The triangle on the grid will be translated two units left.
54321
47
C
2 3 4 5 X
Which shows the triangle when it is translated two units left?

The lines are parallel because they have the same slope in the equation of lines

The equation of a line is expressed as y = mx + b where m is the slope and b is the y-intercept

And y - y₁ = m ( x - x₁ )

y = y-coordinate of second point

y₁ = y-coordinate of point one

m = slope

x = x-coordinate of second point

x₁ = x-coordinate of point one

The slope m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Given data ,

Let the equation of line be represented as A

Now , the value of A is

Let the first equation be 9y - 6x = -18   be equation (1)

Let the second equation be 3y - 2x = 24   be equation (2)

On simplifying the equation , we get

Adding 6x on both sides of the equation , we get

9y = 6x - 18

Divide by 9 on both sides of the equation , we get

y = ( 2/3 )x - 2

So , the slope of line 1 is m = 2/3

And , for the second equation ,

Adding 6x on both sides of the equation , we get

3y = 2x + 24

Divide by 3 on both sides of the equation , we get

y = ( 2/3 )x + 8

So , the slope of line 2 is m = 2/3

Since the slopes of the lines are same , they are parallel lines

Hence , the equation of lines are solved

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The complete question is :

The lines represented by the equations 9y - 6x = -18 and 3y - 2x = 24 are

a) perpendicular

b) parallel

c) none of the above

Step-by-step explanation:

a. On Monday, the percentage of large bags sold was 57/(57 + 132) x 100 = 30.22%.

b. On Monday, the percentage of small bags sold was 132/(57 + 132) x 100 = 69.78%.

c. The total number of large and small bags sold on the two days combined was 130/(130 + 154) x 100 = 45.45%.

The difference in the production levels will be 3x + 8.

The amount that Jackson spent more will be 5.20 - p.

An equation simply has to do with the statement that illustrates the variables given. In this case, it is vital to note that two or more components are considered in order to be able to describe the scenario.

Based on the information, a company has two manufacturing plants that had levels of 5x + 11 and 2x - 4.

The difference in the production levels will be:

= 5x + 11 - 2x - 3

= 3x + 8

The amount that Jackson spent more will be:

= 7.65 + 5p - 2.45 - 4p

= 5.20 - p.

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Answer:

x = 9/2

Step-by-step explanation:

As both equations are set equal to "y", we can set the equations equal to each other and solve for the x-value:

[tex]4=2x-5\\9=2x\\x=\frac{9}{2}[/tex]

The length of the incline plane is equivalent to 13.9ft

Application of Pythagoras theorem

According to the theorem, the square of the hypotenuse is equal to the sum of the square of the adjacent and opposite

c^2 = a^2 + b^2

From the given question, the length of the incline is the hypotenuse 'c' where:

a = 7ft

b = 12ft

Substitute

c^2 = 7^2 + 12^2

c^2 = 49 + 144

c^2 = 193

x = 13.9ft

Therefore the length of the inclined plane is 13.9ft

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The weighted average is 86. To calculate the weighted average, we first need to find the contribution of each score to the total grade based on their weightage.

Lab score contribution = 0.17 x 95 = 16.15

First major test contribution = 0.25 x 68 = 17

Second major test contribution = 0.25 x 95 = 23.75

Final exam contribution = 0.33 x 81 = 26.73

Total contribution = 16.15 + 17 + 23.75 + 26.73 = 83.63

Therefore, the weighted average is 83.63/0.8 = 86.

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Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

By adding together the specific amounts the chef used in each recipe, one can determine the total number of cups of milk she consumed. In order to achieve this, we can condense the phrase:

1/4 + (2 x 5) = 1/4 + 10

The two amounts on the right side of the equation can then be added:

1/4 + 10 = 10.25

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Answer:If A is at point (x,y), then A' would be at point (-x,-y). Same goes for points B and C.

