{sys} = 0.0190 \;kJ[/tex]

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Answer:

Decreasing the volume of solvent in the solution of molecule A

Explanation:

We know that one of the factors that affect the rate of reaction is the concentration of the reactants. The greater the concentration of reactants, the faster the rate of reaction (the greater the frequency of collision between reactants).

Hence, when we decrease the volume of solvent in the solution of molecule A, the concentration of the solution increases and consequently more particles of molecule A are available to collide with particles of molecule B resulting in a higher rate of reaction.

Answer is B

A mixture means two compounds mixed together but not atomically. For example, sand and water solution. A water with sand mixed inside is a mixture because the sand can be separated by physical means.

Water is H2O. This means it is a compound, because hydrogen and oxygen is bonded together atomically. Hydrogen however is an element, because you can't seperate it anymore (You could seperate it in the sense of protons and neutrons, but the definition of element is something you can see on the periodic table)

Compound means more than one element bonded together.

The sample must be a compound because it couldn't be seperated by physical means but can be seperated by chemical means into three pure substances (synonym of element)

Answer:

Sn(s) + MgBr2(aq) --> SnBr2(aq) + Mg(s)

Explanation:

Decide whether a chemical reaction happens in either of the following situations.

- A reaction happens. The type of this reaction is the single replacement reaction.

If a reaction does happen, write the chemical equation for it.

Sn(s) + MgBr2(aq) --> SnBr2(aq) + Mg(s)

Answer:

it is directly proportional to the temperature of the gas

Explanation:

Answer:

Remain unchanged.

Explanation:

The total number of moles of liquid remain unchanged as the some moles of species B are added to the system because specie B that is added in the liquid phase is again restored after addition. If the specie B did not restored after addition to the liquid phase so the total number of moles increases in the liquid phase so that's why we can say that the liquid phase remain unchanged.

Answer:

C . Air resistance

Explanation:

Answer:

Gravity (D)

Explantion:

The more mass the more gravitational force

the more distance the less gravitational force

Answer:

D i took it aswell

Explanation:

The energy the molecules must have in order to react. Hence, option D is correct.

Activation energy is the sufficient amount of energy necessary to initiate a chemical reaction.

It can also be said as the minimum amount of energy needed to energize molecules or atoms so that they can undergo a chemical reaction or transformation.

Hence, the energy the molecules must have in order to react.

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Answer:

%N = 25.94%

%O = 74.06%

Explanation:

Step 1: Calculate the mass of nitrogen in 1 mole of N₂O₅

We will multiply the molar mass of N by the number of N atoms in the formula of N₂O₅.

m(N): 2 × 14.01 g = 28.02 g

Step 2: Calculate the mass of oxygen in 1 mole of N₂O₅

We will multiply the molar mass of O by the number of O atoms in the formula of N₂O₅.

m(O): 5 × 16.00 g = 80.00 g

Step 3: Calculate the mass of 1 mole of N₂O₅

We will sum the masses of N and O.

m(N₂O₅) = m(N) + m(O) = 28.02 g + 80.00 g = 108.02 g

Step 4: Calculate the percent composition  of N₂O₅

We will use the following expression.

%Element = m(Element)/m(Compound) × 100%

%N = m(N)/m(N₂O₅) × 100% = 28.02 g/108.02 g × 100% = 25.94%

%O = m(O)/m(N₂O₅) × 100% = 80.00 g/108.02 g × 100% = 74.06%

Answer:

B bone marrow

Explanation:

I hope it will help

Answer:

There are 0.5 moles

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number  of particles.

To calculate the moles, we use the equation:

Thus there are 0.5 moles

Explanation:

Ammonia chemical formula : NH3

Ammonia molar mass : 14 + (1×3) = 17

Mass = Mol × mm

= 3.5mol × 17 = 59.5g

See pic for formula

nvm i think your question is incomplete. pls report my answer i thought u are asking the mass of ammonia

Answer:

98.68%

Explanation:

Step 1: Write the balanced equation

KBr + AgNO₃ ⇒ AgBr + KNO₃

Step 2: Calculate the moles corresponding to 814.5 mg (0.8145 g) of AgBr

The molar mass of AgBr is 187.77 g/mol.

