The steam requirements of a manufacturing facility are being met by a boiler whose rated heat input is 5.5 x 3^106 Btu/h. The combustion efficiency of the boiler is measured to be 0.7 by a hand-held flue gas analyzer. After tuning up the boiler, the combustion efficiency rises to 0.8. The boiler operates 4200 hours a year intermittently. Taking the unit cost of energy to be $4.35/10^6 Btu, determine the annual energy and cost savings as a result of tuning up the boiler.

Answers

Answer 1

Answer:

Energy Saved = 6.93 x 10⁹ Btu

Cost Saved = $ 30145.5

Explanation:

The energy generated by each boiler can be given by the following formula:

[tex]Annual\ Energy = (Heat\ In)(Combustion\ Efficiency)(Operating\ Hours)[/tex]

Now, the energy saved by the increase of efficiency through tuning will be the difference between the energy produced before and after tuning:

[tex]Energy\ Saved = (Heat\ In)(Efficiency\ After\ Tune - Efficiency\ Before\ Tune)(Hours)[/tex][tex]Energy\ Saved = (5.5\ x\ 3\ x\ 10^{6}\ Btu/h)(0.8-0.7)(4200\ h)[/tex]

Energy Saved = 6.93 x 10⁹ Btu

Now, for the saved cost:

[tex]Cost\ Saved = (Energy\ Saved)(Unit\ Cost)\\Cost\ Saved = (6.93\ x\ 10^{9}\ Btu)(\$4.35/10^{6}Btu)\\[/tex]

Cost Saved = $ 30145.5


Related Questions

You have available three blocks of different material, at various temperatures. They are, respectively, a 2 kg block of iron at 600 K, a 3 kg block of copper at 800 K and a 10 kg block of granite at 300 K. The heat capacities for the three materials are 0.460 (iron), 0.385 (copper), and 0.790 (granite), in kj/(kg*K), all independent of temperature. For solids, the heat capacities at constant pressure and constant volume can be assumed to be equal, Cp=Cv. what is the minimum temperature that could be obtained in any one of the block? what is the maximum temperature that could be obtained? no heat or work interactions with the enviroment are allowed.

Answers

Answer:

max temp = 711.32 k

mini temp = 331.29 k

Explanation:

Given data:

2kg block of Iron : temperature = 600k , C = 0.460 kJ/kgk

3 kg block of copper : temp = 800k ,  C = 0.385 KJ /kgk

10 kg block of granite : temp = 300k , C = 0.790 KJ/kgk

Cp = Cv at constant pressure and constant volume

Determine the minimum temperature that is obtained in any one of the block

considering the heat transfer equation

Q = mC ( T2 - T1 )

attached below is a detailed solution of the problem

A frequenter of a pub had observed that the new barman poured in average 0.47 liters of beer into the glass with a standard deviation equal to 0.09 liters instead of a half a liter with the same standard deviation. The frequenter had used a random sample of 47 glasses of beer in his experiment. Consider the one-sided hypothesis test for volume of beer in a glass: H0: u=0.5 against H1: u<0.5. Determine the P-value of this test.
Round your answer to four decimal places (e.g. 98.7654).

Answers

Answer:

P-value = 0.0011

Explanation:

Formula for the test statistic is;

z = (x¯ - μ)/(σ/√n)

We have;

Sample mean;x¯ = 0.47

Population mean; μ = 0.5

Standard deviation; σ = 0.09

Sample size; n = 47

Thus;

z = (0.46 - 0.5)/(0.09/√47)

z = -3.05

From z-distribution table attached, the p-value corresponding to z = -3.05 is;

P = 0.00114

To four decimal places gives;

P-value = 0.0011

pls help me it’s due today

Answers

Answer:

C. 14.55

Explanation:

12 x 10 = 120

120 divded by 10 is 12

so now we do the left side

7 x 3 = 21 divded by 10 is 2

so now we have 14

and the remaning area is 0.55

so 14.55

Another name for a load-center distribution system is a A. primary radial system. B. complex radial system. C. split-radial system. D. dual-radial system.

