The electric flux through each of the six sides of a rectangular box are as follows:
F1 = +216.0 N · m2/C
F2 = +243.0 N · m2/C
F3 = -346.0 N · m2/C
F4 = +175.0 N · m2/C
F5 = -100 N · m2/C
F6 = +450.0 N · m2/C
How much charge is in this box?________C

Answers

Answer 1

The total charge on rectangular box is  5579.2 ×  10 ⁻¹³ C.

What are electric flux and its measure?

Although an electric field cannot flow by itself, electric flux in electromagnetism is a measure of the electric field passing through a certain surface. Any place in space where there is an electric charge will be affected by the electric field E. The gradient of the potential is the electric field. The distribution of the electric field or the velocity at which the electric field moves through a specific area can both be measured as electric flux. The Greek letter e is used to represent electric flow. Electric flux is measured in SI units as or Nm 2 C – 1.

Total charge = Φ.ε₀

Total flux = 634 N · m2/C .

Total charge = 634 N · m2/C .  8.8 × 10 ⁻¹³

Total charge = 5579.2 ×  10 ⁻¹³ C

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Related Questions

Image intensifiers used in night-vision devices create a bright image from dim light by letting the light first fall on a photocathode. Electrons emitted by the photoelectric effect are accelerated and then strike a phosphorescent screen, causing it to glow more brightly than the original scene. Recent devices are sensitive to wavelengths as long as 900 , in the infrared: Part A If the threshold wavelength is 900 , what is the work function of the photocathode? Part B If light of wavelength 600 strikes such a photocathode, what will be the maximum kinetic energy, in , of the emitted electrons?

Answers

The work function of the photocathode is 1.38ev.,  The value of maximum kinetic energy is 1.174 ev.

Work function = hc/λ

Where h = plank's constant

c = speed of light

λ = wavelength of light

⇒ (6.63 × 10⁻³⁴ × 3 × 10⁸) / 900 × 10⁻⁹

⇒  1.38ev                                                     ......(1)

∴ The work function of the photocathode is 1.38ev.

Max Kinetic energy = hν - hν₀

From (1)

⇒ 1.38 - 6.63 × 10⁻³⁴ × 3 × 10⁸ / 600 × 10⁻⁹

⇒  1.38    - 0.33 × 10 ⁻¹⁹

⇒  1.38 - 0.206ev

⇒ 1.174 ev

The value of maximum kinetic energy is 1.174 ev.

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shows the interference pattern obtained in a double-slit experiment with light of wavelength 2λ.
Enter the letter(s) Indicating the fringe(s) In alphabetical order.

Answers

The interference pattern obtained in a double-slit experiment with light of wavelength 2λ with an intensity ratio between the bright and dark fringes.

What happens to the double-slit pattern as the wavelength is increased?

Due to the dependence of the spacing between the slits on L, the spacings between various fringes get smaller as the distance between them gets bigger. The space between various fringes grows as the light's wavelength rises because this is a wavelength-dependent property.

What kind of pattern does a double-slit create?

The double-slit experiment shows that light is a wave and creates an interference pattern. The interference pattern is made up of alternate black and light lines; the light lines are known as fringes.

What is the interference pattern?

An interface establishes the communication barrier between two entities, in this case two pieces of software, as well as defining the signature actions of an entity.

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By definition, which of the following can be broken down into simpler substances? a: liquid b: solid c: compound d: atom ion

Answers

Correct option is C, Compound can be broken down into simpler substances.

Additionally, compounds can be divided into more basic components. While some elements only have one letter as their symbol, some have two. A formula is what we create when we represent a compound with symbols. For instance, table salt is a substance consisting of one sodium (Na) and one chlorine (Cl) atom (Cl).

Simpler substances cannot be created from elements. When a compound is broken down, two or more simpler compounds result. Elements are pure substances, 113 of which are recognized. Millions of chemicals exist. Each water molecule is made up chemically of two hydrogen and one oxygen atoms. Only chemical processes can break down water into its constituent parts. Features that make it possible to identify one type of substance from another

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a 2.4×105−kg airplane is cruising at 900 km/h.