0.8145 g × 1 mol/187.77 g = 4.338 × 10⁻³ mol

Step 3: Calculate the moles of KBr needed to produce 4.338 × 10⁻³ moles of AgBr

The molar ratio of KBr to AgBr is 1:1. The moles of KBr needed are 1/1 × 4.338 × 10⁻³ mol = 4.338 × 10⁻³ mol.

Step 4: Calculate the pure mass corresponding to 4.338 × 10⁻³ moles of KBr

The molar mass of KBr is 119.00 g/mol.

4.338 × 10⁻³ mol × 119.00 g/mol = 0.5162 g

Step 5: Calculate the purity of KBr

0.5162 g of KBr are in a 0.5231 g-sample. The purity of KBr is:

P = 0.5162 g/0.5231 g × 100% = 98.68%

Answer:

[tex]V_B = 18.3mL[/tex] -- Volume of base used

[tex]M_B = 0.0175M[/tex] --- Molarity of base

Explanation:

Given

[tex]V_A = 20mL[/tex] -- Volume of acid used

[tex]V_B_1 = 18.6mL[/tex] --- Buret Initial reading

[tex]V_B_2 = 36.9mL[/tex] --- Buret Final reading

[tex]M_A = 0.016M[/tex] --- Molarity of the acid

Solving (a): Volume of base used (VB)

This is calculated by subtracting the initial reading from the final reading of the base buret.

i.e.

[tex]V_B = V_B_2 - V_B_1[/tex]

[tex]V_B = 36.9mL - 18.6mL[/tex]

[tex]V_B = 18.3mL[/tex]

Solving (b): Molarity base (MB)

This is calculated using:

[tex]M_A * V_A = M_B * V_B[/tex]

Make MB the subject

[tex]M_B = \frac{M_A * V_A }{V_B}[/tex]

This gives:

[tex]M_B = \frac{0.016M *20mL}{18.3mL}[/tex]

[tex]M_B = \frac{0.016M *20}{18.3}[/tex]

[tex]M_B = \frac{0.32M}{18.3}[/tex]

[tex]M_B = 0.0175M[/tex]

Solving (c): There is no such thing as average molarity

Answer:

Explanation:

From the information given:

The Chemical equation is:

[tex]SO_2Cl_{2(g)} \iff SO_{2(g)} + Cl_{2(g)}\\[/tex]

since 43.6% of the initial concentration remains at equilibrium

Then; the amount of [tex]SO_2Cl_2[/tex] that is being reacted is:

= 0.543 × (100 -43.6)%

= 0.306 M

The ICE table can be computed as follows:

           [tex]SO_2Cl_2[/tex]               ⇔           [tex]SO_{2(g)[/tex]           +             [tex]Cl_{2(g)[/tex]

I            0.543                                    0                           0

C          0.306                                 +0.306                     0.306

E           0.237                                  0.306                      0.306

[tex]K_c = \dfrac{[SO_2] [Cl_{2}]}{[SO_2Cl_2]}[/tex]

[tex]K_c = \dfrac{0.306 \times 0.306}{0.237}[/tex]

[tex]K_c = 0.995[/tex]

Thus; the concentration at equilibrium for the species are:

[tex]SO_2Cl_2[/tex]  = 0.237 M

[tex]SO_{(2g)[/tex] = 0.306 M

[tex]Cl_{2(g)[/tex] = 0.306 M

Answer:

1. x=-2

2. x=65/27

3. x=37/3

Explanation:

Isolate x

1. Divide by 5: 2x+15=11

2x=11-15

x=-2

2. Distribute: 54x+36=166

54x=166-36

x=130/54

Simplify by dividing by 2: x=65/27

3. Distribute: 24x+60=356

24x=356-60

x=296/24

Simplify by dividing by 8: x=37/3

Answer:

Carbon dioxide becomes a poisonous gas when there is too much of it in the air you breathe. Besides the effects it can have on the planet and the atmosphere, carbon dioxide poisoning can lead to central nervous system damage and respiratory deterioration in humans and other breathing creatures.

Answer:

Carbon dioxide becomes a poisonous gas when there is too much of it in the air you breathe. Besides the effects it can have on the planet and the atmosphere, carbon dioxide poisoning can lead to central nervous system damage and respiratory deterioration in humans and other breathing creatures.

Explanation:

Hope This Helps! [ :

Answer:

d. Although the hydrolysis of ATP is thermodynamically favorable, without a catalyst the reaction occurs at a very slow rate because it has a large activation energy.

