The auroras occur in the
C.
a. troposphere
b. stratosphere
mesophere
d. ionosphere

Answers

Answer 1

Answer:

Ionosphere

Explanation:

The thermosphere reaches 600 kilometres just above mesosphere and begins immediately above the mesosphere. This layer is where the aurora and satellites appear.

The ionosphere is the comprehensive career of the mesosphere because most of the thermosphere, located 80–400 kilometres just above ground atmosphere.

Auroras — magnificent flowing streaks of light seen in the night sky – appear in this location.


Related Questions

accord and a track have the same speed of 30 metre per second if their masses are in the ratio of 1 is to 3 find the ratio of the Kinetic energies ​

Answers

Answer:

The ratio of kinetic energy of accord to the truck is 1 : 3.  

Explanation:

Speed, v = 30 m/s

Ratio of mass of accord to truck = 1 : 3

The kinetic energy is given by

[tex]K = 0.5 mv^2[/tex]

As the speed is same so the ratio of the kinetic energies is same as the ratio of masses.

[tex]\frac{K_{accord}}{K_{Trcuk}} =\frac{m_{accord}}{m_{Trcuk}}\\\\\frac{K_{accord}}{K_{Trcuk}} = \frac{1}{3}[/tex]

The symbol for the hydroxide ion is
Он*
Оно
ОН(ОН)
ООН
NEXT QUESTION
ASK FOR HELP

Answers

It is OH and it has a charge of negative 1

1. The algebraic letter 'dy' stands for

Answers

I think it’s the derivative of y

A 45.2 kg softball player slides across dirt with Uk=0.340. What is her acceleration?

Answers

Answer:

The answer is -3.34 m/s^2.

Explanation:

I used another brainly question to help me find the answer. It was pretty similar to this one so yeah. Good luck to you nonetheless.

https://brainly.com/question/25065591

A cheetah runs at a speed of 27.6 m/s. If the
cheetah runs for 9.30 s, what is the distance the
cheetah runs? Show all your work.

Answers

Answer:

256.68m

Explanation:

that is the procedure above

A cheetah runs at a speed of 27.6 m/s. If the cheetah runs for 9.30 s, then the distance covered by the cheetah would be 256.68 metes

What is speed?

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is meter/second. The generally considered unit for speed is a meter per second.

The mathematical expression for speed is given by

speed = distance /Total time

As given in the problem A cheetah runs at a speed of 27.6 m/s. If the cheetah runs for 9.30 s, we have to calculate the distance covered by the cheetah

Distance=?

speed=27.6 m/s

time= 9.30 s

speed = distance /Total time

27.6 m/s = Distance /9.30 s

Distance = 27.6×9.30

               =256.68 metes

Thus, the distance covered by the cheetah would be 256.68 metes

Learn more about speed from here

brainly.com/question/7359669

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Which of the following is NOT accelerating?
Group of answer choices

A Ferris wheel turning at a constant speed

A plane gaining speed down a runway

A runner speeding around the curve toward the finish line

A car traveling down a straight highway at constant speed

Answers

I would say the answer to your question is A Ferris wheel turning at a constant speed. The reasoning behind this answer is the fact that traveling in a constant direction at a constant speed is not accelerating. The Ferris wheel is the only option that fits this description. The last option would be incorrect due to independent causes such as speed limit changes as well as turns and stops on the highway.

when a volcano is about to erupt, the nearby places may also experience an earthquake

TRUE OR FALSE​

Answers

Answer:

True

Explanation:

Volcanically-caused long period earthquakes are produced by vibrations generated by the movement of magma or other fluids within the volcano. Pressure within the system increases and the surrounding rock fails, creating small earthquakes.

a sphere of mass 5kg and volume 2×10-5completely immersed in water find the buoyant force exerted water​

Answers

Answer:

Buoyant force exerted water​ =  0.196 Newton

Explanation:

Given:

Mass of sphere ball = 5 kg

Volume = 2 x 10⁻⁵

Find:

Buoyant force exerted water​

Computation:

Buoyant force exerted water​ = Gravity due to acceleration x volume of object x density of given liquid

Buoyant force exerted water​ = 9.8 x 2 x 10⁻⁵ x 1000

Buoyant force exerted water​ =  0.196 Newton

what is the difference between acceleration due to gravity and gravitational force?​

Answers

Answer:

Gravity.” or “Gravity causes the moon to orbit the earth.” “Acceleration due to gravity” is much more precise. It is the acceleration that an object experiences when it is dropped with no other external forces on it. ... Near the surface of the earth the acceleration due to gravity is about 9.8

Answer:

Acceleration due to gravity is the rate of change in velocity of a body under the influence of gravitational fields while gravitational force is the force of one newton experinced by a body of 1 kg mass placed in gravitational fields.

