The wavelengths that appear in the emission spectrum are the ones that correspond to the transitions of electrons from a higher energy level to a lower energy level.
What is wavelentgh?Wavelength is a measure of the distance between two successive crests or troughs of a wave. It is expressed in units of length, such as meters, centimeters, or nanometers. Wavelength is a fundamental property of any wave that is determined by its frequency and speed. The speed of a wave is determined by its medium; for example, light waves travel faster in a vacuum than in air. Wavelengths of different types of waves can differ significantly. Examples of different types of waves include sound waves, radio waves, and light waves
In this diagram, the transitions represented are from level 3 to 1, from level 3 to 2, and from level 2 to 1. Therefore, the wavelengths that appear in the atom's emission spectrum are from wavelength 3 to 1, from wavelength 3 to 2, and from wavelength 2 to 1.
The wavelengths that appear in the absorption spectrum are the ones that correspond to the transitions of electrons from a lower energy level to a higher energy level. In this diagram, the transitions represented are from level 1 to 2, from level 1 to 3, and from level 2 to 3. Therefore, the wavelengths that appear in the atom's absorption spectrum are from wavelength 1 to 2, from wavelength 1 to 3, and from wavelength 2 to 3.
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Earth travels around the Sun each year in sn elliptical path, as opposed to a perfect curcle. This means that the speed if earth and its dustance from the Sun change over rhe course if a year. What does this sayabout the magnitude of the centripetal acceleration if earth over the course of a year
A change in the linear speed of the Earth around the sun will cause a change in the magnitude of the centripetal acceleration.
What is centripetal acceleration ?
Centripetal acceleration is the acceleration of a body moving a circular path.
The relationship between centripetal acceleration and speed;
a = v²/r
where;
v is linear speeda is centripetal accelerationr is radius of the pathSince the centripetal acceleration is directly proportional to square of linear speed, a change in the linear speed of the Earth around the sun will cause a change in the magnitude of the centripetal acceleration.
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Thanks to the direction finding feature in gmaps application, which most of us use, we can find our way. Here, the maps application offers us alternative routes. Among these suggestions, I want to choose the path that will have the least fuel and do this based on calculations. For example, one of the two directions may be short, but if that short route is also uphill, it will not be an economical route. In my opinion the most important factor is elevation. If we take elevation into account other factors such as friction, where assuming the same asphalt type is often used in the same area for friction, I think the correct result will be achieved. In your opinion, what are the input data required to find the least energy path, what assumptions can be made and what are the necessary formulations and calculations?
In my opinion, I think that the input data that are required to find the least energy path are:
ElevationDistanceWhat is a Map?This refers to the use of a diagram to represent the features of a place that shows its physical landforms to help in navigation.
Hence, we can see that when using maps like gmaps, it is important to consider both elevation and distance to be able to find the path that uses the least energy.
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Haley is trying to pull an object upward. The below forces are acting on the object.
Fp= 5500 N
Fg= 6000 N
Which represents the net force?
The net force is represented by ↓ 500N.
What is the net force?The net force is the force that has the same effect in magnitude and direction as two or more forces acting together.
Now we have the forces;
Fp= 5500 NFg= 6000 NThus we can obtain the net force as;
5500 N - 6000 N
= - 500 N
Therefore the net force is represented by ↓ 500N.
Missing parts:
Haley is trying to pull an object upward. The below forces are acting on the object.
Fp = 5500N
Fg = 6000N
Which represents the net force?
← 500N
→ 500N
↑ 500N
↓ 500N
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How many bytes of memory space are there in an 80 GB hard disk and 256 GB card?
Answer:
80GB= 80000000000 bytes
256GB= 274877906944 bytes
Explanation:80GB= 80000000000 bytes
256GB= 274877906944 bytes
Why is infinity the zero point for electric potential energy true?
A. Electric field strength is zero at the charge
B. Electric field strength is zero at infinity
C. Not enough info
D. Electric field strength is zero somewhere in the middle
Infinity is the zero point for electric potential energy because Electric field strength is zero at infinity.
