True. Keeping the terminals and cable connections clean helps to ensure a good electrical connection, which can prolong the life of the battery.
Keeping the terminals and cable connections of a battery clean is important for prolonging the battery's life. Dirt, corrosion, or other buildup on the terminals can create resistance in the circuit, which can lead to overheating and damage to the battery. This can cause the battery to charge and discharge less efficiently, reducing its overall capacity and lifespan. To clean the terminals, you can use a wire brush or a toothbrush with baking soda and water to scrub away any corrosion. Then, dry the terminals and cables thoroughly before reconnecting them to the battery. This will ensure a good electrical connection and a longer-lasting battery.
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8.A 1580 kg car is traveling with a speed of 150 m/s. What is the magnitude of the horizontal net force that is required to bring the car to a halt in a distance of 50.0 m
The magnitude of the horizontal net force required to bring the car to a halt in a distance of 50.0 m is 2370 N.
What is force?
Force is a quantity that describes the interaction between two objects or systems. It is a vector quantity, meaning it has both magnitude (size or strength) and direction. Forces can cause changes in an object's motion, shape, or internal energy.
The magnitude of the horizontal net force required to bring the car to a halt in a distance of 50.0 m can be calculated using the equation:
force = (mass * velocity^2) / (2 * distance)
where mass is the mass of the car, velocity is the initial velocity of the car, and distance is the distance over which the car is brought to a halt.
Plugging in the given values, we get:
force = (1580 kg * 150 m/s^2) / (2 * 50.0 m)
force = (237,000 N) / 100
force = 2370 N
Hence, the magnitude of the horizontal net force required to bring the car to a halt in a distance of 50.0 m is 2370 N.
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A block is resting on an slope. (Figure 3) Which of the following forces act on the block? Check all that apply. O weight O static friction O normal force O kinetic friction O force of push
The correct option is A, B, and C. A block resting on a slope is Weight, static friction, and Normal force.
Static friction is a force that continues an item at relaxation. Static friction definition can be written as: The friction skilled while individuals try to move a desk-bound object on a surface, without surely triggering any relative movement between the frame and the surface on which it's miles.
Static friction is a form of friction force that acts on a body when there's no relative motion between the object and the surface. So, it can act even if the frame is in motion however there should be no relative motion.
A pressure acting on an item is said to be a static force if it no longer exchanges the scale, function, or route of that precise object. The pressure implemented to a structure acts as a load to that precise structure, that is why static force is likewise called a static load.
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Complete Question:
A block is resting on a slope. (Figure 3) Which of the following forces act on the block?
Check all that apply.
A). Weight
B). Static friction
C). Normal force
D). Kinetic friction
E). Force of push
How to calculate distance of a ball rolling down a ramp?
With the equation: it is possible to determine t for each of the four ramp segments. t 1 = t 2 - t 1, and t 2 = t 4 - t 3 Likewise, x is the distance between the designated spots for times 3 and 4, respectively.
Although the gravitational force is same when you roll the ball down a ramp, it is no longer in free fall. Now, it has a vector structure. Knowing the downward force and the ramp's incline makes the problem appear to be Pythagorean. Keep in mind that the ball will go at the same speed at the bottom of the ramp as it would have. A ball begins rolling down a ramp with constant acceleration at time zero (t=0), initially at rest. It moves 1 foot between t=0 and t=1 seconds, you see. How much movement occurs between t = 1 second and a.
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Which of the following properties of a 2.3 MHz ultrasound wave remains unchanged as it passes into human tissues
When it comes to frequency, a 2.3 MHz ultrasonic wave's characteristic does not alter while it travels through human tissues.
The frequency of a wave is the number of oscillations it performs in a second. It's calibrated in hertz (Hz). The number of waves that pass a specific place in a predetermined period of time is known as wave frequency. The hertz (Hz) is the SI unit for wave frequency, and 1 hertz is equivalent to 1 wave crossing a fixed point in 1 second. A wave with a higher frequency has more energy than a wave with a lower frequency of the same amplitude.
