Answer: the required mass is 1.7628 × 10²⁵ μ
Explanation:
Given that;
energy released in the fission of one ²³⁵U₉₂ is 206.6 MeV
power p = 28.7 Mega Watts = 28.7 × 10⁶ W = 28.7 × 10⁶/ 1.6× 10⁻¹³ = 17.9375 × 10¹⁹ MeV/s
now fission need per second will be;
⇒ power / energy released i fission
= 17.9375 × 10¹⁹ MeV / 206.6 MeV = 8.68 × 10¹⁷ per second
now fission need per day will be;
⇒ ( 8.68 × 10¹⁷ × 360 × 24 ) = 7.5 × 10²² per day
hence mass of ²³⁵U₉₂ that is consumed in one day in this reactor will be;
⇒ (235 × 7.5 × 10²²)μ
= 1.7628 × 10²⁵ μ
Therefore the required mass is 1.7628 × 10²⁵ μ
When an object falls, it is reacting to the force of gravity. true or false
Answer:
The answer is true, as gravity affects everything.
which nervous system includes the spinal cord
A. Sympathetic
B. autonomic
C. Central
D. Somatic
Answer:
the central nervous system
Answer: C. central
Explanation:
Pitch refers to A. how high or low a note is. B. the loudness of a note. C. the length of the note. D. the range of notes in the composition.
This is music by the way.
Answer:
A
Explanation:
OKAY REAL QUICK A NOTE REPRESENTS THE 12 TONES ON THE CHROMATIC SCALE WHICH IN TURN REPRESENTS THE WHOLE OF SOUND IN ALL MUSIC- EACH NOTE HAS A PITCH THAT REPEATS IN EVERY OCTAVE.
Describe the energy transfers and transformations for a javelin, starting from the point at which an athlete picks up the javelin and ending when the javelin is stuck into the ground after being thrown.
Explanation:
When the Javelin is at rest on the ground, Potential Energy and Kinetic Energy are zero. immediately the Athlete picks the javelin up from the ground, there is an increase in the Kinetic Energy this increase continues until the javelin comes to a halt. Potential Energy also increases.
As the Athlete throws javelin, there is a decrease in the Potential Energy, the Kinetic Energy increases simultaneously until the javelin hits the ground.
after which Potential Energy and Kinetic Energy becomes zero.
When two objects collide is the momentum before equal to the momentum after the collision? What happens to the individual carts momentum in terms of momentum before and after collision?
Answer:
a collision occuring between two objects in an isolated system, the total momentum of the two objects after the collision. That is, the momentum lost by object 1 is equal to the momentum gained by object 2.
thank you.
PLEASE HELP ME
1) If a bus travelling at 20 m/s is subject to a steady deceleration of 5 m/s2, how long will it
take to come to rest?
Answer:
Bus will take 4 seconds before it comes to rest.
Explanation:
Initial Velocity of bus = u = 20 ms⁻¹
Final Velocity of bus = v = 0 ms⁻¹
Deceleration of bus = a = -5 ms⁻²
Time taken by bus before it comes to rest = t = ?
Using the equation formula
a = (v - u)/t
-5 = (0 - 20) / (t)
t = -20/-5
t = 4 sec
Therefore, Bus will take 4 seconds before it comes to rest.
Aner shopping. It took Jacob 18 seconds to push his shopping cart to his car. He was moving at 2 meters per second. His daughter walked beside the cart for one-third of the time it took Jacob to reach his car. How far did Jacob's cart move while his daughter was walking beside Write your answer as a whole number meters
Answer:
I am going to answer you just wait a little bit.
ASTRONOMY
Match the following phases of stellar evolution to its characteristics.
*please help me thx*
Answer:
1. Brown dwarf.
2. Red giant.
3. Black dwarf.
4. White dwarf.
5. Black hole.
Explanation:
A star is a giant astronomical or celestial object that is comprised of a luminous sphere of plasma, binded together by its own gravitational force.
Basically, stars are typically made up of two (2) main hot gas, Hydrogen (H) and Helium (He).
Some of the examples of stars are; Canopus, Sun (closest to the Earth), Betelgeus, Antares, Vega etc.
1. Brown dwarf: does not undergo hydrogen fusion.
2. Red giant: has an outer shell of burning hydrogen and a core of helium.
3. Black dwarf: a white dwarf that has lost all its energy.
4. White dwarf: has a core of carbon that is not massive enough to fuse. A white dwarf also known as degenerate dwarf is a star or an electron degenerate matter and is as massive as the Sun but only about as large in size as planet Earth. Also, the maximum mass of a white dwarf is about 1.4 times the mass of the Sun.
5. Black hole: formed from the collapse of a white dwarf beyond 1.5 solar masses.
Answer:
other person is correct!!!
