1. The body must supply approximately 1.2215 × [tex]10^{5}[/tex] joules of heat to warm the air to body temperature.
2. The air's volume increases by approximately 0.3408 liters as it warms.
1. To calculate the amount of heat required to warm the air, we need to determine the change in temperature, the mass of the air, and the specific heat capacity of air.
a) Change in temperature:
ΔT = T2 - T1
ΔT = (37 °C + 273.15 K) - (0 °C + 273.15 K)
ΔT ≈ 310.15 K - 273.15 K
ΔT ≈ 37 K
b) Mass of the air:
Using the ideal gas law, we can determine the number of moles (n) of air:
n = (PV) / (RT)
n = (1 atm * 2.5 L) / (0.0821 atmL/molK * 273.15 K)
n ≈ 0.1134 mol
Since the molar mass of air is approximately 29 g/mol, we can calculate the mass of the air:
Mass = n * molar mass of air
Mass ≈ 0.1134 mol * 29 g/mol
Mass ≈ 3.2894 g
c) Heat required:
Q = m * c * ΔT
Q = 3.2894 g * (1005 J/(kg·K)) * 37 K
Q = 1.2215 × [tex]10^{5}[/tex] joules
The amount of heat required to warm the air to the body temperature of 37 °C is approximately 1.2215 × [tex]10^{5}[/tex] joules.
2. To determine the change in volume of the air as it warms, we can use Charles's law.
V2 - V1 = V1 * (ΔT / T1)
V2 - V1 = 2.5 L * (37 K / 273.15 K)
V2 - V1 ≈ 0.3408 L
The volume of air increases by approximately 0.3408 liters as it warms.
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The ability of a halogen to react with a metals to form a salt is an example of a ________________ property.
how you would orient the magnets and what you would do with the magnets to achieve maximum repulsion
The orientation of the magnets that gives the strongest repulsion because these poles and facing each other that is then leaves highest flux density of the poles for a force of repulsion to be very high
14. If 100 grams of sodium nitrate are dissolved in 100 grams of water
at 60 degrees C, is the solution formed saturated, unsaturated, or
supersaturated?
Answer:
Unsaturated
Explanation:
the solubility of sodium nitrate is at 60 C is 124g/ml therefore, putting 100 grams will not saturate fully.
Ocean waves are hitting a beach with a frequency of 0.100 Hz. Their average wavelength is 15.0 m. What is their average speed?
What is the frequency of a pendulum that is moving at 30 m/s with a wavelength of 0.32 m?
Answer:
Average speed=1.5 m/s
Frequency of pendulum=93.75Hz
Explanation:
We are given
Frequency, [tex]f=0.100Hz[/tex]
Average wavelength =[tex]\lambda=15m[/tex]
Speed of pendulum, [tex]v=30m/s[/tex]
Wavelength, [tex]\lambda'=0.32m[/tex]
We have to find the average speed and frequency of pendulum.
We know that
Speed,[tex]v=\lambda f[/tex]
Using the formula
Average speed,[tex]v=15\times 0.1=1.5m/s[/tex]
Hence, the average speed =1.5m/s
Frequency, [tex]f=\frac{v}{\lambda'}[/tex]
Using the formula
[tex]f=\frac{30}{0.32}[/tex]
[tex]f=93.75Hz[/tex]
Hence, the frequency of a pendulum=93.75Hz
state and explain the joules law
Answer:
Joule’s law of heating states that when a current ‘i ' passes through a conductor of resistance ‘r’ for time ‘t’ then the heat developed in the conductor is equal to the product of the square of the current, the resistance and time.
H = i 2 rt
The reason behind the heat produced is the collision of the free electrons with the lattice ions or atoms while accelerating in presence of the external electric field.
we know that
volt= work done/ total charge or v = w/q
from this we get w= vq
we know that current i = q / t
so q = it
putting this in prev equation
we get w = vit
from ohms law v = ir
putting it in prev eq we get
w = irit = i2rt joule as work is stored as heat soH = I2RT Joules
if a current carrying conductor having resistance (r) gets heated by to passing of current (i) for time (t) and the heat thereby produced be H
joules law states that
H propotional to i^ 2 when r and t are constant
H propotional to r when I and t are constant
H propotional to t when r and I constant
Mercury has the most eccentric (least circular) orbit of all the planets in the Solar System. At aphelion it is 0.467 AU from the Sun while at perihelion it is only 0.308 AU from the Sun. What is Mercury's orbital period in Earth-days?