Answers

A 2.4×105−kg airplane is cruising at 900 km/h will be 6.48 × 10^10J.

What is airplane?
An airplane is a powered, fixed-wing aircraft that is propelled forward by thrust from an engine. Airplanes come in a variety of sizes, shapes, and wing configurations. The wings, engines, and tail are the three main components of an airplane. The wings provide lift, the engines provide thrust, and the tail provides control and stability. When an airplane is in flight, the wings generate lift, the engines generate thrust, and the tail keeps the airplane balanced and flying straight. Airplanes are used for a variety of purposes, including passenger and cargo transportation, military operations, and recreational activities.

The kinetic energy of the airplane is:

KE = 1/2 mv2 = 1/2 (2.4 × 10^5)(900)^2

= 6.48 × 10^10 J

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energy is ____ when an electron is added to H+ ion and ends up in n=3 shell

Answers

Ionisation energy is the correct answer .

What is Energy ?

Energy, in physics the ability to do work. It can exist in electrical, kinetic, thermal, electrical, chemical, nuclear, or various other forms. There is also heat and work. H. After transmission, energy is always referred to according to its nature. Thus, the heat transferred can become thermal energy, while the work done can appear as mechanical energy. All forms of energy are associated with movement. For example, any object has kinetic energy when it is in motion. A taut device such as a bow or spring can create motion even when stationary. Because of its composition, it contains potential energy. Similarly, nuclear energy is potential energy as it results from the composition of subatomic particles within the nucleus .

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How much heat does the air exchange with its surroundings during the process abc? Express your answer using two significant figures.

Answers

The amount of heat does the air exchange with its surroundings during the process abc is 4kJ.

This query is based on the first law of thermodynamics, which is formally defined as, Q = ΔU + W where, Q and ΔU is the changes in internal energy of the system and W is the work performed by the system. There is no change in the gas's internal energy since the temperature at states a and c remains constant. ΔU thus equals 0. Consequently, the heat generated during the process ABC, is Q = ΔU + Wabc

Q = 0 + Wab + Wbc

Q = 0 + 0+ 1 x 10^5Pa x (0.06-0.02) m^3

Here Wab = 0 as  volume remains constant along ab

Q = 4 x 10^3J = 4kJ

Because Q is positive, air will heat up during the process.

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complete question: A volume of air (assumed to be an ideal gas) is first cooled without changing its volume and then expanded without changing its pressure, as shown by the path abc. How much heat does the air exchange with its surroundings during the process abc? Does the air absorb heat or release heat during this process? Explain.

Water flowing out of a 16.0 mm-diameter faucet fills a 1.00 L bottle in 15.0 s. At what distance below the faucet has the water stream narrowed to 10 mm diameter?

Answers

The  3.12 cm distance below the faucet has the water stream narrowed to 10 mm diameter.

What is distance ?

Distance is the overall distance that an object actually travels along its course. The displacement of an object between two points is the smallest straight-line distance between those two points, measured from one position to the other. The metric system is used to measure both displacement and distance (m).

What is diameter ?

The centre of a figure or body is defined as a straight line. specifically: the length of a diameter, which is a line segment passing through the centre of a circle and ending on the circumference.

1 Liter converts to 1 X 10-3 m3, therefore the volume flow rate is

1 X 10-3/15 = 6.667 X 10-5 m3/s

That flow rate = Av so we can find v at the two different diameters

At 16 mm diameter, we get 6.667 X 10-5 = (π)(8 X 10-3)2(v)

v = .3317 m/s

At 10 mm diameter, we get 6.667 X 10-5 = (π)(5 X 10-3)2(v)

v = .8493 m/s

Finally apply vf2 = vo2 + 2ad

(.8493)2 = (.3317)2 + 2(9.8)(d)

d = .0312 m  which is 3.12 cm

Therefore,  3.12 cm distance below the faucet has the water stream narrowed to 10 mm diameter.

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Look at the screenshot and choose the correct statement from the options given.

Answers

Answer:

The force between two magnetic poles will increase as their separation is increased.

If the current carried by a conductor is doubled, how are each of the following affected?
(a) The charge carrier density.
(b) The current density.
(c) The electron drift velocity.
(d) The average time interval between collisions.