As a result, a wave's frequency is unaffected by the medium through which it travels.
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What is B_{\text {out }}, the z component of the magnetic field outside the solenoid?
The magnetic field outside the solenoid [tex]B_{\text {out }}[/tex] is zero.
The magnetic field lines are present outside the solenoid, but there are significantly less of them there than there are inside the solenoid. This is known as the flux. As a result, the magnetic field outside is thought to be almost nil. It is more accurate to assume that the magnetic field outside the solenoid is zero if the solenoid is quite long. It is false close to the solenoid's edge. We consider the magnetic field outside the solenoid to be zero for practical purposes. This amount of flux divided by the area outside the solenoids gives the flux density, which is equal to the strength of the field outside the solenoid is zero.
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Suppose that the railcar passes by a horn that is emitting a sound with frequency f. Which of the following describes the frequency f PS-10-1-prime.gif that the person on the railcar hears?
A. f PS-10-1-prime.gif > f before passing the horn, f PS-10-1-prime.gif < f after passing it
B. f PS-10-1-prime.gif < f before passing the horn, f PS-10-1-prime.gif > f after passing it
C. f PS-10-1-prime.gif = f before passing the horn, f PS-10-1-prime.gif = f after passing it
D. f PS-10-1-prime.gif > f before passing the horn, f PS-10-1-prime.gif > f after passing it
F PS-10-1-prime.gif > f before passing the horn, f PS-10-1-prime.gif < f after passing it describes the frequency f PS-10-1-prime.
Hence, Option A is correct.
The Doppler effect causes the frequency heard by the railcar passenger prior to passing the horn to be higher than the real frequency of the sound released, whilst the frequency heard after passing the horn is lower than the actual frequency. This is why the answer to this question is A. A railcar is a self-propelled passenger-carrying railroad vehicle. A train with a single coach and a driver's cab at one or both ends is typically referred to as a "railcar." Such vehicles are referred to as "railmotors" by several railway companies, including the Great Western.To know more about railcars here
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Find the y-component of this vector: 22.3 m 77.1° Remember, angles are measured from the +x axis.
Answer:
-21.7m
Explanation:
To find the y-component of the vector, we need to find the vertical displacement from the point at the bottom of the vector to the x-axis (or its y-coordinate value).
To calculate this we can create a triangle with the vector as the hypotenuse, the y-axis as the second side and draw an imaginary line from the end of the vector directly horizontally across to the y-axis.
We can use the given angle to find the angle between the y-axis and the angle. Since the angle of a quadrant is 90 degrees, the angle within our triangle must be [tex]90-77.1=12.9[/tex] degrees.
From here, to find the length of the side on the y-axis we can use the trigonometric cos function.
[tex]cos \theta =\frac{adjacent side}{hypotenuse}[/tex]
Therefore [tex]cos 12.9=\frac{y-component}{22.3}[/tex] and [tex]ycomponent = 22.3cos12.9[/tex]
This gives us a value of 21.7 (3.s.f) for our y-component.
Finally, the y-component is also a vector so it also needs a direction. Therefore like its coordinate, its value will be -21.7m.
Why would a parcel of air rise relative to other air in the atmosphere?
a. A parcel of air will rise if it has a lower density than the surrounding air.
b. A parcel of air will rise if the air in the parcel has a lower mass than the surrounding air.
c. A parcel of air will rise if it has a higher density than the surrounding air.
d. A parcel of air will rise if the air in the parcel has a higher mass than the surrounding air.
A) A parcel of air will rise if it has a lower density than the surrounding air. is the relative order of air in the atmosphere.
In the atmosphere, air moves from high pressure to low pressure areas. When a parcel of air is heated, it expands and becomes less dense than the surrounding air. As a result, the parcel of air rises because it is less dense than the surrounding air, which creates a lower pressure area.
