The rate constant for this first order reaction is 0.580 s^-1 at 400 C.
A ----> products
How long (in seconds) would it take for the concentration of A to decrease from 0.670 M to 0.320 M?

Answers

Answer 1

It would take approximately 1.415 seconds for the concentration of A to decrease from 0.670 M to 0.320 M at 400°C.

To calculate the time it takes for the concentration of A to decrease from 0.670 M to 0.320 M in a first-order reaction, we can use the first-order rate equation:

ln([A]_final / [A]_initial) = -k × t

Where:
- [A]_final is the final concentration (0.320 M)
- [A]_initial is the initial concentration (0.670 M)
- k is the rate constant (0.580 s^-1)
- t is the time in seconds

Plugging in the values, we get:

ln(0.320 / 0.670) = -0.580 × t

Now, solve for t:

t = ln(0.320 / 0.670) / (-0.580)

 ≈ 1.415 seconds

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Related Questions

5.690x10^3 miles to meters and give sig figs
Please help!

Answers

The equivalent of 5.690 × 10³ miles in metres is 9157167 metres. Details about metres and miles can be found below.

How to convert miles to metres?

Miles and metres are both units for measuring distance between two bodies or locations.

However, they can be converted interchangeably as follows:

1 mile = 1609.34 metres

According to this question, 5.690 × 10³ miles can be converted to metres as follows;

5.690 × 10³ × 1609.34 = 9157167 metres.

Therefore, the equivalent of 5.690 × 10³ miles in metres is 9157167 metres.

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one model that shows how energy passes from organism to organism is called? 1. an energy link 2. a food chain 3. a phytoplankton cycle

Answers

An energy link. Don’t know how to explain


A chemist develops a medicine
to help patients with thyriod
problems. In which branch of
chemistry is this chemist
working.

Answers

Answer:

Medicinal Chemistry

Explanation:

Medicinal Chemistry deals with the development, design and production of medicines.

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Blank + BaCl2 = BaSO4 + 2NaCl
How to complete this chemical reaction so that it is a Double displacement reaction

Answers

The blank is filled by Na₂SO₄, and the complete equation for the double displacement reaction is:

Na₂SO₄ + BaCl₂ = BaSO₄ + 2 NaCl

What is a double displacement reaction?

It is a reaction in which both reactants exchange anions and cations.

Let's consider the following incomplete double displacement reaction.

_____ + BaCl₂ = BaSO₄ + 2 NaCl

If we compare the left and right sides, we can see that the missing ions in the left side are Na⁺ and SO₄²⁻. Thus, the missing compound is Na₂SO₄. The complete equation is:

Na₂SO₄ + BaCl₂ = BaSO₄ + 2 NaCl

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what is the color of phenolphthalein in weak base

Answers

Answer:

Pink

Explanation:

Phenolphthalein is often used as an indicator in acid–base titrations. For this application, it turns colorless in acidic solutions and pink in basic solutions.

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Answer:

pink

Explanation:

Phenolphthalein is often used as an indicator in acid–base titrations. For this application, it turns colorless in acidic solutions and pink in basic solutions.

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Lead-202 has a half-life of 53,000 years. How long will it take for 15/16 of a sample of lead-202 to decay?.

Answers

Answer:

212 000 yrs

Explanation:

15/16 decay means 1/16 is left

 how many halflives is this?

                    (1/2)^n = 1/16

                       n = 4   half lives

4 half lives * 53 000 yr/ half life = 212 000 yrs

Answer:

c. 212,000 years

Explanation:

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N analyst prepared a sucrose solution by weighing 1kg of water and add 1.5kg sucrose.estimate the concentration of the resultant solution in (i) mass percent (ii) degree brix

Answers

The concentration of the solution in mass percent is 60%.

What is the mass percent?

The concentration of a substance can be expressed in mass percent. This refers to the percentage of the solute that is contained in the solution.

Thus we can write;

Mass percent = Mass of solute/ Mass of solution * 100/1

Mass percent = 1.5kg/1.5kg + 1 Kg * 100/1

Mass percent =  60%

Hence, the concentration of the solution in mass percent is 60%.

