The exponential regression equation y=307.60(1.11)^x models the dollar value of a retirement fund after x years. Which is best estimate for the value of the retirement fund after 6 years, if no additional deposits or withdrawals are made. ?

A. $310

B. $580

C. $1,880

D. $2,050

Answer:

37

Step-by-step explanation:

296÷8=37

Hope this helps! :)

Answer:

37 apples will be in 9 boxes

Step-by-step explanation:

296 ÷ 8 = 37

Answer:

C 0.90

Step-by-step explanation:

Add 0.10 and 0.80=0.90

Answer:

D

Step-by-step explanation:

P(A and B)=P(A)×P(B)=0.80×0.10=0.08

Answer:

Coefficient of determination, R²

Step-by-step explanation:

The proportion of variation of the dependent variable that can be explained by the regression line is defined by the coefficient of determination, R².

In the scenario described above, the proportion of variation in the number of minutes of activity per day(dependent variable) that can be explained by age, hours of sleep and minutes spent on social media (independent variables) which forms the regression line is 0.45 (45%) is the coefficient of determination while (1 - 0.45) = 0.55 is due to other factors.

Answer:

D

Step-by-step explanation:

the end result of a radical can never be negative unless the negative sign shows outside of the radical

Answer:

asap!!

For the following geometric sequence, find the recursive formula.

(-80,20,-5...)

Step-by-step explanation:

asap!!

For the following geometric sequence, find the recursive formula.

(-80,20,-5...)

Answer:

I can graph stuff in different ways. but place share the mentioned tables. the data is missing.

will edit this placeholder answer asap when you show wich data to graph

Answer:

30 I suppose

Step-by-step explanation:

Answer:

first and fourth options

x = pi/6

x= 11pi/6

Step-by-step explanation:

cos(30 degrees) = sqrt(3)/2

as pi stands for a half circle of 180 degrees

30 degrees = pi/6

cos(30) = cos(-30) = cos (330) =

cos(pi/6) = cos(-pi/6) = cos(11×pi/6)

Answer:

A and d

Step-by-step explanation:

Edge:)

Answer:

∅ = 83.9º

Step-by-step explanation:

tan = opp/adj

opp = 15 - 1 = 14

tan∅ = 14/1.5

∅ = arctan 14/1.5

use calculator

∅ = 83.884496433714593º

Rounded

∅ = 83.9º

F(1) is saying the value of x is 1

Look at the graph where x is 1 and find the y value of where the line is.

At x = 1, the line is at y = 1 ( there is actually a dot showing you the location.

The answer is 1

Answer:

Letter B

Step-by-step explanation:

I used a graphing calculator,

Hope this helps

Answer:

3/8

Step-by-step explanation:

Both measurements should be in same measure.So convert m to cm

2.4m = 2.4 * 100 = 240.0 = 240 cm

[tex]\frac{90}{240}=\frac{9}{24}=\frac{3}{8}[/tex]

Answer:

- 54

Step-by-step explanation:

11 c + 5 a - 8

11 × -6 + 5 × 4 - 8 (given :- a = 4 and b = -6)

- 66 + 20 - 8

- 54

Answer:

In explanation

Please let me know if something doesn't make sense.

Step-by-step explanation:

a)

*This relation is not reflexive.

0 is an integer and (0,0) is not in the relation because 0(0)>0 is not true.

*This relation is symmetric because if a(b)>0 then b(a)>0 since multiplication is commutative.

*This relation is transitive.

Assume a(b)>0 and b(c)>0.

Note: This means not a,b, or c can be zero.

Therefore we have abbc>0.

Since b^2 is positive then ac is positive.

Since a(c)>0, then (a,c) is in R provided (a,b) and (b,c) is in R.

*The relation is not antisymmretric.

(3,2) and (2,3) are in R but 3 doesn't equal 2.

b)

*This relation is reflective.

Since a^2=a^2 for any a, then (a,a) is in R.

*The relation is symmetric.

If a^2=b^2, then b^2=a^2.

*The relation is transitive.

If a^2=b^2 and b^2=c^2, then a^2=c^2.

