To solve the equation 6x - 7y = 18 for y, you can start by isolating y on one side of the equation. To do this, you can add 7y to both sides of the equation:
6x - 7y + 7y = 18 + 7y
6x = 18 + 7y
Next, divide both sides of the equation by 7:
6x/7 = 18/7 + 7y/7
x = 3 + y
So the solution is y = 3 - x
This is the final solution for y in the equation 6x - 7y = 18
Linda is training to be an assistant at the local animal shelter. To become an assistant she needs to complete 48 h of training. Linda keeps a graph of the number of hours of training left to be completed. What is the rate of change of the number of hours remaining with respect to the number of days? Remember to include units.
The equation between the number of days remaining and number of hours is given as y= -5x+50.
How to illustrate the equation?Let y be the number of days remaining and x be the no.of hours.
From the graph the slope of the line is given by m.
m=(y2 - y1)/(x2 - x1)
m=(30 - 40)/(4 - 2)
m= -10/2 = -5.
The above slope is in between points 2 and 4. As the line has a constant rate of growth the slope is the same between any points of the line.
Therefore the equation between the no.of days remaining and no.of hours is given by
y=mx +c.
y=-5x+c
Now to find the value of c. This can be determined by substituting the x and y values at a particular instant. For x=0,y=50. Therefore by these values, we get,
50= -5(0)+c
c=50.
Therefore the relation between the number of days remaining and number of hours is given as y= -5x+50.
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The following data show the scores of some students in a competition:
13 points
24 points
31 points
24 points
27 points
23 points
11 points
Which box plot represents the data?
A box plot titled "Scores of Participants" and labeled "Score" uses a number line from 10 to 35 with primary markings and labels at 10, 15, 20, 25, 30, and 35. The box extends from 23 to 27 on the number line. A line in the box is at 24. The whiskers end at 11 and 31.
A box plot titled "Scores of Participants" and labeled "Score" uses a number line from 10 to 35 with primary markings and labels at 10, 15, 20, 25, 30, and 35. The box extends from 13 to 27 on the number line. A line in the box is at 24. The whiskers end at 11 and 31.
A box plot titled "Scores of Participants" and labeled "Score" uses a number line from 10 to 35 with primary markings and labels at 10, 15, 20, 25, 30, and 35. The box extends from 13 to 27 on the number line. A line in the box is at 23. The whiskers end at 11 and 31.
A box plot titled "Scores of Participants" and labeled "Score" uses a number line from 10 to 35 with primary markings and labels at 10, 15, 20, 25, 30, and 35. The box extends from 13 to 27 on the number line. A line in the box is at 24. The whiskers end at 10 and 35.
The box plot that represents the data is a box plot titled "Scores of Participants" and labeled "Score" uses a number line from 10 to 35 with primary markings and labels at 10, 15, 20, 25, 30, and 35. The box extends from 13 to 27 on the number line. A line in the box is at 24. The whiskers end at 11 and 31.(second option)
Which box plot represents the data?A box plot is used to study the distribution and level of a set of scores. The whiskers represent the minimum and maximum values.
On the box, the first line to the left represents the lower (first) quartile. The next line on the box represents the median. The third line on the box represents the upper (third) quartile. 75% of the scores represents the upper quartile.
The data arranged in ascending order : 11, 13, 23, 24, 24, 27, 31
Median = 24
First quartile = 1/4 x (7 + 1) = 2nd term =13
Third quartile = 3/4 x (7 + 1) = 6th term = 27
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Can anyone help me with this question?:)
Answer:
ΔABC ≅ ΔEDF
Step-by-step explanation:
Triangle ABC is congruent to triangle EDF because they're the same size.
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]
[tex] \sf\triangle ABC \cong \triangle DEF[/tex]
For checking congruency, we need to follow a proper order when choosing the triangle. because each triangle name is unique in itself.
So, According to Triangle ABC, we need to find the triangle with first two letters That resembles AB, that is :
AB = DEand next should be :
BC = EF[tex] \qquad \large \sf {Conclusion} : [/tex]
so, now we got the sense for naming, therefore the answer will be :
[tex] \sf\triangle ABC \cong \triangle DEF[/tex]
A matrix A has x rows and x+5 columns. B has y rows and 11−y columns. Both AB and BA exist. Find x and y.
Answer:
x = 3
y = 8
Step-by-step explanation:
A matrix product exists if and only if the number of columns in the left matrix is equal to the number of rows in the right matrix.
