The neck of a gifaffe is 4 1/2 feet in length. Its neck is 30 perocent of it height whats the higet of the giffae

The three positive numbers whose sum is 270 and whose product is a maximum is 67.5, 135, 67.5.

Let x, y, and z be the three positive numbers.

Write an equation relating x, y, and z based on the given constraint: x + y + z = 270.

Use algebra to solve for one of the variables in terms of the others.

Solving for z in terms of x and y: z = 270 - x - y.

Substitute the expression for z into the equation for the product of the three numbers:

P = x * y * z = x * y * (270 - x - y).

Expand the expression for P and simplify as P = 270xy - x²y - xy².

Using calculus to find the critical points of P, which occur when the derivative of P with respect to x is zero:

dP/dx = 270y - 2xy - y²= 0.

Solving for x in terms of y: x = (270y - y²)/(2y).

Simplify the expression for x as x = 135 - (y/2).

Since x and y must be positive, we know that 0 < y < 270/2 = 135.

Therefore, we can choose y = 135.

Using the equation for x in terms of y, we can find x as x = 135/2 = 67.5.

Using the constraint x + y + z = 270, we can find z as z = 67.5.

 Check that x, y, and z are positive and that they add up to 270.

Therefore, the three positive numbers whose sum is 270 and whose product is a maximum are 67.5, 135, and 67.5.

The product of these three numbers is (67.5) * (135) * (67.5) = 614062.5.

So the maximum product is 614062.5.

Thus, the answer is: 67.5, 135, 67.5.

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When the minimum volume of a clown is 60,000 cm³ and the volume of a car is 3 million cm³, 55 is an upper bound on the maximum number of clowns that can fit in a car. The correct answer is Option A.

Bounds are the maximum and minimum limits that are permitted, within which something can or must be performed. Bounds are used to refer to an acceptable range of values that provide safe operation or performance. In mathematics, a set of bounds can define the limits of the amount of things or objects.

The minimum volume of a clown is 60,000 cm³, so to fit 55 clowns in a car we need:

55 clowns × 60,000 cm³/clown = 3,300,000 cm³

This is lower than the volume of the car. Therefore, 55 is an upper bound on the maximum number of clowns that can fit in the car.

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The approximate labor cost increase in percentage is approximately 21%, which is closest to option D.

To calculate the approximate labor cost increase in percentage, we can use the following formula:

Labor cost increase percentage = ((new labor cost - old labor cost) / old labor cost) x 100%

Plugging in the given values, we get:

Labor cost increase percentage = ((53,000 - 44,000) / 44,000) x 100%

Labor cost increase percentage = (9,000 / 44,000) x 100%

Labor cost increase percentage = 0.2045 x 100%

Labor cost increase percentage ≈ 20.45%

Therefore, the approximate labor cost increase in percentage is approximately 21%, which is closest to option D.

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Answer:

The correct order to draw 65 agle would be:

C

A

B

D

the lowest amount of precipitation occurred in February, with a value of approximately 2.32 inches.

Why it is and how to form a graph?

To find the month with the lowest amount of precipitation, we need to find the minimum value of the quadratic equation y = –0.04088x²2 + 0.4485x + 1.862.

Using calculus, we can find the minimum point of the quadratic function by taking its derivative and setting it equal to zero:

y' = -0.08176x + 0.4485

0 = -0.08176x + 0.4485

x = 5.484

This means that the minimum value of the function occurs at x = 5.484. Since x represents the month number (with January being 1), we can conclude that the month with the lowest amount of precipitation is February (the second month in the table).

To verify this, we can plug in x = 2 into the quadratic equation:

y = –0.04088(2)²2 + 0.4485(2) + 1.862

y = 2.31752

Therefore, the lowest amount of precipitation occurred in February, with a value of approximately 2.32 inches.

