Two speakers are driven by the same amplifier. The first speaker is placed in the origin, the second one is free to move along the x-axis (see figure). A receiver is placed on the on the y-axis, a distance L from the origin. The speakers emit sound at frequency f, the velocity of sound in the air is v. The second speaker is initially in the origin and it is the slowly moved toward the positive x-axis. Write the results in terms of L, f, and v.
a) What is the wavelength of the sound waves in the air?
b) Find the first position x of the second speaker at which the receiver does not get any sound (destructive interference).
c) Find the first position x of the second speaker at which the receiver gets maximum intensity (constructive interference). Exclude the x=0 position
Answers
The results in terms of wavelength, velocity, and frequency i.e (L,f,v) are as follow,.
(a) λ = v/f
(b) The value of the first minimum will be [tex]x =\sqrt{\frac{v^2}{4 f^2}+\frac{v L}{f}}[/tex]
(c) The position for the first maxima of 2nd speaker = [tex]$$x=\sqrt{\frac{v}{f}\left(\frac{v}{f}+2 L\right)}$$[/tex]
A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is often defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).
(a) Relation among velocity, wavelength and frequency can be defined the expression: v = fλ
From above, we can write, (λ) (wavelength) can be equal to velocity (v) / Frequency (f)
So, λ = v/f
(b) path difference can be determined by using the expression: [tex]\Delta x=x_2-x_1 \\[/tex]
[tex]\Delta x=\sqrt{L^2+x^2}-L\end{aligned}$$[/tex]
So, for the first minimum, we can conclude the following:
[tex]$\left\{n x=\frac{d}{2}=\frac{v}{2 f}\right.$$$\frac{v}{2 f}=\sqrt{L^2+x^2}-L$$[/tex]
[tex]\left(\frac{v}{2 f}+L\right)^2 & =L^2+x^2 \\\\x^2 =\frac{v^2}{4 f^2}+L^2+\frac{v L}{f}-L^2 \\\\x =\sqrt{\frac{v^2}{4 f^2}+\frac{v L}{f}}[/tex]
(c) for first order maxima
[tex]$$\begin{aligned}& \Delta x=\lambda \\& \frac{v}{f}=\sqrt{L^2+x^2}-L\end{aligned}$$[/tex]
[tex]$$\begin{aligned}x^2 & =\frac{v^2}{f^2}+L^2+\frac{2 V L}{f}-L^2 \\x & =\sqrt{\frac{v^2}{f^2}+\frac{2 v L}{f}}\end{aligned}$$[/tex]
So, the position for the first maxima of 2nd speaker will be:
[tex]$$x=\sqrt{\frac{v}{f}\left(\frac{v}{f}+2 L\right)}$$[/tex]
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The missing diagram is attached below:
Related Questions
A boy exerts a force of 225 N on a lever (Links to an external site.) to raise a 1250 N rock a distance (Links to an external site.) of 0.13 m. If the lever is frictionless, how far did the boy have to move his end of the lever
Answers
If the lever is frictionless, to raise the rock a distance of 0.13 m, then the boy has to move the lever to 0.72 m.
An external force that acts upon an object results in a motion of the object, then it is called a work done upon the object by that force.
Given that the external force on a lever is 225 N and on a rock is 1250 N. The distance of motion by the rock is 0.13 m.
Hence the work done by the lever will be equivalent to the work done by the rock to move a particular distance.
Work (Lever) = Work (Rock)
F(lever) x D (lever) = F (rock) x D (rock)
225x D(lever)= 1250 x0.13
D(lever) is 0.72 m
Hence we can conclude that the distance of the motion by the lever is 0.72 m.
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a total of 10.0j of work is done in accelerating a 20-n object from rest across a horizontal frictionless table. what is the total kinetic energy gained by the object
Answers
The total kinetic energy gained by the object when accelerating a 20-n object from rest across a horizontal frictionless table is 10.0 J.
How do you determine the total kinetic energy?To determine the total kinetic energy gained by the object, we can use the work-energy principle, which states that the work done on an object is equal to the change in kinetic energy of the object.
Work done = change in kinetic energy
W = Kf - Ki
where
W = work done (10.0 J)
Kf = final kinetic energy
Ki = initial kinetic energy (0 J, since the object is at rest)
Given the information provided, we know that a total of 10.0 J of work is done in accelerating the 20-n object from rest.