Step-by-step explanation:

In the expression, 4x+15x,  variable: x; coeficient: 4, 15; constant: 0

In the expression 6n+25+7n+4, variable: n, coeficient: 6, 7; constant: 25, 4

In the expression 3a+4a+17+a+1, variable: a, coeficient: 3, 4, 1; constant: 17, 1

Generally, in an algebraic expression terms, variables, coefficients, and constants are seen. The parts of an expression that are added by either an addition or a subtraction notation are called the terms. The letter of a term is called a variable, the numerical value written along the variable of a term is called a coefficient, and the term contains only the numerical value called a constant.

Take the expression 4x+15x. The terms are 4x and 15x.

Clearly, the variables of the terms are x, the coefficients of the terms are 4 and 15, and the constant is 0. So, the required answers are obtained.

Take the expression 6n+25+7n+4. The terms are 6n, 25, 7n, and 4.

Clearly, the variables of the terms are n, the coefficients of the terms are 6 and 7, and the constants are 25 and 4. So, the required answers are obtained.

Take the expression 3a+4a+17+a+1. The terms are 3a, 4a, 17, a, and 1.

Clearly, the variables of the terms are a, the coefficients of the terms are 3, 4, and 1, and the constants are 17 and 1. So, the required answers are obtained.

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Answer:

False

Step-by-step explanation:

This statement is false.

The set of whole numbers include the set of Natural numbers "N" = {1, 2, 3, 4, 5, 6, ...}, the set of the negatives of the natural numbers: {-1, -2, -3, -4,...}, and the zero: {0}

We see then that the set of Natural numbers is a subset of the set of whole numbers Z = {... -4,-3,-2,-1, 0,1, 2, 3, 4, 5, ...}

Answer: i think False

Step-by-step explanation: why not pick false…..

Hope this helps^^

Answer:

Outliers are points that are on the very edge of a scatter plot, separated from the other points.

Step-by-step explanation:

To prove by contrapositive, we need to show that if n is odd, then n^3+5 is even.

The contrapositive of the original statement is logically equivalent to the original statement.  if we can prove the contrapositive, then we have also proven the original statement.

Proof by contrapositive:

Assume that n is an odd integer, which means that n can be written in the form n = 2k + 1, where k is an integer.

Then, n^3+5 = (2k+1)^3 + 5

= 8k^3 + 12k^2 + 6k + 1 + 5

= 8k^3 + 12k^2 + 6k + 6

We can factor out a 2 from the last two terms of this expression:

n³ + 5 = 2(4k³ + 6k²)

Since 4k³ + 6k² + 3k + 3 is an integer, we can see that n³ + 5 is an even integer, which means that n is even by definition.

we have proven that if n is an integer and n³ + 5 is odd, then n is even by contrapositive.

n^3+5 = 2(4k^3 + 6k^2 + 3k + 3)

Since 4k^3 + 6k^2 + 3k + 3 is an integer, n^3+5 is even.

we have shown that if n is odd, then n^3+5 is even, which is the contrapositive of the statement we were asked to prove.

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A. His monthly mortgage payment is $690.25.

B. He will pay a total of $123,492 in interest over the life of the loan

C. He will make a total of $248,490 in loan payments over the life of the loan.

D. The difference between his monthly loan payment and his monthly rent is $9.75.

Here are the calculations based on the given information:

Loan amount = $125,000

Interest rate = 5.25%

Loan term = 30 years (360 months)

Monthly mortgage payment = $690.25

To calculate the monthly mortgage payment, we can use the following formula:

P = L[c(1 + c)^n]/[(1 + c)^n - 1]

Where:

P = monthly mortgage payment

L = loan amount

c = monthly interest rate (5.25% / 12)

n = loan term in months (30 years x 12 months)

Plugging in the numbers, we get:

P = 125000[(0.0525/12)(1 + 0.0525/12)^360]/[(1 + 0.0525/12)^360 - 1]

P = $690.25

Therefore, Frank's monthly mortgage payment is $690.25.

B. To calculate the total interest he will pay on the loan, we can multiply the monthly mortgage payment by the total number of payments (360) and subtract the loan amount:

Total interest = Pn - L

Total interest = $690.25 x 360 - $125,000

Total interest = $123,492

Therefore, Frank will pay a total of $123,492 in interest over the life of the loan.

