SEP Interpret Data The table shows the atomic radi and balline
points of five halogens that experience intermolecular disea
forces. Plot the boiling point vs the atomic radius was the
resulting pattern to predict the boiling point
of astatine.

Answers

Answer 1

The table shows that as the atomic radius grows, the boiling points of the halogens rise. This implies that the intensity of the intermolecular interactions between the atoms and the size of the halogen atom are related.

Because astatine has a bigger atomic radius than iodine, we can infer from this pattern that it will have a higher boiling point.

Atomic radiusThe attractive forces that occur between molecules are known as intermolecular forces. The sort of molecules involved, as well as their size, shape, and polarity, all affect how strong these forces are. Intermolecular forces are often stronger for bigger molecules and molecules with more polarity.The cause of this pattern is that the distance between the atoms in a molecule rises along with the size of the halogen atom. The London dispersion forces between the molecules become stronger as a result. These forces are a result of the transient dipoles formed as electrons move about in the atom's or molecule's electron cloud.

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Related Questions

How many moles of NH3 is produced from 4.8 mol of H₂
N₂ + 3H₂ = 2NH3
How much hydrogen (in kg) is needed to yield 907 kg of ammonia by the Haber process?

Answers

From the balanced equation, we know that 3 moles of H₂ produces 2 moles of NH₃.Therefore, to find the moles of NH₃ produced from 4.8 moles of H₂, we can set up a proportion 3 moles H₂ / 2 moles NH₃ = x moles H₂ / 4.8 moles H₂.

What is a moles ?

In chemistry, mole is a unit of measurement used to express amounts of a chemical substance. It is defined as the amount of a substance that contains the same number of entities (such as atoms, molecules, or ions) as there are in 12 grams of pure carbon-12, which is approximately 6.022 x 10^23 entities. This number is known as Avogadro's number, and it is a fundamental constant in chemistry.

Moles are used to quantify chemical reactions and calculate the amount of reactants needed to produce a certain amount of product, or the amount of product that can be obtained from a given amount of reactants.

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Devise a 6-step synthesis of a carboxylic acid from ethyne using the reagents provided. 1. reagent 1 4. reagent 4 2. reagent 2 5. reagent 5 3. reagent 3 6. reagent 6 H-CEC-H OH Reagent 1 is: Reagent 2 is: Reagent 3 is: Reagent 4 is: Reagent 5 is: Reagent 6 is:

Answers

6-step synthesis of a carboxylic acid.

Reagent 1 forming a vinyl chloride, Reagent 2 forming an acyl chloride, Reagent 3 forming a carbonyl chloride, Reagent 4 forming a carboxylic acid,  Reagent 5 forming a carboxylate anion and Reagent 6 forming the desired carboxylic acid

This question requires a 6-step synthesis of a carboxylic acid from ethyne using the reagents provided. Here is the solution:

Reagent 1 (HCl) is added to ethyne (H-CEC-H), forming a vinyl chloride.Reagent 2 (Hg(OAc)2) is then added to the vinyl chloride, forming an acyl chloride.Reagent 3 (H2O2) is then added to the acyl chloride, forming a carbonyl chloride.Reagent 4 (K2Cr2O7) is then added to the carbonyl chloride, forming a carboxylic acid.Reagent 5 (NaOH) is then added to the carboxylic acid, forming a carboxylate anion.Finally, Reagent 6 (H2SO4) is added to the carboxylate anion, forming the desired carboxylic acid (OH).

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a burette has an initial reading of 3.50 ml. an experimenter opens the stopcock and after some time closes it recording a new burette reading of 12.75 ml. the experimenter repeats this two more times recording new readings of 15.60 ml and 17.25 ml. what is the total ml of titrant that has been dispensed from the burette.

Answers

The total volume (in ml) of the titrant that has been dispensed from the burette is 13.75 ml.

What is a burette?

A burette is a laboratory apparatus that is used in analytical chemistry to dispense a liquid reagent in a precise and controlled volume to conduct experiments. It consists of a graduated glass tube with a stopcock at the bottom and a funnel at the top that is attached to a burette stand.