Answer:
Mercury's orbital period is approximately 88 days
Explanation:
Mercury's orbit parameters given in the question are;
Mercury's aphelion distance, Rₐ = 0.467 AU
Mercury's perihelion distance, [tex]R_p[/tex] = 0.308 AU
Therefore, the average distance from Mercury to the Sun, 'a', is given as follows;
[tex]a = \dfrac{R_a + R_p}{2}[/tex]
By plugging in the values of 'Rₐ' and '[tex]R_p[/tex]', we get;
[tex]a = \dfrac{R_a + R_p}{2} = \dfrac{0.467 \, AU + 0.308 \, AU}{2} = 0.3875 \, AU[/tex]
a = 0.3875 AU
According to Kepler's third law, we have;
P² = k·a³
Where;
P = The orbital period of the plane
a = The average distance from Mercury to the Sun
k = Constant
When k = 1, we have;
P² = a³
∴ P = √(a³)
From which we have;
P = √(0.3875 AU)³ ≈ 0.241216804711 years
P ≈ 0.2412168 years
1 year = 365 days
∴ 0.241216804711 years = 0.241216804711 years × 365 days/year ≈ 88.0441337 days
0.241216804711 years ≈ 88.0441337 days ≈ 88 days
Mercury's orbital period, P ≈ 88 days.
The change in frequency of a wave as its source moves in relation to an observer.
A)
Ultrasound
B)
Frequency
C)
Doppler Effect
D)
Echo
Answer: B) Frequency
Explanation:
the Himalayas are the highest mountain in the world (positive). grammar question
Answer:
positive degree:
No other peak of the Himalayas is as high as Mount everest
a dolphin that just manage to keep up with a speeding boat for a distance of 2km for a period of 3h in (answer in km/h)
Answer:
6km
Explanation:
3hours X 2km = 6 kilometres
1. Compare the speed that light waves travel in air to the speed that sound waves travel in the air. How many times faster do light waves travel in air in comparison to sound waves in air?
Water-1500 meters per second
steel-5000 meters per second
Air-335 meters per second
Answer:
895522 times faster.
Explanation:
From the question given above, the following data were obtained:
Speed of sound in air (v) = 335 m/s
Speed of light in air (c) = 3×10⁸ m/s
How many times faster =.?
To obtain how many times faster light travels in air than sound, do the following
c : v => 3×10⁸ : 335
c/v = 3×10⁸ / 335
c/v = 895522
Cross multiply
c = 895522 × v
From the illustrations made above, we can see that the speed of the light in air (c) is 895522 times the speed of sound in air.
Thus, light travels 895522 times faster than sound in air.
Two objects, A and B, are in contact with one another. Initially, the temperature of A is 50 °C and the temperature of B is 100 °C. 1. **The particles of which object (A or B) initially have a greater average kinetic energy? How do you know?
Answer:
B
Explanation:
because kinetic energy is directly proportional to temperature so the hottor the object, the more kinetic energy.
3. Gather data: Use the values above to fill in the first row of the table. Then run your own experiments to fill
in the last two rows.
f
d.
d,
h.
h,
ร”
S
d
de
2.0
h;
h.
2.0
s.
2.0
S
f
2.0
15
10
30
Answer:
urjshsus uevus e survey dydvd dydvdyd d dgdv gdyr yrgdvv yth yrhvthr
Explanation:
ydgdydvd yd dv ydvr dyve dysdvdyr gdvr
what are the unique characteristics of romantic music which are not present in Original Pilipino Music (OPM)
Answer:
ITU Sangat bermanfaaat
6. Suppose the resistance of your body between your right and left hands is 500,000 N. What
would be the current flowing through your body if you touched the plus and minus terminals of
a 120 V battery? The threshold of sensation for electric current through your body is about
300 PA. Would you feel the current?
HELP PLS
If a storm is 7.5 kilometers away, how much time is expected between observations of lightning and thunder?