This process is known as convection and is responsible for many weather phenomena such as thunderstorms and cloud formation. In contrast, if a parcel of air cools and becomes more dense, it sinks because it creates a higher pressure area than the surrounding air.
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You rub a piece of wool upon your skin and your skin becomes negatively charged because it gained _____.
When you touch a piece of wool against your skin, your skin acquires a negative charge because of the conservation of charge, which caused it to gain a positive charge.
Charge is a material's property that can be transferred into another person's body. The transfer of the charge results in the generation of electricity. The following are some examples of charge's various properties: 1 Electric charge addition 2 Electric charge conservation 3 Electric charge quantization. Equations in chemistry are denoted by the capital letter Q to denote charge, with the elementary charge of an electron (e) serving as a standard unit. The coulomb is the SI-derived unit of charge (C). In electrical engineering, the ampere-hour (Ah) unit of charge is frequently used.Dipole Definition in Chemistry and Physics. by this primary information we can consider that when you rub a piece of wool upon your skin and your skin becomes negatively charged because it gained a positive charge as the result of conservation of charge.
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A golf ball rolls up a hill toward a miniature-golf hole. Assign the direction toward the hole as being positive. a. If the ball starts with a speed of 2.0 m/s and slows at a constant rate of 0.50 m/s2, what is its velocity after 2.0 s
The velocity of the ball is 1 m/s which starts with a speed of 2.0 m/s and slows at a constant rate of 0.5 m/s².
According to the data given:
Speed of the ball: 2.0 m/s
Acceleration: 0.50 m/s²
Time is 2.0 s
The ball starts rolling up the hill with a speed of 2m/s (u=2 m/s²) and it decelerates at a constant rate of 0.5 m/s² (a = -0.5 m/s², minus because it decelerates).
The equation for calculating velocity is:
v = u + a x t, t represents time here
So, ball's velocity after 2 seconds is:
v = 2m/s + (-0.5m/s² x 2s)
v = 2m/s + (-1m/s)
v = 1m/s
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The mass of the Earth is 5.972 x 1024-kg and its orbital radius is an average of 1.496 x 1011 meters. Calculate its linear momentum. (Hint: It takes the Earth 365 days to complete one orbit.)
The linear momentum of the earth when mass and orbital radius are given is calculated to be 17.8 × 10²⁸ kg m/s.
The orbital radius (r) of earth is 1.496 × 10¹¹ m. So, the distance covered by one rotation is,
Distance = 2 π r = 2π (1.496 x 10¹¹) m
365 day when converted into seconds is, 365 × 24 × 60 ×60 s
So, the period of one rotation is 3.15 × 10⁷ s.
The velocity of earth (v) = distance/time = [2π (1.496 × 10¹¹)]/ 3.15 x 10⁷ = 298840 m/s
Linear momentum = mass × velocity = 5.972 × 10²⁴ kg × 298840 m/s = 17.8 × 10²⁸ kg m/s
Therefore, the linear momentum of earth is 17.8 × 10²⁸ kg m/s
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Is it possible to whirl a bucket of water fast enough in a vertical circle so the water won't fall out if so, what is the minimun speed
Yes, it is possible to whirl a bucket of water fast enough in a vertical circle so the water won't fall out.
The minimum speed required to do this is known as the “Centrifugal Force Limit” and is calculated based on the size and shape of the bucket and the weight of the water. Generally, a speed of at least 20-30 revolutions per minute is required to keep the water from spilling out.
F = (m * v^2) / r
Where:
F = centrifugal force (N) m = mass of water (kg) v = linear velocity (m/s) r = radius of the circle (m)Learn more about speed:
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How much of the world's energy is hydroelectric?
According to the United Nations Environment Programme, hydropower accounted for 16.6% of global electricity generation in 2018.
This is equivalent to a total installed capacity of 706 GW, making it the second largest energy source after thermal sources.