This conclusion is not "derived" from anything else; the electrostatic potential is zero at infinity because that is how we define it.
Define electric field and electric field strength.
The physical field that contains electrically charged particles and pulls or attracts all other charged particles in the vicinity is known as an electric field. Additionally, it describes the physical environment of a system of charged particles.
The intensity of an electric field at a specific location is expressed quantitatively as "electric field strength." The volt per meter (v/m or v m-1) is the common unit.
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The mass of Saturn is 5.68 x 1026 kg, and use an orbital radius of 3.00 x 105 km. (G = 6.67 × 10-11 N ∙ m2/kg2). Find the orbital speed of an ice cube in the rings of Saturn.
The orbital speed of an ice cube in the rings of Saturn is determined as 355,366.5 m/s.
What is orbital speed?
The orbital speed of an astronomical body or object is the speed at which it orbits around the center of mass of the most massive body.
Orbital speed of ice cube in the rings of SaturnThe orbital speed of ice cube in the rings of Saturn is calculated as follows;
v = √GM/r
where;
G is universal gravitation constantM is mass of Saturnr is the distance of the ice cubev = √(6.67 x 10⁻¹¹ x 5.68 x 10²⁶)/(3 x 10⁵)
v = 355,366.5 m/s
Thus, the orbital speed of an ice cube in the rings of Saturn is determined as 355,366.5 m/s.
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A 41-kg pole vaulter running at 10 m/s vaults over the bar. Her speed when she is above the bar is 1.5 m/s. Neglect air resistance, as well as any energy absorbed by the pole, and determine her altitude as she crosses the bar.
Answer:
___________m
The altitude of the pole vaulter as she crosses the bar is 5 m.
The altitude of the barv² = u² - 2gh
where;
v is final velocity of the pole vaulteru is the initial velocity of the pole vaulterh is altitude of the barh = (u² - v²)/2g
h = (10² - 1.5²)/(2 x 9.8)
h = 5 m
Thus, the altitude of the pole vaulter as she crosses the bar is 5 m.
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A particle with a mass of 1.98×10^−4 kg carries a negative charge of -3.50×10^−8 C. The particle is given an initial horizontal velocity that is due north and has a magnitude of 3.78×10^4 m/s.
a) What is the magnitude of the minimum magnetic field that will keep the particle moving in the earth's gravitational field in the same horizontal, northward direction?
b) What is the direction of the minimum magnetic field?
(a) The magnitude of the minimum magnetic field is 1.467 T.
(b) The direction of the minimum magnetic field will be eastwards.
Minimum magnetic fieldF = qvB
mg = qvB
B = mg/qv
where;
B is magnetic fieldv is velocitym is mass of the particleq is charge of the particleB = (1.98 x 10⁻⁴ x 9.8) / (3.5 x 10⁻⁸ x 3.78 x 10⁴)
B = 1.467 T
Direction of the magnetic fieldThe magnetic field will be directed towards the negative charge. Thus, the direction of the minimum magnetic field will be eastwards.
Thus, the magnitude of the minimum magnetic field is 1.467 T and the direction is eastwards.
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Help me please.
A
B
C
D
I will go to school tomorrow .....is this present tense or past tense or future tense
Answer:
D
Explanation:
The given vector can be broken down into two components (as shown in the figure).
Which results ; vector (s) = 3x + 4y.
Light of intensity I0 is polarized vertically and is incident on an analyzer rotated at an angle from the vertical. Find the angle if the transmitted light has intensity
I = (0.750)I0, I = (0.500)I0, I = (0.250)I0, and I = 0.
