Answer:
it is directly proportional to the temperature of the gas
Explanation:
Question 6
To what temperature must 15 L of oxygen gas at -30°C be heated at 1 atm pressure in order to occupy a
volume of 23 L, assuming that the pressure increases by 58 mm Hg?
unit:
Submit Question
Question 7
0/1 pt10 Deta
Jump to Answer
1/1 pt Details
Considering the combined law equation, the new temperature is -244.56 °C or 28.44 K.
Boyle's lawBoyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant: if the pressure increases, the volume decreases while if the pressure decreases, the volume increases.
Mathematically, this law states that the multiplication of pressure by volume is constant:
P×V=k
Charles's lawCharles's law states that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases while if the temperature of the gas decreases, the volume decreases.
Mathematically, Charles' law states that the ratio of volume to temperature is constant:
[tex]\frac{V}{T} =k[/tex]
Gay-Lussac's lawGay-Lussac's law states that the pressure of a gas is directly proportional to its temperature: increasing the temperature will increase the pressure, while decreasing the temperature will decrease the pressure.
Mathematically, Gay-Lussac's law states that the ratio of pressure to temperature is constant:
[tex]\frac{P}{T} =k[/tex]
Combined law equationCombined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:
[tex]\frac{PxV}{T} =k[/tex]
Considering an initial state 1 and a final state 2, it is fulfilled:
[tex]\frac{P1xV1}{T1} =\frac{P2xV2}{T2}[/tex]
New temperatureIn this case, you know:
P1= 1 atm= 760 mmHgV1= 15 LT1= -30 °C= 243 K (being 0 °C= 273 K)P2= 58 mmHgV2= 23 LT2= ?Replacing in the combined law equation:
[tex]\frac{760 mmHgx15 L}{243 K} =\frac{58 mmHgx23 L}{T2}[/tex]
Solving:
[tex]T2x\frac{760 mmHgx15 L}{243 K} =58 mmHgx23 L[/tex]
[tex]T2 =\frac{58 mmHgx23 L}{\frac{760 mmHgx15 L}{243 K}}[/tex]
T2= 28.44 K= -244.56 °C
Finally, the new temperature is -244.56 °C or 28.44 K.
Learn more about combined law equation:
brainly.com/question/4147359
#SPJ1
An ideal gas in a closed container initially has a volume V and Temperature T the final tempera is 5/4T and the final pressure is 2P what is the final gas
Answer:
[tex]V_2 = \frac{5V}{8}[/tex]
Explanation:
I am assuming you are saying what is the final volume of the gas
Known :
Initial volume (V1) = V
Initial temperature (T1) = T
Final temperature (T2) = 5/4 T
Initial pressure (P1) = P
Final pressure (P2) = 2P
Wanted: Final volume (V2)
[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\\frac{PV}{T} = \frac{(2P)V_2}{(5/4)T}\\\frac{V}{1} = \frac{(2)V_2}{5/4}\\5/4V = 2V_2\\\\V_2 = \frac{5V}{8}[/tex]
Which of the following sublevels contains only orbitals that are shaped like bells?
6f
4d
3p
5s
The sublevels that contains only orbitals that are shaped like bells are the 3p. That is option C.
What are atomic orbitals?Atomic orbitals are defined as the mathematical terms that are used to describe the positions of electrons on the atoms.
Examples of sublevels of atomic orbitals are s, p, d, and f. The 3p are the only orbitals that are bell like in shape
Therefore, sublevels that contains only orbitals that are shaped like bells are the 3p.
Learn more about atoms here:
https://brainly.com/question/6258301
#SPJ1
Which of the following arranges the bonds in order of decreasing bond length?
The order of decreasing bond length is; C- P > C - N > C=N. Option B
What is bond length?A chemical bond is formed when two compounds combine together. We know that the strength of a bond is shown by the bond length and the bond order. Clearly, bonds that have shorter bond lengths tend to be stronger than longer bonds that have a longer bond distance.
