Sound will travel fastest in air at _____.
-5°C
0°C
10°C
15°C
The following table lists the speed of sound in various materials. Use this table to answer the question.
Substance
Speed (m/s)
Glass
5,200
Aluminum
5,100
Iron
4,500
Copper
3,500
Salt water
1,530
Fresh water
1,500
Mercury
1,400
Hydrogen at 0°C
1,284
Ethyl Alcohol
1,125
Helium at 0°C
965
Air at 100°C
387
Air at 0°C
331
Oxygen at 0°C
316

Answer:

This link was diagram

Explanation:

https://doubtnut.app.link/FnsNC80Dccb

Answer:

Its velocity

Explanation:

Velocity is speed with a direction.

Speed is the rate at which someone or something is able to move or operate.

In the question its telling us that the bus is going 56 miles per hour but it aslo gives us a direction, in this case is southwest.

Answer:

11.06797181 ms^-1 only.......

Answer:

B

Explanation:

A tractor is the heaviest

Answer:

The positive and negative charges balance each other. Overall, the atom is uncharged (neutral). However, if something happens to make an atom lose or gain an electron then the atom will no longer be neutral. An atom that gains or loses an electron becomes an ion.

Explanation:

I think this is the answer : D

Answer:

208m

Explanation:

since the angle is with the ground which gives a horizontal component to the velocity = v(cos)30°

so the velocity equals 40(cos)30°= 34.64m/s

range(distance) = speed × time

34.64m/s × 6s = 207.8m = 208m

Answer:

1km west

Explanation:

Because if the cyclist is going back 2km then its 3-2=1km

Answer:

3.71 m/s

Explanation:

Given data :

radius of the spherical ball = 0.400 m

Density of the ball material  = 10.65 Kg/m^3

Density of water = 1000 Kg/m^3

Drag coefficient C_d= 0.520

Constant upward force  F_up= 2630

Concept: The moment before it starts to rise Upward force must be equal to downward drag force

⇒ F_up = F_D

F_D =C_d× 0.5 ×ρ_w×V^2×A

where V= terminal velocity and A=  area πR^2

equating the forces we get

2630= 0.52× 0.5×1000×V^2×π(0.4)^2

V= 3.171 m/s

Therefore, the terminal velocity of the ball = 3.71 m/s

The ball while moving through the water in the pool, experiences a drag force. Then, the magnitude of terminal speed during the rise of the ball is 3.171 m/s.

When an object is made to fall through a liquid medium, then the maximum velocity achieved at that instant is known as terminal velocity or terminal speed.

Given data-

The radius of the spherical beach ball is, r = 0.4000 m.

The density of the ball is, [tex]\rho'=10.65 \;\rm kg/m^{3}[/tex].

The density of water in the pool is, [tex]\rho =1000.0 \;\rm kg/m^{3}[/tex].

The drag coefficient of the ball in water is, [tex]C_{d}=0.520[/tex].

The magnitude of the constant upward force is, F = 2630 N.

As per the concept of Buoyancy, "The moment before the ball starts to rise upward force must be equal to downward drag force".

F = Fd

Here,

F is the upward force.

Fd is the downward force.

[tex]F=\dfrac{1}{2} \times C_{d} \times \rho \times v^{2} \times A[/tex]

Here,

A is the area of the ball.

Solving as,

[tex]2630=\dfrac{1}{2} \times 0.520 \times 1000 \times v^{2} \times (\pi r^{2})\\\\2630=\dfrac{1}{2} \times 0.520 \times 1000 \times v^{2} \times (\pi \times 0.4000^{2})\\\\v=3.171 \;\rm m/s[/tex]

Thus, we can conclude that the magnitude of terminal speed during the rise of the ball is 3.171 m/s.

Learn more about the terminal speed here:

https://brainly.com/question/26505185

Answer:

plasma

Explanation:

Cause in the universe many exist in either in gaseous or plasma form but plasma is greater

Answer:

1 m/s

Explanation:

I showed my work in the picture attached.

This web page helped me solve this problem and understand inelastic collisions a little better:

https://byjus.com/physics/inelastic-collision/

She slide(and the ball) backwards at the speed of 1m/s when she catches the ball of 5-kg coming at speed of 17.4 m/s.

Momentum is defined as mass times velocity. it tells about the moment of the body. it is denoted by p and expressed in kg.m/s. mathematically it is written as p = mv. A body having zero velocity or zero mass has zero momentum.  its dimensions is [M¹ L¹ T⁻¹].

Momentum is conserved throughout the motion.

According to conservation law of momentum initial momentum is equal to final momentum.

Given,

mass of the skater m₁ = 82 kg

mass of the ball m₂ = 5kg

initial velocity of the ball v'₂ = 17.4 m/s

initial velocity of the skater v''₂= v'₁= 0

final velocity of the ball & skater = v''₁ = ?

