Answer:
please type your questions well
Sonia takes a 45
-mile walk every day.
What part of her walk has she completed once she has walked 35
mile?
She has completed 3/4 of her walk, she has walked 3/5 miles.
We are given that Sonia takes 4/5 mile walk everyday.
What is a proportion?A proportion is a fraction of a total amount, the relations between variables, could be direct or inverse proportional, can be built to find the desired measures in the problem.
Consider 4/5 represent the 100 percent.
Using the proportion we can find which part of her walk she completed once she has walked 3/5 miles.
Find out what percentage represent 3/5
Let x be the percentage that represent 3/5
Then convert to fraction number
4/500 = 3/5x
x = 75
Therefore, the value of x in percentage is 75 percent.
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The complete question is
Sonia takes a 4/5 mile walk every day. What part of her walk has she completed once she has walked 3/5 miles
Grade level and gender Describing the sampling distribution of ħi - Pz PROBLEM: In a very large high school, the junior class has 800 students, 54% of whom are female. The senior class has 700 students, 49% of whom are female. The student council selects a random sample of 40 juniors and a separate random sample of 35 seniors. Let P, - ., be the difference in the sample proportions of females. (a) What is the shape of the sampling distribution of p,, - P..? Why? (b) Find the mean of the sampling distribution. (c) Calculate and interpret the standard deviation of the sampling distribution.
The size of sample are both large enough 40 and 35. The mean and standard deviation of given data is 0.05 and 0.105 respectively.
The shape of the sampling distribution of [tex]\hat{p}_j - \hat{p}_s[/tex]is approximately normal, according to the Central Limit Theorem. This is because the sample sizes are both large enough (40 and 35, respectively) and the population proportions are unknown but assumed to be independent.
The mean of the sampling distribution is the difference in the population proportions of females, which is 0.54 - 0.49 = 0.05.
The standard deviation of the sampling distribution can be calculated as:
[tex]$\sqrt{\frac{\hat{p}_j(1 - \hat{p}_j)}{n_j} + \frac{\hat{p}_s(1 - \hat{p}_s)}{n_s}}$[/tex]
where [tex]\hat{p}_j = 0.54$, $n_j = 40$, $\hat{p}_s = 0.49$, and $n_s = 35$.[/tex]Plugging in these values, we get:
[tex]$\sqrt{\frac{0.54(1 - 0.54)}{40} + \frac{0.49(1 - 0.49)}{35}} \approx 0.105$[/tex]
Interpretation: The standard deviation of the sampling distribution tells us how much we can expect the sample proportion difference to vary across different random samples. In this case, we can expect the difference between the sample proportions of females in the junior and senior classes to vary by about 0.105 on average across different samples.
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14. Which One Doesn't Belong? Circle the
system of equations that does not belong
with the other two. Explain your reasoning.
y=x+6
y = -x + 2
3x + y = -1
y = 4x + 6
y=-4x-3
y + 4x = -5
The system of equation that does not belong to the other two is the third system of equations; y = -4·x - 3, y + 4·x = -5, This is so because, the third system has no solutions.
What are linear system of equations?A linear system of equations consists of two or more linear equations that consists of common variables.
The possible equations are;
y = x + 6, y = -x + 2
3·x + y = -1, y = 4·x + 6
y = -4·x - 3, y + 4·x = 5
Evaluation of the system of equations, we get;
First system of equations;
y = x + 6, y = -x + 2
x + 6 = -x + 2
x + x = 2 - 6 = -4
2·x = -4
x = -4/2 = -2
x = -2
y = x + 6
y = -2 + 6 = 4
y = 4
The solution is; x = -2, y = 4
Second system of equation;
3·x + y = -1, y = 4·x + 6
3·x + 4·x + 6 = -1
7·x + 6 = -1
7·x = -1 - 6 = -7
x = -7/7 = -1
x = -1
y = 4·x + 6
y = 4 × (-1) + 6 = 2
y = 2
The solution to the second system of equation is; x = -1, y = 2
Third system of equation;
y = -4·x - 3, y + 4·x = 5
y + 4·x = 5
-4·x - 3 + 4·x = 5
-4·x + 4·x - 3 = 5
0 - 3 = 5
-3 = 5
The third system of equation has no solution
The system of equations that does not belong with the other two is the third system of equation; y = -4·x - 3, y + 4·x = 5, that has no solution.
