The data set below shows the number of tickets sold by the Benson High School Bulldog Basketball team per home game in one
season.
75, 120, 255, 113, 225, 190, 108, 91, 134, 95, 163, 178, 171, 105, 100
Using a box plot, determine which of the following are true regarding the data set above.
1. The data is skewed left.
II. The data is skewed right.
III. The data is symmetric.
IV. The median is 120.
OA. I only
OB. I and IV
OC. II only
OD. III and IV
OE. II and IV

The integral does not have a closed-form solution, but it can be expressed using the exponential integral function,where u = 3x and c is the constant of integration.

To evaluate the integral ∫2e^(3xe^(3x)) dx, we can use the substitution method. Let u = 3x, then du = 3dx.

Although this integral does not have a closed-form solution in terms of elementary functions, it can be expressed using special functions such as the exponential integral.

Thus, the integral evaluates to (2/3)Ei(uˣ e^u) + c, where Ei(x) is the exponential integral function and c is the constant of integration.

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Answer:

if you want to know which polynomial is exactly divisible by (x+2) then where is the equation ?

The correct option: A) 60 . Thus, the coil span of a six-pole motor is 60 degrees, which means that the coil sides connected to the same commutator segment are 60 electrical degrees apart.

The coil span of a motor is the distance between the two coil sides that are connected to the same commutator segment.

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The series converges based on the limit comparison test.

To determine whether the given series converges or diverges, we can apply the limit comparison test. The limit comparison test states that if the limit of the ratio between the given series and a known convergent series is a finite positive value, then the given series converges. If the limit is zero or infinite, the given series diverges.

Let's consider the series ∑(9n^(3/2) - 10n - 34n) from n = 1 to infinity.

To apply the limit comparison test, we need to find a known convergent series to compare it with. A good choice is the p-series ∑(1/n^p), where p > 0.

Now, let's find the limit of the ratio of the two series:

lim(n→∞) [(9n^(3/2) - 10n - 34n) / (1/n^(3/2))]

= lim(n→∞) [(9n^(3/2) - 10n - 34n) * (n^(3/2))]

= lim(n→∞) [9n^3 - 10n^(5/2) - 34n^(5/2)]

To simplify the expression, divide all terms by n^(5/2):

= lim(n→∞) [(9n^3 / n^(5/2)) - (10n^(5/2) / n^(5/2)) - (34n^(5/2) / n^(5/2))]

= lim(n→∞) [9n^(3 - 5/2) - 10 - 34]

= lim(n→∞) [9n^(1/2) - 10 - 34]

= lim(n→∞) [9n^(1/2) - 44]

Since the limit is a finite value (-44), the ratio converges. Therefore, by the limit comparison test, the given series ∑(9n^(3/2) - 10n - 34n) converges.

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A parallelogram is a type of quadrilateral with opposite sides that are equal in length and parallel to each other. The perimeter of a parallelogram is the sum of the lengths of all its sides.

To simplify an expression for the perimeter of a parallelogram with sides of 2x - 5 and 5x + 7, we can use the formula: Perimeter = 2a + 2bWhere a and b represent the lengths of the adjacent sides of the parallelogram .So for our parallelogram with sides of 2x - 5 and 5x + 7, we have: a = 2x - 5b = 5x + 7Substituting these values into the formula for perimeter, we get :Perimeter = 2(2x - 5) + 2(5x + 7)Simplifying this expression, we get: Perimeter = 4x - 10 + 10x + 14Combine like terms: Perimeter = 14x + 4Finally, we can rewrite this expression in its simplest form by factoring out 2:Perimeter = 2(7x + 2)Therefore, the simplified expression for the perimeter of a parallelogram with sides of 2x - 5 and 5x + 7 is 2(7x + 2).

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Therefore, the actual SAT score for the 29th percentile, use the SAT score percentiles chart, locate the 29th percentile, and identify the corresponding SAT score.

The percentile score indicates the percentage of students who scored lower than the student in question. To find the actual SAT score, we need to use a conversion table that correlates percentile scores with actual SAT scores. For example, if the conversion table shows that a percentile score of 29 corresponds to an actual SAT score of 1150, then the student's actual SAT score is 1150.