(Enter your answers in degrees.)
a. θ = 41. 4°
b. θ = 60°
c. θ = 75. 5°
d. θ = 90°
How to determine the angleFrom the given information, we would be using the Malus' law
It is given as;
I = I0 cos²θ
Where I0 is the intensity of the polarized light after passing through P
a. To find the angle, compare with the given equation
I = (0.750)I0
I = I0 cos θ
then
cos θ = 0. 750
θ = [tex]cos^-^1(0. 750)[/tex]
θ = 41. 4°
b. I = (0.500)I0
cos θ = 0. 500
θ = [tex]cos^-^1(0. 500)[/tex]
θ = 60°
c. I = (0.250)I0
cos θ = 0. 250
θ = [tex]cos^-^1 (0. 250)[/tex]
θ = 75. 5°
d. I = 0
cos θ = 0
θ = [tex]cos^-^1 (0)[/tex]
θ = 90°
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Using a schematic diagram, explain the steps of the laser technique.
The steps of the use of the laser technique is explained below:
A laser beam is emitted from the diode in the unit and spread into a laser plane (1). The laser plane, appearing as a line on the sphere (2), is reflected and collected by dual CCD arrays (1). The resulting 2D profile is digitized and as the unit travels along the x-axis of the object, multiple profiles are collected yielding a 3D coordinate point cloud of the surface (3). What is a Laser Technique?This refers to the type of surgery that makes use of special light beams in order to cut open the human body in a surgical procedure.
Hence, we can see that the laser technique is considered safer than conventional surgical methods.
Laser techniques include:
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A jet of water squirts out horizontally from a hole near the bottom of the tank, as seen in the figure.
If the hole has a diameter of 3.13 mm, what is the height, h, of the water level in the tank? Assume that x = 1.33 m and y = 1.72 m.
The height, h, of the water level in the tank is mathematically given as
h=1.3675
What is the height, h, of the water level in the tank?Generally, the equation for kinematics is mathematically given as
S=v_o t+(1/2)at^2
Therefore
y=0+(1/2)gt^2
Where
t=(2y/g)^{1/2}
t=(2*1.72/9.8)^{1/2}
t=0.5925s
The horizontal exit velocity will be given as
[tex]Vx=x/t[/tex]
Therefore
[tex]Vx=\frac{0.3.13}{0.5925}[/tex]
Vx=0.5283
In conclusion, applying Bernoulli's Law the tank bottom and tank surface
P+(1/2)pv0^2+pgh=P+(1/2)pvx^2+pgh
(1/2)(p)(0m/s)^2+pgh=(1/2)pvx^2+pg(0m)
gh=(1/2)vx^2
h=(0.5283m/s)^2/(2)(9.8)
h=1.3675
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By how many newtons does the weight of a 100-kg person decrease when he goes from sea level to mountain top at an altitude of 5000 m? The mean radius of the earth is 6.38 × 106 m.
The weight of a 100-kg person decreases by 4 N when he goes from sea level to mountain top at an altitude of 5000 m.
What determines the weight of a person?The weight of a person is determined by the mass of the body and the acceleration due to gravity.
The acceleration due to gravity, g is dependent on the mass of the earth, M the radius of the earth and the gravitational force constant , G.
Mathematically, the acceleration due to gravity at the mountain top is determined using the formula:
g = GM/r²where:
G = 6.67 × 10⁻¹¹ Nm²/kg²
M = 5.9736 x 10²⁴ kg
r = 638000 + 5000 = 6385000
g = (6.67 × 10⁻¹¹ * 5.9736 x 10²⁴ )(6385000)²
g = 9.77 m/s²
His weight at the mountain top will be:
weight = 100 * 9.77
weight = 977 N
Weight at sea level = 100 * 9.81 = 981 N
Decrease in weight = 981 - 977
Decrease in weight = 4 N
In conclusion, the weight of the man varies according to his distance from the earth.
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A thin flexible gold chain of uniform linear density has a mass of 17.1 g. It hangs between two 30.0 cm long vertical sticks (vertical axes) which are a distance of 30.0 cm apart horizontally (x-axis), as shown in the figure below which is drawn to scale.
Evaluate the magnitude of the force on the left hand pole.