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Prove the second part of Theorem 6: Let w be any solution of Ax = b, and define vh = w - p. Show that vh is a solution of Ax = 0. This shows that every solution of Ax = b has the form w = p + vh with p a particular solution of Ax = b and vh a solution of Ax = 0.
The second part of Theorem 6 states that if w is any solution of the linear system Ax=b, and p is a particular solution of Ax=b, then the difference vector v=h−p is a solution of the homogeneous system Ax=0.
We will now prove this statement.
Since p is a particular solution of Ax=b, we have A*p = b. Then we can write w = p + v, where v = w - p.
To show that v is a solution of Ax=0, we need to show that Av=0.
We have:
Av = A(w-p) = Aw - Ap
Since Aw = b (by the assumption that w is a solution of Ax=b) and Ap = b (by the assumption that p is a particular solution of Ax=b), we can simplify this to:
A*v = b - b = 0
Thus, v is a solution of Ax=0, as required.
Therefore, every solution of Ax=b has the form w=p+v, where p is a particular solution of Ax=b and v is a solution of Ax=0.
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Which statement is missing from step 4 above? Part a
part b which of the following reasons complete step 4?
The missing statement from step 4 is that the angles OAKRV, OASVT, OARQP, and OAPQR are congruent.
What is congruent?Congruent is a term used in mathematics to describe two figures or objects that have the same shape and size. This means that the two objects have identical angles and sides, so they can be perfectly superimposed on each other.
This can be concluded using the Angle-Angle-Side (AAS) Theorem, which states that if two triangles have two angles and a side in common, the triangles are similar. Since the angles OAKRV, OASVT, OARQP, and OAPQR are the corresponding angles of the similar triangles AVKR and APQR, the reason that completes step 4 is the converse of the Isosceles Triangle Theorem, which states if two sides of a triangle are congruent, then the angles opposite those sides are congruent.
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Define a 3-chain to be a (not necessarily contiguous) subsequence of three integers, which is either monotonically increasing or monotonically decreasing. We will show here that any sequence of five distinct integers will contain a 3-chain. Write the sequence as a1, a2, a3, a4, a5. Note that a monotonically increasing sequences is one in which each term is greater than or equal to the previous term. Similarly, a monotonically decreasing sequence is one in which each term is less than or equal to the previous term. Lastly, a subsequence is a sequence derived from the original sequence by deleting some elements without changing the location of the remaining elements.
(a) [4 pts] Assume that a1 < a2. Show that if there is no 3-chain in our sequence, then a3 must be less than a1. (Hint: consider a4!)
(b) [2 pts] Using the previous part, show that if a1 < a2 and there is no 3-chain in our sequence, then a3 < a4 < a2.
(c) [2 pts] Assuming that a1 < a2 and a3 < a4 < a2, show that any value of a5 must result in a 3-chain.
(d) [4 pts] Using the previous parts, prove by contradiction that any sequence of five distinct integers must contain a 3-chain.
a3 is greater than or equal to a4, then the subsequence a1, a2, a4 would form a monotonically increasing 3-chain. Hence, a3 must be less than a4. If a1 < a5 < a4, then the subsequence a1, a4, a5 would form a monotonically increasing 3-chain any value of a5 results in a 3-chain.any sequence of five distinct integers must contain a 3-chain.
(a) Assume that a1 < a2 and there is no 3-chain in our sequence. Then, a3 cannot be greater than or equal to a2 (otherwise, the subsequence a1, a2, a3 would form a monotonically increasing 3-chain). Similarly, a3 cannot be less than or equal to a2 (otherwise, the subsequence a3, a2, a1 would form a monotonically decreasing 3-chain). Therefore, a3 must be strictly between a1 and a2. Now, if a3 is greater than or equal to a4, then the subsequence a1, a2, a4 would form a monotonically increasing 3-chain. Hence, a3 must be less than a4.
(b) From part (a), we know that a3 < a1. Also, since there is no 3-chain, a3 < a4 < a2. Combining these inequalities, we get a3 < a4 < a2 and a3 < a1. Hence, a3 < a4 < a2 < a1.