*The relation is not antisymmretric.

(1,-1) and (-1,1) is in the relation but-1 doesn't equal 1.

c)

*The relation is reflexive.

a/a=1 for any a in the naturals.

*The relation is not symmetric.

Wile 4/2 is an integer, 2/4 is not.

*The relation is transitive.

If a/b=z and b/c=y where z and y are integers, then a=bz and b=cy.

This means a=cyz. This implies a/c=yz.

Since the product of integers is an integer, then (a,c) is in the relation provided (a,b) and (b,c) are in the relation.

*The relation is antisymmretric.

Assume (a,b) is an R. (Note: a,b are natural numbers.) This means a/b is an integer. This also means a is either greater than or equal to b. If b is less than a, then (b,a) is not in R. If a=b, then (b,a) is in R. (Note: b/a=1 since b=a)

Answer: 2/3x-y=19/3

Step-by-step explanation:

Points are useless since we already know the point slope form and we can just simply that

y+1=2/3(x-8)

y+1=2/3x-16/3

y=2/3x-19/3

2/3x-y=19/3

Step-by-step explanation:

the answer is in the above image

Answer:

my answer is 225/5 sorry comments for wrong

Answer:

[tex]Width = 59[/tex]

Step-by-step explanation:

Given

The above data

Required

The class width

To do this, we simply calculate the difference between the class limits of any one of the classes.

Taking 1187–1246 as a point of reference, the class width is:

[tex]Width = 1246 - 1187[/tex]

[tex]Width = 59[/tex]

Answer:

question 19 = no solution because not enough information

question 20 = 18 for volume

Step-by-step explanation:

question 19:

cylinder formula

surface A =2πrh+2πr2

2π times 9 times 7 + 2π times 9 times 2

SA = 508.938009882

volume equals 395.840674352

question 20:

biggest one,

4h﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4

V=18 IS the volume

Answer:

The last formulas are called

square based pyramid formula

cone formula

sphere formula

Can help with the first two as im short of time

Hope this helps.

Always remember to check the units^3

Step-by-step explanation:

19)   V = π r 2 h  = 1781.28303 ft3  = 1781.3ft^3

20) V = 1/2 b h l = 180m^3

Answer:

5x+4y=24

Step-by-step explanation:

So Ax+By=C is the standard form equation of a line.

y=mx+b (in which m is the slope and b is the y-intercept) is the equation that most people start off with.

Since the line intersects the y-axis at (0,6), the y-intercept is 6.

So, we can substitute 6 with b, which is y=mx+6.

Now, we can find the slope (m) by either inserting a known point (x,y) or using rise/run. Either way, you get the slope as -5/4 because we go five units DOWN and four units RIGHT from (0,6), one known point, to (4,1), another known point.

The y=mx+b equation becomes: y=(-5/4)x+6.

Now, we subtract (-5/4)x on both sides to get (5/4)x+y=6

Multiply 4 on both sides because standard form requires no fractions or decimals.

The final answer is 5x+4y=24.

That's your answer, fully simplified!

Answer:

Step-by-step explanation:

              Steps                                Justifications

1). -2x = 28 - 6x                               1). Given

2). -2x + 6x = 28 - 6x + 6x              2). Addition property of equality

3). 4x = 28                                       3). Simplification

4). [tex]\frac{4x}{4}=\frac{28}{4}[/tex]                                        4). Division property of equality

5). x = 7                                            5). Simplification

Answer:

[tex] \frac{8}{5} = \frac{4}{x} \\ 8x = 20 \\ x = 2.5[/tex]

Answer:

here the resize factor is 5/8

so we need to calculate

x = 4 *5/8

= 20/8

= 2.5

I assume you get the basic idea from the other question you posted.