C. To calculate the total of all loan payments he will make, we can multiply the monthly mortgage payment by the total number of payments:

Total loan payments = P n

Total loan payments = $690.25 x 360

Total loan payments = $248,490

Therefore, Frank will make a total of $248,490 in loan payments over the life of the loan.

D. To calculate the difference between Frank's monthly loan payment and his monthly rent, we can subtract his monthly rent ($700) from his monthly mortgage payment ($690.25):

Monthly difference = $700 - $690.25

Monthly difference = $9.75

Therefore, the difference between Frank's monthly loan payment and his monthly rent is $9.75.

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The company's profit in 2017, modeled by the given function, was $193651949.5

The equation of the function is given as

P(t) = 0.5t^6 − 3t³ +t² +25

First, we calculate the value of t in 2017

t = 2017 - 1990

t = 27

Using the Remainder theorem

To find the company's profit in 2017, we need to substitute t = 27 in the given function P(t):

P(27) = 0.5(27)^6 - 3(27)^3 + (27)^2 + 25

Evaluate

P(27) = 193651949.5

Therefore, the company's profit is $193651949.5

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The conditional expectation of αX given Y=y is (αλy / β + αλ)^α * e^(-(β+αλ)/βy) and the Law of Iterated Expectation gives E[αX] = (αλ / β + αλ)^α * (β / (β+αλ))^α * (Γ(α) / β).

Let X be a Poisson random variable with parameter λ and Y be a Gamma random variable with parameters α and β. We want to find the conditional expectation of αX given Y=y and then apply the Law of Iterated Expectation to find E[αX].

The conditional probability density function of αX given Y=y is:

fX|Y(x|y) = P(X=x|Y=y) = P(X=x,Y=y) / P(Y=y)

Since X and Y are independent, we have:

P(X=x,Y=y) = P(X=x)P(Y=y)

Therefore, the conditional probability density function of αX given Y=y is:

fX|Y(x|y) = (λ^x/x!) * (β^α / Γ(α)) * y^(α-1) * e^(-βy) / (λ^y * e^(-λ) * β^α / Γ(α))

fX|Y(x|y) = (λ^x / x!) * (y^α * e^(-βy)) / (Γ(α) * λ^y * β^α)

Now we can calculate the conditional expectation of αX given Y=y:

E[αX|Y=y] = ∑ x=0^∞ αx * fX|Y(x|y)

E[αX|Y=y] = ∑ x=0^∞ αx * (λ^x / x!) * (y^α * e^(-βy)) / (Γ(α) * λ^y * β^α)

E[αX|Y=y] = (αλy / β + αλ)^α * e^(-(β+αλ)/βy)

Now we can apply the Law of Iterated Expectation to find E[αX]:

E[αX] = E[E[αX|Y]]

E[αX] = E[(αλY / β + αλ)^α * e^(-(β+αλ)/βY)]

Since Y is a continuous random variable, we need to integrate over all possible values of Y:

E[αX] = ∫ 0^∞ (αλy / β + αλ)^α * e^(-(β+αλ)/βy) * (β^α / Γ(α)) * y^(α-1) * e^(-βy) dy

E[αX] = (αλ / β + αλ)^α * (β / (β+αλ))^α * (Γ(α) / β)

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The product of 4.000329 × 1000 is the second option 4,000.329.

Multiplication of two numbers is defined as the addition of one of the number repeatedly until the times of the other number.

a × b means that a is added to itself b times or b is added to itself a times.

We have to find the product of 4.000329 × 1000.

When a number is being multiplied by (10)ⁿ, 'n' number of zeroes will be added to the right of the number.

If the number is decimal number, decimal point is being shifted n digits to the right.

The question here is 4.000329 × 1000.

4.000329 × 1000 = 4.000329 × (10)³

Decimal point is shifted three digits to the right.

4.000329 × (10)³ = 4,000.329

Hence the correct option is B.  4,000.329.

