The ordered pairs in the table below represent a linear function.
C D
Х
y
2
6
9
8
What is the slope of the function?
AN
4
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What we know:

The baby gains 1.5 pounds per month.

Its weight at birth is 12 pounds.

Therefore, when looking to find the weight after t time, we have to take the constant and the rate of change and place them into the equation. This means our equation will look something like this:

W(t) = Rate of Change x number of months + weight at birth.

Or

W(t) = 1.5(t) + 12

So if in 4 months we look at the weight, the baby will be:

1.5 (4) + 12 = W(t)

6 + 12 = W(t)

18 = W(t)

After 4 months the baby is 18 pounds.

Answer: W(t) = 1.5(t) + 12

I hope this helps! :)

Given that:

f(x) = -2x²-2x+10

f(2) = -2(2)²-2(2)+10

= -2(2*2) - 4 + 10

= -2(4) - 4 + 10

= -8 - 4 + 10

= -12 + 10

= -2 Ans.

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Similar Question

Given f(x) = 1/2x - 5, find f^-1(x) a. f^-1 (x) = -2x+10 b. f^-1(x) = 2x+5 c. f^-1(x) = 2x-10 d. f^-1(x) = 2x+10...

https://brainly.com/question/11148895?referrer

Answer:

4.7 x [tex]10^{7}[/tex] miles

Step-by-step explanation:

You know Mars is further away from the sun

so the distance between earth and mars will be

1.4x[tex]10^{8}[/tex]-9.3x[tex]10^{7}[/tex]

14x[tex]10^{7}[/tex]-9.3x[tex]10^{7}[/tex]

4.7 x [tex]10^{7}[/tex] miles

Answer:

look at the slope rise of 2 run of -1 or other way around so slope is

[tex] y = - \frac{2}{1}x + 5[/tex]

Answer:

(-3,16)

Step-by-step explanation:

(-5,12)

f (x) = ( (x+5) (x+5) ) + 12

f (x) = x^2 + 10x + 37

(-2,15)

f (x) = ( (x+2) (x+2) ) + 15

f (x) = x^2 + 4x + 19

Answer:

-4 and -12

Step-by-step explanation:

For what times what equals 48:

-4(-12) = 48

-4 - 12 = -16

Answer:

x= -4 and y= -12

Step-by-step explanation:

x*y=48

x+y=-16

solve one equation for x

y=-16-x

then plug that y into the other equation

x(-16-x)=48

-16x-x^2=48

multiply by -1

x^2+16x=-48

complete the square

x^2+16x+64=-48+64

(x+8)^2=16

solve for x

x+8=sqrt(16)

x+8=4

x=4-8

x=-4

plug x back into original equation

x+y=-16

-4+y=-16

y=-16+4

y=-12

so your answers are x=-4 and y=-12

Answer:

180/7

Step-by-step explanation:

Answer:

$42,110.65

Step-by-step explanation:

Answer:

The slope is zero

Step-by-step explanation:

0 | 2

1 | 2

3 | 2

Answer:

Therefore, Aroha is 17 yrs old and her brother is 14 yrs old.

Step-by-step explanation:

Let's represent Aroha's brother's Agee with the letter "b" yrs old.

If Aroha is 3yrs older than her brother, she's : (b+3) yrs old.

The sum of their ages is 31,

b+(b+3)=31

2b+3=31

Collect like terms,

2b=31-3

2b=28

Divide both sides by 2,

b=14

b+3=17

A cheerful teen hoping this helps,

stay techy, brilliant and positive!

Answer:

  5.48 lb

Step-by-step explanation:

12 inches is 1 foot.

12.8 times that length will have 12.8 times that weight:

  12.8 · 0.428 lb = 5.4784 lb ≈ 5.48 lb

__

The given values have 3 significant figures, so the answer needs to be rounded to 3 significant figures.

