Answer:
(-9,4)
Step-by-step explanation:
3
x < -5
x + 4
f(x) =
x2 – 3x, -5
x4 – 7,
x > 0
Find f(-2)
f(-2) =
P
Answer: 10
Step-by-step explanation:
Since -2 is in between -5 and 0, we will use the part of the function that says f(x)=x^2 + 3x.
Substituting x=-2, we get (-2)^2 -3(-2)=4+6=10
1/h-5 + 2/h+5 = 16/h²-25
For what values of a are the following expressions true?
1. |a-5|=5-a
2.|a|=-a
Answer:
1. a = 0 and 5
2. no solutions
Step-by-step explanation:
For absolute value, it's the distance from that number on the number line to 0, so it has to be positive. We define absolute value as when |a| = b, a = b and a = -b.
1. |a - 5| = 5 - a
a - 5 = 5 - a
2a = 10
a = 5
AND
a - 5 = -(5 - a)
a - 5 = -5 + a
-5 = -5
a = 0 (a could work as 0 in this scenario)
Thus our solutions are a = 0 and 5.
2. |a| = -1
Now we have to catch ourselves here. Since absolute value is always positive, nothing works. There is no negative distance to 0 (at least in real numbers). Hence, we can say that there are no solutions.
Slove for YZ
Show all work
Answer: 34
Step-by-step explanation:
Answer:
YZ=34
Step-by-step explanation:
[tex]xy(xz)=xw(xv)\\\\6(2x+12+6)=10(x+3+10)\\\\6(2x+18)=10(x+13)\\\\12x+708=10x+130\\\\12x-10x=130-108\\\\\cfrac{2x}{2} =\cfrac{22}{2} \\\\x=11[/tex]
[tex]yz=2x+12\\\\2(11)+12\\\\22+12\\\\yz=34[/tex]
~
26
Kabita has two bags.
In the first bag there are 5 blue discs and 3 red discs.
In the second bag there are 7 blue discs and 4 red discs.
Kabita takes at random a disc from the first bag.
She then takes at random a disc from the second bag.
(a) Complete the probability tree diagram.
second
first bag
blue
7
11
blue
Complete the probability tree diagram
Answer:
I am not sure your is correct
Please help asap! I will gave brainlest!
Step-by-step explanation:
I know that
[tex] \cot {}^{2} (x) + 1 = \csc {}^{2} (x) [/tex]
So These the steps I need to do:
First Apply Reciprocal Identies to find Cot x.
[tex] \frac{1}{ \tan(x) } = \cot(x) [/tex]
So cot x is
[tex] \frac{24}{7} [/tex]
Now, I can squared that result and add 1 to get csc^2(x).
[tex] \frac{576}{49} + 1 = \frac{576}{49} + \frac{49}{49} = \frac{625}{49} [/tex]
Now, I take the principal square root since csc is positve when theta is in the 1st quadrant.
[tex] \frac{ \sqrt{625} }{ \sqrt{49} } = \frac{25}{7} [/tex]
So
[tex] \csc(x) = \frac{25}{7} [/tex]
[tex]cosec{\theta=\frac{25}{7}is\ the\ answer.}[/tex]
Step-by-step explanation:[tex]If\ tan\ \theta=\frac{7}{24},0\ degrees < \theta < 90\ degrees[/tex]
[tex]sec\ \theta=\sqrt{1+\tan^2\theta}=\sqrt{1+\frac{49}{576}}=\sqrt{\frac{625}{576}}=\frac{25}{24}[/tex]
[tex]cos\ \theta=\frac{1}{sec\ \theta}=\frac{24}{25}[/tex]
[tex]sin\ \theta=\sqrt{1-\cos^2\theta}=\sqrt{1-(\frac{24}{25})^2}=\sqrt{\frac{49}{625}}=\frac{7}{25}[/tex]
[tex]cosec\ \theta=\frac{1}{sin\ \theta}=\frac{25}{7}[/tex]
[tex]Hence,\ cosec\ \theta=\frac{25}{7}is\ the\ answer.[/tex]
I hope this helps you
:)
x-4(3-2x) = 3(3x+4)
Find X
Answer:
all x are the solution
Step-by-step explanation:
x - 4×3 - 4×(-2x) = 3×3x + 3×4
x - 12 + 8x = 9x +12
9x + 12 = 9x + 12
9x = 9x
(0 = 0)
no matter which number we take for x the equation will always be correct
ex. x = 3 : left : 9×3 = 27
right : 9×3 = 27
Solve the system.
x + y -z = 17
y +z = 1
Z= -3
Enter your answer as an ordered triple.
