Answer:
d.81
Step-by-step explanation:
81 can be represented by a 9x9 square grid. The rest of the numbers would be represented on rectangular grids.
Answer:
D. 81
Step-by-step explanation:
81 can be represented by 9X9 square grid
9^2 = 81
Sammy’s dad drove their car 150 miles in three hours. At this rate, how far would he drive in nine hours?
Answer:
distance in 3 hours = 150 miles
distance in 1 hour = 150/3 = 50 miles
distance in 9 hours = 50 × 9 = 450 miles
Answer:
Sammy's dad traveled 450 miles in 9 hours.
Step-by-step explanation:
mph = [tex]\frac{Miles}{Hours}[/tex]
Miles = 150
Hours = 3
Plug into the formula of distance/time
[tex]\frac{150}{3} = 50mph[/tex]
Sammy's dad is driving at 50mph
In three hours you can use this formula: [tex]50mph=\frac{miles}{9}[/tex]
Multiply both sides by 9: [tex]50mph * 9 =\frac{miles}{9} *9[/tex]
Solve:
[tex]50mph * 9 =miles[/tex]
[tex]450 =miles[/tex]
Sammy's dad traveled 450 miles in 9 hours.
Hope this helped! :)
Find the distance between the two points
☟ ︎Photo down below ☟
[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer☂}}[/tex]
Let's use distance formula ~
[tex]\qquad \sf \dashrightarrow \: d = \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: d = \sqrt{(2 - ( - 4)) {}^{2} + (0 - 1) {}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: d = \sqrt{(2 + 4) {}^{2} + ( - 1) {}^{2} } [/tex]
[tex]\qquad \sf \dashrightarrow \: d = \sqrt{ {}^{} 36+ 1{}^{} } [/tex]
[tex]\qquad \sf \dashrightarrow \: d = \sqrt{ {}^{} 37{}^{} } [/tex]
Therefore, the required distance is [tex]\sf \sqrt{37}[/tex] units
Write the following series in sigma notation.
7 + 16 + 25 +34 +43 +52 + 61
The series 7 + 16 + 25 +34 +43 +52 + 61 is an illusration of arithmetic series
The sigma notation of the series is: [tex]\sum\limits^7_{n=1} {9n - 2}[/tex]
How to write the series in sigma notation?The series is given as:
7 + 16 + 25 +34 +43 +52 + 61
The above series is an arithmetic series, with the following parameters
First term, a = 7Common difference, d = 9Number of terms, n = 7Start by calculating the nth term using:
a(n) = a + (n - 1) * d
This gives
a(n) = 7 + (n - 1) * 9
Evaluate the product
a(n) = 7 - 9 + 9n
Evaluate the difference
a(n) = 9n - 2
So, the sigma notation is:
[tex]\sum\limits^7_{n=1} {9n - 2}[/tex]
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Put the equation below into vertex form.
y=(x+9)(x+25)
HELP ME PLEASE
PRETTY PLEASEEEEEEEEEEE
Answer:
93
Step-by-step explanation:
19x-2 = 18x+3
x=5
15(5) -2=93
18(5)+3=93
How do you multiplying or dividing a fractions to obtain equivalent
PLSS help important
(will gibe brainliest)!
I dont understand this
To form the vector notation for the translation:
--> must find how much the new graph moved horizontally from the old
graph
--> the graph moved 8 units horizontally
--> must find how much the new graph moved vertically from the old
graph
--> the graph moved 4 units vertically
In vector notation, that would be (8,4)
Hope that helps!
In ΔWXY, y = 8.6 cm, x = 8.5 cm and ∠X=100°. Find all possible values of ∠Y, to the nearest 10th of a degree.
The possible value of ∠Y to the nearest tenth of a degrees in triangle WXY is 85.1 degrees.
How to find angle of a triangle using sine rule
Let's find angle Y using sine rule,
Hence,
x / sin X = y / sin Y
where
x = 8.5 cmy = 8.6 cm∠X = 100°8.5 / sin 100° = 8.6 / sin Y
cross multiply
8.5 sin Y = 8.6 sin 100°
sin Y = 8.6 sin 100° / 8.5
sin Y = 8.4693466759 / 8.5
Y = sin ⁻¹ 0.99639372657
Y = 85.1325941735
∠Y = 85.1°
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please help, what would the answer be?