Answer:

A is is correct since the interquatile or a is 15 since 15 plus 15 equals 30 and 20 plus 20 equals 40

B is incorrect since the interquare are not both 30

C is incorrect since both interquatiles are wrong

D is incorrect since the standrard devations are off

Answer:

a. i. (i + tj + 2tk)/√(1 + 5t²)

ii.  (-5ti + j + 2k)/√[25t² + 5]

b. √5/[√(1 + 5t²)]³

Step-by-step explanation:

a. The unit tangent

The unit tangent T(t) = r'(t)/|r'(t)| where |r'(t)| = magnitude of r'(t)

r(t) = (t, t²/2, t²)

r'(t) = dr(t)/dt = d(t, t²/2, t²)/dt = (1, t, 2t)

|r'(t)| = √[1² + t² + (2t)²] = √[1² + t² + 4t²] = √(1 + 5t²)

So, T(t) = r'(t)/|r'(t)| = (1, t, 2t)/√(1 + 5t²)  = (i + tj + 2tk)/√(1 + 5t²)

ii. The unit normal

The unit normal N(t) = T'(t)/|T'(t)|

T'(t) = dT(t)/dt = d[ (i + tj + 2tk)/√(1 + 5t²)]/dt

= -5ti/√(1 + 5t²)⁻³ + [-5t²j/√(1 + 5t²)⁻³] + [-10tk/√(1 + 5t²)⁻³]

= -5ti/√(1 + 5t²)⁻³ + [-5t²j/√(1 + 5t²)⁻³] + j/√(1 + 5t²)+ [-10t²k/√(1 + 5t²)⁻³] + 2k/√(1 + 5t²)

= -5ti/√(1 + 5t²)⁻³ - 5t²j/[√(1 + 5t²)]⁻³ + j/√(1 + 5t²) - 10t²k/[√(1 + 5t²)]⁻³ + 2k/√(1 + 5t²)

= -5ti/√(1 + 5t²)⁻³ - 5t²j/[√(1 + 5t²)]⁻³ - 10t²k/[√(1 + 5t²)]⁻³ + j/√(1 + 5t²) + 2k/√(1 + 5t²)

= -(i + tj + 2tk)5t/[√(1 + 5t²)]⁻³ + (j + 2k)/√(1 + 5t²)

We multiply by the L.C.M [√(1 + 5t²)]³  to simplify it further

= [√(1 + 5t²)]³ × -(i + tj + 2tk)5t/[√(1 + 5t²)]⁻³ + [√(1 + 5t²)]³ × (j + 2k)/√(1 + 5t²)

= -(i + tj + 2tk)5t + (j + 2k)(1 + 5t²)

= -5ti - 5²tj - 10t²k + j + 5t²j + 2k + 10t²k

= -5ti + j + 2k

So, the magnitude of T'(t) = |T'(t)| = √[(-5t)² + 1² + 2²] = √[25t² + 1 + 4] = √[25t² + 5]

So, the normal vector N(t) = T'(t)/|T'(t)| = (-5ti + j + 2k)/√[25t² + 5]

(b) Use Formula 9 to find the curvature.

The curvature κ = |r'(t) × r"(t)|/|r'(t)|³

since r'(t) = (1, t, 2t), r"(t) = dr'/dt = d(1, t, 2t)/dt  = (0, 1, 2)

r'(t) = i + tj + 2tk and r"(t) = j + 2k

r'(t) × r"(t) =  (i + tj + 2tk) × (j + 2k)

= i × j + i × 2k + tj × j + tj × 2k + 2tk × j + 2tk × k

= k - 2j + 0 + 2ti - 2ti + 0

= -2j + k

So magnitude r'(t) × r"(t) = |r'(t) × r"(t)| = √[(-2)² + 1²] = √(4 + 1) = √5

magnitude of r'(t) = |r'(t)| = √(1 + 5t²)

|r'(t)|³ = [√(1 + 5t²)]³

κ = |r'(t) × r"(t)|/|r'(t)|³ = √5/[√(1 + 5t²)]³

Hope this might help you (•.•) :)

Answer:

x = 2 ± [tex]\frac{\sqrt{2} }{2}[/tex]

Step-by-step explanation:

9514 1404 393

Answer:

  3 units left

Step-by-step explanation:

Replacing x in a function with (x-h) translates the graph to the right by h units. Here, you have h = -3, so the graph is translated left 3 units.