Answer:
(c) 8
Step-by-step explanation:
ANSWER ASAP!! (GIVING BRAINLIEST IF CORRECT!!)
Lindsey estimated the amount of liquid in a container to be 5 oz. The actual amount of liquid was 4 oz.
What is the percent error?
A: 10%
B: 15%
C: 20%
D: 25%
Answer:
and c 20
Step-by-step explanation:
20 percent of t is 1
5 -1 =4
What are the values of the trigonometric ratios for this triangle?
Drag the answers into the boxes.
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
sinθ
cosθ
tanθ
543435434553
A right triangle. The hypotenuse is labeled as 5. The legs are labeled as 3 and 4. The angle opposite the side labeled 3 is theta.
The trigonometric ratios are expressed as;
sin θ = 3/5
cos θ = 4/5
tan θ = 3/4
How to determine the valueTo determine the trigonometric ratios, we need to know the six identities.
These trigonometric identities are listed thus;
sinetangentcosinecotangentcosecantsecantFrom the information given, we have that;
sin θ = opposite/hypotenuse
cos θ = adjacent/hypotenuse
tan θ = opposite/adjacent
We have that;
The hypotenuse is labeled as 5.
The adjacent leg is 4
The angle opposite the side labeled 3 is theta
Now, substitute the value to determine the ratios for each identity, we have that;
sin θ = 3/5
cos θ = 4/5
tan θ = 3/4
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Alex tested three brands of batteries to learn which would last the longest in a flashlight. He placed two brand “A” batteries in a flashing, turned the flashlight on, and measured the time and the light shined. He repeated the experiment with battery brands “B” and “C” using the same flashlight. He recorded the data on the bar graph below.
Which of these is an accurate conclusion that Alex can make about the batteries he tested?
A. Brand “C batteries lasted twice as long as brand “A” batteries.
B. Brand “C” batteries listed three times longer than brand “B” batteries
C. The light was twice as bright with brand “A” batteries than with brand “B” batteries.
D. The light shined three times farther with brand “C” batteries than with brand “B” batteries.
The correct statement regarding the bar graph is given as follows:
D. The light shined three times farther with brand “C” batteries than with brand “B” batteries.
What does a bar graph show?A bar graph shows the output considering a given input.
Hence the bar graph in this problem shows the average lifetime for each battery type, given as follows:
Brand A: 270 minutes.Brand B: 120 minutes.Brand C: 360 minutes.Brand C has triple the length of Brand B, hence the correct statement is given by option D.
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Finding the angle when given the right angle and two sides. Please show explanation. Thank you.
The measure of angle A in the right triangle is 75.52°
What is the measure of angle A?The figure in the image is a right triangle.
Measure of angle A = ?
Adjacent to angle A = 2
Hypotenuse = 8
To solve for the measure of angle A, we use the trigonometric ratio.
Note: cosine = adjacent / hypotensue
Hence:
cos( A) = adjacent / hypotensue
cos( A ) = 2/8
cos( A ) = 1/4
Take the cos inverse
A = cos⁻¹( 1/4 )
A = 75.52°
Therefore, the measure of the angle is 75.52 degree.
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(a) Find the multiples of 2 greater than 40 and less than 80 in such a way that the sum of their digits is 8. (b) Find the multiples of 5 more thane 106 and less than 200 in such a way that the sum of their digits is 12.
Answer:
(a) 44 (4 + 4 = 8), 62 (6 + 2 = 8)
(b) 165 (1 + 6 + 5 = 12)
Numbers 1 to 20 are placed in a bag. Without replacing the first number, what is the probability that the first number drawn will be odd and the second number be even?
Answer:
5/19 or 26.3%---------------------------
There are total 20 numbers and half of them odd and half of them even.
Without replacement, the probability of an odd and then even number is:
P(odd then even) = P(odd) * P(even)P(odd then even) = 10/20 * 10/(20 - 1)P(odd then even) =1/2 * 10/19P(odd then even) = 5/19 or 26.3%i think x is 10 but what do i write for the reason
thanks
Answer:
Step-by-step explanation:
Due to isosceles triangle , ∠ABC = ∠ACB = 7x
∠ACB + ∠ACD = 180 ( Linear pair I think )
7x + 110 = 180
7x = 70
x = 10°
Which of the following statements is true for ∠a and ∠b in the diagram?
