The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Empirical formula is C₃H₄O₁ and Molecular formula is 7(C₃H₄O₁).
What is Empirical Formula ?Empirical formula is the simplest whole number ratio of atoms present in given compound.
Element % Atomic mass Relative no. of atoms Simplest whole ratio
C 83.87 12 [tex]\frac{83.87}{12}[/tex] = 6.98 [tex]\frac{6.98}{0.25}[/tex] = 3
H 11.99 1 [tex]\frac{11.99}{1}[/tex] = 11.09 [tex]\frac{11.09}{0.25}[/tex] = 4
O 4.14 16 [tex]\frac{4.14}{16}[/tex] = 0.25 [tex]\frac{0.25}{0.25}[/tex] = 1
Thus the empirical formula is C₃H₄O₁.
How to find the Molecular formula of compound ?Molecular formula = Empirical formula × n
n = [tex]\frac{\text{Molecular weight}}{\text{Empirical formula weight}}[/tex]
= [tex]\frac{386.64}{56}[/tex]
= 7
Molecular formula = Empirical formula × n
= 7 (C₃H₄O₁)
Thus from the above conclusion we can say that The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Empirical formula is C₃H₄O₁ and Molecular formula is 7(C₃H₄O₁).
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Given the following equation: 2h20=2h2+02 how many grams of o2 are produced if 3.6 grams of h20 react?
Answer:
3.2 g O₂
Explanation:
To find the mass of O₂, you need to (1) convert grams H₂O to moles H₂O (via molar mass), then (2) convert moles H₂O to moles O₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles O₂ to grams O₂ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to reflect the sig figs of the given value (3.6 g).
Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol
Molar Mass (H₂O): 18.014 g/mol
2 H₂O -----> 2 H₂ + 1 O₂
Molar Mass (O₂): 2(15.998 g/mol)
Molar Mass (O₂): 31.996 g/mol
3.6 g H₂O 1 mole 1 mole O₂ 31.996 g
---------------- x --------------- x --------------------- x --------------- = 3.2 g O₂
18.014 g 2 moles H₂O 1 mole
A. Choose one of the four biogeochemical cycles that were discussed in this unit - carbon, nitrogen, water, or oxygen and describe the cycle in some detail using steps.
B. Give two ways man is disrupting the cycle and the effects that disruption has on the cycle.
Water cycle simply refers to the continuous movement or flow of water from the atmosphere to the earth and back to the atmosphere
What is are the stages of water cycle?These are the basic stages through which water passes. These stages are:
EvaporationCondensationPrecipitation Collection.So therefore, water cycle simply refers to the continuous movement or flow of water from the atmosphere to the earth and back to the atmosphere
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If initially there are 8.0 kg of cesium-137 present in a sample, how many kg will remain after 60.0 years
Answer:
2 kg
Explanation:
the half life of cesium is approx 30 years
60 years is 2 half lives
8 kg * 1/2 * 1/2 = 2 kg
How many silver (Ag) atoms are in 3.0 moles of silver?
Answer:
1.8 x 10²⁴ atoms Ag
Explanation:
You can find the amount of silver (Ag) atoms by multiplying the moles by Avogadro's number. It is important to arrange the conversion in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to match the sig figs of the given value.
