Answer:
muscular force in relative to this
The _____________ experiences a temperature increase primarily due to the absorption of gamma rays and X-rays.
Answer:
The thermosphere experiences a temperature increase primarily due to the absorption of gamma-rays and X-rays.
What are the variables that affect the force of gravity between objects?
What does the universe look like on very large scales?
Answer:
it looks like dots and just black space on a large scale
Explanation:
on a large scale the universe especially our milky way looks small
hope this helps
which chamber approves presidential nomination
Answer: The Senate provides advice and consent on presidential nominations.
What unit of pressure in ideal gas law.
Which of these is a likely impact of the stronger than normal trade winds on the eastern Pacific ocean?
Warm surface water builds up, causing lower than average temperature.
Warm surface water builds up, causing higher than average temperature.
Warm surface water is reduced, causing colder conditions than normal.
Warm surface water is reduced, causing hotter conditions than normal.
Just say A B C or D which one
Answer:
b i think
Explanation:
hope this helps
Answer: A B C or D which one
Explanation:
A 16.75 g piece of iron absorbs 986.75 joules of heat energy, and it’s temperature changes from 25 degrees Celsius to 175 degrees Celsius. Calculate the specific heat capacity of iron.
Answer:
0.39 J/g°c
Explanation:
= heat / unit of mass × unit of temperature
986.75J/16.75g
= 58.9 J/g
∆T=175°c - 25°c = 150°c
986.75 / 150°c = 6.578
986.75 / 16.75g.150°c = 0.30 j/g°c
An object is in equilibrium. Which force vector diagram could represent the force(s) acting on the object
Answer:
velocity and force
Explanation:
Velocity and force vector diagram represent the force acting on the object.
What is vector diagram?Diagrams are called vector diagrams to use a vector arrowhead to show the magnitude or direction of a vector quantity. The velocity of an item in motion could be represented in vector diagrams. A vector diagram might be used, for instance, to depict the motion of an automobile traveling down a road.
What is force?A force was an influence that will have the power to alter an object's motion.
Therefore, velocity and force vector diagram represent the force acting on the object.
To know more about vector and force.
https://brainly.com/question/11643003
#SPJ3
In the experiment shown below, which is greater, the force of gravity on the pith balls (Fg) or the electrostatic force between them (Fq)?
Answer:
Electronic force
Explanation:
Maybe because its warmer and may have more force
If an automobile slows from 26 m/s to 18 m/s in a period of 4.0 s, what was the average acceleration?
Answer: -2m/s²
Explanation:
Each second, the acceleration decreases of 2m/s²
N.B.: in physics, deceleration is also acceleration.
An astronomer examines an emission line spectrum for a star from data recorded by a spectroscope. There are four lines: two in the blue region, one in the green region, and one in the red region of the spectrum. How does the spectrum obtained from the spectroscope help the astronomer?
The characteristics of the atomic spectrum allow to find the result so that the measured lines help the astronomer is:
The astronomer can identify the gases that are present in stars using emission lines.
The emission spectrum is the emission of light due to the atomic transition in atoms, consequently the spectrum of each chemical element is unique.
The astronomer was able to identify the chemical elements that are in stars by their emission spectrum.
In the case presented there are two lines in the blue region, a line in the green region and a line in the red region. We know that the most abundant element in stars is hydrogen.
Hydrogen has a series of well-defined spectral lines, the series that is in the visible part of the spectrum is called the Balmer series and is composed of the lines in the table.
Color wavelength (nm)
red 656.3
blue 486.1
violet 434.1
The second element in quantity in stars is helium, which has the spectrum given in the table and in the attached.
color wavelength (nm)
Red 667.8
orange 587.6
green 501.6
Blue 492.2
Blue 447.1
The astronomer compares his measured spectrum with the spectra of these two gases and finds that the element he is measuring is helium.
In conclusion, using the characteristics of the atomic spectra, we can find the result to help the astronomer with the measured lines is:
The astronomer can identify the gases that are present in stars using emission lines.
Learn more here: brainly.com/question/14819167
Answer:b
Explanation:
did it
a race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds , how far does it move during this time
find distance and acceleration
PLEASEEEE HELP I HAVE A PHYSICS EXAM TOMORROW AND IM STRUGGLING
Answer:
add 44m/s and 22m/s then multiply it by 11
Explanation:
A race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds, Acceleration is -2 m/s² (deceleration), and distance is 242 meters.
To solve this problem, it is given:
Initial velocity ([tex]\(v_i\)[/tex] ) = 44 m/s
Final velocity ([tex]\(v_f[/tex] ) = 22 m/s
Time ([tex]\(t\)[/tex] ) = 11 s
We have two tasks: finding the acceleration (a) and then using it to calculate the distance (d).
