The length of a rectangular room is 7 feet longer than twice the width. If the room's perimeter is 146 feet what are the room's dimensions?
Width - 22 ft: length - 51 ft
Width - 33 ft: length - 40 ft
Width - 27 ft: length - 61 ft
Width - 44 ft: length - 102 ft

Answer:

width- 22ft : length-51 ft

Step-by-step explanation:

if you add 22+22 its 44 +7 it will give you 51.

that is twice the width+ the 7 feet

The dimensions of the room will be 22 feet and 51 feet. Then the correct option is A.

The sum of all the sides of the rectangle will be known as the perimeter of the rectangle. Let L be the length and W be the width of the rectangle.

Then the perimeter of the rectangle will be

Perimeter of the rectangle = 2(L + W) units

The length of a rectangular room is 7 feet longer than twice the width. Then we have

L = 2W + 7

If the room's perimeter is 146 feet. Then the dimension of the rectangle will be

P = 2(L + W)

146 = 2(2W + 7 + W)

73 = 3W + 7

3W = 66

W = 22 feet

Then the length of the rectangle will be

L = 2 x 22 + 7

L = 44 + 7

L = 51 feet

The dimensions of the room will be 22 feet and 51 feet. Then the correct option is A.

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