To find the actual SAT score of a student who receives a percentile score of 29, we need to use a conversion table that correlates percentile scores with actual SAT scores. The percentile score indicates the percentage of students who scored lower than the student in question. For example, if the conversion table shows that a percentile score of 29 corresponds to an actual SAT score of 1150, then the student's actual SAT score is 1150.
To find the actual SAT score corresponding to the 29th percentile, we'll use the SAT score percentiles chart. The chart maps percentiles to specific SAT scores. Percentiles represent the percentage of test-takers who scored at or below a particular score.

Step 1: Locate an official SAT score percentiles chart. You can find this on the College Board website or other reputable sources.
Step 2: Find the 29th percentile on the chart. Look for the row with "29" in the percentile column.
Step 3: Identify the corresponding SAT score in the same row. This score represents the 29th percentile.

Therefore, the actual SAT score for the 29th percentile, use the SAT score percentiles chart, locate the 29th percentile, and identify the corresponding SAT score.

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The acceleration at t=10 seconds is approximately 0.2222 m/s^2.

Using Equation 23.9 of the book, we can calculate the acceleration at t=4 seconds and t=10 seconds as follows:

At t=4 seconds:

The first-order divided difference for velocity between t=2.5 and t=6.0 is:

f[t_2, t_1] = (V(t_2) - V(t_1))/(t_2 - t_1) = (18 - 15)/(6.0 - 2.5) = 1.7143 m/s^2

The first-order divided difference for velocity between t=1.0 and t=2.5 is:

f[t_1, t_0] = (V(t_1) - V(t_0))/(t_1 - t_0) = (15 - 10)/(2.5 - 1.0) = 10 m/s^2

The second-order divided difference for velocity between t=2.5, t=6.0, and t=1.0 is:

f[t_2, t_1, t_0] = (f[t_2, t_1] - f[t_1, t_0])/(t_2 - t_0) = (1.7143 - 10)/(6.0 - 1.0) = -1.6571 m/s^2

Therefore, the acceleration at t=4 seconds is approximately -1.6571 m/s^2.

At t=10 seconds:

The first-order divided difference for velocity between t=9.0 and t=12.0 is:

f[t_2, t_1] = (V(t_2) - V(t_1))/(t_2 - t_1) = (30 - 22)/(12.0 - 9.0) = 2.6667 m/s^2

The first-order divided difference for velocity between t=6.0 and t=9.0 is:

f[t_1, t_0] = (V(t_1) - V(t_0))/(t_1 - t_0) = (22 - 18)/(9.0 - 6.0) = 1.3333 m/s^2

The second-order divided difference for velocity between t=9.0, t=12.0, and t=6.0 is:

f[t_2, t_1, t_0] = (f[t_2, t_1] - f[t_1, t_0])/(t_2 - t_0) = (2.6667 - 1.3333)/(12.0 - 6.0) = 0.2222 m/s^2

Therefore, the acceleration at t=10 seconds is approximately 0.2222 m/s^2.

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The proportion of variation explained by the model is called the coefficient of determination, also denoted as R-squared.

It is a statistical measure that represents the percentage of the variance in the dependent variable that is explained by the independent variable(s) in the regression model. In other words, it measures the goodness of fit of the regression line to the observed data points. The coefficient of determination ranges from 0 to 1, where 0 indicates that the model does not explain any of the variance in the dependent variable, and 1 indicates that the model explains all of the variance in the dependent variable. The coefficient of determination is often used in regression analysis to evaluate the predictive power of the model and to compare the fit of different models.

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Kelly's rectangle has four square corners.

A rectangle is a quadrilateral with four sides and four angles. In a rectangle, opposite sides are equal in length, and all angles are right angles (90 degrees). A square is a special type of rectangle where all sides are equal in length

. Since a square is a type of rectangle, it also has four right angles, making all its corners square corners. Therefore, Kelly's rectangle, which is not specified as a square, may have different side lengths, but it will still have four right angles, resulting in four square corners.