1. Calculate Acceleration (a):
[tex]\[a = \frac{v_f - v_i}{t} \\\\= \frac{22 \, \text{m/s} - 44 \, \text{m/s}}{11 \, \text{s}} \\\\= -2 \, \text{m/s}^2\][/tex]
The negative sign indicates deceleration (slowing down).
2. Calculate Distance (d):
Using the kinematic equation:
[tex]\[d = v_i \cdot t + \frac{1}{2} \cdot a \cdot t^2\][/tex]
Plugging in the values:
[tex]\[d = (44 \, \text{m/s}) \cdot (11 \, \text{s}) + \frac{1}{2} \cdot (-2 \, \text{m/s}^2) \cdot (11 \, \text{s})^2\][/tex]
Calculating the first part:
[tex]\[d = 484 \, \text{m} - 121 \, \text{m} \\\\= 363 \, \text{m}\][/tex]
Calculating the second part:
[tex]\[d = 363 \, \text{m} + \frac{1}{2} \cdot (-2 \, \text{m/s}^2) \cdot (121 \, \text{s}^2) \\\\= 363 \, \text{m} - 121 \, \text{m} \\\\= 242 \, \text{m}\][/tex]
The total distance the race car moves during this time is 242 meters.
Thus, acceleration is -2 m/s² (deceleration), and distance is 242 meters.
For more details regarding acceleration, visit:
https://brainly.com/question/2303856
#SPJ3
Calculate the charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts.
The charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts is 350 Coulomb
Potential difference is the amount of work needed to move a unit charge from one point to another. It is given by:
V = E/Q
Where V is potential difference, E is energy and Q is charge. Given that:
V = 15 V, E = 5.25 kJ = 5.25 * 10³ J.
V = E/Q
15 = 5.25 * 10³ /Q
Q = 350 Coulomb
The charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts is 350 Coulomb
Find out more at: https://brainly.com/question/3412043
Voltage ______
Question 1 options:
is measured in Volts
causes current
pushes free electrons around a circuit
all of the choices
all of the choices.
Explanation:
....
t/-15=-3. what is t?
Answer:
[tex]\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}[/tex]
[tex]\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}[/tex]
What is the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod
Answer:
C) 5ML^2
Explanation:
2 Spheres of mass M
Bug's mass 3M
Rod length 2L, radius L
Find Rotational Inertia I
I=Σmr^2
I=(3M+M+M)L^2
I=5ML^2
The rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².
Rotational inertia of the systemThe rotational inertia of the system is determined by summing all the masses together and multiply with the radius.
I(t) = Σmr²
Where;
m is the massr is the radiusI(t) = Inertia of the 2 spheres + inertia of the bug
I(t) = (M + M)L² + (3M)L²
I(t) = 2ML² + 3ML²
I(t) = 5ML²
Thus, the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².
Complete question is below:
There are 2 Spheres of mass M and Bug's mass 3M. The Rod length is 2L, radius L.
Learn more about rotational inertia here: https://brainly.com/question/14001220
2. All objects contain both what and what charges.
Answer:
All objects are composed of these atoms. ... Charged objects have an imbalance of charge - either more negative electrons than positive protons or vice versa. And neutral objects have a balance of charge - equal numbers of protons and electrons.
Explanation:
What happens to the sound an object makes when the speed of vibrations decreases (slow down)?.
PLS HURRY THIS IS DUE TODAY!!!
I WILL GIVE BRAINLIEST!!!!
NO LINKS AND NO STEALING POINTS,
PLS ANSWER IF YOU KNOW FOR SURE WHAT IT IS!!!
THE QUESTION IS IN THE PICTURE ATTACHED!
Answer:
B. between carbon and oxygen
Explanation:
formaldehyde has a carbon atom that has single bonds with two hydrogen atoms on both sides, and it has a double bond with oxygen.
Answer:
The placement of the double bond is between carbon atom and oxygen atom
this same question was for me so I did and got it correct
please mark me as brainliest
Calculate the weight of a 2kg chicken on earth. .. (use the formulas)
Answer:
weight =m x g =2kg × 10m/s 2 = 20N
Formulas:
weight = m × gravity
=unit for weight is newtons
Mass=weight ÷ gravity
= unit for mass is kilograms
Gravity=weight ÷ mass
=unit for gravity is 10m/sec 2
BEFORE COLLISION
MASS = 4200 kg
MASS = 990 kg
V = 10 m/s
AFTER COLLISION
V = ?
V = 2 m/s
What is the velocity after the crash?
Initial kinetic energy KE = 1/2 m1v12 + 1/2 m2v22 = joules. The following calculation expects you to enter a final velocity for mass m1 and then it calculates the final velocity of the other mass required to conserve momentum and calculates the kinetic energy either gained or lost to make possible such a collision.
