Answer:
46
Step-by-step explanation:
Diagonals of square are equal, Therefore,
KM=161
JL=4x-23
4x-23=161
4x=161+23
4x=184
x=184/4
x=46
Find the volume of this rectangular pyramid.
Be sure to include the correct unit in your answer.
6 m
3 m
9 m
Answer:
54 m^3
Step-by-step explanation:
this is the answer = 54 m^3
Volume of the rectangular pyramid will be 54[tex]m^{3}[/tex].
What is Rectangular Pyramid?Rectangular pyramid has 5 faces where one face is rectangular which is at bases and other 4 faces are triangular which is connected at the one point .
How to calculate the volume of the rectangular pyramid?If we assume that l is the length of the base and b is the width of the base and h is height of the rectangular pyramid then we can calculate the volume of the rectangular pyramid using the formula stated below
Volume of the rectangular pyramid = V= (1/3)×l×b×h
According to the asked question
l = 6m
b = 3m
h = 9m
then we can calculate the volume of the rectangular pyramid by using the above formula
= V= (1/3)×l×b×h
= (1/3)×6m×3m×9m
= 54[tex]m^{3}[/tex]
Learn more about volume of the rectangular pyramid
Here:https://brainly.com/question/924442
#SPJ2
Find the length of the third side. If necessary, round to the nearest tenth
Answer:
30
Step-by-step explanation:
third side is the hypotenuse since it is opposite to 90 degree.
using pythagoras theorem
a^2 + b^2 = c^2
24^2 + 18^2 = c^2
576 + 324 = c^2
900 = c^2
[tex]\sqrt{900}[/tex] = c
30 = c
therefore third side is 30.
Answer:
30
Step-by-step explanation:
[tex] {24}^{2} + 18 {}^{2} = c {}^{2} \\ 576 + 324 = c {}^{2} \\ \sqrt{900 = \sqrt{c }^{2} } \\ = 30[/tex]
Which equation, when solved, results in a different value of x than the other three?
-7/8x-3/4=20
3/4+7/8x=-20
-7(1/8)x-3/4=20
-7/8(-8/7)x-3/4=20(-7/8)
Answer:
D. -7/8(-8/7)x-3/4=20(-7/8) is the answer.
Jocelyn finds the blueprints for her house in the basement. The kitchen floor measures 12 inches long and 15 inches wide on the drawing. If the scale of the drawing is 1 inch: 4 ft, what are the dimensions of her actual kitchen floor?
Answer:
Step-by-step explanation:
48 ft by 60 ft
please help me please help me please help me please help me please help me please help me please
Answer:
Q3. 9
Q4. 6
Step-by-step explanation:
i need to see the steps for simplifying 3(m-5)+m
Answer:
4m - 15
Step-by-step explanation:
a( x + y) = ax + ay
[tex]3( m - 5 ) + m\\\\3m - 15 + m \\\\4m - 15[/tex]
Answer:
4m-15
Step-by-step explanation:
Distrubite 3 through the parentheisis
3m-15+m
Collect like terms
4m-15
There are 400 animals that live at a zoo. You find that 22 of 65 randomly chosen animals are
monkeys. About how many animals in the entire zoo are likely to be monkeys?
Answer:
About 135.
Step-by-step explanation:
As the sample is random the number of monkeys likely to be in the zoo
= (22/65) * 400
= 135.38
Evaluate the function.
f(x)=2x^2+8x
Find f(−1)
PLease help!
a:-10
b:-6
c:6
d:10
Answer:b
Step-by-step explanation:
Cho hàm ẩn z=z(x,y) xác định từ phương trình x+y+xz+yz2−1=0. Tính vi phân toàn phần dz(1,0).
Answer:
please write the question in english than I may help you
Mr. Jones lives in City A and drives at a constant speed to City B, which is 400 km 2 of the distance at that same away. On the way back to City A, Mr. Jones drives 5 constant speed. Then, because of rain, he decreases his speed by 20 km/h. The round trip takes 11 hours. How fast did Mr. Jones drive during the rainy part of his trip from City B to City A?