To graph the function, we can plot the points given in the table and connect them with a smooth curve. Here is a completed table with the missing values:

Month (x) Precipitation

January 1 2.27 inches

February 2 2.32 inches

March 3 2.57 inches

April 4 2.94 inches

May 5 3.43 inches

June 6 3.94 inches

July 7 2.72 inches

August 8 2.86 inches

September 9 2.59 inches

October 10 2.03 inches

November 11 1.46 inches

December 12 1.03 inches

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Answer:

D: December

The given model for precipitation in Phoenix, Arizona is y = –0.04088x2 + 0.4485x + 1.862, where x is the month number (1 for January, 2 for February, and so on) and y is the precipitation in inches. We can use this model to fill in the missing values in the table:

| Month (x) | Precipitation |

|-----------|---------------|

| January   | 2.27 inches   |

| February  | 2.27 inches   |

| March     | 2.24 inches   |

| April     | 2.18 inches   |

| May       | 2.09 inches   |

| June      | 1.98 inches   |

| July      | 1.84 inches   |

| August    | 1.68 inches   |

| September | 2.59 inches   |

| October   | 1.50 inches   |

| November  | 1.30 inches   |

| December  | 1.08 inches   |

According to the table, Phoenix received the lowest amount of precipitation in **December** with **1.08 inches** of precipitation, so the correct answer is **D. December**.

Answer:

Let's call the cost of a blouse "b" (in dollars). Then, according to the problem, the cost of a dress is 3/4 of the cost of a blouse, or (3/4)b.

We know that Vicky paid $350 for 3 dresses and 4 blouses, so we can set up the equation:

3(3/4)b + 4b = 350

Simplifying this equation, we get:

9/4 b + 4b = 350

Combining like terms, we get:

17/4 b = 350

To solve for b, we can multiply both sides by 4/17:

b = 350 × 4/17 = $82.35 (rounded to two decimal places)

Therefore, the cost of a dress is:

(3/4)b = (3/4)($82.35) = $61.76 (rounded to two decimal places)

So each dress cost $61.76.

Measurement scales refer to the various methods of assigning scores to measurements according to their precision and accuracy. There are four primary scales of measurement; nominal, ordinal, interval, and ratio.

The four measurement scales and their definitions are listed below:

Nominal scale: This is the lowest level of measurement. It is used to name, classify, or identify objects, events, or groups. It has no logical order, and its units cannot be compared or arranged in a sequence.

Examples of the nominal scale include; gender (male or female), marital status (single or married), color (black or white), and so on.

Ordinal scale: This scale includes a more elaborate classification than nominal measurement. It distinguishes between levels of preference or priority, but it does not have a constant distance between the levels.

Examples of the ordinal scale include; rankings (first, second, third, and so on), level of satisfaction (very happy, happy, neutral, unhappy, very unhappy), and so on.

Interval scale: This scale has a constant distance between its units, and its elements can be compared or arranged in a sequence. It does not have a true zero.

Examples of the interval scale include; temperature (measured in Fahrenheit or Celsius), time (measured in seconds, minutes, or hours), and so on.

Ratio scale: This is the highest level of measurement, where it has a constant distance between its units, its elements can be compared or arranged in a sequence, and it has a true zero.

Examples of the ratio scale include; weight, length, height, and so on. Measures of central tendency include; mean, median, and mode. The mean is the average of all the data points in a set, the median is the middle value in a set of data, and the mode is the value that occurs most often. The table below provides an example of each measurement scale and the appropriate measures of central tendency for each. Scales of Measurement Examples Measures of Central Tendency Nominal Scale Gender Mean Ordinal Scale Ranking Median Interval Scale Temperature Mean Ratio Scale Height Mode.

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Answer:

x = 9

Step-by-step explanation:

[tex]2x + 3 = 3x - 6[/tex]

[tex]3 = x - 6[/tex]

[tex]x = 9[/tex]

The probability that among 12 randomly selected flights, exactly 10 arrive on time is 0.1667

The probability that, among 12 randomly selected flights, exactly 10 arrive on time is 0.1667. This is calculated by using the binomial probability formula:

[tex]P(x) = nCx (p^x) (1-p)^{(n-x)}[/tex]

Where:

[tex]P(x) = 12C10 (0.815^{10}) (0.185)^2 = 0.1667[/tex]

The probability that among 12 randomly selected flights, exactly 10 arrive on time is 0.1667

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The probability of drawing 4 balls at random, without replacement, that include each of the three colors is 0.0061.

