The arrows in the diagram show the direction of the magnetic fields of the atoms that make up a certain material. Which object could the diagram represent ? A. A steel nail B. A refrigerator magnet C. A wooden log D. An iron bar

Answers

Answer 1

The diagram shows atoms with aligned magnetic fields, which means they are capable of producing a magnetic field themselves. The correct answer is option B.

This type of alignment is only found in materials that are magnetized, such as a refrigerator magnet. Steel nails and iron bars can also be magnetized, but they are typically only magnetic if they have been previously exposed to a magnetic field. Wood, on the other hand, is not capable of being magnetized as it does not have magnetic properties. Therefore, the diagram most likely represents a refrigerator magnet, which is made of a material that has been magnetized to produce a magnetic field. Option B is correct.

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Related Questions

Waves portfolios I will give brainliest!

Now, leave the frequency constant, but play with the amplitude. What is the affect of changing the
amplitude on the tone generated?

Answers

Now, leave the frequency of wave constant, but play with the amplitude. then the effect of changing the amplitude on the tone generated is its loudness. more the amplitude more it will be loud.

Wave is is a disturbance in a medium that carries energy as well as momentum . wave is characterized by amplitude, wavelength and phase. Amplitude is the greatest distance that the particles are vibrating. especially a sound or radio wave, moves up and down. Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.

Wavelength is the distance between two points on the wave which are in same phase. Phase is the position of a wave at a point at time t on a waveform. There are two types of the wave longitudinal wave and transverse wave.

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Gavin can type 1/2 page of his book report in 5 3/4 minutes what’s the typingrate

Answers

Answer:

Jim Crow Laws Effects.

User

What were Jim Crow laws? Your response should also describe at least two effects Jim Crow laws

had on the rights of Black Americans. (4 points)

ChatGPT

Jim Crow laws were a set of state and local laws in the United States, enacted between the 1870s and 1960s, that enforced racial segregation and discrimination against Black Americans. These laws were named after a popular 19th-century minstrel show character who stereotyped African Americans.

Two effects of Jim Crow laws on the rights of Black Americans were:

Limited access to public facilities: Jim Crow laws mandated that public spaces such as schools, parks, hospitals, and restaurants were segregated by race. Black Americans were often denied access to public spaces that were reserved for white people. This segregation limited the ability of Black Americans to participate fully in public life and access resources and opportunities that were available to white Americans.

Restricted voting rights: Jim Crow laws were used to disenfranchise Black Americans by making it difficult or impossible for them to vote. These laws included literacy tests, poll taxes, and other requirements that were designed to exclude Black Americans from voting. As a result, many Black Americans were unable to exercise their constitutional right to vote until the Voting Rights Act of 1965 was passed. This restriction on voting rights undermined the ability of Black Americans to participate fully in democracy and have their voices heard.

User

Gavin can type 1/2 page of his book report in 5 3/4 minutes what’s the typingrate

ChatGPT

To calculate Gavin's typing rate, we need to divide the amount he can type by the time it takes him to type it.

First, we need to convert the mixed number 5 3/4 into an improper fraction:

5 3/4 = (4 x 5 + 3)/4 = 23/4

Next, we can convert the mixed number 1/2 into an improper fraction:

1/2 = 2/4

Now, we can add the two fractions:

23/4 + 2/4 = 25/4

This means that Gavin can type 25/4 pages in 5 3/4 minutes.

To find Gavin's typing rate, we need to divide the amount he can type (25/4 pages) by the time it takes him to type it (5 3/4 minutes):

Typing rate = (25/4) / (5 3/4)

To divide fractions, we can multiply the first fraction by the reciprocal of the second fraction:

Typing rate = (25/4) x (4/23)

Simplifying the fractions, we get:

Typing rate = 25/23

Therefore, Gavin's typing rate is 25/23 pages per minute.

A skier slides horizontally along the snow for a distance of 22 m before coming to rest. The coefficient of kinetic friction between the skier and the snow is 0.15. Initially, how fast was the skier going, in meters per second?

Answers

The skier was initially going at 8.046 m/s velocity.

Assume that the skier's initial velocity is v.

The skier travelled 22 metres before coming to a stop.

The kinetic friction coefficient between the skier and the snow is 0.15.

The force of friction acting on the skier is given by:

friction = coefficient of friction multiplied by normal force

The normal force is equal to the weight of the skier, which can be calculated as:

weight = mass x gravity

Assuming the mass of the skier to be m and the acceleration due to gravity to be g, we get:

weight = m x g

The force of friction can then be calculated as:

friction = 0.15 x m x g

The work done by the force of friction is equal to the initial kinetic energy of the skier, which can be expressed as:

work done by friction = 0.5 x m x [tex]v^2[/tex]

Equating the work done by friction to the initial kinetic energy, we get:

0.5 x m x [tex]v^2[/tex] = 0.15 x m x g x 22

Simplifying the equation, we get:

[tex]v^2[/tex] = 2 x 0.15 x 9.8 x 22

When we take the square root of both sides, we get:

v = 8.046 m/s

As a consequence, the skier began moving at 8.046 m/s.