The Force on the left hand pole, F' = 0.167N
What is the force on the left hand pole?Force is an agent which produces a change in the motion or state of an object.
Force is a vector quantity.
The general force is calculated as follows:
F = mg/sinθ
m = 17.1 g = 0.0171 kg
g = 9.81 m/s²
θ = 45°
F = 0.0171 * 9.81/sin45
F = 0.237 N
Force on the left hand pole, F' = Fcosθ
F' = 0.237 * cos 45
F' = 0.167N
In conclusion, the force on the left hand pole is the horizontal component of force.
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What is the x-component of a vector with a magnitude of 115 km at an angle of 22°?
The x-component of a vector are < 106.6, 43.07 >
Depending on the angle we are provided, the x-component of a vector can either be cos or sin. Cos always corresponds to the right triangle's side that contacts the specified angle.
If a vector v with magnitude ||v|| makes an angle θ with the positive x-axis then,
v = ||v|| cos θi + ||v|| sin θj
= < ||v|| cos θ , ||v|| sin θ >
Magnitude p = 115 km
Angle = 22°
p = ||p|| < cos θ, sin θ >
p = 115 < cos 22°, sin 22° >
p = 115 < 0.927, 0.3746 >
p = < 106.6, 43.07 >
Therefore, the x-component of a vector are < 106.6, 43.07 >
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In the given figure, weight of stone inside water
is 9N and water displaced by stone is 2N then,
i)What is the actual weight of stone?
ii) Which principle is the
experiment based on?
The actual weight of the stone is 11 N. It is based on the Archimedes principles.
What is Archimedes principle?Archimedes principle states that the up thrust by water on an object is equal to the weight of water displaced.Upthrust by water on an object= actual weight of object - weight inside waterWhat is the actual weight of the object, if its weight inside water is 9N and weight of water displaced is 2N?Actual weight= weight inside water+ weight of water displaced
= 9N + 2N = 11N
Thus, we can conclude that the actual weight of the object is 11N.
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What is the minimum work needed to push a 950- kg car 700 m up along a 8.5 ∘ incline? Ignore friction.
Express your answer with the appropriate units.
The minimum work needed to pus the cart up the inclined plane is 960000 J.
What is work done on a inclined plane?The work done on a inclined plane is given below as:
Work done = force * distanceDistance = 700 m
The force on an inclined plane, F = mgsinθ
where;
m is mass in kg
g = 9.81 m/s²
θ = 8.5°
Work done = 950 * 9.81 * sin 8.5 * 700
Work done = 960000 J
Therefore, minimum work needed is 960000 J.
In conclusion, the work done is a product of force and distance.
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A toroidal solenoid has 600 turns, cross-sectional area 6.90 cm2, and mean radius 4.30 cm.
a) Calculate the coil's self-inductance.
b) If the current decreases uniformly from 5.00 A to 2.00 A in 3.00 ms , calculate the self-induced emf in the coil.
c) The current is directed from terminal a of the coil to terminal b. Is the direction of the induced emf from a to b or from b to a?
(a) The coil's self-inductance is 7.26 mH.
(b) The self-induced emf in the coil is 7.26 V
(c) The direction of the induced emf is from b to a.
Coil's self-inductance
L = N²μA/I
L = (600² x 4π x 10⁻⁷ x 6.9 x 10⁻⁴)/(0.043)
L = 7.26 x 10⁻³ H
L = 7.26 mH
Self-induced emf in the coilemf = N(ΔBA)/t
where;
B is magnetic fieldA is area N is number of turnst is timeB = μNI/L
B1 = (4π x 10⁻⁷ x 600 x 5)/0.043
B1 = 0.0876 T
B2 = (4π x 10⁻⁷ x 600 x 2)/0.043
B2 = 0.035 T
emf = NΔBA/t
emf = (600)(0.0876 - 0.035)(6.9 x 10⁻⁴) / (3 x 10⁻³)
emf = 7.26 V
The direction of the induced emf is always opposite to the direction of the applied current.