The bowl contains 12 balls6 of the balls are blue2 of the balls are white 4 of the balls are red

Sample space = [tex]n(S) = ^{12}C_4=\frac{12!}{4! (12 - 4)!} = 495[/tex]

The formula for conditional probability is:

P(A ∩ B) = P(A) × [tex]P(\frac{B}{A})[/tex]

P(A ∩ B) is the probability that both A and B occur

P(A) is the probability of event A occurring

[tex]P(\frac{B}{A})[/tex] is the probability of event B occurring given that A has occurred

The probability of drawing 4 balls at random that include each of the three colors can be calculated as follows:

First, we calculate the probability of drawing one ball of each color

P (Drawing one ball of each color) = [tex]\frac{(^6C_1^2C_1^4C_1)}{^{12}C_3} = \frac{(6X2X4)}{220} = 0.0545[/tex]

Next, we calculate the probability of drawing a fourth ball of any color

P (Drawing a fourth ball of any color) = [tex]\frac{^9C_1}{^9C_1} = 1[/tex]

Finally, we use the formula for conditional probability to find the probability of drawing 4 balls at random that include each of the three colors

P (Drawing 4 balls at random that include each of the three colors) = P (Drawing one ball of each color) × P (Drawing a fourth ball of any color | Drawing one ball of each color) = [tex](0.0545)\frac{1}{9}= 0.0061[/tex]

The probability of drawing 4 balls at random, without replacement, that include each of the three colors is 0.0061.

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The approximate number of miles for a warranty is 41,748.57 miles.

Standard deviation refers to the distribution's extent of variability or dispersion. It is a measure of how much the data varies from the mean. It is represented by the Greek letter sigma (σ) and is used to calculate the data variability. It is the square root of the variance of a random variable that describes how widely the data points differ from the average value.

We have, Mean (μ) = 47,500 miles

Standard deviation (σ) = 3,000 miles

Manufacturer replacement threshold = 10% = 0.1

The number of miles for a warranty would have to be determined if the tire company wanted to replace no more than 10% of the tires.

Suppose x is the number of miles for which a warranty can be offered.

Using the standard normal distribution, we may compute the z-score as follows:

z = (x - μ) / σ

At the 10th percentile of the standard normal distribution, we'll find the z-score. This z-score can be found using the standard normal distribution table or software.

At the 10th percentile, the z-score is -1.28 (from the table).

Now, substitute the given values.

z = (x - μ) / σ

-1.28 = (x - 47,500) / 3,000

Cross-multiplying and solving for x gives us:

x = -1.28 × 3,000 + 47,500x ⇒ 43,660 miles

Therefore, the tire company should offer a warranty for around 43,660 miles (approximated).

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The calculation for the price of 10 books is as follows: 10 × (19.60/88) = 2.21

We can use a proportion to determine the cost of 10 books based on the cost of 88 books:

88 books cost $19.60

1 book costs 19.60/88 dollars

Now we can use this information to find the cost of 10 books:

10 books cost 10 × (19.60/88) dollars

Simplifying the expression on the right side, we get:

10 books cost $2.21

Therefore, the equation that would help determine the cost of 10 books is: 10 × (19.60/88) = 2.21 The cost of books is often calculated based on the number of books purchased and the price per book. In this problem, we are given the cost of 88 books, and we need to find the cost of 10 books. Using a proportion, we can find the cost of 1 book and then multiply it by 10 to find the cost of 10 books. This method is useful for determining the cost of any number of books, given the cost of a different number of books. Book prices can vary widely depending on factors such as the format, edition, and publisher, so it is important to carefully consider book prices when making purchases.