These corners are formed by the intersection of the sides at right angles, creating a shape with sharp, 90-degree angles. So, regardless of the specific dimensions of Kelly's rectangle, it will always have four square corners.

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The probability of any one of the eight arrangements is 0.125, or 12.5% when rounded to three decimal places.

There are eight possible arrangements of boys and girls when a couple plans to have three children. They are:

BBB (all boys)

BBG (two boys, one girl)

BGB (one boy, two girls)

BGG (one boy, two girls)

GBB (two boys, one girl)

GBG (one boy, two girls)

GGB (two boys, one girl)

GGG (all girls)

The probability of any one of these arrangements can be calculated using the formula for probability:

Probability = (Number of favorable outcomes) / (Total number of possible outcomes)

In this case, since all eight arrangements are equally likely, the probability of any one of them is:

Probability = 1 / 8

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Answer : the solution to the initial-value problem is y(t) = 2e^(-3t) + 2e^(-27t), where t >= 0.

Initial-value problem using Laplace transforms, we'll follow these steps:

1. Take the Laplace transform of the differential equation.

2. Apply the initial conditions to obtain the transformed equation.

3. Solve the transformed equation for the Laplace transform of the unknown function.

4. Take the inverse Laplace transform to find the solution in the time domain.

Step 1: Taking the Laplace transform of the differential equation:

We have the differential equation: 2y'' + 36y' + 163y = 0

Taking the Laplace transform of each term using the properties of the Laplace transform, we get:

2[s^2Y(s) - sy(0) - y'(0)] + 36[sY(s) - y(0)] + 163Y(s) = 0

Step 2: Applying the initial conditions:

We are given y(0) = 2 and y'(0) = 0. Substituting these values into the transformed equation, we get:

2[s^2Y(s) - 2s] + 36[sY(s) - 2] + 163Y(s) = 0

Step 3: Solving the transformed equation for Y(s):

Rearranging the equation, we have:

(2s^2 + 36s + 163)Y(s) = 4s + 72

Dividing both sides by (2s^2 + 36s + 163), we obtain:

Y(s) = (4s + 72) / (2s^2 + 36s + 163)

Step 4: Taking the inverse Laplace transform:

To find the solution y(t) in the time domain, we need to compute the inverse Laplace transform of Y(s). However, the denominator of Y(s) is a quadratic expression, so we need to perform partial fraction decomposition.

The quadratic expression 2s^2 + 36s + 163 can be factored as (s + 3)(s + 27). Therefore, we can rewrite Y(s) as follows:

Y(s) = (4s + 72) / [(s + 3)(s + 27)]

Using partial fraction decomposition, we express Y(s) as:

Y(s) = A / (s + 3) + B / (s + 27)

To find A and B, we multiply both sides by the denominator and equate the numerators:

(4s + 72) = A(s + 27) + B(s + 3)

Expanding and collecting like terms:

4s + 72 = (A + B)s + 27A + 3B

By comparing coefficients, we get the following system of equations:

A + B = 4    ---(1)

27A + 3B = 72 ---(2)

Solving the system of equations, we find A = 2 and B = 2.

Now we can rewrite Y(s) as:

Y(s) = 2 / (s + 3) + 2 / (s + 27)

Taking the inverse Laplace transform of Y(s) using the table of Laplace transforms, we obtain the solution in the time domain:

y(t) = 2e^(-3t) + 2e^(-27t)

Therefore, the solution to the initial-value problem is y(t) = 2e^(-3t) + 2e^(-27t), where t >= 0.

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In the topical method, we focus on discussing different topics or subjects by considering various aspects and details related to them. This approach allows us to think about and communicate more effectively by addressing both general and specific points that might be relevant to the conversation.

The method of communication that involves reviewing possible things (both general and specific) that might be said. The correct answer is: e. Topical.

The method described in the question is a form of "topical" communication. This approach involves considering different topics or subjects that may need to be discussed and organizing thoughts and information around them. By reviewing possible things that may be said on each topic, one can prepare for a more effective and focused communication.

