The circular floor of a teepee has a diameter of 9 yards. What is the circumference of the floor?

30 points pls show ur work thank u so much!!! :)

Answer:

C

Step-by-step explanation:

If you put 2 different values in for x and it happens 2 times, the eqyations must be equivilent :)

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Answer:

7.011%

Step-by-step explanation:

61/(300+100+7+61+402) = 0.07011

Multiply the result of that by 100 to get 7.011%.

Answer:

x=1/3

Step-by-step explanation:

Answer:

36 Minutes

Step-by-step explanation:

150/8=18.75

675/18.75=36

So hence, your answer is 36 Minutes

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Answer:

60

Step-by-step explanation:

east and north are two axis that are perpendicular to each other, so if we use Pythagorean rule, sqr60^2+20^2=20sqr10, approximately 63.24555

[tex]\bold{\huge{\underline{ Solution }}}[/tex]

Here,

The dimension of larger cuboid are

We know that,

Lateral surface area of cuboid

[tex]\bold{\red{ = 2( lb + bh + hl)}}[/tex]

Subsitute the required values,

[tex]\sf{ = 2[(7)(7) + (7)(12) +(7)(12) ]}[/tex]

[tex]\sf{ = 2[ 49 + 84 ]}[/tex]

[tex]\sf{ = 2[ 49 + 168 ]}[/tex]

[tex]\sf{ = 2[ 217 ]}[/tex]

[tex]\bold{ = 434 cm^{2}}[/tex]

We have to find the lateral surface area of smaller cuboid

Therefore,

Lateral surface area of smaller cuboid

[tex]\sf{ = 2[(2)(7) + (7)(2) +(2)(2) ]}[/tex]

[tex]\sf{ = 2[ 14 + 14 + 4 ]}[/tex]

[tex]\sf{ = 2[ 28 + 4 ]}[/tex]

[tex]\sf{ = 2[ 32]}[/tex]

[tex]\bold{ = 64 cm^{2}}[/tex]

The common base area of both the cuboids

[tex]\sf{ = lb }{\sf{ + lb}}[/tex]

[tex]\sf{ = 14 + }{\sf{ 14}}[/tex]

[tex]\bold{ = 28 cm^{2}}[/tex]

The total surface area of the given composite figure

= SA of larger cuboid + SA of smaller cuboid - common base area

Subsitute the required values,

[tex]\sf{ = 434 + 64 - 28 }[/tex]

[tex]\sf{ = 498 - 28 }[/tex]

[tex]\bold{ = 470cm^{2}}[/tex]

Hence, The surface area of composite figure is 470 cm² .

Answer:

470cm²

Step-by-step explanation:

SA= (12*7)*4+(7*7)*2+(2*2)*2+(7*2)*2

=336+98+8+28

= 470 cm²

Therefore, the surface ares is 470 cm².

~

Answer:

<1 = 77

<2 = 103

<3 = 77

Step-by-step explanation:

<1 = 77 (180-103) by Linear Pair Postulate

<2 = 103 by Vertical Angles Theorem

<3 = 77 by Vertical Angles Theorem

Answer:

For number question #8 its 8/3

Step-by-step explanation:

One way i do is multiply the denominator by the whole number and then add the numerator . For example 2 2/3

2x3=6     6+2=8

Do NOT change the numerator, it stays the same.

Answer:

abcd = -24

Step-by-step explanation:

First, remember that the default operation in algebra is multiplication, so we have to multiply a and b and c and d together to get the answer:

abcd = a × b × c × d

Plugin your values to get the total of:

3 x -2 × 4 × 1 = -24

So the answer to this problem is -24

Answer:

t(d(n)) = 12n + 7

Step-by-step explanation:

t(d(n)) = t(4n + 2)

Substitute the function d(n) into the function t(d) for the variable d.

t(4n + 2) = 3(4n + 2) + 1  

t(d(n)) = 12n + 7

Answer: 0.29

Step-by-step explanation:

The probability of the first being blue is 6/17, the second is 5/16 and the third is 4/15.  Multiply these together to get the total probability:

6/17 x 5/16 x 4/15 = .029

Answer:

10x5.08

Step-by-step explanation:

Answer:

-1

Step-by-step explanation:

5-2=3

2-3=-1

Answer:

787 times 2554 equals 2,009,998

Step-by-step explanation:

Hope that helps!

Answer:

Probability of drawing a yellow candy: 10/36= 5/18

Something besides a yellow candy: for ecample: the red candies: 8/36= 2/9

Step-by-step explanation:

Probability of drawing yellow candies equals the sum of candies over yellow candies.

Answer:

=−148

     3

(Decimal: -49.333333)

Step-by-step explanation:

−364

9

−(

−102

9

)−

182

9

Answer:

hello the data required is missing attached below is the missing data and solution

Answer : Fail to reject H[tex]_{0}[/tex] and conclude that the mean value of weight 1 is the same for Managers and supervisors in the population

Step-by-step explanation:

At 5% level of significance the conclusion of this test is  Fail to reject H[tex]_{0}[/tex] and conclude that the mean value of weight 1 is the same for Managers and supervisors in the population.

