Sugar for domestic use is usually purchased in 2,5kg. Calculate the sugar required in the recipe ,as a percentage,of the quantity usually purchased by a household

Answers

Answer 1

The values, we get ; Percentage = (0.5/2.5) x 100= 20%.Therefore, the sugar required in the recipe is 20% of the quantity usually purchased by a household.

When given a recipe, it is essential to know how to convert the recipe from the metric to the US customary system and then to a percentage. For domestic purposes, sugar is usually purchased in 2.5kg. We can calculate the sugar required in the recipe as a percentage of the amount usually purchased by the household using the following steps:

Step 1: Convert the sugar required in the recipe from grams to kilograms.

Step 2: Calculate the percentage of the sugar required in the recipe to the quantity purchased by a household, usually 2.5 kg.  Let's say the recipe requires 500g of sugar.

Step 1: We need to convert 500g to kg. We know that 1000g = 1kg, so 500g = 0.5kg.

Step 2: We can now calculate the percentage of the sugar required in the recipe as a percentage of the amount usually purchased by a household, which is 2.5kg.

We can use the following formula: Percentage = (amount of sugar required/quantity purchased by household) x 100. Substituting the values, we get; Percentage = (0.5/2.5) x 100= 20%.Therefore, the sugar required in the recipe is 20% of the quantity usually purchased by a household.

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Related Questions

It cost Cai $1,80 to send 12 text messages, How much would it cost to send 90 text
messages?

Answers

Answer:

$13.5

Step-by-step explanation:

cost of 1 text message= $1.80÷12 =$0.15

cost of 90 messages = $0.15×90 = $13.5

Answer: $13.50 for 90 text messages

Step-by-step explanation:

$0.15×90 = $13.5

$0.15 is the unit rate for 1 text message cost.

HELP FAST‼️‼️
Jessenia usually earns $25 each week.
Last week, she received an extra $20 in
bonus. What percent of her usual weekly
income was her total income last week?

Answers

Normal income: 25 $

Last week's income: 25 + 20: 45 $

% = Last week's/normal = 45/25 ×100 =180 %

Find the other endpoint of the line segment with the given endpoint -5, 2 and midpoint 2, -5

Answers

Answer:

( 9, -12 )

Step-by-step explanation:

Mario's Math Tutoring

you have the midpoint

2, -5

use the midpoint formula

(x1+x2)/2 , (y1+y2)/2

to get the endpoint

x :

(-5+x2)/2 = 2

(-5+x2) = 4

-5+x2 = 4

x2 = 9

y:

(2+y2)/2 = -5

(2+y2) = -10

2+y2 = -10

y2 = -12

Thank you Mario!

Which algebraic expression has a term with a coefficient of 9?
• A. 6 + X- 9
• B. 6x - 9
C. 6(x + 5)
• D. 9x ÷ 6

Answers

[tex]\textbf{ Heya !}[/tex]

Your Answer Is:-

[tex]\sf{9x\div6}[/tex]

because,

               it has a coefficient of 9 (a number that comes before a variable)

`hope that was helpful to u ~

The Awnser is b I believe

Find the area of each of these rectangles

Answers

a) 5 square root (2) units square
b) 6 units square
c) 36 units square

What is the measure of arc QR?

Answers

Answer:

answer is the third choice : 104

Step-by-step explanation:

Inscribed Angle Theorem

If an angle is inscribed in a circle, then the measure of the angle equals one half the measure of its intercepted arc.

so the intercepted arc is TWICE the measure of an angle inscribed in a circle

1. A central angle is an angle with endpoints located on a circle's circumference and vertex located at the circle's center. A central angle in a circle determines an arc.

2. An inscribed angle is an angle formed by three points on the circle's circumference.

Angle at the Center Theorem: An inscribed angle is half of the central angle (if they determine the same arc).

In your case angles:

1. ∠QSR is insribed (determines the arc QR);

2. ∠QTR is central (determines the arc QR).

Then by Angle at the Center Theorem, m∠QTR=2m∠QSR=2·52°=104°. Arc QR has the same measure as central angle QSR.

gathmath

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someone please help me with question #14 !!!