Titrant refers to a solution of known concentration that is slowly added to a solution of unknown concentration until a reaction has been completed. When the reaction has been completed, the amount of titrant that has been added is calculated from the burette readings and used to determine the concentration of the unknown solution given that the reaction equation is known.

Here, initial burette reading (Vi) = 3.50 ml, final burette reading (Vf) after first addition = 12.75 ml

Volume of titrant used in the first addition = Vf - Vi = 12.75 ml - 3.50 ml = 9.25 ml

Final burette reading (Vf) after second addition = 15.60 ml

Volume of titrant used in the second addition = Vf - Vi = 15.60 ml - 12.75 ml = 2.85 ml

Final burette reading (Vf) after third addition = 17.25 ml

Volume of titrant used in the third addition = Vf - Vi = 17.25 ml - 15.60 ml = 1.65 ml

The total volume of titrant that has been dispensed from the burette is the sum of the volume of titrant used in all three additions. Therefore, Total volume of titrant = Volume of titrant in first addition + Volume of titrant in second addition + Volume of titrant in third addition= 9.25 ml + 2.85 ml + 1.65 ml= 13.75 ml

Hence, the total ml of titrant that has been dispensed from the burette is 13.75 ml.

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In Part A of this Experiment, which direction did the equilibrium shift when water was added? Explain what caused this shift. Keep in mind that water is not included in the K expression. It may be helpful to examine the hydrolysis of the SbCl3 in your lab manual. K is the equilibrium constant Q Is the reaction quotient Equilibrium shifts remains the same; Q=K Equilibrium shifts in the reverse direction; Q K. The equilibrium shifts in the direction with more moles of aqueous products O Equilibrium shifts in the forward direction; Q< K. The equilibrium shifts in the direction with more moles of aqueous products o Equilibrium shifts in the reverse direction; Q > K. The equilibrium shifts in the direction with less moles of aqueous products

Answers

Equilibrium shifts in the forward direction; Q< K. The equilibrium shifts in the direction with more moles of aqueous products.

How do you know the direction of equilibrium shift?

The direction of an equilibrium shift can be predicted by applying Le Chatelier's principle, which states that when a system at equilibrium is subjected to a stress, the system will shift in a direction that counteracts the stress.

The direction of an equilibrium shift depends on the nature of the stress and the equilibrium constant of the reaction. The equilibrium constant can be used to determine the relative concentrations of the reactants and products at equilibrium, and can also be used to calculate the equilibrium concentrations of the species at a given set of conditions.

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Identify and check the number of stereoisomers expected for each of the following: A. option. B. option. C. option. D. option.

Answers

X = 2n, where n is the number οf stereο genic atοms in the mοIecuIe, is the fοrmuIa fοr determining the maximum number οf stereοisοmers.

Hοw many stereοisοmers are pοssibIe fοr ?`

The fοrmuIa X = 2n cοnsistentIy deIivers the maximum number οf stereοisοmers, but it faiIs tο prοduce the true number in circumstances with great symmetry. If a mοIecuIe cοntains twο stereοcenters, it shοuId have fοur stereοisοmers. If a mοIecuIe cοntains three stereοcenters, it shοuId have nο mοre than eight stereοisοmers.

Thus, fοr a given cοmpοsitiοn, the maximum number οf stereοisοmers is 2n, where n is the number οf chiraI centers. Therefοre there are fοur structuraI isοmers and fοur stereοisοmers. As a resuIt, οptiοn 'D' is the right answer. Chain isοmerism is a sοrt οf structuraI isοmerism in which the cοmpοnents οf these isοmers are branched in distinct ways.

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In  which way the Chain isomerism is a sort of structural isomerisam  andd what are the components of these isomers ?

Which of the following foods are complete proteins?a. bread and butterb. animal foods quinoa, or soyc. almonds, peanuts, or cashewsd. potato and sour cream

Answers

the answer would be B. animal foods, quinoa,or soy.

Below you will see the election transmission of hydrogen atoms which of do you think represents the low frequency protons emissions.

Answers

The highest frequency of the lines that we have in the hydrogen atom will be line D

Is frequency inversely related to wavelength?

Frequency is inversely related to wavelength. The wavelength and frequency of a wave are related by the equation:

c = λf

where c is the speed of light, λ (lambda) is the wavelength of the wave, and f is the frequency of the wave. This equation is known as the wave equation.