Answer:
[tex]z = - 3[/tex]
[tex]y - z = 1[/tex]
[tex]y + ( - 3) = 1[/tex]
[tex]y = 4[/tex]
[tex]x + 4 +3 = 17[/tex]
[tex]x = 10[/tex]
What is the y-intercept of the graph shown? Will give the brainiest answer
Answer:
(0, 4)
Step-by-step explanation:
The y-intercept is defined as the point where the line intersects the y-axis. All we need to do is find where the line intersects the y-axis.
(0, 4) is the answer.
Which of the figures shown above has the greater volume? Please show ALL of your work.
What is the best estimate for a length of a car?
Answer:
Yards
Step-by-step explanation: Yards make the most since because the average car is about 3 to 5 yards.
Find the area of this circle.
A= ?
5 in
Hint: First, plug in the value
of the radius into the
formula for r.
If radius, r = 5in., then we can compute that the area of the circle = 78.55in² or approximately 79in².
Using the formula, Area of Circle = πr²
It is given in the question, r = 5in and as we know that the value of π = 3.142
Now, putting the values from above in the formula of area of circle, we will get:
A = π × 5² = 3.142 × 25 = 78.55
= 79in² (to the nearest whole number).
The space a circle takes up in a two-dimensional plane is known as its area. Alternately, the area of a circle is the area contained within the circumference or boundary of the circle. The sum of the square units inside that circle is another name for it.
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For this function, find each of the following
a. f(-1)
b f(0)
c f(3)
f(x)=-2|3x+5|-2
I will mark it as the brainiest
Answer:
F=3-53-5=-12-t-2-54-
Step-by-step explanation:
Answer:
a. -6
b. -12
c. -30
Step-by-step explanation:
a. f(-1) b. f(0) c. f(3)
f(-1)=- 2|3× -1 +5| -2 f(0)= -2|3× 0 +5| -2 f(3)= -2|3× 3 +5| -2
f= -2|-3+5|-2 f= -2|0+5| -2 f= -2|9 +5| -2
f= -2|2|-2 f= -2|5| -2 f= -2|14| -2
f= -4-2 f= -10-2 f= -28 -2
f= -6 f= -12 f= -30
Last February there were 617,624 scheduled passenger flights in a certain country, and in February of 1999 there were 709,639. Use a percentage to express the relative change. Use the second given value as the reference value. The relative difference between February of 1999 and last February is -13%. What % decrease in the number of scheduled passenger flights from February of 1999 to last February?
The % decrease in the number of scheduled passenger flights from February of 1999 to last February was 12.97%.
PercentagesGiven that last February there were 617,624 scheduled passenger flights in a certain country, and in February of 1999 there were 709,639, to determine the % decrease in the number of scheduled passenger flights from February of 1999 to last February, the following calculation must be made:
709639 = 100617624 = X617624 x 100 / 709639 = X61762400 / 709639 = X87.03 = X100 - 87.03 = X12.97 = XTherefore, the % decrease in the number of scheduled passenger flights from February of 1999 to last February was 12.97%.
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how many 6/14 feet of rope can you make out of 49/14 peices of rope?
This word problem is another way of saying
How many times can 6/14 go into 49/14
To find this out we divide
(49/14)/(6/14)
We also know that dividing by a fraction is the same as multiplying
=(49/14)(14/6)
=49/6
≈8.16
As we just want how many segments of 6/14 feet rope, we can ignore the decimals/round down getting the answer
Eight pieces of rope can be made our of 49/14 piece of rope.
Show that ln(x^3 "-4x)" − ln(x^2 "-2x)=" ln(x + 2).
[tex] ln({x}^{3} - 4x) - ln(x {}^{2} - 2x ) [/tex]
can be written as;
[tex] ln( \frac{ {x}^{3} - 4x }{ {x}^2 - 2x } ) [/tex]
[tex] ln( \frac{x( {x}^{2 } - 4) }{x(x - 2)} ) = ln( \frac{x(x - 2)(x + 2)}{x(x - 2)} ) [/tex]
Now all you have to do, is divide the numerator and denominator by x and by (x-2)
to get,
[tex] ln( \frac{x(x - 2)(x + 2)}{x(x - 2)} ) = ln( \frac{x + 2}{1} ) = ln(x + 2) [/tex]
We proved that ln(x³-4x)-ln(x²-2) is equal to ln(x+2) :)
Calculate two iterations of Newton's Method to approximate a zero of the function using the given initial guess. (Round your answers to four decimal places.) f(x) = cos x, x1 = 1.2
a side of an equlateral triangle is 2/8 cm long. draw a picture that shows the triangle. what is the perimeter of the triangle?