A) m∠a = m∠b
B) m∠a + m∠b = 90°
C) m∠a + m∠b = 180°
D) m∠a – m∠b = 90°
Answer:
A
Step-by-step explanation:
If you look at the angles or use something to measure it you can tell that a and b are opposite sides that are parallel to each other. So they are equal.
Solve each of the following graphically method method
A. Max Z = 10x1 + 20x2
Subject to
5x1+ 3x2 ≤ 30
3x1+ 6x2 ≤ 36
2x1+ 5x2 ≤ 20
x1 ≥ 0 , x2 ≥
Answer:
Step-by-step explanation:
To solve the given linear programming problem graphically, we'll plot the feasible region determined by the given constraints and then identify the optimal solution by maximizing the objective function Z = 10x1 + 20x2.
Step 1: Plotting the Constraints
We'll start by plotting the equations representing each constraint.
Constraint 1: 5x1 + 3x2 ≤ 30
To plot this constraint, we'll first find the points on the line 5x1 + 3x2 = 30. We can do this by setting x1 to 0 and solving for x2, then setting x2 to 0 and solving for x1.
Setting x1 = 0, we get: 3x2 = 30
x2 = 10
So, one point is (0, 10).
Setting x2 = 0, we get: 5x1 = 30
x1 = 6
So, another point is (6, 0).
Plotting these two points and drawing a line passing through them, we get a boundary line for the first constraint.
Constraint 2: 3x1 + 6x2 ≤ 36
Similarly, we find two points on the line 3x1 + 6x2 = 36.
Setting x1 = 0, we get: 6x2 = 36
x2 = 6
So, one point is (0, 6).
Setting x2 = 0, we get: 3x1 = 36
x1 = 12
So, another point is (12, 0).
Plotting these points and drawing a line passing through them, we get a boundary line for the second constraint.
Constraint 3: 2x1 + 5x2 ≤ 20
Again, we find two points on the line 2x1 + 5x2 = 20.
Setting x1 = 0, we get: 5x2 = 20
x2 = 4
So, one point is (0, 4).
Setting x2 = 0, we get: 2x1 = 20
x1 = 10
So, another point is (10, 0).
Plotting these points and drawing a line passing through them, we get a boundary line for the third constraint.
Step 2: Finding the Feasible Region
Now, we shade the region of the graph that satisfies all the constraints. The feasible region is the intersection of the shaded regions determined by each constraint.
Step 3: Maximizing the Objective Function
To maximize the objective function Z = 10x1 + 20x2, we look for the highest possible value within the feasible region. The optimal solution will be at one of the corner points of the feasible region.
We calculate the coordinates of each corner point formed by the intersection of the constraint lines and evaluate Z = 10x1 + 20x2 at each of these points. The corner point with the highest Z value will be the optimal solution.
By evaluating Z at each corner point, we can determine the optimal solution and its corresponding values of x1 and x2.
Note: Without specific numerical values for the corner points, I am unable to provide the exact coordinates and the optimal solution for this problem. However, by following the steps outlined above and evaluating the objective function at each corner point, you can identify the optimal solution for the given linear programming problem.
Hi. First of all, please give me 5 stars. There is the response:
To solve this problem graphically, we first plot the lines corresponding to the constraints, and then find the feasible region by shading the region that satisfies all constraints. Finally, we evaluate the objective function at each corner point of the feasible region to find the optimal solution.
The constraints can be rewritten in slope-intercept form as follows:
5x1 + 3x2 ≤ 30 => x2 ≤ (-5/3)x1 + 10
3x1 + 6x2 ≤ 36 => x2 ≤ (-1/2)x1 + 6
2x1 + 5x2 ≤ 20 => x2 ≤ (-2/5)x1 + 4
We plot these lines on a graph:
```
| / 5x1 + 3x2 = 30
6 +-------/------------
| / 3x1 + 6x2 = 36
| /
4 +----/--------------
| / 2x1 + 5x2 = 20
| /
2 +-/----------------
| /
|/
+------------------
0 2 4 6 8
```
Next, we shade the feasible region:
```
| /
6 +-------/-----RR-----
| / -----RR-----
| / -----RR-----
4 +----/-----RRR------
| / --RRRRRR------
| / -RRRRR--------
2 +-/----RRRR----------
| / R--------------
|/ R--------------
+------------------
0 2 4 6 8
```
The feasible region is the shaded area. There are 4 corner points: (0, 4), (4, 2), (6, 0), and (8/7, 26/21).