This explains why triple bonds are shorter and stronger bonds. This stems for the high s contribution (50%) in the formation of the bond. Therefore, the order of decreasing bond lengths is single bonds > Double bonds > triple bonds.
Now applying this background to the case in point, we can see that the decreasing order of bond energy must have to do with increasing bond order and decreasing bond distance.
Hence, the order of decreasing bond length is; C- P > C - N > C=N.
Learn more about bond order:https://brainly.com/question/16526043
#SPJ1
QUESTION 18
A container with a volume of 3.76 L holds 0.574 moles of nitrogen gas at 2.88 atm. What is the temperature of the gas in °C?
Answer:
-43.3 °C
Explanation:
To find the temperature, you need to use the Ideal Gas Law equation. The equation looks like this:
PV = nRT
In this formula,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas Law constant (0.08206 atm*L/mol*K)
-----> T = temperature (K)
By plugging the given values into the equation and simplifying, you can find the temperature. After you get a temperature, you need to convert it into Celsius.
P = 2.88 atm R = 0.08206 atm*L/mol*K
V = 3.76 L T = ? K
n = 0.574 moles
PV = nRT
(2.88 atm)(3.76 L) = (0.574 moles)(0.08206 atm*L/mol*K)T
10.8288 = (0.04710244)T
230. K = T
Kelvin - 273.15 = Celsius
230 K - 273.15 = -43.3 °C
15. When traveling through a smoke-filled area, a person must be able
distance of at least
in order to safely reach a fire exit.
O A. 10 feet
B. 12 feet
C. 4 feet
D. 8 feet
When traveling through a smoke-filled area, a person must be able to have distance of at least 4 feet in order to safely reach a fire exit. That is option C.
What is a smoke-filled area?Smoke-filled area is an enclosed area that is filled with smoke gas that is usually made up of carbon monoxide.
The smoke-filled area is usually caused by
Fire out breakBurning of plastics or chemical productsRelease of fuming gases.When there is smoke-filled area die to fire out break, there are some guidelines to follow to safely reach the fire exit early enough.
The importance of these guidelines include the following:
enable rescuers to navigate a scene more quickly,identify risks and hazards,locate safety points, determine the safest way in and out of a building, and map out evacuation routes.The affected individual should get down and crawl while taking short breath through the nose because cleaner air is nearest to the floor.
Learn more about distance here:
https://brainly.com/question/7243416
#SPJ1
When 50 electrons drop from energy level 4 to energy level 2, how many photons of light are given off?
1 photon
100 photons
2 photons
50 photons
The number of photons given off will be 50 photons.
To find the answer, we need to know about the plank's equation.
How to find the number of photons emitted?We have the expression for energy of a single electron in eV as,[tex]E=-13.6(\frac{1}{(n_f)^2}- \frac{1}{(n_i)^2})eV\\[/tex]
We have,[tex]n_f=4\\n_i=2\\N=50[/tex]
Substituting values, we get,[tex]E=-13.6(\frac{1}{(4)^2}- \frac{1}{(2)^2})eV\\\\E=-13.6*-0.188=2.55eV[/tex]
For N electrons,[tex]E=50*2.55eV=127.5eV[/tex]
We have the plank's equation,E=nhf
From this, the number of photons emitted from 50 electrons will be,[tex]n=\frac{E}{h*f} =\frac{127.5*1.67*10^{-19}J}{(6.63*10^-34)Js} \\[/tex]
To find n, we have to find the frequency f. For that, we have the equation,[tex]\frac{1}{wave length}=R_H(\frac{1}{(n_i)^2}- \frac{1}{(n_f)^2})\\\\1/wv= 1.1*10^5(\frac{1}{(2)^2}- \frac{1}{(4)^2})=20625cm^{-1}.\\wavelength=486nm.[/tex]
Thus, frequency will be,[tex]f=\frac{c}{wavelength} =\frac{3*10^8}{486*10^{-9}} =6.172*10^{14}s{-1}[/tex]
Then, the number of photons will be,[tex]n=\frac{E}{h*f} =\frac{127.5*1.67*10^{-19}J}{(6.63*10^-34)Js*6.17*10^{14} s^{-1}} \\\\n=52.05 photons[/tex]
Thus, we can conclude that, the number of photons given off will be 50 photons.
