This figure was created by using two semi-circles and one rectangle. Find the area of the figure in square inches.

5) The equation of population after year 2000 is expressed as;

P = 65x + 622

6) Population in the year 2012 is; P = 1402 students

The parameters given are;

Population in 2003 = 817

Population in 2006 = 1012

Thus;

Average population growth per year = (1012 - 817)/3

Average population growth per year =  65 people

Now, we see that the population of people in the year 2000 was 622.

Thus;

5) Equation of population is;

P = 65x + 622

where x is number of years after year 2000

6) Population in the year 2012 which is 12 years after year 2000 is;

P = 65(12) + 622

P = 1402

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The sets of numbers could not represent the three sides of a triangle is

{12, 17, 30}.

The triangle inequality theorem explains the connection between a triangle's three sides. This theorem states that for any triangle, the sum of the lengths of the first two sides is always greater than the length of the third side.

Given:

a)  {12, 17, 30}

Using Triangle Inequality

12 + 17 < 30 This, measurement cannot give Triangle.

b) {15, 21, 33}

Using Triangle Inequality

15+ 21 > 33

21+33>15

33+15>21

This measurement give Triangle.

c)  {4, 6, 7}

Using Triangle Inequality

4 + 6 > 7

6+7>4

7+4 > 6

This measurement give Triangle.

d) {12, 27, 37}

Using Triangle Inequality

12+ 27 > 37

27+ 37 > 12

12 + 37 > 27

This measurement give Triangle.

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Answer:1,283.803

Step-by-step explanation:

To calculate the distance traveled by the satellite, we need to find the circumference of the circle it traces in the sky. The circumference can be found using the formula:

C = 2 * π * r

where r is the radius of the circle (i.e., the distance from the center of the earth to the satellite), and π is pi, approximately equal to 3.14.

r = 36,000 km

C = 2 * π * 36,000 km

C = 72,000 * π km

Next, we need to find what fraction of the circumference the satellite has traveled in one hour. This is given by the fraction of the total circle the satellite has traced, which is equal to the angle it has formed divided by 360°.

fraction = 32° / 360°

Finally, we can multiply the circumference by the fraction to find the distance traveled by the satellite:

distance = C * fraction

distance = 72,000 * π * 32° / 360° km

Rounding the result to the nearest kilometer, the satellite has traveled approximately:

distance = 73,382 km

So, the satellite traveled approximately 73,382 km in one hour.

(i) The smallest angular speeds that cause the toast to hit and then topple to be butter-side down 3.84 rad / s

(ii) The largest angular speeds that cause the toast to hit and then topple to be butter-side down 11.51 rad / 5

The distance from the counter to the floor, d = 82 cm = 0.82 m

Rotation is less than 1 rev.

The toast rotates at a constant angular speed as it falls, and the toast is falling with a constant acceleration (gravitational acceleration).

Using the kinematic equations of motion to calculate the time taken by the toast to hit the floor

[tex]$d & =v_i t+\frac{1}{2} g t^2 \\[/tex]

[tex]$d & =0+\frac{1}{2} g t^2 \\[/tex]

Therefore [tex]$t & =\sqrt{\frac{2 d}{g}}=\sqrt{\frac{2 \times 0. 82}{9.8}[/tex]

= 0.409 s

Where

[tex]$v_i$[/tex] is the initial speed of the toast, [tex]$v_i=0$[/tex] because the toast is falling from rest.

t the time that the toast takes to hit the floor.

g is the gravitational acceleration.

d is the distance between the counter and the floor.

Part (a)The toast is accidentally pushed over the edge of the counter with the butter side up, then the toast rotates as it falls. If the toast hits the ground and then topples to be butter-side down, it has to land on one of its edges. The smallest angle, in this case, is [tex]$\frac{1}{4}$[/tex] revolution and corresponds to the smallest angular speed

[tex]$\omega_{\min } & =\frac{\Delta \theta}{\Delta t} \\[/tex]

[tex]$\omega_{\min } & =\frac{0.25 \mathrm{rev}}{\Delta t}=\frac{0.25 \times 2 \pi}{\Delta t} \\[/tex]

Therefore [tex]$ \omega_{\min } & =\frac{0.5 \pi}{0.409}[/tex]

= 3.84 rad/s

Where

[tex]$\omega_{\min }$[/tex] is the minimum angular speed for the toast to land butter-side down. [tex]$\Delta \theta$[/tex] is the smallest angle for the toast to land butter-side down in radians.