According to law of conservation of momentum,

initial momentum = final momentum

m₁v'₁ +m₂v'₂ = m₁v₁'' + m₂v''₂

putting all values in the equation.

0+ 5×17.4 = 82×v₁'' + 5×v₁''

v₁''(82+5) = 87

v₁'' = 1 m/s

Hence he(and the ball) slide backwards at 1m/s

To know more about conservation of momentum click :

https://brainly.com/question/24301052

#SPJ2

convex lenses.

eyeglasses with convex lenses increase refraction, and accordingly reduce the focal lenght

Answer:

25 (kg) and 40.5 (N).

Explanation:

1) the value of 'g' on the Earth is ~9.81 (N/kg), the value of 'g' on the Moon is ~1.62 (N/kg).

It means, the mass is not depended on the value of 'g', but the weight is depended on it.

2) the mass on the Moon is the same, 25 kg.

the weight is 25*1.62=40.5 N

Answer:

Mechanical Waves

Why I Know:

Science Class

A type of wave that needs a medium to travel is sound wave because it travels through oscillating molecules.

A sound wave can be defined as a form of mechanical wave that requires a medium for its propagation and it creates a disturbance in the medium. Also, the energy of a sound wave travels in a perpendicular direction.

This ultimately implies that, a sound wave needs a medium to travel and it creates a disturbance when it travels through any medium.

In conclusion, a type of wave that needs a medium to travel is sound wave because it travels through oscillating molecules.

Read more on sound wave here: https://brainly.com/question/19250621

Answer:

I dunno

Explanation:

I really wanted to help you, but then I realized i didnt know how to

Complete Question

A child throws a ball with an initial speed of 8.00 at an angle of 40.0° above the horizontal. The ball leaves her hand 1.00 m above the ground and experience negligible air resistance. (a) What is the magnitude of the ball's velocity just before it hits the ground? (b) At what angle below the horizontal does the ball approach the ground?

Answer:

[tex]v=9.16m/s[/tex]

[tex]\theta=48.1 \textdegree[/tex]

Explanation:

From the question we are told that

Angle of ball [tex]\angle=40 \textdegree[/tex]

Height of ball h=1m

Generally the equation for vertical component  is mathematically given by

[tex]v_y=vsin \theta[/tex]

[tex]v_y=8sin 40 \textdegree[/tex]

[tex]v_y=5.14m/s[/tex]

Generally the equation for horizontal component  is mathematically given by

[tex]v_x=vcos \theta[/tex]

[tex]v_x=8cos 40 \textdegree[/tex]

[tex]v_x=6.12m/s[/tex]

Generally the equation for vertical displacement of ball is mathematically given by

[tex]y=1+v-yt-\frac{1}{2}gt^2[/tex]

[tex]0=1+5.14t-\frac{1}{2}*9.87*t^2[/tex]

[tex]t=1.22sec[/tex]

[tex]v_yt=v_yt-gt[/tex]

[tex]5.14-(9.8*1.22)=-6.816m/s[/tex]

[tex]v_yt=-6.816m/s[/tex]

Generally the velocity of ball before it hits the ground is mathematically given by

Magnitude

[tex]v=\sqrt{6.12^2 +(-6.816)^2}\\[/tex]

[tex]v=9.16m/s[/tex]

Direction of  ball

[tex]\theta=tan^{-1}(\frac{-6.816}{6.12} )[/tex]

[tex]\theta=48.1 \textdegree[/tex]  beneath the horizontal

Answer:

To calculate the voltage, current, power and energy for an inductor and also to examine the behavior of an inductor under dc conditions.

an inductor is a passive circuit element that stores energy in its magnetic field.

Explanation:

An inductor has been described as a passive electronic component that stores electrical energy in a magnetic form.  It uses a conductor that is wound into a coil to produce DC current, acting as a short circuit when direct current is applied.  When electricity flows into the coil from the left to the right, a current is generated through a magnetic field in the clockwise direction.  It is also called a choke because of its frequency regulation.

Answer:

12.5 m/s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Height (h) = 8 m

Final velocity (v) at 8 m above the lowest point =?

NOTE: Acceleration due to gravity (g) = 9.8 m/s²

The velocity of the roller coaster at 8 m above the lowest point can be obtained as follow:

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 8)

v² = 0 + 156.8

v² = 156.8

Take the square root of both side

v = √156.8

v = 12.5 m/s

Therefore, the velocity of the roller coaster at 8 m above the lowest point is 12.5 m/s.

Answer:

Think of an object you have observed ... Work with your group to gather evidence that light carries energy, then answer the questions below. Shine the flashlight on the liquid crystal sheet.

Plate tectonic theory is the movement of the plates or slabs of rigid rocks over the surface of the earth or the molten rocks that is the mantel.  

Learn more about plate tectonics and how they have changed Earth.

brainly.com/question/19649061.