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The diagram below shows the velocity vectors for two cars that are moving
relative to each other.
45 m/s west
25 m/s east
Car 1
Car 2
From the frame of reference of car 1, what is the velocity of car 2?
OA. 20 m/s west
OB. 70 m/s east
C. 70 m/s west
D. 20 m/s east

Answers

The relative velocity of the car 2 with respect to car 1 is 70 m/s west. So, the correct option is C.

Velocity of the car 1 with respect to the ground, v₁ = 45 m/s west

Velocity of the car 2 with respect to the ground, v₂ = 25 m/s east

Let the direction towards the east be positive and the opposite direction towards the west be negative.

The expression for the relative velocity of the car 2 with respect to car 1 is given by,

v₂₁ = v₂ - v₁

v₂₁ = 25 - (-45)

Therefore, the relative velocity,

v₂₁ = 70 m/s west

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Attaching the image file here.

4 Starting from rest on a level road a girl can reach a speed of 5 m/s in 10s on her bicycle. a Find the acceleration b Find the average speed during the 10s. c Find the distance she travels in 10 s. [2] Eventually, even though she still pedals as fast as she can, she stops accelerating and her speed reaches a maximum value. Explain in terms of the forces acting why this happens. ​

Answers

a. To find the acceleration, we can use the equation:

acceleration = change in velocity / time taken

Here, the initial velocity is 0 m/s (since she starts from rest), the final velocity is 5 m/s, and the time taken is 10 s. Therefore:

acceleration = (5 m/s - 0 m/s) / 10 s = 0.5 m/s^2

So the acceleration of the girl on her bicycle is 0.5 m/s^2.

b. The average speed during the 10 s can be found by dividing the total distance traveled by the time taken. We don't know the distance traveled yet, so we can use another equation:

distance = (initial velocity x time taken) + (0.5 x acceleration x time taken^2)

Here, the initial velocity is 0 m/s, and the time taken is 10 s. We already calculated the acceleration in part (a) as 0.5 m/s^2. Plugging these values in, we get:

distance = (0 m/s x 10 s) + (0.5 x 0.5 m/s^2 x (10 s)^2) = 25 meters

So the girl traveled 25 meters in 10 seconds.

c. As the girl pedals, she applies force to the pedals, which in turn transfers the force to the rear wheel. This force drives the bicycle forward, causing it to gain speed. However, when the bicycle picks up speed, air resistance (also called drag) comes into play, which increases. Eventually, the force of air resistance becomes equal and opposite to the force that propels the bicycle forward. This means that the net force on the bicycle becomes zero, stopping its acceleration and reaching its maximum speed, known as the terminal velocity. Even if the girl pedals faster, she won't be able to increase her speed because the drag force counteracts the propelling force.

1. Which of the following does not affect the resistance of a wire?
a) Length
b) Temperature
c) Usage time
d) Cross-sectional area
2. If a 12V battery is passing current through a resistor with a current of 2A, what is the value of the resistor?
a 24resistance
b) 14resistance
c) 10resistance
d) 6resistance
3. Describe the differences between series and parallel circuits.
4. A circuit contains resistors of 8resistance and 4resistance,what is combined resistance if the resistors are combined:
a) In series
b) In parallel
5. A 0.5A current is passing across three resistors of 8resistance, 4resistance and 12resistance that are linked in series.
What is the potential difference of the circuit?
6. Wire A has a resistance of 24resistance. If wire B is double the length and has a diameter four times as large as wire A, what is the resistance of wire B?

Answers

The answer right there is b

A plane wave in a nonmagnetic medium has E = 50 sin (10^8 + 2*z) ay V/m. Find (a) The direction of wave propagation (b) λ, f, and Er (c) H​

Answers

(a) The direction of wave propagation is along the negative z-axis.

(b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × [tex]10^{7}[/tex] Hz, and the wave impedance (Er) is approximately 0.1667 sin ([tex]10^{8}[/tex] + 2z) ohms.

(c) The magnetic field (H) is (50 sin ([tex]10^{8}[/tex] + 2z)) / (3 × [tex]10^{8}[/tex]) ay A/m.

If the direction of wave propagation is specified as along the negative z-axis, we can conclude that the wave is traveling in the opposite direction to the positive z-axis. In the given expression: E = 50 sin(10^8 + 2z) ay V/m

Since the wave is traveling along the negative z-axis, it means that as z increases (in the positive direction), the wave is propagating in the opposite direction.

Hence, the direction of wave propagation for the given wave is along the negative z-axis.

To find the wavelength (λ), frequency (f), and wave impedance (Er), we can relate the electric field (E) and magnetic field (H) components using the wave equation in a nonmagnetic medium:

E = c * H,

where c is the speed of light in the medium, which can be approximated as 3 × [tex]10^{8}[/tex] m/s in free space.

