Use Pythagorean Theorem to find each missing length
please help with the steps

Answer:

I think choose (1)

[tex]125 ^{ \frac{1x}{3} } [/tex]

Step-by-step explanation:

câu trả lời là trong bức ảnh trên

Answer:

Option (3)

Step-by-step explanation:

By applying the property of inscribed angle and intercepted arc in the given circle,

"Measure of an inscribed angle is half the measure of the intercepted arc"

[tex]m(\angle LKJ)=\frac{1}{2}m(\text{arc LJ})[/tex]

[tex]85=\frac{1}{2}(20x+10)[/tex]

[tex]170=20x+10[/tex]

[tex]20x=160[/tex]

[tex]x=8[/tex]

Therefore, Option (3) is the correct option.

the answer is in the picture

Answer:

x = 14 is your answer

Step-by-step explanation:

76 = 7x-22, so to figure it out, you first move -22 to the other side and get

76+22 = 7x.

add them together and you get 98 = 7x

7x would be your equation, so divide 98 by 7 and you get your solution

x = 14 is your answer

Answer:

2/3

Step-by-step explanation:

2/3 is 66 2/3%

Answer:

D. 7:10

Step-by-step explanation:

The Correct Answer

Answer:

94%

Step-by-step explanation:

4,700/5,000 x 100%

0.94 x 100% = 94%

Answer:

94%

Step-by-step explanation:

Answer:

Step-by-step explanation:

tan(30) = x/1

sqrt(3) / 3 = x/1

x= sqrt(3) / 2

Answer:

[tex]x = 24.75[/tex]

Step-by-step explanation:

Required

Find x

To find x, we have:

[tex]\angle PQR + \angle RPQ + \angle QRP = 180[/tex] -- angles in a triangle

Because [tex]\bar {PR}[/tex] is extended to S, then:

[tex]\angle QRS = \angle QRP[/tex]

So, we have:

[tex]2x + 6 + x - 7 + 5x -17 = 180[/tex]

Collect like terms

[tex]2x + x + 5x = 180 + 17 + 7-6[/tex]

[tex]8x = 198[/tex]

Divide by 8

[tex]x = 24.75[/tex]

Hope it's help you

Answer:tu culo

Step-by-step explanation:

[tex]7 - 3x = 2x - 3 \\ 7 - 3x - 2x = - 3 \\ 7 - 5x = - 3 \\ - 5x = - 3 - 7 \\ - 5 = - 10 \\ x = \frac{ - 10}{ - 5} \\ x = 2[/tex]

Answer:

Completing the square

Step-by-step explanation:

The proof is lengthy, and I don't think you came here to see that whole proof. Here it is anyway to show you the process of completing the square.

https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:quadratic-functions-equations/x2f8bb11595b61c86:more-on-completing-square/a/quadratic-formula-proof-review

Answer:

7 x 1/10 = 7/10

Step-by-step explanation:

There are 7 "bumps" on the number line, and each "bump" moves the line 1/10.

This can also be modeled as

1/10 + 1/10 + 1/10 +1/10 +1/10 +1/10 +1/10 = 7/10

Answer:

Below,

Step-by-step explanation:

The exponent part is done first

7 x 2^3

= 7 * 8

= 56.

You use the acronym PEMDAS:-

( E ( exponential) comes before  M (multiply))

Answer:

Step-by-step explanation:

18x-6=120

18x=120+6

18x=126

    x=126÷18

    x=7

Answer:

36

Step-by-step explanation:

9 is the difference

9 times 4 is 36

Subtraction is a mathematical operation. The statement "Four times the difference of 15 and 6" is equal to 36.

Subtraction is a mathematical operation that reflects the removal of things from a collection. The negative symbol represents subtraction.

The statement "Four times the difference of 15 and 6" can be expressed as,

= 4 × (15 - 6)

= 4 × (9)

= 36

Hence, The statement "Four times the difference of 15 and 6" is equal to 36.

Learn more about Subtraction:

https://brainly.com/question/1927340

#SPJ2

Answer:

First one and Third one

Step-by-step explanation:

Answer is correct from Plato

The correct expressions are:

[tex]17^{-1/4}[/tex] [tex]= \frac{1}{17^{1/4}}[/tex]

[tex]y^{1/2}[/tex] [tex]= \frac{1}{y^{-1/2}}[/tex]

In the given expression,

Since we know that the rule of exponent,

[tex]a^{-n} = \frac{1}{a^n}[/tex]

Therefore,

For the given expression,

[tex]17^{-1/4}[/tex]

Using the above property of exponent we can write it,

[tex]= \frac{1}{17^{1/4}}[/tex]

Hence this is the correct expression.

For the given expression,

[tex]y^{1/2}[/tex]

Using the above property of exponent we can write it,

[tex]= \frac{1}{y^{-1/2}}[/tex]

Hence this is the correct expression.