Hydropower is a renewable energy source and is often seen as a more sustainable alternative to thermal sources, as it does not release any greenhouse gases into the atmosphere. Additionally, hydropower is a reliable source of energy, and can be used to meet peak energy demand.
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a child swings on a playground swing with a 2.5 m long chain. what is the period of the child's motion. what is the frequency of the vibration
The period of the child's motion is 3.171 seconds. The frequency of the vibration is 0.315 Hz.
The time period is 3.171 seconds.
2 × [tex]\pi[/tex] [tex]\frac{L}{g} ^{\frac{1}{2} }[/tex]
= 3.171 seconds
The frequency is the reciprocal of the time period.
f = 1 ÷ 3.171
= 0.315Hz
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an explorer walks 22 km north, then 47 km at 55o south of east. what is her resultant displacement?
Answer:
Below
Explanation:
Vertical components
22 - 47 sin 55 = - 16.5 km
Horizontal components
47 cos 55 = 26.96
Use Pythagorean Theorem
d^2 = (-16.5)^2 + 26.96^2
d = 31.6 km
The set of spectral lines that we see in a star's spectrum depends on the star's (a) atomic structure. (b) chemical composition. (c) rotation rate.
The set of spectral lines that we see in a star's spectrum depends on the star's (b) chemical composition, (d) temperature.
The spectral lines of a star are determined by its chemical composition and temperature. These properties determine the number and type of atoms present in the star's atmosphere. Each type of atom has its own unique set of spectral lines, and the temperature of the star determines the energy level of the atoms, which affects the wavelengths of the spectral lines emitted. The rotation rate and atomic structure of a star do not affect the set of spectral lines we see in its spectrum.
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A soft drink bottle resonates as air is blown across its top. What happens to the resonant frequency as the level of fl uid in the bottle decreases
As air is blowing across the top of a soft drink bottle, it reverberates. The frequency grows as the chamber's length lengthens.
Who defines frequency?The frequency of physics is the number of waves that pass by a specific location in a time period. According to this concept, how several cycles or waves do a body in periodical motion experience in a single unit of time?
What is a wave length?The distance between normal incidence (adjacent crests) in adjacent cycles determines how far a waveform signal has traveled in place or over a wire. In wireless systems, this length is often expressed in metres (m), centimeters (cm), or millimeters (mm) (mm).
Therefore, As air is blown, a soda pop bottle reverberates.
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When a rubber rod is rubbed with wool, the rod becomes negatively charged. What can you conclude about the magnitude of the wool's charge after the rubbing process
The wool must start out negatively charged before becoming positively charged after donating its electrons to the rubber rod.
What happens when wool is rubbed on a rubber rod?A rubber rod becomes negatively charged when wool is brushed against it, and the magnitude of the charge on the wool is equal to the charge on the rod. By applying the same amount of negative charge to the rod, the wool becomes positively charged.
Why does a polythene rod become negatively charged when it is brushed against wool?Electrons generate energy while rubbing a polythene rod with a duster because of the friction. When they have enough energy, electrons can escape from an atom and "rub off" onto a polythene rod.
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What is the distance a catcher has to throw the ball from home to second base?
To throw out a runner, the catcher must toss the ball 130 feet out, 3 feet behind home plate, up to second base.
What is the explanation for the given answer?In order to throw out a runner, the catcher must throw the ball a distance of c=84.85 ft from home base to second base.
The distance between second base and the back tip of home plate shall be 127 feet, 3 inches.
As a result, although though the bases' "points" are 90 feet apart, the actual distance between each subsequent set of base markers is more like 88 feet (26.8 m).
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Is SCID a deletion mutation?
No, SCID is not a deletion mutation.
The AK2 gene, which codes for the mitochondrial enzyme adenylate kinase 2 (AK2), is mutated (missense mutations; deletions) in SCID, which is brought on by an increase in lymphocyte apoptosis [75,76]. A category of extremely rare diseases known as severe combined immunodeficiency (SCID) are brought on by abnormalities in various genes involved in the growth and operation of immune cells that fight infections. At birth, infants with SCID seem healthy, yet they are prone to serious infections.