(a) Direction of wave propagation: Along the positive z-axis.

(b) Calculating λ, f, and Er:

Since the electric field (E) is given as E = 50 sin ([tex]10^{8}[/tex] + 2z) ay V/m, we can see that the angular frequency (ω) is [tex]10^{8}[/tex] rad/s and the wave number (k) is 2.

The relationship between wave parameters is given by: c = λ * f, where c is the speed of light.

Using the relation c = ω/k, we can solve for λ and f:

λ = 2π/k = 2π/2 = π m (meters)

f = ω/2π = [tex]10^{8}[/tex]/2π ≈ 1.59 × [tex]10^{7}[/tex] Hz (Hertz)

To find the wave impedance (Er), we can use the equation Er = E/H:

Er = E/c = (50 sin ([tex]10^{8}[/tex] + 2z)) / (3 × [tex]10^{8}[/tex]) ≈ 0.1667 sin ([tex]10^{8}[/tex] + 2z) ohms.

(c) The magnetic field (H) can be calculated using the relationship H = E/c:

H = (E/c) = (50 sin ([tex]10^{8}[/tex] + 2z)) / (3 × [tex]10^{8}[/tex]) ay A/m.

The direction of wave propagation is along the negative z-axis. (b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × [tex]10^{7}[/tex] Hz, and the wave impedance (Er) is approximately 0.1667 sin ([tex]10^{8}[/tex] + 2z) ohms. The magnetic field (H) is (50 sin ([tex]10^{8}[/tex] + 2z)) / (3 × [tex]10^{8}[/tex]) ay A/m.

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An isolated charged conductor sphere of radius 12cm has an electric field 49000 N/C at distance 21cm its center
What is its surface charge denisty

Answers

The surface charge density of the isolated charged conductor sphere is approximately 22.15 [tex]C/m^{2}[/tex]

The surface charge density of an isolated charged conductor sphere can be determined using the formula:

σ = E / ([tex]4πr^{2}[/tex])

where σ is the surface charge density, E is the electric field strength, and r is the distance from the center of the sphere.

In this case, the electric field strength E is given as 49000 N/C, and the distance from the center of the sphere r is 21 cm (which can be converted to meters as 0.21 m). Plugging these values into the formula, we have:

σ = (49000 N/C) / [tex](4π * (0.21 m)^{2})[/tex]

Calculating this expression, we find:

σ ≈ 22.15 [tex]C/m^{2}[/tex]

Therefore, the surface charge density is approximately 22.15 [tex]C/m^{2}[/tex]. This indicates the amount of charge per unit area distributed on the surface of the sphere.

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weight of a person is less inside the deep cave​

Answers

The weight of a person is less inside the deep cave​ because, the acceleration due to gravity decreases as we go down towards the depth.

What is meant by gravity ?

Gravity is defined as the force that pulls a body towards the centre of the earth or any other mass-containing physical body.

Here,

Since weight is directly proportional to the acceleration due to gravity, it changes as we travel deeper inside the earth.

This is because as we travel deeper, the acceleration due to gravity also decreases. As a result, the weight decreases when the acceleration due to gravity decreases. Mass is constant; it doesn't change at all.

The gravitational field weakens, and your weight falls as you travel closer to the centre because there is progressive decrease in the acceleration due to gravity as, we go down towards the centre.

Hence,

The weight of a person is less inside the deep cave​ because, the acceleration due to gravity decreases as we go down towards the depth.

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What is the minimum amount ( in kg) of liquid water at 26 degrees that would be required to completely melt 41 grams of ice? The specific heat capacity of liquid water is 4180 J/kg/°C and the specific heat of fusion of ice is 3.33×105 J/kg.

Answers

Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.


To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.

The energy required to melt 1 kg of ice is 3.33×105 J/kg.

Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.

To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.

Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.

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A particle of mass 2unit moves along space curve defined by ~r(t) = (4t 2 − t 3 )ˆi − 5tˆj + (t 4 − 2)ˆk. Find the force acting on it at any time to work out​

Answers

The force acting on the particle at t = 1 s is 24.4 N.

Mass of the particle, m = 2 units

Distance of the curve, r(t) = (4t²- t³)i - 5tj + (t⁴- 2)k

The velocity of the particle,

v = d[r(t)]/dt = (8t - 3t²)i - 5j + 4t³k

The acceleration of the particle,

a = d²[r(t)]/dt² = (8 - 6t)i + 12t²k

Let the time for which the force is acting be 1 second.

Therefore, acceleration at t = 1 is,

a₁ = 2i + 12k

Hence, the magnitude of acceleration,

|a₁| = √(2²+ 12²)

|a₁| = √148

|a₁| = 12.2 unit/s²

Therefore, the force acting on the particle at t = 1 s is,

F₁ = m x |a₁|

F₁ = 2 x 12.2

F₁ = 24.4 N

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