                             This method can be especially helpful in situations where there are multiple topics to cover or when discussing complex information that requires careful organization and planning.

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The intersection over the indexed family {A_i} is nonempty, as there are no elements that belong to all three sets:
⋂(A_i) = A_1 ∩ A_2 ∩ A_3 = ∅ (empty set)

An indexed family of sets that is pairwise disjoint but has a nonempty intersection can be represented as follows:

Consider an indexed family of sets {A_i} where i belongs to the index set I, with I = {1, 2, 3}. Define the sets A_i as:

A_1 = {1, 2}
A_2 = {2, 3}
A_3 = {1, 3}

The sets are pairwise disjoint since no two sets share any common elements:
A_1 ∩ A_2 = {2} (not empty)
A_1 ∩ A_3 = {1} (not empty)
A_2 ∩ A_3 = {3} (not empty)

However, the intersection over the indexed family {A_i} is nonempty, as there are no elements that belong to all three sets:

⋂(A_i) = A_1 ∩ A_2 ∩ A_3 = ∅ (empty set)

In this example, the indexed family of sets is pairwise disjoint, but the intersection over the family is nonempty.

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By applying the Intermediate Value Theorem for continuous functions, we can conclude that if the integral of a continuous function f over the interval [a, b] is equal to zero, then there exists at least one point c in the interval [a, b] where f(c) is also equal to zero.

To prove that there exists a point c in the interval [a, b] where f(c) is equal to zero, we will make use of the Intermediate Value Theorem.

The Intermediate Value Theorem states that if a function f is continuous on a closed interval [a, b] and f(a) and f(b) have opposite signs (i.e., f(a) < 0 and f(b) > 0, or f(a) > 0 and f(b) < 0), then there exists at least one point c in the interval (a, b) where f(c) is equal to zero.

In our case, we are given that the integral of f over the interval [a, b] is equal to zero, i.e., ∫[a,b] f(x) dx = 0. Since the integral represents the signed area under the curve of f(x), the fact that the integral is zero indicates that the positive and negative areas cancel each other out.

Now, let's assume, for the sake of contradiction, that there does not exist any point c in the interval [a, b] where f(c) is equal to zero. This would mean that f(x) maintains a constant sign (either positive or negative) throughout the interval [a, b].

If f(x) is always positive or always negative, then the integral of f over [a, b] cannot be zero, as it would represent a nonzero positive or negative area under the curve. This contradicts the given condition that the integral is equal to zero.

Therefore, by contradiction, we can conclude that there must exist at least one point c in the interval [a, b] where f(c) is equal to zero. This completes the proof.

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To find the length and width of a rectangle with an area of 64m² that gives the minimum perimeter, we can use calculus. The length and width should be 8m and 8m, respectively.

Let's assume the length of the rectangle is L and the width is W. The perimeter of the rectangle is given by P = 2L + 2W. We are given that the area of the rectangle is 64m², so we have the equation LW = 64.

To find the minimum perimeter, we can use calculus. We need to minimize P with respect to L while keeping the area constant. We can express L in terms of W using the area equation: L = 64/W. Substituting this into the perimeter equation, we have P = 2(64/W) + 2W.

To find the minimum value of P, we can take the derivative of P with respect to W and set it equal to zero. The derivative of P is dP/dW = -128/W^2 + 2. Solving dP/dW = 0, we find W = 8. Substituting this value back into the area equation, we get L = 8.

Therefore, the length and width of the rectangle that give the minimum perimeter with an area of 64m² are 8m and 8m, respectively.

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The weighted moving average formula with weights of 0.3 and 0.7 can be calculated using the AVERAGE and SUMPRODUCT functions in Excel. This formula can be used to calculate forecasted values for a range of years.

