Thiamin, niacin, and riboflavin work together in important biochemical pathways that involve energy production and metabolism.
Thiamin, niacin, and riboflavin are all B vitamins that play crucial roles in various biochemical pathways in the body. They are involved in energy production and metabolism, supporting the conversion of carbohydrates, proteins, and fats into usable forms of energy. Thiamin, also known as vitamin B1, is essential for the metabolism of glucose. It is a coenzyme in important reactions that convert pyruvate into acetyl-CoA, which enters the citric acid cycle for energy production.
Niacin, or vitamin B3, is involved in energy metabolism as well. It functions as a coenzyme in the conversion of carbohydrates, fats, and proteins into energy. Niacin is a component of NAD (nicotinamide adenine dinucleotide) and NADP (nicotinamide adenine dinucleotide phosphate), which participate in redox reactions and electron transfer processes. Riboflavin, also known as vitamin B2, is essential for energy production through its involvement in the electron transport chain.
It serves as a precursor for the coenzymes FAD (flavin adenine dinucleotide) and FMN (flavin mononucleotide), which play a vital role in oxidative phosphorylation and the production of ATP. Together, thiamin, niacin, and riboflavin contribute to the efficient utilization of nutrients for energy production and metabolic processes in the body.
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What is the name of the amide bond between amino acids?
a. polyamide bond
b. polyamine bond
c. polyamino acids bond
d. protein bond
e. peptide bond
The name of the amide bond between amino acids will be peptide bond.
Peptide bonds are amide-type covalent bonds that form bonds that connect two adjacent alpha-amino acids throughout peptide or protein chains, starting at C1 of one as well as [tex]N_{2}[/tex] of another.
The substances are known as amino acids, or the "building blocks of proteins," and play a variety of vital functions in the human body. Humans require them for essential functions like producing hormones, neurotransmitters, even proteins. In meals high in protein like meat, fish, as well as soybeans, amino acids could be concentrated.
Therefore, the name of the amide bond between amino acids will be peptide bond.
Hence, the correct answer will be option (e)
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an acid accepts H and removes them from a solution, is a solution where the water molecules are intact
When placed in water, acids, bases, and salts dissociate (separate) into electrolytes (ions). Salts dissociate into a cation (that is not H+) and an anion (that is not OH-), whereas acids and bases dissociate into H+ and an anion. An acid separates into anions and hydrogen ions (H+). Strong acids produce a high concentration of H+ by dissociating every single one of their molecules . Water-based solutions,
Acid:
When a material or chemical is in solution, it releases hydrogen ions (H+), which are known as acids. All hydrogen ions (H+) and chloride ions (Cl-), which are normally bound together by ionic bonding, dissociate (separate) in water when exposed to a strong acid like hydrochloric acid (HCl). Only some ions disintegrate into hydrogen ions (H+) and bicarbonate ions (HCO3-) in a weak acid like carbonic acid (H2CO3), while others are still bound together by ionic bonds.
Define base?
A base is a chemical that, when in solution, emits hydroxyl ions -{OH). We can also define a base as a substance that releases hydroxyl ions (OH-), which mix with any hydrogen ions (H+) in the solution to generate water molecules (OH- + H+ = H2O).
Therefore, a substance that receives or accepts hydrogen ions (H+) that are already present in the solution qualifies as a base.
Because it totally dissociates into sodium ions (Na+) and hydroxyl ions (OH-) when placed in water, sodium hydroxide (NaOH), which is a strong base, is now liberated and dissolves in water.
c
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Which molecules are types of lipids?
Answer: The answer is fatty acids and triglycerides
Explanation:
Briefly explain how you would name an organic compound containing each of the functional groups.
Functional groups include hydroxyl, methyl, carbonyl, carboxyl, amino, phosphate, and sulfhydryl.
Functional groups:
Regardless of the other atoms in a molecule, functional groups are particular groupings of atoms within molecules that have their own distinctive capabilities.
The prefixes di, tri, and tetra are applied when there are several substituents. Function-specific groups contain identifying suffixes. For instance, the parent chain name of alcohols has the suffix "ol" and a number indicating the location of the hydroxyl group. One is used to identify ketones.
If a compound has multiple functional groups, the highest priority functional group will be considered the "parent structure" and will define the "parent name"; the remaining functional groups will be considered the "substituents." The name of the parent structure is denoted by the "suffix," and the substituent is denoted by the "prefix."