What is the number with the mark
[tex]\huge\mathsf\blue{♧ANSWER♧}[/tex]
[tex]\huge \mathfrak \blue{\frac{ - 7}{8} }[/tex]
PRESLEY
You are curious about the amount of coffee that the giant fountain cup could actually hold.
The dimensions of the fountain cup are as follows:
• Height is 8 feet.
• Diameter of the top is 6 feet.
• Diameter of the base is 4 feet.
Use this formula with height, h, radius of the base, roase, and radius of the top, rtop, to determine the volume
of the cup:
(πh).
V= -((rbase)+ (rbase) (stop) + (top)).
3
There are 7.5 gallons of liquid per cubic foot.
Enter the volume, in gallons, of the fountain cup.
The volume of the fountain cup in gallons is 4775.2 gallons
Volume of a frustumSince the fountain cup is in the shape of a frustum, its volume is given by
V = πh/3(r² + rr' + r'²) where
h = height of cup = 8 feet, r = radius of base of cup = 4 feet and r' = radius of top of cup = 6 feet.So, substituting the values of the variables into th equation, we have
V = πh/3(r² + rr' + r'²)
V = π × 8 ft/3[(4 ft)² + 4 ft × 6 ft + (6 ft)²]
V = π × 8 ft/3[16 ft² + 24 ft² + 36 ft²]
V = π × 8 ft/3 × (76 ft²)
V = 608π ft³/3
V = 1910.088 ft³/3
V = 636.69 ft³
V ≅ 636.7 ft³
Volume of the fountain cup in gallonsSince there are 7.5 gallons per cubic foot,
The volume of the fountain cup in gallons is V = 636.7 ft³ × 7.5 gallons/ft³ = 4775.2 gallons
So, the volume of the fountain cup in gallons is 4775.2 gallons
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Which graph matches? I'll give brainliest. and 100pts
Function:
[tex]\sf 2\left(3\right)^{x}+2[/tex]
Find y-intercept:
[tex]y=2\left(3\right)^{0}+2[/tex]
[tex]y=\sf 4[/tex]
option B is correct as it cuts y-intercept at 4
Answer:
This is a positive exponential graph with a y-intercept of 4 (when x is 0, y is 4)
Hope this helps!
On Saturday, the temperature was
75.5°F. The temperature rose by
6°F on Sunday, then dropped by
3.5°F on Monday. Write an expression
to represent how the temperature
changed. What was the temperature
on Monday?
Answer:
78°F
Step-by-step explanation:
75.5°F on Saturday...
75.5 + 6 = 81.5 on Sunday
81.5 - 3.5 = 78°F on Monday
The expression that represents the temperature change is
N = L + 6°F + 3.5°F
The temperature on Monday is 85°F.
What is an expression?An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.
Example: 2 + 3x + 4y = 7 is an expression.
We have,
Temperature:
Saturday = L= 75.5°F ______(1)
Sunday = M = Rose by 6°F
M = L + 6 _____(2)
Monday = N = Dropped by 3.5°F
N = L + 6 - 3.5 _____(3)
The expression that represents the temperature change:
From (1), (2), and (3) we get
N = L + 6°F + 3.5°F
The temperature on Monday:
N = 75.5 + 6 + 3.5
N = 85°F
Thus,
The expression that represents the temperature change is
N = L + 6°F + 3.5°F
The temperature on Monday is 85°F.
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An investment account plays 3.7% annual interest compound weekly. If $370 is invested in this account, what will be the balance after 12 years?
Answer: 358
Explanation: 370 - 12 = 358
round to the nearest hundredth
(please help picture inculded)
Answer:
AB ≈ 6.53
Step-by-step explanation:
using the cosine ratio in the right triangle
cos40° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{5}{AB}[/tex] ( multiply both sides by AB )
AB × cos40° = 5 ( divide both sides by cos40° )
AB = [tex]\frac{5}{cos40}[/tex] ≈ 6.53 ( to the nearest hundredth )
-2x^2+bx -5 Determine the b-value that would ensure the function has two real root.