To use a 2-year weighted moving average to calculate forecasts for the years 1992-2002 with the weight of 0.7 assigned to the most recent year data, we can use the SUMPRODUCT function.
First, we need to create a table that includes the years 1990-2002 and their corresponding data points. Then, we can use the following formula to calculate the weighted moving average:
=(0.3*AVERAGE(B2:B3))+(0.7*B3)
This formula calculates the weighted moving average for each year by taking 30% of the average of the data for the previous two years (B2:B3) and 70% of the data for the most recent year (B3). We can then drag the formula down to calculate the forecasted values for the remaining years.
The SUMPRODUCT function can be used to simplify this calculation. The formula for the weighted moving average using SUMPRODUCT would be:
=SUMPRODUCT(B3:B4,{0.3,0.7})
This formula multiplies the data for the previous two years (B3:B4) by their respective weights (0.3 and 0.7) and then sums the products to calculate the weighted moving average for the most recent year. We can then drag the formula down to calculate the forecasted values for the remaining years.
In summary, the weighted moving average formula with weights of 0.3 and 0.7 can be calculated using the AVERAGE and SUMPRODUCT functions in Excel. This formula can be used to calculate forecasted values for a range of years.

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Answer:

21.5 cm

Step-by-step explanation:

a² + b² = c²

20² + 8² = c²

400 + 64 = c²

464 = c²

c = √464

c = 21.5

Answer: 21.5 cm

Answer:

Step-by-step explanation:

I think it would be 500

Answer:

The value of the car after 5 years is $12271.05

The present value of the car, PV = $16500

The rate of depreciation, r = 5.75%

r = 5.75/100

r = 0.0575

Step-by-step explanation:

The answer is option 13. 4 square centimeters.

Let's first find the length of the sides of each triangle. Since the perimeter of each triangle is 10 centimeters, and each triangle has 3 sides of equal length, the length of each side of the triangles is given by;

Side length = Perimeter ÷ Number of sides

= 10 ÷ 3= 3.33 (rounded to 2 decimal places)

The base of each triangle measures 2 centimeters, and the length of the side is 3.33 centimeters.

We can use the Pythagorean theorem to find the height of the triangles. Using Pythagorean theorem,

a² + b² = c²where a = 1, b = h and c = 3.33

From the formula above, we can find that:

h² = c² - a²

= 3.33² - 1²

≈ 10.77h

≈ √10.77

≈ 3.28

The area of each triangle is given by the formula;

Area = 1/2 x base x height

= 1/2 x 2 x 3.28

= 3.28 square centimeters (rounded to 2 decimal places)

Since there are 4 triangles, the total area of the plastic triangles on the spinner is approximately:

Total area = 4 x 3.28

= 13.12 square centimeters (rounded to 2 decimal places)

Therefore, the answer is option 13. 4 square centimeters.

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A) is correct answer. The inequality that represents the range of possible pounds purchased is 0.41 < (3.40/x) < 0.50.

The inequality that represents the range of possible pounds purchased is as follows:

0.41 < (3.40/x) < 0.50.

Let's discuss the given problem step-by-step.

Sarah pays $3.40 for x pounds of bananas.

The cost of one pound of bananas is greater than $0.41 and less than $0.50.

Therefore, the cost of x pounds of bananas can be written as:

3.40 < x(0.50) and 3.40 > x(0.41)

⇒ 0.41x < 3.40 < 0.50x

⇒ 0.41 < (3.40/x) < 0.50

Hence, the inequality that represents the range of possible pounds purchased is 0.41 < (3.40/x) < 0.50.

The answer is option A.

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The  rate of change of Wayne's hours of sleep with respect to each day is  5  hours per day.

The rate of change of Wayne's hours of sleep with respect to each day is calculated as follows;

Mathematically, the formula is given as;

rate of change of sleep = change in sleep / change in time of sleep

The change in the sleep pattern = 30 - 15 = 15 hours

The change in the time of sleep = 6 - 3 = 3 days

The  rate of change of Wayne's hours of sleep with respect to each day is calculated as

rate of change of sleep = ( 15 hours ) / ( 3 days )

rate of change of sleep = 5  hours per day

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The simplified expression √39(√6 + 7) is equal to √(39 * 6) + 7√(39 .