Avogadro's Number:
6.022 x 10²³ atoms = 1 mole
3.0 moles Ag 6.022 x 10²³ atoms
---------------------- x -------------------------------- = 1.8 x 10²⁴ atoms Ag
1 mole
Calculate the number of ions of the following compound :16g of H2CO3
Answer:
1) a) 1.81 × 10²³ molecules (b) 1.93 × 10²³ molecules (c) 0.66× 10²³ molecules
2) a) 0.45× 10²³ions (b) 0.84× 10²³ions (c) 3.6 × 10²³ions
Explanation:
1) Number of molecules:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
a) 16g of H₂CO₃
Number of moles = mass/ molar mass
Number of moles = 16 g/ 62.03 g/mol
Number of moles = 0.3 mol
1 mol = 6.022 × 10²³ molecules
0.3 mol × 6.022 × 10²³ molecules /1 mol
1.81 × 10²³ molecules
b) 20g of HNO₃
Number of moles = mass/ molar mass
Number of moles = 20 g/ 63.01 g/mol
Number of moles = 0.32 mol
1 mol = 6.022 × 10²³ molecules
0.32 mol × 6.022 × 10²³ molecules /1 mol
1.93 × 10²³ molecules
c) 30g of C₆H₁₂O₆
Number of moles = mass/ molar mass
Number of moles = 20 g/ 180.156 g/mol
Number of moles = 0.11 mol
1 mol = 6.022 × 10²³ molecules
0.11 mol × 6.022 × 10²³ molecules /1 mol
0.66× 10²³ molecules
2. Calculate the number of ions in the following compounds:
a) 10g of AlCl₃
Number of moles = mass/ molar mass
Number of moles = 10g/ 133.34 g/mol
Number of moles = 0.075 mol
1 mol = 6.022 × 10²³ ions
0.075 mol × 6.022 × 10²³ ions/1 mol
0.45× 10²³ions
b) 30g of BaCl₂
Number of moles = mass/ molar mass
Number of moles = 30g/ 208.23 g/mol
Number of moles = 0.14 mol
1 mol = 6.022 × 10²³ ions
0.14 mol × 6.022 × 10²³ ions/1 mol
0.84× 10²³ions
c) 58 g of H2SO4
Number of moles = mass/ molar mass
Number of moles = 58g/ 98.079 g/mol
Number of moles = 0.59 mol
1 mol = 6.022 × 10²³ ions
0.59 mol × 6.022 × 10²³ ions/1 mol
3.6 × 10²³ions
Explanation:
Molecular weight and configurational stability of poly [(fluorophenyl) acetylene]s prepared with metathesis and insertion catalysts
A detailed article on formation of poly [(fluorophenyl) acetylene]s prepared with metathesis and insertion catalysts has been given below.
What is Molecular weight and configurational stability of poly [(fluorophenyl) acetylene]s?By polymerizing (2-fluorophenyl)acetylene, (3-fluorophenyl)acetylene, and (4-fluorophenyl)acetylene with catalysts [Rh(1,5-cyclooctadiene) OCH3]2, high-cis PFPhAs and tungsten(VI) oxychloride/tetraphenyltin, respectively, PFPhAs have been created.Size exclusion chromatography, 1H-NMR, and UV-vis methods were used to investigate the molecular weight and configurational stability of both PFPhAs series under varied circumstances at room temperature.The rate of degradation was independent of the F-position on the Ph ring for all samples while they were in the solid state and exposed to the environment. For high-cis polymers compared to their cis/trans counterparts, the rate of breakdown in the tetrahydrofuran solution increased by up to three orders of magnitude. In an aerated tetrahydrofuran solution, there was considerable cis-to-trans isomerization along with the degradation of high-cis PFPhAs.The F-position on the Ph ring showed the similar dependence on the rate of degradation and isomerization. It was proposed that cis-to-trans isomerization, which increases the amount of unpaired electrons on the main chains, hastened the degradation of high-cis PFPhAs in solution. The ortho-substituted isomers shown increased stability compared to the meta- and para-substituted isomers in both the high-cis and cis/trans series of polymers.To know more about isomerization visit: https://brainly.com/question/2226351
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25. Which is an irreversible process?
1) mixing of two gases by diffusion
2) Evaporation of water at 373k and 2atm
pressure
3) Dissolution of Nacl in water
4) All are correct
(S
The answer is 1) mixing of two gases by diffusion.
Once 2 gases are mixed by diffusion, they cannot be obtained from the mixture of gases. Hence, it is considered to be an irreversible process.
Will mark you brainliest and give you 15 points!!
what is the mass of 22.4 l of n2 at stp? (5 points)
a
11.2 grams
b
14.00 grams
c
22.4 grams
d
28.01 grams
Answer:
d
Explanation:
22.4 L is the same as 1 mol.
Diatomic nitrogen has a formula mass of 28.01 g/mol, so the answer is d.
A sample of food is put into a bomb calorimeter and its caloric content is measured. The final measurement reads 100 (large) Calories. How many joules of energy does this food contain
The amount of energy, in Joules, that the food contains will be 414.8 Joules
Calories to Joule conversionAccording to metrics, 1 kilocalorie = 4184 Joules.
100 Calories = 100/1000 = 0.1 kiloCalories.
0.1 kilocalories = 0.1 x 4184 = 414.8 Joules
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Why has nuclear fusion been difficult to develop?
A. Fuel for nuclear fusion is very rare.
B. Fusion normally occurs in the vacuum of space and the atmosphere on Earth stops the
reaction.
