substances can be categorised in two ways: as an element, mixture or compound ora as a solid, liquid or gas. which
of these methods Is of most use ti chemist?​

Answers

Answer 1

Answer:

Most substances on earth are compounds and most interesting chemistry is done with compounds. Most interesting chemistry is done with mixtures of compounds although they often start with pure compounds and then do reactions as mixtures. Most chemistry is carried out in liquid solutions made up of compounds that are solids, liquids, or gases in their pure form.

Explanation:

Answer 2

Here, we are required to determine which of these methods of classifying substances is most important to chemists.

The most useful classification of compounds to chemists is as Elements, Compounds or Mixtures

First classification of substances involves categorising them as pure substances (elements and compounds) or mixtures.

The second classification of substances is categorisation with respect to their state of matter. In essence, we can have solid, liquid or gas.

However, the most useful classification of compounds to chemists is as Elements, Compounds or Mixtures.

This is so because, the type of matter present in Elements are distinct for each element, same as for Compounds and Mixtures formed from a combination of pure substances.

Chemists focus on the diverse properties of substances, as such classification as elements, compounds and mixtures provides a wide basis for the qualitative and quantitative analysis of the properties of substances.

Classification of substances as solid, liquid or gas leaves a narrow avenue for the study of substances as the substance still contains the same type of matter, only this time in different states.

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Related Questions

Which is more precise

164 or 165 if the true value is 167

Answers

165

because it’s closer

How many atoms are in 76.15 grams of fe

urgently needed, will mark brainliest

Answers

Answer:

See below

Explanation:

From periodic table

mole weight of Fe   is   55.845  gm / mole

76.15 gm  /  55.845 gm/mol   *  6.022 x 10^23  atoms/mole =

                8.212 x 10^23   atoms    ( four signif. digits)

What is δs° for the reaction so2(s) no2(g) → so3(g) no(g)? substance s°(j/k • mol) so2(g) 248.5 so3(g) 256.2 no(g) 210.6 no2(g) 240.5

Answers

The value of ΔS° for reaction  is - 22.2 J/K.mol

[tex]SO_{2}(s)+NO_{2} (g)[/tex] → [tex]SO_{3}(g)+NO(g)[/tex]

Calculation,

Given value of S°(J/K.mol) for

[tex]SO_{2}(s)[/tex] = 248.5

[tex]NO_{2} (g)[/tex] = 240.5

[tex]NO(g)[/tex] = 210.6

[tex]SO_{3}(g)[/tex] = 256.2

Formula used:

ΔS° (Reaction) =  ∑S°(Product) - ∑S°(Reactant)

ΔS° = (256.2 + 210.6 ) - ( 248.5 + 240.5) = 466.8 - 489 = - 22.2 J/K.mol

The change in stander entropy of reaction is  - 22.2 J/K.mol. The negative sign indicates the that entropy of reaction is decreases when reactant converted into product.

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The elements of the group IA are termed as alkali metals, because their ___ are alkaline.

Answers

The answer is hydroxides.

The elements of the group IA are termed as alkali metals, because their hydroxides are alkaline.

The formula c₂H₄o can represent?

Answers

Answer:

Ethylene oxide

Explanation:

Ethylene oxide is an organic compound with the formula C2H4O. It is a cyclic either and the simplest epoxied: a three-membraned ring consisting of one oxygen atom and two carbon atoms!

How many moles of carbon are in 7.87x10^7 carbon atoms
?x10^?

Answers

Answer:

1.3 x10^-16

Explanation: answered it in your comments! :)

The soft ionization technique that uses a UV-absorbing compound upon which the analyte of interest is placed and eventually vaporized into a plume of ions directed into the mass analyzer is

Answers

The soft ionization technique that uses a UV-absorbing compound upon which the analyte of interest is placed and eventually vaporized into a plume of ions directed into the mass analyzer is matrix-assisted laser desorption ionization.

What is Soft ionization technique ?

Soft Ionizer produces less fragment ions. Soft ionizer produce the molecular ions or a quasi molecular ion. This technique not fragment the macromolecules into the more smaller charged particles.

Thus from the above conclusion we can say that The soft ionization technique that uses a UV-absorbing compound upon which the analyte of interest is placed and eventually vaporized into a plume of ions directed into the mass analyzer is matrix-assisted laser desorption ionization.