(c) Assume that a1 < a2 and a3 < a4 < a2. If a5 is less than a4, then the subsequence a3, a4, a5 would form a monotonically decreasing 3-chain. If a5 is greater than a2, then the subsequence a2, a5, a4 would form a monotonically decreasing 3-chain. If a4 < a5 < a2, then the subsequence a3, a4, a5 would form a monotonically increasing 3-chain. If a1 < a5 < a4, then the subsequence a1, a4, a5 would form a monotonically increasing 3-chain. Therefore, any value of a5 results in a 3-chain.
(d) Assume that there is a sequence of five distinct integers with no 3-chain. Without loss of generality, we can assume that a1 < a2. From part (a), we know that a3 < a1. From part (b), we know that a3 < a4 < a2 < a1. From part (c), we know that any value of a5 results in a 3-chain. Therefore, we have a contradiction and our assumption is false. Hence, any sequence of five distinct integers must contain a 3-chain.
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A Cepheid variable star is a star whose brightness alternately increases and decreases. Suppose that Cephei Joe is a star for which the interval between times of maximum brightness is 4.4 days. Its average brightness is 4.2 and the brightness changes by +/-0.45. Using this data, we can construct a mathematical model for the brightness of Cephei Joe at time t , where t is measured in days: B(t)=4.2 +0.45sin(2pit/4.4)
(a) Find the rate of change of the brightness after t days.
(b) Find the rate of increase after one day.
(a) The rate of change of the brightness after t days is dB/dt = (2π/4.4) * 0.45 * cos(2πt/4.4).
(b) The rate of increase after one day is 0.22 radians/day.
For the given case the equation for the brightness of cepheid joe is B(t)=4.2 +0.45sin(2pit/4.4). This equation tells us that the brightness of the star is determined by the sine of the time multiplied by a constant. Since the sine of a number is always changing, the brightness of the star is always changing too.
Therefore, the rate of change of the brightness is given by the derivative of the equation, which is 2π/4.4)*0.45*cos(2πt/4.4), when t is 1 day, we can plug this value into the equation to get the rate of increase after one day, which is dB/dt = (2π/4.4) * 0.45 * cos(2π/4.4) = 0.22 radians/day.
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suppose the mean height in inches of all 9th grade students at one high school is estimated. the population standard deviation is 5 inches. the heights of 7y randomly selected students are 68, 63, 70, 69, 75, 63 and 72.x¯ = Margin of error at 90% confidence level = 90% confidence interval = [
,
]
[smaller value, larger value]
The 90% confidence interval is [64.21, 73.79].
To find the margin of error and confidence interval,
we can use the following formula:
Margin of error [tex]= z* (sigma / \sqrt{(n))[/tex]
where z* is the z-score corresponding to the desired confidence level, sigma is the population standard deviation, n is the sample size, and sqrt represents the square root.
Since we want a 90% confidence interval, the corresponding z-score can be found using a standard normal distribution table or calculator.
The z-score for a 90% confidence level is 1.645.
Plugging in the values we have:
Margin of error = 1.645 * (5 / sqrt(7))
≈ 4.05
So the margin of error is approximately 4.05 inches.
To find the confidence interval, we need to add and subtract the margin of error from the sample mean:
Lower bound = x¯ - margin of error
= (68+63+70+69+75+63+72) / 7 - 4.05
≈ 64.21
Upper bound = x¯ + margin of error
= (68+63+70+69+75+63+72) / 7 + 4.05
≈ 73.79
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what’d the inequality of x > 23
The graph of the given inequality of x > 23 is attached.
What is an Inequality?The relationship between two expressions or values that are not equal to each other is called inequality.
A number line can be used to represent numbers placed on regular intervals. A number line can be used to represent an inequality.
Given that the inequality of x > 23
We are asked to plot the given inequality on a number line.
x > 23
The above inequality says that, the value of x is equal to or greater than 23.
Hence, the graph of the given inequality is attached.
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A phone sells for $230. It is now on sale for 30% off. How much money will April save if she
buys the phone on sale?
A
B
C
D
$69
$25
$49
$68
Answer:
I believe the answer would be A- $69. I just do 230-30% and I got the answer of 69.
I hope this helped!
Answer:
Option 1. A
Step-by-step explanation:
= (30/100)*230
= (30*230)/100
= 6900/100 = 69.
