suppose sin(A) = 1/4. use the trig identity sin^2(A)+cos^2(A)=1 to find cos(A) in quadrant II. around to ten-thousandth.

a. 0.1397
b. 0.4630
c. -0.8572
d. -0.9682

Answers

Answer 1

In quadrant II, [tex]\cos(A)[/tex] will be negative. So

[tex]\sin^2(A) + \cos^2(A) = 1 \implies \cos(A) = -\sqrt{1 - \sin^2(A)} = -\dfrac{\sqrt{15}}4 \approx \boxed{-0.9682}[/tex]

Answer 2

The requried, rounded to four decimal places, cos(A) is approximately -0.9682. The correct answer is option d. -0.9682.

To find cos(A) in quadrant II, we can use the given information and the trigonometric identity  [tex]sin^2(A) + cos^2(A) = 1[/tex].

Given [tex]sin(A) = 1/4[/tex], we can find  [tex]cos(A)[/tex]  as follows:

[tex]sin^2(A) + cos^2(A) = 1[/tex]

[tex](1/4)^2 + cos^2(A) = 1[/tex]

[tex]1/16 + cos^2(A) = 1[/tex]

Now, let's solve for [tex]cos^2(A)[/tex]:

[tex]cos^2(A) = 1 - 1/16[/tex]

[tex]cos^2(A) = 16/16 - 1/16[/tex]

[tex]cos^2(A) = 15/16[/tex]

Next, find the value of [tex]cos(A)[/tex] by taking the square root:

[tex]cos(A) = \pm \sqrt{(15/16)[/tex]

Since we are in quadrant II, where cosine is negative, we take the negative value:

[tex]cos(A) \approx -\sqrt{(15/16)[/tex]

Now, calculate the approximate value of cos(A):

[tex]cos(A) \approx -0.9682[/tex]

Rounded to four decimal places, cos(A) is approximately -0.9682. The correct answer is option d. -0.9682.

Learn more about trigonometric identity here:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

25w+140=290

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Answer:

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Step-by-step explanation:

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Double check (optional but suggested)

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Answers

Answer

160 divided by 16 = 10

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Answer:

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Answer:

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Answer:

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_____

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Answer:Triangle Inequality Theorem

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