The magnitude of the electrical force between the two identical electrical charges is 8.98755 × 10⁹N.
Given the data in the question;
Single charge each with; [tex]q_1\ and\ q_2[/tex] [tex]= 1C[/tex]Distance between; [tex]r = 1m[/tex]Electric force between; [tex]F = \ ?[/tex]Coulomb's lawCoulomb's law states "that the force between two electrical charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them".
It is expressed as;
[tex]F = k\frac{q_1q_2}{r^2}[/tex]
Here, [tex]q_1\ and\ q_2[/tex] are the two electrical charges, r is the distance between them and k is the Coulomb constant ( [tex]k = 8.98755*10^9 kgm^3/s^2C^2[/tex])
To determine the electrical force between the two charges, we substitute our values into the expression above.
[tex]F = k\frac{q_1q_2}{r^2}\\\\F = (8.98755*10^9 kgm^3/s^2C^2)*\frac{(1C)(1C)}{(1m)^2}\\\\F = (8.98755*10^9 kgm^3/s^2C^2)*\frac{1C^2}{1m^2}\\\\F = 8.98755*10^9 kgm/s^2\\\\F = 8.98755*10^9 N[/tex]
Therefore, the magnitude of the electrical force between the two identical electrical charges is 8.98755 × 10⁹N.
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The magnitude of the electrical force between the two charges is 8.987×10⁹ N.
What is coulomb's law?As per the coulomb's law, the electrical force between any two charges separated by a distance of r is given by the formula,
[tex]F = k\dfrac{q_1q_2}{r^2}[/tex]
Given that the value of q₁ and q₂ is 1 coulomb, while the distance between them is 1 meter. Also, the value of k is 8.987×10⁹ N·m²·C⁻², therefore, the force can be written as,
[tex]F = k\dfrac{q_1q_2}{r^2}\\\\F = (8.987 \times 10^{9}) \times (\dfrac{1 \times 1}{1^2})\\\\F= 8.987 \times 10^{9}\rm\ N[/tex]
Hence, the magnitude of the electrical force between the two charges is 8.987×10⁹ N.
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1 point
8. A magnetic field of 30 T is directed perpendicular to the force of a coil
with an area of 0.36 m^2. Calculate the magnetic flux in the coil.
A)0.27 Wb
B)9.3 Wb
C)10.8 Wb
D)83.3 Wb
Answer:
the answer is. C.
Explanation:
[tex] 0.36 \times 30 = 10.8[/tex]
the solution
Which is the destructive interference formula for diffraction grating problems? dsin = dcos = dcos = n dsin = n.
The destructive interference formula for diffraction grating problems is [tex]d sin \theta = (n+\frac{1}{2})\lambda[/tex].
What is the definition of destructive interference?Destructive interference happens when the maxima of two waves are 180° out of phase a positive displacement of one wave is canceled exactly by a negative displacement of the other wave.
The formula for brighter patches resulting from constructive interference and darker patches resulting from destructive interference in a diffraction grating is:
[tex]\rm d sin \theta = n \lambda[/tex]
The grating spacing is denoted by d, the angle of light is denoted by a the fringe order is denoted by n, and the wavelength is denoted by [tex]\rm \lambda[/tex].
The destructive interference formula is now based on the fact that destructive interference occurs between the fringes.
Hence the destructive interference formula for diffraction grating problems is [tex]d sin \theta = (n+\frac{1}{2})\lambda[/tex].
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Answer:
A. dsin =
Explanation:
Two horses pull horizontally on ropes attached to a tree stump each horse pulls with a force of F if the angle between the two ropes is 126° what's resultant force?
Answer:
126 / 2 = 63 = angle between one rope and the direction of the resultant force
t = F cos 73 = .45 F force on stump due to one horse
T = 2 t = .90 F force on stump due to both horses - T would be the resultant of the two horses each pulling with force F
If Earth had no greenhouse gases, the planet would be
Earth would be an icy wasteland if greenhouse gases were not present. Greenhouse gases keep our planet livable by retaining some of the Earth's heat energy, preventing it from escaping into space. The greenhouse effect refers to the trapping of heat.