Answers

According to the given statement the current carried by a conductor is doubled then the charge carrier density are remains constant.

Assume that I is the original current conduction. I' = 21

(a) charge density on doubling current The density of charge carriers is unaffected by the passage of current. It is dependent on the material's volume and atomic mass. carrier for electron density

As a result, the carrier's charge density doesn't change.

Current density (J)

J = Current / Area = I / A

the present J ∝ I. As a result, when the current doubles, so does the density.

velocity of electron drift.

Vd = I / nea

because Vd ∝ I. Therefore, the election drift velocity twice with a doubling of current.

(d) average time between collisions (1) The value of I is independent of the wire's current flow. Therefore, it has no impact on the current's doubling. Therefore, b/w collision does not change.

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a canonball is shot 80 m/s horizontally from the top of a 15 meter tower​

Answers

Answer:

ok what do you want answered

7) A 2 kg cart rolls down a frictionless ramp. It starts with 58.8 J of energy at the top of the ramp. How fast would the cart be moving when it is halfway (in height) down?​

Answers

Answer:

The problem is asking one to assume that the potential energy at the top of the ramp is 58.8 J and the potential bottom is zero:

then 1/2 m v^2 = 29.9 J or 1/2 the energy - one cannot solve for v without knowing a value for KE

v^2 = 58.8 / 2 = 29.9

v = 5.47 m/s

(if the cart had any KE at the top of  the ramp then one cannot solve the problem because the speed of the cart is not defined)

How fastmust a proton move so that its kinetic energy is 80% of its total energy? A) 0.92c B) 0.98c C) 0.87c D) 0.80c E) 0.020c

Answers

The proton's speed will be 2.68 x 108 m/s if its overall kinetic energy is 80%.

What is kinetic energy?

The energy of motion, or kinetic energy, can be seen in the movement of an item or subatomic particle. Kinetic energy is present in every moving object and particle. Kinetic energy is present when something moves, such as a person walking, a baseball soaring through the air, a piece of food dropping from a table, or a charged particle in an electric field.

Kinetic energy of proton ,

K.E = ¹/₂mc²

c is the speed of light

m is the mass

Given, K.E2 is 80% of K.E1 i.e. 0.80K.E1

If K.E₁/c₁² = K.E₂/c₂²

c₂ = √(0.8K.E₁c₁²/K.E₁)

c₂ = √(0.8c₁²)

c₂ = c₁√(0.8)

c₂ = 3 x 10⁸ m/s x √(0.8)

c₂ = 2.68 x 10⁸ m/s

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A car drives to 215 km East and then 45 km north what is the magnitude of the car displacement? round your answer to the nearest whole number?

Answers

The answer is.....

= 220

true/false. the earth and the moon are attracted to each other by gravitational force. the more massive earth attracts the less massive moon with a force that is (greater than, less than, the same as) the force with which the moon attracts the earth.

Answers

Yes, the earth and the moon are attracted to each other by gravitational force.

The greater an object's mass, the more gravitational force it exerts. So, Earth has a greater gravitational pull than the moon simply because the Earth is more massive.

Let m and M be the mass of moon and earth respectively which are separated by a distance r

Force of attraction that earth exert on moon,

                             Fe = GMm/ r^2

Force of attraction that moon exert on earth, Fm = GmM / r^2

Thus earth attracts the moon with same force by which moon attracts the  earth.

Also the gravitational force is an internal force of attraction between the two bodies, thus they have to be equal.

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A certain circuit element is known to be a resistance, an inductance, or a capacitance.
Determine the type and value (in ohms, henrys, or farads) of the elemnt if the voltage and
current for the element are given by
a v(t) = 100 sin (200t +30°)V, i(t) = cos(200t +30°) A
b v(t) = 500 cos(100t + 50°)V, i(t) 2 cos(100% +50°)A
cv(t) = 100 cos(400t +30°)V, i(t) sin (100t+30°) A

Answers

To determine the type and value of the circuit element, we can use the relationship between voltage, current, and impedance for each type of element.

A. v(t) = 100 sin (200t +30°)V, i(t) = cos(200t +30°) A

The voltage and current are in phase, meaning that the circuit element is a resistance.