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The combustion of hydrogen gas releases 286 kJ per mol of hydrogen. If 13.0 L of hydrogen at STP was burned to produce electricity, how long would it power a 100-watt (W) light bulb

Answers

Combustion of hydrogen produces electricity:

It would power a 100-watt (W) light bulb in 27.66 min.

Calculation:

At STP conditions, we know that 1 mole of any gas is contained in 22.4L.

So let's make the operation:

The volume of one mole of gas at STP is 22.4 L

Then, 13.0 L may be the volume for (13.0) /22.4  = 0.58 moles.

The total energy is released = 0.58 x 286 kJ

Total energy = 165.98 kJ

Energy = Power x time

Time = energy / power

where power = 100W = 100 J/s

Therefore, Time = 165.98 kJ/ 100J/s = 1659.8 sec

Time = 1659.8 sec / 60 min = 27.66 min

∴ Time = 27.66 min

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1. Determine the molecular formula of an oxide of iron in which the mass of iron and oxygen are 69.9% and 30% respectively given that the molar mass of the oxide 159.898/mol, find the empirical and molecular formula.

2. a crystalline salt when heated becomes anhydrous and loses 51.2% of its weight the anhydrous salt analysis gave the percent composition as magnesium is equal to 20.0% and sulphur is equal to 26.66% and oxygen is equal to 53.33%.

3. In three moles of Ethane calculate the following
1. calculate number of carbon atoms.
2. number of moles of hydrogen atoms
3. number of molecules of Ethane.​

Answers

1a. The empirical formula of the compound is Fe₂O₃

1b. The molecular formula of the compound is Fe₂O₃

2a. The molecular formula of the anhydrous salt is MgSO₄

2b. The formula of the crystalline salt is MgSO₄.7H₂O

3i. The number of mole of carbon atoms in the compound is 6 moles

3ii. The number of mole of hydrogen atoms in the compound is 18 moles

3iii. The number of molecules in 3 moles of ethane is 1.806×10²⁴ molecules

1a. How to determine the empirical formulaFe = 69.9%O = 30%Empirical formula =?

Divide by their molar mass

Fe = 69.9 / 56 = 1.248

O = 30 / 16 = 1.875

Divide by the smallest

Fe = 1.248 / 1.248 = 1

O = 1.875 / 1.248 = 3/2

Multiply by 2 to express in whole number

Fe = 1 × 2 = 2

O = 3/2 × 2 = 3

Thus, the empirical formula of the compound is Fe₂O₃

1b. How to determine the molecular formulaEmpirical formula = Fe₂O₃Molar mass of compound = 159.89 g/molMolecular formula = ?

Molecular formula = empirical × n = molar mass

[Fe₂O₃]n = 159.89

[(56×2) + (16×3)]n = 159.89

160n = 159.89

n = 159.89 / 160

n = 1

Molecular formula = [Fe₂O₃]n

Molecular formula = [Fe₂O₃] × 1

Molecular formula = Fe₂O₃

2a. How to determine the molecual formula of the anhydrous salt

We'll begin by calculating the empirical formula

Mg = 20.0% S = 26.66% O = 53.33%Empirical formula =?

Divide by their molar mass

Mg = 20.0 / 24 = 0.83

S = 26.66 / 32 = 0.83

O = 53.33 / 16 = 3.33

Divide by the smallest

Mg = 0.83 / 0.83 = 1

S = 0.83 / 0.83 = 1

O = 3.33 / 0.83 = 4

Thus, the empirical formula of the anhydrous salt is MgSO₄

The molecular formula of the anhydrous salt can be obtained as follow:

Empirical formula = MgSO₄Molar mass of compound = 120 g/molMolecular formula = ?

Molecular formula = empirical × n = molar mass

[MgSO₄]n = 120

[24 + 32 + (16×4)]n = 159.89

120n = 120

n = 120 / 120

n = 1

Molecular formula = [MgSO₄]n

Molecular formula = [MgSO₄] × 1

Molecular formula = MgSO₄

2b. How to determine the formula of the crystalline saltWater (H₂O) = 51.2%Anhydrous salt (MgSO₄) = 100 - 51.2 = 48.8%Formula of crystalline salt =?