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Liquids A and B form an ideal solution. The vapor pressure of pure A is 0.700 atm at the normal boiling point of a solution prepared from 0.250 mole of B and 0.650 mole of A. What is the vapor pressure of pure B at this temperature
The vapor pressure of pure B is 1.77atm
Given:-
Vapor pressure of Pure A = 0.700atm
Mole of A = 0.650mole
Mole of B = 0.250mole
Dalton's law of partial pressures states that the total pressure exerted by a gas mixture is equal to the sum of the partial pressures of all of the constituent gases.
So, Ptotal = [tex]P_A + P_B[/tex]
According to Raoult's law, a solvent's partial vapor pressure in a solution (or mixture) is equal to or the same as the pure solvent's vapor pressure times the mole fraction present in the solution.
So, Ptotal = [tex]X_AP_A + X_BP_B[/tex]
Ptotal = 1atm
1atm = (0.650/0.650+0.250 X 0.700atm) + 0.250/0.650+0.250 X [tex]P_B[/tex]
1atm = 0.722 X 0.700atm + 0.278 X [tex]P_B[/tex]
1atm = 0.506atm + 0.278 X [tex]P_B[/tex]
1atm - 0.506atm = 0.278 X [tex]P_B[/tex]
0.494atm = 0.278 X [tex]P_B[/tex]
[tex]P_B[/tex] = 0.494atm / 0.278
[tex]P_B[/tex] = 1.77atm
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Given the incomplete equation for the combustion of ethane (C2H6): 2 C2H6 7 O2 --> 4 CO2 6 ___ Group of answer choices
The correct option is D. H2O.
For the combustion of ethane (C2H6); the chemical equation is;
2 C2H6 + 7 O2 --> 4 CO2 + 6 H2O.
All hydrocarbons go through combustion processes, and the only byproducts are water (H2O) & carbon dioxide (CO2).
What is hydrocarbons?Any of a group of organic molecules with only the atoms carbon (C) & hydrogen are known as hydrocarbons (H). The hydrogen atoms bind to the carbon atoms in a variety of ways to create the compound's structural framework. chemical mixture.
The classification of hydrocarbons are done by-
It is not necessary for a substance to be classified into a single class; rather, this categorization of hydrocarbons is meant to help in the association of structural traits with properties. In fact, it is typical for molecules to contain structural elements that are unique to two or even more hydrocarbon families. For instance, a molecule with a benzene ring and a carbon-carbon triple bond would have certain features that are typical of alkynes and some that are typical of arenes.Alkenes, alkynes, and aromatics are referred to as unsaturated hydrocarbons, whilst alkanes are regarded as saturated hydrocarbons.To know more about hydrocarbons, here
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The complete question is -
Given the incomplete equation for the combustion of ethane (C2H6): 2 C2H6 + 7 O2 --> 4 CO2 + 6 ___
Group of answer choices:
A. H2O2
B. HCOOH
C. CH3OH
D. H2O
You have two buffered solutions. Buffered solution 1 consists of 5.0 M HOAc and 5.0 M NaOAc; buffered solution 2 is made of 0.050 M HOAc and 0.050 M NaOAc. How do the pHs of the buffered solutions compare
The pH of buffered solution is:
The two buffered solutions have 'equal' pH values.
Comparison between two buffer solutions:
To compare the pH of two different buffer solutions with different concentrations, Henderson-Hasselbalch equation is used.
pH = pKa + log [tex]\frac{Salt}{Acid}[/tex]
pKa of HOAc = 4.76
In solution 1:
Concentration of salt= 5 M
Concentration of acid= 5 M
Putting the values in the equation,
pH = 4.76 + log [tex]\frac{5}{5}[/tex]
pH = 4.76 + log1
pH = 4.76
In solution 2:
Concentration of salt= 0.050 M
Concentration of acid= 0.050 M
Putting the values in the equation,
pH = 4.76 + log[tex]\frac{0.050}{0.050}[/tex]
pH = 4.76 + log1
pH = 4.76
As the ratio [tex]log\frac{salt}{acid}[/tex] is the same for the different solutions.
Therefore, the pH of the solution remains the same in both the buffer solutions even if the two solutions have different concentrations.
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4. A 0.51 kg solution contains 87 mg of potassium iodide. Calculate the W/W concentration
of this solution.