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The molar mass of calcium chloride (CaCl₂) is
110.98 g/mol. If you were to calculate the number
of moles in 23.4 g of CaCl₂, which example shows
the correct way to set up the calculation?
O
23.4 g CaCl₂x.
O
110.98 g CaCl₂
1mole CaCl₂
1 mole CaCl₂
110.98 g CaCl₂
23.4 g CaCl₂x-

Answers

The example that shows the correct way to set up the calculation will be the second example.

Number of moles

Mathematically:

  Number of moles = mass/molar mass

In this case, mass = 23.4 g and molar mass = 110.98 g/mol

Number of moles = 23.4/110.98 = 0.21 moles

Thus, the second example is the correct way.

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In general, which solvent should be used to wash the solid material collected from a filtration?

Answers

The same solvent as the liquid in the original mixture should be used to wash the solid material collected from a filtration.

The solid material which is collected from the filtration is washed by that solvent in which that solid material is dissolved. Generally methanol solvent is used to wash the solid material collected from a filtration.

The filtration is the process in which solid particles present in liquid or gaseous fluid are removed by using of a filter.This filter is only permits or allow only the fluid to pass though it and retain the solid particles.The solid particles left is known as filtrate.

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When 3-methyl-2-butanone undergoes a baeyer-villiger oxidation reaction, the product is:_____.

Answers

When 3-methyl-2-butanone undergoes a baeyer-villiger oxidation reaction, the product is isopropyl acetate and methyl isobutyrate.

The Baeyer-villiger oxidation would seem to be a chemical reaction that uses peroxy acids using peroxides as the oxidant to transform a ketone into an ester or a lactone from such a cyclic ketone.

The main product produced by the Baeyer-Villiger oxidation of camphor using m-CPBA in buffer conditions could be created as a result of the migration of a tertiary bridgehead carbon as opposed to a methylene group.

By the reaction between 3-methyl-2-butanone with m-CPBA , will form isopropyl acetate and methyl isobutyrate.

It reaction can be shown as:

Therefore, when 3-methyl-2-butanone undergoes a Baeyer-villiger oxidation reaction, the product is isopropyl acetate and methyl isobutyrate.

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5.690x10^3 miles to meters and give sig figs
Please help!

Answers

The equivalent of 5.690 × 10³ miles in metres is 9157167 metres. Details about metres and miles can be found below.

How to convert miles to metres?

Miles and metres are both units for measuring distance between two bodies or locations.

However, they can be converted interchangeably as follows:

1 mile = 1609.34 metres

According to this question, 5.690 × 10³ miles can be converted to metres as follows;

5.690 × 10³ × 1609.34 = 9157167 metres.

Therefore, the equivalent of 5.690 × 10³ miles in metres is 9157167 metres.

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If the dissociation constant of a weak acid is 7.1 x 10-5, at what ratio should you adjust the concentration of the weak acid and its conjugate base in order to prepare a buffer that has a pH of 4.15

Answers

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A certain amount of substance has a mass of 120 g and the number of moles is 2. Calculate the molar mass. Group of answer choices

Answers

Answer:

60 g / mole

Explanation:

120 g  / 2 mole   = 60  g/mole

The half-life of silicon-32 is 710 years. If 40 grams is present now, how much will be present in 800 years

Answers

18 g of silicon-32 will be present in 800 years.

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and it's given by

                              [tex]N(t) = N_0 (\frac{1}{2}) ^\frac{t}{t_\frac{1}{2} }[/tex]

where,

[tex]N(t) =[/tex] quantity of the substance remaining

[tex]N_0 =[/tex]  the initial quantity of the substance

[tex]t =[/tex]  time elapsed

[tex]t_1_/_2 =[/tex] the half-life of the substance

From the given information we know:

The initial quantity of silicon-32 is 40 g.

The time elapsed is 800 years.

The half-life of silicone-32 is 710 years.

So, using the calculation above, we can determine how much silicon-32 is left.

                  [tex]N(t) = 40 (\frac{1}{2}) ^\frac{800}{710} \\N(t) = 40 (\frac{1}{2}) ^\frac{80}{71} \\\\N(t) = 18 g[/tex]

Therefore,18 g of silicon-32 will be present in 800 years.

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6. which metal will not be able to be oxidized by any of the other metals listed?

Answers

Metal that won't be oxidized:

Metal that will not be able to oxidize by any of the other metals is gold.

