Triangle IJK has the coordinates listed:
Where is J' after a reflection over the y-axis?

It will take 16.66years long for the money to double

The formula for calculating the compound amount is expressed as:

A = P(1+r)^t

Substitute into the formula to have:

1800 = 900(1+0.0425)^t

2 =(1+0.0425)^t

2 = 1.0425^t

ln2 = tln1.0425

t =  ln2/ln1.0425

t = 0.6931/0.0416

t = 16.66years

This shows that it will take 16.66years long for the money to double

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Answer: I was thinking (5,0), (4,1), and (3,2) for a total of 12 ways.

Step-by-step explanation:1

It is 3: the partitions of 5 into ≤2 parts.

Answer:

buuuuuuuuuuut butt

Step-by-step explanation:

Answer:

Step-by-step explanation:

The perimeter of a circle is 2πr

r here is 7 so the perimeter of the full circle is 14π which is 43.9822972

But you only have half a circle, so 43.9822972 / 2 = 21.991148.

But now you have to add the 14 cm to it to close the half circle, so 21.991148 + 14 = 35.991148 or 36 cm

Answer:

Solution

9

1

3

6

Step-by-step explanation:

Answer:

gas barrels = 20,400,000

diesel barrels = 17,400,000

other barrels =  22,200,000

Step-by-step explanation:

Total barrels = 60,000,000

gas = 34%   of the barrels

diesel = 29% of the barrels

others = 37% of the barrels     100% - 34% - 29% = 37%

How many of each type of barrels?

60,000,000 ×  34% = gas barrels ;   60,000,000 × .34 = 20,400,000

60,000,000 × 29% = diesel barrels; 60,000,000 × .29 = 17,400,000

60,000,000 × 37% = other barrels;   60,000,000 × .37 = 22,200,000

 Check: Total  barrels  60,000,000                                 = 60,000,000                                    

Step-by-step explanation:

apply angle sum property of triangle in ∆BCA

now,

x + x + 110° = 180

2x = 180 - 110 = 70

x = 70/2 = 35

x = 35°

HOPE THIS ANSWER HELPS YOU DEAR! TAKE CARE

Answer:

a= -1

b= 7

c= 0

Step-by-step explanation:

equation is

y=h(x)(x-7)

let x be 5 and y be 10 to solve for a

10=h(5)(5-7)

10=h(-10)

h=-1

now equation is

y= -x²+7x

so a=-1

b=7

c=0

The value of a is -1, the value of b is 7 and the value of c will be equal to zero.

Mathematical actions are called expressions if they have at least two terms that are related by an operator and include either numbers, variables, or both.

Adding, subtraction, multiplying, and division are all reflection coefficient operations. A mathematical operation such as reduction, addition, multiplication, or division is used to integrate terms into an expression.

As per the data provided in the question,

y = h(x) × (x-7)

let x be 5 and y be 10 to solve for a

10=h(5) × (5-7)

10 = h(-10)

h = -1

now equation is

y = -x²+7x

So,

a = -1

b = 7

c = 0

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[tex]\boxed{\sf Area_{(Square)}=(side)^2}[/tex]

[tex]\boxed{\sf Area_{(Rectangle)}=Length\times Breadth}[/tex]

[tex]\boxed{\sf Area_{(Rhombus)}=\dfrac{1}{2}\times Diagonals}[/tex]

[tex]\boxed{\sf Area_{(Triangle)}=\dfrac{1}{2}\times Base\times Height}[/tex]

Answer:

He needs 132

Step-by-step explanation:

hope it helps

Answer:

8, 13, 18

Step-by-step explanation:

Middle number is 13, there are only 3

Max is 10/2 more so 18

Min is 18-10

Answer:

20%

Step-by-step explanation:

(61200-51000)/51000×100

(102000/51000)×100

0.2×100=20%

Hope that helped! :)

Answer:

8n+2 first let’s plug in n which is 1

8(1)+2=10

The answer is 10 but Brian said the expression is equal to 83. He is incorrect because 8 times 1 is 8 and then plus 2 is 10.

I hope it helps.

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Average rate of change between x = 2 and x = 4 is:

[tex]\boxed{\sf Average\: change=\dfrac{f(a)-f(b)}{a-b}}[/tex]

[tex]\\ \sf\longmapsto f(x)=3x^3-1[/tex]

[tex]\\ \sf\longmapsto f(4)=3(4)^3-1=3(64)-1=192-1=191[/tex]

[tex]\\ \sf\longmapsto f(2)=3(2)^3-1=3(8)-1=24-1=23[/tex]

Average change

[tex]\\ \sf\longmapsto \dfrac{192-23}{4-2}[/tex]

[tex]\\ \sf\longmapsto \dfrac{168}{2}[/tex]

[tex]\\ \sf\longmapsto 84[/tex]

The number is 3947

It should be noted that 36 hundreds will be equal to:

= 36 × 100

= 3600

It should be noted that 34 tens will be:

= 34 × 10

= 340

7 ones will be:

= 7 × 1

= 7.

Therefore, the sum will be:

= 3600 + 340 + 7 = 3947

Answer:

3947

Step-by-step explanation:

Answer:

-500

Step-by-step explanation:

i knew the answer

have a great day ;)

Answer:

Yes.

Step-by-step explanation:

They are similar by the AA (Angle-Angle) Similarity Theorem.

Angle P is congruent to Angle P,

and another angle congruency is <Q and <S OR <R and <T by the

Corresponding

Angle Congruency Theorem.

With two pairs of congruent angles, we can say that Triangle PQR and Triangle PST are similar by the AA Similarity Theorem.