Due to mutations in the gene encoding the common chain for several cytokine receptors, X-linked SCID is the most prevalent kind. Adenosine deaminase deficiency (ADA def.) and IL-7R-chain deficiency are the second and third most frequent causes, respectively.
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You are deigning another dolly andbag ytem for a different actor in the performance the ma of the dolly and the actor combined i 76kg and then ma of the andbag i 18kg the coefficient of kinetic friction Between the dolly and the tage floor i 0. 20. What i the acceleration
The acceleration of a dolly-sandbag system when mass and coefficient of kinetic friction is given is calculated to be 0.29 m/s².
Given that,
The mass of the dolly and actor combined M = 76 kg
The mass of the sandbag m = 18 kg
The coefficient of kinetic friction between the dolly and the stage floor = 0.20.
Let the acceleration is a.
From Newton's 2nd law of motion, we can write that,
ΣF = (m+M) a
mg - μMg = (m+M) a
a = g (m- μM)/ (m+M)
a = 9.8 ( 18 - 0.20×76)/(18+76)
a = 0.29 m/s².
Thus, the acceleration of the dolly-sandbag system is 0.29 m/s².
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Ball A od mass 5.0 kilograms moving at 20. meters per second colides with ball B of imknnown mass moving at 10 meters per scond in the same direction. After the collision, ball A movies at 10. meters per second and ball B at 15 meters per second, both still in the same direction. What is the mass of ball B
Answer:
10 kg
Explanation:
Use law of conservation of momentum
momentum of system before collision = momentum of system after collision
5 kg * 20 m/s + x kg * 10 m/s = 5 kg * 10 m/s + x kg * 15 m/s
100 + 10x = 50 + 15 x
50 = 5x
x = 10 kg
Spring constant problem. What is the formula for k in terms of the period T and the mass?
A. K= 4pi^2m/T^2
B. K= 4*pi^2/mT^2
C. K= 2*pi*m/T
The formula for k in terms of the period T and the mass m in spring constant problem is k = 4π²m/T². The formula applies to a spring-mass system.
What is a spring-mass system?A spring-mass system is a system where a mass of object is attached at the free end of the spring. The system will perform a simple harmonic motion where the oscillations occur periodically. The period of any moving object in that motion can be counted as follows
T = 2π√(m/k)
Where
T = period (s)m = mass of object (kg) k = spring constant (N/m)Find the formula for the spring constant k in terms of T and m!
We use the formula above to find k.
T = 2π√(m/k)
√(m/k) = T/2π
m/k = (T/2π)²
m/k = T²/4π²
k = 4π²m/T²
Hence, the formula for the spring constant in the spring-mass system is k = 4π²m/T². The answer is A.
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What are the coefficients in the equation for the magnetic field component of the wave after the period increases by a factor of 2.70
The coefficient of magnetic field was found to be Bmax, k = 1.53x10¹¹, 1.14x10⁴,3.43x10¹² T,1/m,rad/s.
Define magnetic field ?Moving charges, wave action, and magnetic materials all experience the magnetic influence of a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetization is applied to it when it moves through a magnetic field. A permanent magnet's magnetic field draws on ferromagnetic materials like iron and repels or attracts other magnets. The three additional magnetic effects of diamagnetism, electromagnetism, and biomagnetism also cause tiny forces to be exerted on "nonmagnetic" materials by a nonuniform magnetic field, although these forces are frequently so minute , they can only be detected using laboratory apparatus. Electric currents used in electromagnets and time-varying electric fields produce magnetic fields that surround magnetized objects.
Magnetic field maximum = 1.531011,
The wave number is 1.14104.
In teslas, the angular frequency is 3.431012 T.
meters-1 in reverse,
rad/s = radians per second
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Mercury thermometer is not suitable to measure the temperature of very cold place. Why?