Answer:
No solutionStep-by-step explanation:
Given is the quadratic function
y = -2x² + bx - 5In order to have two real roots the discriminant should be posivive
D = - b² - 4acD = - b² - 4(-2)(-5) = - b² - 40We need D > 0
-b² - 40 > 0b² + 40 < 0b² < - 40There is no solution as b² is never negative
Is (-7, -3) a solution to this system of equations?
x = -7
y = -x - 10
Yes or no
===========================================================
Explanation:
The point (-7,-3) means x = -7 and x = -3
Right off the bat, the first equation x = -7 is proven true based on the first coordinate.
Let's now plug the coordinates into the second equation.
y = -x-10
-3 = -(-7)-10
-3 = 7-10
-3 = -3
Which is a true statement.
Both equations are true when (x,y) = (-7,-3)
This is why it is a solution to the system. It turns out it's the only solution to this system. This system is consistent and independent.
You can use a graphing tool like Desmos to plot the two equations, and you should see them crossing at the point (-7,-3)
Answer:
The answer is yes
*View the attached graph to check your answer graphically.*
Step-by-step explanation:
x = -7
y = -x - 10
For this problem, I will be using substitution, since the second equation is already in the slope-intercept form.
First, I will substitute the first equation, for x, into the first equation:
x = -7
y = -x - 10
y = -(-7) - 10 <== multiplying two negatives, makes a positive
y = 7 - 10
y = - 3 <== the value of y
Now, we find the value of x by substituting - 3 for y:
y = -x - 10
- 3 = -x - 10
+10 +10
7 = -x <== you can't have a negative variable
/-1 /-1
-7 = x <== the value of x
(x, y) ==> (-7, -3)
Therefore, yes (-7,-3) is a solution to this system of equations.
*View the attached graph to check your answer graphically.*
Hope this helps!
Please help me my teacher hasn't been helping me I really need your help
Answer:
550.5323531336038
Step-by-step explanation:
I have a hint: if you ever need help with triangle trigonometry questions go to carbside depot trigonometry calculator it is a literal life savor
how to multiply and divide decimals with whole numbers
PLS HELP I am giving 25 points here is the question
A shopkeeper sold 12 bags of potatoes for $2.99 each. He bought the potatoes for $1.90 for each bag what was his total profit
Find theFind tha amount of profit per bag by subtracting:
2.99 - 1.90 = 1.09
He made $1.09 profit per bag.
Now multiply the profit per bag by the number of bags:
1.09 x 12 = 13.08
Total profit = $13.08 amount of profit per bag by subtracting:
2.99 - 1.90 = 1.09
He made $1.09 profit per bag.
Now multiply the profit per bag by the number of bags:
1.09 x 12 = 13.08
Total profit = $13.08
If 3x - 5y = 11 and 2x + 3y = 5, then what is the ratio of x to y?
Answer:
-58/7
Step-by-step explanation:
Alright so this is a system of equations. First we'll solve the system, and then find the ratio afterwards.
[tex]3x-5y = 11\\2x+3y =5\\[/tex]
Isolate for y on both.
[tex]2x + 3y = 5\\3y = 5-2x\\y = \frac{5-2x}{3}[/tex]
and
[tex]3x - 5y = 11\\-5y = 11-3x\\y = \frac{11-3x}{-5}[/tex]
Set both equations equal to each other:
[tex]\frac{11-3x}{-5} = \frac{5-2x}{3}\\ \\\frac{3(11-3x)}{-5} = 5-2x\\ \\3(11-3x) = -5(5-2x)\\\\33 - 9x = -25 + 10x\\33 = -25 + 19x\\58 = 19x\\\frac{58}{19} = x[/tex]
We've got x, now let's solve for y:
[tex]y = \frac{11-3x}{-5} = \frac{11-3(\frac{58}{19}) }{-5}[/tex]
Now we got both x and y, and what they equal.
[tex]y = \frac{-7}{19}\\[/tex]
[tex]x = \frac{58}{19}[/tex]
The ratio of x to y, is essentially [tex]\frac{x}{y}[/tex]. So we will calculate that.
[tex]\frac{\frac{58}{19} }{\frac{-7}{19} } = \frac{58}{19} * \frac{19}{-7} = \frac{-58}{7}[/tex]
you buy a sandwich for $6.965, a salad for $3.25, and a drink for $1.79. if sales tax is 7%, how much change do you receive from $20 bill, rounded to the nearest cent?
