The sample calculation for iron oxide in the IDEAS section of this experiment used known atomic weights to calculate an empirical formula. However, early chemists did not have any references in which they could look up atomic weights. Instead, they guessed at the formulas of compounds and measured the percent compositions of elements in compounds in order to calculate atomic weights. Calculate an atomic weight for iron using the hypothetical formula Fe101 and the composition data given in the example in the IDEAS section. You may assume the atomic weight of oxygen is known from other sources to be 16 amu.

Answer:

The volume for this is 29.7

Explanation:

Trust me on this I'm an expert

Answer:

a g i

Explanation:

nnj

Solution :

Given data :

p = 315612 Pa

[tex]$V_1=7.07 \ m/sec$[/tex]

At exit of B,

p = [tex]$P_{atm}$[/tex]

[tex]$V_B = 26.1 \ m/sec$[/tex]

At exit of A,

[tex]p=P_{atm}[/tex]

[tex]$V_{A} = 26.1 \ m/s$[/tex]

We need to determine X component of force ([tex]$R_x$[/tex]) to hold in its place.

From figure,

[tex]$\sum F_x = m_0'V_{0x} - m_iV_{ix} $[/tex]

[tex]$=F_x+P_1A_1\sin 30=-mVA-mV_1 \sin 30$[/tex]

[tex]$=F_x=-pA_1\sin 30-m_AV_AA-m_B \sin30$[/tex]

Substitute all the values,

[tex]$=F_x=[-315612 \times \frac{\pi}{4}(0.3)^2 \sin 30]-[26.1 \times 1000 \times 26.1 \frac{\pi}{4}(0.1)^2]-[7.07 \times 1000\times 0.5 \sin 30]$[/tex][tex]$=F_x = -11154.64-5350.21-1767.28$[/tex]

[tex]$F_x = -18.2733 \ kN$[/tex]

Therefore, the force required to hold the nozzle in its place along horizontal direction.

[tex]$F_x = -18.2733 \ kN$[/tex]

Answer:

here is your answer

Explanation:

1. First observe the syllabus for all subjects.

2. Then gather all your books

3. For a particular exam read the book related to it ( if possible read early in the morning.

4. After that write the things you learnt by reading.

5. Finally give your exams by giving it all

HOPE IT HELPS......

OM NAMO SHIVAYE

Answer:

Answer to the following is as follows;

Explanation:

A request for proposal is a documentation that invites prospective contractors to submit business opportunities to an agency or corporation interested in procuring a commodities, product, or valuable resource through a bid procedure.

A request for proposal (RFP) is a commercial document that introduces a project, defines it, and invites eligible contractors to compete on its completion.

Answer:

In the clevis shown in Fig. 1-11b, find the minimum bolt diameter and the minimum thickness of each yoke that will support a load P = 14 kips without exceeding a shearing stress of 12 ksi and a bearing stress of 20 ksi.

127-clevis-double-shear-bolt.gif

Solution 127

Hide Click here to show or hide the solution

127-fbd-clevis-double-shear-bolt.gifFor shearing of rivets (double shear)

P=τA

14=12[2(14πd2)]

d=0.8618in → diameter of bolt answer

For bearing of yoke:

P=σbAb

14=20[2(0.8618t)]

t=0.4061in → thickness of yoke answer

Answer:

Time required = 287.2 secs  

Explanation:

Volume  of room = 25 * 10 * 4 = 1000 m^3

power consumed by pump = 15 kW

T1 ( initial temperature ) = 12°C

P1 ( Initial pressure ) = 1 bar

COPhp = 3

Calculate time taken to raise room Temp to 27°C

average heat supplied ( ∅ ) = COPhp * power consumed by pump

                                             = 3 * 15 = 45 kW

Time required can be calculated using the relation below

∅t = P*V*Cv ( T2 - T1 )   [ p = 1.2 kg/m^3 , Cv = 0.718 KJ/kg ( air properties ) ]

45 * 10^3 ( t )  = 1.2*1000* 718 ( 27 - 12 )

∴ solving for t

t = 287.2 secs  ≈ 4.79 mins

Answer:

[tex]n=5.36kg[/tex]

Explanation:

From the question we are told that:

Volume [tex]V=2.5m^3[/tex]

Pressure[tex]\rho=500Kpa[/tex]

Temperature [tex]T=28^o[/tex]

Atmospheric pressure [tex]\rho_{atm} =97 kPa.[/tex]

Generally the equation for an Ideal gas is mathematically given by

 [tex]PV=nRT[/tex]