What causes oxidation to happen?

This chemical reaction might take place in the air or after the metal has been in contact with acids or water. The most prevalent example is corrosion of steel, which occurs when the iron molecules on the surface of steel change into iron oxides, most frequently Fe2O3 and Fe3O4.

If you've ever seen a rusted-out vehicle or corroded metal bits, you've witnessed oxidation in action.

Metals that don't oxidize:

In their native condition, noble metals like platinum or gold resist oxidation. Ruthenium, rhodium, palladium, silver, osmium, and iridium are more examples of these metals. Humans have developed a wide variety of corrosion-resistant alloys, including brass and stainless steel.

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A balloon contains a 10% glucose solution. The balloon is permeable to water but not to glucose. A beaker contains a 5% glucose solution. What will happen when the balloon is submerged in the beaker

Answers

The state of the balloon:

When the balloon is submerged in the beaker, the amount of water in the beaker will get reduced.  

What is Osmosis:    

Based on the concentration of solutes on both sides of the membrane, water will flow through a permeable membrane in a specific direction.

Hypertonic solution:

It means that there are more solutes present in the surrounding environment than in the cell itself.

Hypotonic solution:

In a hypotonic solution, the concentration of solutes inside the cell is higher than that outside the cell.

When comparing two solutions, the one with the larger solute concentration is hypertonic, and the one with the lower solute concentration is hypotonic. Isotonic solutions have an identical solute concentration.

While the solution in the beaker is hypertonic, Meaning that will draw water molecules out of the cell. As water molecules move from a location of high water potential (dilute solution) to a region of reduced water potential (10% glucose solution), the water from the 5% glucose solution will flow into the 10% one (concentrated solution)This is the reason why the amount of water decreases when the balloon is submerged in the beaker.

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A chemist develops a medicine
to help patients with thyriod
problems. In which branch of
chemistry is this chemist
working.

Answers

Answer:

Medicinal Chemistry

Explanation:

Medicinal Chemistry deals with the development, design and production of medicines.

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Have a nice day:)

Potassium secretion is linked to:________.
a. sodium reabsorption
b. glucose reabsorption
c. sodium secretion
d. chloride reabsorption
e. chloride secretion

Answers

chloride reabsorption

Cesium-137 has a half life of 30.0 years. If initially there are 8.0 kg of cesium-137 present in a sample, how many kg will remain after 60.0 years

Answers

Mass after 60 years:

2 kg of cesium-137 will remain after 60.0 years.

What is Half-life?

The duration needed for a quantity to decrease to half of its initial value is known as the half-life.

Given:

N0 = is the initial amount of cesium-137 = 8.0 Kg

N = is the amount remaining after a time =  Unknown

t =  Duration of cesium-137 decay in 8.0 Kg = 60 years

t1/2 = half-life of cesium-137 = 30.0 years

Formula = N/No = (1/2)^t/t1/2

After putting the value:

N/8= (1/2)^60/30

N/8= (1/2)^2

N/8= 1/4

4N= 8

N= 8/4

N= 2 Kg

As a result, 2 Kg of cesium-137 will be present after 60 years.

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Which is a type of star system?

Answers

hope my answer is useful..hope my answer is useful..

______ is a naturally occurring metal found in the environment as well as manufactured in products. The major source of this metal has historically been from fuels in on-road motor vehicles such as cars and trucks, and industrial sources.

Answers

Lead is a naturally occurring metal found in the environment as well as manufactured in products. The major source of this metal has historically been fuels in on-road motor vehicles such as cars and trucks, and industrial sources.

Lead: An Air Pollutant

Both naturally occurring in the environment and used in manufactured goods are the metal lead. In the past, industrial sources and fuels used in on-road motor vehicles (such as cars and trucks) have been the main sources of lead emissions. Lead emissions from the transportation industry rapidly reduced by 95% between 1980 and 1999 thanks to regulatory measures in the U.S. to remove lead from gasoline for on-road motor vehicles, while lead levels in the air decreased by 94% over the same period. The areas closest to lead smelters typically have the greatest airborne lead concentrations today. Today, the processing of ores and metals as well as piston-engine aircraft using leaded aviation gasoline are the main sources of lead emissions into the atmosphere.

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What is the de broglie wavelength of an electron (m = 9. 11 × 10-31 kg) moving at a velocity of 3. 0 × 107 m/s?

