Answer:
Parallelogram law of vector addition states that. if two vectors are considered to be the adjacent sides of a parallelogram, then the resultant of the two vectors is given by the vector that is diagonal passing through the point of contact of two vectors.
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A tennis racket hits a tennis ball forward by exerting a force of 55 N on the ball.
What force does the ball exert on the tennis racket during the hit?
A. The ball exerts an equal backward force on the racket.
B. The ball is light, so it exerts almost no force on the racket.
C. The ball causes drag on the racket with a small forward force as it flies away.
D. The ball exerts a smaller force that alternates forward and backward to vibrate the racket.
A 7.50 kg bowling ball moving
6.42 m/s strikes a 1.60 kg bowling
pin at rest. After, the ball moves
5.43 m/s at a 12.0° angle. What is
the x-component and y-component of the pin's final
velocity?
Answer:
Explanation:
To solve this problem we need to know the direction in which the ball was moving to start with.
The answer will be different depending n the original angle of the ball's movement.
It might be reasonable to assume that the ball is meant to approach along the x-axis,
but if so, the initial speed of 6.42m/s would be irrelevant to the answer.
So I will solve the problem for the general case of two objects colliding at arbitrary angles, and
tell you how to specialize it for any assumption about the initial conditions.
Let
m1 = 7.5 kg be the mass of the ball,
m2 = 1.6 kg be the mass of the pin,
v1 = 6.42 m/s be the velocity of the ball before the strike,
v2 = 0 m/s be the velocity of the pin before the strike,
α1 be the angle of v1,
α2 be the angle of v2,
w1 be the velocity of the ball after the strike,
w2 = 14.8 m/s be the velocity of the pin after the strike,
β1 be the angle of w1,
β2 = -47° be the angle of w2.
By conservation of momentum:
m1v1 + m2v2 = m1w1 + m2w2
Since the velocities are vectors, the addition is vector addition, and the equality is vector equality.
"Vector equality" means that the x-coordinates are equal and the y-coordinates are equal.
The problem cares only about y-coordinates, specifically the y-coordinate of w1, which is w1sin(β1).
(In general, the y-coordinate of any vector is obtained by multiplying the vector's norm by the sine of its angle.)
Conservation of momentum in the y-coordinate is then
m1v1sin(α1) + m2v2sin(α2) = m1w1sin(β1) + m2w2sin(β2)
Expressing the sought quantity
w1sin(β1) = (m1v1sin(α1) + m2v2sin(α2) - m2w2sin(β2))/m1
Substituting known quantities:
w1sin(β1) = (7.5×6.42×sin(α1) + 1.6×0×sin(α2) - 1.6×14.8×sin(-47°))/7.5
= (48.15×sin(α1) + 17.3)/7.5
In the above expression we do not know α1.
If we assume that the ball is approaching along the x-axis then α1 = 0, and
w1sin(β1) = 17.3/7.5 = 2.3
Under that assumption the y-component of the ball's final velocity is 2.3 m/s;
being positive, it is opposite the direction of the pin.
A container is filled to a depth of 154.7 cm with water. On top of the water floats a 124.5 cm thick layer of oil with specific gravity 0.754. What is the absolute pressure at the bottom of the container
Gravity, momentum, and friction are examples of:
Answer:
Gravity,momentum & friction are examples of FORCE.
Explanation:
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A ball is thrown upward and let fall down a building. Another identical ball was dropped straight down the building at the same time with the same initial speed as the first ball. How will the velocities of these two balls compare when they each hit the ground? Justify your response.
Answer:
same velocity
Explanation:
energy is conserved-
KE=PE
Discuss the methods of linear measures in Surveying
A motorcycle travels a distance of 420 miles in 8.5 hours. Give the average speed of the motorcycle
Answer:
As per Provided Information
Distance travelled by motorcycle is 420 miles
Time taken by motorcycle is 8.5 hours
we have been asked to determine the average speed of the motorcycle .