Learn more about the photons here:
https://brainly.com/question/15946945
#SPJ1
Suppose you experimentally calculate the value of the gas constant R
as 0.0878 L-atm/mol-K. The known value is 0.0821 L-atm/mol-K.
What is the percent error of your experimentally determined R?
Answer: 5.72%
Explanation:
Given:
Experimental value of gas constant, R = 0.0878 L.atm/mol⋅K
Known value of gas constant, R = 0.0821 L.atm/mol⋅K
This percent error is defined as the difference in percentage between a measurement's real value and its observed value.
[tex]\text { Percent Error }=\frac{\mid \text { Experimental Value }-\text { Known Value } \mid}{\text { Known Value }} * 100[/tex]
[tex]\text { Percent Error }=\frac{\mid \text {0.0878}-\text { 0.0821 } \mid}{\text { 0.0821 }} * 100[/tex]
[tex]\bf{Percent \ Error = 5.72\%}[/tex]
At 1755 oC the equilibrium constant for the reaction: 2 IBr(g) I2(g) + Br2(g) is KP = 0.748. If the initial pressure of IBr is 0.00465 atm, what are the equilibrium partial pressures of IBr, I2, and Br2? p(IBr) = . p(I2) = . p(Br2) = .
From the calculation, the equilibrium partial pressure of IBr is 6.5 * 10^-4 atm while that of I2 and Br2 is 0.002 atm.
What is the equilibrium pressure?We must set up the ICE table as shown hence;
2 IBr(g) < ------> I2(g) + Br2(g)
I 0.00465 0 0
C - 2x + x + x
E 0.00465 - 2x + x + x
Kp = pI2. pBr2/pIBr^2
pI2 = pBr2 = x
0.748 = x^2/ 0.00465 - 2x
0.748 (0.00465 - 2x) = x^2
3.5 * 10^-3 - 1.496x = x^2
x^2 + 1.496x - 3.5 * 10^-3 = 0
x=0.002 atm
Hence;
For IBr = 0.00465 - 2(0.002) = 6.5 * 10^-4 atm
For I2 and Br2 = 0.002 atm
Learn more about equilibrium constant:https://brainly.com/question/10038290
#SPJ1
Lactic acid has a pKa of 3.08. What is the approximate degree of dissociation of a 0.35 M solution of lactic acid?
A) 1.1%
B) 2.2%
C) 4.8%
D) 14%
E) none of the above
Your answer would be C, 4.8%.
balance the redox reaction in alkaline medium & identify the oxidizing & reducing agents
I- + MnO4- ——> IO3- + MnO2
The balanced redox equation of the reaction is given below:
I⁻ + 2 MnO₄ + H₂O → IO₃⁻ + 2 MnO₂ + 2 OH⁻The oxidizing agent is MnO₄ while the reducing agent is I⁻.
What are redox equations?Redox equations are equations in which oxidation and reduction reactions occur together.
Redox reactions can take place in alkaline or acidic mediums.
The balanced redox equation of the reaction is given below:
I⁻ + 2 MnO₄ + H₂O → IO₃⁻ + 2 MnO₂ + 2 OH⁻The oxidizing agent is MnO₄ while the reducing agent is I⁻
In conclusion, a balanced redox equation is one in which the atoms and the change in oxidation state is equal on both sides of the reaction.