If the wavelength of a wave increases, then the frequency of the wave must decrease to maintain the same speed. Conversely, if the wavelength of a wave decreases

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what is the expected color of the starch complex formed during this experiment?(A) The.correct answer is not shown. (B) orange-red (C) green (D) blue-black (E) yellow

Answers

When starch is treated with iodine solution, its color changes to Blue-black. Option c is correct.

This reaction is used as a test for the presence of starch in a sample. Iodine reacts with the helical amylose component of starch to form a dark blue complex, while amylopectin, which has a branched structure, forms a less intense blue color. This color change occurs due to the formation of an iodine-starch complex, which has a characteristic blue-black color. Therefore, the intensity of the color indicates the amount of starch present in the sample. Hence, option c is correct choice.

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--The complete question is, When starch is treated with iodine solution, its color changes to

(A) Yellow

(B) Red

(C) Blue-black

(D) Green--

What mass of hydrogen will react with 84g of N2

Answers

To determine the mass of hydrogen that will react with 84g of N2, we need to use stoichiometry and balanced chemical equation for the reaction between nitrogen (N2) and hydrogen (H2).

The balanced chemical equation for this reaction is:

N2 + 3H2 → 2NH3

This means that one mole of N2 reacts with three moles of H2 to produce two moles NH3.

To find out how many moles of N₂ are present in 84 g, we can use its molar mass which is about 28 g/mol.

Number of Moles = Given Mass / Molar Mass
= 84 g /28 g/mol
= 3 mol

From the balanced chemical equation above, we know that it takes three moles of H₂ to react with one mole N₂. Therefore,

1 mol N₂ : 3 mol H₂

Using these ratios, we can calculate the number of moles needed for Hydrogen.

Moles H₁= Ratio * given amount
= (3/1)* Number_of_Moles_Nitrogen
=(3/1)* (3mol)
=9mol

Now that you have calculated how many moles are needed based on stoichiometry calculation, you can now calculate the mass using :

Mass= Number Of Moles * Molar Mass
=9mol* (about) 2g/mol
≈18 g

Therefore, approximately **18 grams** of hydrogen will react with **84 grams**of Nitrogen.

How many moles of gas does it take to occupy 120 liters at a pressure of 2.3 atmospheres and a temperature of 350 K?
Remember:R=0.0821 L•atm/mol k
A. 9.6 mol
B. 3.4 mol
C. 4.7 mol
D.0.79 mol

Answers

Answer:

A - 9.6 mol.

Explanation:

Took the test.

If 50 grams of water are saturated at 90°C with potassium nitrate and then cooled to 40°C, how much will precipitate?

Answers

Answer:

43.1gramms

Explanation:

change the temperatures to kelvin

90--363

40--313

50grams of water are saturated at 90 degree celcius.

then,

50___363

x_____313

then cross multiply

363x=15650

divide both sides by 363

x=43.1gramms

2c2h6 + 7o2 = 4co2 + 6h2o

what mass of co2 will be produced from the reaction of 37. 5 g c2h6

Answers

The mass of CO2 produced from the reaction of 37.5 g of C2H6 is 109.92 g.

The balanced chemical equation for the combustion of ethane (C2H6) with oxygen (O2) is:

2C2H6 + 7O2 → 4CO2 + 6H2O

This equation concludes that 2 moles of C2H6 react with 7 moles of O2 to produce 4 moles of CO2 and 6 moles of H2O.

To find the mass of CO2 produced from the reaction of 37.5 g of C2H6, we need to use stoichiometry. Here are the steps to follow:

Calculate the number of moles of C2H6:

moles of C2H6 = mass of C2H6 / molar mass of C2H6

moles of C2H6 = 37.5 g / 30.07 g/mol

moles of C2H6 = 1.248 mol

Use the mole ratio from the balanced chemical equation to calculate the number of moles of CO2 produced:

moles of CO2 = moles of C2H6 × (4 moles of CO2 / 2 moles of C2H6)

moles of CO2 = 1.248 mol × 2

moles of CO2 = 2.496 mol

Calculate the mass of CO2 produced:

mass of CO2 = moles of CO2 × molar mass of CO2

mass of CO2 = 2.496 mol × 44.01 g/mol

mass of CO2 = 109.92 g

Therefore, the mass of CO2 produced from the reaction of 37.5 g of C2H6 is 109.92 g.