[tex] \bf \: Speed_{(Average)} = \cfrac{total \: distance \: travelled}{time \: taken} [/tex]
Now let's put the given value to find the average speed of motorcycle
[tex] \longrightarrow \sf \: Speed_{(Average)} \: = \cfrac{420}{8.5} \\ \\ \\ \longrightarrow \sf \: Speed_{(Average)} \: = \cfrac{4200}{85} \\ \\ \\ \longrightarrow \sf \: Speed_{(Average)} \: = \cancel\cfrac{4200}{85} \\ \\ \\ \longrightarrow \sf \: Speed_{(Average)} \: = 49.41 \: miles \: per \: hour[/tex]
Therefore,
Average speed of the motorcycle is 49.41 miles per hour .A lightbulb uses 98 J of electrical energy every second to produce 10 J of light energy in the same time frame. What is the percent efficiency of the lightbulb in converting electricity into light?
Answer:
10.2 % efficiency.
Explanation:
Percent efficiency formula: (output / input) * 100%
The output energy (in Joules) is how much was used eventually. - It is 10 J
The input energy (in Joules) is how much energy was put into the lightbulb initially. It is 98 J
(10 J / 98 J) * 100% = 10.2 % efficiency.
As a hiker in Glacier National Park, you are looking for a way to keep the bears from getting at your supply of food. You find a campground that is near an outcropping of ice from one of the glaciers. Part of the ice outcropping forms a slope of angle θup to a vertical cliff. You decide that this is an ideal place to hang your food supply, as the cliff is too tall for a bear to reach it. You put all of your food into a burlap sack, tie an unstretchable rope to the sack, and tie another bag full of rocks to the other end of the rope to act as an anchor. The mass of rocks that you put into the anchor bag is equal to the mass of food in the other bag.What will be the acceleration aof the food bag when you let go of the anchor bag? Assume that the weight of the rope is negligible, and that the ice can be considered frictionless.Express the resulting acceleration aof the food bag in terms of θ and g, the acceleration due to gravity. Let the positive direction for this bag be downwards.
Answer: the acceleration is (g( 1 - sinθ)) / 2
Explanation:
the tension in one bag is expressed as;
T = ma + mg sin θ ........................lets say equ 1
now the tension in another bag is expressed as;
T = -ma + mg..................lets say equ 2
so equate both equations
ma + mg sinθ = -ma + mg
2ma = mg ( 1 - sinθ)
a = (g( 1 - sinθ)) / 2
therefore the acceleration is (g( 1 - sinθ)) / 2
the speed of sound in air at a temperature of -40c° ?
Answer:
304.87 m/s
Explanation:
v2 = v1 × √T2÷√T2
v2 = 330 × √233÷√273
v2 = 304.87 m/s
A bus run at 100 km/hr top speed. It can carry a maximum of 6 persons. If speed of bus decreases in fixed proportion with increase in number of person, find speed when three person are traveling in bus.
Answer:
150 km/h
Explanation:
It is given that,
Speed of a bus is 100 km/h and it can carry a maximum of 6 persons.
If speed of bus decreases in fixed proportion with increase in number of person, then we need to find the speed when 3 person are traveling in bus.
6 person = 100 km/h
1 person = (100/6) km/h
Ans
3 person = [tex]\dfrac{100}{6}\times 3=50\ km/h[/tex]
Net speed = 100 km/h + 50 km/h = 150 km/h
Hence, if the required speed is 150 km/h.
does a radio wave have a high or low frequency
Answer:
Low
Explanation:
Radio waves have photons with the lowest energies.
What is the average kinetic energy of a molecule of an ideal gas at temperatures of 27°c? what is the total random kinetic energy of the molecule in 1 mole of this gas .what is the RMS of speed of oxygen molecule .
(a) The average kinetic energy of a molecule of an ideal gas is 6.21 x 10⁻²¹ J.
(b) The total random kinetic energy of the molecule in 1 mole of this gas is 3,741.3 J.
(c) The RMS speed of the oxygen molecule is 215.25 m/s.