So,
Kf = W + Ki
Kf = 10.0 J + 0 J
Kf = 10.0 J
Therefore, the total kinetic energy gained by the object is 10.0 J
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. Two spherical objects have masses of 8,000 kg and 5.0 kg. Their centers are separated by a distance
of 1.5 m. Find the gravitational attraction between them.
Answers
Two spherical objects have masses of 8000 KG and 1500 KG their centers are separated by a distance of 1.5 M, the gravitational attraction between them is 3.56 × 10⁻⁴N.
How does gravitational force work?The gravitational force, also known as gravity, pulls objects with mass in the same direction. We frequently think about the Earth's gravitational pull. This force is firmly holding your body in place. But every mass-bearing object attracts other mass-bearing objects toward it through gravity.
Using the formula of gravitational attraction
F = G× M₁M₂/d²
where G = 6.67 × 10⁻¹¹ Nm²Kg⁻²
M₁ = 8000Kg
M₂ = 1500 Kg
F = 6.67 × 10⁻¹¹ × 8000 × 1500 / (1.5)²
F = 3.56 × 10⁻⁴ N
The gravitational force of attraction between them is 3.56 × 10⁻⁴ N.
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A mass of 0.343 kg moves down a 5 meter ramp in 5.8 seconds. What is its velocity and kinetic energy
Answers
According to the given information the velocity is .0148 m/s2 and the kinetic energy is 3.78 J.
What is the straightforward meaning of velocity?The movement that an item or particle experiences with regard to time is expressed vectorially as velocity. One metre per second (m/s) is the accepted unit of flow speed (also known as speed).
What does velocity in SI mean?The metric speed unit is the meter per minute (m/s). A different way to express velocity magnitude is in centimeters per second (cm/s).
vilocity = 5/(5.8×5.8)
= 0.148
kinetic energy = 1/2mv^2
= 1/2 × (0343 × 0.148×0.148)
= 3.78 J
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Help!!!!!
Question answer in the photo
Answers
Answer: D
Explanation:
The wind will begin to blow the sediments of the arch away, causing the arched structure to become thinner over time. Therefore, the best answer is option D.
5. Is the motion of the stars around Polaris (NCP) due to the __________rotation (daily motion) or ___________revolution (yearly motion) of Earth
Answers
The motion of the stars around Polaris (NCP) is due to rotation (daily motion) of Earth.
Polaris is a star in Ursa Minor's northern circumpolar constellation. It is known as Ursae Minoris and is also known as the North Star or Pole Star. With an apparent brightness of roughly 1.98, it is the brightest star in the constellation and may be seen with the bare eyes at night. The star's location is less than one degree from the north celestial pole, making it the current northern pole star. The star's constant location in the Northern Sky makes it ideal for navigation.
Its distance is considered as part of the cosmic distance ladder since it is the nearest Cepheid variable. The updated Hipparcos stellar parallax distance to Polaris is approximately 433 light-years (133 parsecs), whereas the successor mission Gaia distance is around 448 light-years (137 parsecs). Other techniques of calculation produce significantly disparate results.
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A simple pendulum has a period of 3 seconds . If the value of ‘g’ is taken as 9.98 ms-2 calculate the length of the pendulum.
Answers
Answer: The length of the pendulum is approximately 2.495 meters.
Explanation:
The period of a simple pendulum is the time it takes for the pendulum to swing back and forth through one full oscillation. The period of a simple pendulum is related to the length of the pendulum and the acceleration due to gravity (g) by the formula:
Period = 2 * pi * sqrt(length / g)
In this case, you are given that the period of the pendulum is 3 seconds and the value of g is 9.98 ms-2. You can use these values to solve for the length of the pendulum using the formula above.
Substituting in the values given, you get:
3 = 2 * pi * sqrt(length / 9.98)
Solving for length, you get:
length = (3 / (2 * pi))^2 * 9.98
= 0.5^2 * 9.98
= 0.25 * 9.98
= 2.495
Therefore, the length of the pendulum is approximately 2.495 meters.
A stone is thrown vertically upward with an initial speed of 18.1 m/s. Neglect air resistance. The speed of the stone when it is 8.26 m higher is:
Answers
The velocity of the object when it first reaches a height of 8.10 meters is 18.05 m/s.
