The measure of the second angle of a triangle is twice as large as the measure of the first measure of the third angle is 30° less than the sum of the measures of the other two angles find measure of each angle

Answer:

y = - 2x - 4

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, - 4) ← 2 points on the line

m = [tex]\frac{-4-0}{0-(-2)}[/tex] = [tex]\frac{-4}{0+2}[/tex] = [tex]\frac{-4}{2}[/tex] = - 2

the line crosses the y- axis at (0, - 4 ) ⇒ c = - 4

y = - 2x - 4 ← equation of line

The two-column proof that proves that ∠O ≅ ∠R using the SSS and CPCTC theorems is shown in the image attached below.

The side-side-side congruence theorem (SSS) states that when three sides of a triangle are congruent to the corresponding three sides of another triangle, then both triangles are considered congruent to each other.

The CPCTC theorem states that when two triangles are proven to be congruent by any triangle congruent theorem, then all the corresponding parts of the congruent triangle are congruent. This implies that the corresponding sides and angles of both triangle are equal or congruent.

We are asked to prove that ∠O ≅ ∠R.

With the given image, we would draw segment UP. Thus, based on the reflexive property, UP ≅ UP (one pair of congruent sides).

We are given two pairs of corresponding sides already, which are: UO ≅ UR and PO ≅ PR.

This means that triangles OUP and RUP have three pairs of corresponding congruent sides. Therefore, ΔOUP ≅ ΔRUP.

Applying the CPCTC theorem, ∠O ≅ ∠R.

The two-column proof is attached in the image below.

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The two sets of parametric equations for the rectangular equation are;

It follows from the task content that the parametric equations can be determined as follows;

By substituting the x= t+6 into the rectangular equation; we have;

y = (t+6-6)²-7(t+6)

y = t²-7t-42.

By substituting the x= 7t into the rectangular equation; we have;

y = (7t-6)² -7(7t)

y = 49t² - 84t +36 - 49t

y = 49t² - 133t +36.

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a. central angle is ∠QPR

b. semicircle is QRS

c. major arc is arc QTS

d. m∠QPR = 130° [central angle theorem]

e. arc QTS = 180°

The central angle theorem states that the measure of the intercepted arc will always be equal to the central angle.

a. A central angle is ∠QPR

b. A semicircle is QRS

c. A major arc is arc QTS

d. Measure of arc QR = m∠QPR = 130° [central angle theorem]

e. arc QTS = semicircle = 180°

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By definition of vectors exist as quantities that contain magnitude (positive or negative) and direction.

A) The unit vector in the direction of [tex]$F = i + \frac{3j}{2} +2k.[/tex]

B) The distance between [tex]F_{1}[/tex] and [tex]F_{2}[/tex] exists 2.

C) i.) Required vector = −4j − 5k

ii.) Required vector = 5i − 6j − 8k

To estimate the unit vector in the direction of V = 2i+3j+4k

|V| [tex]$= \sqrt{2^2+3^2+4^2}[/tex]

[tex]$= \sqrt{29}[/tex]

A) Unit vector

[tex]$F= \frac{V}{ |V|}[/tex]

[tex]$F= \frac{2i+3j +4k}{2}[/tex]

[tex]$F = \frac{2i}{2} + \frac{3j}{2} +\frac{4k}{2}[/tex]

[tex]$F= i + \frac{3j}{2} +2k.[/tex]

Therefore, unit vector in the direction of [tex]$F = i + \frac{3j}{2} +2k.[/tex]

B) To estimate the distance between [tex]F_{1}[/tex] = 3i+2j+ 5k and [tex]F_{2}[/tex] = 3i +4j +5k

[tex]$d = \sqrt{(3-3)^{2}+(4-2)^{2}+(5-5)^{2}}[/tex]

= 2

Therefore, the distance between [tex]F_{1}[/tex] and [tex]F_{2}[/tex] exists 2.

C) i.) P, (3,2,2), P₂(3,-2,-3)

Required vector =|[tex]P_{1}[/tex]P₂|=(3−3)i + ((−2)-2)j ​+ ((-3)-2)k

= −4j − 5k

ii.) P₂ (2,-3,-6), [tex]P_{3}[/tex] (-3,3,2) ​

Required vector =|P₂[tex]P_{3}[/tex]|=(-3-2)i + (3-(-3))j ​+ (2-(-6))k

= 5i − 6j − 8k

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The logarithmic function expresses the output variable, y, as a function of the logarithm of the input variable, x, as a function of a base b. The true statements are therefore;

The given logarithmic equation is presented as follows;

[tex]y = log_{b}(x) [/tex]

Therefore, we have;

[tex]x = {b}^{y} [/tex]

Where b = 1, we have that x will always be 1, therefore;

[tex]b = \sqrt[y]{x} [/tex]

Therefore;

Which gives;

The statements that are true is therefore;

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The expected value of the outcome of the bid is $0.18

So let's start by counting how many bids are placed up to a total of 160.