Answer:
≈ 22 seconds
Explanation:
7,5 km = 7500 m
Speed of light 300 000 000 m/s (for lightning)
Speed of sound 343 m/s (for thunder)
time = distance / speed
lightning time = 7500 m / 300 000 000 m/s = 0.000025 s
thunder time = 7500 m / 343 m/s ≈ 22 s
thunder time - lightning time = 22 s - 0.000025 s ≈ 22 s
The electromagnetic spectrum is divided into regions by Group of answer choices a.wavelengths and frequencies b.the way they are used c.speed d.colors
Answer:
Generally, by wavelengths and frequencies.
Colors only occur for a narrow portion of the spectrum.
The speed for these waves is c the speed of light regardless of wavelength.
The way they are used seems somewhat irrelevant.
The electromagnetic spectrum is divided into regions by wavelengths and frequencies. The spectrum is arranged in the order of increasing frequency.
What is electromagnetic spectrum ?The electromagnetic spectrum is the arrangement of waves in the order increasing frequency or decreasing wavelength. The order of the spectra starts from radio waves, microwaves, infrared, visible light, ultraviolet, x -rays and gamma rays.
The visible light that we can see is in between IR and UV rays. Hence, visible light has a frequency greater than IR rays but shorter than IR. Similarly visible light is longer than UV- rays but less frequency than UV rays.
Gamma rays are the most energetic and shorter waves in the electromagnetic spectrum with smaller wavelength and greater frequency. Hence, options a is correct.
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The electrostatic force between two charged metal spheres is 2N. If the charge on each sphere is doubled, what is the new force between the spheres?
Question 2 options:
A. 2N
B. 4N
C. 1N
D. 8
Answer:
8 N
Explanation:
The force between two charges is given by :
[tex]F=\dfrac{kq_1q_2}{d^2}[/tex]
Where
k is electrostatic constant
d is the distance between two charges
It means,
[tex]F\propto \dfrac{1}{d^2}[/tex]
When the distance is d, the force is 2 N. If the charge on each sphere is doubled, q₁' = q₂' = 2q₁ = 2q₂. New force will becomes:
[tex]F'=\dfrac{kq_1'q_2'}{d^2}\\\\F'=\dfrac{k2q_1\times 2q_2}{d^2}\\\\F'=4\times \dfrac{kq_1q_2}{d^2}\\\\F'=4\times 2\\\\F'=8\ N[/tex]
So, the new force becomes 8N. Hence, the correct option is (d).
If a girl walks 6km due west changes directions and walk another 5km due north. Find her displacement in both magnitude and direction
Answer:
the girl's displacement in both magnitude and direction is 7.81 m at 50.2⁰ North west.
Explanation:
Given;
6km due west, and
5km due north
The magnitude of her displacement is calculated by forming a right angled triangle. The hypotenuse side of the triangle is the girl's displacement.
d² = 5² + 6²
d² = 25 + 36
d² = 61
d = √61
d = 7.81 m
The direction of the girl is calculated as;
[tex]tan \ \theta = \frac{6}{5} \\\\tan \ \theta = 1.2\\\\\theta = tan^{-1} (1.2)\\\\\theta = 50.2^0[/tex]
Therefore, the girl's displacement in both magnitude and direction is 7.81 m at 50.2⁰ North west.
5. A car accelerates from 0 to 72 km/hour in 8.0 seconds. What is the car's acceleration?
Answer:
2.5 m/s
Explanation:
There are calculators online that can help you easily calculate the accerlation.
Please help (choose a b or c)
(the image is attached)
In the adjacent circuit, the voltage across the terminals of the dry cell is equal to 12 V.