Calculation-To find the speed of the stone when it is 8.26 m higher, we can use the equation for vertical motion under constant acceleration. The equation is:
v^2 = u^2 + 2as
Where:
v = final velocity (m/s)
u = initial velocity (m/s)
a = acceleration due to gravity (9.8 m/s^2, downward)
s = distance traveled (m)
In this case, the initial velocity is 18.1 m/s, the distance traveled is 8.26 m upward, and the acceleration due to gravity is 9.8 m/s^2 downward. We can substitute these values into the equation and solve for the final velocity.
v^2 = 18.1^2 + 2 * 9.8 * 8.26
v^2 = 327.61
v = sqrt(327.61)
v = 18.05 m/s
Why ignore air resistance while calculating projectile motion?Air resistance is the term for the frictional force that slows an object's velocity as it moves through the air. Although air resistance considerably affects trajectory motion, it is not taken into account in beginning physics due to the complexity of the calculations.
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when the time of day for a certain ship is 12 noon the time of day at the Prime Meridian is 5 p.m. what's the ship's longitude
Answers
The required longitude of the certain ship when the time of the day is 12 noon at the Prime Meridian is 5 p.m is 75° West.
The sun is highest in London, but will not pass the ship for another 5 hours.
Given that,
The time of day for a certain ship is 12 noon at the Prime Meridian is 5 p.m.
The ship must be five hours west of Greenwich since the sun goes from east to west.
Each hour of sun motion is 15° of longitude. The ship is located at (5 x 15°) = 75° West longitude.
Thus, the ship's longitude is 75° West.
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i need help with this can give a heart or like if its right
Answers
The new electrostatic force between the charges, given that q₁ is reduced to 1/2q₁ and q₂ is tripped is 3/2Fₑ (Option C)
How do I determine the new electrostatic force?First, we shall determine the initial electrostatic force between the charges. Details below:
First Charge (q₁) = q₁second Charge (q₂) = q₂Electric constant (K) = KDistance apart (r) = rInitial electrostatic force (F) = Fₑ =?F = Kq₁q₂ / r²
Fₑ = Kq₁q₂ / r²
Finall, we shall determine the new electrostatic force. The is illustrated below:
First Charge (q₁) = 1/2q₁second Charge (q₂) = 3q₂Electric constant (K) = KDistance apart (r) = rNew electrostatic force (F) =?F = Kq₁q₂ / r²
F = (K × 1/2q₁ × 3q₂) / r²
F = 3/2Kq₁q₂ / r²
But,
Fₑ = Kq₁q₂ / r²
Thus
F = 3/2Fₑ
Thus, we can conclude that the new electrostatic force is 3/2Fₑ (Option C)
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Just as a light-year is the distance that light can travel in 1 year, we define a light-second as the distance that light can travel in 1 second, a light-minute as the distance that light can travel in 1 minute, and so on. Calculate the distance in both kilometers and miles represented by each of the following:
Answers
Approximately 5.878 x 1012 miles or 9.461 x 1015 meters, a light-year is the maximum distance light can travel in a single year..
What is light year and calculate the distance in both kilometers and miles?A light year is the distance light travels in one year, approximately 9.461 x 10^15 meters or 5.878 x 10^12 miles.A light-second is the distance that light can travel in one second, which is approximately 299,792,458 meters or approximately 186,282.397 miles.A light-minute is the distance that light can travel in one minute, which is approximately 17,987,000,000 meters or approximately 11,162,913.12 miles.A light-hour is the distance that light can travel in one hour, which is approximately 1,079,000,000,000 meters or approximately 669,573,787.2 miles.A light-day is the distance that light can travel in one day, which is approximately 25,902,000,000,000 meters or approximately 16,093,441,632 miles.A light-year is the distance that light can travel in one year, which is approximately 9.461 x 10^15 meters or approximately 5.878 x 10^12 miles.To learn more about light year refer:
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Which type of engine takes in air, accelerates it, and pushes it out the exhaust nozzle to produce thrust that pushes the aircraft forward
Answers
A jets engine is a device that produces a strong pushing force known as thrust out of liquid fuel that is high in energy.
What do aircraft turbine engines do?A rotary engine called a gas turbine converts the flow of combustion into energy.Axial or centrifugal compressors (or both) can be used to boost air pressure and temperature before it enters the combustion chamber. Ambient air is pulled into the engine intake.
How is thrust produced by a jet engine?By raising internal engine pressure, jet or rocket engines generate thrust.This higher pressure inside the jet and rocket engine causes the forward force to be greater than the backward force.
