the elctric field 2.0 cm from a small object points away from the object with a strength of 270,000 nC. What is the objects charge?
Please show work and Units

Answers

Answer 1

The object's charge is 1.35 μC. The electric field strength is calculated to be 3.375 x 10^11 N/C using the formula for electric field strength.

To solve for the object's charge, we can use the formula for electric field strength:
Electric field strength = charge / distance^2
First, we need to convert the distance from centimeters to meters:
2.0 cm = 0.02 m
Plugging in the given values:
270,000 nC = 270,000 x 10^-9 C (converting from nanocoulombs to coulombs)
Electric field strength = 270,000 x 10^-9 C / (0.02 m)^2
Electric field strength = 3.375 x 10^11 N/C
Now we can rearrange the formula to solve for charge:
charge = electric field strength x distance^2
charge = (3.375 x 10^11 N/C) x (0.02 m)^2
charge = 1.35 x 10^-6 C
Therefore, the object's charge is 1.35 microcoulombs (μC).
Answer: The object's charge is 1.35 μC. The electric field strength is calculated to be 3.375 x 10^11 N/C using the formula for electric field strength. To solve for the object's charge, we rearranged the formula and substituted in the given values. The units for charge are coulombs (C), which we converted from the given value in nanocoulombs. The distance was converted from centimeters to meters to match the units of the formula.

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Answer:

12 neutrons

Explanation:

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b) Include this table on your slide:
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urur

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will mark as brainliest !! plz answer it
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Answer:

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pls mark me as brainliest thanks

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Answer:

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Explanation:

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Explanation:

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Answer:

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Answer:

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a

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Answer:

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Answers

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False

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The car's overall displacement if, A car drives 40 km due east and then 50 km due west is 10 km in the west.

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A car drives 40 km due east and then 50 km due west,

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