Learn more about redox equations at: https://brainly.com/question/27239694
#SPJ1
3. What is the molar mass of Li2SO4? (2 points)
O 54.9 g/mol
103.0 g/mol
O109.9 g/mol
O 206.1 g/mol
Answer:
C.) 109.9 g/mol
Explanation:
The molar mass is the sum of each element's atomic weight times their quantity. There is one atom of each element unless denoted by subscripts.
Atomic Mass (Li): 6.9410 g/mol
Atomic Mass (S): 32.065 g/mol
Atomic Mass (O): 15.998 g/mol
Molar Mass (Li₂SO₄): 2(6.9410 g/mol) + 32.065 g/mol + 4(15.998 g/mol)
Molar Mass (Li₂SO₄): 109.939 g/mol
Suppose a gas mixture used for anesthesia contains 4.60 mol oxygen (O₂) and 6.00 mol nitrous oxide (N₂O). The total pressure of the mixture is 2.00 atm. A mole fraction is defined as the moles of a specific component divided by the total number of moles present. What is the mole fraction of O₂ in this mixture?
Considering the definition of mole fraction, the mole fraction of O₂ in the mixture is 0.434.
Definition of mole fractionThe molar fraction is a way of measuring the concentration that expresses the proportion in which a substance is found with respect to the total moles of the solution.
In other words, the mole fraction expresses the concentration of solute in a solution as the ratio of moles of substance to total moles of solution:
[tex]mole fraction=\frac{moles of substance}{moles of solution}[/tex]
Mole fraction of O₂ in this mixtureIn this case, you know a gas mixture used for anesthesia contains 4.60 mol oxygen (O₂) and 6.00 mol nitrous oxide (N₂O).
So, the total moles of the solution can be calculated as:
Total moles = moles of oxygen (O₂) + moles of nitrous oxide (N₂O)
Then:
Total moles= 4.60 moles + 6 moles
Total moles= 10.60 moles
Finally, the more fraction of O₂ can be calculated as follow:
[tex]Mole fraction of O_{2} =\frac{moles of O_{2}}{total moles}[/tex]
[tex]Mole fraction of O_{2} =\frac{4.60 moles}{10.6o moles}[/tex]
Solving:
Mole fraction O₂ = 0.434
Finally, the mole fraction of O₂ in the mixture is 0.434.
Learn more about mole fraction:
brainly.com/question/14434096
brainly.com/question/10095502
#SPJ1
Which organelle in the table is correctly matched with its function?
which one is it??
Answer:
[tex]\huge\boxed{\sf Ribosomes}[/tex]
Explanation:
Organelles and their function:Lysosomes:Lysosomes functions in the digestion of food of the cell.It contains hydrolytic enzymes.Vacuole:Vacuole mostly functions in storage.Mitochondrion:Mitochondrion is the power house of the cell.Ribosome:Ribosome functions in protein synthesis.[tex]\rule[225]{225}{2}[/tex]
• An alkane with the formula C5H12 undergoes chlorination to give only one product with the formula C5H11Cl. What is the structure of this alkane? •
Answer:
When an alkane undergoes a halogenation reaction, the majority of the products will add the halogen to the most substituted and most stable carbon. In this case, this would likely be the third carbon (middle).
Key:
Leftmost molecule = C₅H₁₂
Rightmost molecule = C₅H₁₁Cl
*Not pictured = HCl (another product)
An analyst prepared a sucrose solution by weighing 1kg of water and add 1.5kg of sucrose. what is the concentration of the resultant solution in mass percent
The concentration of solution in mass percent is 60%.
What is mass percentage?Mass percentage refer to the percentage of solute present in solution.
The concentration of substance can be expressed in mass percent.
So, we can write,
Mass percent = mass of solute / mass of solution x 100.
Mass of solution = mass of solute + solvent.
Here, sucrose is the solute and water is solvent.
Mass of solute is 1.5Kg and mass of solvent is 1Kg.
Mass of solution = 1.5 + 1 = 2.5 Kg.