Taking into account the definition of percentage composition, the percent composition of potassium iodide in this sample is 0.017%.
Definition of percent compositionThe Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.
To calculate the percentage of composition, it is necessary to know the mass of the element in a known mass of the compound.
Percentage Composition in this caseIn this case, you know that a 0.51 kg (or 510000 mg, being 1 kg= 1000000 mg) solution contains 87 mg of potassium iodide.
Dividing the mass amount of potassium iodide present in the compound by the mass of the sample and multiplying it by 100 to obtain a percentage value, the percentage composition of potassium iodide is obtained:
[tex]percentage composition of potassium iodide=\frac{87 mg}{510000 mg} x100[/tex]
percentage composition of potassium iodide= 0.017%
Finally, the percent composition of potassium iodide in this sample is 0.017%.
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calculate the number of moles in 2 kg of iron
Answer:
111600 moles
Explanation:
Number of moles= Mass ×Mr, where Mr is the relative molecular mass of the substance of interest. Note that the mass is calculated in terms of grams (1 kg= 1000 g), while the Mr can be found using the periodic table.
Mass of iron
= 2 kg
= 2(1000)
= 2000 g
Mr of iron= 55.8
Number of moles
= 2000(55.8)
= 111600 mol
Additional:
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https://brainly.com/question/21042927Calculate your % yield of co2 in the reaction based on the grams of nahco3 being the limiting reagent in the reaction.
The percent yield of CO₂ is 93.3%.
What is the percent yield of CO₂?The percent yield of a substance is given as follows:
Percent yield = actual yield/theoretical yield * 100 %The equation of the reaction is used to determine the theoretical yield.
NaHCO₃ + CH₃COOH → CH₃COONa + H₂O + CO₂Moe ratio of sodium bicarbonate and CO₂ is 1 : 1.
Given that sodium bicarbonate is the limiting reactant, the theoretical yield of CO₂ will be:
Moles of NaHCO₃ reacting = 2.01/84 = 0.0239 moles
Theoretical yield of CO₂ = 0.0239 moles * 22.4L/mol = 0.536 L
Actual yield = 0.50 L
Percent yield = 0.50/0.536 * 100%
Percent yield = 93.3%
In conclusion, the percent yield is the ratio of the actual yield and theoretical yield.
Note that the complete question is given below:
Calculate your % yield of co2 in the reaction based on the grams of nahco3 being the limiting reagent in the reaction between 2.01 g of sodium bicarbonate and 24.6 mL of 1.5 M acetic acid? They produce 0.50 L of at s.t.p.
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when gas evolution becomes very slow, heat the solution gently in the hood, then allow it to cool. What gas is formed in this reaction
Nitrogen gas is formed in this reaction.
Nitrogen gasAtomic number 7 and the letter N designate nitrogen as the chemical element. Group 15 of the periodic table, often known as the pnictogens, contains nitrogen as the lightest nonmetal element. It ranks eighth in overall abundance in the Milky Way and the Solar System, making it a common element in the cosmos. Two of the element's atoms combine to create the colorless and odorless diatomic gas N2 at standard temperature and pressure. The most common element that isn't mixed, N2 makes up around 78 percent of the Earth's atmosphere. All living things contain nitrogen, which is mostly found in amino acids (and thus proteins), nucleic acids (DNA and RNA), and the energy-transfer molecule adenosine triphosphate.
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How many moles of MgCl₂ are present in 60.0 mL of 0.100 M MgCl₂ solution?
There is 0.0600moles of MgCl2 in 60.0ml of 0.100M MgCl2 solution.
Explanation:
First we need to determine the number of moles of MgCl2 in 60.0L of solution.
After determining the number of moles,now multiply moles of MgCl2 by its Molar mass i.e (95.205g/mol)
We know Molarity= mol of solute/L solution
∴ 0.10 M MgCl2 = 0.10mol MgCl2/L
Step1:
First convert 60.0ml to litres.
1L=1000mL
60.0mL×1L/1000mL=0.0600L
Step2:
To determine moles of MgCl2, multiply 0.0600 L by the molarity of the solution
0.0600L×0.10mL/1L=0.0600mol MgCl2
∴ 0.0600moles of MgCl2 are present in 60.0mL of 0.100M MgCl2 solution.
what is molar mass?Relative molar mass is defined as the smallest mass unit of a compound with one twelfth of the mass of one carbon – 12 atom.