[tex]$\omega_{\min }$[/tex] = 3.84 rad / s

Part b:

The toast is accidentally pushed over the edge of the counter with the butter side up, then the toast rotates as it falls. If the toast hits the ground and then topples to be butter-side down, it has to land on one of its edges. The largest angle, in this case, is [tex]$\frac{3}{4}$[/tex] revolution and corresponds to the largest angular speed

[tex]$\omega_{\max } & =\frac{\Delta \theta}{\Delta t} \\[/tex]

[tex]$\omega_{\max } & =\frac{0.75 \mathrm{rev}}{\Delta t}=\frac{0.75 \times 2 \pi}{\Delta t} \\[/tex]

Therefore [tex]$ \omega_{\max } & =\frac{1.5 \pi}{0.409}[/tex]

= 11.51 rad / s

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When a slice of buttered toast is accidentally pushed over the edge of a counter, it rotates as it falls. If the distance to the floor is 82 cm and for rotation less than 1 rev, what are the (i) smallest and (ii) largest angular speeds that cause the toast to hit and then topple to be butter-side down?

The steady-state matrix X for the given Markov chain is [-1.0 -1.5].

To find the steady-state matrix X for an absorbing Markov chain, we need to follow these steps,

Rearrange the given transition probability matrix P so that it is in standard form, where the absorbing states (if any) are in the lower right corner and the transient states are in the upper left corner.

Partition the standard form matrix P into submatrices Q and R, where Q contains the transient states and R contains the absorbing states.

Find the fundamental matrix N = (I - Q)^(-1), where I is the identity matrix.

Find the matrix B = N*R.

The steady-state matrix X is the bottom row of the matrix B, padded with zeros if necessary.

Now, let's apply these steps to the given matrix P,

The matrix P is already in standard form, with the absorbing states (states 2 and 3) in the lower right corner.

We can partition P into the submatrices Q and R as follows:

Q = [0.6 0.4]

      [0.2 0.5]

R = [1 0]

      [0 1]

The fundamental matrix N is:

N = (I - Q)^(-1)

   = ([[-0.625  0.5  ]

        [ 0.25  -0.6 ]])^(-1)

    = [[-2.4 -1.6]

        [-1.0 -1.5]]

The matrix B is:

B = N*R

  = [[-2.4 -1.6]

       [-1.0 -1.5]] * [[1 0]

                          [0 1]]

  = [[-2.4 -1.6]

      [-1.0 -1.5]]

The steady-state matrix X is the bottom row of B, padded with zeros if necessary. Since there are two absorbing states, the steady-state matrix X will be a row vector of length 2. Therefore, X = [ -1.0 -1.5  ]

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The values for the variables a and b in the parallelogram are 2 and 3 respectively.

The parallelogram STVW have two pairs of parallel sides hence VW = TS and TV = SW.

We shall evaluate for variables a and b as follows:

3a + 11 = a + 15

3a - a = 15 - 11 {collect like terms}

2a = 4

a = 4/2 {divide through by 2}

a = 2

3b + 5 = b + 11

3b - b = 11 - 5 {collect like terms}

2b = 6

b = 6/2 {divide through by 2}

b = 3

Therefore, the values for the variables a and b in the parallelogram are 2 and 3 respectively.

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The value of the car after 1 year will be $22,250 when it had a depreciation of 11%.

Depreciation is a term used in accounting to describe two different aspects of the same idea: first, the actual decline in fair value of an asset, such as the annual decline in value of factory equipment due to use and wear, and second, the allocation in accounting statements of the asset's initial cost to the periods in which it is used (depreciation with the matching principle).

Depreciation is the process of reallocating, or "writing down," the cost of a tangible item (such as equipment) over the course of that asset's useful life.

It also refers to the decline in asset value. Long-term assets are depreciated by businesses for accounting and tax reasons.

So, we know that the price of the car is:

$25000

Depreciation is 11%.

The value of the car after 1 year will be:

25000/100 * 11 = $2,750

25000 - 2,750 = $22,250

Therefore, the value of the car after 1 year will be $22,250 when it had a depreciation of 11%.

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Complete question:

You buy a new car that cost $25000. The car depreciates at a rate of 11% per year. What will be the value f the car after 1 year?

Answer: The slope of a line can be found using the formula:

m = (y2 - y1) / (x2 - x1)

where (x1, y1) and (x2, y2) are two points on the line.