C. It is hard to recreate the extremely high temperatures and pressures found inside stars.
D. An efficient shape to contain the reaction has not been found.
Answer:
C. It is hard to recreate the extremely high temperatures and pressures found inside stars.
Explanation:
Nuclear fusion occurs when atomic nuclei are forcefully combined to create a new atomic nuclei or subatomic particles. In nature, this process takes place in our Sun and other stars. Within stars, extremely high temperatures and pressures are achieved and cause nuclear fusion to occur. Humans have not yet been successful in recreating the environment necessary to mimic this process.
Ammonia, NH3, undergoes reaction with oxygen to form nitrogen and water. When 7.00 x 1022 molecules of ammonia react with 6.00 x 1022 molecules of oxygen, what mass of nitrogen results (grams)
Amount of nitrogen produced = 1.624 g
To calculate the moles, we use the equation:
4NH3(g) + 3 O2 (g) ---> 2 N2 (g) + 6 H2O (g) ....(1)
For ammonia:
Putting values in above equation, we get:
Moles of ammonia = 7.00 x 1022 / 6.023 * 10 ^23 = 0.116 mol
Moles of oxygen = 6.00 x 1022 / 6.023 * 10 ^23 = 0.099 mol
For the reaction:
4NH3(g) + 3 O2 (g) ---> 2 N2 (g) + 6 H2O (g)
By Stoichiometry of the reaction,
4 moles of ammonia combine with 3 moles of Oxygen
Thus 0.116 moles of ammonia will combine with= 3/4 * 0.116 = 0.087 of oxygen
Thus ammonia is the limiting reagent as it limits the formation of product.
4 moles of ammonia produces 2 moles of nitrogen
0.132 moles of ammonia will produce=2/4 * 0.116 = 0.058 of nitrogen
Molar mass of nitrogen = 28 g/mol
Amount of nitrogen produced=
No of moles * molar mass = 0.058 * 282 = 1.624 g
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Which four items are changes in the hazard communication standard for chemical labels and sds?.
The four items that change in the hazard communication standard for chemical labels and SDS
Product identifier.Signal word.Hazard statement.Pictograms.Precautionary statement.This is further explained below.
What is the hazard communication standard?Generally, The Hazard Communication Standard (HCS) was developed to ensure that employees have the "right to know" about any possible dangers that may be related to the work that they do. The HCS is a preventative strategy that is meant to distribute information to employees and employers about the health dangers that are associated with the chemicals that they handle and the protection that is necessary.
In conclusion, Hazard communication labels and SDS product identifiers have undergone four changes as a result of the new standard. The term serves as a signal to the driver. There is a risk. Pictograms. Statement of caution.
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A
What type of reaction is illustrated?
C₂H4+302 → 2CO₂ + 2H₂O
combustion
decomposition
double
replacement
Answer:
A.) combustion
Explanation:
Combustion reactions are a specific type of redox reaction which always have the same general structure: CₓHᵧ + O₂ ---> H₂O + CO₂ + heat/light
Decomposition reactions are reactions which involve a molecule breaking down into smaller compounds/elements. They have the general structure: AB ---> A + B
Double replacement reactions are reactions in which the cation of one compound is swapped with the cation of another compound. They have the general structure: AB + CD ---> AD + CB
i need help with these two questions, i been stuck for 2 hours
1. The mass of Fe2O3 required will be 51.29 grams
2. The mass of Cu that will be formed is 36 kg
Stoichiometric problems1) The equation of the reaction goes thus: [tex]2Fe_2O_3 + 3Pt --- > 3PtO_2 + 4Fe[/tex]
Mole ratio of Fe to Fe2O3 = 2:1
Mole of 35.9 g Fe = 35.9/56 = 0.6411 mol
Equivalent mole of Fe2O3 = 0.6411/2 = 0.3205 mol
Mass of 0.3205 mol Fe2O3 = 0.3205 x 160 = 51.29 grams
2) [tex]2CuO --- > 2Cu + O_2[/tex]
Mole ratio of CuO to Cu = 1:1
Mole of 45 kg CuO = 45000/80 = 562.5 mol
Equivalent mole of Cy = 562.5 mol
Mass of 562.5 mol of Cu = 562.5 x 64 = 36,000 grams or 36 kg
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If a reaction occurs, what will be the products of the unbalanced reaction below?
Zn(s) + HCl(aq) -->
A. No reaction will occur
B. ZnH(s) + Cl2(g)
C. ZnCl2(s) + H2(g)
D. HZnCl(s)
Answer:
C) ZnCl2(s) + H2(g)
Explanation:
On reaction between Zn and HCl, Zn is more reactive than Hydrogen thus displacing it from HCl making a bond with two atoms of chlorine and releases hydrogen gas.