In a substance, the amount of entities present for e.g. atoms, molecules, ions, is defined as a mole. A mole of any substance is 6.022×1023 molecules. Just as we take a standard value to calculate different things e.g. 1 dozen =12 items similarly we use the mole to calculate the size of the smallest entities quantitatively.
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what is molarity?Molarity of a solution is defined as the number of moles of the solute dissolved per litre of the solution. I is represented as \textbf{`M`}. Thus a solution, which contains one gram mole of the the solution dissolved per litre* of the solution is regarded as molarity.
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What product is used in a pedicure bath to cleanse and soften the skin? a foot masque a foot soak massage oil cuticle remover submitnext
The product which is used in a pedicure bath to cleanse and soften the skin is foot soak
What is skin pedicure?Skin pedicure is a special and cosmetic treatment of the body's skin including the feet and toenails, analogous to a manicure.
So therefore, the product which is used in a pedicure bath to cleanse and soften the skin is foot soak
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For what mechanistic reason does g1 of lactase first act as a brønsted acid during catalysis?.
Glucose becomes a better leaving group.
In a manner similar to how protonation of an alcohol makes it easier to substitute a -OH group, glucose becomes a better leaving group when the oxygen atom is protonated.
What is Bronsted acid-base theory?A substance that releases or donates hydrogen ions during a chemical reaction is referred to as a Bronsted-Lowry acid. A Bronsted-Lowry base, on the other hand, takes hydrogen ions. Another way to look at it is that a base accepts protons whereas a Bronsted-Lowry acid donates them. Amphoteric species are those that, depending on the circumstance, can either give or take protons.
Every Bronsted-Lowry acid gives a species that is its conjugate base a proton in exchange for the species' support. Each base in the Bronsted-Lowry system similarly accepts a proton from its conjugate acid.
I understand the question you are looking for is this:
For what mechanistic reason does G1 of lactase first act as a Bronsted acid during catalysis?
A) G1 becomes a better nucleophile
B) G2 becomes a better nucleophile
C) Glucose becomes a better leaving group.
D) Galactose becomes a better leaving group.
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He nitrogen cycle is one of the most important (and complex!) of the biogeochemical cycles. Why is nitrogen important?
Nitrogen is an essential part of proteins and nucleic acids (DNA).
Why is nitrogen important?All living things require nitrogen. It is a part of proteins, ATP, chlorophyll, DNA, and RNA. Given that it makes up a significant portion of the structures of biomolecules in living organisms, its synthesis and consumption in the biogeochemical cycle are of highest importance. Proteins are made up of amino acids (NH2 group).
The structural development of living species' genetic material (DNA, RNA) also involves nitrogen. It is a part of the nitrogenous bases, which together with other nucleotides create RNA and DNA.
Therefore, a nitrogen deficit can cause major structural issues for such an organism.
What happens if nitrogen cycle is disrupted?A number of undesirable consequences can result from the nitrogen cycle being disrupted. For instance, an abundance of nitrogen in aquatic systems leads to eutrophication. Acid rain can be caused by a rise in atmospheric nitrogen.
The majority of ecosystems can tolerate low nitrogen levels since the majority of nitrogen is not biologically accessible in nature. Ecosystems become out of balance when humans significantly increase the quantity of nitrogen that is accessible through fertilizers, fertilizer use, and other means.
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Zinc Sulfide reacts with oxygen according to the reaction:
2ZnS (s) + 3 O2(g) 2 ZnO (s) +2 SO2 (g)
A reaction mixture contains 4.2 moles of zinc sulfide and 6.8 moles of oxygen. Once the reaction occurred as a completely as possible, what amount in moles is left of the excess reactant?
The amount in moles of the excess reactant left is 0.5 mole
Balanced equation2ZnS (s) + 3O₂(g) --> 2ZnO (s) + 2SO₂(g)
From the balanced equation,
2 moles of ZnS reacted with 3 moles of O₂
How to determine the excess reactantFrom the balanced equation,
2 moles of ZnS reacted with 3 moles of O₂
Therefore,
4.2 moles of ZnS will react with =(4.2 × 3) / 2 = 6.3 moles of O₂
From the calculations made above, we can see that only 6.3 moles of O₂ out of 6.8 moles given, is required to react completely with 4.2 moles of ZnS.