Thus, your answer is, A.
( There is nothing else I could explain to you! )
what is the probability that delay time is within one standard deviation of its mean value? (round your answer to four decimal places.)
The probability that a data point falls within one standard deviation of its mean value is 0.6827 or 68.27%.
The normal distribution is a continuous probability distribution that describes the distribution of a set of data around its mean. It is often represented by a bell-shaped curve, where the mean is located at the center and the standard deviation determines the width of the curve.
To find the probability that a data point falls within one standard deviation of the mean, we need to calculate the area under the normal distribution curve between the mean minus one standard deviation and the mean plus one standard deviation. This area represents the proportion of the data that falls within one standard deviation of the mean.
The probability of a data point falling within one standard deviation of the mean can be calculated using the following formula:
P(x - s < X < x + s) = 0.6827
Where P represents the probability, X represents the variable we are measuring, x represents the mean value, and s represents the standard deviation.
The value 0.6827 represents the proportion of the data that falls within one standard deviation of the mean in a normal distribution.
This means that if we have a data set with a mean value of 50 and a standard deviation of 5, then there is a 68.27% chance that a randomly chosen data point will fall between 45 and 55.
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Find the perimeter and the
area of this triangle
18.5cm
8.5cm
4cm
Answer:
Perimeter: 31 cm
Step-by-step explanation:
18.5 + 8.5 + 4 = 31 cm.
Can you send a picture of the math problem?
-x + 3y <= 3
-2x + y >= -2
solve please and then graph
The graph of the system of inequalities is in the image at the end.
How to solve and graph the system?Here we have a system of inequalities, first we want to solve them:
-x + 3y ≤ 3
-2x + y ≥ -2
Isolating y in both of these we will get:
y ≥ -2 + 2x
y ≤ (3 + x)/3
So we just needto graph the two lines, on the first one we will shade the region above the line and on the second one we will shade the region below the line.
The graph of the system is on the image below.
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Find an equation for the tangent to the curve at the given point. Then sketch the curve and the tangent together. y = 8 , (4,16) y = Choose the correct graph of the curve and the tangent below.
The equation of tangent to the curve y = 8√x at the point (4,16) is y = 2x + 8 .
We have to find equation of tangent line to the curve y = 8√x at the point (4, 16), we first find the slope ;
So , slope of the tangent line is derivative of function y = 8√x at point (4, 16).
which means : y' = 4[tex]x^{-\frac{1}{2} }[/tex] ;
At the point (4, 16), the value of x is 4.
So , y' = 4 × [tex]4^{-\frac{1}{2} }[/tex] = 2 .
By Using the point slope form, the equation of the tangent line is ;
⇒ y - 16 = (2)(x - 4) ;
Simplifying this equation, we get:
⇒ y - 16 = 2x - 8
⇒ y = 2x + (16 - 8)
⇒ y = 2x + 8 .
Therefore, the equation of the tangent line to the curve is y = 2x + 8 .
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The given question is incomplete , the complete question is
Find an equation for the tangent to the curve y = 8√x at the point (4,16) .
: A tank is is half full of oil that has a density of 900 kg/m3. Find the work w required to pump the oil out of the spout. (Use 9.8 m/s2 for g. Assume r = 15 m and h = 5 m.) W = h A tank is full of water. Find the work required to pump the water out of the spout. (Use 9.8 m/s2 for g. Use 1000 kg/m3 as the density of water. Assume r = 3 m and h = 1 m.) 3.11.107 X h A tank is full of water. Find the work W required to pump the water out of the spout. (Use 9.8 m/s2 for g. Use 1000 kg/m3 as the weight density of water. Assume that a = 4 m, b = 4 m, c = 9 m, and d = 4 m.) W = 96000 kb
The work required to pump water out of the spout is calculated by multiplying the density of water (1000 kg/m3) by the height of the tank (h) and the area of the spout (a x b x c x d). The acceleration due to gravity (g) is 9.8 m/s2.