To simplify the expression √39(√6 + 7), we can follow these steps:

Step 1: Distribute the square-root (√) to both terms inside the parentheses:

  √39 * √6 + √39 * 7

Step 2: Simplify the square roots separately:

  √(39 * 6) + √(39 * 7)

Step 3: Calculate the products under the square roots:

  √234 + √273

Step 4: Simplify the square roots further:

  √(9 * 26) + √(9 * 3 * 3 * 3)

Step 5: Split the square root of a product into the product of the square roots:

  √9 * √26 + √9 * √(3 * 3 * 3)

Step 6: Simplify the square roots of perfect squares:

  3√26 + 3√(3 * 3 * 3)

Step 7: Multiply the numbers outside the square roots:

  3√26 + 9√3

Note that the simplified form is obtained by simplifying the square roots as much as possible and combining like terms.

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Answer:

Step-by-step explanation:

The correct sentence that corrects Nico's colon mistake is:

O Prepare for a hurricane by having the following supplies on hand: water, batteries, and food.

In this sentence, the colon is used correctly to introduce a list of supplies that should be prepared for a hurricane. The first letter of "water" is in lowercase because it is not a proper noun.

Answer:

Prepare for a hurricane by having the following supplies on hand: water, batteries, and food.

Step-by-step explanation:

You use the : whenever you're listing things such as supplies.

The number and the kind of roots of the equation, f(x) = x³ - x² - x + 1, is: D. 3 complex roots.

To determine the number and kind of roots of the equation f(x) = x³ - x² - x + 1, we can analyze the discriminant of the equation.

The discriminant, denoted as Δ, is given by:

Δ = b² - 4ac

In this case, the equation is in the form ax³ + bx² + cx + d = 0, where a = 1, b = -1, c = -1, and d = 1.

Calculating the discriminant:

Δ = (-1)² - 4(1)(-1)(-1) = 1 - 4(1)(1) = 1 - 4 = -3

The discriminant is negative (Δ < 0). This means that there are no real roots for the equation f(x) = x³ - x² - x + 1.

Therefore, the answer is:

D. 3 complex roots

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Panchito should mix 30 ml of cranberry juice with 120 ml of orange juice to make 150 ml of a 22% cranberry-orange juice blend.

To determine the amounts of cranberry juice and orange juice that Panchito should mix, we can set up a system of equations based on the given information. Let's assume Panchito mixes x ml of cranberry juice and y ml of orange juice.

The total volume of the mixture is 150 ml: x + y = 150.

The percentage of cranberry juice in the mixture is 22%: (0.05x) / 150 = 0.22.

Simplifying the second equation, we get:

0.05x = 0.22 * 150

0.05x = 33

x = 33 / 0.05

x = 660 ml

Substituting this value back into the first equation, we can solve for y:

660 + y = 150

y = 150 - 660

y = -510 ml

Since the solution for y is negative, it is not feasible. This indicates that there is no way to create a 22% cranberry-orange juice blend using a 5% cranberry juice and a 90% orange juice.

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To find the area enclosed by the polar curve r = 12sinθ, we can use the formula for the area of a polar curve: A = 1/2 * ∫(r^2)dθ. For r = 12sinθ, the integral limits are from 0 to π because the curve covers a full period of the sine function.

Let's evaluate the integral using angle identity:

A = 1/2 * ∫(r^2)dθ
A = 1/2 * ∫((12sinθ)^2)dθ, with θ from 0 to π

A = 1/2 * ∫(144sin^2θ)dθ

Now, we can use the double angle identity sin^2θ = (1 - cos(2θ))/2:

A = 1/2 * ∫(144(1 - cos(2θ))/2)dθ

A = 72 * ∫(1 - cos(2θ))dθ, with θ from 0 to π

Now, we can integrate:

A = 72 * [θ - 1/2 * sin(2θ)] from 0 to π

A = 72 * [π - 0 - (1/2 * sin(2π) - 1/2 * sin(0))]

A = 72 * π

The exact area enclosed by the polar curve r = 12sinθ is 72π square units.

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The subtended arc for the second circle is 31.2 cm long.