Thus, the direction of the induced emf is from b to a.
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Discuss the aspects of either the Gemini Program or the Soyuz Program.
Answer:
The Gemini program
Explanation:
The Gemini Program was the second human spaceflight program hosted by Nasa in the year 1961. Taking place between mission Mercury and Apollo, the Gemini spacecraft carried two people to space and marked the foundation to the upcoming Apollo mission to Moon. It was a series of missions into the outer orbital which took place between 1965 and 1966. Prior to the Gemini missions, NASA had little to no information about space and space traveling. It was crucial for them to get acquainted with life outside before establishing successful Moon landings. And the series of Gemini missions helped them do just that.
Two spheres with uniform surface charge density, one with a radius of 7.4 cm and the
other with a radius of 5.0 cm, are separated by a center-to-center distance of 38 cm. The
spheres have a combined charge of +55μC and repel one another with a force of 0.62 N.
Assume that the charge of the first sphere is greater than the charge of the second sphere.
Question 1.
What is the surface charge density in the sphere of radius 7.4?
Question 2
What is the surface density on the 2nd sphere?
EXPRESS ANSWER USING TWO SIGNIFICANT FIGURES.
(a) The surface charge density in the sphere of radius 7.4 is 0.0322 C/m³.
(b) The surface density on the 2nd sphere is 3.48 x 10⁻⁴ C/m³.
Total charge of the spheresF = kq₁q₂/r²
Fr² = kq₁q₂
q₁q₂ = Fr²/k
where;
r is distance between the chargesk is Coulomb's constantq₁q₂ = (0.62 x 0.38²) / (9 x 10⁹)
q₁q₂ = 9.95 x 10⁻¹² C
q₂ = 9.95 x 10⁻¹² C/q₁
From the question;
q₁ + q₂ = 55 x 10⁻⁶
q₁ + 9.95 x 10⁻¹² /q₁ = 55 x 10⁻⁶
q₁² + 9.95 x 10⁻¹² = 55 x 10⁻⁶q₁
q₁² - 55 x 10⁻⁶q₁ + 9.95 x 10⁻¹² = 0
solve the quadratic equation using formula method;
q₁ = 5.48 x 10⁻⁵ C
q₂ = 55 x 10⁻⁶ C - 5.48 x 10⁻⁵ = 1.82 x 10⁻⁷ C
Volume of the first sphereV1 = ⁴/₃πr³
V1 = (⁴/₃ π)(0.074)³ = 1.7 x 10⁻³ m³
Surface charge density = (5.48 x 10⁻⁵ C) / (1.7 x 10⁻³ m³) = 0.0322 C/m³
Volume of the second sphereV2 = (⁴/₃ π)(0.05)³ = 5.236 x 10⁻⁴ m³
Surface charge density = ( 1.82 x 10⁻⁷ C) / (5.236 x 10⁻⁴ m³) = 3.48 x 10⁻⁴ C/m³
Thus, the surface charge density in the sphere of radius 7.4 is 0.0322 C/m³.
The surface density on the 2nd sphere is 3.48 x 10⁻⁴ C/m³.
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An object of height 8.50 cm is placed 20.0 cm to the left of a converging lens with a focal length of 12.0 cm. Determine the image location in cm, the magnification, and the image height in cm.
The image distance is 33.3 cm while the image height is 14.2 cm.
What is a converging lens?A converging lens will always have a positive focal length hence, we have to find the object distance as follows;
1/f = 1/v + 1/u
1/12 = 1/v + 1/20
1/v = 1/12 - 1/20
1/v = 0.08 - 0.05
v =33.3 cm
Now;
Magnification = 33.3 cm/20.0 cm =1.67
M = Image height/Object height
1.67 = Image height/8.50 cm
Image height = 1.67 * 8.50 cm
Image height = 14.2 cm
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when a branding iron gets heated in a fire the handle becomes hot, how is the energy transferred to the handle
Conduction is a process through which energy is transferred from the branding iron to the handle.