Thus, ZnS is the limiting reactant and O₂ is the excess reactant.
How to determine the mole of the excess reactant remainingThe excess reactant is O₂. Thus the mole remaining after the reaction can be obtained as illustrated below:
Mole of O₂ given = 6.8 molesMole of O₂ that reacted = 6.3 molesMole of O₂ remaining =?Mole of O₂ remaining = (Mole of O₂ given) - (Mole of O₂ that reacted)
Mole of O₂ remaining = 6.8 - 6.3
Mole of O₂ remaining = 0.5 mole
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1. You have learned that alkyl iodides may be prepared by SN2 replacement of other leaving groups, or by treatment of alcohols or ethers with co centrated hydriodic acid (HI). A milder method for preparation of alkyl iodides from alcohols is shown below:
Imidazole's cyclic structure is aromatic and the lone pair present at the N₁ atom available for donation. hence, according to question N₁ is the most basic atom in the structure.
What is resonating structure?Two π bonds (between C₂-C₃ and N₁-C₅), as well as one lone pair on N₄, can interact with one another to generate a delocalized π system in the cyclic structure.This delocalization is intriguing since it has the same number of delocalized electrons as benzene—six.As a result, imidazole, like benzene, has a closed, delocalized ring with six π electrons. So, like benzene, it is regarded as an aromatic chemical with resonance stability.N₄ is neutral since it cannot be donated because it needs to use its lone pair to be aromatic.On the other hand, N₁ already forms a π connection, which helps the system become delocalized.N₁ is sp² hybridized and has a trigonal planar basic form. Its lone pair cannot communicate with the delocalized π system since it is pointed away from the cyclic structure.Know more about Resonating structure
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If 10.0 moles of sulfur dioxide react with excess chlorine gas, what is the theoretical yield (in grams) of CI2O produced?
Answer:
869 g Cl₂O
Explanation:
To find the theoretical yield of Cl₂O, you need to (1) convert moles SO₂ to moles Cl₂O (via mole-to-mole ratio from reaction coefficients) and then (2) convert moles Cl₂O to grams Cl₂O (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs of the given amount (10.0 moles).
1 SO₂ (g) + 2 Cl₂ (g) ----> 1 SOCl₂ (g) + 1 Cl₂O (g)
Molar Mass (Cl₂O): 2(35.453 g/mol) + 15.998 g/mol
Molar Mass (Cl₂O): 86.904 g/mol
10.0 moles SO₂ 1 mole Cl₂O 86.904 g
------------------------ x ---------------------- x ------------------ = 869 g Cl₂O
1 mole SO₂ 1 mole
What mass of oxygen reacts during the incomplete combustion of 18.0 g of propane?
Answer:
66 grams of carbon dioxide
C3H8+5O2=3CO2+4H2O
Match the instrument described below with the decimal place of the
value to which this instrument must be recorded.
our meter stick
our quadruple beam scale
a 100 mL cylinder
a 1 L cylinder
The decimal place value of these instrument must be recorded as (i) our meter scale = 1 (ii) our quadruple beam scale = 0.001 (iii) a 100 mL cylinder = 1 (iv) a 1 L cylinder = 0.001.
What is Meter Stick ?Meter stick which is used to measure the length especially used in the construction industry. The meter stick is 1 meter long. The metric unit for length is meter.
What is Quadruple beam scale ?This is the instrument which is used to measure the mass very precisely. In quadruple beam scale the reading error is 0.001.
Thus from the above conclusion we can say that The decimal place value of these instrument must be recorded as (i) our meter scale = 1 (ii) our quadruple beam scale = 0.001 (iii) a 100 mL cylinder = 1 (iv) a 1 L cylinder = 0.001.
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Question: Match the instrument described below with the decimal place of the value to which this instrument must be recorded. ( 1 , 0.01 , 0.001 , 0.1 , 10 choose)
our meter stick =
our quadruple beam scale =
a 100 ml cylinder=
a 1 L cylinder=
Which best describes the oxidizing agent in this reaction?
Cl2(aq) + 2Br–(aq) Right arrow. 2Cl–(aq) + Br2(aq)
Bromine (Br) is the oxidizing agent because it gains an electron.
Bromine (Br) is the oxidizing agent because it loses an electron.