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The largest meteorite of lunar origin reportedly has a mass of 19 g. If the meteorite placed on a scale whose spring constant is 83 N/m, what is the compression of the spring
Answers
According to reports, the biggest meteorite with lunar origin weighs 19 g. If the meteorite placed on a scale whose spring constant is 83 N/m, 0.22 m is the compression of the spring.
We can use Hooke's Law to calculate the compression of the spring caused by the meteorite. Hooke's Law states that the force exerted on a spring is directly proportional to the spring's compression or extension.
= F
= k * x
where F is the force (in newtons), k is the spring constant (in N/m), and x is the compression (in meters).
Given the mass of the meteorite is 19 g and the spring constant is 83 N/m, the force exerted on the spring can be calculated as
= F
= (mass of the meteorite) * g
= (19 g) * (9.8 m/s^2)
The compression of the spring can be found by rearranging Hooke's Law and substituting in the force and spring constant
x = F/k
x = (19 * 9.8) / 83
x = 0.22 m
The compression of the spring caused by the meteorite is 0.22 m.
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How do you think the speed a satellite fall towards Earth compares to the speed it is moving forward
Answers
The speed a satellite fall towards Earth compares to the speed it is moving forward If the speed drops, it will fall toward the earth.
We can say that satellite speed has a significant impact on satellite motion because if a satellite's speed is reduced by half, it will fall towards the earth because it is drawn in by the earth's gravitational pull. However, if a satellite's speed is doubled, it will travel into space because the earth's gravitational pull will no longer hold it in orbit.
When a satellite is moving quickly, the force of gravity may not be able to hold it in orbit. If it moves slowly, it won't make enough progress to resist gravity's pull and collide with the object it is orbiting.
Rockets are used to put the majority of satellites into orbit. When the pull of Earth's gravity and the satellite's speed are equal, the satellite circled the planet. Without this equilibrium, the satellite would either fall back to Earth or shoot off into space in a straight path.
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Copper (Cu) reacts with phosphorus (P) to produce copper (II) phosphide.
so far all ive got is Cu₂ +4P --> _____
Answers
Answer: The answer is Cu+ P4 = Cu3P2
Which after balancing would be, 6Cu + P4 = 2Cu3p2
Explanation: Copper (Cu) is a metal and Phosphorous (P) is a non-metal. Metals and Non-metals combine to form ionic compounds where there is a transfer of ions from metal to non-metal.
Phosphorous has 5 valence electrons in its outer shell and Copper has 2 valence electrons. Following the octet rule, which means that the outer shell should have 8 electrons to be complete we see that combining these two metals on combining have electrons insufficient so we combine till we reach the octet structure. In this case, it happens when there are three copper and two phosphorous. We see that there are no more valence electrons. So it forms Copper II Phosphide, where the two indicates the charge of Copper.
Then we move on to balance both the sides of the equation, upon placing one number after the other to make the numerical value of elements equivalent to the other. Which gives us the answer.
Due to the drivers not paying attention, a small car and a big truck collide, both are initially moving at 25 mph towards each other. Compare the magnitude of the force the truck exerts on the car to the magnitude of the force the car exerts on the truck. Which force is greater? Which vehicle would you rather ride in? Describe why you made your choice.
Answers
As a result, the amount of force the truck exerts on the automobile is equal to the amount of force the truck exerts on the car.
As per Newton's third law of motion
If object A applies a force to object B, then object B must apply a force to object A in the opposite direction and of equal strength. This rule illustrates a symmetry in nature whereby forces always occur in pairs and that no body can exert a force without also being subjected to one.
Because the accident is a head-on collision, according to Newton's third law, both the automobile and the truck will exert equal force against one another.
As a result, it will be safe to ride in the truck since the automobile will accelerate more quickly under the same force due to its lighter weight. Bigger acceleration results in a greater change in velocity, which increases the driver's workload.
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What velocity must a 2. 25 kg croquet mallet have in order to have the same momentum as 1. 25 kg ball that has a momentum 6. 25 kg•m/s to the west
Answers
2.78 m/s to the west velocity must a 2. 25 kg croquet mallet have in order to have the same momentum as 1. 25 kg ball that has a momentum 6. 25 kg•m/s to the west.