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to what volume should you dilute 49 ml of a 12 m stock hno3 solution to obtain a 0.113 m hno3 solution?

Answers

Answer: To obtain a 0.113 M HNO3 solution, you need to dilute 49 mL of 12 M HNO3 solution to a final volume of 5220 mL (or 5.22 L) by adding enough water to make up the difference.


Explanation: The stock HNO3 solution is 12 M and has a volume of 49 ml.

To get a 0.113 m HNO3 solution, we must dilute it to a certain volume. The volume to which it must be diluted is a mystery.

Let the final volume be V liters. The stock HNO3 solution's volume is 49 mL, which equals 0.049 L.

HNO3's molarity is 12 M.

We must use the formula to calculate the required volume of diluted solution, C1V1 = C2V2

where C1 is the concentration of the stock solution, V1 is the volume of the stock solution used, C2 is the desired concentration of the diluted solution, and V2 is the final volume of the diluted solution.

In this case, we have:

C1 = 12 M

V1 = 49 mL

C2 = 0.113 M

V2 = unknown

Let's do some math.

12 M x 49 mL = 0.113 M x V2

(12 x 0.049) / 0.113 = 5.22 L

The diluted volume is 5.22 L.

The stock HNO3 solution of 49 ml must be diluted to a volume of 5.22 L to obtain a 0.113 m HNO3 solution.

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an unknown gas effuses at a rate 0.667 times the rate of co₂. what is the molar mass of the unknown gas?

Answers

An unknown gas effuses at a rate 0.667 times the rate of co₂. The molar mass of the unknown gas is 120 g/mol.

The rate of effusion for an ideal gas is proportional to the inverse square root of the gas' molar mass. It's known as Graham's law. Graham's Law explains the rate of effusion of a gas through a small hole into a vacuum. The rate of effusion for an ideal gas is proportional to the inverse square root of the gas' molar mass (relative molecular mass). According to the question, the effusion rate of the unknown gas is 0.667 times that of CO₂.

Let the molar mass of the unknown gas be "x".

Therefore, the effusion rate for the unknown gas is proportional to

.[tex]\[\frac{1}{\sqrt{x}}\].[/tex]

The effusion rate of CO₂ is proportional to \[\frac{1}{\sqrt{44}}\].

Now,

[tex]\[\frac{\text{Effusion rate of the unknown gas}}{\text{Effusion rate of CO}_2}=\frac{0.667}{1}\][/tex]

or,

\[tex]\[\frac{1}{\sqrt{x}}=\frac{0.667}{\sqrt{44}}\][/tex]]

or,

[tex]\[\sqrt{x}=\frac{\sqrt{44}}{0.667}\][/tex]

or,

[tex]\[x=\left ( \frac{\sqrt{44}}{0.667} \right )^{2}\][/tex]

Therefore, the molar mass of the unknown gas is 120 g/mol.

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Explain the following observations:a) HCl is a stronger acid than H2Sb) H3PO4 is a stronger acid than H3AsO4c) HBrO3 is a stronger acid than HBrO2d) H2C2O4 is a stronger acid than HC2O−4e) benzoic acid, C6H5COOH, is a stronger acid than phenol, C6H5OH

Answers

a) HCl is a stronger acid than H2S due to weak bond between hydrogen and sulfur.

b) H3PO4 is a stronger acid than H3AsO4 due to smaller size of phosphorous atom than the arsenic atom.

c) HBrO3 is a stronger acid than HBrO2 as the oxidation state of Br in HBrO3 is +5.

d) H2C2O4 is a stronger acid than HC2O−4 as HC2O−4 is a conjugate base of H2C2O4.

e) Benzoic acid, C6H5COOH, is a stronger acid than phenol, C6H5OH due to strong resonance structure.