Therefore

 [tex]n=\frac{500*2.5}{8.314*28}[/tex]

 [tex]n=5.36kg[/tex]

Answer:

ay man ima be real, i just need the points yo

Answer:

 0.287

Explanation:

Design-stage uncertainty can be expressed as :

Ud = √ Uo^2 + Uc^2 ------ ( 1 )

where : Uo = 1/2( resolution value ) = 1/2 * 0.01 V = 0.005 V

Uc = √(0.10)^2 + (0.10)^2 + (0.15)^2 + (0.20)^2  = 0.287

back to equation 1

Ud = √ ( 0.005)^2 + ( 0.287 )^2 =  0.287

Answer:

0.287

Explanation:

Answer:

Minimum city gas mileage is 15

Explanation:

Minimum city gas mileage among 13 different car sizes in 2008 is 15.

Answer:

a)  ∝  and β

   The phase compositions are :

    C[tex]_{\alpha }[/tex] = 5wt% Sn - 95 wt% Pb

    C[tex]_{\beta }[/tex] =  98 wt% Sn - 2wt% Pb

b)

The phase is; ∝  

The phase compositions is;   82 wt% Sn - 91.8 wt% Pb

Explanation:

a) 15 wt% Sn - 85 wt% Pb at 100⁰C.

The phases are ; ∝  and β

The phase compositions are :

C[tex]_{\alpha }[/tex] = 5wt% Sn - 95 wt% Pb

C[tex]_{\beta }[/tex] =  98 wt% Sn - 2wt% Pb

b) 1.25 kg of Sn and 14 kg Pb at 200⁰C

The phase is ; ∝  

The phase compositions is;  82 wt% Sn - 91.8 wt% Pb

Csn = 1.25 * 100 / 1.25 + 14 = 8.2 wt%

Cpb = 14 * 100 / 1.25 + 14 = 91.8 wt%

Answer:

can you translate

Explanation:

what Is that?

Answer:

From what year did 3.5G enter Vietnam?

Explanation:

Vietnam does not have 3.5G network. MobiFone's first trial with 3.5G technology on this band was able to cover the whole waters of Vung Tau and Con Dao in August 2014.

This question is incomplete, the complete question is;

To convert from the U.S. Customary (FPS) system of units to the SI system of units. A first-year engineering student records three separate measurements as 653 lb, 69.0 mi/h, and 293 × 10⁶ ft². Suppose this engineering student has to turn in the results, but the professor only accepts results given in SI units.  

Required:

What is the area measurement, 293 × 10⁶ ft², in SI units?

293 × 10⁶ ft² = ?km²

Answer:

the area measurement is  27.221 km²

Explanation:

Given the data in the question;

What is the area measurement, 293 × 10⁶ ft², in SI units

we are to the result of the measured area from ft² to km²

we know that;

1 meter = 3.2808 ft

1 km = 1000 m

1 ft = (1 / 3.2808)m

1 m = ( 1/1000 ) km

since our measured are is 293 × 10⁶ ft²

hence

A = 293 × 10⁶ × [ (1 / 3.2808)m ]²

A = 27221252.74 m²

A = 27221252.74 × [ ( 1/1000 ) km ]²

A = 27.221 km²

Therefore, the area measurement is  27.221 km²

Answer:

is there a picture of the figure?

Answer:

The costs to run the dryer for one year are $ 9.03.

Explanation:

Given that the clothes dryer in my home has a power rating of 2250 Watts, and to dry one typical load of clothes the dryer will run for approximately 45 minutes, and in Ontario, the cost of electricity is $ 0.11 / kWh, to calculate the costs to run the dryer for one year the following calculation must be performed:

1 watt = 0.001 kilowatt

2250/45 = 50 watts per minute

45 x 365 = 16,425 / 60 = 273.75 hours of consumption

50 x 60 = 300 watt = 0.3 kw / h

0.3 x 273.75 = 82.125

82.125 x 0.11 = 9.03

Therefore, the costs to run the dryer for one year are $ 9.03.

Answer:

-Khái niệm:

Đo dòng điện là sử dụng các dụng cụ như ôm kê, vôn kế, ampe kế, tần số kế… để xác định các đại lượng vật lý của dòng điện

-Đo lường điện để làm gì?