Answers

Answer: a, c, e

Step-by-step explanation:

a) True. If x=0, f(0)=c.

b) False. Considering the quadratic formula, we know the solutions are not always x=c.

c) True. This is a standard fact.

d) False. If the discriminant is not positive, there are less than two x-intercepts.

e) True. If you plug into the formula [tex]x=-\frac{b}{2a}[/tex], if b=0, then obviously the x-coordinate of the vertex is also 0.

True or false, if a domain is restricted to x > 1, then there will be an open circle at x = 1.

Answers

Answer:

Step-by-step explanation:

true

Can you plssss help !!!

Answers

The parts of the circle shown in the image include, chord, diameter, radius, tangent and center point.

Parts of the circle shown in the image

The following are the parts of the circle shown;

Chord: the length DC and DG represent the chord of the circleDiameter: the length HF represent the diameter of the circleRadius: the length HA and FA represents the radius of the circletangent: the line JB represents a tangent to the circleCenter: point A represents the center of the circle

Thus, the parts of the circle shown in the image include, chord, diameter, radius, tangent and center point.

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If sin (90° - α) = BC /CA,write down the ratio of sina.​

Answers

Answer:

Step-by-step explanation:

sin(90-a)=cos

cos = angle adjacent

theta=BC/CA

The length of a rectangle is 3 less than twice the width. Determine how the area will change if the length of the rectangle is increased by 5 and the width is decreased by 2. Show your work.

Answers

The change in the area is represented by the expression ΔA = 9 · x + 4, where x is the original width of the rectangle.

What is the change in the area of the rectangle if side lengths are changed?

By geometry we know that the area of a rectangle is equal to the product of its width (x) and length (y). Based on the statement, the original rectangle is equal to:

A = x · y

A = x · (2 · x - 3)

And the change in the area is:

A + ΔA = (x + Δx) · (y + Δy)

A + ΔA = x · y + Δx · y + Δy · x + Δx · Δy

ΔA = Δx · y + Δy · x + Δx · Δy

ΔA = (2 · x - 3) · Δx + Δy · x + Δx · Δy

ΔA = 2 · (2 · x - 3) + 5 · x + 10

ΔA = 9 · x + 4

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Please answer questions three to five!

Answers

The computation shows that the amount that will be charged will be $5.00 and $9.00 respectively.

How to illustrate the information?

When the customer has a 6 pound Chihuahua, the amount that will be charged will be $5.00.

When a customer has a 65 pound Labrador, the amount that will be charged is $9.00.

This is illustrated as the cost is based on the weights given.

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Lowest common multiple of 12,18,56

Answers

Step-by-step explanation:

12 = 2 × 2 × 3

18 = 2 × 3 × 3

56 = 2 ×2 × 2 × 7

Now

Common factor = 2

Remaining factor = 2 × 3 × 2 × 3 × 7

LCM = RF × CF

= 504

hence the lCM of 12 , 18 and 56 is 504...

[tex]...[/tex]

504 IS THE ANSWER .. . . . . . . . . . . ††††††††††††††††††††††††††††††††††††††††††††††

A construction company buys a certain number of boxes of nails depending on how many houses they plan to build in a year. They have 5 boxes left over from the previous year and predict that this year they will need 3 boxes per house. Write an equation where y represents the number of boxes they need to purchase and x the number of houses they plan to build.

Answers

Answer:

Step-by-step explanation:

43

I dont exactly know if this is correct sorry if its wrong

Segment ab falls on line 6x 3y = 9. segment cd falls on line 4x 2y = 8. what is true about segments ab and cd? they are parallel because they have the same slope of −2. they are perpendicular because they have slopes that are opposite reciprocals of −2 and one half. they are parallel because they have the same slope of 2. they are perpendicular because they have opposite reciprocal slopes 2 and negative one half.

Answers

They are parallel because they have the same slope of 2.

How to determine the true statements about the segments?

The segments are given as;

AB => 6x - 3y = 9

CD => 4x - 2y = 8

We start by making y the subject of both equations

AB => 6x - 3y = 9

-3y = -6x + 9

Divide through by -3

y = 2x - 3

CD => 4x - 2y = 8

-2y = -4x + 8

Divide through by -2

y = 2x - 2

A linear equation is represented as:

y = mx + b

Where m represents the slope of the line.