Answer:

A football is a sphere, so the formula for calculating its surface area is 4πr²

Hope it helps:)

Answer:

see explanation

Step-by-step explanation:

(10)

Since the triangles are congruent then corresponding sides are congruent, so

EF = BC , that is

4x - 1 = 19 ( add 1 to both sides )

4x = 20 ( divide both sides by 4 )\

x = 5

and

DE = AB , that is

y - 6 = 8 ( add 6 to both sides )

y = 14

-------------------------------------------------------

(11)

Since the triangles are congruent the corresponding angles are congruent, so

∠ K = ∠ Y , that is

3x - 37 = 41 ( add 37 to both sides )

3x = 78 ( divide both sides by 3 )

x = 26 , then

∠ K = 3x - 37 = 3(26) - 37 = 78 - 37 = 41°

The sum of the 3 angles in Δ ZMK = 180° then

∠ Z = 180° - (41 + 112)° = 180° - 153° = 27°

So

∠ A = ∠ Z

2y + 7 = 27 ( subtract 7 from both sides )

2y = 20 ( divide both sides by 2 )

y = 10

------------------------------------------------------------------------

(12)

Since the triangles are congruent the corresponding sides and angles are congruent

DG = BS

4x - 11 = 25 ( add 11 to both sides )

4x = 36 ( divide both sides by 4 )

x = 9

∠ T = 180° - (56 + 21)° = 180° - 77° = 103°

Then

∠ H = ∠ T

7y + 5 = 103 ( subtract 5 from both sides )

7y = 98 ( divide both sides by 7 )

y = 14

Answer:

y= 2x-3

when X= -1

y= 2(-1)-3

y= -2-3

y= -5

The value of the given function y=2x-3 is  -5 when x=-1

A function is a correspondence from the two set A to set B in which each element of set A has a unique image in B. Generally we denote a function by f or y.

Here the given function is y=2x-3

Putting x= -1 in the given function y=2x-3 , we get

y= 2(-1) -3

y= -2-3

y= -5

Hence the value of the function y= 2x-3 is -5 when x=-1 .

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Answer: 2x-y=3

Step-by-step explanation:

Rewrite 2x-y=3 in standard form:  y = 2x -3

The line on the graph has a y-intercept of -3, as does this equation.  We can also see a slope of 2 (y goes up by 2 for every time x increase by 1).

Step-by-step explanation:

5x+3x-14=180

8x-14=180

8x=180+14

8x=174

x=174/8

x= 21.75°

if x is 21.75°, then 5x is 108.75°

which means 3x-14 is 51.25°

therefore, f +108.75+51.25=180

f = 180-160

f=20°

It looks like given matrices are supposed to be

[tex]\begin{array}{ccccccc}\begin{bmatrix}3&2\\2&3\end{bmatrix} & & \begin{bmatrix}1&-1\\2&-1\end{bmatrix} & & \begin{bmatrix}1&2&3\\0&2&3\\0&0&3\end{bmatrix} & & \begin{bmatrix}3&1&1\\1&3&1\\1&1&3\end{bmatrix}\end{array}[/tex]

You can find the eigenvalues of matrix A by solving for λ in the equation det(A - λI) = 0, where I is the identity matrix. We also have the following facts about eigenvalues:

• tr(A) = trace of A = sum of diagonal entries = sum of eigenvalues

• det(A) = determinant of A = product of eigenvalues

(a) The eigenvalues are λ₁ = 1 and λ₂ = 5, since

[tex]\mathrm{tr}\begin{bmatrix}3&2\\2&3\end{bmatrix} = 3 + 3 = 6[/tex]

[tex]\det\begin{bmatrix}3&2\\2&3\end{bmatrix} = 3^2-2^2 = 5[/tex]

and

λ₁ + λ₂ = 6   ⇒   λ₁ λ₂ = λ₁ (6 - λ₁) = 5

⇒   6 λ₁ - λ₁² = 5

⇒   λ₁² - 6 λ₁ + 5 = 0

⇒   (λ₁ - 5) (λ₁ - 1) = 0

⇒   λ₁ = 5 or λ₁ = 1

To find the corresponding eigenvectors, we solve for the vector v in Av = λv, or equivalently (A - λI) v = 0.

• For λ = 1, we have

[tex]\begin{bmatrix}3-1&2\\2&3-1\end{bmatrix}v = \begin{bmatrix}2&2\\2&2\end{bmatrix}v = 0[/tex]

With v = (v₁, v₂)ᵀ, this equation tells us that

2 v₁ + 2 v₂ = 0

so that if we choose v₁ = -1, then v₂ = 1. So Av = v for the eigenvector v = (-1, 1)ᵀ.

