The daily rainfall experienced by Soaking City has been recorded on 9 randomly selected days throughout the year. This process has been repeated for every possible combination of 9 days in a year. The standard error of the mean has been calculated and is equal to 0.39 inches. If the rainfall was recorded on 36 (instead of 9) randomly selected days throughout the year, the standard error of the mean would be equal to:____.
a. 0.078 inches.
b. 0.248 inches.
c. 0.045 inches.
d. 3.429 inches.

Answers

Answer 1

If the rainfall was recorded on 36 (instead of 9) randomly selected days throughout the year, the standard error of the mean would be equal to 0.195 inches.

The standard error measures the variability or uncertainty in an estimate or statistic based on a sample. It is often denoted as SE or SE(θ), where θ represents a population parameter of interest.

Given that

the standard error of the mean, SE = 0.39 (when sample size,n = 9).

Let s be the standard deviation around the mean, then

Since SE = [tex]\dfrac{s}{\sqrt n}[/tex]

In this sample,

0.39 = [tex]\dfrac{s}{\sqrt9}[/tex]

s = 0.39 × 3

s = 1.17.

If the sample size is increased from 9 to 36,

SE = [tex]\dfrac{1.17}{\sqrt36}[/tex]

SE = [tex]\frac{1.17}{6}[/tex]

SE = 0.195 inches.

Thus, the standard error of the mean changes from 0.39 inches to 0.195 inches.

Learn more about Standard Error here:

https://brainly.com/question/13179711

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

The shape is approximately normal, with mean of 140 grams and standard deviation of 5.37 grams.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

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For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

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The shape is approximately normal, with mean of 140 grams and standard deviation of 5.37 grams.

Lincoln went to the grocery store and purchased cans of soup and
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sodium. Determine the number of cans of soup purchased and the
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Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answer:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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