Chlorine (Cl) is the oxidizing agent because it gains an electron.
Chlorine (Cl) is the oxidizing agent because it loses an electron.
For the reaction Cl₂(aq) + 2 Br⁻(aq) ⇒ 2Cl⁻(aq) + Br₂(aq), Chlorine (Cl) is the oxidizing agent because it gains an electron.
What is the oxidizing agent?In a redox reaction, the oxidizing agent is the one that gains electrons, causing the other element to oxidize.
Let's consider the following redox reaction.
Cl₂(aq) + 2 Br⁻(aq) ⇒ 2Cl⁻(aq) + Br₂(aq)
The corresponding half-reactions are:
Reduction: 2 e- + Cl₂(aq) ⇒ 2Cl⁻(aq)
Oxidation: 2 Br⁻(aq) ⇒ Br₂(aq) + 2 e-
Which best describes the oxidizing agent in this reaction?
Bromine (Br) is the oxidizing agent because it gains an electron. NO. Br is the reducing agent.Bromine (Br) is the oxidizing agent because it loses an electron. NO. Br is the reducing agent.Chlorine (Cl) is the oxidizing agent because it gains an electron. YES.Chlorine (Cl) is the oxidizing agent because it loses an electron. NO. Cl gains electrons.For the reaction Cl₂(aq) + 2 Br⁻(aq) ⇒ 2Cl⁻(aq) + Br₂(aq), Chlorine (Cl) is the oxidizing agent because it gains an electron.
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Answer:
C: Chlorine (Cl) is the oxidizing agent because it gains an electron.
Explanation:
Conclusion: why do you think it is important to record your data with all the decimals provided by the instruments even if they are zero? How does this help with data analysis?
6) What is the pH of a solution with [H3O+] = 1 × 10-9 M?
A) 1.0 × 10-5
B) -9.0
C) 5.0
D) -5.0
E) 9.0
Answer:
E) 9.0
Explanation:
pH = -log [1×10^-9] = 9
Since volume and temperature are constant, this means that pressure and_____are____proportional. the sample with the largest____will have the_____pressure.
Since volume and temperature are constant, this means that pressure and number of moles are directly proportional. the sample with the largest number of moles will have the high pressure.
Since, the ideal gas equation is also called ideal gas law. So, according to ideal gas equations,
PV = nRT
P is pressure of the sampleT is temperatureV is volume n is the number of molesR is universal gas constantAt constant volume and temperature the equation become ,
P ∝ nR
since, R is also constant. So, conclusion of the final equation is
P ∝ n
The number of moles and pressure of the sample is directly proportion. So, on increasing number of moles in the sample , pressure of the sample also increases.
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You can use mass percent composition as a conversion factor between grams of a constituent element and grams of the compound. Write the conversion factor (including units) inherent in each mass percent composition. (a) Water is 11.19% hydrogen by mass. (b) Fructose, also known as fruit sugar, is
You can use mass percent composition as a conversion factor between grams of a constituent element and grams of the compound. The conversion factor in each mass percent composition are (a) 11.19 g H‚ 100 g H₂O (b) 53.29 g O‚100 g fructose (c) 84.12 g C‚100 g octane (d) 52.14 g C‚100 g ethanol
What is the Mass Percent ?The percent by mass of each element present in a compound is called Mass Percent.
(a) Water is 11.19% hydrogen by mass.
Here it is given mass of hydrogen is 11.19 %. That means 11.19 % of solute should be added in 100 g H₂O.
(b) Fructose, also known as fruit sugar, is 53.29% oxygen by mass.
Here it is given mass of oxygen is 53.29 %. That means in 53.29% of solute should be added in 100 g fructose.
(c) Octane, a component of gasoline, is 84.12% carbon by mass.
Here it is given mass of carbon is 84.12 %. That means in 84.29% of solute should be added in 100 g Octane.
(d) Ethanol, the alcohol in alcoholic beverages, is 52.14% carbon by mass.
Here it is given mass of carbon is 52.14 %. That means in 52.14% of solute should be added in 100 g Ethanol.
Thus from the above conclusion we can say that You can use mass percent composition as a conversion factor between grams of a constituent element and grams of the compound. The conversion factor in each mass percent composition are (a) 11.19 g H‚100 g H2O (b) 53.29 g O‚100 g fructose (c) 84.12 g C‚100 g octane (d) 52.14 g C‚100 g ethanol
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Question: You can use mass percent composition as a conversion factor between grams of a constituent element and grams of the compound. Write the conversion factor (including units) inherent in each mass percent composition.