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Answer:

5) 12.2       6) 2

Step-by-step explanation:

Use Pythagoras for both

Rearrange for x in question 6

a. Hence proved that the sum of fractions  [tex]${\frac{1}{\sqrt{1+\sqrt{2}}}}+{\frac{1}{\sqrt{2+\sqrt{3}}}}+{\frac{1}{\sqrt{3}+\sqrt{4}}}=1$[/tex]

b. The value will be 7 for the expression

⇒ [tex]${\frac{ 1-\sqrt{2}}{-1}+{\frac{ \sqrt{2}-\sqrt{3}}{-1}+ \cdot \cdot \cdot+{\frac{\sqrt{63}-8}{-1}}$[/tex]

Square rοοt οf a number is a value, which οn multiplicatiοn by itself, gives the οriginal number. The square rοοt is an inverse methοd οf squaring a number. Hence, squares and square rοοts are related cοncepts.

Suppοse x is the square rοοt οf y, then it is represented as x=√y, οr we can express the same equatiοn as x² = y. Here, ‘√’ is the radical symbοl used tο represent the rοοt οf numbers. The pοsitive number, when multiplied by itself, represents the square οf the number. The square rοοt οf the square οf a pοsitive number gives the οriginal number.

Here,

a. [tex]${\frac{1}{\sqrt{1+\sqrt{2}}}}+{\frac{1}{\sqrt{2+\sqrt{3}}}}+{\frac{1}{\sqrt{3}+\sqrt{4}}}=1$[/tex]

Using (a + b)(a - b) = a² - b²

⇒ [tex]${\frac{1 \cdot \sqrt{1}-\sqrt{2}}{\sqrt{1}+\sqrt{2}\cdot \sqrt{1 }-\sqrt{2}}+{\frac{1 \cdot \sqrt{2}-\sqrt{3}}{\sqrt{2}+\sqrt{3}\cdot \sqrt{1}-\sqrt{2}}}+{\frac{1 \cdot \sqrt{3}-\sqrt{4}}{\sqrt{3}+\sqrt{4}\cdot \sqrt{3}-\sqrt{4}}}$[/tex]

⇒ [tex]${\frac{ \sqrt{1}-\sqrt{2}}{1-2}+{\frac{ \sqrt{2}-\sqrt{3}}{2-3}+{\frac{\sqrt{3}-\sqrt{4}}{3-4}}$[/tex]

⇒ [tex]${\frac{ \sqrt{1}-\sqrt{2}}{-1}+{\frac{ \sqrt{2}-\sqrt{3}}{-1}+{\frac{\sqrt{3}-\sqrt{4}}{-1}}$[/tex]

⇒ [tex]${\frac{ 1-\sqrt{2}}{-1}+{\frac{ \sqrt{2}-\sqrt{3}}{-1}+{\frac{\sqrt{3}-2}{-1}}$[/tex]

⇒ [tex]${\frac{ 1-\sqrt{2}}{-1}+{\frac{ \sqrt{2}-\sqrt{3}}{-1}+{\frac{\sqrt{3}-2}{-1}}$[/tex]

⇒ [tex]$ -1+\sqrt{2}}- \sqrt{2}+\sqrt{3}}-{\sqrt{3}+2}$[/tex]

⇒ [tex]$ -1+2}$[/tex]

⇒ 1

a. Hence proved that the sum of fractions  [tex]${\frac{1}{\sqrt{1+\sqrt{2}}}}+{\frac{1}{\sqrt{2+\sqrt{3}}}}+{\frac{1}{\sqrt{3}+\sqrt{4}}}=1$[/tex]

B. This will be done with the same process,

⇒ [tex]${\frac{ 1-\sqrt{2}}{-1}+{\frac{ \sqrt{2}-\sqrt{3}}{-1}+ \cdot \cdot \cdot+{\frac{\sqrt{63}-8}{-1}}$[/tex]

⇒ [tex]${\frac{ 1-\sqrt{2}}{-1}+{\frac{ \sqrt{2}-\sqrt{3}}{-1}+ \cdot \cdot \cdot+{\frac{\sqrt{63}-8}{-1}}$[/tex]