The use of a mercury thermometer is not suitable for the purpose of determining the temperature of extremely cold ice because at such low temperatures, mercury transforms into a translucent state, making it impossible to read.
Another reasons why mercury thermometer is not suitable to measure the temperature of the very cold place are:
Since mercury freezes at a temperature of -38.83 degrees Celsius, a mercury thermometer will not work in extremely cold temperatures. We are unable to use a thermometer that contains mercury at low temperatures because the glass could shatter at those temperatures.The body whose temperature we are measuring with the thermometer does not radiate heat in the opposite direction.When exposed to low temperatures, mercury takes on a transparent appearance, making it more challenging to obtain accurate readings.To learn more about mercury thermometer, click here:
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Answer the questions based on the information given. The Amur plate, a small plate, has moved away from the Eurasian plate. It has moved125,000 meters in 25 million years. It is moving eastward. What is the rate of motion of the Amur plate
The solutions are: The movement is 5 mm per year. The plate is 5,000 meters to the east. The Amur and Eurasian plates would collide, creating an ocean floor.
The rate of motion is in mm per year so you need to convert the distance it has moved to millimeters.
1 meter = 1,000 meters
125,000 will therefore be:
= 125,000 * 1,000
= 125,000,000 millimetersRate of motion = 125,000,000 / 25,000,000 years
= 5 mm/year
The plate is moving east and in 1 million years it would be:
= 1,000,000 * 5 mm/year
= 5,000,000 mm
n meters this is:
= 5,000,000 / 1,000
5,000 meters east
ecause the Amur and the Eurasian plates are moving apart, the ocean would have to fill up the space left which would lead to the development of a new oceanfloor.
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Answer: 5 mm/year, 5000 meters east, new ocean floor
Explanation:
Does speed increase down a ramp?
The speed depends on the gravitational force acting on the object in the rolling motion of the object that is acting on it at a continuous moment rate. the speed increases at a constant rate.
Rolling motion of any object occurs when the object starts sliding in a different methods from the other objects such as when the objects starts to roll from the ramp or any other sloppy surface and it rolls down due to the gravitational force and with many other forces such as the rolling tangential force. many forces are acting on the object at the same moment and we are just seeing the gravitational force which is playing a major portion. Hence by this information we can consider that the ball accelerates at a constant rate as it moves down the slope because of the constant gravitational force acting on it in a major portion and the rolling tangential force on the object is acting in the smaller form.
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An electric dipole is formed from +/- 5. 0 nC point charges spaced 3. 0 mm apart. The dipole is centered at the origin, oriented along the y-axis. Part A What is the electric field strength at point (x, y) = (25 mm, 0 cm)? Express your answer using two significant figures. Part B What is the electric field strength at point (x, y) = (0 cm, 25 mm)? Express your answer using two significant figures
The electric field strength at point (x,y) = ( 25 mm ,0cm) is =16321.0769 N/C
The electric field strength at point (x,y) = (0cm, 25 mm) is =35321.58999 N/
What is meant by electric strength?An insulating substance can withstand a certain voltage at its electric strength before losing its ability to insulate. The thickness of the insulating material, as well as the test technique and conditions, will all affect the value for the electric strength.To avoid flash over before breakdown, samples with a thickness of 2mm or more are often examined in oil. Once the breakdown voltage and sample thickness have been determined, the dielectric strength may be estimated. Dielectric strengths for the majority of polymers range from 10 to 30 kV/mm, which is a respectable value.A material's capacity to withstand large voltage swings without experiencing current breakdown is measured by its dielectric strength.To learn more about electric strength refer to:
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The electric field strength at point (x,y) = ( 20 mm ,0cm) is =16321.0769 N/C
The electric field strength at point (x,y) = (0cm, 20 mm) is =35321.58999 N/C
What distinguishes an electric field from an electric field of strength?A vector is a quantity with both a magnitude and a direction, like the electric field. The vector's magnitude corresponds to the electric field intensity.