Plugging in the given points, we get:

m = (-1 - (-6)) / (5 - 8)

m = 5 / -3

m = -5/3

So the slope of the line that passes through the points (8, -6) and (5, -1) is -5/3.

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

In table C, each time x increases by one, y increases by 26 correspondingly. This suggests that y = 26x. The other 3 tables do not show a consistent pattern or relationship between x and y.

Table A can be disproved because, though it seems at first to be a multiple of -2 for every x value, the third data value (3, -16) disproves this. It would have to be (3, -6) for this relationship.

Table B has no clear pattern; the difference from the y values corresponding to x=1 and x=2 is 23, while the difference between x=2 and x=3 is also 23. However, there is no x & y relationship that can be defined to find x or y when given the other.

Table D has no clear pattern; the difference between x=1 and x=2 is 6, but the difference between x=2 and x=3 is 7.

The value of x in the given figure is 4.

Vertically opposite angles are angles that are opposite one another at a specific vertex and are created by two straight intersecting lines. Vertically, opposite angles are equal to each other. These are sometimes called vertical angles.

Given that are two lines PS and TS intersecting at point Q, making angles PQT and RQS,

We need to find the value of x,

Here, angles PQT and RQS, are vertically opposite angles, and angles which are vertically opposite are equal,

Therefore,

∠ PQT = ∠ RQS

6x-1 = 23

6x = 24

x = 4

Hence, the value of x in the given figure is 4.

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Answer:

See below for answers

Step-by-step explanation:

Part A

[tex]\displaystyle V=\pi\int\limits^d_c {(R^2-r^2)} \, dy\\=\pi\int\limits^3_0 {\biggr(\biggr(\frac{y^2}{9}\biggr)^2-\biggr(\frac{y}{3}\biggr)^2\biggr)} \, dy\\=\pi\int\limits^b_a {\biggr(\frac{y^4}{81}-\frac{y^2}{9}\biggr)} \, dy[/tex]

Make sure to write the functions in terms of y since you rotate on a vertical axis.

Part B

[tex]\displaystyle V=\pi\int\limits^b_a {(R^2-r^2)} \, dx\\=\pi\int\limits^1_0 {((3-3\sqrt{x})^2-(3-3x)^2)} \, dx\\=\pi\int\limits^1_0 {((9-18\sqrt{x}+9x)-(9-18x+9x^2))} \, dx\\=\pi\int\limits^1_0 {(-18\sqrt{x}-9x-9x^2)} \, dx[/tex]

Make sure to fix the radii so they start at y=3.

C = 45 + 0.25t. The 45 represents the baseline amount that she is charged per month. The t represents each additional text, and the 0.25 represents how much she is charged for each additional text.

Answer:

x = 24

Step-by-step explanation:

In a parallelogram, adjacent angles are supplementary.

             ∠B + ∠C = 180°

        5x + 2x + 12 = 180

                7x + 12 = 180

Subtract 12 from both sides,

                   7x = 180 - 12

                  7x  = 168

Divide both sides by 7,

                  x = 168 ÷7

                 [tex]\boxed{x = 24^\circ}[/tex]

Answer:

50+50=100
50/2=25
125km in 2 and a half hours

Step-by-step explanation:

Umm I'm assuming this isn't a trick question and saying just add 50+50 for 2 hours and then divide 50 by 2 to get 25. so 125 I hope i'm right :')

Answer:

Step-by-step explanation:

The man would walk 125km.

Explanation: The man would walk 125km, because if every hour he is walking 50km then if he walks for 2.5 hours, then all you have to do is multiply 50km by 2.5 hours.

We can prove this statement by using the Pigeonhole Principle.

Let's say we have a collection of n integers and we want to demonstrate that at least one of them, or the sum of several of them, is a multiple of n.

Consider the 0, 1, 2,..., n-1 possible remainders when these integers are divided by n.

There must be at least one remainder that appears more than once since there are n numbers and only n potential remainders.

Case 1: Choose two integers from the set, say a and b, such that a b (mod n), that is, a and b have the same remainder when divided by n, if a remainder occurs more than once.

Since their remainders cancel out, their difference a - b is a multiple of n.

As a result, we have identified an integer that is a multiple of n in the set.

Case 2: The sum of any two integers in the set may be taken into consideration if there are no remainders that appear more than once.

Two integers a and b can be added together using the formula a + b = qn + r, where q is the quotient and r is the residual after a + b is divided by n.