1. Calculate the volume of the tank:
V = a x b x c x d = 4 x 4 x 9 x 4 = 576 m3
2. Calculate the mass of the water in the tank:
m = V x density = 576 x 1000 = 576000 kg
3. Calculate the height of the tank:
h = m / density = 576000 / 1000 = 576 m
4. Calculate the work required to pump the water out of the spout:
W = m x g x h = 576000 x 9.8 x 576 = 3.11.107 x 576 = 1.79.107 J
The work required to pump water out of a spout can be calculated by multiplying the density of water (1000 kg/m3) by the height of the tank (h) and the area of the spout (a x b x c x d). The acceleration due to gravity (g) is 9.8 m/s2.To calculate the work, first we need to find the volume of the tank (V) by multiplying the length (a), width (b), height (c), and depth (d). Then we can calculate the mass (m) by multiplying the volume with the density of water. We can then calculate the height of the tank (h) by dividing the mass with the density. Finally, we can calculate the work required (W) by multiplying the mass, acceleration due to gravity, and the height of the tank.
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43⁰ 1200 m 53⁰ H 1500 m 30 m 40 m 8. At a ski resort, the highest ski run, Hattie's Haven, can only be accessed by taking two lifts. The first lift leaves the lodge area and travels 1200 m at an inclination of 43° to a transfer point. From the transfer point, the new lift travels 1500 m at an inclination of 53° to the top of Hattie's Haven ski run. The resort is undergoing renovations and is planning on creating a new ski run called Giffin's Gallop. This run would be 30 m to the right of the top of Hattie's Haven and 40 m higher. A new lift must be installed that goes directly from the lodge area to the top of Giffin's Gallop. Determine the angle of elevation of the lift from the lodge area to the top of Giffin's Gallop. (Thinking and Inquiry)
Answer: We can use trigonometry to solve this problem. Let's call the angle of elevation of the lift from the lodge area to the top of Giffin's Gallop "θ". Then we can break down the lift into two parts: the horizontal distance from the lodge area to the top of Giffin's Gallop, and the vertical distance from the lodge area to the top of Giffin's Gallop.
Horizontal distance:
The horizontal distance from the lodge area to the top of Giffin's Haven is 1200 m * cos(43°) + 1500 m * cos(53°) + 30 m = 1759.29 m
The horizontal distance from the top of Giffin's Haven to the top of Giffin's Gallop is 30 m.
So, the total horizontal distance from the lodge area to the top of Giffin's Gallop is 1759.29 m + 30 m = 1789.29 m
Vertical distance:
The vertical distance from the lodge area to the top of Giffin's Haven is 1200 m * sin(43°) + 1500 m * sin(53°) + 40 m = 1174.70 m
The vertical distance from the top of Giffin's Haven to the top of Giffin's Gallop is 40 m.
So, the total vertical distance from the lodge area to the top of Giffin's Gallop is 1174.70 m + 40 m = 1214.70 m
Finally, using the tangent function, we can find the angle of elevation of the lift from the lodge area to the top of Giffin's Gallop:
θ = tan^-1(vertical distance / horizontal distance) = tan^-1(1214.70 m / 1789.29 m) = tan^-1(0.67967)
θ = 37.90° (approximately)
So, the angle of elevation of the lift from the lodge area to the top of Giffin's Gallop is approximately 37.90°.
Step-by-step explanation:
Help me pls…………………..
The solution of the expression 2 x 2[tex]\frac{1}{5}[/tex] is 4.4.
What is multiplication?Multiplication is a type of mathematical operation. The repetition of the same expression types is another aspect of the practice.
For instance, the expression 2 x 3 indicates that 3 has been multiplied by two.
Given:
Two fractions are 2 and 2[tex]\frac{1}{5}[/tex].
To find the product of two fractions:
Applying multiplication operation,
we get,
2 x 2[tex]\frac{1}{5}[/tex]
To simplify further;
Converting mixed fractions to improper fractions,
we get,
2 x 11/5
= 22/5
= 4.4
Therefore, 2 x 2[tex]\frac{1}{5}[/tex] = 4.4.
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GDP has many known biases that make it a poor absolute measure of the welfare of a society. Why might GDP still be a good measure of changes in welfare?
Select one:
a.
The underground economy bias is rapidly changing.
b.
The biases may be relatively constant over time.
c.
This question is silly; GDP can’t be used to measure change in welfare.
d.
The biases are mainly political and they can change with different election results.