Given,
Mass = 2.25kg
Momentum = 6.25 kg•m/s
To find,
Velocity
Formula used,
Momentum = Mass x velocity
Calculation,
6.25 kg•m/s = 2.25 kg x velocity
Velocity = 6.25/2.25
Velocity = 2.78 m/s
The conservation of momentum principle asserts that the quantity of momentum inside a problem domain remains constant; momentum is not generated nor destroyed, but only modified by the action of forces as defined by Newton's equations of motion.
Newton's third law says that for every force exerted by object A on object B, object B exerts an equal but opposite force in magnitude and direction. Newton utilised this concept to create the law of conservation of momentum.
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what is the momentum of a 25.1g rifle bullet traveling with a velocity of 351 m/s at 45 degrees northeast
Answers
We know that momentum is defined as the product of mass and velocity, hence p = 0.025 kg x 0.1 m/s or p = 0.0025 kg m/s. Therefore, the bullet's momentum is equal to 0.0025 kg/s.
The ability of a gun to cause such substantial damage is due to the momentum that the gun imparts to the projectile. An object's momentum is equal to its mass times its velocity. Making a thing more large or moving more quickly can increase its momentum and, thus, its capacity for destruction. The force acting on both is therefore the same, but the rifles have smaller recoils since their mass is higher than that of the bullet, which results in a reduced recoil compared to the bullet's speed.
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A 1.41-kg block slides across a rough surface such that it slows down with an acceleration of 1.10 m/s2. What is the coefficient of kinetic friction between the block and the surface
Answers
The coefficient of kinetic friction between the block and the surface is 0.11.
The coefficient of kinetic friction can be found using the equation:
friction = force of friction = coefficient of kinetic friction * normal force
The normal force is equal to the weight of the object, which can be calculated as weight = mass * acceleration due to gravity
The force of friction can be calculated using the equation:
friction = force of friction = coefficient of kinetic friction * weight
The coefficient of kinetic friction can be found by rearranging the equation and substituting the known values:
coefficient of kinetic friction = friction / weight
= (1.10 m/s2) / (1.41 kg * 9.8 m/s2)
= 0.11
So, the coefficient of kinetic friction between the block and the surface is 0.11.
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A naval navigator is using sonar to look for sunken cargo. The waves he is using have a frequency of 120
kHz and a wavelength of 3 mm. How far away is the cargo if the sound wave is emitted at exactly 9:24 a.m.
and returns to hit the ship's sensor 3 seconds later?
Answer should be in meters
Answers
The distance between the Naval Navigator and the sunken cargo was found to be 2175 m by using sonar with 120kHz frequency and a wavelength of 3mm.
What is the purpose of sonar?Sonar is largely used by NOAA scientists to create nautical charts, find underwater navigational hazards, find and map things on the bottom like shipwrecks, and map the actual seafloor. Sonar comes in active and passive varieties.
Speed of sound in water =1450m/s
Time lag between transmission and reception of Sonar waves =3 s
sound waves travel a distance is twice the distance between the navigator and cargo (2S) in this time lag.
Time taken for the sound to reach the submarine = 1/2 ×3 = 1.5s
Distance between the Navigator and the sunken cargo, S=1450×1.5s =2175m.
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Because of the Doppler effect, a light- or sound-emitting object moving toward you has a ________ compared to a stationary object.
Answers
Because of the Doppler effect, a light- or sound-emitting object moving toward you has a lower amplitude compared to a stationary object.
The Doppler effect is generally defined as the shift in wave frequency (whether it be sound or light) caused by relative motion between the wave source and the observer. Every time a source wave moves in reference to the observer, this effect can be seen.
The Doppler effect allows astronomers to determine the frequency of light waves as an object moves in relation to the observer. As it approaches you, the frequency decreases and the item exhibits a blueshift. A redshift indicates that an item is travelling away from us.
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If a circle has a circumference of 25.1 cm compare where the object would have been if it had gone in a straight line at 4 cm/s for 6.28 seconds(no acceleration) to where it is after it has gone around the circle for 6.28 at 4.0cm/s
Answers
The object would have returned to its initial starting point if it had travelled round a circle.
What is the distance travelled by the object?
The distance travelled by the object is determined from the product of speed of the object and the time of motion of the object.