SetupFor AB to exist, we must have ...
columns of A = rows of B
x +5 = y
For BA to exist, we must have ...
columns of B = rows of A
11 -y = x
SolutionUsing the second equation to substitute for x in the first equation, we have ...
(11 -y) +5 = y
16 = 2y
8 = y
Then the value of x is ...
11 -8 = x = 3
The values of x and y are ...
x = 3y = 8__
Additional comment
The dimensions are A = 3×8; B = 8×3.
A Textile Company bought equipment for $40,000. The residual value is $6,000.
The company assumes the equipment will have a useful life of 170,000 units. What
is depreciation expense per unit of production?
$2.00
$1.20
$0.75
$0.20
The depreciation expense per unit of production for the Textile Company is D. $0.20.
What is the unit-of-production depreciation method?The unit-of-production depreciation method uses the useful life of an asset based on the units of production and the depreciable amount to estimate the depreciation expense per unit.
For each period, the depreciation expense per unit is multiplied by the units of production to determine the period's total depreciation expense.
Data and Calculations:Cost of equipment = $40,000
Residual value = $6,000
Depreciable amount = $34,000 ($40,000 - $6,000)
Estimated useful life = 170,000 units
Depreciation expense per unit of production = $0.20 ($34,000/170,000)
Thus, the depreciation expense per unit of production for A Textile Company is D. $0.20.
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2) (x+3)
2) Correct the error:
There is an error in the students' work shown below:
Question: Simplify (x-3)(x-7)
Solution: (x-3)(x-7)
x-x-3(x)-7(x) - 21
x²-10x-21
What is the error? Explain how to solve the problem.
The expression x²-10x-21 is wrong since the product of two negative signs is equal to positive.
Simplifying factorsQuadratic equations are equations that has a leading degree of 2. The standard quadratic equation is given as;
f(x) = ax^2+bx+c
Given the product of the expression below;
f(x) = (x-3)(x-7)
Expand
f(x) = x(x) - 7x - 3x -3(-7)
f(x) = x^2 - 7x - 3x + 21
f(x) = x^2 - 10x + 21
Hence the expression x²-10x-21 is wrong since the product of two negative signs is equal to positive.
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Q1. A man wants to paint his house in 3 colors. If he can choose 3 colors out of 6 colors, how many
different color settings can he make?
(A) 216 (B) 20 (C) 18 (D) 120
The equation T^2= A^3 shows the relationship between a planets orbital period, T, and the planets mean distance from the sun, A, in astronomical units, AU. if the orbital period of planet Y is twice the orbital period of planet x, by what factor is the mean distance increased?
The mean distance increased by a factor of 2^(²/₃)
How to find the factor of increase?
The given equation for the relationship between a planet's orbital period, T and the planet's mean distance from the sun, A is;
T² = A³.
Let the orbital period of planet X = T(X).
Let the orbital period of planet Y = T(Y).
Let the mean distance of planet X from the sun = A(X).
Let the mean distance of planet Y = A(Y).
Thus;
A(Y) = 2A(X)
Therefore;
[T(Y)]² = [A(Y)]³ = [2A(X)]^3
However, [T(X)]² = [A(X)]³
Thus;
[T(Y)]² = 2³[T(X)]² * [T(Y)]²/[T(X)]² = 2³T(Y)/T(X) = 2^(³/₂)
That's for orbital period but the mean distance will increase by 2^(²/₃)
Thus we conclude that, the mean distance increased by a factor of 2^(²/₃)
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Answer:
2 Superscript three-halves
Step-by-step explanation:
Edge
The function f(x)=−4x4+3x3−2x2−x+5 is/has A. order 2 rotational symmetry about the origin
B. neither symmetry about the y-axis nor has order 2 rotational symmetry about the origin
C. even
D. odd
The answer choice which describes the function is; Choice B; neither symmetry about the y-axis nor has order 2 rotational symmetry about the origin.
What is rotational symmetry?Rotational symmetry, otherwise termed radial symmetry, is the characteristic of a shape when it looks the same after some rotation by a partial turn. On this note, since the function represents a quartic graph, it follows that the function has neither symmetry about the y-axis nor has order 2 rotational symmetry about the origin.
Therefore, the function f(x) = −4x⁴ + 3x³ − 2x² − x + 5 is neither symmetry about the y-axis nor has order 2 rotational symmetry about the origin.