The following observations can be explained as follows:

a) HCl is a stronger acid than H2SIn hydrogen sulfide (H2S). The bond between hydrogen and sulfur is relatively weak. As a result, this bond is more difficult to break than that between hydrogen and chlorine in hydrogen chloride (HCl). Therefore, HCl is a stronger acid than H2S.

b) H3PO4 is a stronger acid than H3AsO4. The phosphorous atom has a smaller size than the arsenic atom. As a result, the P–O bond is more stable than the As–O bond. This makes the H3PO4 a stronger acid than H3AsO4.

c) HBrO3 is a stronger acid than HBrO2. HBrO3 is a stronger acid than HBrO2 since the oxidation state of Br in HBrO3 is +5. In contrast, Br has an oxidation state of +3 in HBrO2. As a result, the bond between Br and oxygen in HBrO3 is weaker, resulting in a higher acidity than in HBrO2.

d) H2C2O4 is a stronger acid than HC2O−4. HC2O−4 is a conjugate base of H2C2O4. The conjugate base is less acidic than the original acid, according to the conjugate acid-base theory. As a result, H2C2O4 is a stronger acid than HC2O−4.

e) Benzoic acid, C6H5COOH, is a stronger acid than phenol, C6H5OH. Benzene ring has a strong resonance structure due to the presence of electron donating OH- group in phenol. Resonance delocalizes the negative charge formed by the loss of a proton, and it makes it less acidic. The absence of an electron-donating group in benzoic acid allows for more hydrogen ion dissociation, making it a stronger acid than phenol.

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74. 5 g of KCl was dissolved in 1000. ML of water. What is the

molality of the solution? (Molar mass of KCI = 74. 5 g/mol)

m.

Answers

The molarity of the solution is 1.0 m

The first step is to convert the mass of KCl to moles:

Number of moles of KCl = 74.5 g / 74.5 g/mol = 1.0 mol

Next, we need to calculate the mass of water in kilograms:

Mass of water = 1000 mL x 1 L/1000 mL x 1 kg/L = 1 kg

Now we can calculate the molality of the solution:

Molality = moles of solute / mass of solvent (in kg)

Molality = 1.0 mol / 1 kg = 1.0 m

Therefore, the molality of the solution is 1.0 m.

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why don’t we change the subscripts in order to balance an equation?

Answers

Answer:

Because if we changed the subscript number we will change the identity of the compound and we Well creat a new compound  or substance different than what they gave us to balance also the law of conservation of mass states that the mass cannot be created nor destroyed.

Explanation:

What is compact bone made up of?

Answers

A closely packed mineralized matrix, which comprises hydroxyapatite, collagen fibres, and osteocytes as well as trace quantities of other proteins and minerals, makes up the majority of compact bone.

Compact bone is one of the two types of osseous tissue that makes up bones in vertebrates. It forms the outer layer of bone and provides strength and support to the skeleton. The structure of compact bone is composed of a tightly packed mineralized matrix, which is made up of hydroxyapatite crystals and collagen fibers. The hydroxyapatite crystals provide hardness and rigidity to the bone while the collagen fibers give it flexibility and resilience. Osteocytes, or bone cells, are also found in the mineralized matrix, which are responsible for maintaining the bone tissue. Additionally, small amounts of other proteins and minerals are present in the matrix, including calcium, phosphate, and magnesium. Together, these components create a strong and durable structure that is able to support the body's weight and withstand stress and strain.

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Whats the difference between zinc amino acid chelate with any other type of zincs?​

Answers

Answer:

chelated zinc is more easily absorbed than zinc on it's own.

Did the control experiment verify or refute the results from exercise 1? use your results from exercises 1 and 2 to validate your answer.

Experiment 1 E Data Table 1 B Data Table 2 Data Table 1: Antacid Neutralization Data Mass of 0. 59 Crushed Antacid (9) Concentration 1. 0 of HCI (M) Volume HCI 5. 0 (mL) Concentration 1. 0 of NaOH (M) Initial NaOH 9. 4 mL Volume (mL) Final NaOH 8. 2 mL Volume (mL) Total Volume 1. 2 mL of NaOH Used (mL) Experiment 1 Data Table 1 Data Table 2 Data Table 2: Experimental Results I 0. 1825 g 0. 0012 HCl available for neutralization (g): Moles of NaOH required to reach stoichiometric point (mol): HCI neutralized by antacid (g): НСІ neutralized per gram of antacid (9) 0. 1387 0. 2774 Experiment 2 El Data Table 3 B Data Table 4 Data Table 3: Control Experiment Data Concentration 1. 0 of HCI (M) Volume HCI 5. 0 (mL) Concentration 1. 0 of NaOH (M) Initial NaOH 9. 2 mL Volume (mL) Final NaOH 3. 6 mL Volume (mL) Total Volume 5. 6 mL of NaOH Used (mL) Data Table 4: Control Experiment Results 0. 2049 Moles of 0. 0056mol NaOH needed to neutralize 5. 0 mL of 1. OM HCI (mol): Grams of HCI neutralized (g): NaOH 4. 4mL volume difference between back titration and control (ml): Grams of 0. 160g HCI neutralized by NaOH volume difference (9)