The equation of reaction
Zn(s) + HCl(aq) => ZnCl2(s) + H2(g).
Therefore, the required products are ZnCl2(aq) and H2(g).
Determine the molarity of a solution that contains 30 moles naoh in 0.80 liters of solution?
Taking into account the definition of molarity, the molarity of a solution that contains 30 moles naoh in 0.80 liters of solution is 37.5 [tex]\frac{moles}{liters}[/tex].
Definition of molarityMolar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
[tex]Molarity=\frac{number of moles}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liters}[/tex].
This caseIn this case, you have:
number of moles= 30 molesvolume= 0.80 LReplacing in the definition of molarity:
[tex]Molarity=\frac{30 moles }{0.80 L}[/tex]
Solving:
Molarity= 37.5 [tex]\frac{moles}{liters}[/tex]
Finally, the molarity of a solution that contains 30 moles naoh in 0.80 liters of solution is 37.5 [tex]\frac{moles}{liters}[/tex].
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What is the electron configuration for a calcium atom? 01s². 2s 2.2p5.3s 2.3p 5.4s¹ 02s², 2s ², 2p5.3s 2.3p 6,4s1 01s 2. 2s 2. 2p5.3s 2.3p 5, 452 Ots1,2s2, 2p5.3s 2.3p5,4s¹
Answer:
Ca = 1s²2s²2p⁶3s²3p⁶4s²
Explanation:
Calcium is located in the second column and the 4th row of the periodic table. Thus, there are 2 valence electrons and the highest quantum number is 4. This is represented by 4s². However, all of the previous orbitals and electrons must be listed beforehand, making the entire electron configuration: 1s²2s²2p⁶3s²3p⁶4s².
Which one of the following has little bearing on whether profitable opportunity exists to install additional new or refurbished production equipment in the upcoming decision round
The option that has little bearing on whether profitable opportunity exists is option c) How many companies in the industry have expanded their plant capacity since Year 10 because it is not detailed enough.
What is Decision Making:Decision making is known to be a term that connote the method or act that is based on making the right and best decision among the numbers of alternative available.
Note that It includes the act of classifying and knowing the best on the use of preference, belief, and others.
Therefore, the option that has little bearing on whether profitable opportunity exists is option c) How many companies in the industry have expanded their plant capacity since Year 10 because it is not detailed enough.
See full question below
Which one of the following has little bearing on whether profitable opportunity exists to build additional plant capacity in the upcoming decision round?
a) Whether data in the most recent FIR indicates that unsold inventories of branded footwear were so disturbingly high that many of these unsold pairs were cleared from company inventories at money-losing prices.
b) Whether the most recent year's FIR shows that ample production capacity already exists to supply the combined demand for branded footwear and private-label footwear three years from now.
c) How many companies in the industry have expanded their plant capacity since Year 10.
d) How potential global supply of footwear in the upcoming year compares with expected global demand
e) Whether the branded pairs available for sale in the most recent year (as reported in FIR)
exceeded global branded demand and, if so, by how much.
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What is the amount of space occupied by a sample of matter
The amount of space that matter occupies is called its volume. Solids, liquids, and gases all have volume.
Which equation agrees with the ideal gas law?
StartFraction V subscript 1 over T subscript 1 EndFraction equals StartFraction V subscript 2 over T subscript 2 EndFraction.
V subscript 1 n subscript 1 equals V subscript 2 n subscript 2.
P subscript 1 n subscript 1 equals P subscript 2 n subscript 2.
StartFraction P subscript 1 over P subscript 2 EndFraction equals StartFraction T subscript 2 over T subscript 1.
The equation for ideal gas law is written as PV = nRT.
What is Ideal gas law?Ideal gas law states that, the volume of a given amount of gas is directly proportional to the number on moles of gas, directly proportional to the temperature and inversely proportional to the pressure.
PV = nRT
where;
P is pressure of the gasV is volume of the gasn is number of molesR is ideal gas constantT is temperatureThus, the equation for ideal gas law is written as PV = nRT.
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What was the first expert system developed to determine the chemical structure of molecules?
Dendral was the first expert system developed to determine the chemical structure of molecules.
A molecule refers to a set of (2) or more atoms that are chemically bonded collectively, which allows you to form the smallest essential unit of a chemical compound. additionally, molecules are capable of taking elements in a chemical reaction.