Average kinetic energy of ideal gasThe average kinetic energy of a molecule of an ideal gas is calculated as follows;
[tex]K .E = \frac{3}{2} K T[/tex]
Where;
K is Boltzmann constant = 1.38066 x 10⁻²³ J/KT is temperature in Kelvin, = 27°c + 273 = 300 K[tex]K.E = \frac{3}{2} \times (1.38 066 \times 10^{-23}) \times 300\\\\K.E = 6.21 \times 10^{-21} \ J[/tex]
Total random kinetic energyThe total random kinetic energy of the molecule in 1 mole of this gas is calculated as follows;
[tex]K.E = \frac{3}{2} nRT\\\\K.E = \frac{3}{2} (1) (8.314)(300)\\\\K.E = 3,741.3 \ J[/tex]
RMS of speed of oxygen moleculeThe RMS speed of the oxygen molecule is calculated as follows;
[tex]K.E = \frac{1}{2} mV_{rms}^2\\\\V_{rms}^2 = \frac{2K.E}{m} \\\\V_{rms} = \sqrt{\frac{2 K.E}{m} }[/tex]
one mole of oxygen gas = 32 g = 0.032 kg
[tex]V_{rms} = \sqrt{\frac{2 \times 741.3 }{0.032} }\\\\V_{rms} = 215.25 \ m/s[/tex]
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Suppose that a car starts from rest at t = 0. The car moves with an acceleration of 1.5 m/s2. How far will the car travel in 3.0 s?
Answer:
6.75m
Explanation:
To calculate the distance in this question, we can use the formula:
S = ut + 1/2at^2
Where; S = distance
u = initial velocity = 0m/s
t = 3s
a = 1.5m/s^2
Hence:
S = (0 × 3) + 1/2 (1.5 × 3 × 3)
S = 0 + 1/2 (13.5)
S = 13.5/2
S = 6.75
Therefore, the car will travel 6.75m in 3seconds.
To find the distance traveled by the car in 3 seconds is equal to 6.75 meters.
Given the following data:
Initial velocity = 0 m/s (since it starts from rest).Acceleration = 1.5 [tex]m/s^2[/tex]Time = 3 seconds.To find the distance traveled by the car in 3 seconds, we would apply the second equation of motion:
The second equation of motion.Mathematically, the second equation of motion is given by the formula;
[tex]S=ut +\frac{1}{2} at^2[/tex]
Where:
S is the distance traveled.u is the initial velocity.a is the acceleration.t is the time measured in seconds.Substituting the given parameters into the formula, we have;
[tex]S=0(3) +\frac{1}{2} \times 1.5 \times 3^2\\\\S=\frac{1}{2} \times 1.5 \times 9\\\\S = 1.5 \times 4.5[/tex]
Distance, S = 6.75 meters.
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Which event causes the formation of trenches in Earth’s crust?
magma rising
mantle emerging
volcanoes erupting
lithosphere colliding
Answer:
D lithosphere colliding
Reason:
Image result for what causes the formation of trenches in Earth’s crust
Trenches are formed by subduction, a geophysical process in which two or more of Earth's tectonic plates converge and the older, denser plate is pushed beneath the lighter plate and deep into the mantle, causing the seafloor and outermost crust (the lithosphere) to bend and form a steep, V-shaped depression.
The formation of trenches in Earth's crust is caused by the collision of lithospheric plates, so the correct answer is "lithosphere colliding."
What are trenches in Earth's crust?Trenches are long, narrow depressions or canyons in the Earth's crust that form at subduction zones, where one lithospheric plate is forced beneath another plate into the Earth's mantle. Trenches are primarily found on the ocean floor, where they can be several kilometers deep and hundreds of kilometers long.
Trenches are formed by the process of subduction, which occurs when one tectonic plate moves beneath another plate. As the denser plate sinks into the mantle, it creates a deep trench in the ocean floor. This process is associated with volcanic activity, as the sinking plate often triggers the melting of rock in the mantle, which can then rise to the surface and form volcanic islands or arcs.
Trenches are important features of the Earth's crust because they provide evidence for the movement and interaction of tectonic plates over time. Additionally, they are often associated with earthquakes and can serve as warning signs of potential seismic hazards in the surrounding region.
Therefore, lithosphere colliding causes the formation of trenches in Earth’s crust.
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Calculate the current in a circuit if 500 C of charge passes through it in 10 minutes. *
(1 Point)
a) 0.83A
b) 0.083A
c) 8.3A
d) 83A
Answer:
Choice a. Approximately [tex]0.83\; \rm A[/tex] on average.
Explanation:
The electric current through a wire is the rate at which electric charge flows through a cross-section of this wire.
Assume that electric charge of size [tex]Q[/tex] flowed through a wire cross-section over a period of time [tex]t[/tex]. The average current in that wire would be:
[tex]\displaystyle I = \frac{Q}{t}[/tex].