The value displayed by the voltmeter is:
a- 0 V
b- 12 V
c- -12 V
The two terminals that correspond to the correct connection of a voltmeter in a circuit are:
a- A and COM
b- A and V
c- V and COM
I GEUSS A and COM is correct answer to this question
Answer:
1. (a) =0
2.(c) = v and COM
Long Answer Type Questions
1 Can you differentiate between opaque, transparent and translucent objects
2 What is reflection of light?
3. What are the conditions for a shadow to be formed?
4. Prove through an experiment that light travels in straight lines.
5. What is pinhole camera? Explain its working with the help of a diagram
6. What are the main differences between a reflected image and shadows?
(1).....opaque -object that not allow light to pass through it
we can't look through opaque objects
ex..wall
translucent... objects that all some light to pass through it
we can partially see through it
ex...coloured glass window
transparent... objects that wholly allow light to pass through it
we can clearly see through it
ex...glass of specs
(2)..the bouncing back of light from a smooth polished surface is called reflection of light
(3)/.....there must be a solid ,opaque to block light
there must be a source of light
there must be a surface to have shadow on it..
(6)...reflected images r formed by light reflection from a smooth polished surface while shadows are formed by blockage of light by an solid,opaque object...
Explanation:
we should talk here thanks
Motion and acceleration may only be used to refer to physical objects moving or changing speed/direction
Answer:
True
Explanation:
It is TRUE that Motion and acceleration may only be used to refer to physical objects moving or changing speed/direction.
This is because if an object is not moving or changing speed/direction to a determined point of reference, the object is considered to be at rest or motionless, thereby, with no absolute point of reference, absolute motion or acceleration cannot be distinguished.
All weather stations have to make weather observations at the same time of the day.
True
False
Answer:
false
Explanation:
Answer:
True
Explanation:
The answer is true do not listen to the other person they will get you wrong just look at the votes between mine and the other person's (hint like my answer and rate 5 stars so other people know what to pick)
write any four importance of pressure
Answer:
Here is your ans
Explanation:
hope it helps you tq
a ball rolled a velocity of 20m/s after 5s it comes to stop what is the acceleration of the ball
Answer:
please find the attached pdf
Explanation:
True or false. Your weight will change on the moon
What is the SPEED of a train that travels 15000 meters in 1200 seconds (20 minutes)?
PLEASE SHOW WORK!!!! EASY POINTS!!!!
Answer:
27.9617 mi/h
Explanation:
Speed= distance/time
S= 15000/1200
A que profundidad esta nadando una persona dentro de una alberca si la presión absoluta sobre ésta es de 156kPa?
Answer:
La persona está nadando en la alberca a una profundida de 5.575 metros.
Explanation:
La presión absoluta ([tex]P_{tot}[/tex]) experimentada por la persona es la suma de la presión atmosférica ([tex]P_{atm}[/tex]) y la presión hidrostática de la columna de agua de la alberca ([tex]P_{h}[/tex]), medidas en kilopascales. Es decir,
[tex]P_{tot} = P_{atm}+P_{h}[/tex] (1)
[tex]P_{tot} = P_{atm} + \frac{\rho\cdot g \cdot z}{1000}[/tex] (2)
Donde:
[tex]\rho[/tex] - Densidad del fluido de la alberca, medida en kilogramos por metro cúbico.
[tex]g[/tex] - Aceleración gravitacional, medida en metros por segundo al cuadrado.
[tex]z[/tex] - Profundidad de la persona en la alberca, medida en metros.
Si sabemos que [tex]P_{atm} = 101.325\,kPa[/tex], [tex]\rho = 1000\,\frac{kg}{m^{3}}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] y [tex]P_{tot} = 156\,kPa[/tex], entonces la profundidad de la persona en la alberca es:
[tex]156 = 101.325 +\frac{(1000)\cdot (9.807)\cdot z}{1000}[/tex]
[tex]54.675 = 9.807\cdot z[/tex]
[tex]z = 5.575\,m[/tex]
La persona está nadando en la alberca a una profundida de 5.575 metros.
what's 4 x 5
i need help with this question please
Answer:
4 × 5 = 5 + 5 + 5 + 5 = 20
Explanation:
Pick one factor and add it.
A 2 kg ball is thrown down with 50J of energy from a height of 10m, what is its velocity before it strikes the ground (neglect air resistance).
Answer:
V=14
Explanation:
PE=KE
mgh=1/2mv^2
(2)(9.8)(10)=1/2(2)v^2
(radical) 196=(radical) v
V=14