To determine the value of the resistance, we can use Ohm's law (V=IR).

100 = R * cos(200t + 30°)

R = 100/cos(200t + 30°) ohms

B. v(t) = 500 cos(100t + 50°)V, i(t) 2 cos(100% +50°)A

The voltage and current are 90 degrees out of phase, meaning that the circuit element is an inductance.

To determine the value of the inductance, we can use the relationship between voltage, current, and inductance (V = L di/dt).

500 = L * 2 * (-100sin(100t + 50°))

L = 250/100 = 2.5 henries

C. v(t) = 100 cos(400t +30°)V, i(t) = sin (400t+30°) A

The voltage and current are 90 degrees out of phase, meaning that the circuit element is a capacitance.

To determine the value of the capacitance, we can use the relationship between voltage, current, and capacitance (V = 1/C * ∫i(t) dt).

100 = 1/C * (-cos(400t+30°))

C = 100/-cos(400t+30°) farads

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If two city buses are traveling at 24 miles per hour and the buses are the same model and year but one bus has 30 passengers while the other bus has 12 passengers. Which is the best prediction?

Answers

If two city buses are traveling at 24 miles per hour and the buses are the same model and year but one bus has 30 passengers while the other bus has 12 passengers.  the best prediction is that the bus with 12 Passengers will cover those 24 miles with faster speed than the other.

What is Speed?

Speed means, the rate by which an object's location changes in any direction. The distance traveled in relation to the time it took to travel that distance is how speed is defined.

Miles:

mile, any of several distance measurements, such as the statute mile (5,280 ft) (1.609 km). It generally derived from the mille passus, or "thousand paces," of the Romans, which was equivalent to 5,000 Roman feet.

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Answer:

1. What does an object's kinetic energy depend on?

its mass and speed

2. Two city buses are traveling at 24 miles per hour. The buses are the same model and year. One bus has 30 passengers. The other bus has 12 passengers. Which is the best prediction?

The bus with 12 passengers will have less kinetic energy.

3. A softball player hits a ball at 78 miles per hour. Then she hits a ball at 80 miles per hour. Which is the best prediction?

The ball hit at 80 miles per hour will have more kinetic energy.

4. A hawk is chasing a sparrow. At the beginning of the chase, the hawk's kinetic energy is 5.1 Joules. At the end of the chase, the hawk doubles its speed. What is the best prediction for its kinetic energy at the end of the chase?

20.4 J

5. A student rolls two marbles down an inclined plane. One marble has a mass of 4.8 grams. The student calculates its kinetic energy to be 0.0035 Joules when it reaches the end of the plane. The second marble has a mass of 2.4 grams. What is the best prediction for its kinetic energy at the end of the plane?

0.00175 J

One of the earliest practical uses of astronomy was the timing of crop planting by
Choose one:
A. lunar eclipses.
B. the appearance of comets.
C. solar eclipses.
D. the appearance of specific planets.
E. the appearance of specific constellations.

Answers

Option- E. the appearance of specific constellations is the correct answer.

What is astronomy ?

Astronomy, a science that includes the study of all extraterrestrial objects and phenomena. Until the invention of the telescope in the 17th century and the discovery of the laws of motion and gravity, astronomy was primarily concerned with finding and predicting the positions of the sun, moon, and planets. Initially for calendar and astrological purposes, later for navigation and astronomy. Scientific use Interest. The catalog of celestial bodies currently being studied is much more extensive, including in order of increasing distance, the solar system, the stars that make up the Milky Way, and other more distant galaxies. With the advent of scientific space probes, the Earth has also been studied as one of the planets, but more detailed study remains the realm of Earth science.

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Help me with this q please

Answers

i think it’s y but not sure

David is driving a steady 30 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady 2.0 m/s2 at the instant when David passes.
a. How far does Tina drive before passing David?
b. What is her speed as she passes him?

Answers

With an acceleration of 2 m/s2, Tina must go distance of 900 metres before passing David.

David's speed is 30 m/s.

Tina's vehicle accelerates at a = 2 m/s2.

Allow Tina's time to pass David is t.