Answers

the de Broglie wavelength of the electron moving at a velocity of 3. 0 × 107 m/s is 2.4×10∧-11nm

lambda = h/mv

The de Broglie wavelength is defined as follows: lambda = h/mv, wherein the greek letter lambda represents the wavelength, h is Planck's consistent, m is the particle's mass and v is its pace. One may also explicit mv as the particle's momentum

according to wave-particle duality, the De Broglie wavelength is a wavelength manifested in all the gadgets in quantum mechanics which determines the chance density of locating the item at a given factor of the configuration area. The de Broglie wavelength of a particle is inversely proportional to its momentum

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The combustion of hydrogen gas releases 286 kJ per mol of hydrogen. If 13.0 L of hydrogen at STP was burned to produce electricity, how long would it power a 100-watt (W) light bulb

Answers

Combustion of hydrogen produces electricity:

It would power a 100-watt (W) light bulb in 27.66 min.

Calculation:

At STP conditions, we know that 1 mole of any gas is contained in 22.4L.

So let's make the operation:

The volume of one mole of gas at STP is 22.4 L

Then, 13.0 L may be the volume for (13.0) /22.4  = 0.58 moles.

The total energy is released = 0.58 x 286 kJ

Total energy = 165.98 kJ

Energy = Power x time

Time = energy / power

where power = 100W = 100 J/s

Therefore, Time = 165.98 kJ/ 100J/s = 1659.8 sec

Time = 1659.8 sec / 60 min = 27.66 min

∴ Time = 27.66 min

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A sample of propane (C3H8) has a mass of 0.47 g. The sample is burned in a bomb calorimeter that has a mass of 1.350 kg and a specific heat of 5.82 J/(g • °C). How much energy is released by the reaction if the temperature of the calorimeter rises by 2.87°C?
Use q equals m C subscript p Delta T..
7.85 kJ
10.6 kJ
22.5 kJ
47.9 kJ

Answers

Propane is burned in a 1.350-kg bomb calorimeter with a specific heat of 5.82 J/g.°C. For a temperature rise of 2.87 °C, the energy released is 22.5 kJ.

What is a bomb calorimeter?

It is a device that can measure heats of combustion, used in various applications such as calculating the calorific value of foods and fuels.

A sample of propane is burned in a bomb calorimeter with a mass (m) of 1.350 kg and a specific heat (c) of 5.82 J/g.°C. All the energy released by the propane is absorbed by the bomb calorimeter.

If the temperature rises by 2.87 °C (ΔT), we can calculate the energy released (Q) using the following expression.

Q = c × m × ΔT = 5.82 J/g.°C × 1,350 g × 2.87 °C × (1 kJ/1000 J)

Q =  22.5 kJ

Propane is burned in a 1.350-kg bomb calorimeter with a specific heat of 5.82 J/g.°C. For a temperature rise of 2.87 °C, the energy released is 22.5 kJ.

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Answer:

22.5 kj

Explanation:

Gaseous nitrogen dioxide dissolved in warm liquid water to form hno3 and gaseous nitrogen monoxide enter a balanced equation for this reaction

Answers

Answer:

3 NO₂ (g) + H₂O (l) ---> 2 HNO₃ (aq) + NO (g)

Explanation:

Gaseous nitrogen dioxide = NO₂ (g)

Liquid water = H₂O (l)

Because the reactants are dissolved = HNO₃ (aq)

Gaseous nitrogen monoxide = NO (g)

In order for a reaction to be balanced, there needs to be an equal amount of each type of atom on both sides of the equation. The equation can be balanced by adding coefficients to modify the quantities of certain compounds.

The unbalanced equation:

NO₂ (g) + H₂O (l) ---> HNO₃ (aq) + NO (g)

Reactants: 1 nitrogen, 3 oxygen, 2 hydrogen

Products: 2 nitrogen, 4 oxygen, 1 hydrogen

The balanced equation:

3 NO₂ (g) + H₂O (l) ---> 2 HNO₃ (aq) + NO (g)

Reactants: 3 nitrogen, 7 oxygen, 2 hydrogen

Products: 3 nitrogen, 7 oxygen, 2 hydrogen

It is a long tube-like canal ,also called alimentary canal where digestion take place.

Answers

Explanation:

The alimentary canal is the long tube of organs - including stomaches and intestines

Answer: digestive strat.