Which characteristic is common to the four outer planets in our solar system?.
Answer: They Are all gas giants.
Explanation:
Collette is twisting a screwdriver. The scredriver has a handle with a radius of 18 mm. If she is exerting a force of 14 N, how much torque is she causing? PLEASE HELPPP!!!!
A. 25 Nm
B. 0.25 Nm
C. 1.3 Nm
D 0.75 Nm
Torque:-
[tex]\\ \rm\Rrightarrow \tau =14(0.018)[/tex]
[tex]\\ \rm\Rrightarrow \tau=0.25Nm[/tex]
option B
A rocket is launched straight up with a velocity of 7.59. What would be the velocity when it lands?
Answer:
the same as the initial launch velocity (7.59 m/s)
Explanation:
vf^2 = vi^2 + 2ad
d = displacement = 0, so vf^2 = vi^2, so vf = vi = 7.59m/s
7. An object with a mass of 2.0 kg is accelerated from rest. The above graph shows the magnitude of the net force
as a function of time. At t = 4.0 s the object's velocity is closest to which of the following?
a. 2.0 m/s
b. 4.0 m/s
C. 10 m/s
d. 13 m/s
The object's velocity accelerating from rest from the applied force and time is closest to 4 m/s.
Velocity of the object
The velocity of the object can be determied by applying Newton's second law of motion as shown below;
F = ma
where;
F is the applied forcem is the mass of the objecta is the acceleration of the objectThe acceleration of the object is calculated as follows;
a = F/m
at time, t 4.0 s, the corresponding force = 2 N
a = 2/2
a = 1 m/s²
Velocity of the object is calculated as;
v = u + at
v = 0 + 1 x 4
v = 4 m/s
Thus, the object's velocity accelerating from rest from the applied force and time is closest to 4 m/s.
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An object moving in the xy-plane is subjected to the force f⃗ =(2xyı^ 3yȷ^)n, where x and y are in m
The magnitude of the work done by force experience by the object is (2a²b + 3b²)J.
Work done by the force experienced by the objectThe magnitude of the work done by force experience by the object is calculated as follows;
W = f.d
where;
F is the applied force (2xyi + 3yj), where x and y are in metersd is the displacement of the object = (a, b)The work done by the force is determined from the dot product of the force and the displacement of the object.
F = (2xyi + 3yj).(a + b)
W = (2abi + 3bj).(ai + bj)
W = (2a²b + 3b²)J
Thus, the magnitude of the work done by force experience by the object is (2a²b + 3b²)J.
The complete question is below:
The particle moves from the origin to the point with coordinates (a, b) by moving first along the x-axis to (a, 0), then parallel to the y-axis.
How much work does the force do?
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The total work done for an object moving in the xy-plane is subjected to the force f⃗ =(2xyı^ 3yȷ^)n, where x and y are in m is 3ab N.
What is work done?Work done is the force applied on a body to move it over a distance. Work done for inclined plane can be given as,
[tex]W=F\times d[/tex]
Here (F) is the magnitude of force and (d) is the distance traveled.
An object moving in the xy-plane is subjected to the force
[tex]\vec f =(2xy\hat i +3y\hat j)[/tex]
Here, x and y are in meter.
The particle moves from the origin to the point with coordinates (a, b) by moving first along the x-axis to (a, 0), then parallel to the y-axis.
(a) How much work does the force do?For the first part, the particle moves along x-axis. It moves zero along x-axis. Thus, the force, as y=0.
[tex]W_1=\int\limits^a_0 {2xy\hat i} \, dx =0\\[/tex]
Now, when the object moves along y-axis,
[tex]W_2=\int\limits^a_0 {3y\hat j} \, dx \\W_2=3\int\limits^b_0 {y\hat j} \, dx\\W_2=3y(a-0)\\W_2=3ba\\W_2=3ab[/tex]
Total work done,
[tex]W=0+3ab\\W=3ab\rm\; N[/tex]
Thus, the total work done for an object moving in the xy-plane is subjected to the force f⃗ =(2xyı^ 3yȷ^)n, where x and y are in m is 3ab N.
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Blue, green, and red are _______ colors of light.