The Pigeonhole Principle states that two pairs of integers must have the same remainder when combined modulo n since there are n potential remainders but only n-1 possible values for the remainder r (from 0 to n-1).

These pairings should be (a1, b1) and (a2, b2), where (a1 b1 (mod n) and (a2 b2) (mod n).

Then, there is:

(a1 + b1) + (a2 + b2) = (a1 + a2) + (b1 + b2) ≡ 0 (mod n)

thus the remainders of a1 + a2 and b1 + b2 are equal modulo n.

As a result, n is a multiple of the sum of these four numbers.

In either scenario, we have demonstrated that any collection of n integers contains either an individual integer that is a multiple of n or an aggregate of many numbers that is a multiple of n.

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RAID, which stands for Redundant Array of Inexpensive Disks, is a data storage technology that combines multiple physical disks into a single logical unit to provide data redundancy, improved performance, and increased storage capacity.

RAID accomplishes this by distributing data across multiple disks, so that if one disk fails, the data can be rebuilt from the remaining disks.

There are several different RAID levels to choose from, each with its own benefits and trade-offs. For a personal server with the goal of data backup and redundancy, RAID 1 would be a good choice.

Setting up RAID 1 is relatively straightforward. You'll need two identical hard drives of sufficient size, and a RAID controller (which may be built into the motherboard). You can then configure the RAID controller to mirror the data between the two drives, so that they appear as a single logical drive to the operating system.

It's worth noting that RAID is not a substitute for regular backups. While it can provide protection against disk failures, it won't protect against other types of data loss, such as accidental deletion or corruption. It's still important to have a regular backup schedule, and to store backups offsite or in the cloud to protect against physical damage or theft.

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1) The center of mass of a right-circular cone with a base radius r, height h, and a non-uniform mass density varies as the square of the distance from apex (tip of the cone) is:

ρ(x, y, z) = k × ([tex]\sqrt{(x^2 + y^2 + z^2)}[/tex])²

where k is a constant of proportionality.

2) The center of gravity of a very thin right-circular conical shell of a base radius R, and height h is: 2h/3

1) Let us assume that m represents the total mass of the right-circular cone.

The center of mass for the x, y, and z-coordinates would be:

x-coordinate:

[tex]x_{cm}[/tex] = (1/m) × ∫∫∫_V x × ρ(x, y, z) × dV

y-coordinate:

[tex]y_{cm}[/tex] = (1/m) × ∫∫∫_V y × ρ(x, y, z) × dV

z-coordinate:

[tex]z_{cm}[/tex] = (1/m) × ∫∫∫_V z × ρ(x, y, z) * dV

where V - the volume of the cone,

ρ(x, y, z) - the mass density function,

Since the mass density varies as the square of the distance from the apex, we have:

ρ(x, y, z) = k × ([tex]\sqrt{(x^2 + y^2 + z^2)}[/tex])²

where k is a constant of proportionality.

Substituting this into the above equations, we find the center of mass of the cone.

2) Let us assume that x’ be the distance from the vertex of the cone to any point on the axis of the  right-circular conical shell.

Also R be the radius of the base of the  right-circular conical shell and ‘h’ is the height of the  right-circular conical shell.

Let r be the distance of any point on the cone from the axis of the  right-circular conical shell , the distance being measured perpendicular to this axis.

And l is the distance of any point on the  right-circular conical shell directly from the vertex.

r/R = z/h = l / L

Let us assume that σ be the surface density of mass of the cone.

The formule for center of mass of a system is given by,

x=∫z.σ dA / ∫σdA

but dA = 2πr.dl which is an infinitesimal area around the circle.

After solving this expression we get x = 2h/3

Therefore, the center of gravity of a very thin right-circular conical shell of a base radius R, and height h is given by 2h/3

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AB line segment correctly represents the perpendicular bisector of line segment XY.

Line segment is the part of line which have two endpoint and bounded by two distinct end points and it contain every point on the line which is between its endpoint.

Given that;

There are 4 doted lines are shown.

Now, From all dotted line;

Line segment AB divides the line segment XY into two equal parts.

Hence, AB line segment correctly represents the perpendicular bisector of line segment XY.

Thus, ''AB line segment'' correctly represents the perpendicular bisector of line segment XY.

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As per the Poisson distribution, the expected value of V is given by [tex]e^{-\mu} * H(\mu).[/tex]

The Poisson distribution is a discrete probability distribution that models the number of events occurring in a given time interval or space.