Given a circle with a radius of 6 cm and a subtended arc of 15.6 cm, we can find the angle's measure in radians using the formula: angle (in radians) = arc length/radius. Plugging in the values, we get angle = 15.6 cm / 6 cm = 2.6 radians.
For the second circle with a radius of 12 cm, we can find the subtended arc length by rearranging the formula: arc length = angle (in radians) * radius. Using the angle of 2.6 radians, we get arc length = 2.6 radians * 12 cm = 31.2 cm. Therefore, the subtended arc for the second circle is 31.2 cm long.

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Let us assume that m is not prime. This means that there exists a prime factor p of m such that p ≤ √m. Since a is relatively prime to m, it must also be relatively prime to p.

Now, let's consider the order of a modulo p. We know that ordpa divides p-1, since p is prime. However, since a and p are relatively prime, we also know that ordpa cannot be equal to p-1, since this would imply that a is a primitive root modulo p, which is impossible since p is a prime factor of m and therefore does not have any primitive roots modulo p.
So, ordpa must divide p-1, but it cannot be equal to p-1. Therefore, ordpa must be strictly less than m-1 (since m has p as a factor, which means that m-1 has p-1 as a factor). However, we know that ordma = m-1. This means that ordpa cannot be equal to ordma.
This is a contradiction, since we assumed that ordma = m-1 and that ordpa divides m-1. Therefore, our initial assumption that m is not prime must be false. Therefore, m must be prime.
In conclusion, if m is a positive integer and a is an integer relatively prime to m such that ordma = m-1, then m must be prime.

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Therefore, (a) ∫58cos(0.1635t - 0.642)dt from 0 to 10 gives approximately 822.6 cars, (b) ′′(5) = -65cos(0.281) which is approximately -62.4 cars per hour per hour, (c) Approximately 559 cars in the garage at t = 10.

(a) To find the number of cars entering the parking garage over the interval 0 ≤ t ≤ 10, we need to integrate the rate of cars entering the garage with respect to time. ∫58cos(0.1635t - 0.642)dt from 0 to 10 gives approximately 822.6 cars.
(b) To find ′′(5), we need to differentiate the rate of cars leaving the garage with respect to time twice. ′′(t) = -65cos(0.281) and ′′(5) = -65cos(0.281) which is approximately -62.4 cars per hour per hour. This value represents the rate of change of the rate of cars leaving the garage at t = 5.
(c) To find the number of cars in the parking garage at time t = 10, we need to subtract the total number of cars leaving the garage from the total number of cars entering the garage from t = 0 to t = 10. This gives approximately 559 cars in the garage at t = 10.


Therefore, (a) ∫58cos(0.1635t - 0.642)dt from 0 to 10 gives approximately 822.6 cars, (b) ′′(5) = -65cos(0.281) which is approximately -62.4 cars per hour per hour, (c) Approximately 559 cars in the garage at t = 10.

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The slope of the median-median line for this dataset is 0.8.

To calculate the slope of the median-median line for this dataset, we need to first calculate the medians of both the x and y variables.

The median of the x variable is (15+16+18+19+20+22)/6 = 17.
The median of the y variable is (15+16+18+19+20+22)/6 = 17.

Next, we need to calculate the slopes of all the lines connecting the pairs of medians (x1,y1) and (x2,y2).
(x1,y1) = (15,16), (x2,y2) = (22,20), slope = (20-16)/(22-15) = 0.8
(x1,y1) = (15,16), (x2,y2) = (22,19), slope = (19-16)/(22-15) = 0.75
(x1,y1) = (15,16), (x2,y2) = (22,22), slope = (22-16)/(22-15) = 1.2
(x1,y1) = (15,18), (x2,y2) = (22,20), slope = (20-18)/(22-15) = 0.4
(x1,y1) = (15,18), (x2,y2) = (22,19), slope = (19-18)/(22-15) = 0.1667
(x1,y1) = (15,18), (x2,y2) = (22,22), slope = (22-18)/(22-15) = 0.6667

We then calculate the median of all these slopes to get the slope of the median-median line.

Median slope = (0.4, 0.6667, 0.75, 0.8, 1.2) = 0.8
Therefore, the slope of the median-median line for this dataset is 0.8.

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