Divide by their molar mass

MgSO₄ = 48.8 / 120 = 0.4

H₂O = 51.2 / 18 = 2.8

Divide by the smallest

MgSO₄ = 0.4 / 0.4 = 1

H₂O = 2.8 / 0.4 = 7

Thus, the formula of the crystalline salt is MgSO₄.7H₂O

3i. How to determine the mole of carbon atoms in 3 moles of C₂H₆

1 mole of C₂H₆ contains 2 moles of carbon atoms.

Therefore,

3 moles of C₂H₆ will contain = 3 × 2 = 6 moles of carbon atoms

3ii. How to determine the mole of hydrogen atoms in 3 moles of C₂H₆

1 mole of C₂H₆ contains 6 moles of hydrogen atoms.

Therefore,

3 moles of C₂H₆ will contain = 3 × 6 = 18 moles of hydrogen atoms

3iii. How to determine the number of molecules

From Avogadro's hypothesis,

1 mole of ethane = 6.02×10²³ molecules

Therefore,

3 moles of ethane = 3 × 6.02×10²³ molecules

3 moles of ethane = 1.806×10² molecules

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Complete question

2. A crystalline salt when heated becomes anhydrous and loses 51.2% of its weight the anhydrous salt analysis gave the percent composition as magnesium is equal to 20.0% and sulphur is equal to 26.66% and oxygen is equal to 53.33%. Ccalculate the molecular formula of the anhydrous and the crystalline salt. The molecular weight of the anhydrous salt is 120

The elements of the group IA are termed as alkali metals, because their ___ are alkaline.

Answers

The answer is hydroxides.

The elements of the group IA are termed as alkali metals, because their hydroxides are alkaline.

If the dissociation constant of a weak acid is 7.1 x 10-5, at what ratio should you adjust the concentration of the weak acid and its conjugate base in order to prepare a buffer that has a pH of 4.15

Answers

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Gaseous nitrogen dioxide dissolved in warm liquid water to form hno3 and gaseous nitrogen monoxide enter a balanced equation for this reaction

Answers

Answer:

3 NO₂ (g) + H₂O (l) ---> 2 HNO₃ (aq) + NO (g)

Explanation:

Gaseous nitrogen dioxide = NO₂ (g)

Liquid water = H₂O (l)

Because the reactants are dissolved = HNO₃ (aq)

Gaseous nitrogen monoxide = NO (g)

In order for a reaction to be balanced, there needs to be an equal amount of each type of atom on both sides of the equation. The equation can be balanced by adding coefficients to modify the quantities of certain compounds.

The unbalanced equation:

NO₂ (g) + H₂O (l) ---> HNO₃ (aq) + NO (g)

Reactants: 1 nitrogen, 3 oxygen, 2 hydrogen

Products: 2 nitrogen, 4 oxygen, 1 hydrogen

The balanced equation:

3 NO₂ (g) + H₂O (l) ---> 2 HNO₃ (aq) + NO (g)

Reactants: 3 nitrogen, 7 oxygen, 2 hydrogen

Products: 3 nitrogen, 7 oxygen, 2 hydrogen

The half-life of silicon-32 is 710 years. If 40 grams is present now, how much will be present in 800 years

Answers

18 g of silicon-32 will be present in 800 years.

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and it's given by

                              [tex]N(t) = N_0 (\frac{1}{2}) ^\frac{t}{t_\frac{1}{2} }[/tex]

where,

[tex]N(t) =[/tex] quantity of the substance remaining

[tex]N_0 =[/tex]  the initial quantity of the substance

[tex]t =[/tex]  time elapsed

[tex]t_1_/_2 =[/tex] the half-life of the substance

From the given information we know:

The initial quantity of silicon-32 is 40 g.

The time elapsed is 800 years.

The half-life of silicone-32 is 710 years.

So, using the calculation above, we can determine how much silicon-32 is left.

                  [tex]N(t) = 40 (\frac{1}{2}) ^\frac{800}{710} \\N(t) = 40 (\frac{1}{2}) ^\frac{80}{71} \\\\N(t) = 18 g[/tex]

Therefore,18 g of silicon-32 will be present in 800 years.

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An oxygen gas tank holds 1 mole of gas at 10.0 atm of pressure. In order to reduce the pressure of the tank to 2.5 atm, moles must be released. How many moles will be left

Answers

Answer:

0.25 moles

Explanation:

To find the number of moles, you need to use a variation of the Ideal gas Law. The manipulated equation looks like this:

P₁ / n₁ = P₂ / n₂

In this formula, "P₁" and "n₁" represent the initial pressure and number of moles. "P₂" and "n₂" represent the final pressure and number of moles. You can find the final amount of moles by plugging the given values into the equation and simplifying.