Answer:
He traveled at 72km/hr during the rain
Step-by-step explanation:
Question is not well formatted. See comment
Given
[tex]d=400km[/tex] --- distance
[tex]t = 11hrs[/tex] --- total time
Let his speed from city A till the rain starts on his return trip be [tex]s_1[/tex]
Let his speed from city during the rain be [tex]s_2[/tex]
So:
[tex]s_2 = s_1 -20[/tex]
Required
Calculate [tex]s_2[/tex]
From the question, we understand that; he drives the whole 400 km and 2/5 of 400 km at [tex]s_1[/tex]
The distance covered during this period is:
[tex]d_1 = 400 + \frac{2}{5} * 400[/tex]
[tex]d_1 = 400 + 160[/tex]
[tex]d_1 = 560[/tex]
And the time during this period is:
[tex]t_1 = \frac{2}{5} * 11[/tex]
[tex]t_1 = 4.4[/tex]
So, the distance during the rain is:
[tex]d_2 = 2 * 400 - d_1[/tex]
[tex]d_2 = 2 * 400 - 560[/tex]
[tex]d_2 = 800 - 560[/tex]
[tex]d_2 = 240[/tex]
And the time during the rain is:
[tex]t_2 = 11 - t_1[/tex]
[tex]t_2 = 11 - 4.4[/tex]
[tex]t_2 = 6.6[/tex]
So, we have:
[tex]d_1 = 560[/tex] --- distance covered before the rain
[tex]d_2 = 240[/tex] --- distance covered when raining
[tex]s_2 = s_1 -20[/tex]
[tex]t_1 = 4.4[/tex] ---- time spent before the rain
[tex]t_2 = 6.6[/tex] --- time spent in the rain
Speed is calculated as:
[tex]Speed = \frac{distance}{time}[/tex]
Make distance the subject
[tex]distance = speed * time[/tex]
So:
[tex]d_1 + d_2 = s_1 * t_1 + s_2 * t_2[/tex]
Recall that:
[tex]s_2 = s_1 -20[/tex]
Make [tex]s_1[/tex] the subject
[tex]s_1 = s_2 + 20[/tex]
The expression [tex]d_1 + d_2 = s_1 * t_1 + s_2 * t_2[/tex] becomes:
[tex]560 + 240 = (s_2 + 20) * 4.4 + s_2 * 6.6[/tex]
[tex]800 = 4.4s_2 + 88+ 6.6s_2[/tex]
Collect like terms
[tex]6.6s_2 + 4.4s_2 = 880 - 88[/tex]
[tex]11s_2 = 792[/tex]
Solve for [tex]s_2[/tex]
[tex]s_2= \frac{792}{11}[/tex]
[tex]s_2=72km/h[/tex]
The distance and time 400 km and 11 hours as well as the speed
reduction gives the speed during the rainy part as 60 km/h.
Which method can be used to find the speed in the rain?Based on the comment in the question, we have;
Given:
Distance between City A and City B = 400 km
Distance travelled at the same speed on his way back = [tex]\mathbf{\frac{2}{5}}[/tex] of the distance
Amount by by which his speed is reduced in the remaining [tex]\frac{3}{5}[/tex] of the distance because of rain = 20 km/h
The duration of the trip = 11 hours
Required:
How fast Mr. Jones was driving during the rainy part of his trip from City
B to City A?