Finally, we evaluate the objective function at each corner point:
- (0, 4): Z = 10(0) + 20(4) = 80
- (4, 2): Z = 10(4) + 20(2) = 80
- (6, 0): Z = 10(6) + 20(0) = 60
- (8/7, 26/21): Z = 10(8/7) + 20(26/21) = 170/7
The optimal solution is (8/7, 26/21) with a maximum value of 170/7.
Let E be the event where the sum of two rolled dice is greater than 3
. List the outcomes in Ec
The number of possible outcomes that Event E has is 33.
The 36 possible conclusions when rolling two dice is given in the image.
Now, we need to find the event where the sum of two rolled dice is greater than 3
Then, from the outcomes given above we can write those pair whose sum is greater than 3 as
1 + 3=4
1 + 4= 5
1+ 5 = 6
1 + 6 = 7
2+ 2 = 4
2 + 3 = 5
2 + 4 =6
2 + 5 = 7
2 + 6 = 8
3 +3=6
3 + 4 = 7
3 + 5 =8
3 + 6 =9
4 + 3 =7
4 + 4=8
4 + 5 = 9
5+ 5 = 10
5 + 6= 11
6 + 6 = 12
So, there are 33 outcomes whose sum is greater than 3.
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Mrs horwitz is wrapping a present in a rectangular prism box for mr roberts. the dimensions of the gift are 13 in by 8 in by 11 in. how much wrapping paper does she need. should mrs horwitz find the volume or surface area to figure out how much wrapping paper she needs. based on your answer above, find the solution. show all your work
Mrs. Horwitz needs 670 square inches of wrapping paper to wrap the present.
We have,
To figure out how much wrapping paper Mrs. Horwitz needs, she should find the surface area of the rectangular prism box.
The surface area of a rectangular prism is given by the formula:
Surface Area = 2lw + 2lh + 2wh
Given dimensions:
Length (l) = 13 in
Width (w) = 8 in
Height (h) = 11 in
Plugging these values into the formula, we get:
Surface Area = 2(13)(8) + 2(13)(11) + 2(8)(11)
Surface Area = 208 + 286 + 176
Surface Area = 670 in²
Therefore,
Mrs. Horwitz needs 670 square inches of wrapping paper to wrap the present.
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How do I covert 45 degrees to a radian
Step-by-step explanation:
There are pi radians in 180 degrees
you want 1/4 of 180 degrees (45/180 = 1/4)
so this would be 1/4 pi radians or pi / 4 radians
45 * pi / 180 = pi/4
100 Points! Geometry question. Photo attached. Please show as much work as possible. Thank you!
Answer:
The correct answer is:
(A) enlargement
Number 6 look at the image
It would take Arron 3 hours to travel 18 miles upstream (against the river)
What is an equation?An equation is an expression that shows how numbers and variables are related to each other using mathematical operations.
Speed is the ratio of total distance to total time taken.
Arron boat has a speed of 9 mph in still water and the speed of the river is 3 mph. Since he is travelling upstream, we subtract both speed:
He needs to travel 18 miles upstream at time t, hence:
(9 mph - 3 mph) = 18 miles / t
6t = 18
t = 3 hours
It would take Arron 3 hours
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Find the missing probability.
P(B)=1/4P(AandB)=3/25P(A|B)=?
The missing probability is P(A|B) is 12/25 if P(B) is 1/4P and (A and B) is 3/25P.
P(B) = 1/4
P(A and B) = 3/25
The conditional probability is used to find the P(A|B):
P(A|B) = P(A and B) / P(B)
Conditional probability is defined as the number of possible outcomes from a given event based on the previous outcomes of the events.
By substituting the given values in the given probability, we get:
P(A|B) = (3/25) / (1/4)
Divide the fraction and multiply it with its reciprocal:
P(A|B) = (3/25) * (4/1)
P(A|B) = 12/25
Therefore, we can conclude that the missing probability is P(A|B) is 12/25.
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The complete question is:
Find the missing probability.