P₁ = 10.0 atm                      P₂ = 2.5 atm

n₁ = 1 mole                          n₂ = ? moles

P₁ / n₁ = P₂ / n₂                                                <----- Equation

(10.0 atm) / (1 mole) = (2.5 atm) / n₂               <----- Insert values

10.0 = (2.5 atm) / n₂                                        <----- Divide 1 from 10.0

(10.0) x n₂ = 2.5 atm                                       <----- Multiply both sides by n₂

n₂ = 0.25                                                        <----- Divide both sides by 10.0

Based on their composition and structure list, CH2Cl2, CH3CH2CH3, and CH3CH2OH in order of: a. Increasing intermolecular forces b. Increasing viscosity c. Increasing surface tension

Answers

Based on their composition and structure list CH₂Cl₂, CH₃CH₂CH₃ and CH₃CH₂OH in order of (a) Increasing order of Intermolecular Forces are CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH. (b) Increasing order of Viscosity are CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH. (c) Increasing order of Surface Tension are: CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH.  

What is Intermolecular Forces ?

Intermolecular forces often abbreviated to IMF (or Secondary force) are the forces that hold atoms together with in a molecule. These forces are electrostatic in nature and exist between molecules.

Increasing order of Intermolecular Forces are: CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH.

How Intermolecular forces affect Viscosity ?

Higher the intermolecular force then higher the viscosity. Stronger the intermolecular force then stronger the viscosity.          

Increasing order of Viscosity are: CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH.    

How Intermolecular forces affect Surface tension ?

Stronger the intermolecular forces of liquid have higher surface tension. Surface tension depend upon the intermolecular forces.

Increasing order of Surface Tension are: CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH.  

Thus from the above conclusion we can say that Based on their composition and structure list CH₂Cl₂, CH₃CH₂CH₃ and CH₃CH₂OH in order of (a) Increasing order of Intermolecular Forces are CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH. (b) Increasing order of Viscosity are CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH. (c) Increasing order of Surface Tension are: CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH.  

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The formula c₂H₄o can represent?

Answers

Answer:

Ethylene oxide

Explanation:

Ethylene oxide is an organic compound with the formula C2H4O. It is a cyclic either and the simplest epoxied: a three-membraned ring consisting of one oxygen atom and two carbon atoms!

Two-thirds of a bone's weight is composed of calcium phosphate which interacts with calcium hydroxide to form crystals of __________.

Answers

Two-thirds of a bone's weight is composed of calcium phosphate which interacts with calcium hydroxide to form crystals of hydroxyapatite

The two component of bones are 33% organic matter and 67% inorganic matter( Calcium phosphate and  hydroxyapatite crystal).Calcium phosphate make up almost 2/3 of the bone's weight.Collagen fibers make up almost 1/3 of the bone's weight.The calcium phosphate interacts with calcium hydroxide to form crystals of hydroxyapatite, whose molecular formula is [tex]Ca_{10} (PO_{4} )_{6} (OH)_{2}[/tex]

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Relative humidity is described as: Group of answer choices a basically unused concept when it comes to weather topics. the amount of water vapor in the air at a given temperature expressed as a percentage of the water vapor capacity of the air. the amount of water vapor in the air compared to the normal amount. the amount of moisture in the air relative to your own sensible feelings.

Answers

Correct answer:

The relative humidity is best described as the amount of water vapor in the air at a given temperature expressed as a percentage of the water vapor capacity of the air.

What is relative humidity?

The ratio of the current absolute humidity to the highest absolute humidity is known as relative humidity (which depends on the current air temperature).

Water vapor is also measured by relative humidity, which is stated as a percentage but RELATIVE to the air's temperature. In other words, it is a comparison between the amount of water vapor that is actually present in the air and the maximum amount of vapor that is possible for the air at the current temperature.

With the same quantity of absolute/specific humidity, air will have a HIGHER relative humidity if it is cooler and a LOWER relative humidity if it is warmer because warm air may contain more water vapor (moisture) than cold air. The actual amount of moisture (absolute humidity) in the air is what we "feel" outside.