True or false please help I’ll give brainliest

Answers

Answer:

7. F

8. T

Explanation:

7. An anion is indicated by a negative superscript charge (- something) to the right of the atom. For example, if a sodium atom loses one electron, it will have one more proton than electron, giving it an overall +1 charge. The chemical symbol for the sodium ion is Na+1 or just Na+

8.Like charges repel each other; unlike charges attract. Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges

1.) False

2.) True

hope this helped,, good luck!! :]

least count of vernier caliper is dash​

Answers

Answer:

0.02 is the count of vernier caliper.

Answer:

0.01 mm

A Vernier calliper scale can have a minimum count of 0.01 mm, while a micrometre can have a minimum count of 0.001 mm.

A -0.00125 C charge is placed 3.62 m from a +0.00333 C charge. What is the magnitude of the electric force between them?

Answers

Answer:

The magnitude of the force between the charges is approximately -2,858.77 N

Explanation:

The given details are;

The magnitude of the given charges;

q₁ = -0.00125 C, q₂ = +0.00333 C

The distance between the charges, r = 3.62 m

The magnitude of the electric force between the charges, 'F', between two charged particles or objects is given as follows;

[tex]F = \dfrac{k \cdot q_1 \cdot q_2}{r^2}[/tex]

Where;

k = Constant = 9 × 10⁹ N·m²/C²

q₁ = The magnitude of charge on the first charged object = -0.00125 C

q₂ = The magnitude of charge on the second charged object = +0.00333 C

r = The distance between the charges = 3.62 m

Plugging in the values, gives;

[tex]F = \dfrac{9 \times 10^9 \ \dfrac{N \cdot m^2}{C^2} \times (-0.00125 \, C) \times (+0.00333 \, C)}{\left( 3.62 \, m \right)^2} \approx -2,858.77 \, N[/tex]

The magnitude of the force between the charges, F ≈ -2,858.77 N

IV. The table below shows how the speed of a car changes with time. 1 What is the acceleration of the car? please help! :(​

Answers

Acceleration = change in velocity/ time

So I believe that the change in velocity will be 20-0 which is 20

And the time will be 5

Therefore 20/5 so the acceleration will be 4

What is the ratio of surface area to volume for a sphere with the following measurements?
surface are=432m^2
volume=864m^3

Answers

Answer:

S:V = 1 : 2

Explanation:

Given the following data;

Surface area, S = 432 m²

Volume, V = 864 m³

To find the ratio of surface area to volume for a sphere;

The ratio of two or more numbers are determined by reducing the numbers to their nearest minimum i.e dividing all through by the same or common number.

S:V = 432 : 864

Dividing both sides by 432, we have;

S:V = 432/432 : 864/432

S:V = 1 : 2

¿Cuál es el valor del coeficiente de roce estático entre dos superficies, sabiendo que para poner en movimiento un cuerpo de 35kg. Es necesario, vencer una fuerza de resistencia de 45 Newton?

Answers

Answer:

El coeficiente de roce estático entre las dos superficies es 0.131.

Explanation:

El coeficiente de roce estático entre dos superficies ([tex]\mu_{s}[/tex]), sin unidad, es igual a la fuerza de resistencia ([tex]F[/tex]), en newtons, dividida por el peso del cuerpo a mover ([tex]W[/tex]), en newtons.

[tex]\mu = \frac{F}{m\cdot g}[/tex] (1)

Donde:

[tex]m[/tex] - Masa, en kilogramos.

[tex]g[/tex] - Aceleración gravitacional, en metros por segundo al cuadrado.

Si sabemos que [tex]F = 45\,N[/tex], [tex]m = 35\,kg[/tex] y [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], entonces el coeficiente de roce estático es:

[tex]\mu = \frac{45\,N}{(35\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}[/tex]

[tex]\mu = 0.131[/tex]

El coeficiente de roce estático entre las dos superficies es 0.131.