The value of the test statistic tcal = 0.7402 lies between the critical values

±[tex]t_{\frac{0.05}{2.2} }[/tex] = ±2.086

attached below is the detailed solution and missing part of the question

The volume of the rectangular prism with the dimensions given are as follows:

v = 72 inches³

v = 36 inches³

v =  80 inches³

v = 54 inches³

where

l = length

w = width

h = height

Therefore,

a.  

b.

c.

d.

learn more on rectangular prism here: https://brainly.com/question/13512346

Answer:

I don't know-how to answer that

Answer: -3

Step-by-step explanation:

[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$8911\\ r=rate\to 7.71\%\to \frac{7.71}{100}\dotfill &0.0771\\ t=years\dotfill &20 \end{cases} \\\\\\ A=8911e^{0.0771\cdot 20}\implies A=8911e^{1.542}\implies A\approx 41649.38[/tex]

Answer:

me sandip is a jokeerrrr..........

Step-by-step explanation:

no god sucks......... **** brainly

Answer:

$20

Step-by-step explanation:

The large ones cost $4 more so what you would do is to subtract that $4 from the $24.

24-4=20

Origin = [tex](0, 0)[/tex]

Point = [tex](-18, 24)[/tex]

Distance = [tex]\sqrt{(24 - 0)^2 + (-18 - 0)^2} = \sqrt{24^2 + (-18)^2} = \sqrt{576 + 324} = \sqrt{900} = 30[/tex]

The distance from the origin to the point (-18, 24) is 30 units.

To find the distance from the origin (0, 0) to the point (-18, 24), we can use the distance formula in two-dimensional Cartesian coordinates.

The distance formula between two points [tex](x_1, y_1) and\ (x_2, y_2)[/tex] is given by:

[tex]\[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\][/tex]

In this case, the coordinates of the origin are (0, 0) and the coordinates of the point are (-18, 24). Plugging these values into the distance formula, we get:

[tex]\[d = \sqrt{(-18 - 0)^2 + (24 - 0)^2} = \sqrt{(-18)^2 + 24^2} = \sqrt{324 + 576} = \sqrt{900} = 30\][/tex]

So, the distance from the origin to the point (-18, 24) is 30 units.

To know more about distance, refer here:

https://brainly.com/question/30717348

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Answer:

I am pretty sure it is

y >_ 20(0.061)^t

t >_ 0

Step-by-step explanation:

Answer:

none

Step-by-step explanation:

plug it in, it doesnt add up

For the integral ∫asin(x)dx, use integration by parts ∫udv=uv−∫vdu.

Let u=asin(x) and dv=dx.

Then du=(asin(x))′dx=[tex]\rm \dfrac{dx}{ \sqrt{1 - {x}^{2} } } [/tex] and v=∫1dx=x

So,

[tex] \rm{\int{\operatorname{asin}{\left(x \right)} d x}}=\color{h}{\left(\operatorname{asin}{\left(x \right)} \cdot x-\int{x \cdot \frac{1}{\sqrt{1 - x^{2}}} d x}\right)}=\color{h}{\left(x \operatorname{asin}{\left(x \right)} - \int{\frac{x}{\sqrt{1 - x^{2}}} d x}\right)} \\ [/tex]

Let u=1−x2.

Then du=(1−x2)′dx=−2xdx and we have that xdx=−du/2.

The integral can be rewritten as

[tex] \rm x \operatorname{asin}{\left(x \right)} - \color{g}{\int{\frac{x}{\sqrt{1 - x^{2}}} d x}} = x \operatorname{asin}{\left(x \right)} - \color{j}{\int{\left(- \frac{1}{2 \sqrt{u}}\right)d u}} \\ [/tex]

Apply the constant multiple rule ∫cf(u)du=c∫f(u)du with c=-1/2 and f(u)=[tex] \frac{1}{ \sqrt{u} } [/tex]

[tex] \rm x \operatorname{asin}{\left(x \right)} - \color{h}{\int{\left(- \frac{1}{2 \sqrt{u}}\right)d u}} = x \operatorname{asin}{\left(x \right)} - \color{h}{\left(- \frac{\int{\frac{1}{\sqrt{u}} d u}}{2}\right)} \\ [/tex]

Apply the power rule

[tex] \rm\int u^{n}\, du = \frac{u^{n + 1}}{n + 1} \\ [/tex]

with n=−1/2

[tex] \rm x \operatorname{asin}{\left(x \right)} + \frac{\color{h}{\int{\frac{1}{\sqrt{u}} d u}}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{j}{\int{u^{- \frac{1}{2}} d u}}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{j}{\frac{u^{- \frac{1}{2} + 1}}{- \frac{1}{2} + 1}}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{j}{\left(2 u^{\frac{1}{2}}\right)}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{h}{\left(2 \sqrt{u}\right)}}{2} \\ [/tex]

[tex] \rm Recall \: that  \: u=1− {x}^{2} [/tex]

[tex] \rm x \operatorname{asin}{\left(x \right)} + \sqrt{\color{re}{u}} = x \operatorname{asin}{\left(x \right)} + \sqrt{\color{rd}{\left(1 - x^{2}\right)}} \\ [/tex]

Therefore,

[tex] \rm\int{\operatorname{asin}{\left(x \right)} d x} = x \operatorname{asin}{\left(x \right)} + \sqrt{1 - x^{2}}+C \\ [/tex]

Answer:

Step-by-step explanation:

The formula for calculating the volume of a right triangular prism is:

Let's use the formula to calculate the volume of the right triangular prism.