• For λ = 5, we would end up with

[tex]\begin{bmatrix}-2&2\\2&-2\end{bmatrix}v = 0[/tex]

and this tells us

-2 v₁ + 2 v₂ = 0

and it follows that v = (1, 1)ᵀ.

Then the decomposition of A into PDP⁻¹ is obtained with

[tex]P = \begin{bmatrix}-1 & 1 \\ 1 & 1\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}1 & 0 \\ 0 & 5\end{bmatrix}[/tex]

where the n-th column of P is the eigenvector associated with the eigenvalue in the n-th row/column of D.

(b) Consult part (a) for specific details. You would find that the eigenvalues are i and -i, as in i = √(-1). The corresponding eigenvectors are (1 + i, 2)ᵀ and (1 - i, 2)ᵀ, so that A = PDP⁻¹ if

[tex]P = \begin{bmatrix}1+i & 1-i\\2&2\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}i&0\\0&i\end{bmatrix}[/tex]

(c) For a 3×3 matrix, I'm not aware of any shortcuts like above, so we proceed as usual:

[tex]\det(A-\lambda I) = \det\begin{bmatrix}1-\lambda & 2 & 3 \\ 0 & 2-\lambda & 3 \\ 0 & 0 & 3-\lambda\end{bmatrix} = 0[/tex]

Since A - λI is upper-triangular, the determinant is exactly the product the entries on the diagonal:

det(A - λI) = (1 - λ) (2 - λ) (3 - λ) = 0

and it follows that the eigenvalues are λ₁ = 1, λ₂ = 2, and λ₃ = 3. Now solve for v = (v₁, v₂, v₃)ᵀ such that (A - λI) v = 0.

• For λ = 1,

[tex]\begin{bmatrix}0&2&3\\0&1&3\\0&0&2\end{bmatrix}v = 0[/tex]

tells us we can freely choose v₁ = 1, while the other components must be v₂ = v₃ = 0. Then v = (1, 0, 0)ᵀ.

• For λ = 2,

[tex]\begin{bmatrix}-1&2&3\\0&0&3\\0&0&1\end{bmatrix}v = 0[/tex]

tells us we need to fix v₃ = 0. Then -v₁ + 2 v₂ = 0, so we can choose, say, v₂ = 1 and v₁ = 2. Then v = (2, 1, 0)ᵀ.

• For λ = 3,

[tex]\begin{bmatrix}-2&2&3\\0&-1&3\\0&0&0\end{bmatrix}v = 0[/tex]

tells us if we choose v₃ = 1, then it follows that v₂ = 3 and v₁ = 9/2. To make things neater, let's scale these components by a factor of 2, so that v = (9, 6, 2)ᵀ.

Then we have A = PDP⁻¹ for

[tex]P = \begin{bmatrix}1&2&9\\0&1&6\\0&0&2\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}1&0&0\\0&2&0\\0&0&3\end{bmatrix}[/tex]

(d) Consult part (c) for all the details. Or, we can observe that λ₁ = 2 is an eigenvalue, since subtracting 2I from A gives a matrix of only 1s and det(A - 2I) = 0. Then using the eigen-facts,

• tr(A) = 3 + 3 + 3 = 9 = 2 + λ₂ + λ₃   ⇒   λ₂ + λ₃ = 7

• det(A) = 20 = 2 λ₂ λ₃   ⇒   λ₂ λ₃ = 10

and we find λ₂ = 2 and λ₃ = 5.

I'll omit the details for finding the eigenvector associated with λ = 5; I ended up with v = (1, 1, 1)ᵀ.

• For λ = 2,

[tex]\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix}v = 0[/tex]

tells us that if we fix v₃ = 0, then v₁ + v₂ = 0, so that we can pick v₁ = 1 and v₂ = -1. So v = (1, -1, 0)ᵀ.

• For the repeated eigenvalue λ = 2, we find the generalized eigenvector such that (A - 2I)² v = 0.