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The molar mass of calcium chloride (CaCl₂) is
110.98 g/mol. If you were to calculate the number
of moles in 23.4 g of CaCl₂, which example shows
the correct way to set up the calculation?
O
23.4 g CaCl₂x.
O
110.98 g CaCl₂
1mole CaCl₂
1 mole CaCl₂
110.98 g CaCl₂
23.4 g CaCl₂x-

Answers

The example that shows the correct way to set up the calculation will be the second example.

Number of moles

Mathematically:

  Number of moles = mass/molar mass

In this case, mass = 23.4 g and molar mass = 110.98 g/mol

Number of moles = 23.4/110.98 = 0.21 moles

Thus, the second example is the correct way.

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What is δs° for the reaction so2(s) no2(g) → so3(g) no(g)? substance s°(j/k • mol) so2(g) 248.5 so3(g) 256.2 no(g) 210.6 no2(g) 240.5

Answers

The value of ΔS° for reaction  is - 22.2 J/K.mol

[tex]SO_{2}(s)+NO_{2} (g)[/tex] → [tex]SO_{3}(g)+NO(g)[/tex]

Calculation,

Given value of S°(J/K.mol) for

[tex]SO_{2}(s)[/tex] = 248.5

[tex]NO_{2} (g)[/tex] = 240.5

[tex]NO(g)[/tex] = 210.6

[tex]SO_{3}(g)[/tex] = 256.2

Formula used:

ΔS° (Reaction) =  ∑S°(Product) - ∑S°(Reactant)

ΔS° = (256.2 + 210.6 ) - ( 248.5 + 240.5) = 466.8 - 489 = - 22.2 J/K.mol

The change in stander entropy of reaction is  - 22.2 J/K.mol. The negative sign indicates the that entropy of reaction is decreases when reactant converted into product.

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23
What is the mass of 3.01 x 10 atoms of neon?

Answers

Answer:

10.0 g

Explanation:

Avogadro's law states that there are 6.02 × 10²³ molcules in one mole of a substance, so we know that this sample has half a mole of neon.

The atomic mass of neon is 20.1797 g/mol, so 0.5 mol has a mass of about 10.0 g.

it is 10.09 g

According to Avogadro;

1 mole of neon would have 6.022 x 10^23 atoms

3.0 x 10^23 atoms of neon would have:

            3.0 x 10^23/6.022 x 10^23

                                         = 0.5 moles

mass of 0.5 moles neon = mole x molar mass

                                            = 0.5 x 20.18

                                             = 10.09 g

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How many atoms are in 76.15 grams of fe

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Answers

Answer:

See below

Explanation:

From periodic table

mole weight of Fe   is   55.845  gm / mole

76.15 gm  /  55.845 gm/mol   *  6.022 x 10^23  atoms/mole =

                8.212 x 10^23   atoms    ( four signif. digits)

When 3-methyl-2-butanone undergoes a baeyer-villiger oxidation reaction, the product is:_____.

Answers

When 3-methyl-2-butanone undergoes a baeyer-villiger oxidation reaction, the product is isopropyl acetate and methyl isobutyrate.

The Baeyer-villiger oxidation would seem to be a chemical reaction that uses peroxy acids using peroxides as the oxidant to transform a ketone into an ester or a lactone from such a cyclic ketone.

The main product produced by the Baeyer-Villiger oxidation of camphor using m-CPBA in buffer conditions could be created as a result of the migration of a tertiary bridgehead carbon as opposed to a methylene group.

By the reaction between 3-methyl-2-butanone with m-CPBA , will form isopropyl acetate and methyl isobutyrate.

It reaction can be shown as:

Therefore, when 3-methyl-2-butanone undergoes a Baeyer-villiger oxidation reaction, the product is isopropyl acetate and methyl isobutyrate.

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Determine the number of oxygen atoms in 1.00 g of CaCO3

Answers

Answer:

1.81 x 10²² atoms O

Explanation:

To find the number of oxygen atoms, you need to (1) convert grams CaCO₃ to moles CaCO₃ (via molar mass), then (2) convert moles CaCO₃ to moles O (via mole-to-mole ratio from formula subscripts), and then (3) convert moles O to atoms O (via Avogadro's Number). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the amount of sig figs in the given value.