Phát hiện hư hỏng sự cố trong mạch điện và các thiết bị vi mạch

Xác định các giá trị cần đo

Đánh giá chất lượng của các thiết bị sau sản xuất

Xác định thông số kỹ thuật của thiết bị

-Phân loại dụng cụ đo điện: Hiên nay có 2 phương pháp phân loại chính

a. Theo nguyên lý làm việc

Dụng cụ đo kiểu điện từ

Dụng cụ đo kiểu điện động

Dụng cụ đo kiểu cảm ứng

Dụng cụ đo kiểu từ điện

b. Theo đai lượng, giá trị cần đo

+Đo điện năng: Ví dụ công tơ điện

+Đo điện áp: Ví dụ: Vôn kế

+Đo dòng điện: Ví dụ: Ampe kế

+Đo công suất: Oát kế

+Đo điện trở: Ôm kế

Sai số khi đo: Khi đo lường luôn xảy ra các sai số

Sai số tương đối: Là tỷ lệ % của sự chênh lệch giữa giá trị đo được và giá trị thự

A find the ganeral solution to this equation

An object moving through the water has an initial velocity of 40 m/s. Two seconds later, the velocity has decreased to 30 m/s. The velocity after ten seconds is 0.

Velocity is defined as the speed at which an object's position changes in relation to time and a frame of reference.  Speed is the rate at which an object travels along a path over time, whereas velocity is the speed and direction of an item's motion. In other words, speed is a scalar value, but velocity is a vector.

As given

Initial velocity = 40 m / sec

Velocity after 2 seconds = 30 m / sec

So the velocity after 10 seconds will be = 0 m / sec

That is the object will stop moving.

Thus. an object moving through the water has an initial velocity of 40 m/s. Two seconds later, the velocity has decreased to 30 m/s. The velocity after ten seconds is 0.

To learn more about velocity, refer to the link below:

https://brainly.com/question/28738284

#SPJ2

Your question is incomplete, but probably your complete question was

Answer:

Una canica de masa 15g, con velocidad horizontal de 10 m/s impacta a otra de masa de 8g que se encuentra en el piso y en reposo. Suponga que el movimiento ocurre en la linea que une sus centros. Encuentra la velocidad de cada canica inmediatamente despues de la colisionExplanation:

Answer:

a) 1,607,973.9  K/W

b)

i)  0.3082 = 30.82%

ii)  0.1821 = 18.21%

iii)  0.1293 = 12.93%

iv)  0.1002 = 10.02%

Explanation:

Value of thermal conductivity ( calculated value ) KCN  = 3113 W/m-k

Thermal conductivity ( theoretical value ) K = 4500 W/m-k

Island separation = 5 μm

a) Determine the thermal contact resistance

Resistance due to contact between carbon nano tube and top surfaces can be determined using the relation below

( I / A*K ) + 2Rc  =  ( l / A*KCN ) ------- ( 1 )

where ; I = 5 * 10^-6 m

A = π * ( 14 * 10^-9 )^2 m^2  = 153.93 * 10^-18 , K = 4500 , KCN = 3113

input  values into equation 1 above

hence Rc = 1,607,973.9  K/W

b) Determine fraction of total resistance between heated and sensing

fraction of total resistance ; f1 = [tex]\frac{2 Rc}{I/KA + 2Rc}[/tex]

where : Rc = 1607973.9,  K = 4500, A =  153.93 * 10^-18 ,  

i) for I = 5 * 10^-6 m  

fraction = 0.3082 = 30.82%

ii) for I = 10 * 10^-6 m

fraction = 0.1821 = 18.21%

iii) for I = 15 * 10^-6 m

fraction = 0.1293 = 12.93%

iv) for  I = 20*10^-6

fraction = 0.1002 = 10.02%

Answer:

A tunnel built in soft ground—such as clay, silt, sand, gravel or mud—requires specialized techniques compared to hard rock, to compensate for the shifting nature of the soil.

It's from web...

Soft ground tunneling describes the additional measures needed when Microtunneling through soil conditions that are vulnerable to collapse. ... This process ensures tunneling can happen effectively in soft grounds.

It's from me...

Answer:

Therefore the value of the line currents IR, IY, and IB are

[tex]I_{R}=I_{1}=83\angle 6.87^{o}A\\I_{B}=-I_{2}=-71.88\angle-23.13^{o}A\\I_{Y}=I_{2}-I_{1}\\I_{Y}=-I_{2}=41.50\angle113.3^{o}A[/tex]

Explanation:

Apply KVL for loop 1  

[tex]415\angle 120^{o}=\left ( 3+j4+3+j4 \right )I_{1}-\left ( 3+j4 \right )I_{2}\\415\angle 120^{o}=\left ( 6+j8 \right )I_{1}-\left ( 3+j4 \right )I_{2}\\415\angle 120^{o}=\left ( 10\angle 53.13^{o} \right )I_{1}-\left ( 5\angle 53.13^{o}\right )I_{2} \rightarrow \left ( 1 \right )[/tex]