Solution:
Let v represent the constant speed, we have;
[tex]Time = \mathbf{ \dfrac{Distance}{Speed}}[/tex]
The distance for which his speed is v = ([tex]\frac{2}{5}[/tex] + 1) × 400 km = 560 km
Total distance of the round trip = 400 km + 400 km = 800 km
The distance for which the speed = v - 20 = 800 km - 560 km = 240 km
Therefore, we have;
[tex]\mathbf{\dfrac{560}{v} + \dfrac{240}{v - 20}}= 11[/tex]
Which gives;
[tex]\mathbf{\dfrac{560 \times (v - 20) + 240 \cdot v}{v\times (v - 20) } } = 11[/tex]
11 × (v² - 20·v) = 560·v - 20 × 560 + 240·v
11·v² - 220·v - 560·v - 240·v + 11200
11·v² - 1020·v + 11,200 = 0
Using the quadratic formula, to solve the above quadratic equation we have;
[tex]v = \dfrac{1020 \pm\sqrt{(-1020)^2 - 4 \times 11 \times 11200} }{2 \times 11} = \dfrac{1020 \pm740 }{22} = \mathbf{ \dfrac{1020 \pm740 }{22}}[/tex]
v = 80 or v = [tex]12 . \overline{72}[/tex]
The possible value for the constant speed is therefore;
v = 80 km/h
The speed during the rain = v - 20, which gives;
The speed during the rain = 80 km/h - 20 km/h = 60 km/hLearn more about quadratic formula here;
https://brainly.com/question/283838
how to solve 4 > 11 - x/3
Answer:
21 < x
Step-by-step explanation:
4 > 11 -x/3
Subtract 11 from both sides
4 - 11 > -x/3
-7 > -x/3
Multiply both sides by 3
-7*3 > -x
-21 > -x
Multiply both sides by (-1)
21 < x
When we are multiplying by negative, then inequality sign changes.
Need help with practice problem please
2. A bag contains one red, one blue and one white marble. One marble is chosen at random
from the bag, and then replaced into the bag. A second marble is chosen.
a) Draw a probability tree and find the sample space.
(3 marks)
Answer:
Step-by-step explanation:
The length of a rectangle should be 20 meters longer than 8 times the width. If the length must be
between 116 and 180 meters long, what are the restrictions for the width, z?
Write the solution set as an algebraic inequality solved for the variable
Answer:
The width of the rectangle lies between 12 and 20.
Step-by-step explanation:
Let the width of the rectangle is w.
length of the rectangle,
L = 8 w + 20
116 < L < 180
So,
116 < 8 w + 20 < 180
96 < 8 w < 160
12 < w < 20
So, the width of the rectangle lies between 12 and 20.
if marvin bought 490 soda cans and candy bars, where the ratio is 3:4, respectively, how many of each did marvin buy?
9514 1404 393
Answer:
210 soda cans280 candy barsStep-by-step explanation:
The 3+4 = 7 ratio units represent the total of 490 snacks, so each ratio unit represents 490/7 = 70 snacks.
The number of soda cans is 3·70 = 210.
The number of candy bars is 4·70 = 280.
Marvin bought 210 soda cans and 280 candy bars.
Zari folds the net shown into model of a solid figure. How many edges, faces, and vertices does the model have?
Answer:
Faces = 6
Vertices = 8
Edges = 12
Step-by-step explanation:
In a solid geometric shape :
A face is a flat surface : faces = 6
A vertex (plural: vertices) is a Corner : vertices = 8
An edge is a particular type of line segment joining
two vertices : Edges = 12
find the area
steps, please
Answer:
45) 35.75 sq km
46) 24.5 sq km
Step-by-step explanation:
Area of Square:
A= [tex]\frac{(base)(height)}{2}[/tex]
45) A = (11)(6.5) ÷ 2 =
46) A = (10)(4.9) ÷ 2 =
Answer:
45) [tex]35.75[/tex] [tex]km^2[/tex]
46) [tex]24.5[/tex] [tex]km^2[/tex]
Step-by-step explanation:
------------------------------
The formula to find the area of a triangle is [tex]A=\frac{1}{2}bh[/tex] where [tex]b[/tex] stands for the base and [tex]h[/tex] stands for the height.
So, let's solve and find out the answer.
--------------->>>>
45)
[tex]A=\frac{1}{2}(11)(6.5)[/tex]
[tex]A=\frac{1}{2}(71.5)[/tex]
[tex]A=35.75[/tex]
The area of this triangle is [tex]35.75[/tex] [tex]km^2[/tex]
--------------->>>>
46)
[tex]A=\frac{1}{2} (10)(4.9)[/tex]
[tex]A=\frac{1}{2} (49)[/tex]
[tex]A=24.5[/tex]
The area of this triangle is [tex]24.5[/tex] [tex]km^2[/tex]
------------------------------
Hope this is helpful
2(f-9)=-28 f=?
