The photoelectric threshold wavelength of a tungsten surface is 272 nm.a) What is the threshold frequency of this tungsten?b) What is the work function (in eV) of this tungsten?c) Calculate the maximum kinetic energy (in eV) of the electrons ejected from this tungsten surface by ultraviolet radiation of frequency 1.46×10151.46×1015 Hz.

Answers

Answer 1

a) The threshold frequency of the tungsten is 1.102 × 10^15 Hz.

b) The work function of the tungsten is 4.57 eV.

c) No electrons will be ejected from the tungsten surface by the given ultraviolet radiation, and the maximum kinetic energy of the ejected electrons is 0 eV.

a) The threshold frequency of the tungsten can be calculated using the formula:

f = c / λ

Where f is the frequency, c is the speed of light (299,792,458 m/s), and λ is the threshold wavelength (272 nm or 272 × 10^-9 m).

Plugging in the values, we get:

f = (299,792,458 m/s) / (272 × 10^-9 m) = 1.102 × 10^15 Hz

Therefore, the threshold frequency of the tungsten is 1.102 × 10^15 Hz.

b) The work function of the tungsten can be calculated using the formula:

Φ = h × f_threshold

Where Φ is the work function, h is the Planck's constant (6.626 × 10^-34 J·s), and f_threshold is the threshold frequency (1.102 × 10^15 Hz).

Plugging in the values, we get:

Φ = (6.626 × 10^-34 J·s) × (1.102 × 10^15 Hz) = 7.32 × 10^-19 J

To convert this to electron volts (eV), we can use the conversion factor 1 eV = 1.602 × 10^-19 J. Therefore:

Φ = (7.32 × 10^-19 J) / (1.602 × 10^-19 J/eV) = 4.57 eV

Therefore, the work function of the tungsten is 4.57 eV.

c) The maximum kinetic energy of the ejected electrons can be calculated using the formula:

KEmax = hf - Φ

Where KEmax is the maximum kinetic energy, h is the Planck's constant, f is the frequency of the incident radiation, and Φ is the work function.

Plugging in the values, we get:

KEmax = (6.626 × 10^-34 J·s) × (1.46 × 10^15 Hz) - (4.57 eV × 1.602 × 10^-19 J/eV)

KEmax = 9.684 × 10^-20 J - 7.32 × 10^-19 J

KEmax = -2.351 × 10^-19 J

Since the result is negative, it means that no electrons will be ejected from the tungsten surface by the given ultraviolet radiation.

Therefore, the maximum kinetic energy of the ejected electrons is 0 eV.

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What is displacement?

Displacement is defined as the overall alteration of an object's location and motion direction. Displacement is recognized as a vector quantity since it takes into account both the direction of the motion and the magnitude of the changing position. Displacement may be zero, positive, or negative.

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Thus, the displacement of the car is +10 km.

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Answer:

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Answer:

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20.Two balls are in motion. A 2-kg ball moving at 4m/s and a 4-kg ball moving at 2m/s, which one has greater kinetic energy? a. 2 kg ball moving at 4 m/s c. Both balls have the same KE b. 4 kg ball moving at 2 m/s d. Cannot be determined

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Given that two balls are in motion. A 2-kg ball moving at 4m/s and a 4-kg ball moving at 2m/s, which one has greater kinetic energy? a. 2 kg ball moving at 4 m/s c. Both balls have the same KE b. 4 kg ball moving at 2 m/s d. Cannot be determined

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JUST A MINUTE KAPENG MAINIT

The model shows eight positions of the moon around Earth during the
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اليا
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CM

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if u just look at a diagram of like the moons it says that

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A crate is sliding on the floor. If there is a total force acting on the crate in the same direction as it is sliding, the crate would
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b) Include this table on your slide:
Mass of Object 1 Mass of Object 2 (kg)
(kg)
Gravitational Force
(N)
1 x 1020
1 x 1020
1 x 1040 G
3 x 1020
1 x 1020
3 x 100 G
2 x 1020
2 x 1020
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20
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12 x 10 G
c) Use the table to explain how the masses of Objects 1 and 2 relate to the gravitational force
between them. Be sure to:
Describe the scenario.
Explain the table headings to introduce the data in the table.
Use the data to show a trend.
Summarize the information from the table in a sentence, showing the relationship between
the masses of objects and the gravitational force between the objects.
d) Place text in the notes section below the slide explaining the information presented on it. This text
will act as the script for your presentation.
e) Remember to save your work.

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Answer:

hryrbrhrururjrn djbrr he dvhd the ry rhr

urur

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jrurhr dye dhrb the yd rhd due sh dgd eye rh

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I dont know i was looking for the same answer for my project

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Answers

Answer:

  t = 1.177 10⁴ s

Explanation:

For this exercise we use the uniform motion relationships

         v = x / t

         t = x / v

let's reduce the magnitudes to the SI system

          v = 57 km / h (1000m / 1km) (1h / 3600s) = 15.833 m / s

          x = 186.4 km (1000m / 1 km) = 186.4 10³ m

let's calculate

         t = 186.4 10³ / 15.833

         t = 11.77 10³ s

         t = 1.177 10⁴ s

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