Answers

Volume difference between back titration and controlHCI neutralized by NaOH volume difference is 0.0056 moles.

Given,

* Mass of Antacid = 0.5g

* [HCl] = 1M

* [tex]V_{HCl}[/tex] = 5 ml (pipetted out)

* [NaOH] = 1M

* [tex]V_{NaOH}[/tex] - 1.2 ml (consumed)

* Amt. of HCl avaliable for neutralisation = 0.1825 g

* No. of moles of NaOH req. to reach eq. point = 0.0012

* Amt. of HCl neutralised by antalid = 0.1387 g

* Amt. of HCl neutralised by antalid = 0.1387 g

* Amt. of HCl neutralised per gram of antalid = 0.1387 g

Solution: [tex]([/tex][tex]N[/tex] × [tex]V[/tex][tex])_{HCl}[/tex] =  [tex]([/tex][tex]N[/tex] × [tex]V[/tex][tex])_{NaOH}[/tex]

               (1 x 5 ) =  [tex]([/tex][tex]1[/tex] × [tex]V[/tex][tex])_{NaOH}[/tex]

             = [tex]V(NaOH)[/tex] = ( 1 x 5) / 1 = 5ml

In control expt. data  [tex]V(NaOH)[/tex] = 5.6ml

But in given data, [tex]V(NaOH)[/tex] = 1.2ml

So, Volume diff. of NaOH between back titration and control = 5.6 - 1.2 = 4.4ml

So, given follows

So, 4.4 ml of HCl means,

its Conc. will be equal to, 4.4 x 36.5 / 1000 = 0.1606 g

This is correct in control expt. results

In control expt. data, [tex]V(NaOH)[/tex] = 5.6ml

This corresponds to 5.6 x 40 / 1000 = 0.224g

This correspond to 0.224 / 40 = 0.0056 moles

This is correct in control expt. results.

Titration is a laboratory technique used to determine the concentration of an unknown solution by reacting it with a known solution. It is a quantitative method used to determine the amount of a substance in a sample. Titration is often used in chemistry to determine the concentration of acids, bases, and salts.

In a titration, a measured amount of the unknown solution is slowly added to a known solution of a substance with a known concentration called the titrant. The titrant is added until the reaction is complete, and a color change or other observable change occurs. The point at which the reaction is complete is known as the endpoint, and it is usually determined using an indicator, which changes color when the reaction is complete.

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8 H₂S+_8_Cl₂ --> _16_HCI + _1_Sg8
57 g H₂S makes how many grams of HCL

Answers

Answer:109.5g HCL

Explanation: 1st get the GFM of H2S, which is 34g/mol, and divide 57g by it. You get the moles for H2S: 1.7. Put what you have over what you want (have/want) equal to what other chemical you want like this:

8H2S/1.7H2S = 16HCl/X

Solve for it like an algebra equation

8x = 27.2 27.2/8 = 3.4molHCl

Round to sig figs

3molHCl

Multiple by HCL GFM (36.5g/mol)

3mol x 36.5g/mol


109.5gHCl

Each tablet contains the same number of moles of CaCO 3 and MgCO 3. One tablet reacted with excess hydrochloric acid to produce 0.24 dm 3 of carbon dioxide at r.t.p.
1.Calculate how many moles of CaCO 3 there are in one tablet?
2.number of moles CO 2 = ?

can anyone please give me explained answer.

Answers

The  number of moles of CaCO3 and number of moles of CO2 produced by one tablet is 0.00974 mol.