(a) Water is 11.19% hydrogen by mass.
(b) Fructose, also known as fruit sugar, is 53.29% oxygen by mass.
(c) Octane, a component of gasoline, is 84.12% carbon by mass.
(d) Ethanol, the alcohol in alcoholic beverages, is 52.14% carbon by mass.
Consider the following intermediate chemical equations.
CH₂(g) → C(s) + 2H₂(g)
ΔΗ, = 74.6KJ
CCl4(g) →C(s) + 2Cl₂(g)
AH₂ = 95.7 kJ
H₂(g) + Cl₂(g) → 2HCl(g)
AH₂=-92.3 KJ
What is the enthalpy of the overall chemical reaction CH4(g)+4Cl₂(g) → CCl4(g) + 4HCI(g)?
O-205.7 kJ
O-113.4 kJ
O-14.3 kJ
O 78.0 kJ
Based on the calculations, the enthalpy of the overall chemical reaction is equal to: C. -14.3 kJ.
What is a chemical reaction?A chemical reaction can be defined as a chemical process that involves the continuous transformation (rearrangement) of the ionic, atomic or molecular structure of a chemical element by breaking down and forming chemical bonds, in order to produce a new chemical compound while new bonds are formed.
What is a chemical equation?A chemical equation can be defined as a group of chemical symbols that is typically used in chemistry to represent the chemical reaction between two (2) or more chemical elements.
Mathematically, an expression for enthalpy of the overall chemical reaction is given by:
ΔHrxn = (n × ΔH₃) + (-n × ΔH₁) + (n × ΔH₂)
Where:
n represents the number of moles.
Substituting the given points into the formula, we have;
ΔHrxn = (2 × ΔH₃) + (-1 × ΔH₁) + (1 × ΔH₂)
ΔHrxn = (2 × (-92.3)) + (-1 × (-74.6)) + (1 × (-95.7))
ΔHrxn = -184.6 + 74.6 + 95.7
ΔHrxn = -14.3 kJ.
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Name the following ether: OCH2CH3
A. ethyl benzyl ether
B. methyl phenyl ether
C. ethyl phenyl ether
D. ethyl propyl ether
The name of the given ether is ethyl benzyl ether .
What are ethers?Ethers are organic compounds formed when nan oxygen atom is bonded to two alkyl or aryl groups.
Ethers usually have relatively high boiling points as a result of the central oxygen atom. An example of an ether, is ethyl propyl ether
The name of the given ether is ethyl benzyl ether as it has a benzyl and ethyl group attached to the oxygen atom.
In conclusion, ethers are characterized by an oxygen atom bonded to two alkyl or aryl groups.
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The procedure calls for 2.0 ml of concentrated nitric acid. how many moles is this?
Answer:
ρHNO₃= 1.51 g/cm3
ρ = m/V
m = ρ x V
m = (1.51 g/cm3)(2 cm3)= 3.02 g de HNO₃
n = m/PM = 3.02 g/63.01 g/mol = 0.0479 mol de HNO₃
Explanation:
2 mL of concentrated nitric acid equals 0.0479 mol
Which state of matter is being described below?
It cannot be squashed easily, spreads out slowly, is of medium density & flows to
fill up space
A. Plasma
B. Liquid
C. Gas
D. Solid
Answer:
C. Gas
Explanation:
I think this is the right answer because it fits the description
5.18 L of nitrogen gas at 76.0°C are cooled to 6.0°C at constant pressure. Calculate the new volume of
the gas.
(write your answer in this space with sig digs and units - submit your work in the work space provided)
Answer:
0.409 L
Explanation:
Because you are dealing with volume and temperature, you need to use the Charles' Law equation:
V₁ / T₁ = V₂ / T₂
In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature.
V₁ = 5.18 L V₂ = ? L
T₁ = 76.0 °C T₂ = 6.0 °C
V₁ / T₁ = V₂ / T₂ <----- Charles' Law equation
5.18 L / 76.0 °C = V₂ / 6.0 °C <----- Insert values
0.06815789 = V₂ / 6.0 °C <----- Simplify left side
0.409 L = V₂ <----- Multiply both sides by 6.0