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a. P(Z = 1) = ∫G(s)f(s)ds is the distribution of Z.

b. X and Z are independent.

c. X and Y are not independent.

a) We have Z = I(S > 2T), where I is the indicator function. Then,

P(Z = 1) = P(S > 2T) = ∫∫(s > 2t) f(s) f(t) ds dt

Using the fact that S and T are independent, we get

∫∫(s > 2t) f(s) f(t) ds dt = ∫∫f(s)ds ∫∫f(t)I(s > 2t)dt ds

Letting G(s) = ∫f(t)I(s > 2t)dt, we get

P(Z = 1) = ∫G(s)f(s)ds

b) We have X = min(S,T) and Z = I(S > 2T). To check whether X and Z are independent, we compute their joint distribution:

P(X > x, Z = 1) = P(S > 2T, S > x, T > x) = ∫∫(s > 2t) f(s) f(t) ds dt ∫[tex]x^\infty[/tex]f(u)du

= ∫[tex]x^\infty[/tex]f(u)du ∫[tex](u/2)^x[/tex] f(t) dt ∫[tex]t^\infty[/tex] f(s) ds

= 1/2 ∫[tex]x^\infty[/tex]f(u) ∫[tex]t^\infty[/tex] f(s) ds dt

= 1/2 ∫[tex]x^\infty[/tex]f(u) G(t) dt

= 1/2 ∫[tex]x^\infty[/tex]f(u) ∫f(t)I(u > 2t)dt du

= ∫[tex]x/2^\infty[/tex] f(u) ∫f(t)I(u > 2t)dt du

= P(X > x)P(Z = 1), using the fact that S and T are independent.

Therefore, X and Z are independent. Similarly, we can show that Y and Z are independent and (X, Y) and Z are independent.

c) X and Y are not independent, since the event {X > x} implies that both S and T are greater than x, which means that the event {Y > y} is more likely to occur for larger values of y.

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The probability of picking one ball of each color is 10/19. The probability of picking a red ball with a number one less than the number on the black ball is 9/190.

(I) To figure the probability of picking one repudiate and one red ball, we can separate it into two cases: first, picking a debase and afterward a red ball, and second, picking a red ball and afterward a renounce.

The probability of picking a torpedo on the principal draw is 10/20 (since there are 10 renounces and 20 all out balls), and the probability of then picking a red ball on the subsequent draw is 10/19 (since there are currently 9 red balls avoided with regards to a sum of 19 balls). So the probability of picking a repudiate first and afterward a red ball is (10/20) * (10/19) = 1/19.

Essentially, the probability of picking a red ball first and afterward a torpedo is (10/20) * (10/19) = 1/19.

Hence, the probability of picking one chunk of each tone is the amount of these two probabilities: 1/19 + 1/19 = 2/19.

Notwithstanding, we want to isolate by 2 to represent the way that we might have picked the balls in the contrary request nevertheless have one chunk of each tone. So the last probability is (2/19)/2 = 10/19.

Consequently, the probability of picking one wad of each tone is 10/19.

(ii) To figure the probability of picking a red ball with a main not exactly the number on the debase, we can initially fix the renounce that we pick. There are 10 decisions for the renounce. The main red ball with a main not exactly the torpedo is the red ball with the following most minimal number, so there is just a single decision for the red ball.

In this manner, the probability of picking a debase and afterward a red ball with the number on the red ball one not exactly the number on the repudiate is (10/20) * (1/19) = 1/190.

We really want to duplicate this by 9, since there are 9 sets of contiguous numbers (1 and 2, 2 and 3, ..., 9 and 10) for which the condition is fulfilled. So the last likelihood is 9/190.

Thusly, the probability of picking one chunk of each tone, with the number on the red ball being one not exactly the number on the debase, is 9/190.

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A, B, and C's interest rates are 49.96, 296.32 and 102.96, respectively. Since the total interest is $449.24.

The annual percentage rate (APR) on a credit card indicates that the interest you pay over a year is generally equivalent to your balance.

The balances and annual percentage rates for Jimmy's credit cards are shown below.

If Jimmy pays the same amount each month, he will be free of his credit card debt in a year.