By comparing the three equations, we have:

m1 = 2

m2 = 2

Parallel lines have equal slopes.

This means that the lines AB and CD are parallel lines

Hence, they are parallel because they have the same slope of 2.

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Answer: They are parallel because they have the same slope of 2.

Step-by-step explanation:vvvvvvvvvvvvvvvvvvvvv

help me!!!
please I am in a rush

Answers

Answer:

A= 54

B=3

Step-by-step explanation:

I hope this helps!

A group of students consists of four people in all; two women and two men. They agree to take turns taking notes in lecture. One person at a time will be selected at random from the group (without replacement) until everyone has had a turn. The expected value of the number of people selected before and including the first time a woman has a turn is (Q17)______ .
The standard error of the number of people selected before and including the first time a woman has a turn is (Q18)______ .

Answers

The expected value of the number of people selected before and including the first time a woman has a turn is 1.6667 and the standard error is 0.7454.

How to illustrate the information?

It should be noted that the expected value will be:

1[p(x = 1)] + 2[p(x = 2)] + 3[p(x = 3)]

= 1(0.5) + 2(0.3333) + 3(0.1667)

= 1.6667

Var(X) = E(X²) - E(X)2

= 3.3335 & (1.6667)²

= 0.555611

The standard error will be:

= ✓0.555611

= 0.7454

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A safe has a 4-digit lock code that does not include zero as a digit and no digit is repeated. what is the probability that the lock code consists of all even digits?

Answers

Probability that the lock code consists of all even digits is [tex]1344[/tex] if we choose the [tex]4[/tex] digit lock is randomly from numbers [tex]1,2,3,4,5,6,7,8,9[/tex]

How can we find the probability that the lock code consists of all even digits?

Total numbers are [tex]1,2,3,4,5,6,7,8,9[/tex]

And we choose [tex]4[/tex] digit code

So probability of choosing [tex]4[/tex] numbers from [tex]9[/tex] numbers without reapitation is

[tex]9p_{4} =\frac{9!}{(9-4)!} \\=\frac{9*8*7*6*5!}{5!} \\=3024[/tex]

For All numbers are even , probability the last digit of number is even.

So we have [tex]4[/tex]  even number and if we fix one on last digit and can change other [tex]3[/tex] then the probability is

[tex]4*8P_{3} =4*\frac{8!}{(8-3)!} \\=4*\frac{8*7*6*5!}{5!} \\=1344[/tex]

So the total probability of code lock having all even number is [tex]1344[/tex]

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You and a friend are playing a game of chance. Every time you roll a 1 or 2 you are successful, and your friend will pay you $1. Every time you roll (using a fair die) a 3, 4, 5 or 6, you must pay your friend $2. If 71% of your rolls are successful and 29% of your rolls are unsuccessful, how much money do you expect to have earned/owed by the end of the game

Answers

Considering the mean of a discrete distribution, you are expected to earn $0.13 by the end of the game.

What is the mean of a discrete distribution?

The expected value of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.

Since 71% of your rolls are successful and 29% of your rolls are unsuccessful, the distribution of your earnings is:

P(X = 1) = 0.71.P(X = -2) = 0.29

Hence the expected value is:

E(X) = 1 x 0.71 - 2 x 0.29 = 0.71 - 0.58 = 0.13

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Need help with explanation on solving this problem.

Answers

Answer:

x=27.80

Step-by-step explanation:

we know that cosA=base/hypotaneous

so,

[tex]cos44 = \frac{20}{x} \\ x = \frac{20}{cos(44)} \\ = \frac{20}{0.7193...} \\ = 27.80 [/tex]

In apirl is rained 1/4 of a inch on 15 diffret day how many inches of rain fell

Answers

In [tex]15[/tex] diffret days [tex]15/4[/tex] inches of rain fell in April month if every day rained [tex]1/4[/tex] of a inch .

How to find the rain fell in [tex]15[/tex] diffret days ?

We know that rain in every day is [tex]1/4[/tex] of a inch

So for [tex]15[/tex] days

[tex]1/4+1/4+1/4+......15times\\=15/4[/tex]

So in [tex]15[/tex] diffret days in April rain fell is [tex]15/4[/tex] inches.

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The reciprocals of what three different positive integers have sum equal to 1?