When two objects with different surface temperatures come into close touch with one another, conduction happens. Up until they reach thermal equilibrium, or the point at which they are at the same temperature, the heat energy moves from the hotter to the cooler object.
The metal tip of the branding iron, which makes contact with the branded surface, becomes extremely hot when it is placed in the fire because of the high fire temperature.
Hence, conduction is a process through which energy is transferred from the branding iron to the handle.
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A shot-putter accelerates a 7.5 kg shot from rest to 12 m/s .
If this motion takes 1.6 s , what average power was developed?
Express your answer using two significant figures.
From the calculations, the power developed is 337.5 W.
What is the power developed?First we must obtain the acceleration from;
v = u + at
u = 0 m/s because the motion started rom rest
v = at
a = v/t
a = 12 m/s/ 1.6 s
a= 7.5 m/s^2
The force is obtained from;
F = ma = 7.5 kg * 7.5 m/s^2 = 56.25 N
Now the distance covered is obtained from';
v^2 = u^2 + 2as
v^2 = 2as
s = v^2/2a
s = (12)^2/2 * 7.5
s = 9.6 m
Now;
Work = Fs = 56.25 N * 9.6 m = 540 J
Power expended = 540 J/ 1.6 s = 337.5 W
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A rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. Calculate the normal force (in N) acting on an astronaut of mass 87.4 kg, including his space suit. (Assume the rocket's initial motion parallel to the +y-direction. Indicate the direction with the sign of your answer.)
According to Newton's 3rd law, there will be equal and opposite force on the astronaut which is -6048 N
What does Newton's third law say ?The law state that in every action, there will be equal and opposite reaction.
Given that a rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. We are to calculate the normal force (in N) acting on an astronaut of mass 87.4 kg, including his space suit.
Let us first calculate the force involved in the acceleration of the rocket by using the formula
F = ma
Where mass m = 87.4 kg, acceleration a = 69.2 m/s2
Substitute the two parameters into the formula
F = 87.4 x 69.2
F = 6048.08 N
According to the Newton's 3rd law, there will be equal and opposite force on the astronaut.
Therefore, the normal force acting on the astronaut is -6048 N approximately
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How much work must be done to stop a 975- kg car traveling at 105 km/h ?
Express your answer to two significant figures and include the appropriate units.
The amount of work done to stop a 975- kg car traveling at 105 km/h is 414,808.34J.
How to calculate work done?The amount of work done by a moving object can be calculated using the following formula:
W (Kinetic energy) = ½ mv²
Where;
m = massv = velocityAccording to this question, a car of 975 kg is traveling at 105 km/h. This speed in m/s is 29.17m/s.
K.E = ½ × 975 × 29.17²
K.E = 414,808.34J
Therefore, the amount of work done to stop a 975- kg car traveling at 105 km/h is 414,808.34J.
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Three ropes A, B and C are tied together in one single knot K.
If the tension in rope A is 65.3 N, then what is the tension in rope B?
The tension in the rope B is determined as 10.9 N.
Vertical angle of cable Btanθ = (6 - 4)/(5 - 0)
tan θ = (2)/(5)
tan θ = 0.4
θ = arc tan(0.4) = 21.8 ⁰
Angle between B and Cθ = 21.8 ⁰ + 21.8 ⁰ = 43.6⁰
Apply cosine rule to determine the tension in rope B;
A² = B² + C² - 2BC(cos A)
B = C
A² = B² + B² - (2B²)(cos A)
A² = 2B² - 2B²(cos 43.6)
A² = 0.55B²
B² = A²/0.55
B² = 65.3/0.55
B² = 118.73
B = √(118.73)
B = 10.9 N
Thus, the tension in the rope B is determined as 10.9 N.
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Hello!
This is an example of a force summation in the vertical direction.
We have the tension of rope A upward (+), and the equal vertical components of the tensions of rope B and C downward (-).