Molar Mass (CaCO₃): 40.078 g/mol + 12.011 g/mol + 3(15.998 g/mol)

Molar Mass (CaCO₃): 100.083 g/mol

1 CaCO = 1 Ca and 1 C and 3 O

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

1.00 g CaCO₃           1 mole                 3 moles O           6.022 x 10²³ atoms
----------------------  x  ------------------  x  ----------------------  x  ------------------------------  =
                                100.083 g          1 mole CaCO₃                 1 mole

=  1.81 x 10²² atoms O

What is the de broglie wavelength of an electron (m = 9. 11 × 10-31 kg) moving at a velocity of 3. 0 × 107 m/s?

Answers

the de Broglie wavelength of the electron moving at a velocity of 3. 0 × 107 m/s is 2.4×10∧-11nm

lambda = h/mv

The de Broglie wavelength is defined as follows: lambda = h/mv, wherein the greek letter lambda represents the wavelength, h is Planck's consistent, m is the particle's mass and v is its pace. One may also explicit mv as the particle's momentum

according to wave-particle duality, the De Broglie wavelength is a wavelength manifested in all the gadgets in quantum mechanics which determines the chance density of locating the item at a given factor of the configuration area. The de Broglie wavelength of a particle is inversely proportional to its momentum

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Potassium secretion is linked to:________.
a. sodium reabsorption
b. glucose reabsorption
c. sodium secretion
d. chloride reabsorption
e. chloride secretion

Answers

chloride reabsorption

It is a long tube-like canal ,also called alimentary canal where digestion take place.

Answers

Explanation:

The alimentary canal is the long tube of organs - including stomaches and intestines

Answer: digestive strat.

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Provide the organometallic reagent that is needed to perform the transformation shown below. The reagent should be formatted as LiR or BrMgR, where R is an alkyl group written as a Condensed Formula. Do not use subscripts.

Answers

The correct answer is   [tex]LiCH_{3}CH(CH_{3} )CH_{3}[/tex] .

Organometallic reagent

Organometallic chemistry is the study of organometallic compounds, which are substances that contain at least one chemical bond between a carbon atom from an organic molecule and a metal. These substances include alkali, alkaline earth, and transition metals, as well as metalloids like boron, silicon, and selenium. In addition to links to organyl fragments or molecules, bonds to 'inorganic' carbon, such as those to carbon monoxide (metal carbonyls), cyanide, or carbide, are also typically regarded as organometallic. Although they are not strictly speaking organometallic compounds, some similar compounds, such as transition metal hydrides and metal phosphine complexes, are frequently included in discussions of such substances. The phrase "metalorganic compound," which is comparable but different, describes molecules that contain metals but do not have direct metal-carbon bonds but do have organic ligands.

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How many sucrose molecules are in 3.0 moles of sucrose?

Answers

Answer: No of molecule of sucrose = 1.806 X 10^24

Explanation:

No. of molecules = No. of moles X NA

No. of molecule of sucrose = 3 moles X 6.02 X 10^23

No of molecule of sucrose =18.06 X 10^23

No of molecule of sucrose =1.806 X 10^24

Answer:

1.80 × 10²⁴ Molecules of Sucrose

A sample of neon gas in a bulb is at 149.05 °C and 349.84 kPa. If the pressure drops
to 103.45 kPa, what is the new temperature (in °C)? Provide your answer to two
decimals.

Answers

The new temperature (in °C) of the gas, given the data is –148.20 °C

Data obtained from the question Initial temperature (T₁) = 149.05 °C = 149.05 + 273 = 422.05 KInitial pressure (P₁) = 349.84 KPa Volume = constant New pressure (P₂) = 103.45 KPaNew temperature (T₂) =?

How to determine the new temperature

The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

Since the volume is constant, we have:

P₁ / T₁ = P₂ / T₂

349.84 / 422.05 = 103.45 / T₂

Cross multiply

349.84 × T₂ = 103.45 × 422.05

Divide both side by 349.84

T₂ = (103.45 × 422.05) / 349.84

T₂ = 124.80 K

Subtract 273 from 124.80 K to express in degree celsius

T₂ = 124.80 – 273

T₂ = –148.20 °C

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