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Experiment 1: in the synthesis reaction, the white powder produced is magnesium oxide (mgo, mm = 40.3 g/mol). how many moles (n) of magnesium oxide were formed? select the closest answer.

Answers

1.98 moles of Magnesium oxide were formed.

What is Balanced Chemical Equation ?

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now write the balanced chemical equation

2Mg + O₂ → 2MgO

(2 × 24)          2 × (24 + 16)

48 g of Mg gives 80 g of MgO

How to find the number of moles ?

To find the number of moles use the expression

Number of moles = [tex]\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

                              = [tex]\frac{80}{40.3}[/tex]

                              = 1.98 mole

Thus from the above conclusion we can say that 1.98 moles of Magnesium oxide were formed.

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Based on their composition and structure list, CH2Cl2, CH3CH2CH3, and CH3CH2OH in order of: a. Increasing intermolecular forces b. Increasing viscosity c. Increasing surface tension

Answers

Based on their composition and structure list CH₂Cl₂, CH₃CH₂CH₃ and CH₃CH₂OH in order of (a) Increasing order of Intermolecular Forces are CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH. (b) Increasing order of Viscosity are CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH. (c) Increasing order of Surface Tension are: CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH.  

What is Intermolecular Forces ?

Intermolecular forces often abbreviated to IMF (or Secondary force) are the forces that hold atoms together with in a molecule. These forces are electrostatic in nature and exist between molecules.

Increasing order of Intermolecular Forces are: CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH.

How Intermolecular forces affect Viscosity ?

Higher the intermolecular force then higher the viscosity. Stronger the intermolecular force then stronger the viscosity.          

Increasing order of Viscosity are: CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH.    

How Intermolecular forces affect Surface tension ?

Stronger the intermolecular forces of liquid have higher surface tension. Surface tension depend upon the intermolecular forces.

Increasing order of Surface Tension are: CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH.  

Thus from the above conclusion we can say that Based on their composition and structure list CH₂Cl₂, CH₃CH₂CH₃ and CH₃CH₂OH in order of (a) Increasing order of Intermolecular Forces are CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH. (b) Increasing order of Viscosity are CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH. (c) Increasing order of Surface Tension are: CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH.  

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Help me pls!!!!!!!!!!!!!!!!!!!!!

Answers

The liberated electron will have 10.28 eV kinetic energy.

Given that light of frequency 3.62 × [tex]10^{15}[/tex] Hz strikes a surface of copper metal with work function([tex]W_{0}[/tex]  = 4.70 eV).

The incident (photon) energy given as hf (Planck's Constant time's frequency) minus the energy that "binds" the electron to the metal (the work function) will equal the maximum kinetic energy of the emitted electron.

K.E. = hf − ϕ

Where K = Kinetic energy

h = Planck's constant = 6.62607015 × [tex]10^{-34}[/tex] J s

f = frequency = 3.62 × [tex]10^{15}[/tex] Hz

ϕ = 4.70 eV = 4.7 × 1.6 × [tex]10^{-19}[/tex] = 7.52 × [tex]10^{-19}[/tex]

K.E. = 6.62607015 × [tex]10^{-34}[/tex] × 3.62 × [tex]10^{15}[/tex] - 7.52 × [tex]10^{-19}[/tex]

       = 6.62607015 × 3.62 × [tex]10^{-19}[/tex] - 7.52 × [tex]10^{-19}[/tex]

       = 23.98 × [tex]10^{-19}[/tex] - 7.52 × [tex]10^{-19}[/tex]

K.E. = 16.46 × [tex]10^{-19}[/tex] J = 10.28 eV

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Blank + 3Fe, reaction arrow, Fe3O4+4H2
How to complete this equation so that it is a Single displacement reaction

Answers

The complete reaction equation is [tex]3Fe + 4H_2O -- > Fe_3O_4 + 4H_2[/tex]

What are single displacement reactions?

They are reactions in which one of the elements in a reactant is displaced by another element in the product.

In the reaction leading to the production of [tex]Fe_3O_4[/tex], Fe displaced H atoms from [tex]H_2O[/tex].