100*160 = 16000.

What will be your arbitrary bid? As each bid has an equal chance of success, the average of all bids is used. (One cent plus 160 dollars) / 2 = 80 dollars (rounded)

Your odds of winning are 1/16000 (1 bid out of 16000).

If you win, your profit is 1920 ($2000 minus $80.00).

1920/16000 is $0.12

Your cost to enter the auction is $1, and your average winning offer is $0.12.

The result is $0.18 (0.12-1=-0.88).

Thus the expected value of the outcome of the bid is $0.18

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Using the normal distribution, it is found that the cut-off time which 75.8% of the college students exceed when trying to find a parking spot in the library parking lot is of 3.7 minutes.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation are given as follows:

[tex]\mu = 4.5, \sigma = 1[/tex]

The cut-off time is the 100 - 75.8 = 24.2th percentile, which is X when Z = -0.7, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.7 = \frac{X - 4.5}{1}[/tex]

X - 4.5 = -0.7

X = 3.7.

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Work Shown:

m^2+9m=0

m(m+9)=0

m = 0 or m+9 = 0

m = 0 or m = -9

For more information, check out the topics about factoring and the zero product property.

The cubic function can be graphed using the function behavior and the points.

x   0    1     2        3      4

y   0  −4   −12   −18  −16

Put  x = 0.

Replace the variable x with 0 in the expression.

[tex]f(0)=(0)^3-5(0)^2[/tex]

Raising 0 to any positive power yields 0.

f(0) = 0 − 5⋅0

f(0) = 0

y = 0

Put x = 1.

Replace the variable x with 1 in the expression.

[tex]f(1)=(1)^3-5(1)^2[/tex]

f(1) = 1− 5⋅1

f(1) = −4

y = −4

Put x = 2.

Replace the variable x with 2 in the expression.

[tex]f(2)=(2)^3-5(2)^2[/tex]

[tex]f(2)=8-5(2)^2[/tex]

f(2) = 8 − 5⋅4

f(2) = −12

y = −12

Put x = 3.

Replace the variable x with 3 in the expression.

[tex]f(3)=(3)^3-5(3)^2[/tex]

f(3) = 27 − 45

f(3) = −18

y = −18

Put x = 4.

Replace the variable x with 4 in the expression.

[tex]f(4)=(4)^3-5(4)^2[/tex]

[tex]f(4)=64-5(4)^2[/tex]

f(4) = 64 − 5 ⋅16

f(4) = 64 − 80

f(4) = −16

y = −16

The cubic function can be graphed using the function behavior and the points.

x   0    1     2        3      4

y   0  −4   −12   −18  −16

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Answer:

Did you know that the first person convicted of speeding was going eight mph.

Step-by-step explanation:

Answer:

6 x 2 x 2 x 1

Step-by-step explanation:

6 x 2 = 12

12 x 2 = 24

24 x 1 = 24

Answer:

a. 13/26 = 1/2

b. 3/13

c. 2/26 = 1/13

Step-by-step explanation:

A. 26 red cards and 13 of them are hearts so 13/26 which can be simplified to 1/2

B. 13 hearts but only jack, queen king are higher than 10 so 3/13

C. 26 red cards altogether and we have a total of 2 red jacks so 2/26 which can be simplified to 1/13

is this what you wanted?

Answer:

2358.1

Step-by-step explanation:

2.3581 x 10^3

= 2.3581 x 10000

=2358.1

The previous tax rate was 20%

What is tax rate?

Tax rate is the percentage of the earnings tax payers would pay to the government from their earnings as taxes.

It should be borne in mind that the new tax rate is 25% which has increased by 25% compared to the previous tax rate, which is the unknown.

The mathematical relationship between the current and prior tax rates is as shown below:

Current tax rate=previous tax rate*(1+% increase in tax rate)

Current tax rate=25%

previous tax rate=X

% increase in tax rate=25%

25%=X*(1+25%)

25%=X*1.25

X=25%/1.25

X=previous tax rate=20%

Technically speaking, an increase of 25% in 20% is 5%(i.e. 20%*25%=5%), which when added to the original 20% would give a tax rate of 25%.That the shortcut to affirming that the new tax rate of 25% is correct

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Answer:

The solution for the above fraction is

[tex] \frac{146}{167} [/tex]

Step-by-step explanation:

Greetings!

look at the attachment above for the explanation.

Answer: 4766125

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Answer:

Step-by-step explanation:

first you we need to times 350,000 4.75 and you got 1662500 then subtract 1662500 - 13 years you got 1662487.