What is the number of moles of CaCO 3 there are in one tablet?

Based on the given information, we can use stoichiometry to calculate the number of moles of CaCO3 in one tablet and the number of moles of CO2 produced.

To calculate the number of moles of CaCO3 in one tablet, we need to know the balanced chemical equation for the reaction between hydrochloric acid (HCl) and calcium carbonate (CaCO3):

CaCO3 + 2HCl → CaCl2 + CO2 + H2O

From the equation, we can see that 1 mole of CaCO3 produces 1 mole of CO2.

Therefore, the number of moles of CaCO3 in one tablet is equal to the number of moles of CO2 produced by the tablet.

The given information states that one tablet reacted with excess hydrochloric acid to produce 0.24 dm3 of carbon dioxide at r.t.p. We can convert the volume of CO2 to moles using the ideal gas law:

PV = nRT

where;

P is the pressure (which is 1 atm at r.t.p.),

V is the volume (0.24 dm3),

n is the number of moles of gas,

R is the gas constant, and

T is the temperature (which is 273 K at r.t.p.).

Rearranging the equation and solving for n, we get:

n = PV/RT = (1 atm)(0.24 dm3)/(0.08206 L·atm/mol·K)(273 K)

n = 0.00974 mol

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4. A sample of water with a mass of 785 g and a starting temperature of
15.0°C is heated. What would the final temperature of the water be if 250,000
joules of heat are added to the water?(Ans: 91°C)

Answers

The final temperature of the water would be approximately 91°C after 250,000 joules of heat are added.

Describe Heat Capacity?

Heat capacity is the amount of heat energy required to increase the temperature of a substance by one degree Celsius (or one Kelvin). It is a measure of how much energy a substance can absorb without a significant change in its temperature.

The heat capacity of a substance depends on its mass and composition. Substances with more mass or more complex molecular structures generally have higher heat capacities, meaning they require more energy to increase their temperature than substances with less mass or simpler molecular structures.

To solve this problem, we can use the specific heat capacity formula:

Q = m * c * ΔT

where Q is the amount of heat transferred, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

We can rearrange this formula to solve for ΔT:

ΔT = Q / (m * c)

We are given the mass of the water (m = 785 g), the amount of heat added (Q = 250,000 J), and the specific heat capacity of water (c = 4.184 J/g°C).

Substituting these values into the equation, we get:

ΔT = 250,000 J / (785 g * 4.184 J/g°C)

ΔT ≈ 75.4°C

Therefore, the final temperature of the water would be:

15.0°C + 75.4°C = 91 °C

So the final temperature of the water would be approximately 91 °C after 250,000 joules of heat are added.

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Geothermal energy is produced when water touches _______________.

A oil
B hot rocks
C biomass

Answers

Answer: Hot Rocks

Explanation:

what do carbon dioxide and methane do for our atmosphere?

Answers

Methane and carbon dioxide are both greenhouse gases that are crucial in controlling the temperature of Earth's atmosphere.

Both natural processes like respiration and volcanic eruptions, as well as human activity like burning fossil fuels, emit carbon dioxide (CO2) into the atmosphere. It aids in keeping the planet warm enough to support life by retaining heat in the atmosphere. Carbon dioxide levels that are too high, however, can exacerbate climate change and global warming.

Methane (CH4) is another greenhouse gas that is emitted into the atmosphere as a result of human activity such as cattle husbandry and natural gas production as well as natural processes such as decomposition. Even though it decomposes more quickly in the atmosphere than carbon dioxide, it is even more efficient at trapping heat.

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Consider the following compound: 8 N 5 2. 3. 4. Determine the oxidation number atoms (a) 1. (b) 6, and (c) 7, a.) b.) c.) What is the average oxidation number for carbon in this compound? Use the algorithm method with the formula, not the structure. Enter fractions in decimal form with at least 3 spaces after the decimal. e.g. if O.N. E. then enter 2.500. Evaluate

Answers

The oxidation number of atoms (a) 1. (b) 6, and (c) 7 are as follows:The oxidation number of atom 1 is +8,The oxidation number of atom 6 is +5,The oxidation number of atom 7 is -2.The average oxidation number for carbon in this compound is -1.875.