Thus, the equation of the reaction is as follows:

[tex]3Fe + 4H_2O -- > Fe_3O_4 + 4H_2[/tex]

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fuzzy set has a graphical description that expresses how the transition from one to another takes place. This graphical description is called a membership___ Find the arc length of the curve below on the given interval.x=(y^4/4)+(1/8y^2) for 2 Determine if the set is a basis for R3. Justify your answer. -1 -4 7 0 -7 -5 -2 - 11 3 Is the given set a basis for R3? A. No, because these vectors do not form the columns of a 3x3 matrix. A set that contains more vectors than there are entries is linearly dependent. B. Yes, because these vectors form the columns of an invertible 3x3 matrix. A set that contains more vectors than there are entries is linearly independent. C. Yes, because these vectors form the columns of an invertible 3 x 3 matrix. By the invertible matrix theorem, the following statements are equivalent: A is an invertible matrix, the columns of A form a linearly independent set, and the columns of A span R". D. No, because these vectors form the columns of a 3x3 matrix that is not invertible. By the invertible matrix theorem, the following statements are equivalent: A is a singular matrix, the columns of A form a linearly independent set, and the columns of A span R". a coin is flipped 5 times. each outcome is written as a string of length 5 from {h, t}, such as thhth. select the set corresponding to the event that exactly one of the five flips comes up heads. what type of immune disorder is characterized by antibodies that attack ones own body cells and tissues? A line has vector form r(t) 2, 0) (3,-5) Find the coordinate functions The coordinate functions of the line parametrized by: r(t) - (6t- 1,9t+ 2). are x(t) The y-coordinate of the line, as a function of t, is y(t) = maternal effect gene products are most likely going to affect what stage in development? a. specification b. differential transcription c. activation d. determination e. differentiation how many signals would you expect to see in the proton nmr spectrum of the following compound? please input a numerical (e.g., 1, 2, 3, 4, etc.) response. a nurse is collecting data on a client who has received a preoperative dose of morphine kellen and thomas are mistaken as to the facts surrounding their contract. what is absent when a mistake of fact occurs? find the code polynomial (in systematic form) for m(x) = 1 x^2 x^4 estimate the tkn associated with a sample having 50 mg/l of cell tissue and 10 mg/l of ammonia. assume cell tissue has a molecular composition of c5h7o2n biological rhythms are controlled by biological clocks, which include which of the following? a.Annual cycles b.Twenty-four hour cyclesc.Sleep cycles Using the following assumptions, determine the solids retention time, the cell wastage flow rate, and the return sludge flow rate for the ACME Hospital WWTP.Assume:Allowable BOD5 in effluent = 25.0 mg/LSuspended solids in effluent = - 20.0 mg/LWastage is from the return sludge lineYield coefficient = 0.55 mg VSS/mg BODs removedDecay rate of microorganisms = - 0.065 d^-1Inert fraction of suspended solids = -55.5% if you can assume that a variable is at least approximately normally distributed, then you can use certain statistical techniques to make a number of ____ about the values of that variable desai industries is analyzing an average-risk project, and the following data have been developed. unit sales will be constant, but the sales price should increase with inflation. fixed costs will also be constant, but variable costs should rise with inflation. the project should last for 3 years, it will be depreciated on a straight-line basis, and there will be no salvage value. no change in net operating working capital would be required. this is just one of many projects for the firm, so any losses on this project can be used to offset gains on other firm projects. what is the project's expected npv? do not round the intermediate calculations and round the final answer to the nearest whole number. pretty much any attempt to guess the contents of some kind of data field that isnt obvious (or is hidden) is considered a(n) __________ attack. what european country has heavily influenced the philippines because it once controlled its islands? You find that the patient's neurologic function is rapidly improving.Is this patient still a candidate for fibrinolytic therapy? (7%) Problem 8: Consider a conducting rod of length 32 cm moving along a pair of rails, and a magnetic field pointing perpen Lynch, Michael Smit - maynchroemion du the pic20-9027590, dance with pet TAY Thief Servicelog this information to any solutions whis Domayin of you let TA A & At what speed (in m/s) must the sliding rod move to produce an emf of 0.85 V in a 1.55 T field? Grade Summary Deductions 03 Potential 1005 sin) cos tan al 7 89 Submissions cotan asino acos 4 5 16 Attempts remaining per attempo atan acotan sinh 1 2 3 detailed view cosho tanh cotanho + - 0 Degrees Radians VO Submit Hint I give up! Hints: 0 deduction per hint. Hints remaining 4 Feedback: 0. deduction per feedback.