The hull of a sunken boat, laying on the seabed, is 9 m below the surface of the sea, where the sea water has an average density of 1,025 kg/m3. The hull’s surface area is 12 m2. What is the total force exerted by seawater on the hull?Required to answer. Single line text.

Answers

Answer:

1084860 N

Explanation:

Applying,

P = ρgh................ Equation 1

Where P = pressure, ρ = density, h = height, g = acceleration due to gravity.

From the question,

Given:  ρ = 1025 kg/m³, h = 9 m

Constant: g = 9.8 m/s²

Substitute these values into equation 1

P = (1025)(9)(9.8)

P = 90405 N/m²

Also,

P = F/A.............. Equation 2

Where, F = Force, A = Area.

Make F the subject of the equation

F = PA............... Equation 2

Given: A = 12m²

F = 12(90405)

F = 1084860 N

A person is pushing a box across a table. The measured forces on the box are 10N, 14N, -7N, -10N.

Which force is represented by -7N?

A) force of friction
B) normal force
C) force of gravity
D) push force

Answers

Answer:

the answer to this question is c

Answer:

A) force of friction

Explanation:

frictional forces are always negative, they are an opposing force they act opposite to the applied force.

Tâm ống dẫn đặt dưới đường phân giới giữa nước và thuỷ ngân h1 = 820mm, chênh lệch chiều cao cột thuỷ ngân h2 = 880mm (Hg = 13,6). Ap suất dư tại điểm A trong ống dẫn (at)?

Answers

Answer:

P = 79993.43245

Explanation:

Được -

Vị trí tâm ống dẫn dưới đường thuỷ ngân h1 = 820 mm

Chênh lệch chiều cao của cột thủy ngân h2 = 880mm

Tỷ trọng của thủy ngân = 13,5951 g / cm3

P = mật độ * gia tốc do trọng lực a * h

Thay thế các giá trị đã cho, chúng ta nhận được -

P = 13,5951 g / cm3 * 980,665 cm / s2 * (88-82) cm

P = 79993.43245

A diverging lens will always produce an image with _______.
a) a negative focal length and a magnification more than 1
b) a positive focal length and a magnification more than 1
c) negative focal length and magnification less than 1
d) a positive focal length and a magnification less than 1

Answers

Answer:

Option C

Explanation:

Diverging lens are negative lens as they have negative focal length. Their

magnification is smaller than one.

They produce virtual image in which the refracted rays extended back in order to meet

Hence, option C is correct

calculate the answer to the correct number of significant digits
0.055 * 5.1 =

Answers

Answer:

0.055 * 5.1 = 0.2805

Explanation:

I used a calculator so it should be accurate! yw!! :D

the acceleration of a moving vehicles is 10 metre per second square what does it means ​

Answers

Answer:

Acceleration is the rate of change of velocity. What is commonly said as ‘ten meter per second squared’ can bee broken down into ‘ten meter per second per second.’ This gives us the true meaning of the term acceleration.

Just like ‘ten meter per second’ means increasing the displacement by ten meters every second, ‘ten meter per second per second’ means increasing the velocity by ten meters per second every second.

So, basically if you consider the case of a free fall motion, where ‘t’ stands for time and ‘v’ stand for velocity at that instant:

At,

t=0, v=0 m/s

t=1, v=0+10 m/s;

t=2, v=0+10+10 m/s;

t=3, v=0+10+10+10 m/s;

This can also be thought as a Arithmetic Progression where common difference ‘D’ is the acceleration(a), since it adds a 10 m/s to velocity every second and the first term ‘A’ stands for the initial velocity (u). Using this approach we can derive to the first equation of motion:

v = u + at

Hope this Answer Helps!!

Explanation:

plz mark me as a brainlest and thank my answer

It means that the vehicle's speed increases at the rate of 10m/s every second.

At any time, it's speed is 10 m/s faster than it was 1 second earlier.

''Hydropower is also the product of solar energy''. clarify this statement​

Answers

Answer:

well, hydropower is using fast-running water as a source of power to power machines or produce electricity, and using water can help make the earth a little cleaner, just like solar energy (energy from the sun). instead of using things like coal, oil, gas which is bad for the earth

Explanation:

what is it called when a body covers certain distance per unit time​

Answers

Explanation:

Hey there!

The answer is Speed.

Reason:

Simply we know that distance (d) = speed*time

and speed = distance/ time. And according to the question, when a body covers certain distance/unit time, it's speed.

Hope it helps!