Answer:
the answer is white they combine to give white
Answer:
they are primary colors of light.
(pls don't delete this answer because I am just trying to help)
Hello~
Which of the following produces least friction?
(a) Sliding friction
(b) Rolling friction
(c) Composite friction
(d) Static friction
Answer:
Rolling friction
Explanation:
When a object rolls down the all sides of object comes contact to under surface for very low timeFor which the friction decreases .Option B is correct
A man pushes a 8 kg object. A distance of 5. 0 m upward along a frictionless slope that makes an angle of 30° with the horizontal. His force is parallel to the slope. If the speed of the object decreases at a rate of 1. 5 m/s, then the work done by the man is:
Answer:
is 200 J
Explanation:
hope this is the right answer
Arm ab has a constant angular velocity of 16 rad/s counterclockwise. At the instant when theta = 60
The linear acceleration of collar D when θ = 60° is - 693.867 inches per square second.
How to determine the angular velocity of a collarIn this question we have a system formed by three elements, the element AB experiments a pure rotation at constant velocity, the element BD has a general plane motion, which is a combination of rotation and traslation, and the ruff experiments a pure translation.
To determine the linear acceleration of the collar ([tex]a_{D}[/tex]), in inches per square second, we need to determine first all linear and angular velocities ([tex]v_{D}[/tex], [tex]\omega_{BD}[/tex]), in inches per second and radians per second, respectively, and later all linear and angular accelerations ([tex]a_{D}[/tex], [tex]\alpha_{BD}[/tex]), the latter in radians per square second.
By definitions of relative velocity and relative acceleration we build the following two systems of linear equations:
Velocities[tex]v_{D} + \omega_{BD}\cdot r_{BD}\cdot \sin \gamma = -\omega_{AB}\cdot r_{AB}\cdot \sin \theta[/tex] (1)
[tex]\omega_{BD}\cdot r_{BD}\cdot \cos \gamma = -\omega_{AB}\cdot r_{AB}\cdot \cos \theta[/tex] (2)
Accelerations[tex]a_{D}+\alpha_{BD}\cdot \sin \gamma = -\omega_{AB}^{2}\cdot r_{AB}\cdot \cos \theta -\alpha_{AB}\cdot r_{AB}\cdot \sin \theta - \omega_{BD}^{2}\cdot r_{BD}\cdot \cos \gamma[/tex] (3)
[tex]-\alpha_{BD}\cdot r_{BD}\cdot \cos \gamma = - \omega_{AB}^{2}\cdot r_{AB}\cdot \sin \theta + \alpha_{AB}\cdot r_{AB}\cdot \cos \theta - \omega_{BD}^{2}\cdot r_{BD}\cdot \sin \gamma[/tex] (4)
If we know that [tex]\theta = 60^{\circ}[/tex], [tex]\gamma = 19.889^{\circ}[/tex], [tex]r_{BD} = 10\,in[/tex], [tex]\omega_{AB} = 16\,\frac{rad}{s}[/tex], [tex]r_{AB} = 3\,in[/tex] and [tex]\alpha_{AB} = 0\,\frac{rad}{s^{2}}[/tex], then the solution of the systems of linear equations are, respectively:
Velocities[tex]v_{D}+3.402\cdot \omega_{BD} = -41.569[/tex] (1)
[tex]9.404\cdot \omega_{BD} = -24[/tex] (2)
[tex]v_{D} = -32.887\,\frac{in}{s}[/tex], [tex]\omega_{BD} = -2.552\,\frac{rad}{s}[/tex]
Accelerations[tex]a_{D}+3.402\cdot \alpha_{BD} = -445.242[/tex] (3)
[tex]-9.404\cdot \alpha_{BD} = -687.264[/tex] (4)
[tex]a_{D} = -693.867\,\frac{in}{s^{2}}[/tex], [tex]\alpha_{BD} = 73.082\,\frac{rad}{s^{2}}[/tex]
The linear acceleration of collar D when θ = 60° is - 693.867 inches per square second. [tex]\blacksquare[/tex]
RemarkThe statement is incomplete and figure is missing, complete form is introduced below:
Arm AB has a constant angular velocity of 16 radians per second counterclockwise. At the instant when θ = 60°, determine the acceleration of collar D.