Mass percent = 1.5/2.5x100
So, Concentration of solution in mass percent = 60%.
For a detailed study of mass percent refer the given link https://brainly.com/question/13896694.
#SPJ1.
please help me with this question as soon as possible
Answer:
nah what questionExplanation:
liquid octane(CH3)(CH2)6CH3) reacts with gaseous oxygen gas(O2) to produce gaseous carbon dioxide(CO2) and gaseous water(H2O). If 5.18 g of carbon dioxide is produced from the reaction of 3.43 g of octane and 19.1 g of oxygen gas, calculate the percent yield of carbon dioxide. Round your answer to 3 significant figures.
The percent yield of carbon dioxide will be 49.0 %.
Percent yieldFirst, let's look at the equation of the reaction:
[tex]2C_8H_1_8 + 25O_2 -- > 16CO_2 + 18H_2O[/tex]
The mole ratio of octane to oxygen is 2:25.
Mole of 3.43 g octane = 3.43/114.23 = 0.03 mol
Mole of 19.1 g oxygen = 19.1/32 = 0.60 mol
Thus, octane is limiting.
Mole ratio of octane to carbon dioxide = 2:16.
Equivalent mole of carbon dioxide = 0.03 x 8 = 0.24 mol
Mass of 0.24 mol carbon dioxide = 0.24 x 44.01 = 10.5624 grams
Percent yield of carbon dioxide = 5.18/10.5624 = 49.0 %
More on percent yield can be found here: https://brainly.com/question/17042787
#SPJ1
Two isotopes of lithium are found in nature Li6 has a mass of 6. 02u and Li7 has a mass of 7.02u . Use the atomic weight of lithium found on the periodic table to determine which isotope is more abundance
The isotope that is more abundant, given the data is isotope Li7
AssumptionLet Li6 be isotope ALet Li7 be isotope BHow to determine whiche isotope is more abundantMolar mass of isotope A (Li6) = 6.02 uMolar mass of isotope B (Li7) = 7.02 uAtomic mass of lithium = 6.94 uAbundance of A = A%Abundance of B = (100 - A)%Atomic mass = [(mass of A × A%) / 100] + [(mass of B × B%) / 100]
6.94 = [(6.02 × A%) / 100] + [(7.02 × (100 - A)) / 100]
6.94 = [6.02A% / 100] + [702 - 7.02A% / 100]
6.94 = [6.02A% + 702 - 7.02A%] / 100
Cross multiply
6.02A% + 702 - 7.02A% = 6.94 × 100
6.02A% + 702 - 7.02A% = 694
Collect like terms
6.02A% - 7.02A% = 694 - 702
-A% = -8
A% = 8%
Thus,
Abundance of B = (100 - A)%
Abundance of B = (100 - 8)%
Abundance of B = 92%
SUMMARY
Abundance of A (Li6) = 8%Abundance of B (Li7) = 92%From the above, isotope Li7 is more abundant.
Learn more about isotope:
https://brainly.com/question/24311846
#SPJ1
Balance the following reaction: NH3 + I2 --> N2I6 + H2
The balanced equation will be [tex]2NH_3 + 3I_2 -- > N_2I_6 + 3H_2[/tex]
What are balanced equations?They are chemical equations that obey the law of conservation of atoms.
In other words, they are equations in which the number of atoms before and after reactions are the same.
Thus, the balanced equation for the reaction will be [tex]2NH_3 + 3I_2 -- > N_2I_6 + 3H_2[/tex]
More on balancing equations can be found here: https://brainly.com/question/7181548
#SPJ1
An ion of an element can have the same as another element.
A. number of protons
B. None of these
OC. electron configuration
D. atomic mass
Answer:
A
Explanation:
In a simple perspective, an ion of an element is an element +- [tex]n[/tex] amount of electrons.