-3(2t+3)=-21 t=?
Answer:
1. f= 3/5
2. t= 3/5
Step-by-step explanation:
FYI you can use the app photo math, you just take a pic of the problem and it gives you the answer and explains the steps and it is free.
Answer:
Below in bold.
Step-by-step explanation:
2(f - 9) = -28
2f - 18 = -28
2f = -28 + 18
2f = -10
f = -5.
-3(2t + 3) = -21
2t + 3 = -21/-3
2t + 3 = 7
2t = 4
t = 2.
1. A photograph measures eleven inches wide and fourteen inches long. The picture is enlarged to fit on a wall. If the new larger picture is 231 inches wide, how long is it?
234 inches
294 inches
181.5 inches
412.5 inches
.
Answer:
294 in
Step-by-step explanation:
set a ratio w/l
11/14
set it equal to 231/x
x = length
[tex]\frac{11}{14}[/tex] = [tex]\frac{231}{x}[/tex]
cross multiply
11x = 3234
divide by 11
x = 294
How do I solve this
Answer:
P(A or B) = 1.16
Step-by-step explanation:
Given probability:
Probability of event A = P(A) = 0.46
Probability of event B = P(B) = 0.7
P(A and B) = 0.43
Find:
P(A or B)
Computation:
If A is an incident and B is a separate event, P(A or B) is the possibility of either A, B, or both events occurring.
P(A or B) = P(A) + P(B)
P(A or B) = 0.46 + 0.7
P(A or B) = 1.16
Determine the equation of the line that is perpendicular to the given line, through the given point.
y=3x+4; (9, -7)
Answer:
The equation of the line is [tex]y + 7 = -\frac{1}{3}(x - 9)[/tex]
Step-by-step explanation:
Equation of a line:
The equation of line, in point-slope form, is given by:
[tex]y - y_0 = m(x - x_0)[/tex]
In which m is the slope and the point is [tex](x_0, y_0)[/tex]
Perpendicular lines:
If two lines are perpendicular, the multiplication of their slopes is -1.
Through (9,-7)
This means that [tex]x_0 = 9, y_0 = -7[/tex]
So
[tex]y - y_0 = m(x - x_0)[/tex]
[tex]y - (-7) = m(x - 9)[/tex]
[tex]y + 7 = m(x - 9)[/tex]
Perpendicular to y = 3x + 4
This line has slope 3, so:
[tex]3m = -1[/tex]
[tex]m = -\frac{1}{3}[/tex]
Thus
[tex]y + 7 = m(x - 9)[/tex]
[tex]y + 7 = -\frac{1}{3}(x - 9)[/tex]
5 x 10 - 2 = ??
HALP MOIIIIIIIIIIIIIIIIIIIIII
Answer:
48
Step-by-step explanation:
the answer is 48 I got this answer by multiplying 5 by 10 and subtracting is from 2 which gives me 50 - 2 which is 48
Answer:
48
Step-by-step explanation:
5×10-2=50-2
=48
hope it helps!!
find the area of the given figure
[tex]\sf \bf {\boxed {\mathbb {GIVEN:}}}[/tex]
Radius of the circle "[tex]r[/tex]" = 5.5 yd
[tex]\sf \bf {\boxed {\mathbb {TO\:FIND:}}}[/tex]
The area of the given figure.