Answer:

es 54 espero que esto ayude adiós!

Step-by-step explanation:

El volumen de un cilindro con un radio de 6 cm y una altura de 9 cm es 1018 cm³

Un cilindro es una forma tridimensional con dos bases paralelas unidas por una trayectoria curva a una distancia constante.

El volumen de un cilindro es:

Volumen = πr²h

Given that: r = 6 cm; h = 9 cm;

Volumen = πr²h = π(6)²(9) = 1018 cm³

El volumen de un cilindro con un radio de 6 cm y una altura de 9 cm es 1018 cm³

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Answer:

[tex]- \frac{3}{5}[/tex]

Step-by-step explanation:

slope-intercept form: y = mx + b

y = (x , y)

m = slope = [tex]-\frac{3}{5}[/tex]

x = (x , y)

b = y-intercept = [tex]- \frac{7}{9}[/tex]

With this given information, your slope will be [tex]-\frac{3}{5}[/tex]

Answer:

-3/5

Step-by-step explanation:

The answer is -3/5 I think

Answer: How would i know what im calculating?

Step-by-step explanation:

Step-by-step explanation:

1)

x⁴×x^a = x¹²

you know that you can add the exponents when multiplying terms with the same base value/variable ?

because that is what we are doing here to solve it :

x^(4 + a) = x¹²

therefore,

4 + a = 12

a = 8

2)

y^b / y⁵ = y²

similar to 1), but when we divide, we subtract the exponents.

y^(b - 5) = y²

b - 5 = 2

b = 7

3)

3^c = 1/27

27 = 3³

27×3^c = 1

3³×3^c = 1

3^(3 + c) = 1

now we need to remember : x⁰ = 1.

therefore, 3⁰ = 1

3^(3 + c) = 3⁰

3 + c = 0

c = -3

4)

(m³)² = m^d

aha !

now we need to remember, we can multiply the exponents, when we have an exponent of an exponent term.

m^(3×2) = m^d

3×2 = d

6 = d

5)

7⁰ = e

remember, x⁰ = 1, so also 7⁰ = 1.

therefore, e = 1.

6)

4^-2 × 4⁹ × 4^‐5 = 4^f

so, now we need apply what we just learned to a sequence of operations :

each term has the same base value (4), and they are all multiplied, so we can do the described adding of the exponents :

4^(-2 + 9 - 5) = 4^f

therefore,

f = -2 + 9 - 5 = 2

Answer:

just here 4 points

Step-by-step explanation:

Answer:

I'm not sure what the question is. Graph?

Step-by-step explanation:

See graph.

Answer:

352

what r u do

789

why nt coming

why r u nt talking

Answer:

13/20

Step-by-step explanation:

65% = 65/100 = 13/20

Hoped this helped.

Answer:

13/20

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

Answer:

Hint #33 / 3

The equation is y=\dfrac{1}{2}x -2y=

2

1

​

x−2y, equals, start fraction, 1, divided by, 2, end fraction, x, minus, 2.

Step-by-step explanation:on kan

Answer:

I believe it is 252 correct me if I'm wrong

Answer:

252

Step-by-step explanation:

25 dozen is 300 cookies subtract 48 and get 252

The sentence representing the equation is 912 is the same as 15 decreased by a number.

An equation is a mathematical statement that shows that two mathematical expressions are equal.

Given an equation, 912 = 15 − x

Here, 912 is equal to a number which is being subtracted from 15.

Hence, The sentence representing the equation is 912 is the same as 15 decreased by a number.

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Answer:

Converse

Step-by-step explanation:

Converse

Ghhhhhhhnbb tggy

Answer:

Option: B is the correct

Step-by-step explanation:

Step-by-step explanation:

We are given two matrices A and B as follows:

\begin{gathered}A=\left[\begin{array}{ccc}3&0\\2&-1\end{array}\right]\end{gathered}

A=[

3

2

0

−1

]

and

\begin{gathered}B=\left[\begin{array}{ccc}2&8\\0.6&3\end{array}\right]\end{gathered}

B=[

2

0.6

8

3

]

We know that the multiplication of two matrices of the type:

\begin{gathered}A=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]\end{gathered}

A=[

a

c

b

d

]

and

\begin{gathered}B=\left[\begin{array}{ccc}a'&b'\\c'&d'\end{array}\right]\end{gathered}

B=[

a

′

c

′

b

′

d

′

]

is given by:

\begin{gathered}AB=\left[\begin{array}{ccc}aa'+bc'&ab'+bd'\\ca'+dc'&cb'+dd'\end{array}\right]\end{gathered}

AB=[

aa

′

+bc

′

ca

′

+dc

′

ab

′

+bd

′

cb

′

+dd

′

]

Hence, here we have:

\begin{gathered}AB=\left[\begin{array}{ccc}3\times 2+0\times 0.6&3\times 8+0\times 3\\2\times 2+(-1)\times 0.6&2\times 8+(-1)\times 3\end{array}\right]\end{gathered}

AB=[

3×2+0×0.6

2×2+(−1)×0.6

3×8+0×3

2×8+(−1)×3

]

i.e.

\begin{gathered}AB=\left[\begin{array}{ccc}6+0&24+0\\4-0.6&16-3\end{array}\right]\end{gathered}

AB=[

6+0

4−0.6

24+0

16−3

]

i.e.

\begin{gathered}AB=\left[\begin{array}{ccc}6&24\\3.4&13\end{array}\right]\end{gathered}

AB=[

6

3.4

24

13

]