Answer:

An equilateral triangle with a length of 2

Step-by-step explanation:

A 2-by-2 square implies that the square has a length and width of 2. Since equilateral triangles have the same length for all sides, it tells you that if one side is a certain length, all the other sides must have the same length. The largest length we can fit into this square would be 2 because any larger, the sides of the triangles would not fit into the square. Under the assumption that the length needs to be a whole number, the answer would be 2.

Answer:Joey is 18 hope that helped you

Answer:

y= 4x -4

Step-by-step explanation:

Slope-intercept form is given by y= mx +c, where m is the slope and c is the y-intercept.

Given that the slope is 4, m= 4.

Substitute the value of the slope into the equation:

y= 4x +c

The value of c can be found by substituting any point in which the line passes through into the equation above.

When x= 4, y= 12,

12= 4(4) +c

12= 16 +c

Subtract 16 from both sides:

c= 12 -16

c= -4

Thus, the equation of the line is y= 4x -4.

Additional:

For more questions on slope-intercept form, do check out the following!

Answer:

C) 100

Step-by-step explanation:

250+600-350-400

850-350-400

500-400=100

The function y = -16x² + 48x + 64 is a non linear function with a parabolic shape graph.

An equation is an expression that shows the relationship between two or more numbers and variables.

A non linear function is a function whose graph is not linear or can be represented by a straight line.

The function y = -16x² + 48x + 64 is a non linear function with a parabolic shape graph.

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Answer:

Step-by-step explanation:

10yy'=x

[tex]10y\frac{dy}{dx} =x\\separating~the~variables\\10 ydy=xdx\\integrating\\\int 10ydy=\int xdx+c\\\frac{10y^2}{2} =\frac{x^2}{2} +c\\10y^2=x^2+2c\\when~x=10\\y=4\\10(4)^2=10^2+2c\\160=100+2c\\2c=160-100=60\\c=\frac{60}{2} =30\\10y^2=x^2+60\\10y^2-x^2=60[/tex]

The two statements that are true for g(x ) are:

g(x) = [tex]4^{x}[/tex] - 1

g(x) is translated both vertically and horizontally.

A function is a relation showing the relationship between two or more variables.

A function produces a unique output when a unique input is given to it. The input is called the domain and the output is called the Range.

Analysis:

If we use the values of x as 0,1,2,3

for x = 0

g(0) = [tex]4^{0}[/tex] -1  = 1 -1 = 0

for x = 1

g(1) = [tex]4^{1}[/tex] -1  = 4 - 1 = 3

for x = 2

g(2) = [tex]4^{2}[/tex] - 1 = 16 - 1 = 15

for x = 3

g(3) = [tex]4^{3}[/tex] - 1 = 64 - 1 = 63

Therefore g(x) = [tex]4^{x}[/tex] - 1

Also since the values of g(x) changes along the y - axis and x-axis also changes, therefore, g(x) is translated along both axes.

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The terms that completes the sentence are zeros; vertical. Option A

The functions of a sign chart include;

From the mentioned functions, we can se that the terms that completes the sentence are zeros and vertical asymptotes.

Thus, the terms that completes the sentence are zeros; vertical. Option A

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When x = -2, we use the second part of the function, so g(-2)=0.

Similarly, g(4) = -4.

Answer:

==============

We know each interior angle of an equilateral triangle is 60°, since each of three angles are of same value.

The middle triangle with two interior angles 4x and y has the missing angle also y, since it is isosceles, because both adjacent angles are equal at vertex N.

First

Measure of any angle in an equilateral triangle is 60°

So

And

Apply angle sum property

Answer:

10

9

0

Step-by-step explanation:

you subtract the number of all your answers

[tex]a {}^{2} + ab - 2 {b}^{2} [/tex]

[tex] = (a - b) {}^{2} [/tex]

The solution of x in the given expression [tex]\mathbf{\sqrt{(3x-8)}+1 = \sqrt{(x+5)}}[/tex] is 4. However, if it is [tex]\mathbf{\sqrt{(3x-8)+1} = \sqrt{(x+5)}}[/tex], it is 6.

The solution to the given algebra expression involving surds can be seen in the steps below.

Given that:

[tex]\mathbf{\sqrt{(3x-8)}+1 = \sqrt{(x+5)}}[/tex]

Remove the square roots, we have:

12x - 32 = 4x² - 48x + 144

Solving the quadratic equation at the RHS and equating it to LHS, we have:

x = 11, x = 4

Verifying the solutions by replacing the value of x with the given equation:

Therefore, we can conclude that the value of x = 4

NOTE:

Given that:

[tex]\mathbf{\sqrt{(3x-8+1)} = \sqrt{(x+5)}}[/tex]

Square both sides

3x - 7 = x +5

Solve for x

3x - x = 5 + 7

2x = 12

x = 6

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