Explanation:
got 100 on test
When landing from a jump, a basketball player of mass 82 kg has a velocity of 1.2 m/s right before they hit the ground. The player then lands on the floor with their feet and is quickly brought to a stop. If the the floor deforms by 0.025 m while the player lands on it, what was the average force under the player's feet during the landing
Answer:
2361.6N
Explanation:
Mass of player = 82kg
Velocity = 1.2m/s
Kinetic energy of player:
= 1/2mv²
= 1/2*82*1.2²
= 41x1.44
= 59.04J
Final kinetic energy = 0
Change in kinetic energy
|∆k| = |0-59.04|
= 59.04
Workdone by the feet = fd
d = 0.025
Fd = 59.04
F = 59.04/0.025
= 2361.6N
This is his average force.
A space probe is sent to an alien planet and conducts an experiment in order to determine the acceleration due to gravity on the planet. It produces the following table
Object Rock Grain of sand Metal bolt
Mass 20 grams 0.8 grams 79 grams
Recorded force of gravity :0.1224 N 0.00501 N 0.4871 N
Given this data, which of the following the closest approximation of the acceleration due to gravity on this planet
a
3.8 m/s^2
b
4.0 m/s^2
c
9.9 m/s^2
d
6.1 m/s^2
Answer: D. 6.1 m/s^2
Explanation:
23 POINTS!! will get brainiest
What is the relationship between temperature range and proximity to the coast?
Answer:I think it’s because both can provide heat and cold
Explanation:
What could you do to decrease the rate at which salt dissolves in water?
Add more salt.
Stir the mixture.
Use cold water.
Use hot water.
Answer:
use hot water
Explanation:
hot water helps dissolve things faster
These steps are involved in the production of work by a four-stroke heat engine. Place the steps in the correct order. Piston moves up, compressing gas and causing gas to increase its temperature: Piston moves up, pushing burned gases through exhaust valve: 1 Spark plug fires, causing combustion as gas is still compressed; increase in energy from combustion pushes piston down: Piston moves down, allowing fuel-air mixture to enter intake valve:
Answer:
correct order 2,4,3,1
Explanation: correct on edge
A woman exerts a horizontal force of 3 pounds on a box as she pushes it up a ramp that is 10 feet long and inclined at an angle of 30 degrees above the horizontal. Find the work done on the box.
Answer: 67 how much candy does nick have
Explanation:
True or False: Solids always have a higher density than liquids and gases.
Answer:
TRUE THE ANSWER IS TRUE
What happens when someone lets go of the button on an electric doorbell?
The electromagnet gets stronger.
The circuit is broken and the electromagnet turns off.
The current moving through the circuit changes direction.
The metal striker hits the bell.
Answer:
The current moving through tha circuit changes direction.
Explanation:
hope this helps
The electromagnet is activated. It causes a buzzer to go off. The hammer strikes the bars which creates sound. When you let go, it will stop making a sound by the circuit stop flowing.
What is electromagnet ?"Electromagnet, device consisting of a core of magnetic material surrounded by a coil through which an electric current is passed to magnetize the core. An electromagnet is used wherever controllable magnets are required, as in contrivances in which the magnetic flux is to be varied, reversed, or switched on and off."
What is Circuit ?"A circuit is a complete circular path that electricity flows through. A simple circuit consists of a current source, conductors and a load. The term circuit can be used in a general sense to refer to any fixed path that electricity, data or a signal can travel through."
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when an object (like a ball) falls, some of its _____ energy changes to _____ energy, due to the law of conservation of energy
a.) kinetic, potential
b.) kinetic, motion
c.) potential, kinetic
d.) motion, potential
Answer:
c ) potential your welcome hehe_________ is the distance an object travels per unit of time.