⇒ [tex]$ -1+\sqrt{2}}- \sqrt{2}+\sqrt{3}} \cdot \cdot \cdot -{\sqrt{63}+8}$[/tex]

There, will be same roots of every number until - 8

So,

⇒ [tex]$ -1+8}$[/tex]

= 7

b. The value will be 7 for the expression

⇒ [tex]${\frac{ 1-\sqrt{2}}{-1}+{\frac{ \sqrt{2}-\sqrt{3}}{-1}+ \cdot \cdot \cdot+{\frac{\sqrt{63}-8}{-1}}$[/tex]

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Answer:

180

Step-by-step explanation:

Form an equation

27x+17=180

Solve it for x  

x = 6.0recurring

the perimeter is 180

Let me know if it helps

We need to add 10 students to the hostel so that the food is enough for only 45 days.

Let's assume that "x" students need to be added to the hostel so that the food is enough for only 45 days.

We know that the total amount of food available is fixed, so the product of the number of students and the number of days that the food will last must also be fixed.

We can use this fact to set up an equation:

50 × 54 = (50 + x) × 45

To solve for x, we can simplify and solve for x:

Expand using FOIL method

50 × 54 = (50 + x)45

50 × 54 = 45 × 50 + 45 × x

2700 = 2250 + 45x

450 = 45x

x = 10

Therefore, number of students to be added is 10.

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Answer:

y = 12

Step-by-step explanation:

if a tangent and a secant are drawn from an external point to a circle, then the square of the measure of the tangent is equal to the product of the measures of the secant's external part and the entire secant , that is

y² = 8(8 + 6 + 4) = 8 × 18 = 144 ( take square root of both sides )

y = [tex]\sqrt{144}[/tex] = 12

Then we will get the following odds

a.  None will have high blood pressure. Let the probability of having high blood pressure be denoted by P(A) and the probability of not having high blood pressure be denoted by P(A'). Since none will have high blood pressure, it means all the sixteen Americans selected are healthy, and therefore P(A') = 1. Therefore

P(A) = 1 - P(A')= 1 - 1= 0

b. One-half will have high blood pressure. The probability that one-half of the sixteen Americans will have high blood pressure can be found using the binomial distribution formula that is given by the expression

[tex]P(X = r) = (nCr) * p^r * q^{(n-r)}[/tex]

Where

Therefore

[tex]P(X = 8) = (16C8) * 0.2^8 * 0.8^8= 0.202[/tex]

c. Exactly 4 will have high blood pressure Similarly, the probability that exactly four of the sixteen Americans will have high blood pressure can be found using the binomial distribution formula as follows:

[tex]P(X = r) = (nCr) * p^r * q^{(n-r})[/tex]

Where

Therefore

[tex]P(X = 4) = (16C4) * 0.2^4 * 0.8^{12}= 0.236[/tex]

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Therefore, 15% of the beads on Tiana's necklace are blue.

Percentage is a way of expressing a fraction or a proportion out of 100. It is denoted by the symbol "%". For example, if we say that 50% of the students in a class are girls, it means that 50 out of every 100 students are girls.

Percentage can be calculated by dividing the given quantity by the total and multiplying by 100. For example, if there are 20 girls out of a total of 40 students in a class, the percentage of girls in the class can be calculated as follows:

Percentage of girls = (number of girls / total number of students) x 100%

= (20 / 40) x 100%

= 50%

by the question.

Tiana's necklace has a total of 3 + 17 = 20 beads.

To find the percentage of blue beads, we need to divide the number of blue beads by the total number of beads and then multiply by 100 to get the percentage:

percentage of blue beads = (number of blue beads / total number of beads) x 100

percentage of blue beads = (3 / 20) x 100

percentage of blue beads = 15

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The formula for the total number of factors for a given number is given by; Total Number of Factors for N = (a+1) (b+1) (c+1)

From the following three options for running the appropriate t-test, Both Options (2) and (3) could be applicable depending on the specific research question being investigated.

The appropriate t-test to use in this scenario is paired t-test. This test compares before and after values for one type using excel. In this scenario, you would be comparing either the altimeter error of ACME or brand x before adjustment and calibration and after adjustment and calibration to see if there are any differences in the means (performance).