Answers

Answer:

A

Explanation:

Primary radial system

QUESTION 4:
4.1
Name FOUR principles of kinetic friction ​

Answers

Answer:

The force of friction always acts in a direction, opposite to that in which the body is moving.

The magnitude of kinetic friction bears a constant ratio to the normal reaction between the two surfaces. ...

For moderate speeds, the force of friction remains constant.

Answer:

Explanation:Kinetic friction is a force that acts between moving surfaces. An object that is being moved over a surface will experience a force in the opposite direction as its movement. The magnitude of the force depends on the coefficient of kinetic friction between the two kinds of material.

A contractor excavates 10,000 m3 soil at moist unit weight of 17.5 kN/m3 and moisture content of 10% from a borrow pit and transports it to a project site. The project has an area of 20,000 m2 to be filled with this compacted soil. If the required dry unit weight and moisture content of the compacted soil are 18.3 kN/m3 and 12.5% (assume there is no soil loss during transportation and compaction), what is the thickness of the compacted soil and how much water needs to be added?

Answers

Answer:

Part A

The thickness of the compacted soil is approximately 4.3467 × 10⁻¹ m

Part B

The weight of water to be added is approximately 19886.[tex]\overline{36}[/tex] kN, the volume of the water added is approximately 2,027.77 m³

Explanation:

The parameters of the soil are;

The volume of sol the excavator excavates, [tex]V_T[/tex] = 10,000 m³

The moist unit weight, W = 17.5 kN/m³

The moisture content = 10%

The area of the project, A = 20,000 m²

The required dry unit weight = 18.3 kN/m³

The required moisture content = 12.5%

Part A

Therefore, we have;

The moist unit weight = Unit weight = ([tex]W_s[/tex] + [tex]W_w[/tex])/[tex]V_T[/tex]

The moisture content, MC = 10% = ([tex]W_w[/tex]/[tex]W_s[/tex]) × 100

∴ [tex]W_w[/tex] = 0.1·[tex]W_s[/tex]

∴ The moist unit weight = 17.5 kN/m³ = ([tex]W_s[/tex] + 0.1·[tex]W_s[/tex])/(10,000 m³)

1.1·[tex]W_s[/tex] = 10,000 m³ × 17.5 kN/m³ = 175,000 kN

[tex]W_s[/tex] = 175,000 kN/1.1 = 159,090.[tex]\overline{09}[/tex] kN

For the required soil, we have;

The required dry unit weight = 18.3 kN/m³ = [tex]W_s[/tex]/[tex]V_T[/tex] = 159,090.[tex]\overline{09}[/tex] kN/[tex]V_T[/tex]

[tex]V_T[/tex] = 159,090.[tex]\overline{09}[/tex] kN/(18.3 kN/m³) ≈ 8,693.4923 m³

The total volume of the required soil ≈ 8,693.4923 m³

Volume [tex]V_T[/tex] = Area, A × Thickness, d

∴ d =  [tex]V_T[/tex]/A

d = 8,693.4923 m³/(20,000 m²) ≈ 4.3467 × 10⁻¹ m

The thickness of the compacted soil ≈ 4.3467 × 10⁻¹ m

Part A

The moisture content, MC = 12.5% = ([tex]W_w[/tex]/[tex]W_s[/tex]) × 100

[tex]W_w[/tex] = [tex]W_s[/tex] × MC/100 = 159,090.[tex]\overline{09}[/tex] kN × 12.5/100 = 19886.[tex]\overline{36}[/tex] kN

The weight of water to be added, [tex]W_w[/tex] = 19886.[tex]\overline{36}[/tex] kN

Where the density of water, ρ = 9.807 kN/m³

Therefore, we have;