The distance between Tina when she was at rest and when Tina passes her will be equal to the distance David travelled, based on the information provided.

David has travelled the same distance as Tina has.

David has gone a distance of s = v x t s = 30t.

Utilizing the second motion equation

[tex]s=ut+\frac{1}{2} at^2[/tex]

Substitute,

[tex]30t=(0)t+\frac{1}{2} (2)t^2[/tex]

[tex]t^2 = 30t\\t=30[/tex]

As a result, Tina needs 30 seconds to pass David.

Tina's distance travelled equals David's distance travelled,

hence

s = v x t

s = 30 x 30

s = 900m.

Therefore, Tina travelled 900 metres before passing David at a 2 m/s2 acceleration rate.

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With an acceleration of 2 m/s², Tina must go a distance of 900 meters before passing David.

David's speed is 30 m/s.

Tina's vehicle accelerates at a = 2 m/s².

Allow Tina's time to pass David is t.

The distance between Tina when she was at rest and when Tina passes her will be equal to the distance David traveled, based on the information provided.

David has traveled the same distance as Tina has.

David has gone a distance of s = v x t s = 30t.

Utilizing the second motion equation

[tex]S=ut+\frac{1}{2}at^{2}[/tex]

Substitute,

[tex]30t=(0)t+\frac{1}{2}(2)t^{2}[/tex]

[tex]t^{2} =30t\\t=30[/tex]

As a result, Tina needs 30 seconds to pass David.

Tina's distance traveled equals David's distance traveled,

Hence

s = v x t

s = 30 x 3

s = 900m.

Therefore, Tina traveled 900 meters before passing David at a 2 m/s² acceleration rate.

The distance between two points in bodily space is the length of an instant line among them, which is the shortest possible route. this is the usual meaning of distance in classical physics, which includes Newtonian mechanics.

Distance is a numerical or now-and-again qualitative dimension of ways some distance apart gadgets or points are. In physics or regular utilization, the distance may additionally refer to a physical duration or an estimation based totally on other standards (e.g. " counties over"). because spatial cognition is a rich supply of conceptual metaphors in human concepts, the time period is also regularly used metaphorically to intend a measurement of the amount of distinction between comparable items (along with statistical distance among opportunity distributions or edit distance among strings of text) or a degree of separation (as exemplified with the aid of distance between human beings in a social network). maximum such notions of distance, both bodily and metaphorical, are formalized in mathematics using the notion of a metric area.

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determine the force exerted by the bicep muscle, assuming that the hand is holding a ball with a mass of 5.00kg. Assume that the mass of the forearm is 8.50kg with the center of the mass located 20.0cm away from the elbow joint. Assume also that the center of the mass of the ball in the hand is 30.0 cm away from the elbow joint.

Answers

In the event when the hand is carrying a ball with a mass of 5.00 kg, the bicep muscle will exert  132.3 N of force. Let's say the forearm weighs 8.50 kg, with the mass's centre 20.0 cm from the elbow.

M = the ball's mass

mass of the forearm is mf.

rf = distance of centre of mass of forearm from elbow, which is 20 cm (0.20 m) away from elbow, and rb = distance of ball from elbow

force exerted by the biceps, F

r = distance of biceps force from elbow

Using elbow-based torque equilibrium

F r = mf rf + mb rb

using the equilibrium of force in the vertical direction, F r = 3.2 eq-1 where F r = 5 x 0.30 + 8.50 x 0.20

F = mb + mf g

F = 8.50* 9.8 + 5 * 9.8

F = 132.3 N

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A square copper loop,10.0 cm on a side,is located in a region of changing magnitude field.the direction of the magnetic field makes an angle 37° with the plane of the loop.the time changing field has the following time dependence , B(t) = 0.01T + (1.00×10^-3 T/s )t.find the induced emf in the copper loop for time t>0.

Answers

The induced emf in the copper loop is -79.86 mV.

What is induced emf?

The induced emf in the copper loop is given by the equation:

[tex]e = -(dΦ/dt) = - (d/dt)(BAcosθ)[/tex]

where Φ is the magnetic flux through the loop, B is the magnitude of the magnetic field, A is the area of the loop, and θ is the angle between the magnetic field and the plane of the loop.