P(B)=1/4P
(AandB)=3/25P
P(A|B)=?
find the gradient of the curve y = 3x^4 - 2x^2 + 5x - 2 at the points (0, - 2) and (1,4)
Answer: To find the gradient of a curve at a given point, we need to find the derivative of the function with respect to x and then evaluate it at the desired x-coordinate.
Given the function y = 3x^4 - 2x^2 + 5x - 2, we can find its derivative dy/dx as follows:
dy/dx = d/dx(3x^4) - d/dx(2x^2) + d/dx(5x) - d/dx(2)
Taking the derivative of each term:
dy/dx = 12x^3 - 4x + 5
Now, let's evaluate the derivative at the given points:
Point (0, -2):
Substituting x = 0 into the derivative:
dy/dx = 12(0)^3 - 4(0) + 5
dy/dx = 0 - 0 + 5
dy/dx = 5
Therefore, the gradient at (0, -2) is 5.
Point (1, 4):
Substituting x = 1 into the derivative:
dy/dx = 12(1)^3 - 4(1) + 5
dy/dx = 12 - 4 + 5
dy/dx = 13
Therefore, the gradient at (1, 4) is 13.
Fill out the following MRP scheme.
The lead time is two weeks. There is no safety stock kept. Orders can be placed lot-for-lot.
MRP Scheme: Determine demand, calculate gross requirements, consider lead time, determine scheduled receipts, calculate planned order receipts, determine planned order release, monitor inventory levels, repeat process periodically. Lot-for-lot ordering, no safety stock.
MRP (Material Requirements Planning) Scheme:
Determine the Demand:
Gather the demand forecast or sales orders for the upcoming period.
Calculate the net demand by subtracting any existing inventory from the total demand.
Calculate the Gross Requirements:
Gross requirements are the total quantity of materials needed to fulfill the net demand.
Consider the lead time of two weeks when calculating the gross requirements.
Determine the Scheduled Receipts:
Check if there are any open purchase or production orders scheduled to arrive within the lead time.
Include the quantities of materials expected to be received during this period.
Calculate the Planned Order Receipts:
Subtract the scheduled receipts from the gross requirements to determine the planned order receipts.
If the planned order receipts are negative, no action is required as the scheduled receipts are sufficient.
If the planned order receipts are positive, create a purchase or production order for that quantity.
Determine the Planned Order Release:
The planned order release specifies when the purchase or production order should be initiated.
It is typically based on the lead time, taking into account any constraints or preferences.
The planned order release should ensure that the materials arrive in time to meet the net demand.
Monitor Inventory Levels:
Keep track of inventory levels regularly to identify any deviations from the plan.
If the actual inventory falls below the net demand, adjust the planned order releases accordingly.
If the actual inventory exceeds the net demand, consider reducing the planned order releases.
Repeat the Process:
Review and update the MRP scheme periodically based on the changing demand and inventory levels.
Continuously adjust the planned order releases to align with the updated requirements.
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Venessa bought 80 apples for 4$.out of these apples 25 precent were rotten and had to be thrown away Vanessa sold the remaining apples at 6 cents per apple. What is the profit or loss percentage
The loss percentage is 91%.Given that Venessa bought 80 apples for 4$, out of these apples, 25% were rotten and had to be thrown away. Venessa sold the remaining apples at 6 cents per apple.To calculate the profit or loss percentage, we need to determine the cost price, selling price, and the number of apples sold.
Cost price (CP) = 4 $.Selling price (SP) = 80 × 0.75 × 6 cents= 36 cents = 0.36 $.Now, let's calculate the profit.Profit = SP – CP= 0.36 $ – 4 $= – 3.64 $Loss = CP – SP= 4 $ – 0.36 $= 3.64 $.
Therefore, Venessa incurred a loss of $3.64 when she sold 80 apples at 6 cents per apple.Now let's calculate the loss percentage Loss Percentage = (Loss / CP) × 100= (3.64 / 4) × 100= 91%.
Therefore, the loss percentage is 91%.Note: If the result obtained after the subtraction of SP from CP is negative, it means there is a loss, and the percentage of loss can be calculated by (loss/CP) × 100.
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help please ambree!!
Answer:
130 blackberries
Step-by-step explanation:
[tex]\displaystyle 600\biggr(\frac{78^\circ}{360^\circ}\biggr)=130[/tex]
WHICH STATEMENT ABOUT A QUADRILATERAL IS TRUE
A quadrilateral is a polygon with four sides. All trapezoids have two pairs of parallel sides. Option (a) is correct.