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Henri becquerel shared a nobel prize for his work in discovering what?.
Where are active volcanoes most likely to found?
A.where rivers form
B where tectonic plate meet
C. Where oceans are deepest
D. Where land and water meet
Answer:
B. where tectonic plates meet
Explanation:
Most volcanoes occur near tectonic plate boundaries. For example, a large amount are found on the Ring of Firez connecting several plates.
A soft foam block of mass m slides without friction in the
positive x-direction with speed v. At time t = 0, a student briefly
pushes the block with a force probe in the positive x-direction. The
graph to the right shows the force probe's measurements as a
function of time during the push. Which of the following statements
is true about the block's momentum between t = 0 and t = t;?
The true statement about the blocks momentum is : The momentum of the block has increased by approximately 1/2 F₀t₁ ( B )
Change in MomentumGiven that the change in momentum is equivalent to the Area which is under the force time graph
where :
Area under the force time graph = 1/2 F₀t₁ . Therefore we can conclude that the momentum of the block has increased by an equivalent value of the are under the time graph.
Hence we can conclude that the true statement about the blocks momentum is The momentum of the block has increased by approximately 1/2 F₀t₁ .
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Attached below is the missing part of your question
missing options
The momentum of the block has decreased to zero at time t1. - AThe momentum of the block has increased by approximately 1/2 F0t1 - BThe momentum of the block has decreased by approximately 1/2 F0t1 - CThe change in momentum cannot be determined without knowing the distance by which the force probe compressed the block. - DHow much force does the astronaut exert on his chair while accelerating straight up at 10.0 m/s2m/s2
Answer:
M a = Fc -M g
Use up as positive - a is the acceleration upwards
Fc = M (a + g) force exerted by chair
Fc = 19.8 M m/s^2 where M is the mass of the astronaut
The force exerted by the astronaut accelerating straight up with an acceleration of 10 m/s² is m/5 Newton.
What is force?If you want to accelerate a body of mass 'm' with acceleration 'a' than a force of magnitude given by the product of mass and acceleration is needed.
Given is an astronaut accelerating straight up with an acceleration of 10 m/s².
Since the astronaut is moving in upward direction, the resultant resultant force is in upward direction. Now, assume that the force exerted by the astronaut on the chair is F[A]. The normal reaction force on the astronaut will also be same. Mathematically -
F[N] = F[A]
Now, we can write the resultant normal reaction force as -
ma - mg = F[N]
F[N] = m(a - g)
F[N] = m(10 - 9.8)
F[N] = m(0.2)
F[N] = m/5
F[A] = F[N] = m/5
where m is the mass of astronaut.
Therefore, the force exerted by the astronaut accelerating straight up with an acceleration of 10 m/s² is m/5 Newton.
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Which law of Newton explains why it's harder to stop a truck than a car moving at the same speed.
Answer:
Inertia
Explanation:
Inertia is also the reason that it is harder to stop a loaded truck going 55 miles per hour than to stop a car going 55 miles per hour. The truck has more mass resisting the change of its motion and therefore, more inertia.
A solid sphere is released from the top of a ramp that is at a height
h1 = 2.20 m.
It rolls down the ramp without slipping. The bottom of the ramp is at a height of
h2 = 1.87 m
above the floor. The edge of the ramp is a short horizontal section from which the ball leaves to land on the floor. The diameter of the ball is 0.14 m.
a.) Through what horizontal distance d, in meters, does the ball travel before landing?
b.) How many revolutions does the ball make during its fall?
Hi there!
We can use the work-energy theorem and apply it to this situation.
At the top of the ramp, the ball only has gravitational potential energy, and at the bottom of the ramp, the ball has BOTH translational and rotational kinetic energy.