Given that the side of the square loop is 10.0 cm, the area of the loop is ([tex]10.0 cm)^2 = 100 cm^2.[/tex]

[tex]B(t) = 0.01T + (1.00×10^-3 T/s )t ,[/tex]

Given that the direction of the magnetic field makes an angle 37° with the plane of the loop, so the angle θ=37°

Substituting the values we have:

[tex]e = - (100 cm^2)( d/dt)((0.01T + (1.00×10^-3 T/s )t)cos37°)e = - (100 cm^2)(1.00×10^-3 T/s) cos37°e = - (100 cm^2)(1.00×10^-3 T/s) * 0.7986e = - (79.86×10^-3 T/s)[/tex]

The induced emf in the copper loop is -79.86 mV.

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The pulmonary artery, which connects the heart to the lungs, is 8.5 cm long and has a pressure difference over this length of 450 Pa
Part A If the inside radius of the artery is 2.4 mm, what is the volume of blood that flows per second through the pulmonary artery? Express your answer using two significant figures
Part B If the radius of the artery is reduced by 10%, by what factor is the blood flow rate reduced? Assume that all other properties of the artery remain unchanged. Express your answer using two significant figures
(note: the answers need to be in cm^3/s)

Answers

The volume of blood that flows per second through the pulmonary artery  is  2.81 cm^3/s and the blood flow rate is reduced to 0.75.

A. To find the volume of blood that flows per second through the pulmonary artery, we need to use the formula for the volume flow rate of a fluid, which is:

Q = A × v

Where Q is the volume flow rate, A is the cross-sectional area of the artery, and v is the velocity of the blood flow.

We can find the cross-sectional area of the artery using the formula for the area of a circle:

A = πr²

Where r is the radius of the artery.

Substituting in the given values:

r = 2.4 mm = 0.0024 m

A = πr² = π×(0.0024 m)² = 1.13 × 10⁻⁶ m²

We are given that the pressure difference over the length of the pulmonary artery is 450 Pa, and Poiseuille's Law states that the flow rate of a fluid is directly proportional to the pressure difference, and inversely proportional to the viscosity of the fluid and the radius of the vessel, and directly proportional to the fourth power of the radius.

Q = (πr⁴Ρ)÷8ηL

Where η is the viscosity of the fluid and L is the length of the vessel.

Q = (π×(0.0024 m)⁴⁴⁵⁰ Pa)÷8η×8.510⁻² m

Q = 2.81 × 10⁻⁵ m³/s

Q=2.81×10⁻⁵ m³/s ×1000 cm³/m³ = 2.81 cm³/s

B. When the radius of the artery is reduced by 10%, the radius becomes 0.0024 m × 0.9 = 0.00216 m. The new cross-sectional area of the artery is A = π×(0.00216 m)² = 9.55 * 10⁻⁷ m²

Using Poiseuille's Law again we can find the new volume flow rate,

Q = (π×(0.00216 m)⁴⁴⁵⁰ Pa) ÷8η×8.510⁻² m

Q = 2.10 × 10⁻⁵ m³/s

Q=2.10×10⁻⁵ m³/s × 1000 cm³/m³ = 2.10 cm³/s

The new flow rate is 2.10 cm³/s / 2.81 cm³/s = 0.75

So the blood flow rate is reduced by a factor of 0.75 (or 75%) when the radius of the artery is reduced by 10%.

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how much energy is stored in a 5.0-h inductor carrying 35 a?

Answers

The energy stored in a 5.0 henry inductor carrying 35 A is 3062.5 Joule.

What is inductance?

An electrical conductor's tendency to resist a change in the flow of current through it is known as inductance. The SI unit for inductance is Henry, and L is used to denote it.

Inductance of the inductor is: L = 5.0 Henry.

Current flowing through it is: I = 35 ampere.

Hence, the energy stored in it = 1/2 × L × I²

= 1/2 × 5.0 × 35² Joule

= 3062.5 Joule.

So, the energy stored in the inductor  is  3062.5 Joule.