Understanding the Properties of QuadrilateralA quadrilateral is a polygon with four sides, and there are several properties and characteristics that can be true about a quadrilateral. Some possible true statements about a quadrilateral include:
1. A quadrilateral has four angles.
2. A quadrilateral has four vertices.
3. The sum of the interior angles of a quadrilateral is always 360 degrees.
4. A quadrilateral can have sides of different lengths.
5. A quadrilateral can have parallel sides.
Compare each of the properties above to the given options.
Options:
a) All trapezoids have two pairs of parallel sides.
b) Only some rectangles have four right angles.
c) All squares are rectangles.
d) Some rhombuses are trapezoids.
We can conclude that option (a) is correct because it correspond to the property 5 of a quadrilateral.
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please help me solve this
The minor arcs of the circle C are given as follows:
Arc LM.Arc MN.Arc NP.Arc PL.How to classify the arcs of a circle?The arcs of a circle can be classified as minor arcs or major arcs, depending on their angle measures, as follows:
Minor arcs: angle measure less than 180º.Major arcs: angle measure greater than 180º.The entire circumference of the circle is of 360º, hence we have that segment LN, connecting two points on the circumference of the circle through the center, represents the diameter of the circle, with an arc length of 180º.
Hence the minor arcs are all the arcs that are smaller than LN, given as follows:
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Draw the following shapes on geoboard paper. Find the area of each shape by partitioning it into sub-shapes and finding the areas of the sub-shapes. Remember to label your answers.
Draw the following shapes on geoboard paper. Surround each triangle with a rectangle so that the vertices of the triangle are on the exterior of the rectangle. Think about how you can use rectangles to determine the areas of right triangles that are inside the rectangles.
Answer:
I apologize, I am not able to provide visual drawings or diagrams. However, I can still provide a step-by-step guide to solve the problem.
To find the area of each shape, we need to use rectangles to determine the areas of right triangles that are inside the rectangles. Here are the steps:
1. Draw the given shape on geoboard paper.
2. Surround each triangle with a rectangle so that the vertices of the triangle are on the exterior of the rectangle.
3. Identify the right triangles that are inside the rectangles.
4. Use the formula for the area of a triangle, which is A = (base x height) / 2, to find the area of each right triangle.
5. Use the formula for the area of a rectangle, which is A = length x width, to find the area of each rectangle.
6. Add up the areas of the triangles and rectangles to find the total area of the shape.
Remember to label your answers with the correct units (square units).
Out of 200 students in a senior class, 10 students are varsity athletes and on the honor roll. There are 70 seniors who are varsity athletes and 68 seniors who are on the honor roll. What is the probability that a randomly selected senior is a varsity athlete or on the honor roll? Write your answer as a fraction in simplest form or as a decimal.
Answer: We can use the formula:
P(A or B) = P(A) + P(B) - P(A and B)
where A and B are two events.
In this case, we want to find the probability that a randomly selected senior is a varsity athlete or on the honor roll. We can define the events as follows:
A = the event that a senior is a varsity athlete
B = the event that a senior is on the honor roll
From the problem statement, we know:
P(A and B) = 10/200 = 1/20
P(A) = 70/200 = 7/20
P(B) = 68/200 = 17/50
Plugging these values into the formula:
P(A or B) = P(A) + P(B) - P(A and B)
= 7/20 + 17/50 - 1/20
= 21/50
Therefore, the probability that a randomly selected senior is a varsity athlete or on the honor roll is 21/50.
need help fast just answer
Step-by-step explanation:
The volume of a pyramid is 1/3 bh
First step is to find the base
The area of a triangle is 1/2 bh
We have both b and h of the base triangle
Area of base = 16.5 cm^2
Now we can sub. that in with the volume formula
1/3 16.5 x 9
1/3 x 148.5
49.49999999999995
13 and 4/20 converted to a decimal
The mixed number4 13/20 is equal to the decimal 4.65.
How to convert 13/20 to a decimalBy Converting the mixed number to an improper fraction
To convert 4 13/20 to an improper fraction, we multiply the whole number (4) by the denominator (20) and add the numerator (13) to get the new numerator. The denominator remains the same.