We know that the formula

[tex]$P V=\frac{P M T\left[1-\left(1+\frac{r}{12}\right)^{12 n}\right]}{\frac{r}{12}}$[/tex]

Where, PV be present value

PMT be monthly payment

r be interest rate

n be time

For credit card A, we have

[tex]$\begin{aligned} 563 & =\frac{{PMT}\left[1-\left(1+\frac{0.16}{12}\right)^{12}\right]}{\frac{0.16}{12}} \\ \text { PMT } & =51.08\end{aligned}$[/tex]

Total payment will be, 51.08 × 12 = 612.96

The interest charge will be, 612.96 − 563 = 49.96

For credit card B, we have

[tex]$\begin{aligned} & 2525=\frac{{PMT}\left[1-\left(1+\frac{0.21}{12}\right)^{12}\right]}{\frac{0.21}{12}} \\ & \mathrm{PMT}=235.11\end{aligned}$[/tex]

Total payment will be, 235.11 × 12 = 2821.32

The interest charge will be, 2821.32 − 2525 = 296.32

For credit card C, we have

[tex]$\begin{aligned} 972 & =\frac{\text { PMT }\left[1-\left(1+\frac{0.19}{12}\right)^{12}\right]}{\frac{0.19}{12}} \\ \text { PMT } & =89.58\end{aligned}$[/tex]

Total payment will be, 89.58 × 12 = 1074.96

The interest charge will be, 1075.96 − 972 = 102.96

Total interest = 102.96 + 296.32 + 49.96

Total interest = 449.24

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The value of x for the system of equations will be x=6.7.

What is a system of equations?

A set of simultaneous equations is a finite set of equations for which common solutions are sought in mathematics. It is also known as a system of equations or an equation system.

Given that the two equations are 2x + 2y = 17 and 4x - y = 25. The value of x will be calculated by eliminating the variable y from the equation.

Multiply the second equation by 2 and subtract from the first equation,

2x+2y=17.

8x-2y=50.

10x=67.

x= 67/10

x = 6.7.

Therefore, the value of x for the system of equations will be x=6.7.

\

Answer:

To find y'(3), we need to use implicit differentiation to differentiate both sides of the equation with respect to x and then solve for y'.

Differentiating both sides with respect to x, we get:

(2x/25) + (2y/64) * (dy/dx) = 0

Now we can solve for dy/dx:

(2y/64) * (dy/dx) = -(2x/25)

dy/dx = -(2x/25) / (2y/64)

dy/dx = -32x/25y

To find y'(3), we need to substitute x=3 and y=6.4 into the expression for dy/dx:

y'(3) = -32(3)/(25)(6.4)

y'(3) = -0.3

Therefore, the value of y'(3) is -0.3

The value of y'(3) in (2x/25) + (2y/64) = 1, is  - 0.3

Finding the derivative of an implicit function is the process of implicit differentiation.

In other words, this method is utilized to discover the implicit derivative.

To find y'(3), After differentiating both sides of the equation with respect to x using implicit differentiation, we must next solve for y'.

Differentiating both sides with respect to x we get,

(2x/25) + (2y/64)×(dy/dx) = 0

Solving for dy/dx

(2y/64)×(dy/dx) = -(2x/25)

dy/dx = -(2x/25) / (2y/64)

dy/dx = -32x/25y

To find y'(3), Replacing x=3 and y=6.4 into the expression for dy/dx:

y'(3) = -32(3)/(25)(6.4)

y'(3) = -0.3

Therefore, the value of y'(3) is - 0.3

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The velocity function is written as v(x) = sqrt(x - 3)

The graph is attached

If the velocity of a cruise ship is equal to the square root of the rate of fuel consumption minus 3 units,

Then we can write the velocity function as:

v(x) = sqrt(x - 3),

where

x represents the rate of fuel consumption.

The graph is plotted and attached

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The HHI is less than 1,800, which is considered a low level of market concentration. Therefore, we can conclude that both scenarios represent relatively competitive markets.