Does the nucleus of animal or plant cells contain chromosomes?​

Answers

both animal and plant cells contain chromosomes

Answer:

both animal and plant cells contain chromosomes

what two forces contribute to the nuclear tug of war in an atom

Answers

Answer:2 protons and 2 neutrons

Explanation:In Nuclei, There are 2 forces. 1 force is electrostatic and acts as repulsion between 2 protons. The other is force of attraction called Nuclear force between 2 neutrons.

if escape velocity and orbital velocity of a satellite for Orbit close to the Earth's surface then these are related by​

Answers

Answer:

The ratio of the escape velocity to the orbital velocity is [tex]\sqrt 2[/tex].

Explanation:

The minimum velocity given to an object so that it escapes from the earth's gravitational pull is called escape velocity.

The formula of the escape velocity is

[tex]v=\sqrt\frac{2GM}{R}[/tex]

The velocity of an object in the orbit around the earth is called orbital velocity.

The formula of the orbital velocity is

[tex]v=\sqrt\frac{GM}{R}[/tex]

The ratio of the escape velocity to the orbital velocity is

[tex]\frac{v_e}{v_o}=\sqrt 2[/tex]

4. Alcohol of mass 21g and density 0.7gcm-3 is mixed with 10g of water. Determine the density
of the mixture. (density of water = 1.0g cm-3)

Answers

Answer:

The density of the mixture is 0.775 g/cm³

Explanation:

The given parameters are;

The mass of the alcohol, m₁ = 21 g

The density of the alcohol, ρ₁ = 0.7 g/cm³

The mass of the water with which the alcohol is mixed, m₂ = 10 g

The density of wate, ρ₂ = 1.0 g/cm³

The density of a substance is given by the ratio of the mass to the volume of the substance

The density of the mixture, ρ is given as follows;

[tex]\rho = \dfrac{m_1 + m_2}{\dfrac{m_1}{\rho_1} + \dfrac{m_2}{\rho_2} }[/tex]

Therefore;

[tex]\rho = \dfrac{21 + 10}{\dfrac{21}{0.7} + \dfrac{10}{1.0} } = 0.775[/tex]

The density of the mixture, ρ = 0.775 g/cm³.

state the factor that affect the gravity of a planet​

Answers

Answer:

The planet's mass and size determine the gravity of a planet

Explanation:

The smaller and less mass a planet has, the less gravitational pull it has on things and vice versa. The same can be applied with all living things, we all have an extremely small gravitational pull.

a condenser of capacitor 50 micro coulomb is charged to 10 volt the energy stored is can you do derivation please

Answers

Answer:

2.5x10^-3 J

Explanation:

C=50mC

V=10V

U=1/2 C (V)^2

=1/2(50)(10)^2 x (10)^-6

=25(100)/1000000

=2.5x10^-3

(Please help if you can, I need this last answer done by tonight.)
Use the universal law of gravitation to solve the following problem.


Hint: mass of the Earth is = 5.97 x 1024 kg


A scientific satellite of mass 1300 kg orbits Earth 200 km above its surface. If Earth has a radius of 6378 km, what is the force of gravity acting on the scientific satellite?


a. Write out the formula for this problem.


b. Plug in the values from this problem into the formula.


c. Solve the problem, writing out each step.


d. Correct answer

Answers

Answer:

11963.43 N

Explanation:

From the question given above, the following data were obtained:

Mass of the earth (Mₑ) = 5.97x10²⁴ Kg

Mass of satellite (Mₛ) = 1300 Kg

Radius of the earth (R) = 6378 km

Distance between the earth and satellite (r) = R + 200 Km = 6378 + 200 = 6578 Km

Force of gravity (F) =?

Next, we shall convert 6578 Km to m. This can be obtained as follow:

1 Km = 1000 m

Therefore,

6578 Km = 6578 Km × 1000 m / 1 Km

6578 Km = 6578000 m

Finally, we shall determine the force of gravity. This can be obtained as follow:

Mass of the earth (Mₑ) = 5.97x10²⁴ Kg

Mass of satellite (Mₛ) = 1300 Kg

Distance apart (r) = 6578000 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force of gravity (F) =?

F = GMₑMₛ / r²

F = (6.67×10¯¹¹ × 5.97x10²⁴ × 1300) / (6578000)²

F = 11963.43 N

Therefore, the force of gravity on the scientific satellite 11963.43 N

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