4 13/20 = (4 * 20 + 13) / 20 = 93/20
Dividing the numerator by the denominator:
Divide the numerator (93) by the denominator (20) to get the decimal representation.
93 ÷ 20 = 4.65
Therefore, the decimal representation of 4 13/20 is 4.65.
Complete question: How do you write 4 13/20 as a decimal
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Evaluate: 0.36×4.2_0.008÷25.5
The value of the expression 0.36 × 4.2 - 0.008 ÷ 25.5 is approximately 1.5116863.
To evaluate the expression 0.36 × 4.2 - 0.008 ÷ 25.5, we follow the order of operations, which is parentheses, exponents, multiplication and division (from left to right), and addition and subtraction (from left to right).
First, let's simplify the division: 0.008 ÷ 25.5 = 0.0003137 (rounded to six decimal places).
Now, we can substitute the simplified division back into the expression: 0.36 × 4.2 - 0.0003137.
Next, we perform the multiplication: 0.36 × 4.2 = 1.512.
Finally, we subtract the result of the multiplication from the simplified division: 1.512 - 0.0003137 = 1.5116863 (rounded to seven decimal places).
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PLEASE HELP ASAP! For show and tell, Sophie brought 28 trading cards to class. During the day, Sophie got 54 more from her friends. How many trading cards does Sophie have now?
Answer:
84
Step-by-step explanation:
28+54=84
Answer:84
Step-by-step explanation:
Hi! So to start/set up the problem, since Sophie brought 28 cards, that is how many she has so, so far we only have, 28+_=_.
The next step is to add 54 cards since she added that many. Now we have 28+54=_.
The last step is to calculate. 28+54=84.
Can someone please answer and provide an explanation for these problems?
The measure of the arc or angle indicated are:
(9). m∠KLN = 55°, (10). m∠LMN = 40°, (11). arc RT = 61°, (12). arc PR = 240°, (13). arc EG = 150° and (14). arc ? = 225°
How to calculate for the measure of the arc and angle indicated(9). m∠KLN = 1/2(arc NK - arc MK) {secant tangent angle}
m∠KLN = 1/2(160 - 50)
m∠KLN = 110/2
m∠KLN = 55°
(10). m∠LMN = 1/2(140 - 60)
m∠LMN = 80/2
m∠LMN = 40°
(11). 60° = 1/2(181 - arc RT)
120° = 181 - arc RT {cross multiplication}
arc RT = 181 - 120
arc RT = 61°
(12). Angle subtended by an arc of a circle at it's center is twice the angle it substends anywhere on the circles circumference.
arc PR = 2(120)
arc PR = 240°
(13). arc EG = 2(75)
arc EG = 150°
(14). m∠TUV = 180 - arc TV {angle between two tangents}
arc TV = 180 - 45
arc TV = 135°
the larger arc ? = 360° - 135°
arc ? = 225°.
Therefore, the measure of the arc or angle indicated are:
(9). m∠KLN = 55°, (10). m∠LMN = 40°, (11). arc RT = 61°, (12). arc PR = 240°, (13). arc EG = 150° and (14). arc ? = 225°
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Consider the quadrilateral above. It undergoes the following sequence of transformations:
Answer: (-2, -1)
Step-by-step explanation:
Ok since we just have to find A", let's transform only point A.
Point A=(-1, 5).
Now let's translate it: (-1+3, 5-4). Point A' = (2, 1).
Now, we have to do a 180° rotation. The formula is (-x, -y).
Point A'' = (-2, -1)
Toheebah ran round the playground 12 times. the playground is 240m by 160m.What distance did she cover?
Toheebah covered a distance of 9600 meters by running around the playground 12 times.To
How to determine 160m.What distance did she cover?The perimeter of a rectangle can be calculated by adding the lengths of all four sides. In this case, the playground has dimensions of 240 meters by 160 meters, so the perimeter is:
Perimeter = 2 * (Length + Width)
Perimeter = 2 * (240m + 160m)
Perimeter = 2 * 400m
Perimeter = 800m
Therefore, the perimeter of the playground is 800 meters.
To find the distance Toheebah covered by running around the playground 12 times, we multiply the perimeter by 12:
Distance covered = Perimeter * Number of laps
Distance covered = 800m * 12
Distance covered = 9600m
So, Toheebah covered a distance of 9600 meters by running around the playground 12 times.
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