Apply KVL for loop 2

[tex]415\angle 0^{o}=\left ( 3+j4+3+j4 \right )I_{2}-\left ( 3+j4 \right )I_{1}\\415\angle 0^{o}=\left ( 6+j8 \right )I_{2}-\left ( 3+j4 \right )I_{1}\\415\angle 0^{o}=\left ( 10\angle 53.13^{o} \right )I_{2}-\left ( 5\angle 53.13^{o}\right )I_{1} \rightarrow \left ( 2 \right )[/tex]

Solving the above equations,

[tex]415\angle 120^{o}+830\angle 0^{o}=\left ( 10\angle 53.13^{o} \right )I_{1}-\left ( 5\angle 53.13^{o}\right )I_{2} +\left ( 20\angle 53.13^{o}\right )I_{2}- \left ( 10\angle 53.13^{o} \right )I_{1}\\415\angle 120^{o}+830\angle 0^{o}=\left ( 20\angle 53.13^{o}\right )I_{2}- \left ( 10\angle 53.13^{o} \right )I_{2}\\415\angle 120^{o}+830\angle 0^{o}=\left ( 10\angle 53.13^{o} \right )I_{2}\\I_{2}= 71.88\angle -23.13^{o}A[/tex]&

[tex]415\angle 0^{o}=\left ( 10\angle 53.13^{o} \right ) \times 71.88\angle -23.13^{o}-\left ( 5\angle 53.13^{o} \right )I_{1}\\415\angle 0^{o}=718.8\angle 30^{o}-\left ( 5\angle 53.13^{o} \right )I_{1}\\\left ( 5\angle 53.13^{o} \right )I_{1}=415\angle 60^{o}\\I_{1}= 83\angle 6.87^{o}A[/tex]

Hence,

[tex]I_{R}=I_{1}=83\angle 6.87^{o}A\\I_{B}=-I_{2}=-71.88\angle-23.13^{o}A\\I_{Y}=I_{2}-I_{1}\\I_{Y}=-I_{2}=41.50\angle113.3^{o}A[/tex]

Answer:

Probability of no red ball from 4 balls = 0.1258 (Approx.)

Explanation:

Given:

Number of black ball = 3

Number of red ball = 5

Number of green ball = 6

Find:

Probability of no red ball from 4 balls

Computation:

Probability of no red ball from 4 balls = 9c4 / 14c4

Probability of no red ball from 4 balls = 126 / 1001

Probability of no red ball from 4 balls = 0.12587

Probability of no red ball from 4 balls = 0.1258 (Approx.)

Answer:

a. 67607.9psi

b. 123278.33

Explanation:

to get the yield strength of the material

= load/ cross sectional area

cross sectional area = π * 0.253²/4

= 0.0502927

The yield strenght

= 3400/0.0502927

= 67609.9 psi

b. the uts of the material

= maximum load/cross sectional area

= 6200/0.0502927

= 123278.33

Answer:

1 NAND gate

Explanation:

The minimum number of 2 input NAND gates that can be used to implement the combinational circuit = 1

The only true combinations conditions that can produce a false result ( i.e. condition/result different from the expected result as stated in the question )

Sensor 2 activated + Emergency switch pressed = False ( Line will keep moving )

Answer: hello attached below is the question properly written

a) 2670 Kw

b) product will be made up of vapor and liquid

c) Product will be a super cooled liquid

Explanation:

mass Flow rate ( m ) = 175 kg/min

pressure = 1 atm

molecular weight of ethylene glycol ( mw ) = 62.07 g/mol

enthalpy of vaporization ( ΔHv ) = 56.9 KJ/mol

Using values from the table 8.1 related to the question

a) Determine the rate at which heat must be transferred from condenser

Using values from the table 8.1 related to the question

ΔH = 2670 Kw

b) If heat is transferred  at a lower temperature the product will be made up of vapor and liquid

c) If heat was transferred at a higher temperature the product will be a super cooled liquid

Answer:

0.2063

Explanation:

Given data:

packing factor = 0.5

percentage of reduction of powders = 70%

Calculate the final porosity

after sintering Bulk specific volume = 0.9 * 0.7 = 0.63

assuming true specific volume = 1

packing factor = 0.5 , bulk specific volume = 2

packing factor after pressing and sintering

= 1 / ( 2 * 0.63 ) = 0.7937

hence : porosity = 1 - packing factor

                            = 1 - 0.7937 = 0.2063