As research have shown that GDP has many known biases that make it a poor absolute measure of the welfare of a society. A reason why GDP will still be a good measure of changes in welfare will likely be because biases may be relatively constant over time. The Option B is correct.
Why do GDP produce poor measure of welfare?GDP is a poor indicator of a society's standard of living because it does not directly account for leisure, environmental quality, levels of health and education, activities conducted outside the market, changes in income inequality, increases in variety, increases in technology, and so on.
So, GDP does not directly measure the things that make life worthwhile, but it does measure our ability to obtain many of the inputs that make life worthwhile. GDP, however, is not a perfect measure of happiness. Some factors that contribute to a happy life are excluded from GDP.
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_______ the term applies to an ordered set of observations from smallest to largest. the cumulative relative frequency is the sum of the relative frequencies for all values that are less than or equal to the given value
Ascending order is a term that applies to an ordered set of observations from smallest to largest.
This means that the values are arranged in order of increasing magnitude, starting from the lowest value. The cumulative relative frequency is the sum of the relative frequencies for all values that are less than or equal to the given value. This is calculated by adding the relative frequencies of each value from the lowest value up to the given value, and then dividing the sum by the total number of observations. This helps us to determine the percentage of observations that lie below or equal to the given value. For example, given a set of five values, the cumulative relative frequency of the third value would be calculated by adding the relative frequencies of the first two values and then dividing by 5.
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Maggie is making 30 sundaes with mint, chocolate, and vanilla ice cream.
1
3
of the sundaes are mint ice cream and
1
2
of the remaining sundaes are chocolate. The rest will be vanilla. How many sundaes will be vanilla? 1 unit = 10 sundaes help!!!!!!!!!!!!!!!!!!!!! Please
Its due BY TOMORROW!
There are how much total chocolate and vanilla sundaes.
Proportionately, the number of sundaes that will be vanilla is 10 sundaes.
What is proportion?Proportion refers to the part or portion of a whole.
Proportions show the relative size (ratio) of a value compared to another.
The difference between proportion and ratio is that proportions are two ratios equated to each other.
The total number of sundaes Maggie is making = 30
The types of sundaes = mint, chocolate, and vanilla ice cream.
Proportions:Mint ice cream = 1/3 = 10 sundaes (1/3 x 30)
The remaining sundaes = 2/3 (1 - 1/3)
= 20 (30 - 10) or (30 x 2/3)
Chocolate ice cream = 1/2 of 20 = 10 sundaes
Vanilla sundaes = 10 (30 - 10 - 10) or (1/2 of 20)
Thus, using the proportional or fractional relationships among the different sundaes, the number of vanilla sundaes that Maggie will make is 10.
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prove that for every positive rational number r satisfying the condition r2<2 one can always find a larger rational number r h (h>0 ) for which (r h)2<2 .
Answer: Suppose there exists a positive rational number r such that r^2 < 2. Then we have 2 - r^2 > 0. Let h = (2 - r^2)/4. Then h > 0 because r^2 < 2.
Consider the number rh = r + h. We have:
(rh)^2 = (r + h)^2 = r^2 + 2rh + h^2 = r^2 + 2(2 - r^2)/2 + (2 - r^2)/16
= r^2 + 2 + (2 - r^2)/16
< 2 + 2 + (2 - 2)/16 = 2.
Thus, for any positive rational number r such that r^2 < 2, there exists a larger positive rational number rh = r + h such that (rh)^2 < 2.
Step-by-step explanation:
Market Foods sells 24 cans of soda for $6.79, a 128-ounce bottle of detergent for $2.89, a 13.8-ounce can of peanuts for $2.59, and a cooked 1.75-pound chicken half for $2.65
According to the information, the unit price of the products is: $0.28 for each can of soft drink, $0.022 for each ounce of detergent, $0.18 for each ounce of peanuts, $0.0033 for each gram of cooked chicken.
How to calculate the unit price of products?To calculate the unit price of the products we must perform the following procedure:
We must divide the value of each product into the amount of product as shown below:
$6.79 / 24 cans = $0.022$2.89 / 128oz = $0.022$2.59 / 13.8oz = $0.18$2.65 / 793.7g (1.75 lbs) = $0.0033Accordingly, the unit price of these products is the result of these divisions.
Note: This question is incomplete. Here is the complete information:
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What is 4/16 in simplest form
Answer:
[tex]\frac{1}{4}[/tex].