We know that electrons have atomic mass, so we can mark off D
We know that with more or fewer electrons, the electron configuration would change
However, the number of protons won't change in the ion of an element, this is because an ion is only the change in electrons, not protons or neutrons (the particles that make up a nucleus of an atom)
Which equation obeys the law of conservation of mass? H2(g) + O2(g) → H2O(g)
H2(g) + O2(g) → H2O(g) +4He(g)
2H2(g) + O2(g) → 2H2O(g)
H2(g) → H2O(g)
H2(g) + O2(g) → 2H2O(g)
Answer:
2H2(g) + O2 -> 2H2O
Explanation:
According to the law of conservation of mass, mass cannot be created nor destroyed in a chemical formula.
The only chemical reaction of the five options that follows this law is
2H2(g) + O2 -> 2H2O because the mass of the compounds stays the same before the reaction (arrow) and after.
Before reaction (reactants) we have:
2 (H2) = 4H
1 (O2) = 2O
After reaction takes place (products) we have:
2 (H2O) = 4H and 2O
and so mass is conserved.
Answer: its the 3rd option
Explanation: on edge hope this helps
Which of the following rules is applicable for balancing a chemical equation?
Change only the coefficients
Add the coefficients and change the subscripts
Change only the subscripts
Change the coefficients and the subscripts
Answer:
A.) Change only the coefficients
Explanation:
An equation is balanced when there is an equal quantity of each type of element on both sides of a reaction. When balancing an equation, the only way to manipulate the amounts of each element is by changing the coefficient values. The coefficients alter the amount of each molecule in the reaction.
The subscripts cannot be altered. If you were to change the subscripts, you would be altering the amount of atoms in a particular molecule.
If U-235 decays into Cs-135 and 4 neutrons, what other nuclide will be produced?
Fr-223
Pu-244
Ra-226
Rb-96
If U-235 decays into Cs-135 and 4 neutrons, the other nuclide that will be produced is Rb-96 (option D).
What is radioactive decay?A radioactive decay is the process by which an unstable large nuclei emit subatomic particles and disintegrate into one or more smaller nuclei.
According to this question, a radioactive material Uranium- 235 undergoes radioactive decay into Cs- 135 and 4 neutrons (1/0n).
This means that the mass of the products we have is 135 + 4 = 139.
The mass of the nuclide left must be 235 - 139 = 96, hence, the other nuclide that will be produced is Rb-96.
Learn more about radioactive decay at: https://brainly.com/question/1770619
#SPJ1
The second order reaction A → Products takes 13.5 s for the concentration of A to decrease from 0.740 M to 0.319 M. What is the value of k for this reaction?
The rate constant of the second order reaction is 0.137 M-1s-1.
What is the rate constant?For the second order reaction we can write;
1/[A] = kt + 1/[A]o
[A]o = initial concentration
[A] = final concentration
k = rate constant
t = time
Now;
1/0.319 = 13.5k + 1/ 0.740
1/0.319 - 1/0.740 = 13.5k
3.13 - 1.35 = 13k
k = 3.13 - 1.35/13
k = 0.137 M-1s-1
Learn more about second order reaction:https://brainly.com/question/12446045
#SPJ1
When the soil is saturated in a gently sloping area, any additional rainfall in the area will most likely
When the soil is saturated in a gently sloping area, any additional rainfall in the area will most likely become surface run off.
What is super saturation?
Super saturation occurs with a chemical solution when the concentration of a solute exceeds the concentration specified by the value equilibrium solubility.
Additional water into the soil will cause the soil to be super saturated and eventually runs off due to the steepness of the area.
Thus, when the soil is saturated in a gently sloping area, any additional rainfall in the area will most likely become surface run off.
Learn more about surface run off here: https://brainly.com/question/21926984
#SPJ1
A solution is prepared by mixing 200.0 g of water, H2O, and 300.0 g of
ethanol, C2H5OH. Determine the mole fractions of each substance.
Answer:
Mole Fraction (H₂O) = 0.6303
Mole Fraction (C₂H₅OH) = 0.3697
Explanation:
(Step 1)
Calculate the mole value of each substance using their molar masses.
Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol
Molar Mass (H₂O): 18.014 g/mol
200.0 g H₂O 1 mole
--------------------- x ------------------ = 11.10 moles H₂O
18.014 g
Molar Mass (C₂H₅OH): 2(12.011 g/mol) + 6(1.008 g/mol) + 15.998 g/mol
Molar Mass (C₂H₅OH): 46.068 g/mol
300.0 g C₂H₅OH 1 mole
---------------------------- x -------------------- = 6.512 moles C₂H₅OH
46.068 g
(Step 2)
Using the mole fraction ratio, calculate the mole fraction of each substance.
moles solute
Mole Fraction = ------------------------------------------------
moles solute + moles solvent
11.10 moles H₂O
Mole Fraction = -------------------------------------------------------------
11.10 moles H₂O + 6.512 moles C₂H₅OH
Mole Fraction (H₂O) = 0.6303
6.512 moles C₂H₅OH
Mole Fraction = -------------------------------------------------------------
11.10 moles H₂O + 6.512 moles C₂H₅OH
Mole Fraction (C₂H₅OH) = 0.3697
For any spontaneous process, universe entropy intensifies is known as the __________ law of thermodynamics.
Group of answer choices
fourth
second
tenth
For any spontaneous process, universe entropy intensifies is known as the second law of thermodynamics.
What is entropy?Entropy is defined as the degree of randomness or disorderliness of a system.
The entropy of a system generally increases for any spontaneous process.
This is according to the second law of thermodynamics.
In conclusion, the entropy of a system is the a measure of randomness of the system.
Learn more about entropy at: https://brainly.com/question/21578229
#SPJ1
The diagram shows the setup of an experiment. A few observations of the experiment are listed in table below the diagram.
Experimental Observations
1. Color of solution turned blue
2. Shiny hair like crystals deposited on the copper strip
Which of the following is the correct explanation for one of the given observations?
Observation 1 is a result of silver ions moving into the solution.
Observation 2 is a result of nitrate ions moving into the solution.
Observation 1 is a result of silver ions changing their oxidation state.
Observation 2 is a result of silver ions changing their oxidation state.
Answer:
Observation 2 is a result of silver ions changing their oxidation state.
Explanation:
Silver is reduced and forms silver precipitate. Observation 1 is a result of coppe being oxidized and forming copper nitrate
How many liters of fluorine gas are needed to
form 919 L of sulfur hexafluoride gas if the
following reaction takes place at 2.00 atm
and 273.15 K:
S(s) + 3F₂(g) → SF. (g)?
2756.1 liters of fluorine gas is needed to produce 919 liters of sulfur hexafluoride.
Given data:The volume of SF₆ = 919 L
Pressure = 2 atm
Temperature = 273.15 k
The volume of fluorine required =?
Balance chemical equation:
S (s) + F₂(g) → SF₆(g)
First of all, we will calculate the moles of SF₆.
PV = nRT
n = PV/RT
n = 2. atm× 919L / 0.0821 L. atm. mol⁻¹. K⁻¹ × 273.15 K
n = 1838 atm. L/ 22.43 L. atm. mol⁻¹
n = 81.9 mol
81.9 moles of SF₆ will produce.
Now we will compare the moles of SF₆ and fluorine from the balanced chemical equation.
SF₆: F
1 : 3
81.9 : 3/1 × 81.9 = 245.7 moles
Now we will calculate the volume of fluorine.
PV = nRT
V = nRT / P
V= 245.7 mol × 0.0821 L. atm. mol⁻¹. K⁻¹ × 273.15 K / 2 atm
V = 5512.2 / 2
V = 2756.1 L
2756.1 liters of fluorine gas are needed to produce 919 liters of sulfur hexafluoride.
To know more about volume refer to: https://brainly.com/question/18241314
#SPJ1