Answers

Answer:

1/a + 1/b + 1/c = 1 , a,b,c is nonzero

Step-by-step explanation:

bc +ac +ab /abc = 1

bc + ac + ab = abc

a = b = c = 1

A has the coordinates (-4, 3) and B has the
coordinates (4, 4). If Do,1/2(x, y) is a dilation of AABC,
what is true about the image AA'B'C'? Check all that
apply.

Answers

If [tex]$D_{o,\frac{1}{2}} \frac{1}{2} (x, y)[/tex] exists a dilation of △ ABC, the facts regarding the image

△A'B'C' exist AB exists parallel to A'B'.

What is a coordinate plane?

Any point in the coordinate plane exists directed by a point (x, y), where the x value exists the position of the point with respect to the x-axis, and the y value exists the position of the point with respect to the y-axis.

A dilation exists a transformation [tex]$D_{o,k} \frac{1}{2} (x, y)[/tex], with center O and a scale factor of k that exists not zero, that maps O to itself and any other point P to P'. The center O exists as a fixed point, P' exists as the image of P, and points O, P, and P' exist on the exact line.

In a dilation of [tex]$D_{o,\frac{1}{2}} \frac{1}{2} (x, y)[/tex], the scale factor, 1/2 exists mapping the original figure to the image in such a manner that the distances from O to the vertices of the image exist half the distances from O to the original figure.

Also, the size of the image exists half the size of the original figure.

If [tex]$D_{o,\frac{1}{2}} \frac{1}{2} (x, y)[/tex] exists a dilation of △ ABC, the facts regarding the image △A'B'C' exist AB is parallel to A'B'.

[tex]$D_{o,k} \frac{1}{2} (x, y) = (\frac{1}{2} x, \frac{1}{2}y)[/tex]

The distance from A' to the origin exists half the distance from A to the origin.

Therefore, the correct answer is option A). △ A'B'C' exist AB is parallel to A'B'.

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4x-6y=-20
-2x+4y=6
8th grade pre algebra

Answers

The values of x and y that are solutions to the simultaneous equations are; x = -11 and y = -4

How to Solve Simultaneous Equations?

We are given the simultaneous equations;

4x - 6y = -20   -----(eq 1)

-2x + 4y = 6     -----(eq 2)

Multiply equation 2 by 2 and eq 1 by 1 to get;

-4x + 8y = 12     -----(eq 3)

Add eq 3 to eq 1 to get;

2y = -8

y = -4

Thus;

4x - 6(-4) = -20

4x + 24 = - 20

4x = -20 - 24

4x = -44

x = -44/4

x = -11

Thus, the values of x and y that are solutions to the simultaneous equations are; x = -11 and y = -4

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Suppose the variable x is represented by a standard normal distribution. What value of x is at the 40th percentile of the distribution

Answers

The value value of x is at the 40th percentile of the distribution is 0.65.

The standard normal distribution is a normal distribution with a mean of zero and standard deviation of 1. The standard normal distribution is centered at zero and the degree to which a given measurement deviates from the mean is given by the standard deviation

Given:- μ[tex]_X[/tex]=0,σ[tex]_X[/tex]=1

We can standardize the random variable: Z=(X−μx)/σx,

Then the equation is P(X≤ x )=Φ(x−μx/σx)=Φ(x−0/1)=0.4

Inverse function

Ф[tex]\\^{-1}[/tex](0.4) = [tex]\frac{x-0}{1}[/tex]

From the table we get,

Ф[tex]^{-1}[/tex] = 0.65

Thus

[tex]\frac{x-40}{10}[/tex] = 0.65

x -0 = 0.65

x = 6.5

Thus the value value of x is at the 40th percentile of the distribution is 0.65

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Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its mean number of unoccupied seats per flight over the past year. To accomplish this, the records of 225 flights are randomly selected and the number of unoccupied seats is noted for each of the sampled flights. The sample mean is 11.6 seats and the sample standard deviation is 4.1 seats. Assume the underlying population of unoccupied seats is normally distributed. Using a t- statistic, construct a 95% confidence interval for the population mean number of unoccupied seats per flight.

Answers

The given sample's 95% confidence interval is 11.6 ± 0.5357. I.e., from the lower bound 11.06 to the upper bound 12.14. Its margin error is 0.5357.