To learn more about exponent visit:

https://brainly.com/question/31242910

#SPJ2

Answer: hello your question lacks some information attached below is the complete question

answer :

a) attached below

b) 65 students aged 1-2 years

Step-by-step explanation:

For a Leslie matrix ; there is a relation

Pn = L^n Po  where ; Pn = population vector after n years , Po = initial population vector .

a) Initial population vector

attached below

[tex]\left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]

b) Number of birds aged 1-2 years are available after 10 years

i.e. P10 = L^10 Po

note : Po = Xo

∴ P10 = [tex]\left[\begin{array}{ccc}0&2&1\\0.2&0&0\\0&0.4&0\end{array}\right][/tex]   [tex]\left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]

we will apply  MATLAB to resolve the above matrix

P10  = [tex]\left[\begin{array}{ccc}217.91\\65.24\\31.911\end{array}\right][/tex]

∴ Number of children between 1-2 years left after 10 years  = 65.24 ≈ 65

The total number of birds aged between 1-2 years which are available after 10 years is 65 and this can be determined by using the Leslie matrix relation.

Given :

According to the given data, the initial population vector is given by:

[tex]x_0 = \left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]

Now, the total number of birds aged between 1-2 years which are available after 10 years is:

[tex]\rm P_{10} = \left[\begin{array}{ccc}0&2&1\\0.2&0&0\\0&0.4&0\end{array}\right] \left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]

Now, solve the above matrices in order to determine the value of [tex]\rm P_{10}[/tex].

[tex]\rm P_{10} = \left[\begin{array}{ccc}217.91\\65.24\\31.911\end{array}\right][/tex]

Therefore, the total number of birds aged between 1-2 years which are available after 10 years is 65.

For more information, refer to the link given below:

https://brainly.com/question/16823190

Answer:

I NOT 100% SURE BUT I THINK ITS .B)

Step-by-step explanation:

Answer:

-2 and -2

Step-by-step explanation:

Answer:

False

Step-by-step explanation:

Rational number :

A rational number is a number which can be represent as p/q of two integers where q is not equal to zero

Example: 2/3

[tex]\sqrt{3}[/tex] = 17320508075........ and it keeps extending. Since it does not terminate or repeated after the decimal point.

Therefore [tex]\sqrt{3}[/tex] is an irritational number,

Hence given statement is FALSE

Answer:

The equation of the line is [tex]y = -\frac{2}{5}x + \frac{24}{5}[/tex]

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

[tex]y = mx + b[/tex]

In which m is the slope and b is the y-intercept.

Slope:

Having two points, the slope is given by the change in y divided by the change in x. Points (2,4) and (7,2)​, so:

Change in y: 2 - 4 = -2

Change in x: 7 - 2 = 5

Slope: [tex]m = \frac{-2}{5} = -\frac{2}{5}[/tex]

So

[tex]y = -\frac{2}{5}x + b[/tex]

(2,4)

This means that when [tex]x = 2, y = 4[/tex]. So

[tex]y = -\frac{2}{5}x + b[/tex]

[tex]4 = -\frac{2}{5}(2) + b[/tex]

[tex]b = 4 + \frac{4}{5} = \frac{20}{5} + \frac{4}{5} = \frac{24}{5}[/tex]

The equation of the line is [tex]y = -\frac{2}{5}x + \frac{24}{5}[/tex]

Answer:

See explaation

Step-by-step explanation:

Given

Represent the balls with the first letters

[tex]W =1[/tex]

[tex]R =2[/tex]

Solving (a): P(F) --- White balls twice

The event of F is:

[tex]F = \{(W,W)\}[/tex]

So:

[tex]P(F) = P(W) * P(W)[/tex]

[tex]P(F) = \frac{n(W)}{n} * \frac{n(W)}{n}[/tex]

[tex]P(F) = \frac{1}{3} * \frac{1}{3}[/tex]

[tex]P(F) = \frac{1}{9}[/tex]

Solving (b): P(G) --- two different colors

The event of G is:

[tex]G = \{(W,R),(R,W)\}[/tex]

So:

[tex]P(G) = P(W) * P(R) + P(R) * P(W)[/tex]

[tex]P(G) = \frac{n(W)}{n} * \frac{n(R)}{n} + \frac{n(R)}{n} * \frac{n(W)}{n}[/tex]

[tex]P(G) = \frac{1}{3} * \frac{2}{3} + \frac{2}{3} * \frac{1}{3}[/tex]

[tex]P(G) = \frac{2}{9} + \frac{2}{9}[/tex]

[tex]P(G) = \frac{4}{9}[/tex]

Solving (c): P(H) --- White picked first

The event of H is:

[tex]H = \{(W,R),(W,W)\}[/tex]

So:

[tex]P(H) = P(W) * P(R) + P(W) * P(W)[/tex]

[tex]P(H) = \frac{n(W)}{n} * \frac{n(R)}{n} + \frac{n(W)}{n} * \frac{n(W)}{n}[/tex]

[tex]P(H) = \frac{1}{3} * \frac{2}{3} + \frac{1}{3} * \frac{1}{3}[/tex]

[tex]P(H) = \frac{2}{9} + \frac{1}{9}[/tex]

[tex]P(H) = \frac{3}{9}[/tex]

[tex]P(H) = \frac{1}{3}[/tex]

Solving (d): F and G, mutually exclusive?

We have:

[tex]F = \{(W,W)\}[/tex]

[tex]G = \{(W,R),(R,W)\}[/tex]

Check for common elements

[tex]n(F\ n\ G) = 0[/tex]

Hence, F and G are mutually exclusive

Solving (e): G and G, mutually exclusive?

We have:

[tex]G = \{(W,R),(R,W)\}[/tex]

[tex]H = \{(W,R),(W,W)\}[/tex]

Check for common elements

[tex]n(G\ n\ H) = 1[/tex]

Hence, F and G are not mutually exclusive