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A government buys `x`fighter planes at `z` dollars each, and `y` tons of wheat at w dollars each. It spends a total of `B`dollars, where `B=xz+yw`. Write an equation whose solution is the given quantity:
2. The price of a ton of wheat, given that a fighter plane costs 100,000 times as much as a ton of wheat, and that the government bought 20 fighter planes and 15,000 tons of wheat for a total cost of $90 million.
The equation whose solution is the given quantity is 90,000,000 = 2,000,000w + 15,000w where w = $44.67
EquationB = xz + yw
Where,
B = Total cost = 90x = number of fighter plane = 20y = tons of wheat = 15,000w = cost of each tons of wheatz = cost of fighter planez = 100,000wB = xz + yw
90,000,000 = (20 × 100,000w) + (15,000 × w)
90,000,000 = 2,000,000w + 15,000w
90,000,000 = 2,015,000w
w = 90,000,000 / 2,015,000
= 44.6650124069478
Approximately,
w = $44.67
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A person draws a card from a hat. Each card is one color, with the following probabilities of being drawn: 1/5 for pink, 1/25 for blue, 1/10 for yellow, and 1/15 for black. What is the probability of pulling a blue or yellow card,
The probability of pulling a blue or yellow card, written as a reduced fraction is 7/50
How to determine the probability of pulling a blue or yellow card, written as a reduced fraction?From the question, we have the following probabilities:
P(Pink) = 1/5
P(Blue) = 1/25
P(Yellow) = 1/10
P(Black) = 1/15
The probability of pulling a blue or yellow card, written as a reduced fraction is the calculated as:
P(Blue or yellow card) = P(Blue card) + P(Yellow card)
Substitute the known values in the above equation
P(Blue or yellow card) = 1/25 + 1/10
Express 1/25 as 2/50 and 1/10 as 5/10
P(Blue or yellow card) = 2/50 + 5/50
Take the LCM
P(Blue or yellow card) = (2+ 5)/50
Evaluate the sum
P(Blue or yellow card) = 7/50
Hence, the probability of pulling a blue or yellow card, written as a reduced fraction is 7/50
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Thomas took 3h to paint a room. Brian could paint the same room in 6h. How long would it take for both of them to finish painting the same room together?
please help !! no algebra please
Answer:
2 hours
Step-by-step explanation:
If Thomas can paint 1/3 = 2/6 of the room in a hour and Brian can paint 1/6 of the room in an hour. Which means in an hour they can collectively paint 3/6 = 1/2 of the room. Now you need to find how long it would take then to paint 2/2 of the room. Knowing that 1/2+1/2 = 2/2, it would take them 2 hours to paint the room together
A group of college students are going to a lake house for the weekend and plan on renting small cars and large cars to make the trip. Each small car can hold 5 people and each large car can hold 7 people. A total of 10 cars were rented which can hold 66 people altogether. Write a system of equations that could be used to determine the number of small cars rented and the number of large cars rented. Define the variables that you use to write the system.
The system of equations that could be used to determine the number of small cars rented and the number of large cars rented is;
x + y = 10
x + y = 105x + 7y = 66
Simultaneous equationSmall car = 5 peopleLarge car = 7 peopleTotal cars = 10Total number of people = 66Let
Number of small cars rented = x
Number of large cars rented = y
x + y = 10
x + y = 105x + 7y = 66
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Write the expression as a polynomial:
(a-2)(4a³-3a²)
Answer:
[tex]4a^{4} -11a^{3} + 6a^{2}[/tex]
QUICK I need help on what the answer is and an explanation would be much appreciated too thank you
The nonreal solutions to the polynomial equation are: (2 + i√11, 2 - i√11).
How to determine the nonreal solutions?By critically observing the graph given, we can logically deduce that the real solutions of the polynomial are -1 and 4. This ultimately implies that, the given polynomial expression can be evaluated as follows:
(x + 1)(x - 4) = x² - 3x - 4.
x⁴ - 7x³ + 23x² - 29x - 60 = x² - 3x - 4.
Also, the nonreal solutions can be determined by dividing the polynomial expression by the real solutions as follows:
Nonreal solutions = (x⁴ - 7x³ + 23x² - 29x - 60)/(x² - 3x - 4)
Nonreal solutions = (2 + i√11, 2 - i√11).