You find a rock that is about 20 grams large. This rock contains about 10 grams of Uranium-235 and 10 grams of the element it decays into (Thorium-231). The half life of Uranium-235 is 700 million years. How old is this rock?
The age of the given rock is 700 million years.
The given parameters;
original mass of the rock, = 20 gmass of the rock remaining after decay, = 10 ghalf life of Uranium, [tex]t_{1/2}[/tex] = 700 yearsage of the rock ----------------------------- mass remaining
0 [tex](t_0)[/tex] ------------------------------------------- 20 g
1 half life ([tex]1 \ t_{1/2}[/tex] ) ------------------------------ 10 g
Age of the rock [tex]= t_{1/2} - t_0 = 700 \ - 0 = 700 \ million \ years[/tex]
Thus, the age of the given rock is 700 million years.
Learn more here:https://brainly.com/question/23774743
How much work is done by a student holding a book with a force of 5N and walking forward 10 m?
Answer:
50 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 5 × 10 = 50
We have the final answer as
50 JHope this helps you
A block with a mass of 6.0 kg is
held in equilibrium on an incline
of angle θ = 30.0° by a horizontal
force, F, as shown in the figure.
Find the magnitudes of the
normal force on the block and of F. (Ignore friction.)
(a) The normal force on the block is 50.92 N.
(b) The horizontal force on block keeping it in equilibrium is 29.4 N.
The given parameters;
mass of the block, m = 6 kgangle of inclination, θ = 30.0°The normal force on the block is calculated as follows;
[tex]F_n = W \times cos(\theta)[/tex]
where;
W is the weight of the block[tex]F_n = mg \times cos(\theta)\\\\F_n = 6 \times 9.8 \times cos(30)\\\\F_n = 50 .92 \ N[/tex]
The horizontal force on block keeping it in equilibrium is calculated as follows;
[tex]F- F_x = 0\\\\F-mgsin\theta= 0\\\\F = mgsin\theta\\\\F = 6 \times 9.8 \times sin(30)\\\\F = 29.4 \ N[/tex]
Learn more here:https://brainly.com/question/24860178
Составьте правильное соответствие:
1. А. Лавуазье
А. Он говорил: «Знание – сила»
2. Д. Дальтон
Б. Изучал теорию газов.
3. Д.И. Менделеев
В. Опубликовал труд «Методы наименования химических элементов»
4. Р. Броун
Г. Работы посвящены морфологии и систематике растений.
5. М. Смолуховский
Д. Работы посвящены броуновскому движению.
6. Р. Бойль
Е. Ввел понятие «атомный вес»
7. Ф. Бэкон
Ж. Открыл периодический закон химических элементов.
1. good morning mam going to be a long day for me to be a long day for me to be a long day for me to be a long day for me to be a long day for me to be a long day for
What are 2 examples of Newton's second law in everyday life?
Answer:
kicking ball and throwing stone
Answer:
- Pushing a shopping cart
- Kicking a soccer ball
Explanation:
The second law states "It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it."
So two examples would be pushing / kicking anything (shopping cart or soccer ball for example) and riding a bicycle (bike = mass and you are the force)
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
solar power generates electricity from what source
4) An 873kg dragster, starting from rest, attains a speed of 26.3m/s in 0.590s.
A) What was the acceleration of the dragster?
B) What was the net force needed to accelerate the dragster?
C) Assume that the driver has a mass of 68.0kg. What horizontal force does the seat exert on
him?
Answer:
A.)a=44.57m/s
B.)f=38,909.61
C.)f=666.4
Explanation:
A.) A=v/t 26.3/0.590=44.57
B.) 873kg x 44.57= 38,909.61
C.) 68kg x 9.8=666.4
Which event happens in a solar cell when the photoelectric effect occurs?
A. Electromagnetic waves strike the transparent glass on the top of
the cell, removing electrons from it.
B. The wave model of light is supported, but the particle model is
not.
C. A current forms when electromagnetic waves strike a
semiconductor, removing some of its electrons.
the
D. Electrons flow from the positively charged semiconductor to
negatively charged one.
Answer:
current forms when electromagnetic waves strike a semiconductor, removing some of its electrons.
Explanation:
Answer:
current forms when electromagnetic waves strike a semiconductor, removing some of its electrons.
trust me i just did it
Explanation:
Dark matter is inferred to exist because Select one: a. we can observe its gravitational influence on visible matter. b. it explains how the expansion of the universe is accelerating. c. we see lots of dark patches in the sky. Clear my choice
Answer:
(a) the gravitational influence on visible matter can not be explained by matter that can be seen.