A molecule is the smallest particle of a substance that has all of the physical and chemical houses. Molecules are made up of one or extra atoms. A molecule is a hard and speedy of or greater atoms held together via the use of a way of appealing forces called chemical bonds.
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Carbon-14 can be used to date remains as far back as ____________.
A. 60,000 years
B. the 1940's
C. 710 million years
D. 5700 years
A. Carbon-14 can be used to date remains as far back as 60,000 years.
What is carbon dating?Carbon dating is a method for determining the age of an object containing organic material by using the properties of radioactive isotope of carbon.
Carbon-14 dating can be used to estimate the age of carbon-bearing materials up to about 58,000 to 62,000 years old.
Thus, Carbon-14 can be used to date remains as far back as 60,000 years.
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A sample of gas has its number of molecules quadrupled, its Kelvin temperature doubled, and its volume tripled. By what factor has the new pressure changed relative to the original pressure
The new pressure changed relative to the original by a factor of 8/3.
What is the change in the pressure?Using the ideal gas equation;
PV = nRT
P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
P1 = nRT/V
P2 = 4n * R * 2T/3V
Hence;
P2/P1 = 4n * R * 2T/3V ÷ nRT/V
P2/P1 = 4n * R * 2T/3V * V/nRT
P2/P1 =4 * 2/3
= 8/3
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In what way did political policies act as a centrifugal force in the Soviet Union during the late 1980s
The government gave the people more freedom to criticize the government which led to nationalist movements
What way did political policies act as a centrifugal force in the Soviet Union during the late 1980s ?In the late 1980s, the economic and social situation in the Soviet Union was tense. The socialist economy was on the verge of collapse, the war in Afghanistan was an assured defeat, and the quality of life for Soviet citizens was appalling.
Due to these situations, the Soviet leader Mikhail Gorbachev decided to carry out a series of economic and political reforms, known as Perestroika and Glasnost, aimed at liberalizing the economy from a pure socialist model to a mixed model, and granting greater rights and civil liberties to the citizens.This led to numerous mobilizations and demonstrations, which further weakened the already weak Soviet political apparatus and made possible the emergence of regionalist nationalisms in the former Soviet nations, especially those subjugated to the power of Russia.Learn more about Soviet Union here:
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Show the calculations to determine the volume of the 0.1 M buffer from Part A needed to make 100 mL of a 0.01 M buffer.
The volume of the 0.1 M buffer from Part A needed to make 100 mL of a 0.01 M buffer is 10mL.
How to calculate volume?The volume of a substance can be calculated using the following formula;
C1V1 = C2V2
Where;
C1 = initial concentrationC2 = final concentrationV1 = initial volumeV2 = final volume0.1 × V1 = 100 × 0.01
0.1V1 = 1
V1 = 1/0.1
V1 = 10mL
Therefore, the volume of the 0.1 M buffer from Part A needed to make 100 mL of a 0.01 M buffer is 10mL.
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What mass of oxygen reacts during the incomplete combustion of 18.0 g of propane?
Answer:
45.82 gm O2
Explanation:
From your balanced equation in the first part, you can see that 2 moles propane need 7 moles O2
Find the number of moles of propane in 18 gm
mole wt of propane = ~ 12 * 3 + 8 *1 = 44 gm/mole
18 gm / 44 gm/mole = 9/22 gm/mole propane
we need 7/2 of this as O2 moles 7/2 * 9/22 = 1.432moles of O2
O2 mole weight =~ 32
1.432 moles * 32 gm/mole = 45.82 gm O2
How does the number of osmoles factor in when trying to calculate the molar mass of a substance?
To calculate the molar mass of substance, divide the number of moles by the given mass of substance.
The quantity of a substance is known as a mole. You can measure it in terms of grams, liters, atoms, molecules, or particles.
Use the substance's molar mass to convert between grams and moles. Divide the given mass by the number of moles to convert from moles to molar mass.
Using the formula, Number of moles = Given mass/ molar mass
The molar mass of a substance can be calculated as-
Molar mass = Given mass/number of moles
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Question 7 of 10
Carbonic anhydrase is an enzyme in the human body that participates in the
reaction shown below:
CO₂ + H₂O → H₂CO3
How will this reaction be affected if carbonic anhydrase acts as a catalyst?
OA. CO₂ and H₂O will be produced.
OB. H₂CO3 will be produced faster.