We must use the following equations:
[tex]GPE = mgh \\KE_T = \frac{1}{2}mv^2\\\\KE_R = \frac{1}{2}I \omega^2[/tex]
m = mass of sphere (kg)
g = acceleration due to gravity (m/s²)
h = height of ramp (m)
v = final velocity (m/s)
I = Moment of Inertia (kgm²)
ω = angular velocity (rad/sec)
Since:
[tex]E_i = E_f\\\\mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega ^2[/tex]
In order to make things easier, since the ball is not slipping, we can relate angular velocity to translational velocity:
[tex]\omega = \frac{v}{r}[/tex]
Also, recall the equation for the moment of inertia for a solid sphere:
[tex]I = \frac{2}{5}mr^2[/tex]
We can use these to simply our equation:
[tex]KE_R = \frac{1}{2}(\frac{2}{5}mr^2)(\frac{v}{r})^2 = \frac{1}{5}mv^2[/tex]
Now, we can rewrite the equation and solve for 'v'.
[tex]mgh = \frac{1}{2}mv^2 + \frac{1}{5}mv^2\\\\mgh = \frac{7}{10}mv^2\\\\v = \sqrt{\frac{10gh}{7}} = \sqrt{\frac{10(9.8)(2.2 - 1.87)}{7}} = 2.149\frac{m}{s}[/tex]
a)
We can begin by solving for the time taken for the ball to land on the ground. The ball only has a horizontal velocity, so this is essentially a free-fall situation. Use the rearranged kinematic equation:
[tex]t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2(1.87)}{9.8}} = .6178 s[/tex]
Now, use the following equation to solve for horizontal distance given horizontal velocity and time:
[tex]d_x = v_x t\\\\d_x = 2.149 * .6178 = \boxed{1.328 m}[/tex]
b)
We can use the previously-stated relationship between translational and angular velocity to solve for the angular velocity.
[tex]\omega = \frac{v}{r}[/tex]
It is given that the diameter is 0.14 m, so the radius is 1/2th the diameter, or 0.07 m.
Solve for the angular velocity:
[tex]\omega = \frac{2.149}{0.07} = 30.706 \frac{rad}{sec}}[/tex]
Using the above fall time and dimensional analysis to convert from rad/sec to revolutions, we can solve for the # of revolutions made by the ball:
[tex]\frac{30.706rad}{sec} * .6178 sec * \frac{1 rev}{2\pi rad} = \boxed{3.019 rev}[/tex]
What is the speed of a wave that has a frequency of 440 Hz and a wavelength of 0.78 m? O A. 564 m/s m B. 0.003 m/s C. 343 m/s D. 0.002 m/s
Explanation:
velocity = frequency × wave length
velocity = 440 × 0.78
velocity = 343 m/sec
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A light-year is a unit of measurement that would most appropriately be used to measure which distance?
a. Between two galaxies b. Between Earth and Jupiter c. Between Earth and the sun d. Between the moon and Earth
A light-year is a unit of measurement which is used to measure distance between the Earth and the sun.
What is Light year?This is defined as the distance light travels in the time it takes the Earth to orbit the Sun.
It is also the distance a beam of light travels in a single earth year which is why option C was chosen as the most appropriate choice.
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Which statement explains how the charges on objects determine the electric force between them? (1 point)
O Objects with positive charges repel each other, and objects with negative charges attract each other
O Objects with the same charge attract each other, and objects with opposite charges repel each other
O Objects with positive charges attract each other, and objects with negative charges repel each other.
O Objects with the same charge repel each other, and objects with opposite charges attract each other
Objects with the same charge repel each other, and objects with opposite charges attract each other
Effect of similar charges on each otherAccording to Coulomb, the electric force for charges at rest has the following properties: Like charges repel each other; unlike charges attract. Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges.
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Which characteristic is the same for every color of light in a vacuum?.
In a vacuum all colors of light travel with same speed and this is the reason a white ray travels through the vacuum without going through any dispersion..
What is speed?Speed of light is the distance per time light waves propagate through different materials. The value for the speed of light in a vacuum is now defined as exactly 299,792,458 metres per second.