The algorithm method with the formula is used to determine the average oxidation number for carbon in the compound. The formula to calculate the oxidation state of carbon can be given as:

Oxidation state of carbon = (number of carbon atoms x oxidation state of carbon) / total number of atoms.The given compound 8 N 5 2.3.4 consists of 19 atoms, of which 8 are carbon atoms, 5 are nitrogen atoms, and 6 are hydrogen atoms.

The oxidation state of nitrogen is -3 in the compound, and the oxidation state of hydrogen is +1.Now, the oxidation state of carbon is calculated as follows:

Oxidation state of carbon = (8 × oxidation state of carbon) / 19

We are supposed to find the average oxidation number of carbon atoms. To do this, we sum up the oxidation numbers of all carbon atoms and divide the sum by the total number of carbon atoms.

Oxidation state of carbon = (5* -1 + 3* -2 + 6 * +1) / 8

Oxidation state of carbon = (-5 - 6 + 6) / 8

Oxidation state of carbon = -1.875

Thus, the average oxidation number for carbon in this compound is -1.875.

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three metals, a, b and c, of equal mass, have heat capacities of 0.3 j/goc, 0.4 j/goc, and 0.5 j/goc, respectively. which of these metals will have the largest increase in temperature if the same amount of heat is added to the each of their systems?

Answers

The metal that will respond to the added temperature by increasing is metal A because it has the lowest heat capacity.

How to determine increase in temperature?

The metal with the smallest heat capacity will have the largest increase in temperature if the same amount of heat is added to each of their systems. This is because metals with smaller heat capacities require less heat energy to increase their temperature compared to those with larger heat capacities.

Therefore, metal A with the heat capacity of 0.3 J/g°C will have the largest increase in temperature if the same amount of heat is added to each of their systems, followed by metal B with 0.4 J/g°C and metal C with 0.5 J/g°C.

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Which of the following is the source of electrons for the light reactions?
a. C6H12O6 b. CO2 c. NADPH d. H2O

Answers

Answer: d. H2O

Explanation: Electrons for the light reactions are found in water. These electrons are taken by a certain enzyme complex known as the water splitting complex

Select an O for organic and an I for inorganic for each compound.
H 2 O: Choose...
C 3 H 6: Choose...
C 22 H 24: Choose...
CH 4: Choose...
NO 2: Choose...

Answers

H2O and CH4 are inorganic substances, whereas C3H6, C22H24, and NO2 are organic substances.

What is compound?

Compounds, which are objects, are created when two or more unique elements bond chemically. The components of a compound are held together by chemical bonds, which are created when atoms share or transfer electrons.

Given that it is made up of two covalently bound elements—hydrogen (H) and oxygen (O)—H2O is an inorganic compound.

Because its carbon (C) and hydrogen (H) atoms are covalently bound, the chemical C3H6 is considered to be organic. Propene, a significant ingredient in the manufacture of plastics and synthetic rubber, is an unsaturated hydrocarbon.

C22H24 is an additional chemical substance, specifically a triterpene hydrocarbon. It is a naturally occurring substance that can be found in a variety of plants and is frequently employed in conventional medicine.

Due to the fact that CH4 only has two elements—carbon (C) and hydrogen (H)—covalently bound to one another, it is an inorganic compound. It is generally referred to as methane and is the simplest and most prevalent hydrocarbon.

Due to the presence of two covalently bound elements—nitrogen (N) and oxygen (O)—NO2 is an inorganic molecule. It is a frequently occurring, highly reactive gas in the atmosphere and a significant source of air pollution.

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Eight moles of glucose have been oxidized under aerobic conditions. How many total moles of CO2 were produced? Enter a number below.

Answers

48 moles of CO2 were produced from 8 moles of glucose under aerobic conditions.

Eight moles of glucose have been oxidized under aerobic conditions, and we need to find the total moles of  CO2 produced.

For this purpose, we will utilize the balanced chemical equation for the complete combustion of glucose.

The balanced equation is given as below:  C6H12O6  + 6O2 → 6CO2 + 6H2O

From the above equation, we can see that one mole of glucose produces six moles of carbon dioxide.

Therefore, eight moles of glucose will produce 8 × 6 = 48 moles of carbon dioxide.

So, the total moles of CO2 produced are 48.

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