Explanation:

Hello!

In this case, since negative Gibbs free energies of reaction stand for thermodynamically favored processes, we can immediately rule out choices a. and b.

Moreover, since the reaction is slow without the presence of a catalyst, which the context of biochemistry is an enzyme, we infer that correct choice is d. Although the hydrolysis of ATP is thermodynamically favorable, without a catalyst the reaction occurs at a very slow rate because it has a large activation energy because the higher the activation energy the slower the reaction according to the Arrhenius equation.

Best regards!

Answer:

number 2

Explanation:

even though i have never done this i still got it right

Because metals do not form covalent bonds, when naming covalent bonds, all the given rules apply except write the metal first; option 4.

Covalent bonds are bonds formed by the sharing of valence electrons between the atoms involved in the bonding.

In naming covalent bonds, the following rules are applied:

For example, CO₂, is carbon dioxide.

Therefore, when naming covalent bonds, all the given rules apply except write the metal first because metals do not form covalent bonds.

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Answer:

a, d

Explanation:

a. The pressure in the container will be 42.8 mm Hg.

d. Some of the vapor initially present will condense.

Answer:ok so When heat is added to a substance, the molecules and atoms vibrate faster. As atoms vibrate faster, the space between atoms increases. The motion and spacing of the particles determines the state of matter of the substance. The end result of increased molecular motion is that the object expands and takes up more space.

hope this helps have a nice day❤️

Explanation:

Answer:

i think the answer is b temperature

Answer:

no

Explanation:

Answer: The mass of [tex]CO_2[/tex] and [tex]H_2O[/tex] produced are 336.6 g and 183.6 g respectively.

Explanation:

The combustion reaction between propane and oxygen leads to formation of carbon dioxide and water.

Law of Conservation of mass states that the mass will remain constant for a balanced equation. This is carried out when the total number of atoms on reactant side is same as the total number of atoms on the product side. Thus the equation must be balanced.

[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]

a) 1 mol of propane produces = 3 moles of [tex]CO_2[/tex]

Thus 2.55 mol of propane produces = [tex]\frac{3}{1}\times 2.55=7.65 moles of [tex]CO_2[/tex]

mass of [tex]CO_2=moles\times {\text {molar mass}}=7.65mol\times 44g/mol=336.6g[/tex]

b) 1 mol of propane produces = 4 moles of [tex]H_2O[/tex]

Thus 2.55 mol of propane produces = [tex]\frac{4}{1}\times 2.55=10.2 moles of [tex]H_2O[/tex]

mass of [tex]H_2O=moles\times {\text {molar mass}}=10.2mol\times 18g/mol=183.6g[/tex]

The mass of [tex]CO_2[/tex] and [tex]H_2O[/tex] produced are 336.6 g and 183.6 g respectively.

Answer: a)  The maximum mass of sulfur trioxide that can be formed is 31.4 grams

b) The FORMULA for the limiting reagent is [tex]O_2[/tex]

c) Mass of excess reagent remains is 4.8 grams

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} SO_2=\frac{29.9g}{64g/mol}=0.467moles[/tex]

[tex]\text{Moles of} O_2=\frac{6.26g}{32g/mol}=0.196moles[/tex]

[tex]2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)[/tex]  

According to stoichiometry :

1 mole of [tex]O_2[/tex] require = 2 moles of [tex]SO_2[/tex]

Thus 0.196 moles of [tex]O_2[/tex] will require=[tex]\frac{2}{1}\times 0.196=0.392moles[/tex]  of [tex]SO_2[/tex]

Thus [tex]O_2[/tex] is the limiting reagent as it limits the formation of product and [tex]SO_2[/tex] is the excess reagent as (0.467-0.392) = 0.075 moles or [tex]0.075mol\times 64g/mol=4.8g[/tex] are left.  

As 1 mole of [tex]O_2[/tex] give = 2 moles of [tex]SO_3[/tex]

Thus 0.196 moles of [tex]O_2[/tex] give =[tex]\frac{2}{1}\times 0.196=0.392moles[/tex]  of [tex]SO_3[/tex]

Mass of [tex]SO_3=moles\times {\text {Molar mass}}=0.392moles\times 80g/mol=31.4g[/tex]

Thus 31.4 g of [tex]SO_3[/tex] will be produced from the given masses of both reactants.