The volume of water, V = [tex]W_w[/tex]/ρ

∴ V = 19886.[tex]\overline{36}[/tex] kN/(9.807 kN/m³) ≈ 2027.77 m³

The volume of water, V ≈ 2027.77 m³

Build a 32-bit accumulator circuit. The circuit features a control signal inc and enable input en. If en is 1 and inc is 1, the circuit increments the stored value by an amount specified by an input A[31:0] on the next clock cycle. If en is 1 and inc is 0 the circuit decrements the stored value by the amount specified in the input A on the next clock cycle. If en is 0, the circuit simply stores its current value without modification. The circuit has the following interface:______.
Input clock governs the state transitions in the circuit upon each rising edge.
Input clear is used as a synchronous reset for the stored value.
Input inc controls whether the value stored is to be incremented or decremented.
Input en is a control signal that activates the values increment/decrement
Input A determines how much to increment or decrement by
Output value is a 32-bit signal that can be used to read the stored value at any time.
* Note: Use any combination of combinational or sequential logic. It may be helpful to look into D Flip Flops and Registers.

Answers

Sorry need.points I'm new

Other Questions
Write 2 9/10 as an improper fraction.pls hurry!and pls explain how to do it Please help and show work PLEASE HELPPPP What is the relationship between mutation, the cell cycle, and cancer? Select all statements that apply.A Mutated genes typically allow cells to respond to checkpoint proteins that halt the cell cycle, thus avoiding formation of tumors.B. As a result of unregulated cell cycles, cells may become cancerous, meaning that the cells grow and divide uncontrollably.Cancerous cells may form malignant tumors that invade and destroy surrounding healthy tissue.D. Mutated, defective genes may cause cells to become unable to respond to signals that regulate the cell cycle. how many formula units of lead (IV) phosphate in 1.75g Izzy deposits any money the team has left at the end of the season into a savings account, where it will remain until next season. This year, Izzy deposited $440 into a savings account that earns 312% simple interest. If the next season starts in 6 months, how much money will be in the account then? Explain Simplify (3v^5+8v^310v^2 )(12v^5 +4v^3+14v^2 ) . Write answer in standard form.please help Which of the following sentences hasa Nonessential clause?A. Every student who passed the test can go to recess.B. All runners who are eligible for this race line uphere.C. New reporters, which are actually quite a few,should report to the registration desk.D. The swimmer who won the Olympic Gold Medal wasMichael Phelps. If two lines have the same y intercept and the same slope will they intercept at exactly one point?True or false or partly true Mark the absolute maximum point of the graph Watch help videoFind the y-coordinate of the y-intercept of the polynomial function defined below.f(x) = 2x(x - 3)Answer:Submit Answer Create a food chain directions the following organisms Someone please help with this! I'll give brainliest the metamorphosis events and actions that occurred I need help, please don't do it for the points. The parts of the rhetorical triangle are in a ______________ relationship.A. staticB. adversarialC. dynamicD. fixed find the y-coordinate of the y-intercept of the polynomial function defined below f(x)=2x(x^2+3) Please help me, I can't figure this out. You have a 450.0 mL balloon filled with 0.0184 moles of Helium gas. The volume of the balloon will change, but the pressure of the gas inside will always match the 1.00 atm pressure outside. If the balloon is kept at a constant 25oC, how many moles of gas must you remove to shrink the balloon down to 200.0 mL? Jerry buys a new cell phone and signs up for a yearly cell phone plan. The cell phone costs $329 and the yearly plan costs 490 per year for every year he uses the cell phone. The only costs associated with the cell phone are the purchase price and the cost of the yearly cell phone plan.a) Describe the annual cost of the cell phone per year as a function of the number of years he uses the cell phone.b) What happens to the average price per year the longer Jerry holds onto this plan and explain why? 4x - 8 = 32?!!!! please help me plss 8. You throw a ball downward 40 feet per second from a buildingthat is 256 feet above the ground. How long will it takethe ball to hit the ground?