How to find the confidence interval?

To find the confidence interval C.I,

Determine the mean(μ) of the sampleDetermine the standard deviation(σ)Determine the z-score for the given confidence level using the z-score tableUsing all these, the confidence interval is calculated by the formula,  C. I = μ ± z(σ/√n) where n is the sample size and z(σ/√n) gives the margin error. So, we can also write C. I = mean ± margin error.

Calculation:

It is given that,

Sample size n = 225

Sample mean μ = 11.6

Standard deviation σ = 4.1

Since 95% confidence interval, z-score is 1.96

So, the required confidence interval is calculated by,

C. I = μ ± z(σ/√n) or mean ± margin error

On substituting,

C. I = 11.6 ± 1.96(4.1/√225)

     = 11.6 ± 1.96 × 0.2733

     = 11.6 ± 0.5357

So, the lower bound = 11.6 - 0.5357 = 11.065 and

the upper bound = 11.6 + 0.5357 = 12.135.

Thus, the confidence interval is from 11.06 to 12.14, and its margin error is 0.0537 for the population mean number of unoccupied seats per flight.

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Elena is making an open-top box by cutting squares out of the corners of a piece of paper that is 11 inches wide and 17 inches long, and then folding up the sides. If the side lengths of her square cutouts are inches, then the volume of the box is given by V(x)=(11-2x)(17-2x).
There are 4 questions in the bottom! Please solve and explain them for me!
Thank youuu

Answers

See below for the solution to each question

The reasonable domain of V(x)

From the graph, we can see that:

V(x) have a positive value from x > 0 to x < 5.5

When x = 0 and ≥ 5.5, the values of V(x) are either 0 or negative

Hence, the reasonable domain of V(x) is 0 < x < 5.5

The value of x that gives the maximum volume

From the graph, the maximum value of V(x) is at

V(2) = 182

Hence, the approximate value of x that gives the maximum volume is 2

The values of x where the volume increases

This is the interval where V(x) increase as x increase

From the graph, V(x) increase from x > 0 to x = 2

Hence, the approximate values of x where the volume increases are 0 < x ≤ 2

The interpretation of the point of intersection

The other function is

B(x) = 140

So, the point of intersection represent where the volume is 140

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PLEASE HELP IM REALLY STUCK

Answers

Answer:

[tex]a_{18}=-70[/tex]

Step-by-step explanation:

[tex]a_n=a_1+(n-1)d[/tex]

[tex]a_1=2, d = -4[/tex]

[tex]a_{18}=-2+(18-1)*(-4)=-2-68=-70[/tex]

What is the area of a square with a perimeter of 44 mm?

Answers

Answer:

The area of the square is 121mm

Step-by-step explanation:

To solve this we need two basic formulas:

P = 4s

A = [tex]s^{2}[/tex]

P = perimeter

s = the length of the side

Since the shape is a square all the sides are the same length. To get the value of 's' we need to isolate:

P = 4s

44 = 4s

44 / 4 = 4s / 4

11 = s

Now plug in the answer for 's' to get the area:

A = [tex]s^{2}[/tex]

A = [tex]11^{2}[/tex]

A = 121

Hope this helps.

Which value is not part of the five-number summary for the following data set?
35, 23, 24, 30, 28, 23, 27, 33, 27, 34, 30, 30

A. 29
B. 23
C. 31.5
D. 24

Answers

Answer:

  D. 24

Step-by-step explanation:

The 5-number summary of a data set includes ...

minimum1st quartilemedian (2nd quartile)3rd quartilemaximum

Summary values

When the data are written in increasing order, they are ...

  23 23 24  27 27 28  30 30 30  33 34 35

The minimum is the first value on the list, 23.

The first quartile is the average of the two middle values in the lower half of the data set: (24+27)/2 = 25.5.

The median is the average of the two middle values: (28+30)/2 = 29.

The third quartile is the average of the two middle values in the upper half of the data set: (30+33)/2 = 31.5.

The maximum is the last value on the list: 35.

Answer choices

A. 29 is the median

B. 23 is the minimum

C. 31.5 is the 3rd quartile

D. 24 is not part of the 5-number summary

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