6.965 + 3.25 + 1.79 = 12.005, now, let's apply a 7% taxation on that
[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{7\% of 12.005}}{\left( \cfrac{7}{100} \right)12.005}\implies 0.84035~\hfill \underset{total~bill}{\stackrel{12.005~~ + ~~0.8435}{12.84535}} \\\\\\ 20~~ - ~~12.84535\implies 7.15465~~\approx ~~ \$7.15[/tex]
Hazel and 4 of her friends bought tickets for a baseball game. They received a $30 group discount. If the total cost was under $125, how much could each ticket have been?
Each ticket could have cost up to $31.
What is the discount?
A discount is a reduction in the price of an item or service. It is often offered as an incentive to encourage customers to purchase or use a particular product or service. The discount amount may be a percentage of the total price, a fixed dollar amount, or a combination of both.
Let the cost of each ticket be $x. Then the total cost for 5 tickets would be 5x. After applying the $30 group discount, the total cost would be 5x - $30.
We know that the total cost was under $125, so we can set up the inequality:
5x - $30 < $125
Simplifying this inequality, we get:
5x < $155
Dividing both sides by 5, we get:
x < $31
Hence, each ticket could have cost up to $31.
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Solve for x: √(32^0 + 2/3)=(0.6)^2-3x
Step-by-step explanation:
Given: √{32⁰ + (2/3)} = (0.6)²⁻³ˣ
Asked: Find the value of x = ?
Solution: Given that √{32⁰ + (2/3)} = (0.6)²⁻³ˣ
⇛√{1 + (2/3)} = (0.6)²⁻³ˣ
⇛√{(1/1) + (2/3) = (0.6)²⁻³ˣ
⇛√{(1*3 + 2*1)/3} = (0.6)²⁻³ˣ
⇛√{(3 + 2)/3} = (0.6)²⁻³ˣ
⇛√(5/3) = (0.6)²⁻³ˣ
Squaring on both sides then
⇛{√(5/3)}² = {(0.6)²⁻³ˣ}²
⇛√(5²/3²) = {0.6}(²⁻³ˣ)²
⇛√{(5*5)/(3*3)} = {0.6}(²⁻³ˣ)²
⇛5/3 = {0.6}(²⁻³ˣ)²
[[tex]\mathsf{\because}[/tex] (aᵐ)ⁿ = aᵐⁿ]
⇛5/3 = (0.6)²*²⁻³ˣ*²
⇛5/3 = (0.6)⁴⁻⁶ˣ
⇛5/3 = (6/10)⁴⁻⁶ˣ
⇛5/3 = {(6÷2)/(10÷2)})⁴⁻⁶ˣ
⇛5/3 = (3/5)⁴⁻⁶ˣ
⇛(3/5))⁻¹ = (3/5)⁴⁻⁶ˣ
[[tex]\mathsf{\because}[/tex] a⁻ⁿ = 1/aⁿ]
Base are the same, so the exponents must be equal.
[tex]\mathsf{\therefore}[/tex] -1 = 4 - 6x
Shift the number 4 from RHS to LHS, changing it's sign.
⇛-1 - 4 = -6x
⇛-5 = -6x
⇛x = {(-5)/(-6)}
[tex]\mathsf{\therefore}[/tex] x = 5/6
Answer: Hence, the value of x for the given problem is 5/6.
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how does the number if possible outcomes of a single event help you determine the total number of possible outcomes of a compound event?
The possible outcomes of an event is the sample space
The product of the sample spaces of the single events determines the total number of possible outcomes of a compound event
How to determine the possible outcomes?Assume that the number of outcomes of n single events are:
[tex]n_1[/tex], [tex]n_2[/tex], [tex]n_3[/tex],........ [tex]n_n[/tex]
When these single events are combined, they form a compound event.
The number of outcomes of the compound event is the product of the number of outcomes of the single events.
i.e.
[tex]Outcomes = n_1 * n_2 * ......... n_n[/tex]
Hence, the product of the sample spaces of the single events determines the total number of possible outcomes of a compound event
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Consider the function defined by f(x) lnx/x^4 for x > 0 and its graph y = f(x).
The graph of f has a horizontal tangent at point P. Find the coordinates of P.