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The stability of a vehicle is often rated by the static stability factor, which is one-half the track width divided by the height of the center of gravity above the road.
Part A
One SUV has a static stability factor of 1.2. What is the critical angle?
Express your answer using two significant figures.

Answers

The critical angle of SUV has a static stability factor of 1.2 is found to be Ф = 47.73

How is the static stability factor determined?

The static stability factor (SSF) is defined as the ratio of the height of the centre of gravity to one half the track width.

static stability factor (SSF)= tan Ф

 => Ф = tan^-1 (SSF)

=> tan^-1(1.2) =>  47.73

How can you gauge the stability of a vehicle?

The formula SSF=T/2H is used to determine a vehicle's SSF, where T denotes "track width" and H denotes "height of centre of gravity."

Where is the gravity's centre?

The average location of an object's weight is known as its centre of gravity. Any object's motion through space may be completely explained in terms of how its centre of gravity moves from one location to another and that is how it rotates around its axis.

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The figure(Figure 1) shows four sides of a 6.0cm×6.0cm×6.0cm cube.
Part A
What is the electric flux Φ1 through side 1?
Express your answer using two significant figures.
Part B
What is the electric flux Φ2 through side 2?
Express your answer using two significant figures.
Part C
What is the electric flux Φ3 through side 3?
Express your answer using two significant figures.
Part D
What is the electric fluxe Φ4 through side 4?
Express your answer using two significant figures.
Part E
What is the net flux through these four sides?
Express your answer using two signifi​cant figures.

Answers

The electric flux of various sides of cube are found to be - 1.558845727 N m2 , 0.9 N m2 /C, 1.558845727 N m2 /C and - 0.9 N m2 /C.

What is electric flux ?

Electric flux is a characteristic of an electric field that can be conceptualised as the quantity of electric lines of force (or electric field lines) that cross a specific region. Positive electric charges are thought to be where electric field lines begin, while negative electric charges are thought to be where they end.

What is net flux?

The total number of electric field lines that are perpendicular to the surface and crisscross it is known as net electric flux. Scalar quantity is used to represent the electric flux. D = E in mathematics.

Electric flux is nothing but the dot product between the Electric field vector and the area vector whose direction is given by the outward normal (indicated by the green arrows)

Area S = 0.06 x 0.06 = 0.0036 m2

a.)  ? = E.S = ESCos?    = 500 x 0.0036 x Cos 150 = - 1.558845727 N m2 /C  

b.)  ? = E.S = ESCos?    = 500 x 0.0036 x Cos 60 = 0.9 N m2 /C

c.)  ? = E.S = ESCos?    = 500 x 0.0036 x Cos 30 =  1.558845727 N m2 /C

d.)  ? = E.S = ESCos?    = 500 x 0.0036 x Cos 120 = - 0.9 N m2 /C

e.) Net flux through these four sides is the sum of all the fluxes through the individual sides.

? =   - 1.558845727 + 0.9 +  1.558845727  - 0.9 =  0  N m2 /C

Therefore, all the parts of questions are explained above.

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If there is going to be a total lunar eclipse tonight, then you know that:
If there is going to be a total lunar eclipse tonight, then you know that:
the Moon's phase is full.
the Moon's phase is new.
the Moon is unusually close to Earth.

Answers

The correct option about total lunar eclipse is that the moon's phase is full and the moon is unusually close to Earth.

Moon is also known as satellite of earth and revolves around the Earth. Earth is the planet that revolves around the sun. When the moon is unusually close to Earth such that it crosses the Earth's orbital plane, it is results in lunar eclipse.

The mentioned two points in answers the conditions that must be fulfilled for a lunar eclipse to occur.

The condition of moon phase to be new is important and required in the case of solar eclipse. Another required point is close proximity of moon and earth as stated above for lunar eclipse.

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A pulley system has a mechanical advantage of 3, and an object weighing 9 Newtons must be lifted 15 meters. How much force
must be applied to lift the object?
Use the following equation to find the answer:
MA= F0/Fi
(1 point)
O 27 N
O 03 N
O 3 N
O 1.7 N

Answers

The amount of  force that must be applied to lift the object is 3 N.

option B is the correct answer.

How much force must be applied to lift the object?