(5 Points)
speed
displacement
velocity
rate
Explanation:
Speed is the distance an object travel per unit of time
Two planes of charge with no thickness, A and B, are parallel and vertical. The electric field in region I to the left of plane A has magnitude 3σ/2????0 and points to the left. The electric field in the region to the right of B has magnitude 3σ/2????0 and points to the right. The electric field in the region between the two planes has magnitude σ/2????0 and points to the right. The surface charge density on planes A and B respectively is
Answer:
The surface charge density on planes A and B respectively is
[tex]\sigma__{A}} } = 2\sigma[/tex]
and
[tex]\sigma__{B}} = \sigma[/tex]
Explanation:
From the question we are told that
The electric field in region to the left of A is [tex]E_i = \frac{3 \sigma}{2 \epsilon_o}[/tex]
The direction of the electric field is left
The electric field in the region to the right of B is [tex]E_f = \frac{3 \sigma}{2 \epsilon_o}[/tex]
The direction of the electric field is right
The electric field in the region between the two planes is [tex]E_m = \frac{\sigma }{2 \epsilon_o }[/tex]
The direction of the electric field is right
Let the surface charge density on planes A and B be represented as [tex]\sigma__{A}} \ \ and \ \ \sigma__{B}} \ \ \ respectively[/tex]
From the question we see that
[tex]E_i = E_f[/tex]
Generally the electric to the right and to the left is due to the combined electric field generated by plane A and B so
[tex]E_i = E_f = \frac{3\sigma }{2\epsilon} = \frac{\sigma_A }{ 2 \epsilon_o } + \frac{\sigma_B }{ 2 \epsilon_o }[/tex]
=> [tex]\sigma__{A}} + \sigma__{B}} = 3 \sigma -- -(1)[/tex]
Generally the electric field at the middle of the plane A and B is due to the diffencence in electric field generated by plane A and B
i.e
[tex]\frac{\sigma }{2 \epsilon_o } = \frac{\sigma_A }{ 2 \epsilon_o } - \frac{\sigma_B }{ 2 \epsilon_o }[/tex]
=> [tex]\sigma__{A}} - \sigma__{B}} = \sigma[/tex]
=> [tex]\sigma__{A}} } = \sigma + \sigma__{B}[/tex]
From equation 1
[tex]\sigma + \sigma__{B}}+ \sigma__{B}} = 3 \sigma[/tex]
=> [tex]\sigma__{B}} = \sigma[/tex]
So
[tex]\sigma__{A}} } = \sigma + \sigma[/tex]
=> [tex]\sigma__{A}} } = 2\sigma[/tex]
Find the range of projectile launched at the angle of 45 with an intial velocity of 25 m/s
Answer:
10
Explanation:
Given that :
Initial Velocity (u) = 25 m/s
Range can be obtained using the relation :
Range = (u² * sin2θ) / g
g = 10m/s ; θ = 45
Range = [10² * sin2(45)] / 10
Range = [100 * 1] ÷ 10
Range = 10
The spiral spring showed are identical. Each spring has a spring constant K =100N/m determine the total extension caused by the 150N weight
1 spring k=100
2 springs k =200
f=kx
then k=f/x
200=150/x
x=200/150
x=4/3
Explanation:
need thanks ..................
The total extension caused by the 150N weight is 1.5 m
Data obtained from the question Spring constant (K) = 100 N/mForce (F) = 150 NExtention (e) =? How to determine the extensionFrom Hooke's law,
Force (F) = spring constant (K) × extention (e)
F = Ke
150 = 100 × e
Divide both side by 100
e = 150 / 100
e = 1.5 m
Therefore, the total extention caused by the weight is 1.5 m
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A horse pulls a wagon with 2000N of at constant velocity. What is the friction acting on the wagon?
0N
1000N
1500N
2000N
Answer:
f = 0 N
Explanation:
It is given that,
A horse pulls a wagon with 2000N of at constant velocity.
We need to find the friction acting on the wagon.
As the wagon is pulled with a constant velocity. If its velocity is constant, it means its acceleration is 0. As a result friction force is 0.
Hence, the correct option is (a).
An insulating rod is bent into the shape of a quarter-circle having total charge Q distributed uniformly over its length. At the origin, the magnitude of the total electric field due to this charge configuration is E0 and the potential is V0. A second insulating rod is added to the fourth quadrant to complete a semi-circle. This second quarter-circle has charge -Q uniformly distributed. In terms of E0 and V0, determine the total electric field vector and the total potential at the origin due to the semi-circle of charge.
Answer:
E = - 2*E₀*sinθ*i
V = V = 2*E₀*sinθ /r
Explanation:
First situation: a quarter-circle rod produces at the origin
E₀ and V₀
We know that E = K * Q/r and
E = E₀ Q = L*λ Q = 1/4 * 2*π*r*λ Q = (1/2)*π*r*λ
where:
r is the radius of the circle which at the same time is the distance between the rod quarter of the circle and the origin.
λ is the longitudinal density of charge, and
k = 1/4*π*ε₀
Then E₀ = (1/2)* k*π*λ and V₀ = - E₀/Q V₀ = - E₀/r
E₀ = E₀ₓ + E₀y E₀ₓ = E₀*cosθ E₀y = - E₀*sinθ
θ the angle between E₀ and the x-axis
Second situation half of a circle ( first quarter +Q and fourth -Q )
In that configuration, the components in the x-axis cancel each other ( by symmetry) and the y-axis components of +Q and -Q are to be added then
E = Eₓ + Ey but by inspection we find Eₓ = 0 ( the components of the
the electric field produced of the two quarters canceled each other)
and we have to add the two identical y-axis components of the two quarters therefore
E = 2*E₀y
each component of E₀y = - E₀*sinθ
Then the new electric field becomes
E = - 2*E₀*sinθ*i
The new V = - (- 2*E₀*sinθ /r)
V = 2*E₀*sinθ /r
(Note remember that V is a scalar )
A small hole P is made in a piece of cardboard. The hole is illuminated by a torch as shown in Fig. 16.3. The pencil of light coming out of the hole falls on a mirror.