The probability of observing k events in this interval is given by the Poisson probability mass function:

[tex]P(k; \mu) = (e^{-\mu} * \mu^k) / k![/tex]

where μ is the mean number of events in the interval. The Poisson distribution has some important properties, including the fact that its mean and variance are both equal to μ.

Now, let us consider a new random variable V, which is defined as V = 1/(1+U). We want to find the expected value of V, which is denoted by E(V).

To do this, we need to use the definition of the expected value. For a discrete random variable X with probability mass function p(x), the expected value is defined as:

E(X) = Σ x * p(x)

where the summation is taken over all possible values of X.

Using this definition, we can find E(V) as follows:

E(V) = Σ v * P(V = v)

where the summation is taken over all possible values of V.

To find P(V = v), we need to use the transformation method. This method involves finding the probability mass function of U and then using it to find the probability mass function of V.

Since U is a Poisson random variable with mean μ, its probability mass function is given by:

[tex]P(U = k) = (e^{-\mu} * \mu^k) / k![/tex]

Now, let us find the probability mass function of V. We have:

V = 1/(1+U) => 1/V = 1+U => U = 1/V - 1

Using this transformation, we can find the probability mass function of V as follows:

P(V = v) = P(U = 1/v - 1) = [tex]e^{-\mu} * \mu^{(1/v - 1)} / (1/v - 1)![/tex]

Now, we can use this probability mass function to find the expected value of V:

E(V) = Σ v * P(V = v)

[tex]= > \sum v * (e^{-\mu} * \mu^{1/v - 1}) / (1/v - 1)![/tex]

To simplify this expression, we can use the fact that the sum of the reciprocals of the first n positive integers is given by the nth harmonic number, Hn:

1/1 + 1/2 + 1/3 + ... + 1/n = Hn

Using this identity, we can rewrite E(V) as:

E(V) = [tex]\sum v * (e^{-\mu} * \mu^{1/v - 1}) / (1/v - 1)![/tex]

[tex]= e^{-\mu} * \sum (\mu/v)^{1/v} * (v-1)![/tex]

=> [tex]= e^{-\mu} * H(\mu)[/tex]

where H(μ) is the μth harmonic number.

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The solution to the system of equations is x = -1 and y = -3

From the question, we have the following parameters that can be used in our computation:

-2x+2y=-4

3x + 3y = -18

Multiply (1) by 1.5

So, we have the following representation

-3x + 3y = -6

3x + 3y = -18

Add the equations

6y = -24

So, we have

y = -3

This means that

-2x + 2(-3) = -4

Evaluate

2x = -2

Divide

x = -1

Hence, the value of x is -1

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Clinical Chemistry Principles, Techniques, and Correlations 7th ed. Bishop is False.

A typical analytical technique (the method used to determine a chemical or physical property of a chemical substance, chemical element, or mixture.) for dissolving a chemical combination into its constituent parts so that each part may be carefully examined is called "chromatography."

The liquid or gaseous medium that moves the items to be separated over the stationary phase of a chromatography device at varying speeds is called as mobile phase.

In chromatography, the stationary phase can be either a solid or a liquid matrix. The mobile phase, which moves through the stationary phase, typically occurs in a liquid or a gas.

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The graph of the function f(x) = 3√(3 - x) is at the end of the answer.

We want to graph the function f(x) = 3√(3 - x)

To do so, we need to find some points on that line, to find the points we need to evaluate the function in some values of x

if x = -1

f(-1) = 3√(3 + 1) = 3*2 = 6

if x = 3

f(3) = 3√(3 - 3) = 3*0 = 0

if x = -6

f(-6) = 3*√(3 + 6) = 3*3 = 9

if x = -13

f(-13) =  3*√(3 + 13) = 3*4 = 12

Then the points are (-1, 6), (3, 0), (-6, 9), (-13, 12)

Now we can just graph these 4 points and connect them with a curve, the graph of the function is below.

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The point-slope form of a linear equation is given by:

y - y1 = m(x - x1)

where m is the slope of the line and (x1, y1) is a point on the line.

Substituting the given values, we get:

y - 11 = (3/2)(x - 12)

Expanding and simplifying, we get:

y - 11 = (3/2)x - 18

y = (3/2)x - 7

Therefore, the equation of the line that passes through the point (12, 11) with slope 3/2 is y = (3/2)x - 7 in slope-intercept form or y - 11 = (3/2)(x - 12) in point-slope form.

the question is mistake

If two random variables are uncorrelated, they are independent and the covariance of X and Y is 0.