For this question:
[tex]Q = 500\; \rm C[/tex], whereas[tex]t = 10\; \rm \text{minutes}[/tex].Therefore, the average current in this circuit would be:
[tex]\displaystyle I = \frac{Q}{t} = \frac{500\; \rm C}{10\; \text{minutes}} = 50\; \rm C /\text{minute}[/tex].
However, the units in the choices are all in [tex]\rm A[/tex] (for Amperes.) One Ampere is equal to one [tex]\rm C / \text{second}[/tex]. It will take some unit conversations to change the unit of [tex]I = 50\; \rm C/ \text{minute}[/tex] (coulombs-per-minute) to coulombs-per-second.
[tex]\begin{aligned}I &= 50\; \rm C/ \text{minute} \\ &= \frac{50\; \rm C}{1\; \rm \text{minute}} \times \frac{1 \; \text{minute}}{60\; \rm \text{seconds}} \approx 0.83\; \rm C/ \text{second} = 0.83 \; \rm A\end{aligned}[/tex].
Hence, the most accurate choice here would be choice a.
If 2 J of wok is done in raising a 180 g red delicious apple to bring it to your mouth to take a bite of the apple, how far is it lifted?
Answer:
Most likely 2ft
Explanation:
Your arm aint that long
An object started moving with an initial velocity of 10m/s after travelling a distance of 5m gets a velocity of 20m/s find its: (a)acceleration
(b)time taken
Answer: a = 30 m/s^2
t = .33 s
Explanation:
(v final)^2 = (v initial)^2 + 2*a*d → 20^2 = 10^2 + (2)(a)(5) → a = 30 m/s^2
Acceleration = change in velocity / time → 30 = (20 - 10) / t → t = .33 s :)
For a rocket traveling at 12010 m/s, by what factor does its relativistic momentum differ from its ordinary momentum
The relativistic momentum of the rocket differ from the ordinary momentum by a factor of 1.2m.
Relativistic momentum of the rocketThe relativistic momentum of the rocket is calculated as follows;
[tex]P = \frac{mv}{\sqrt{1- \frac{v^2}{c^2} } } \\\\P = \frac{m(12010)}{\sqrt{1- \frac{(12010)^2}{(3\times 10^8)^2} } } \\\\P = 12,011.2 m \ (kgm/s)[/tex]
where;
m is mass of the rocketOrdinary momentum of the rocketThe ordinary momentum of the rock is calculated from the product of mass and velocity of the rocket.
P = mv
P = 12010m (kgm/s)
Difference between the two momentumΔP = 12,011.2m - 12,010m
ΔP = 1.2m
Thus, the relativistic momentum of the rocket differ from the ordinary momentum by a factor of 1.2m.
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An ideal fluid is moving at 3.0 m/s in a section of a pipe of radius 0.20 m. If the radius in another section is 0.35 m, what is the flow speed there
The flow speed of the fluid in the second section of the pipe is 0.98 m/s
What is flow speed?Flow speed is the rate at which the distance of a fluid changes with respect to time as it moves in a pipe.
To calculate the flow speed in the second section, we use the formula below.
Formula:
AV = A'V'............ Equation 1Where:
A = Cross-sectional area of the first section of the pipeV = Velocity of fluid in the first section of the pipeA' = cross-sectional area in the second section of the pipeV' = Velocity of fluid in the second section of the pipe.Make V' the subject of the equation
V' = AV/A'......... Equation 2From the question,
Given:
A = πR² = 0.04π m²V = 3 m/sA' = πr² = (0.35²×π) = 0.1225π m²Substitute these values into equation 2
V' = 3(0.04π)/(0.1225π)V' = 0.98 m/sHence, The flow speed of the fluid in the second section of the pipe is 0.98 m/s
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What effect does the finite of the black paper have on the field?
The effect of black papper on the field is that the black paper have a form of chimney effect. Thid is because the black paper heat up the space between the field and the body in order to allow an upward air current like a chimney. This air current adds to the cooling of the field.
Black paper absorb heat from the surrounding and generate it to current flow in the field.
What is a Field?A field refer to a egion in which each point has a physical quantity like time or gravitational or space which are connected and associated with the region.
Therefore, the black paper allow air current flow.
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A boy pulls a wagon with an applied force of 40 N on frictionless surface. If the mass of the wagon is 13kg, what is the acceleration of the wagon?