These forces sum to zero, since the knot is stationary.
[tex]\Sigma F = T_A - T_{By} - T_{Cy} \\\\0 = T_A - T_{By} - T_{Cy}[/tex]
Ropes 'B' and 'C' form equivalent angles from the vertical. (If you were to draw a line from rope A down). We can use right-triangle trig to determine the angle:
[tex]tan^{-1}(\frac{O}{A}) = \theta[/tex]
The ropes are 5 m long and 2 m tall, which are the opposite and adjacent sides respectively:
[tex]tan^{-1}(\frac{5}{2}) = 68.2^o[/tex]
The vertical components are the adjacent sides from this angle, so, we would use cosine.
[tex]0 = T_A - T_Bcos\theta - T_Ccos\theta[/tex]
Rope 'B' and 'C' have the same tensions since they form the same angle with the vertical and are the same length, so we can call them 'T'.
[tex]0 = T_A - 2Tcos\theta[/tex]
Solving for 'T':
[tex]2Tcos\theta = T_A \\\\T = \frac{T_A}{2cos\theta}\\\\T = \frac{65.3}{2cos(68.2)} = \boxed{87.92 N}[/tex]
A 2.30 mH toroidal solenoid has an average radius of 6.20 cm and a cross-sectional area of 2.80 cm2.
a) How many coils does it have? In calculating the flux, assume that B is uniform across a cross section, neglect the variation of B with distance from the toroidal axis.
b) At what rate must the current through it change so that a potential difference of 2.60 V is developed across its ends?
(a) The number of turns of the coil is determined as 1,596 turns.
(b) The rate of change of current is determined as 1,130.43 A/s.
Number of turns of the solenoid
L = N²μA/l
where;
L is inductance N is number of turnsA is areal is average length = 2πrN²μA = LI
N² = LI/μA
N² = (2.3 x 10⁻³ x 2π x 0.062)/(4π x 10⁻⁷ x 2.8 x 10⁻⁴)
N² = 2,546,428.6
N = √2,546,428.6
N ≈ 1,596 turns
Rate of current changeL = (emf)/I
I = (emf)/L
I = (2.6)/(2.3 x 10⁻³)
I = 1,130.43 A/s
Thus, the number of turns of the coil is determined as 1,596 turns.
The rate of change of current is determined as 1,130.43 A/s.
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ATTA-KAY PHYSICS 121 3. A ball A is left to roll down an inclined plane of inclination 30º. Just at the moment a second ball B is pushed up the plane with a velocity of 45ms¹. The balls met at a point where the velocity of B is 1.8 times the velocity of A. Calculate (a) the velocities of A and B when they meet. (b) when the two balls meet. (c) where the two ball meet. (g = 10 ms²)
vr>vs because the rolling ball acquires rotational as well as translational kinetic energy.
The accelerating force acting on the ball as it goes along a smooth plane is mgsin. Its acceleration is therefore equal to gsin. The mgsin acts down the plane as the ball travels down the rough inclined plane, but friction develops that acts up the plane.
Since both balls' potential energy is lost at the same rate, their KEs are actually equal at the base of the planes. However, a ball sliding down a smooth plane has only translational kinetic energy, but a ball rolling down a rough plane contains both translational and rotational kinetic energy at the bottom of the plane. As a result, the ball's translational KE will be lower than its translational Kinetic energy.
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How big is this restoring force compared with the tensile force stretching the spring?
A. Bigger
B. Not enough info
C. Smaller
D. Same size
The restoring force on the spring is found to have exactly the same magnitude as the stretching force. Option D
What is the restoring force?The restoring force is the force that seeks to restore the spring to its equilibrium position. It has the same magnitude as the stretching force but acts in opposite direction.
Thus, the restoring force on the spring is found to have exactly the same magnitude as the stretching force.
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in a motor, what do the combined effect of electric currents and magnetic forced turn electrical energy into?
mechanical energy
a battery
electromagnetic energy
a generator
(please explain too)