Therefore, In a vacuum all colors of light travel with same speed and this is the reason a white ray travels through the vacuum without going through any dispersion
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Lightning always follows
(a) a thunder
(b) rain pour
(c) the easiest path
(d) a straight path
Answer:
a thunder
Explanation:
It's because the difference in speed of light and sound
Light has speed about 3×10^8m/sSound has speed 344m/sSo we hear thunder later
Answer:
C
Explanation:
Lightning is a giant spark. A single stroke of lightning can heat the air around it to 30,000 degrees Celsius This extreme heating causes the air to expand at an explosive rate. The expansion creates a shock wave that turns to a booming sound wave, better known as thunder. Thunder & lightning occur at roughly the same time, although u see the flash of lightning before u hear the thunder. This is because light travels much faster than sound.Lightning always follows the easiest path. Lightning strikes buildings or projecting objects such as trees, poles, wires or building than larger, flatter surfaces because the material in them provide easier paths to the ground than the other. The primary target of lightning are lone buildings.Therefore, Thunder Follows The Easiest Part. And it is not (A) because Thunder Follows A Lightening Not Vice Versa.
One source error is __________, and one of its solutions is having a lie scale inserted into the assessment. a. social desirability bias b. deliberate deception c. response bias d. response set please select the best answer from the choices provided a b c d
One source error is deliberate deception and one of its solutions is having a lie scale inserted into the assessment.]
What is the error?An error is a mistaken or erroneous action. In some contexts, an error is interchangeable with a mistake.
The discrepancy between the calculated value and the correct value is referred to as an "error" in statistics.
When a person is completely aware of what they are doing, they are engaging in deception. They are concealing the truth and making a deliberate decision to tell someone something that is false.
When describing a magic trick, such as a sleight of hand, the term deception can also be used.
When there are repetitive questions that ask the same questions over and over with different formats to check if the responses are constant over time, lie scales are utilized.
Hence one source error is deliberate deception and one of its solutions is having a lie scale inserted into the assessment.
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A wave pulse on a spring is 5.40 cm high and oriented upward. This pulse meets another pulse of the same shape which is 1.10 cm high but oriented downward.
At the moment when the two pulses come together, what is the amplitude of the resulting pulse? Note: if the pulse is oriented upward, make its amplitude positive. If it is oriented downward, make its amplitude negative.
The resulting positive amplitude of the two waves after the superimposition is 4.30 cm.
Amplitude of the waves
The amplitude of the waves is the maximum displacement of the wave. This is the vertical position of the wave measured from the zero origin.
After the superimposition of the two similar waves, the resulting amplitude will be less than the initial amplitude of the wave with the highest vertical height since the superimposition creates destructive interference.
Resulting amplitude of the two waves is calculated as;
A = 5.4 cm - 1.10 cm
A = 4.30 cm
Thus, the resulting positive amplitude of the two waves after the superimposition is 4.30 cm.
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How many feet will it take you to stop from 60 mph.
Hello people ~
Sound cannot travel through
(a) air
(b) water
(c) air
(d) vacuum
Answer:
Vaccum
Explanation:
Sound travels through the particles of different matter In vaccum there is no air so no matter and so no particles .So sound can't travel through vaccum.You can test it .
Take a speaker and keep it inside a bottle ,close it .You won't hear any sound
When we harness energy using photovoltic cells in a large panel on the roofs of buildings, we are using
power
A solar
B geothermal
C wind
D biomass
Answer:
solar
Explanation:
this is a form of solar panel
Radio galaxies have twin radio jets that emanate from a central core. An astronomer
finds a radio galaxy whose frequency is 20 MHz. What wavelength of radio waves
does the galaxy emit?
The wavelength of the radio waves emitted by the radio galaxies which have twin radio jets that emanate from a central core is determined as 15 m.
Wavelength of the radio wavesThe wavelength of the radio waves is the distance traveled by the radio waves. The magnitude of the wavelength is determined from the ratio of speed of radio waves to the frequency of the radio waves.
v = fλ
where;
v is the speed of the radio wavesf is the frequency of the radio wavesλ is the wavelength of the radio wavesRadio wave is an example of electromagnetic radiation, and it travels at the same speed as light (3 x 10⁸ m/s).
λ = v/f
λ = (3 x 10⁸ ) / (20 x 10⁶)
λ = 15 m
Thus, the wavelength of the radio waves emitted by the galaxy is 15 m.
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