Answer:
4/16 cm
Step-by-step explanation:
I just did the test and i got it right yourwelcome bye
Mrs Gallo weighs 94 kg. Her doctor says she has to reduce her weight! If she
reduces her weight by 16% what will her new weight be (to the nearest
kilogram)?
what means crazy plz help
Answer:
insane, fanatical, deranged, etc.
Step-by-step explanation:
What is the image point of (1,-2)(1,−2) after a translation right 4 units and down 4 units?
Answer:
(-3, 2)
Step-by-step explanation:
If we are dealing with vertical movement up/down, we manipulate the x-axis.
If we are dealing with horizontal movement left/right, we manipulate the y-axis.
We are trying to move the point right 4 units (horizontal movement) and down 4 units (vertical movement).
(1, -2) → (1 - 4, -2 + 4) → (-3, 2)
The interest on an investment varies directly as the rate of interest. If the interest is
$40 when the interest rate is 5%, find the interest when the rate is 3.2%.
The interest when the rate of interest is 3.2% is $
(Simplify your answer. Type an integer or a decimal.)
Answer:
40.32
Step-by-step explanation:
I hopped I helped! <3
what is the area of this shape? in cm please and ty
Answer:
[tex]15cm^2[/tex]
Step-by-step explanation:
Split the shape
Find the area of smaller shapes
Add two smaller shapes' area together
.52 is 10 times greater than what number
Answer:
0.052
Step-by-step explanation:
0.52 divided by 10
Answer:
Simple. It’s 0.052.
Step-by-step explanation:
0.052•10=.52
In the year 2000, the height of an apple tree was
150 centimeters. In the year 2020, the same tree has
grown to 270 centimeters. What was the average rate
of change in the height of the tree from 2000 to 2020?
In other words: On average, how fast was the tree
growing? Include units.
Answer:
(270+150)/(2020-2000)= 21 - average rate of change in the height per year
Answer:
I think to get the average rate you subtract 150 from 270 centimetres you'll get 120 centimetres then subtract 2000 from 2020 to get 20 now to get the rate divide 120cm by 20 and you will get six so the rate is 6 cm per year
Priya is mixing drops of food coloring to create purple frosting for a cake she uses 24 drops of red dye and 16 drops of blue dye find the ratio of drops of red dye to total drops of dye
Answer:
24:40
Step-by-step explanation:
To find the radio for red dye to total drops of dye, just add the red and blue dye.
The ratio of drops of red dye to total drops of dye is 3:2.
What is Ratio?When a number is divisible by another number, then it can be written in the form of a:b, this is called Ratio.
Priya is making frosting.
The number of drops of blue dye is 16.
The number of drops of red dye is 24.
Ratio ( Red dye : Blue dye) = 24 : 16
Ratio ( Red dye : Blue dye) = 3:2
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Will Give Brainliest: Quadratic Equations: 8th Grade Algebra
I need the axis of symmetry, the coordinates of the vertex, and whether the vertex is a minimum or maximum for the following three quadratic equations.
1. [tex]2x^2-8x+7[/tex]
2. [tex]y=-2x^2+3x-5[/tex]
3. [tex]y=4x+2x^2-5[/tex]
Answer:
Axis of symmetry:
1. x=2
2. x=3/4
3. x=-1
Vertex:
1. (2,-1)
2. (3/4, -31/8)
3. (-1,-7)
Vertex min/max:
1. Minimum
2. Maximum
3. Minimum
8.A golfer swings a club about a pivot point. If the head of the club travels a distance of 26 feet and rotates through an angle of 5 radians, which of the following gives the distance the club head is from the pivot point?
The distance the club head is from the pivot point is about 5.2 feet.
What is a circle?A circle is the locus of a point such that its distance from a fixed point known as the center is always constant.
Let r represent the radius of the circle, that is the distance the club head is from the pivot point. Hence:
Length of arc = angle in radians * radius
26 = 5r
r = 5.2 feet
The distance the club head is from the pivot point is about 5.2 feet.
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I REALLY NEED HELP MY GRADES GO IN TONIGHT AND I CAN SOLVE I NEED A REAL ANSWER I WILL CHECK BEFORE GIVING
POINTS!!!!!!!!