OC. H₂CO3 will be produced more slowly.
OD. H₂CO3 will not be produced at all.
SUBMIT
H₂CO₃ will be produced faster if carbonic anhydrase acts as a catalyst and the correct option is option B.
What is Carbonic Anhydrase?Carbonic anhydrase enzyme helps to maintain acid-base homeostasis, fluid balance and regulate pH. Based on its location, the enzyme role changes slightly.
The inter-conversion that occurs between water, carbon dioxide, and dissociated carbonic acid ions, is catalyzed by a group of enzymes that form by carbonic anhydrase, or carbonate dehydratase.
The active site for most carbonic anhydrase is supposed to be a zinc ion, and it is as a result classified as metalloenzymes.
Therefore, H₂CO₃ will be produced faster if carbonic anhydrase acts as a catalyst and the correct option is option B.
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The percentage composition of an organic acid is found to be 39.9% C, 6.7% H, and 53.4% O. The molar mass for the compound is 60.0g/mol. What is the molecular formula
Answer:
C₂H₄O₂
Explanation:
To find the molecular formula of the organic acid, you need to (1) determine the mass of each element (from the given percents), then (2) convert grams of each element to moles (via atomic masses), then (3) find the empirical formula, and then (4) find the molecular formula.
(Step 1)
39.9% C -----> 39.9 g C
6.7% H -----> 6.7 g H
53.4% O -----> 53.4 g O
(Step 2)
Atomic Mass (C): 12.011 g/mol
Atomic Mass (H): 1.008 g/mol
Atomic Mass (O): 15.988 g/mol
39.9 grams C 1 mole
---------------------- x ---------------------- = 3.32 moles C
12.011 grams
6.7 grams H 1 mole
-------------------- x --------------------- = 6.65 moles H
1.008 grams
53.4 grams O 1 mole
---------------------- x ---------------------- = 3.34 moles O
15.998 grams
(Step 3)
The empirical formula is made up of the lowest possible amount of each element in the molecule. These amounts can be found by dividing the molar value of each element by the smallest molar value. In this case, the smallest molar value is 3.32 moles C. The calculated values make up the subscripts in the empirical formula.
3.32 moles C / 3.32 = 1 mole C
6.65 moles H / 3.32 = 2 moles H
3.34 moles O / 3.32 = 1 mole O
Empirical Formula: CH₂O
(Step 4)
To find the molecular formula, you first need to determine the molar mass of the empirical formula. Once you have this value, you need to determine how much you need to scale the formula up by. In this case, the molar mass of the empirical formula is half of the molar mass of the molecular formula. Therefore, you need to multiply the amount of each element in the molecule by 2.
Molar Mass (CH₂O): 12.011 g/mol + 2(1.008 g/mol) + 15.998 g/mol
Molar Mass (CH₂O): 30.025 g/mol
30.025 g/mol x 2 = 60.05 g/mol
CH₂O x 2 = C₂H₄O₂
Lead(II) oxide from an ore can be reduced to elemental lead by heating in a furnace with carbon. Calculate the expected yield of lead if 50.0 kg of lead oxide is heated with 50.0 kg of carbon.
Find the expected yield of lead:
The expected yield of lead if 50.0 kg of lead oxide is heated with 50.0 kg of carbon is 46 kg
Calculation:
First and foremost, we must correctly write the equation of reaction in order to answer this issue. This is what it is:
PbO(s) + C(s) → Pb(l) + CO (g)
We continue from here. The limiting reactant should be found, however finding out how many moles of each reactant are present is the only way to do so.
The number of moles is calculated using the formula: the mass of each reactant divided by the molar mass of each reactant.
Mass of PbO is 50kg = 50000g
Molar mass of PBO = 223.20g/mol
The number of moles is thus 50000/223.2 = 224 moles
For carbon, mass is also 50kg = 50000g
Molar mass is 12g/mol
Number of moles of carbon = 50000/12 = 4166.6 moles
We can observe from the number of moles that there are more moles of carbon than PbO. This indicates that the limiting reagent is PbO.
So, in order to determine percentage yield, we employ it.
Since we have a mole ratio of 1 to 1, the number of moles of lead created is equal to the number of moles of lead oxide, which is 224.
The molar mass of lead = 207.20 g/mol
The mass of lead formed = moles of lead x molar mass of lead
The mass of lead formed = 207.20 x 224 = 46,412.8 g = 46 kg
Hence, the expected yield is 46 kg.
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