[tex]\sf \bf {\boxed {\mathbb {SOLUTION :}}}[/tex]
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {b. \:47.5\:sq\:yd.}}}}}}[/tex]
[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:EXPLANATION:}}}[/tex]
We know that,
[tex]\sf\pink{Area\:of\:a\:semi-circle}[/tex] = [tex]\frac{\pi \: {r}^{2} }{2} [/tex]
Using 3.14 for π, we have
[tex] = \frac{3.14 \times ( {5.5 \: yd})^{2} }{2} \\[/tex]
[tex] = \frac{3.14 \times 5.5 \times 5.5 \: {yd}^{2} }{2}\\ [/tex]
[tex] = \frac{94.985 \: {yd}^{2} }{2} \\[/tex]
[tex] = 47.5 \: {yd}^{2} \\[/tex]
Using [tex]\frac{22}{7} [/tex] for π,
[tex] = \frac{22 \times 5.5 \times 5.5 \: {yd}^{2} }{7 \times 2} \\[/tex]
[tex] = \frac{665.5 \: {yd}^{2} }{14}\\ [/tex]
[tex] = 47.5 \: {yd}^{2} \\[/tex]
Therefore, the area of the semi-circle is [tex]47.5\: yd²[/tex].
[tex]\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♨}}}}}[/tex]
the points -6/5 and -5/6 will line in which quadrant
A negative x is to the left of the y axis and a negative y value is below the x axis. Any value to the left and below the axis’ will be in the 3rd quadrant.
Answer: 3rd quadrant
Question 1 of 25 f(x) = 2x2 + 6x - 4 g(x) = 5x3 - 6x? - 3 Find (f + g)(x).
Answer:
option B
Step-by-step explanation:
[tex]f(x) = 2x^2 + 6x -4\\\\g(x) = 5x^3 - 6x^2 - 3\\\\(f + g)(x) = f(x) + g(x) \\\\[/tex]
[tex]= (2x^2 + 6x - 4) + ( 5x^3 -6x^2 - 3) \\\\= 2x^2 + 6x - 4 + 5x^3 - 6x^2 - 3\\\\= 5x^3 + 2x^2 - 6x^2 + 6x - 4 - 3 \\\\= 5x^3 - 4x^2 + 6x - 7[/tex]
Answer:
the answer is b
Step-by-step explanation:
hope this helps :)
Consider the following number line:
Answer:
here is your answer
Step-by-step explanation:
b
c
a answer
Mathematics
Evaluate the equations or inequalities. Write the Letter of your answer to the corresponding boxes at the bottom of the page to discover the answer to the title questions.
How does an ESP Expert send his mail?
☐☐☐☐☐☐☐☐☐☐☐☐☐☐☐☐☐☐☐☐☐
7 11 1 8 2 9 11 3 1 8 9 4 6 9 4 9 1 2 10 5
help po.
Step-by-step explanation:
ejdjbd x bxbx k wbu y DJ UK j HK JM dz
nb
santino is renting a canoe from a local shop that charges a $10 fee, plus an hourly rate of $7.50. For how long can santino rent a canoe if he pays a total of $70
Answer:
Santino rented the canoe for 8 hours.
Step-by-step explanation:
The total bill is represented by the formula r(h) = $10 + ($7.50/hour)h,
where h is the number of hours over which the canoe is rented.
If the total bill is $70, then $70 = $10 + ($7.50/hour)h.
Solve this for h. Start by subtracting $10 from both sides, obtaining:
$60 = ($7.50/hour)h.
Dividing both sides by ($7.50/hour), we get:
$60
h = --------------------- = 8 hours
($7.50/hour)
Santino rented the canoe for 8 hours.
How many different 5 digit natural numbers are there starting with odd numbers or ending with even numbers.
A circle has a circumference of 28 centimeters. If an arc subtends a central angle of 55 degrees, what is the arc length?
A.4.28 centimeters
B.26.88 centimeters
C.53.76 centimeters
D.8.56 centimeters
Answer:
s = 4.28 cm (Answer A)
Step-by-step explanation:
1) The formula for the circumference of a circle of radius r is C = 2(pi)r, and this corresponds to a full circle, with central angle 360 degrees.
2) Here the circumference is 28 cm. Therefore, solving for the radius involves the following calculation: 28 cm = 2(pi)r, or
r = (28 cm) / (2 pi), or (28 cm) / 6.28 = 4.46 cm.
3) The arc length s = r(theta), when the central angle (theta) is 55 degrees, is (55/360) times the circumference of the circle: (55/360)(28 cm), or
s = 4.28 cm (Answer A)