The midpoint of \overline{\text{AB}}AB is M(-6, -4)M(−6,−4). If the coordinates of AA are (-4, -3)(−4,−3), what are the coordinates of BB?​

Answers

Answer 1

Answer:

The coordinates of B is (-8,-5).

Step-by-step explanation:

The midpoint of line AB is M. The coordinate of M is (-6,-4).

The coordinates of A is (-4,-3)

We need to find the mid point of B.

If M(x,y) is the midpoint of the coordinates (x₁,y₁) and (x₂,y₂). The mid point theorem is used as follows :

[tex]M(x,y)=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})[/tex]

Let the mid point of B is (x₂,y₂). Put (x,y) = (-6,-4), (x₁,y₁) = (-4,-3).

[tex](-6,-4)=(\dfrac{-4+x_2}{2},\dfrac{-3+y_2}{2})\\\\\dfrac{-4+x_2}{2}=-6\ \text{and}\ \dfrac{-3+y_2}{2}=-4\\\\-4+x_2=-12\ \text{and}\ -3+y_2=-8\\\\x_2=-12+4\ \text{and}\ y_2=-8+3\\\\x_2=-8\ \text{and}\ y_2=-5[/tex]

So, the coordinates of B is (-8,-5).

Answer 2

The coordinates of B are (-8, -5).

Given that,

The midpoint of AB is M(-6, -4). If the coordinates of A is (4,-2),

We have to determine,

The coordinates of B.

According to the question,

The midpoint of line AB is M. The coordinate of M is (-6,-4).

And the coordinates of A is (-4,-3)

If M(x, y) is the midpoint of the coordinates (x₁, y₁) and (x₂, y₂). The midpoint theorem is used as follows :

[tex]M(x, y) = ( \dfrac{x_1+x_2}{2}, \dfrac{y_1+y_2}{2})[/tex]

Let the midpoint of B be (x₂, y₂).

M (x, y) = (-6,-4), and (x₁, y₁) = (-4,-3).

[tex]M(-6, -4) = ( \dfrac{-4+x_2}{2}, \dfrac{-3+y_2}{2})\\\\[/tex]

Solving the equation for the co-ordinate B.

[tex]\dfrac{-4+x_2}{2} = -6\\\\-4 + x_2 = -6 \times 2\\\\-4 + x_2 = -12\\\\x_2 = -12+4\\\\x_2 = -8[/tex]

And,

[tex]\dfrac{-3+y_2}{2} = -4\\\\-3 + y_2 = -4 \times 2\\\\-3 + y_2 = -8\\\\y_2 = -8 + 3\\\\y_2 = -5[/tex]

Hence, The required coordinates of B are (-8, -5).

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answers

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Step-by-step explanation:

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Answers

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Answers

Answer:

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Answer:

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Step-by-step explanation:

Answer:

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