The amount of force that must be applied to lift the load is calculated by applying formula of mechanical advantage.

The mechanical advantage of a simple machine is the ratio of load to effort applied to overcome the load. Also, it can be defined as the ratio of output force to input force, otherwise known as force ratio.

Mathematically, the formula for mechanical advantage is given as;

M.A = output force / input force

M.A = load / effort

The amount of  force that must be applied to lift the object is calculated as;

M.A = Fo / Fi

where;

Fo is the output force = loadFi is the input force = applied force

Fi = ( Fo ) / ( M.A )

Fi = ( 9 N ) / ( 3 )

Fi = 3 N

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A certain electric dipole consists of charges + and − separated by distance , oriented along the -axis as shown in the figure. Find an expression for the magnitude of the electric field of the dipole at a point far away in the -direction, a distance away from the midpoint of the dipole. Assume that is much greater than . Enter your answer in terms of , , , and 0.

I've seen other questions like this but the answers are coming back as incorrect or they have it with k included. Please help!

Answers

The magnitude of the electric field of the dipole at a point far away in the -direction, a distance away from the midpoint of the dipole is given by

|E| = |-(p * k) / r^3|

What is magnitude of the electric field?

Generally, The electric field of an electric dipole at a point far away from the midpoint of the dipole is given by the following expression:

E = (p * k) / r^3 * (3 *cos(theta) * i^ + sin(theta) * j^)

where:

p is the magnitude of the dipole moment, equal to q * d (q is the charge and d is the distance between the charges)

k is the Coulomb constant (9 x 10^9 N * m^2/C^2)

r is the distance from the dipole to the point where the electric field

is being calculated theta is the angle between the vector pointing from the dipole to the point where the electric field is being calculated and the dipole moment vector (in this case, the -axis) i^ and j^ are the unit vectors in the x and y directions, respectively.

Since the dipole is oriented along the -axis and the point where the electric field is being calculated is far away in the -direction,

theta = pi and the expression for the electric field becomes:

E = (p * k) / r^3 * (3 *cos(pi) * i^ + sin(pi) * j^)

E = -(p * k) / r^3 * (i^)

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How do I determine how much an objects weighs , their mass, and their acceleration and it’s direction from a free body diagram ?

Answers

To determine the mass, weight, and acceleration of an object from a free body diagram, you need to use Newton's laws of motion.

State Newton's laws of motion?

The first law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. The second law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The third law states that for every action, there is an equal and opposite reaction.

To calculate the mass of an object, you can use the equation F=ma, where F is the force applied to the object, m is the mass of the object, and a is the acceleration of the object. To calculate the weight, you can use the equation W=mg, where W is the weight of the object, m is the mass of the object, and g is the acceleration due to gravity. To calculate the acceleration of the object, you can use the equation a=F/m, where F is the net force acting on the object and m is the mass of the object. Finally, to determine the direction of the acceleration, you can look at the arrows in the free body diagram that represent the forces acting on the object.

Therefore, we determine how much an objects weighs , their mass, and their acceleration and it’s direction by using Newton's laws of motion.

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there are two types of cellular phones: handheld phones (h) that you carry and mobile phones (m) that are mounted in vehicles. phone calls can be classified by the traveling speed of the user as fast (f) or slow (w). monitor a cellular phone call and observe the type of telephone and the speed of the user. the probability model for this experiment has the following information: p(f)

Answers

The sequential answer is :A) P(W) = 0.5 and B) P(MF) = 0.3 and C) P(H) = 0.6.

What are cellular phone ?

A mobile phone[a] is a portable telephone that allows users to place and receive calls while on the go inside of a phone service area via a radio frequency link. The radio frequency link creates a connection to a mobile phone operator's switching systems, granting access to the public switched telephone network (PSTN). In North America, mobile phones are referred to as cell phones or cellular telephones since modern mobile telephone services use a cellular network design. Digital mobile phones are capable of a wide range of other services in addition to voice calling, including text messaging, multimedia messaging, email, Internet access (via LTE, 5G NR, or Wi-Fi), short-range wireless communications (infrared, Bluetooth), satellite access (navigation, messaging connectivity), business applications, video games, and digital photography.

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