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Which of the following rational functions is graphed below?
Answer: D
Step-by-step explanation:
There are vertical asymptotes at x=7 and x=-3, so the denominator should have factors of (x-7) and (x+3).
This eliminates everything except for D.
Consider the following 8 numbers, where one labelled
x
is unknown.
34
,
31
,
15
,
x
,
17
,
4
,
20
,
25
Given that the range of the numbers is 69, work out 2 values of
x
.
x
=
x
=
Answer:
x = 73
x = -35
Step-by-step explanation:
Here are the 8 numbers:
34, 31, 15, x, 17, 4, 20, 25
Here are the 8 numbers in ascending order with x as the greatest number:
4, 15, 17, 20, 25, 31, 34, x
x - 4 = 69
x = 73
Here are the 8 numbers in ascending order with x as the smallest number:
x, 4, 15, 17, 20, 25, 31, 34
34 - x = 69
-x = 69 - 34
-x = -35
x = -35
Answer:
x = 73
x = -35
The point (–1, 0.5) lies on the graph of
f –1(x) = 2x. Based on this information, which point lies on the graph of f(x) = log2x?
The point which would lie on the graph of f(x) = log2x is; (1, 0.301).
Which point would lie on the graph of f(x) = log2x?Since it follows from the task content that the given point (–1, 0.5) lies on the graph of f –1(x) = 2x.
The subsequent graph of f(x) = log2x would result from taking logarithms in which case, we have the graph passing through points determined as follows;
f(x) = log2^x
f(x) = x log2
Hence, when x = 1;
f(1) = 1log 2
Hence, we have point; (1, 0.301).
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2. State two (2) values of θ (theta) to the nearest degree for
sin θ = − 0. 966
Using equivalent angles, the solutions to the equation are given as follows:
[tex]\theta = 255^\circ, \theta = 285^\circ[/tex]
What are equivalent angles?Each angle on the second, third and fourth quadrants will have an equivalent on the first quadrant.
In this problem, the equation is:
[tex]\sin{\theta} = -0.966[/tex]
Applying the inverse relation:
[tex]\theta = \arcsin{-0.966} = 255^\circ[/tex]
Which is on the third quadrant. The equivalent angle on the fourth quadrant is given as follows:
[tex]270^\circ + (270^\circ - 255^\circ) = 285^\circ[/tex]
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PLEASE HELP!!!!
Cooling towers are used to remove or expel heat from a process. A cooling tower's walls are modeled by x squared over 400 minus quantity y minus 110 end quantity squared over 2304 equals 1 comma where the measurements are in meters. What is the width of the cooling tower at the base of the structure? Round your answer to the nearest whole number.
100 meters
50 meters
48 meters
40 meters
Answer:
(a) 100 meters
Step-by-step explanation:
You want the width at the base of a cooling tower whose walls are modeled by the equation (x/20)² -((y-110)/48)² = 1.
BaseThe width at the base will be the difference in the values of x when y=0.
(x/20)² -((0 -110)/48)² = 1
(x/20)² = 1 +3025/576
x = ±20/24√3601 ≈ ±50.01
The width will be 50.01 -(-50.01) ≈ 100 meters.
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Which of the following is a true proportion of the figure based on the triangle
proportionality theorem?
Based on the triangle proportionality theorem, the true proportion is h/j=k/i
How to solve for the true proportionIn the diagram that we have here, we have TU to be parallel to QR.
We have following
ST is equal to h, TQ is equal to j, SU is equal to k and UR is equal to i.
This can then be used to form the equation
ST/TQ = SU/UR
When we h/j = k/i
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Drag a statement or reason to each blank in the table to complete the proof that <1 is congruent to <7.
Step-by-step explanation:
<1 congruent to <5.
<5 congruent to <7.
<1 congruent to <7.
Answer:
don't know but i need thee points
Step-by-step explanation:
which of the following functions is graphed below?
The function that's illustrated in the graph is function D.
How to explain the function?First, you look at the left side of the graph. You can tell by the shape that it is an x³ function.
Also, the filled-in circle means inclusive. so we know that when x is less than or equal to a number.
The answer that illustrates the information explained is D.
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Answer:
B.
Step-by-step explanation:
An open circle means to exclude the point.
A closed circle means to include the point.
In this graph we see a part of a parabola with an open circle above. The parabola starts at x = 1, but does not include x = 1, and the x values of the parabola increase.
