The molar mass of silicon (Si) is 28.09 g/mol. Calculate the number of atoms in a 92.8 mg sample of Si.

Answers

Answer 1

Explanation:

one mole of any substance there are 6.022×1023 units of that substance. (This number is called Avogadro's number, NA.)

We need to convert the mass of silicon to moles using the molar mass of silicon, 28.06gmol. This number means that one mole of pure silicon would have a mass of 28.06g. Our given mass, however, is in milligrams; to convert this to grams we'll use the conversion factor 1g103mg:

5.86mg Si(1g103mg)=0.00586g Si

Now, using silicon's molar mass, we'll convert this mass to moles of Si:

0.00586g Si(1mol Si28.06g Si)=2.09×10−4mol Si

Finally, let's use Avogadro's number to convert

Answer 2

The number of atoms in a 92.8 mg sample of Si is 1.99×10²¹ atoms

From Avogadro's hypothesis, we understood that:

1 mole of Si = 6.02×10²³ atoms

Recall,

1 mole of Si = 28.09 g

Now, we shall convert 28.09 g to mg. This can be obtained as follow:

1 g = 1000 mg

Therefore,

28.09 g = 28.09 × 1000

28.09 g = 28090 mg

Thus, 28.09 g is equivalent to 28090 mg

Therefore,

28090 mg of Si = 6.02×10²³ atoms

Finally, we shall determine the number of atoms in 92.8 mg sample of Si. This can be obtained as follow:

28090 mg of Si = 6.02×10²³ atoms

Therefore,

92.8 mg of Si = [tex]\frac{92.8 * 6.02*10^{23}}{28090}\\[/tex]

92.8 mg of Si = 1.99×10²¹ atoms

Thus, 92.8 mg sample of Si contains 1.99×10²¹ atoms

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Answers

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Answers

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Answers

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Answers

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