5th question
Answer:
According to law of reflection i know in case of plane mirror the angle of reflection is equal to the angle of incidence. So,if you placed the eye on point A the hole can be seen.
Explanation:
A ball of clay is thrown at a wall at a velocity of 28.0 m/s. After it hits the wall, it
takes 0.020 s to stop. What is the acceleration of the clay when it hits the wall?
Answer:
Explanation:
1400 m/s2
The acceleration of the ball when it hits the vertical wall is -1,400 m/s²
The given expression:
velocity of the ball, v = 28 m/s
time of motion of the ball, t = 0.02 s
To find:
the acceleration of the ball when it hits the vertical wall.The acceleration of the ball is calculated as follows:
[tex]acceleration = \frac{\Delta velocity}{\Delta time} = \frac{Final \ velocity\ - \ initial \ velocity }{time} \\\\final \ velocity \ of \ the \ ball \ when \ it \ hits \ the \ wall = 0\\\\acceleration = \frac{0 - 28}{0.02} \\\\acceleration = - \ 1,400 \ m/s^2[/tex]
Thus, the acceleration of the ball when it hits the vertical wall is -1,400 m/s²
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Young's double slit experiment is one of the quintessential experiments in physics. The availability of low cost lasers in recent years allows us to perform the double slit experiment rather easily in class. Your professor shines a green laser (568 nm) on a double slit with a separation of 0.107 mm. The diffraction pattern shines on the classroom wall 3.5 m away. Calculate the fringe separation between the third order and central fringe.
Answer:
18.58 mm
Explanation:
Formula for the fringe width is;
β = λL/d
We are given;
λ = 568 nm = 568 × 10^(-9) m
L = 3.5 m
d = 0.107 mm = 0.107 × 10^(-3) mm
β = (568 × 10^(-9) × 3.5)/(0.107 × 10^(-3))
β = 0.01858 m = 18.58 mm
2. 290 grams of water is to be heated from 24.0% to 100.0°C to make a cup of
tem, how much heat must be added? The specific heat of water is 4.18 J/g•C
Answer:
92127.2 j
Explanation:
Given that :
Mass of water = 290 g
Specific heat of water (C) = 4.18 j/g.C
Initial Temperature (t1) = 24°C
Final temperature (t2) = 100°C
Using the relation :
Q = mCdt
dt = change in temperature =( 100 - 24)° = 76°C
Q = quantity of heat ; C = specific heat capacity;
m = mass of substance
Q = 290 g * 4.18 j/g.C * 76°C
Q = 92127.2 j
A 430.0 g mass is being pushed by a 1.1 N net force. What is the acceleration?
Answer:
[tex]a = 2.56\ m/s^2[/tex]
Explanation:
Mechanical Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
F = m.a
Where a is the acceleration of the object.
The object has a mass of m=430 g = 0.43 Kg and is pushed by a net force of F=1.1 N. To calculate the acceleration, we solve for a:
[tex]\displaystyle a=\frac{F}{m}[/tex]
[tex]\displaystyle a=\frac{1.1}{0.43}[/tex]
[tex]\mathbf{a = 2.56\ m/s^2}[/tex]
please answer True or false
In two square the server earns a point when the opponent catches the ball.
Light of intensity So and polarized horizontally passes through three polarizes. The first and third are horizontal, but the second is oriented 0.3927 rad to the horizontal. In terms of So , what is the intensity of the light that passes through the set of polarizers
Answer: the intensity of the light that passes through the set of polarizers is 0.7285 S₀
Explanation:
based on the data in the question;
As the first polarizer lets all the light through because its plane of polarization is not different from light.
The second polarizer has 2 effects;
firstly, it reduces the intensity by a factor cos²0.3927^c; if you switch the calculator to radians mode, this will give you 0.85355
Secondly; it changes the plane of polarization of the light to be the same as the polarizer; therefore the light now has a plane of polarization of 0.3927 rad to the horizontal.
Hence;
after the second effect, the light enters the third polarizer at 0.3927 rad to the plane of polarization of third polarizer. So the intensity is again reduced by a factor 0.85355.
Therefore
the Overall reduction is by a factor of 0.85355 × 0.85355 S₀
= 0.7285 S₀
Therefore the intensity of the light that passes through the set of polarizers is 0.7285 S₀