Answer:
[tex]\sqrt[4]{e};\frac1{4e}[/tex]
Step-by-step explanation:
The first derivative of [tex]f(x)[/tex] will give, for each x, the slope of the tangent at that specific x. Let's calculate the derivative, applying the quotient rule.
[tex]D(\frac AB) = \frac{A'B-AB'}{B^2}\\f'(x)= \frac1{x^8}[(\frac1x)x^4-(lnx)(4x^3)]=\frac1{x^8}[x^3(1-4lnx)]=\frac{1-4lnx}{x^5}[/tex]
Now, to find the point with an horizontal tangent (called "stationary points"), we set the first derivative equal to 0. Considering that we're working with [tex]x > 0[/tex] we deal only with the numerator.
[tex]1-4lnx = 0 \rightarrow lnx= \frac14\\x=e^\frac14 =\sqrt[4]{e}[/tex]
At this point we Replace the value we found in the equation to find it's y coordinate
[tex]f(\sqrt[4]e) = \frac{ln\sqrt[4]e}{\sqrt[4]e^4}= \frac{\frac14}{e} = \frac1{4e}[/tex]
6,402.66 divided by 459438.26
Answer: 0.0139358
Step-by-step explanation: 999,999,999,999,999,999,999,999,999,999,999% sure!
When Derek planted a tomato plant, he expected to be picking his first ripe tomato in 45 days. His estimate was 25% less than the actual time. How long did it take before Derek picked his first ripe tomato?
Answer:
60 days.
Step-by-step explanation:
Let the actual time be x, then:
x - 0.25x = 45
0.75x = 45
x = 45/0.75
= 60 days.
Given the equation 47=38+n, tell which value is a solution from the solution set n={7, 9, 11, 13}
First, let's solve this equation by subtract 38 from both sides:-
[tex]\bigstar[/tex] 47-38=n
hence, the answer is:-
9=n
or
[tex]\bigstar{\underline{\boxed{\pmb{n=9}}}[/tex]
note:-Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I'll comment and/or edit my answer :)
Lita must find the area of the sector enclosed by central angle QCR in circle C.
Points Q and R lie on circle C. The measure of angle Q C R is 74 degrees and the radius of circle C is 1 foot.
What steps should Lita take to correctly solve this problem?
A: Lita knows that m∠QCR=74∘ and that the whole circle has a measure of 360∘, so the portion of the area she wants to find is 74∘360∘. Therefore, she must multiply 74∘360∘ times the area, which is πr2.Lita knows that m∠QCR=74∘ and that the whole circle has a measure of 360 degrees textsf comma so the portion of the area she wants to find is 74∘360∘. Therefore, she must multiply 74∘360∘ times the area, which is πr2.
B: Lita knows that m∠QCR=74∘ and that the whole circle has a measure of 360∘, so the portion of the area she wants to find is 74∘360∘, so she must multiply 74∘360∘ times the area, which is 2πr.Lita knows that m∠QCR=74∘ and that the whole circle has a measure of 360 degrees textsf comma so the portion of the area she wants to find is 74∘360∘, so she must multiply 74∘360∘ times the area, which is 2πr.
C: Lita knows that m∠QCR=74∘ and that the whole circle has a measure of 360∘, so she should subtract 74∘ from 360∘. The portion of the area she wants to find is 286∘360∘, so she must multiply 286∘360∘ times the area, which is 2πr.Lita knows that m∠QCR=74∘ and that the whole circle has a measure of 360 degrees textsf comma so she should subtract 74 degrees from The portion of the area she wants to find is 286∘360∘, so she must multiply 286∘360∘ times the area, which is 2πr.
D: Lita knows that m∠QCR=74∘ and that the whole circle has a measure of 360∘, so she should subtract 74∘ from 360∘. The portion of the area she wants to find is 286∘360∘, so she must multiply 286∘360∘ times the area, which is πr2.
To find the area of the sector, Lita must multiply 74°/360° times the area of the circle, which is πr² (Option A).
What is the Area of the Sector of a Circle?Area of sector = ∅/360 × πr², where ∅ = central angle, and r = radius of the circle.
Given the following:
∅ = m∠QCR = 74°r = 1 ft.The area of the circle she wants to find is: 74°/360°.
Since the area of the whole circle is, πr², therefore, to find the area of the sector, Lita must multiply 74°/360° times the area of the circle, which is πr² (Option A).
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