Step-by-step explanation:
[tex]\frac{4}{16}[/tex] is not in simplest form, so that will be our first step.
[tex]4[/tex] and [tex]16[/tex] are both have factors/are divisible by [tex]2[/tex] and [tex]4[/tex].
In order to get the fraction in simplest form fastest, divide by the GCF. (Greatest Common Factor)
Therefore, divide the Numerator, (top number) and Denominator, (bottom number) by [tex]4[/tex].
[tex]4[/tex] ÷ [tex]4[/tex] [tex]= 1[/tex].
[tex]16[/tex] ÷ [tex]4[/tex] [tex]= 4[/tex].
Therefore, the answer is [tex]\frac{1}{4}[/tex].
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Find an autonomous differential equation with all of the following properties:
equilibrium solutions at y=0 and y=5,
y′>0 for 0
y′<0 for −[infinity]
dydt=
dydt = k(y-5)(y-0) where k is a positive constant. This equation has equilibrium solutions of y=0 and y=5, and y' is positive for 0<y<5 and negative for y<0 or y>5.
We can solve this problem by rearranging the equation to separate the y terms from the y' terms. We can do this by factoring the y terms on the left side, and then writing the equation as y' = k(y-5)(y-0). This equation has an equilibrium solution at y=0 and y=5, and the sign of y' depends on the sign of k. Since k is a positive constant, y' is positive when 0<y<5, and y' is negative when y<0 or y>5. Thus, the equation dydt = k(y-5)(y-0) meets all of the given criteria. Therefore, dydt = k(y-5)(y-0) where k is a positive constant. This equation has equilibrium solutions of y=0 and y=5, and y' is positive for 0<y<5 and negative for y<0 or y>5.
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Find the component form and magnitude of the vector v with the given initial and terminal points. Then find a unit vector in the direction of v.
Initial point:
(1, 6, 0)
Terminal point:
(4, 1, 6)
The component form of the vector is <3, -5, 6>, the magnitude of the vector is √70, then the unit vector is <0.386, -0.643, 0.643>.
The initial and terminal points to find the component form of the vector, calculated its magnitude, and then divided the component form by the magnitude to find a unit vector in the direction of v.
To find the component form of the vector, you can subtract the coordinates of the initial point from the coordinates of the terminal point. In this case, we have:
v = (4, 1, 6) - (1, 6, 0)
v = (3, -5, 6)
So the component form of the vector is v = <3, -5, 6>.
To find the magnitude of the vector, we can use the formula:
|v| = √(3² + (-5)² + 6²)
|v| = √70
Therefore, the magnitude of the vector is √70.
Finally, to find a unit vector in the direction of v, we can divide the component form of v by its magnitude:
u = v/|v|
u = <3/√70, -5/√70, 6/√70>
So the unit vector in the direction of v is u = <0.386, -0.643, 0.643>.
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According to the U.S. Mint, the number of quarters minted in 2018 was about 2 x 10°. The mass of a quarter is about 6 X 10-3 kg. Write the number of quarters and the mass of a quarter in standard form.
The number of quarters is 2 and mass of quarter is 0.006 Kg.
What is Scientific Notation?With scientific notation, one can express extremely big or extremely small values. If a number between 1 and 10 is multiplied by a power of 10, the result is written in scientific notation.
Given:
The number of quarters minted in 2018 was about 2 x 10°
and, The mass of a quarter is about 6 X [tex]10^{-3[/tex] kg.
As, in standard form the decimal is place after one significant and the rest raised to 10 to the powers and if the number are in power then it can be written in form of decimal.
Here, number of quarters minted is already in standard form 2 x 10° or 2 x 1
and, mass of a quarter can be written as
= 6 X [tex]10^{-3[/tex] k
= 6/ 10³
= 6/ 1000
= 0.006
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Solve the system of equations using subtraction. 3x−2y =−1
3x+ y =14 QUICK PLEASEE
The required values are,
x = 3
y = 5.