Based on the scenario described, Option 1 is not appropriate because there is no hypothesized population mean to compare against. Therefore, we can exclude this option.

Option 2, comparing one brand against another, could be appropriate if we want to investigate if there are any significant differences in altimeter error between brands. This would be a two-sample t-test.

Option 3, comparing the altimeter error of one brand before and after calibration, could also be appropriate to see if the adjustment and calibration had a significant impact on the altimeter's performance. This would be a paired t-test.

This test is the appropriate test to use because the dependent variable data in this scenario is the ratio and the type of question requires a paired t-test. In this scenario, you are comparing the performance of the two brands before and after adjustment and calibration, which requires paired t-test to answer the research question.

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The bank statement shows a loss of 70 euros, considering the profit concept.

From the table presented in this problem, the parameters are given as follows:

To calculate profit considering money in and money out, you need to subtract the total money out from the total money in.

Hence the formula for calculating profit is given as follows:

Profit = Money In - Money Out

The total money in is given as follows:

Money In = 360 + 295 + 415 = 1070.

The total money out is given as follows:

Money Out = 520 + 70 + 400 + 150 = 1140.

Hence the profit is given as follows:

Profit = Money In - Money Out

Profit = 1070 - 1140

Profit = -70 (negative profit means that it is a loss).

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(a) The horizontal velocity of the dart remains constant throughout its motion, so it will take 0.24 seconds to reach the target (since distance = speed × time)  and the dart will fall a distance of 0.28 m

During this time, the dart will also be accelerating downwards due to gravity at a rate of 9.81 m/s². The vertical distance fallen can be calculated using the formula: distance = ½ × acceleration × time². Thus, the dart will fall a distance of:

distance = ½ × 9.81 m/s² × (0.24 s)² ≈ 0.28 m

Therefore, the dart will hit the board 0.28 meters below the intended target.

(b) This calculation suggests that even highly skilled dart players may not hit the bull's-eye every time, due to the influence of gravity on the dart's trajectory.

However, skilled players can adjust their aim and release the dart with the correct velocity and angle to hit their target consistently. They may also use techniques such as "aiming high" to compensate for the effect of gravity. Overall, this calculation highlights the importance of understanding the physics of projectile motion in the sport of darts.

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Answer:

5x³ = 40

20x^6/4x² = 80

100 is not equal to 80

Step-by-step explanation:

5x³ = 5*2^3

      = 40

20x^6/4x² = 20*2^6/4*2^2

                 = 20*64/16

                 = 80

Answer:

Multiplying the second equation by 5, we get:

15x + 20y = 180

Now, we can add this equation to the first equation:

26x = 208

x = 8

Substituting x = 8 in the second equation:

3(8) + 4y = 36

4y = 12

y = 3

Therefore, the solution to the system is (8, 3).

As a result, the percentage of adults who selected math is different from the percentage of kids who did.

As a number out of 100, a percentage is a method to express a proportion or a fraction. It is symbolized by the number %. If there are 25 boys in a class of 100 pupils, for instance, then there are 25% of boys in the class. It is a helpful method to compare quantities and to express changes in values over time.

given

120 80

Total    200

Women Overall Party A Party B

70 60

Overall    130

Therefore, there are 130 ladies in the group.

b) The chart indicates that 70 women plan to support Party A.

Thus, the percentage of adults who selected English was 40% of 48, which is equal to 0.4 times 48 and 19.2 when rounded to the closest whole number.

b) Reeshma is not accurate. The percentage of adults who selected math is 35%, while for children it is 40%, according to the pie chart.

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The complete question is:-   complete the two-way table, which shows the voting intentions of a group of men and women. a How many women are in the group?

Men

Party A Party B 120

Total    200

Women   130

Total       380

b How many women intend to vote for Party A?

2 A group of 48 adults are asked what their favourite subject was at school. They can choose from

maths, English and science.

A group of 32 school children are asked the

same question.