Answer:

270 Kg e 130 kg

Explanation:

how many times is the number put together

Answer:

The answer is "[tex]2.352 \ \frac{m}{s}[/tex]"

Explanation:

[tex]\to mass(m_1)=102 \ kg\\\\\to mass(m_2)=10 \ kg \\\\\to v=2.10\ \frac{m}{s}\\\\[/tex]

momentum before:

[tex]\to p=(m_1+m_2)v[/tex]

       [tex]=(102+10)2.10\\\\=(102\times 2.10 +10 \times 2.10)\\\\=214.2+21\\\\=235.2[/tex]

momentum After:

[tex]\to p=(m_1+m_2)v[/tex]

       [tex]=(102\times 0 +10 \times v)\\\\ =(0 +10v)\\\\=10v\\[/tex]

Calculating the conservation of momentum:

[tex]\to \text{momentum before = momentum After}[/tex]

[tex]\to 235.2=10v\\\\\to v= \frac{235.2}{10}\\\\ \to v=2.352 \ \frac{m}{s}[/tex]

For the three-point charges fixed in a right triangle, we have:

1. The magnitude of the electric force on the +1.00 μC charge is 1.79 N.

2. The force does an angle of 21.68° with the x-axis.

First, let's denote the charges as is shown in the picture below:

The magnitude of the electric force on the charge 2 (+1.00 μC) is given by:  

[tex]|F_{net}| = \sqrt{(\Sigma\vec{F}_{x})^{2} + (\Sigma\vec{F}_{y})^{2}}[/tex]  (1)    

Where:  

We can calculate the electrical forces with Coulomb's law:

[tex]\vec{F} = \frac{Kq_{1}q_{2}}{d^{2}}[/tex]

Where:

Forces in the x-axis ([tex]\Sigma\vec{F}_{x}[/tex])

The forces in the x-component are given by:

[tex]\Sigma\vec{F}_{x} = \vec{F}_{21}_{x} + \vec{F}_{23}_{x}[/tex]

[tex]\Sigma\vec{F}_{x} = \vec{F}_{21}_{x}cos(\theta) + \vec{F}_{23}_{x}[/tex]

[tex]\Sigma\vec{F}_{x} = \frac{Kq_{1}q_{2}}{d_{12}^{2}}cos(\theta) + \frac{Kq_{2}q_{3}}{d_{23}^{2}}[/tex]   (2)

Where:              

We can calculate the angle θ with the following trigonometric function:

[tex]sin(\theta) = \frac{y}{z}[/tex]

[tex]\theta = sin^{-1}(\frac{y}{z}) = sin^{-1}(\frac{8.10 cm}{9.60 cm}) = 57.5 ^\circ[/tex]

To find the distance x (d₂₃), we need to use Pythagoras:

[tex]x = \sqrt{z^{2} - y^{2}} = \sqrt{(0.0960 m)^{2} - (0.0810 m)^{2}} = 0.051 m[/tex]

After entering θ and x (d₂₃) into equation 2, we have:

[tex]\Sigma\vec{F}_{x} = \frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}cos(57.5) + \frac{9.00 \cdot 10^{9}Nm^{2}C^{-2}(1.00 \cdot 10^{-6} C)(-0.600 \cdot 10^{-6} C)}{(0.051 m)^{2}}[/tex]

[tex]\Sigma\vec{F}_{x} = [0.78*cos(57.5) + (-2.08) N] = -1.66 N[/tex]

Hence, the x-component of the force is -1.66 N.

Forces in the y-axis ([tex]\Sigma\vec{F}_{y}[/tex])

The only force acting on the y-axis is the y-component of the force F₂₁, so:

[tex]\Sigma\vec{F}_{y} = -\vec{F}_{21}_{y} = -\vec{F}_{21}sin(\theta)[/tex]

The minus sign is because the vector is pointing in the negative y-direction (see the picture below).

[tex]\Sigma \vec{F}_{y} = -\frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}sin(57.5) = -0.66 N[/tex]

Hence, the y-component of the force is -0.66 N.

Finally, the magnitude of the electric force on the charge +1.00 μC is (eq 1):  

[tex]|F_{net}| = \sqrt{(-1.66 N)^{2} + (-0.66 N)^{2}} = 1.79 N[/tex]                                  

Therefore, the magnitude of the electric force on the +1.00 μC charge is 1.79 N.

According to the picture below, the angle of the force with respect to the x-axis is given by:  

[tex]tan(\beta) = \frac{\Sigma\vec{F}_{y}}{\Sigma\vec{F}_{x}}[/tex]

[tex]\beta = tan^{-1}(\frac{-0.66 N}{-1.66 N}) = 21.68 ^\circ[/tex]

Therefore, the force does an angle of 21.68° with the x-axis.

Find more about Coulomb's law here:  

brainly.com/question/506926        

I hope it helps you!                

Answer:

Sexual reproduction you need two organisms to reproduce.

Asexual is when you can multiply yourself and there is nothing different about the offspring and the parent.