Answer:
3.1 m/s²
Explanation:
Apply Newton's second law:
∑F = ma
40 N = (13 kg) a
a ≈ 3.1 m/s²
a person drops two objects from the same height one object weighs 15n and the other weighs 10 n how does the mass of the object relate to the force of gravity on them
Answer:
Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.
Explanation:
sorry if this is wrong or is incorrect... but at least I tried right.
A rope is wrapped three and a half times around a cylinder. Determine the range of force T exerted on the free end of the rope for maintaining equilibrium that is required to just support a 5 kN weight. The coefficient of friction between the rope and the cylinder is 0.2
The range of force exerted at the end of the rope is 285.7 N to 1,000 N.
Net horizontal force of the cylinder
The net horizontal force of the cylinder when it is at equilibrium position is determined by applying Newton's second law of motion.
∑F = 0
F - μFn = 0
F - 0.2(5,000) = 0
F - 1,000 = 0
F = 1,000 N
The strength of the applied force increases as the number of turns of the rope increases.
minimum force = total force/number of turns of rope
minimum force = 1,000/3.5
minimum force = 285.7 N
Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.
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What does the atomic number of an atom tell us?
Answer:
The atomic number uniquely identifies a chemical element. It is identical to the charge number of the nucleus. In an uncharged atom, the atomic number is also equal to the number of electrons. The sum of the atomic number Z and the number of neutrons N gives the mass number A of an atom.
Explanation:
Answer:
I believe that the atomic number of an atom represents the number of protons in one atom of an element. It also tells you the number of electrons in a neutral atom of that element
Explanation:I hope that this is helpful.
Describe Health and Exercise
Answer:
plenty of exercise
Explanation:
If you are unhealthy or not happy with yourself. try this. Do a 30 minute walk everyday and eat normal amounts of food portions a human should have an in a day. Make sure you drink plenty of water. If that doesn't work maybe taking to someone about it and see what information they have for you. These things do work because i was over weight and lost 73 pound just by doing those few things.
1.99 m/s^2 for the first 60.0 m, then decelerates at -0.266 m/s^2 for the final 40.0 m. How much time did the race take?
Time required to complete 60m:-
[tex]\\ \rm\longmapsto s=1/2at^2[/tex]
[tex]\\ \rm\longmapsto 60=1.99/2t^2[/tex]
[tex]\\ \rm\longmapsto 120=1.99t^2[/tex]
[tex]\\ \rm\longmapsto t^2=60.3[/tex]
[tex]\\ \rm\longmapsto t\approx 7.7s[/tex]
Time taken to complete last 40m
[tex]\\ \rm\longmapsto 80=-0.266t^2[/tex]
[tex]\\ \rm\longmapsto t^2=300.75[/tex]
[tex]\\ \rm\longmapsto t\approx 17.3s[/tex]
Total time:-
7.7+17.3=25s(Approx)Answer:
Explanation:
Two kinematics equation
v = u + at
and
s = ut + 1/2(at^2)
where u is initial velocity, v is final velocity, a is acceleration, t is time and s is displacement.
For the first 60m, initial velocity is 0 and acceleration is 1.99.
60 = 0 + 1/2(1.99)t^2
t^2 = 120/1.99
t = 7.765s
Velocity at 60m = 0 + 1.99(7.765) = 15.453 m/s
For the final 40m, initial velocity = 15.453, acceleration is -0.266.
40 = 15.453t' + 1/2(-0.266)t'^2
0.133t'^2 - 15.453t' + 40 = 0
Using the quadratic formula, t' = 2.649s or 113.54s
The solution of 113.54s represents someone running pass the finish line and continuing the deceleration until one runs backwards to the finish line again. So that solution should be rejected.
The total time taken = 7.765 + 2.649
= 10.414s
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Which component uses the core muscles of your stomach?
a. Muscular endurance
b. Flexibility
c. BMI
d. Abdominal endurance
Answer:
a. Muscular endurance
is correct answer
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What is the value of 4p − 2, when p = 8? 16 24 30 34
Answer:
30
Explanation:
Plug in p to get 4(8) - 2
32 - 2 = 30
At constant mass, the __________________ of an object varies (directly, inversely) with the net external force applied. That is to say, that an object’s acceleration increases as the force applied is (decreased, increased), but its acceleration decreases if the force applied is (decreased, increased).
At constant force, acceleration varies (directly, inversely) with mass. When subjected to the same amount of net external force, a heavier object will experience (less, greater) acceleration than a lighter one.