D = vt
where;
v is the speed of the object = 4 cm/st is the time of motion of the object = 6.28 sThe distance travelled by the object is calculated as follows;
D = ( 4 cm / s ) x ( 6.28 s )
D = 25.1 cm
Thus, at the given time and speed the object would have travelled round the circle. That is the object would have made one complete revolution.
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If the Barbie had a mass of 0.23kg and the Barbie was dropped 11ft 11inches (assuming there was no rubber bands) how fast would the Barbie be moving at the bottom of the path?
Answers
The Barbie would be moving with speed 27.69 ft/s at the bottom of the path.
What is speed?Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Mass of the Barbie = 0.23 kg.
Initial height of the Barbie: h= 11 ft 11 inches = ( 11 + 11/12) feet = 11.92 feet.
Acceleration due to gravity: g = 32.17 ft/s²
Hence, the speed of the Barbie at the bottom of the path = √(2gh)
= √( 2 × 32.17 ×11.92) ft/s
= 27.69 ft/s.
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a tennis player hits a tennis ball with a force of 15N and moves it 25m . of the tennis players power output was 750W, find out how long they did work on the tennis ball for
Answers
When we do, we make sure to measure our mass in kilograms. We determine that F is equal to 124.26 newtons by entering these numbers into our calculator.
That is the average magnitude of the force applied to the tennis ball.
How is the force of a tennis serve calculated?The equation that Newton was referring to is shown by a serve. You can calculate the total force that was applied by the tennis racket to the ball by multiplying the weight of the racket by the speed at which the player swings their racquet.
After serving, how much does a tennis ball slow down?An average 120-mph serve slows to 82 mph before the bounce, 65 mph after the bounce, and 55 mph at the opponent's racket, according to tennis instructor and analyst John Yandell.
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A 10.0-g bullet is fired into a stationary block of wood having mass m 5 5.00 kg. The bullet imbeds into the block. The speed of the bullet-plus-wood combination immediately after the collision is 0.600 m/s. What was the original speed of the bullet
Answers
The original speed of the bullet was 300.6 m/s.
What is the best meaning of mass?A measure of the amount of matter contained in or constituting a physical body. In classical mechanics, the mass of an object is related to the force required to accelerate it and hence is related to its inertia, and is essential to Newton's laws of motion.
Given:
mV bi +MV wi =mV b +M Vwf
where m= mass of bullet =10 g=10^−2 ∣kg
M= mass of wood block =5 kg
V bI = initial mass of bullet
Vwi = initial mass of wood block and V bf =V wf
=0.06 m/s 10 −2 Vbi+0(10 −2 +5)0.6 V
bi = 10 −2 5.01×0.6 V
bi =300.6 m/s
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A truck travels due east for a distance of 1.4 km, turns around and goes due west for 7.7 km, and finally turns around again and travels 2.6 km due east. (a) What is the total distance that the truck travels
Answers
The total distance that the truck travels is 11.7 km
Part (a)
The algebraic sum of the various distances results in the total distance covered by the trucks.
DT = d1 + d2 + d3
So, total distance that the truck travels = 1.4 + 7.7 + 2.6 = 11.7 km
Part (b) Question is missing :
(b) What are the magnitude (in km) and direction of the truck's displacement? (Enter a number.)
magnitude #? km
direction? east, west or neither.
The quickest route taken by the object to get from one spot to another is called displacement.
As the truck travels in three directions, from east to west to east, it begins out from the east. Think of the east as being good and the west as being negative. As a result, the displacement can be calculated as shown below.
D =d1 - d2 + d3 = 1.4 - 7.7 + 2.6 = 1.4 - 5.1 = -3.7 km
Here, the negative sign shows that the truck has displaced in the west direction.
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10) An ice cube of mass 0.046 kg and temperature -14 C is heated until it is now fully melted and at a temperature of 11C now. What percentage of the total energy was used to melt the ice
Answers
90.23 % percentage of the total energy was used to melt the ice.
Define Energy?Energy is the quantitative property that is transferred to a body or to a physical system, recognizable in the performance of work and in the form of heat and light. Energy is a conserved quantity—the law of conservation of energy states that energy can be converted in form, but not created or destroyed.