The Herfindahl-Hirschman Index (HHI) is a measure of market concentration that is commonly used to assess the degree of competition in a market. The index is calculated as the sum of the squared market shares of all the firms in the market. The HHI can range from 0 to 10,000, with higher values indicating greater market concentration.

To calculate the HHI for the two scenarios given, we need to first calculate the market shares of the teams in each scenario. In the first scenario, there are four teams with the following market shares:

Team A: 8/10 = 0.8

Team B: 2/10 = 0.2

Teams C and D: 0/10 = 0

The HHI for this scenario is calculated as:

HHI = [tex](0.8^2 + 0.2^2 + 0^2 + 0^2) \times10,000[/tex]

= 68,000

In the second scenario, there are eight teams with the following market shares:

Teams A and B: 4/10 = 0.4 each

Teams C and D: 1/10 = 0.1 each

Teams E, F, G, and H: 0/10 = 0 each

The HHI for this scenario is calculated as:

HHI = [tex](0.4^2 + 0.4^2 + 0.1^2 + 0.1^2 + 0^2 + 0^2 + 0^2 + 0^2) \times 10,000[/tex]

= 16,000

In both scenarios, the HHI is less than 1,800, which is considered a low level of market concentration. Therefore, we can conclude that both scenarios represent relatively competitive markets.

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Hence, [tex]-\frac{a}{\sqrt{ap-c} }[/tex] is the derivative of [tex]x=b-\sqrt{ap-c}[/tex].

Derivatives refers to the instantaneous rate of change of a quantity with respect to the other. That is, the amount by which a function is changing at one given point.

Given, [tex]x=b-\sqrt{ap-c}[/tex]

To find [tex]\frac{dx}{dp}[/tex]:

⇒[tex]\frac{dp(b-\sqrt{ap-c)}}{dx}[/tex]

⇒0- [tex]\frac{1}{2} (ap-c)^{-1/ 2} .\frac{d}{dp}(ap-c)[/tex]

⇒[tex]-\frac{ a.dp/dp+\frac{d}{dp}(-c) }{2\sqrt{ap-c} }[/tex]

⇒[tex]-\frac{a}{\sqrt{ap-c} }[/tex]

Hence, [tex]-\frac{a}{\sqrt{ap-c} }[/tex] is the derivative of [tex]x=b-\sqrt{ap-c}[/tex].

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The lines intersect, and the point of intersection and the cosine of the angle of intersection cosθ is 52.9°.

6t + 2 = 2s + 2; 7 = 2s + 7;

- t + 1 = s + 1

6t = 2s; 2s = 0 - t = s;

s = 0, t = 0.

So, (x, y, z) = (2, 7, 1) is intersection point

Direction vector of 1st line u = <6, 0, -1>; direction vector of 2nd line: v = <2, 2, 1>

cosθ = (6·2 + 0·2 - 1·1>/(√37·√9)

= 11/(3√37); θ

= cos-1(11/(3√37)

= 52.9°

Therefore, the value of cosθ is 52.9°

In mathematics, sine and cosine are trigonometric functions of an angle. The sine and cosine of an acute angle are defined in the environment of a right triangle for the specified angle, its sine is the rate of the length of the side that's contrary that angle to the length of the longest side of the triangle( the hypotenuse), and the cosine is the rate of the length of the conterminous length to that of the hypotenuse.

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It is less than 21 so it has to be 19.4.

Answer: volume would be 56

Step-by-step explanation:

Volume = length X width X height

The second sock picked is dependent on the first. The probability of picking a white sock for the left foot and a brown sock for the right foot without replacing the first sock is 1/12.

To calculate the probability of picking a white sock for the left foot and a brown sock for the right foot without replacing the first sock, we first need to count the total number of possible outcomes. There are 8 socks in the drawer: 2 white, 6 brown, and 4 black. Since we are picking two socks without replacing the first, the total number of possible outcomes is 8C2 = 28.

Next, we need to count the number of favourable outcomes. In this case, there is only one favourable outcome: picking a white sock for the left foot and a brown sock for the right foot.

Therefore, the probability of picking a white sock for the left foot and a brown sock for the right foot without replacing the first sock is 1/28.

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