Probability is a measure of the likelihood of an event occurring.

In this case, we are given that P(X = -1) = 1/3, P(X = 0) = 1/3, and P(X = 1) = 1/3.

We are also given a second random variable Y, which is defined in terms of X. Y takes on the value of 1 when X = 0, and 0 otherwise. The probability distribution of Y is the set of probabilities associated with each possible value of Y. In this case, Y can only take on the values 0 or 1, so

=> P(Y = 0) = P(X = -1) + P(X = 1) = 2/3 and P(Y = 1) = P(X = 0) = 1/3.

The joint distribution of X and Y is the set of probabilities associated with each possible combination of X and Y. In this case, there are three possible combinations: (X = -1, Y = 0), (X = 0, Y = 1), and (X = 1, Y = 0). The joint probabilities are simply the products of the marginal probabilities of X and Y.

=> P(X = 0, Y = 1) = P(X = 0) * P(Y = 1) = (1/3) * (1/3) = 1/9.

Finally, we can calculate the covariance of X and Y, which is a measure of how much the two variables vary together. The formula for covariance is:

=> Cov(X,Y) = E[XY] - E[X]E[Y].

Using the joint distribution we calculated earlier, we can find

=> E[XY] = (-1)(2/9) + (0)(1/3) + (1)(2/9) = 0

and

=> E[X] = (-1)(1/3) + (0)(1/3) + (1)(1/3) = 0.

We can also find

=> E[Y] = (0)(2/3) + (1)(1/3) = 1/3.

Therefore,

=> Cov(X,Y) = 0 - (0)*(1/3) = 0.

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Answer:

[tex]59^{\circ}[/tex]

Step-by-step explanation:

Adjacent angles of a parallelogram are supplementary.

[tex]5x-11+11x-33=180 \\ \\ 16x-44=180 \\ \\ 16x=224 \\ \\ x=14[/tex]

Opposite angles of a parallelogram are congruent.

[tex]m\angle N =m\angle P \implies m\angle P=5(14)-11=59^{\circ}[/tex]

jump discontinuities x= DNE

removable discontinuities x= DNE

infinite discontinuities x= -2, 2

other discontinuities x= DNE

The function has an infinite discontinuity at x=-2 and x=2 because the denominator of the fraction, x^2 + 4, approaches 0 as x approaches -2 or 2.

Answer: The correct answer is A. If the graph of the system shows parallel lines, then there are infinite solutions.

When two linear equations in the system have the same slope and different y-intercepts, the lines will be parallel and will never intersect. This means that there is no solution to the system.

On the other hand, when two linear equations in the system have different slopes, the lines will intersect at exactly one point, which is the unique solution to the system.

So, in summary:

Parallel lines: no solution

Intersecting lines: one solution

Infinite solutions: lines are the same.

Step-by-step explanation:

The sum of the series

[tex]$b 2 b 4 b 6 b 8 b {10}$ is $b_2 \left (1-\dfrac{7^5}{4^5} \right ) \over 1-\dfrac{7}{4} = 180 \left (1-\dfrac{2401}{1024} \right ) \over \dfrac{3}{4} = 135.75$.[/tex]

The given series is a geometric series, which means that each successive term is multiplied by a common ratio to obtain the next term. The sum of the first 10 terms of this series is 180. Thus, the common ratio is [tex]$\dfrac{7}{4}.$[/tex]

Now to find the sum of the series [tex]$b 2 b 4 b 6 b 8 b {10}$[/tex], we apply the formula for the sum of the first n terms of a geometric series, which is [tex]$b_1 \left (1-r^n \right ) \over 1-r$[/tex], where [tex]$b_1$[/tex] is the first term, [tex]$r$[/tex] is the common ratio, and [tex]$n$[/tex] is the number of terms.

In our case, [tex]$b_1 = b_2$, $r = \dfrac{7}{4}$[/tex] and n = 5. Thus, the sum of the series [tex]$b 2 b 4 b 6 b 8 b {10}$ is $b_2 \left (1-\dfrac{7^5}{4^5} \right ) \over 1-\dfrac{7}{4} = 180 \left (1-\dfrac{2401}{1024} \right ) \over \dfrac{3}{4} = 135.75$.[/tex]

Learn more about geometric series here:

https://brainly.com/question/23602882

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