[tex]\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix}^2 v = \begin{bmatrix}3&3&3\\3&3&3\\3&3&3\end{bmatrix}v = 0[/tex]

This time we fix v₂ = 0, so that 3 v₁ + 3 v₃ = 0, and we can pick v₁ = 1 and v₃ = -1. So v = (1, 0, -1)ᵀ.

Then A = PDP⁻¹ if

[tex]P = \begin{bmatrix}1 & 1 & 1 \\ 1 & -1 & 0 \\ 1 & 0 & -1\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}5&0&0\\0&2&0\\0&2&2\end{bmatrix}[/tex]

Answer:

  D. (-3, 26)

Step-by-step explanation:

The ratios of x- and y-coefficients are different in the two equations, so there will be a single solution. (Different ratios mean the slopes are different. Lines with different slopes must intersect in exactly one point.)

We can rearrange the first equation to give an expression for y:

  y = 17 -3x

This can be substituted into the second equation to give ...

  x +2(17 -3x) = 49

  -5x +34 = 49 . . . . . . simplify

  -5x = 15 . . . . . . . subtract 34

  x = -3 . . . . . . divide by -5

Then the value of y is ...

  y = 17 -3(-3) = 26

The single solution is (x, y) = (-3, 26).

Answer: x = 7

Step-by-step explanation:

do opposites to both sides. what is the opposite of -5? it would be plus 5.

add 5 to both sides

3x = 21

now what is the opposite of 3 times x? 3 divided by.

divide 3 to both sides

x = 7

Answer:

x = 7

Step-by-step explanation:

First add 5 on both sides to get 3x = 21, then divide 3 on both sides to get x = 7.

Hope this helps you :)

Answer:

16

Step-by-step explanation:

2^-2=0.25

2^6=64

times

=16

[tex]\sf \longmapsto45 - 2x = 75 - 3x[/tex]

[tex]\sf \longmapsto45+−2x=75+−3x[/tex]

[tex]\sf \longmapsto−2x+45=−3x+75[/tex]

[tex]\sf \longmapsto \: −2x+45+3x=−3x+75+3x[/tex]

[tex]\sf \longmapsto \: x+45=75[/tex]

[tex]\sf \longmapsto \: x+45−45=75−45[/tex]

[tex]\sf \longmapsto \: x=30[/tex]

[tex] \boxed{\sf 30}[/tex]

Answer:

The answer in image one is f(x)=2x     Left

The answer in image two is f(x)=x       Center

the answer in image three where right       Right

Answer:

The answer is f(x) = x. Its the second graph.

Step-by-step explanation:

Answer: a = 2.5 (an-1)

Step-by-step explanation: trust me;)

The function which is used to represent the geometric progression 8, 20, 50, 125, 312.5, ... is [tex]a_{n} = 8(2.5)^{n-1}[/tex].

sequence where each succeeding term is produced by multiplying each preceding term by a fixed number, which is called a common ratio. This progression is as a geometric sequence of  numbers.

[tex]a_{n} =ar^{n-1}[/tex]

Where,

[tex]a_{n}[/tex] is the nth term of the sequence or geometric progression

n is the total number of terms

r is the common ratio

and a is the first term

According to the given question

We have

A geometric progression

8, 20, 50, 125, 312.5

Now the common ratio for the above progression is given by

[tex]r = \frac{20}{8} = 2.5[/tex]

And the first term is

a = 8

Therefore, the function which is used to represent the above sequence is given by

[tex]a_{n} = 8(2.5)^{n-1}[/tex]

Hence, the function which is used to represent the geometric progression 8, 20, 50, 125, 312.5, ... is [tex]a_{n} = 8(2.5)^{n-1}[/tex].

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Answer:

156.73 cm

Step-by-step explanation:

height of the person = (2.75 × humerus length)+71.48 cm

length of the found humerus = 31cm

∴ height of the person = (2.75 × 31)+71.48 cm

                                     = 85.25 + 71.48 cm

                                     = 156.73 cm

Answer:

The variable should not be Less than or equal to... it should be GREATER than or equal to [[tex]y\geq 2x-4[/tex]]

Step-by-step explanation:

Answer:

I believe her mistake is that the shaded area is on the wrong side of the line.

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Edge 2021.