Answer/Step-by-step explanation:
Given:
Identify the fraction with the greater value in each pair and color it on the solution strip to solve the riddle.
Given fraction:
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
[tex]\frac{1}{2}\;or\;\frac{2}{5}[/tex]
[tex]\frac{2}{6} \;or\;\frac{1}{4}[/tex]
[tex]\frac{1}{3}[/tex] [tex]or\frac{1}{5}[/tex]
[tex]\frac{2}{3}\;or\frac{2}{5}[/tex]
[tex]\frac{3}{5}\;or\frac{3}{7}[/tex]
[tex]\frac{5}7\;or\frac{6}8[/tex]
[tex]\frac{5}{5}\;or\frac{6}7[/tex]
[tex]\frac{1}6\;or\frac{2}7[/tex]
[tex]\frac{5}8\;or\frac{8}9[/tex]
[tex]\frac{1}6\;or\frac{3}{10}[/tex]
[tex]\frac{3}{10}\;or\frac{4}{12}[/tex]
[tex]\frac{2}{12}\;or\frac{4}{5}[/tex]
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Solve:
Finding greatest value for each;
Starting with [tex]\frac{1}{2}\;or\;\frac{2}{5}[/tex]
Turning both into decimal
1 ÷ 2 = 0.5
2 ÷ 5 = 0.4
Hence, [tex]\frac{1}{2}[/tex] is the greater value
∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞
[tex]\frac{2}{6} \;or\;\frac{1}{4}[/tex]
2 ÷ 6 = 0.33333333333
1 ÷ 4 = 0.25
Hence, [tex]\frac{2}{6}[/tex] is the greater value
∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞
[tex]\frac{1}{3}or\frac{1}{5}[/tex]
1 ÷ 3 = 0.33333333333
1 ÷ 5 = 0.20
Hence, [tex]\frac{1}{3}[/tex] is the greater value
∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞
[tex]\frac{2}{3}\;or\frac{2}{5}[/tex]
2 ÷ 3 =0.66666666666
2 ÷ 5 = 0.4
Hence, [tex]\frac{2}{3}[/tex] is the greater value
∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞
[tex]\frac{3}{5}\;or\frac{3}{7}[/tex]
3 ÷ 5 = 0.6
3 ÷ 7 = 0.42857142857
Hence, [tex]\frac{3}{5}[/tex] is the greater value
∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞
[tex]\frac{5}7\;or\frac{6}8[/tex]
5 ÷ 7 = 0.71428571428
6 ÷ 8 = 0.75
Hence, [tex]\frac{6}{8}[/tex] is the greater value
∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞
[tex]\frac{5}{5}\;or\frac{6}7[/tex]
5 ÷ 5 = 1
6 ÷ 7 = 0.85714285714
Hence, [tex]\frac{5}{5}[/tex] is the greater value
∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞
[tex]\frac{1}6\;or\frac{2}7[/tex]
1 ÷ 6 = 0.16666666666
2 ÷ 7 = 0.28571428571
Hence, [tex]\frac{2}{7}[/tex] is the greater value
∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞
[tex]\frac{5}8\;or\frac{8}9[/tex]
5 ÷ 8 =0.625
8 ÷ 9 = 0.88888888888
Hence, [tex]\frac{8}9[/tex] is the greater value
∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞
[tex]\frac{1}6\;or\frac{3}{10}[/tex]
1 ÷ 6 = 0.16666666666
3 ÷ 10 = 0.3
Hence, [tex]\frac{3}{10}[/tex] is the greater value
∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞
[tex]\frac{3}{10}\;or\frac{4}{12}[/tex]
3 ÷ 10 = 0.3
4 ÷ 12 = 0.33333333333
Hence, [tex]\frac{4}{12}[/tex] is the greater value
∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞
[tex]\frac{2}{12}\;or\frac{4}{5}[/tex]
2 ÷ 12 = 0.16666666666
4 ÷ 5 = 0.8
Hence, [tex]\frac{4}{5}[/tex] is the greater value.
∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞
~Learn with Lenvy~
PLEASE HELP WILL MARK BRAINLIEST THANK YOU
Write down 3 examples of a number that is both divisible by 6 and has the same last digit as 4^n. N is any integer of your choice above 1000
Answer:
Step-by-step explanation:
if n is a positive integer then 4^n has last digit 4 or 6
we choose any number having 4 digits whose sum is divisible by 3 and last digit is 4 or 6.
1014,1026,1104 etc.