Calculation -:Total energy used from -[tex]14^{o}[/tex]C to [tex]11^{o}[/tex]C
= [tex]m_{i}c_{i} T_{i}[/tex] + [tex]m_{i} L_{f}[/tex] +[tex]m_{w} c_{w}[/tex]Δ[tex]T_{2}[/tex]
= (0.013×2200×8) + (0.031×334000) + (0.013×486×11)
= 400.4 + 4342 + 69.498
= 4811.898 J
% energy used to melt = 4342/4811.898 × 100
= 90.23 %
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A cylindrical bucket of liquid (density rho) is rotated about its symmetry axis, which is vertical. If the angular velocity is ω, show that the pressure at a distance r from the rotation axis is P=P 0+ 21rhoω 2r 2where P 0 is the pressure at r=0,
Answers
Answer:
To derive the formula for the pressure at a distance r from the rotation axis, you can use the principle of hydrostatic equilibrium. This states that the pressure at a point in a fluid is equal in all directions and the net force on a fluid element is equal to zero.
Consider a small cylindrical element of fluid at a distance r from the rotation axis, as shown in the diagram below. The dimensions of the element are dr in the radial direction, 2πr in the circumferential direction, and h in the vertical direction. The weight of the element is equal to the product of its volume, density, and the acceleration due to gravity: W = (2πr)(dr)(h)(ρ)(g). The pressure at the top and bottom faces of the element is P + dP, where P is the pressure at the point and dP is a small change in pressure. The forces acting on the element are the weight of the element, the pressure force at the top face, and the pressure force at the bottom face.
[asy]
unitsize(2cm);
pair P1, P2, P3, P4;
P1 = (0,0);
P2 = (1,0);
P3 = (1,1);
P4 = (0,1);
draw((-0.5,0)--(1.5,0));
draw((0,-0.5)--(0,1.5));
draw(P1--P2--P3--P4--cycle);
draw((0.5,0)--(0.5,1));
draw((0.25,0)--(0.25,1));
draw((0.75,0)--(0.75,1));
label("$r$", (0.5,1.5), red);
label("$
At an outdoor phyie demontration, a delay of 0. 50 econd wa oberved between the time ound wave left a loudpeaker and the time thee ound wave reached a tudent through the air. If the air i at STP, how far wa the tudent from the peaker? (1) 1. 5 × 10-m (91. 7 × 102 m (3) 6. 6 × 10? m (4) 1. 5 × 108 m
Answers
1.7×10^2 m
The student was 1.7×10^2 m far from the speaker.
Is sound slower to travel in water?The distance that sound waves travel is mostly influenced by the temperature and pressure of the ocean, even though sound travels through water at a far faster rate than it does through air.
What sounds like a sound with a high amplitude?The change in pressure that a sound wave causes when it is measured at a particular location is related to the amplitude of the wave. If the amplitude grows, the sound is heard as louder, and if it drops, it is heard as quieter.
Does greater amplitude equate to greater speed?The pace at which a wave moves has nothing to do with its amplitude. Waves A and B move forward at the same speed. Only changes in the characteristics of the medium a wave travels through can change its speed.
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To calculate the distance between the loudspeaker and the student, we can use the speed of sound in air, which is approximately 340 meters per second (m/s) at standard temperature and pressure (STP).
How is this calculated?The formula to calculate distance is:
distance = speed x time
where distance is the distance between the loudspeaker and the student, speed is the speed of sound in air, and time is the delay that was observed between the time the sound wave left the loudspeaker and the time it reached the student.
distance = 340 m/s x 0.50 s
distance = 170 m
So, the distance between the loudspeaker and the student is 170 meters.
This answer corresponds to (2) 91.7 x 102m.
It's worth mentioning that sound speed can be affected by temperature, humidity, and atmospheric pressure which can cause slight variations from the standard 340 m/s at STP.
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How long does it take a plane, traveling at a constant speed of 130 m/s, to fly once around a circle whose radius is 2650 m
Answers
51.6 seconds long does it take a plane, traveling at a constant speed of 130 m/s, to fly once around a circle whose radius is 2650 m.
The time it takes for an object to travel once around a circle of radius r at a constant speed v can be found using the equation:
T = 2 x π x r ÷ v
where T is the time in seconds, pi is approximately 3.14, r is the radius of the circle in meters, and v is the speed of the object in meters per second.
Given a constant speed of 130 m/s and a radius of 2650 m, the time it would take for a plane to fly once around the circle would be:
T = 2 x π x 2650 m / 130 m/s
T = 51.6 sec
So, it would take approximately 51.6 seconds for a plane traveling at a constant speed of 130 m/s to fly once around a circle whose radius is 2650 m.
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