A parabola has an x squared in the equation.
The solution has to have an equation with an x² as its greatest exponent, and also must include x > 1.
The lower part of the graph is a third degree polynomial, so it must have an x cube term, x³. Also, the greatest x value for the x³ function is x = 1, but x = 1 is included. Then all x values tot he left of x = 1 are also included, so for the cubic polynomial, the domain (x values) must be x ≤ 1.
The answer is B.
Write the equation of the line that is perpendicular to the graph of
2x-3y=-3
and passes through (–3, 0).
Answer:
Step-by-step explanation:
eq. of line is 2x-3y=-3
its slope=(-co-efficient of x/co-efficient of y)=-2/-3=2/3
slope of line perpendicular to given line=-3/2
eq. of line through (-3,0) is
y-0=-3/2 (x+3)
2y=-3x-9
3x+2y=-9
or
any eq. perpendicular to given line is
3x+2y=c where c is a constant.
it passes through (-3,0)
3(-3)+2(0)=c
c=-9
reqd. eq. is
3x+2y=-9
Let f(x) = √3x and g(x) = x + 3. What's the smallest number that is in the domain of
fºg?
Answer:
-3
Step-by-step explanation:
[tex]f\left( x\right) =\sqrt{3x} \ \ \text{and} \ \ g\left( x\right) =x+3[/tex]
it’s clear that :
f is defined if and only if x ≥ 0
Therefore ,
fºg is defined if and only if x + 3 ≥ 0
x + 3 ≥ 0
⇔ x ≥ -3
Then ,the smallest number that is in the domain of fºg is -3
Use the drawing tool(s) to form the correct answer on the provided graph.
Graph the solution to this system of inequalities in the coordinate plane.
3y 2x+122x + y ≤5
The plotting of the inequalities was done using geogebra online graphing calculator. The graph is attached.
What are inequalities?Inequalities are the mathematical expressions in which both sides are not equal. It should be noted that in inequality, unlike in equations, we compare two values.
The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign. Inequality is an expression used to show the nonequal comparison of numbers and variables.
Given the system of inequalities:
3y > 2x + 12
3y - 2x > 12 (1)
2x + y < -5 (2)
Plotting the inequalities using GeoGebra online graphing calculator. The graph is attached
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A linear function always increases
-true
-false
Answer: False
Step-by-step explanation:
If the function has a negative slope, then it will decrease.
Which expression is it equivalent too help a brother out
The expression which is equivalent to the given expression in the task content is; 1/x²⁴.
Which expression is equivalent to the given expression?It follows from the task content that the given expression is; ((x)^-6/x²)³.
Hence, it follows from the laws of indices that the expression can be evaluated as follows;
= (x^-8)³
= x^-²⁴
= (1/x²⁴).
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A random sample of vehicle mileage expectancies has a sample mean of x¯=169,200 miles and sample standard deviation of s=19,400 miles. Use the Empirical Rule to estimate the percentage of vehicle mileage expectancies that are more than 188,600 miles. Round your answer to the nearest whole number (percent).
The percentage of vehicle mileage expectancies that are more than 188,600 miles is 93%
How to determine the percentage?The given parameters are:
Mean = 169200
Standard deviation = 19400
x = 188600
Calculate the z value using:
[tex]z = \frac{x - \mu}{\sigma}[/tex]
So, we have:
[tex]z = \frac{188600 - 169200}{19400}[/tex]
Evaluate
z = 1
Using the Empirical Rule, we have:
P(x > 188600) = P(z > 1.5)
From z table of probability, we have:
P(x > 188600) = 0.93319
Express as percentage
P(x > 188600) = 93.319%
Approximate
P(x > 188600) = 93%
Hence, the percentage of vehicle mileage expectancies that are more than 188,600 miles is 93%
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Two sides of a triangle have lengths 18m and 23m. Describe the possible length of the thired side
The possible length of the third side will be values that are less than 41 and greater than 5
Triangular theoremFor three sides to be the sides of a triangle, the sum of any two sides of the triangle must be greater than the third.
Given the two sides of a triangle have lengths 18m and 23m, the sum of the sides is given as:
sum = 18 + 23
Sum = 41
Let the third side be x, such that;
x + 18 >23
23 + x > 18
x > 23 - 18
x > 5
Similarly
x > -5
Hence the possible length of the third side will be values that are less than 41 and greater than 5
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