Linear Equation in two variables:An equation is said to be linear equation in two variables if it is written in the form of ax + by + c=0, where a, b & c are real numbers and the coefficients of x and y, i.e a and b respectively, are not equal to zero
Now in the given question,
we have two equations,
3x - 2y = -1 ......(1)
3x + y = 14 .......(2)
subtract (2) from (1), we get
-3y = -15
divide both sides by -3, we get
y = 5
now put this value of y in (2),
3x + 5 = 14
subtarct both sides by 5, we get
3x = 9
divide both sides by 3, we get
x = 3
Hence, the required values are,
x = 3
y = 5
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a continuous random variable x has the probability density function of the following form (3.1) fx(x)
The probability of the continuous random variable X taking on a value greater than one is e⁻¹, which is approximately 0.368.
In probability theory, random variables are used to represent uncertain events. A continuous random variable is a variable that can take any value within a given range of values. The probability density function (PDF) of a continuous random variable is a function that describes the likelihood of the variable taking on a certain value. In this question, we are given the PDF of a continuous random variable and asked to find the probability of the variable taking on a value greater than one.
The given PDF is
=> f(x) = e⁻ˣ, 0 < x < ∞.
To find P{X > 1}, we need to integrate the PDF from 1 to infinity.
P{X > 1} = ∫(1 to ∞) e⁻ˣ dx
Using integration by parts, we get:
P{X > 1} = [-e⁻ˣ](1 to ∞)
= lim t → ∞ [-e⁻ˣ + e⁻¹)]
= e⁻¹
In conclusion, the probability density function of a continuous random variable is used to describe the likelihood of the variable taking on a certain value. In this question, we used the PDF to find the probability of the continuous random variable taking on a value greater than one. By integrating the PDF, we obtained the probability to be e⁻¹, which is approximately 0.368.
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Complete Question:
A continuous random variable X has a probability density function f ( x ) = e⁻ˣ , 0 < x < ∞ . Then P{X > 1} is
The distance d an object falls after t seconds is given by d = 16t² (ignoring air resistance). To find
the height of an object launched upward from ground level at a rate of 32 feet per second, use
the expression 32t - 16t^2, where t is the time in seconds. Factor the expression.
The object will hit the ground in 2 seconds.
What is an expression?Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
The distance d an object falls after t seconds is given by d = 16t²
To detemine the height of an object launched upward from ground level at a rate of 32 feet per second, use the expression 32t - 16t^2, where t is the time in seconds.
Therefore, put h = 0 in the equation;
0 = 32t - 16t²
16t² = 32t
16t = 32
t = 2
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in exercises 23 and 24, choose and such that the system has (a) no solution, (b) a unique solution, and (c) many solutions. give separate answers for each part.
(a) For no solution, we need the two equations to be inconsistent, which means that they cannot be satisfied simultaneously. We can achieve this by making the first equation a multiple of the second equation:
4(x1 + hx2) = 8
4x1 + 4hx2 = 8
4x1 + 8x2 = k
Now, we can see that the second equation is not compatible with the first equation since they imply contradictory statements:
4x1 + 8x2 = k and 4x1 + 4hx2 = 8
(b) For a unique solution, we need the two equations to be independent, which means that they are not multiples of each other. We can achieve this by choosing different coefficients for x1 and x2 in the two equations.
x1 + hx2 = 2 and 4x1 + 8x2 = k
To find the values of h and k that give a unique solution, we can solve the system by elimination or substitution. For example, we can multiply the first equation by 4 and subtract it from the second equation:
4x1 + 8x2 = k
-4x1 - 4hx2 = -8
Simplifying and dividing by -4, we get:
x2 = (2 + h)/2
x1 = (k - 4x2)/4
Since x1 and x2 are expressed in terms of h and k, we can choose any values of h and k that satisfy these equations, and the system will have a unique solution.
(c) For many solutions, we need the two equations to be dependent, which means that they are multiples of each other or one is a linear combination of the other. We can achieve this by making the second equation a multiple of the first equation:
x1 + hx2 = 2
4(x1 + hx2) = 8 + 4hkx2
4x1 + (4h - k)x2 = 8
Now, we can see that the second equation is a linear combination of the first equation, so the system has infinitely many solutions. To find the solutions, we can choose any value of x2 and solve for x1 in terms of x2:
x1 = (8 - (4h - k)x2)/4
Since x1 and x2 are expressed in terms of h and k, we can choose any values of h and k that satisfy the equation 4h - k = 0, and the system will have many solutions.
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