What do you mean by electric field?Each point in space has an electric field associated with it when there is charge present in any form. E, often known as electric field strength, electric field intensity, or just the electric field, is a mathematical constant that expresses the strength and direction of an electric field.
Given:
Charge = 5.0 nC
x = 25 mm, y = 0 cm
The electric field at any given point of the dipole is given as:
E= (KP) ÷ (r^2 + a^2)^3/2
Where:
K = 9x10^9 Nm^2/c^2 (coloumb constant)
P = (0.003) (5x10^-9c) which is the movement of the dipole
(0.003) is arrived at when mm is converted to m. 3.0 mm space apart was converted to a meter.
r= the point, in the question above is 20mm = 0.02m
Now, the electric field (E),
E = (KP) ÷ (r^2 + a^2)^3/2
= (9x10^9 Nm^2/c^2) (0.003 m) (5x10^-9c) ÷ [ (0.02m)^2 + (0.003)^2]^3/2
= 0.135 ÷ (8.271513x10^-6)
=16321.0769 N/C
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A copper rod of length 0.77 m is lying on a frictionless table (see the drawing). Each end of the rod is attached to a fixed wire by an unstretched spring that has a spring constant of k = 76 N/m. A magnetic field with a strength of 0.14 T is oriented perpendicular to the surface of the table.
(a) What must be the direction of the current in the copper rod that causes the springs to stretch?
The current flows (left-to-right/right-to-left) in the copper rod.
(b) If the current is 14 A, by how much does each spring stretch?
________ m
Answer:
a) The direction of the current in the copper rod that causes the springs to stretch is left-to-right. This is because the magnetic field is oriented perpendicular to the surface of the table and the force exerted on the rod by the magnetic field is given by F = qVB, where F is the force, q is the charge of the particle, V is the velocity of the particle, and B is the strength of the magnetic field. Since the force is perpendicular to the velocity of the particle, the direction of the current that produces this force must be parallel to the magnetic field. In this case, the magnetic field is oriented perpendicular to the surface of the table, so the current must flow in the direction left-to-right to produce a force that stretches the springs.
b) To find by how much each spring stretches, you can use the formula F = kx, where F is the force exerted by the spring, k is the spring constant, and x is the distance the spring stretches. In this case, the force exerted by the spring is given by F = qVB, and the spring constant is k = 76 N/m. The charge of the particle is q = Ie, where I is the current and e is the charge of an electron. The velocity of the particle is V = L / t, where L is the length of the rod and t is the time it takes the particle to travel the length of the rod. Since the current is 14 A and the length of the rod is 0.77 m, the velocity of the particle is V = 0.77 m / (1 / 14 A) = 10.78 m/s. The strength of the magnetic field is 0.14 T, so the force exerted by the spring is F = (14 A)(1.60 x 10^-19 C)(10.78 m/s)(0.14 T) = 2.40 x 10^-17 N. Therefore, the distance each spring stretches is x = F / k = 2.40 x 10^-17 N / 76 N/m = 3.16 x 10^-19 meters.
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Identify the boundary type that is being described.
Transform boundaries, continental convergent boundaries, and oceanic convergent boundaries are the boundaries that are recorded.
How do transform boundaries work?A transform boundary is an area of a fault where two surfaces slide horizontally past one another.
What exactly is a convergent ocean boundary?An oceanic convergent boundary is the collision of two oceanic lithosphere-based plates. Even if this boundary contained the same kind of lithosphere, one of the plates would subduct beneath the other.
Transform boundaries are where crust is neither created nor destroyed at this boundary.In the region where the plates come into contact, movement along this boundary causes crumpling, lifting, and folding of the earth's crust—the continental convergent boundary.At this boundary, also known as the oceanic convergent boundary, the subduction zone frequently forms an arc of volcanic islands.To learn more about Transform boundaries here:
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